don't know if this is "the right"(tm) way to do it, but it seems more
pythonic:
import os
[p for p in os.environ['PATH'].split(':') if os.path.exists('%s/%s' %
(p,'phc'))]
which should return a list with the paths in which the file 'phc'
exists, or an empty list if it doesn't
Ronan Paixão
Em Dom, 2008-11-02 às 14:32 -0800, Craig Citro escreveu:
> > But I would highly suggest that someone (i.e. you) make phc detection
> > much more robust. "which" usually returns an error code unequal to
> > zero (it doesn't on Solaris :(), so that is what you should check and
> > otherwise throw a proper exception.
> >
>
> So I ended up doing something like this on #4386, but I'd be really
> curious if there's a better way. In particular, here's what I did:
>
> find_phc = os.popen2('which phc')[1].readlines()
> if find_phc == []:
> raise ValueError, "phc not found"
>
> The popen2 returns a pair of file handles, the first wrapping stdin,
> and the second wrapping stdout. (In fact, looking at this, I realize
> that I forgot to close these file handles ... patch up at #4428.)
>
> So is there a better way to search your path for an executable in Python?
>
> -cc
>
> >
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