Re: [Tutor] Hello again. Still the same problem, different question.
On 2011-11-12 05:16, Nathaniel Trujillo wrote: They gave me a website to go and download a version of livewires that would work (www.courseptr.com/downloads) and I went there but I could not find that download anywhere. http://www.delmarlearning.com/companions/content/1435455002/downloads/index.asp?isbn=1435455002 If you click on "Book related software" you'll get a zip-file which includes "livewires". Bye, Andreas ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Hello again. Still the same problem, different question.
Nathaniel Trujillo wrote: I realize that one of you told me that there is no livewires for python v3.1.1 but the book that I am reading teaches v3.1.1 and the code that is presented in the book has a line that imports a module from the livewires package. Now since the book covers v3.1.1, I would have to conclude that the code containing the line "from livewires import games" should work in version 3.1.1. They gave me a website to go and download a version of livewires that would work (www.courseptr.com/downloads) and I went there but I could not find that download anywhere. I think the website might have changed since the book was written. If anybody knows where I can get the version of livewires I need I would be truly greatful. My book is entitled Python Programming for the Absolute Beginner Third Edition. Anyway, here is the code that my book insists should work. According to one of the reviews on Amazon, that's because the author of the book has written his own customized version of Livewires which you have to use. http://www.amazon.ca/Python-Programming-Absolute-Beginner-Second/dp/1598631128 The book quite clearly says so too: TRAP Although you're welcome to visit the web site of the LiveWires organization at http://www.livewires.org.uk , be aware that the livewires package used in this book is a modified version of the package that LiveWires created. Someone there told me they would've given up by now but I am not giving up on this one or anything else. Just to give you a heads up, you will be getting questions about this until this program works. Thanks for your help. While I admire your persistence, we are all volunteers and may not appreciate being asked the same questions over and over and over again to no value. I'm just saying that at some point, you may have to expect that we'll stop answering questions if we think we're just wasting our time. If the author's custom version is not available, and the standard version doesn't work, then we're probably wasting our time. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Hello again. Still the same problem, different question.
Can you kindly mail the author? That might be a better way to have this resolved. Its interesting you are sticking with python v3. Cheers. Sent from my BlackBerry wireless device from MTN -Original Message- From: Nathaniel Trujillo Sender: tutor-bounces+delegbede=dudupay@python.org Date: Fri, 11 Nov 2011 21:16:30 To: Subject: [Tutor] Hello again. Still the same problem, different question. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Hello again. Still the same problem, different question.
I realize that one of you told me that there is no livewires for python v3.1.1 but the book that I am reading teaches v3.1.1 and the code that is presented in the book has a line that imports a module from the livewires package. Now since the book covers v3.1.1, I would have to conclude that the code containing the line "from livewires import games" should work in version 3.1.1. They gave me a website to go and download a version of livewires that would work (www.courseptr.com/downloads) and I went there but I could not find that download anywhere. I think the website might have changed since the book was written. If anybody knows where I can get the version of livewires I need I would be truly greatful. My book is entitled Python Programming for the Absolute Beginner Third Edition. Anyway, here is the code that my book insists should work. # New Graphics Window # Demonstrates creating a graphics window from livewires import games games.init(screen_width = 640, screen_height = 480, fps = 50) games.screen.mainloop() and here is the error message I keep getting Traceback (most recent call last): File "C:\Python27\new_graphics_window.py", line 6, in games.init(screen_width = 640, screen_height = 480, fps = 50) AttributeError: 'module' object has no attribute 'init' Someone there told me they would've given up by now but I am not giving up on this one or anything else. Just to give you a heads up, you will be getting questions about this until this program works. Thanks for your help. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] My program gives no output (was (no subject)
Welcome to the Tutor list.
Please provide a meaningful subbject as we track posts by subject
On 11/11/2011 4:40 PM, Nic Jaworski wrote:
python: v. 2.7.1
Compiler: WING IDE
OS: Windows 7
I am attempting to use a loop to output a 2D array for days and amount
of pennies. I have it set to loop to do a penny times the day then to
double the the penny and add a day. (the whole a penny doubles each
day problem). However when I run my program I don't get anything, no
output.
IMHO you cannot get nothing. You should either get some error message or
at least "how many days for your salary?"
Exactly what do you do to run the program?
#Nic 11/5/2011
#Penny +=1 Each Day
from math import *
from numberTest import *
from clearPause import *
from locale import *
I highly recommend not using from... import *
Instead import ... and qualify the imported items.
I am not familiar with numberTest or clearPause.
Where did you find them?
#=Main
def main():
days=indays()
salary = calc(days)
#=== Days input
def indays():
integer=0
while integer==0:
salary = raw_input("how many days for your salary? ")
integer,salary=testinteger(salary)
if integer ==0:
print 'the entry was not numeric - Please re-enter'
pause()
elif salary < 0:
print 'please enter a number greater then 0'
integer =0
else:
integer=1
return salary
#=Calculation
def calc(days):
n=0
d=1
while n>days:
n+1
d**(n)
d*2
x = array ([d,n])
print x
main()
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--
Bob Gailer
919-636-4239
Chapel Hill NC
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Re: [Tutor] Suggest Book
On 11/11/11 14:29, Pankaj Jakhar wrote: Please suggest me the best book for Python from which I can learn basics to advanced Python. The "best" book will depend on you, some like informal chatty style with lots of examples other prefer a more formal approach. For me the O'Reilly books get it about right, although APress and Addison Wesley are usually safe bets too. It will also depend on your previous experience - do you already program in another language? Do you have any formal computer science or engineering or math background? These are all things that will affect your preference. Try browsing on Amazon and other web sites, use the previews where available... One other thing to consider os that "advanced" Python tends to be a case of a specialized subject area/library rather than advanced language usage., Python is pretty simple to use at any levels. You can write obscure python but its not often good Python and possibly not even advanced! So you might be better focusing on on-line tutorials to start with then choosing a specialized book to suit your interests - like networking, web, GUI, text processing, Games etc. -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] (no subject)
Please just post plain-text (no html) and use a meaningful subject! On 2011-11-11 22:40, Nic Jaworski wrote: def calc(days): n=0 d=1 while n>days: n+1 d**(n) d*2 You are just calculating some expressions with "n" and "d" but you don't assign the results. Thus "n" and "d" will never change. x = array ([d,n]) print x In "main()" you have the line salary = calc(days) but you just return "None" (the default value for functions without a "return" statement) from "calc()". Is that what you want? main() I don't know about windows but if you want to run the script from the command line you have to add: if __name__ == "__main__": main() See http://docs.python.org/py3k/tutorial/modules.html#executing-modules-as-scripts Bye, Andreas ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] (no subject)
On Fri, Nov 11, 2011 at 4:40 PM, Nic Jaworski wrote:
> python: v. 2.7.1
> Compiler: WING IDE
> OS: Windows 7
>
> I am attempting to use a loop to output a 2D array for days and amount of
> pennies. I have it set to loop to do a penny times the day then to double
> the the penny and add a day. (the whole a penny doubles each day
> problem). However when I run my program I don't get anything, no output.
>
> #Nic 11/5/2011
> #Penny +=1 Each Day
>
> from math import *
> from numberTest import *
> from clearPause import *
> from locale import *
> #=Main
>
>
> def main():
> days=indays()
> salary = calc(days)
>
> #=== Days input
> def indays():
> integer=0
> while integer==0:
> salary = raw_input("how many days for your salary? ")
> integer,salary=testinteger(salary)
> if integer ==0:
> print 'the entry was not numeric - Please re-enter'
> pause()
> elif salary < 0:
> print 'please enter a number greater then 0'
> integer =0
> else:
> integer=1
> return salary
>
> #=Calculation
>
> def calc(days):
>
You are setting n = 0, then you loop only if n > days, and it never is.
> n=0
> d=1
> while n>days:
> n+1
> d**(n)
> d*2
> x = array ([d,n])
> print x
>
>
> main()
>
>
> ___
> Tutor maillist - Tutor@python.org
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>
>
--
Joel Goldstick
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Re: [Tutor] longest common substring
First, just a little rant :-) It doesn't help to randomly change some lines or introduce some new concepts you don't understand yet and then hope to get the right result. Your chances are very small that this will be succesful. You should try to understand some basic concepts first and build on them. From your postings the last weeks and especially from today I have the impression that you still don't understand how fundamental programming concepts work: for-loops, differences between data types (strings, lists, sets, ...) Honestly, have you already read any programming tutorial? (You'll find a big list at http://wiki.python.org/moin/BeginnersGuide/NonProgrammers )? At the moment it looks like you are just copying some code snippets from different places and then you hopelessly try to modify them to suit your needs. IMHO the problems you want to solve are a little too big for you right now. Nevertheless, here are some comments: Based on former advice, I made a correction/modification on the below code. 1] the set and subgroup does not work, here I wish to put all the subgroup in a big set, the set like That's a good idea, but you don't use the set correctly. > subgroups=[] > subgroup=[] > def LongestCommonSubstring(S1, S2): I think it's better to move "subgroups" and "subgroup" into the function. (I've noticed that in most of your scripts you are using a lot of global variables. IMHO that's not the best programming style. Do you know what "global/local variables", "namespace", "scope" mean?) You are defining "subgroups" as an empty list, but later you want to use it as a set. Thus, you should define it as an empty set: subgroups = set() You are also defining "subgroup" as an empty list, but later you assign a slice of "S1" to it. Since "S1" is a string, the slice is also a string. Therefore: subgroup = "" > M = [[0]*(1+len(S2)) for i in xrange(1+len(S1))] Peter told you already why "xrange" doesn't work in Python 3. But instead of using an alias like xrange = range IMHO it's better to change it in the code directly. > longest, x_longest = 0, 0 > for x in xrange(1,1+len(S1)): > for y in xrange(1,1+len(S2)): > if S1[x-1] == S2[y-1]: > M[x][y] = M[x-1][y-1]+1 > if M[x][y]> longest: > longest = M[x][y] > x_longest = x > if longest>= 3: > subgroup=S1[x_longest-longest:x_longest] > subgroups=set([subgroup]) Here you overwrite in the first iteration your original empty list "subgroups" with the set of the list which contains the string "subgroup" as its only element. Do you really understand this line? And in all the following iterations you are overwriting this one-element set with another one-element set (the next "subgroup"). If you want to add an element to an existing set instead of replacing it, you have to use the "add()"-method for adding an element to a set: subgroups.add(subgroup) This will add the string "subgroup" as a new element to the set "subgroups". > print(subgroups) > else: > M[x][y] = 0 > > return S1[x_longest-longest:x_longest] Here you probably want to return the set "subgroups": return subgroups 2] I still have trouble in reading files, mainly about not read "" etc. The problem is that in your data files there is just this big one-line string. AFAIK you have produced these data files yourself, haven't you? In that case it would be better to change the way how you save the data (be it a well-formatted string or a list or something else) instead of trying to fix it here (in this script). Bye, Andreas ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] (no subject)
python: v. 2.7.1Compiler: WING IDEOS: Windows 7
I am attempting to use a loop to output a 2D array for days and amount of
pennies. I have it set to loop to do a penny times the day then to double the
the penny and add a day. (the whole a penny doubles each day problem). However
when I run my program I don't get anything, no output.
#Nic 11/5/2011#Penny +=1 Each Day
from math import *from numberTest import *from clearPause import *from locale
import *#=Main
def main():days=indays()salary = calc(days)
#=== Days inputdef indays():integer=0while
integer==0:salary = raw_input("how many days for your salary? ")
integer,salary=testinteger(salary)if integer ==0:print 'the
entry was not numeric - Please re-enter'pause()elif salary
< 0:print 'please enter a number greater then 0'integer
=0else:integer=1return salary
#=Calculation
def calc(days):n=0d=1while n>days:n+1d**(n)
d*2 x = array ([d,n])print x main()
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Re: [Tutor] Suggest Book
You really don't need a book. There are tons of free materials online including Alan's excellent tutorial. Spend some time working your way through some of these free tutorials, and once you're comfortable enough writing Python programs then buy one or two books as a reference material. Good luck, Evans ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Find all strings that....
hi, this page contains interesting info about this topic. The algorithms that are discussed are all implemented in Python. http://cs.anu.edu.au/~Peter.Christen/Febrl/febrl-0.3/febrldoc-0.3/node38.html Cheers!! Albert-Jan ~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~ > >From: Jerry Hill >To: "tutor@python.org" >Sent: Friday, November 11, 2011 7:38 PM >Subject: Re: [Tutor] Find all strings that > > >On Fri, Nov 11, 2011 at 1:21 PM, Francesco Loffredo wrote: > >Anyway, taking for granted the rules contained in the edit distance definition >(Thank you, Steven!), I think that finding in a given set S all words that can >be converted into some given "target" with at most N such operations (better: >the subset of all words in S with an edit distance from "target" <= N) is a >very interesting and challenging task. Thank you (and your friend!) for this >exercise, I'll give it a try. >> >There are some standard library tools that make this pretty easy. Take a look >into difflib if you're interested. As always, there's nothing wrong with >doing it yourself so that you understand it better, of course. > >-- >Jerry > >___ >Tutor maillist - Tutor@python.org >To unsubscribe or change subscription options: >http://mail.python.org/mailman/listinfo/tutor > > >___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Find all strings that....
On Fri, Nov 11, 2011 at 1:38 PM, Jerry Hill wrote: > On Fri, Nov 11, 2011 at 1:21 PM, Francesco Loffredo wrote: > >> Anyway, taking for granted the rules contained in the edit distance >> definition (Thank you, Steven!), I think that finding in a given set S all >> words that can be converted into some given "target" with at most N such >> operations (better: the subset of all words in S with an edit distance >> from "target" <= N) is a very interesting and challenging task. Thank you >> (and your friend!) for this exercise, I'll give it a try. >> > > There are some standard library tools that make this pretty easy. Take a > look into difflib if you're interested. As always, there's nothing wrong > with doing it yourself so that you understand it better, of course. > > -- > Jerry > > Hi Jerry. I'm checking out difflib. Thanks for the suggestion. Alexander Etter > ___ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Find all strings that....
On Fri, Nov 11, 2011 at 1:21 PM, Francesco Loffredo wrote: > Anyway, taking for granted the rules contained in the edit distance > definition (Thank you, Steven!), I think that finding in a given set S all > words that can be converted into some given "target" with at most N such > operations (better: the subset of all words in S with an edit distance > from "target" <= N) is a very interesting and challenging task. Thank you > (and your friend!) for this exercise, I'll give it a try. > There are some standard library tools that make this pretty easy. Take a look into difflib if you're interested. As always, there's nothing wrong with doing it yourself so that you understand it better, of course. -- Jerry ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Find all strings that....
Alexander Etter wrote: On Nov 10, 2011, at 13:52, Francesco Loffredo wrote: Alexander Etter wrote: Hi. My friend gave me a good wake up exercise ... I'd like to try this exercise too; would you mind defining "operations" more specifically, please? Given a sufficiently broad meaning of "operations" (e.g. operation = any function call) then any word can be converted into any given word with at most ONE operation. Consider an operation not as a function. A function could easily contain more than two operations. An operation would remove two letters. An operation would add one letter. Etc. Alexander Still, it seems to me too fuzzy a definition. Steven D'Aprano gave us a very thorough one in this thread, but you seem to allow many characters to be deleted in one operation... Anyway, taking for granted the rules contained in the edit distance definition (Thank you, Steven!), I think that finding in a given set S all words that can be converted into some given "target" with at most N such operations (better: the subset of all words in S with an edit distance from "target" <= N) is a very interesting and challenging task. Thank you (and your friend!) for this exercise, I'll give it a try. Francesco - Nessun virus nel messaggio. Controllato da AVG - www.avg.com Versione: 2012.0.1869 / Database dei virus: 2092/4608 - Data di rilascio: 10/11/2011 ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] failed to load functions,
I attached the clumsy one as below: https://docs.google.com/open?id=0B93SVRfpVVg3YTNhNTMwODUtMDkyYi00ZTk4LThiOGYtMzdkNzI1ZmNhOWQ0 #!/usr/bin/python3 import os.path from collections import Counter aList=['55', '34', '77', '43', '58', '34', '77', '34', '76', '34', '77', '76', '32', '72', '34', '41', '34', '56', '70', '45', '43', '45', '34', '45', '34', '45', '76', '77', '76', '77', '76', '77', '76', '77', '76', '77', '76', '77', '82', '43', '77', '34', '77', '61', '59', '82', '65', '55', '71', '82', '80', '65', '71', '82', '65', '64', '65', '80', '84', '80', '82', '58', '74', '76', '58', '76', '74', '76', '57', '34', '57', '77', '34', '52', '84', '34', '57', '35', '34', '32', '55', '53', '34', '35', '34', '32', '54', '34', '54', '57', '54', '34', '57', '54', '57', '34', '54', '34', '54', '57', '54', '34', '57', '54', '34', '32', '34', '57', '34', '54', '35', '54', '34', '58', '77', '34', '77', '34', '53', '76', '58', '34', '56', '54', '58', '34', '57', '34', '56', '77', '54', '56', '34', '77', '76', '77', '76', '77', '53', '77', '56', '34', '32', '34', '54', '32', '54', '32', '34', '32', '54', '32', '34', '55', '61', '54', '34', '32', '54', '32', '54', '55', '34', '32', '34', '54', '34', '55', '32', '54', '34', '57', '54', '34', '54', '57', '34', '55', '59', '33', '59', '55', '34', '54', '59', '34', '55', '34', '54', '35', '57', '34', '54', '34', '55', '34', '54', '57', '55', '54', '34', '57', '34', '33', '34', '20', '54', '55', '54', '34', '54', '32', '54', '32', '34', '54', '32', '54', '32', '54', '34', '32', '34', '57', '34', '54', '35', '34', '32', '59', '34', '54', '34', '55', '33', '34', '55', '34', '35', '34', '54', '34', '32', '34', '35', '34', '54', '34', '54', '34', '54', '34', '53', '34', '57', '20', '58', '57', '76', '58', '74', '76', '55', '59', '57', '34', '57', '34', '77', '34', '54', '56', '34', '56', '54', '34', '56', '34', '54', '58', '32', '54', '76', '34', '76', '53', '34', '77', '32', '34', '77', '32', '54', '34', '32', '34', '57', '34', '32', '55', '32', '54', '32', '34', '54', '55', '54', '55', '56', '32', '76', '53', '76', '34', '53', '76', '57', '76', '53', '34', '58', '34', '54', '76', '77', '34', '76', '34', '32', '34', '35', '32', '34', '53', '76', '53', '57', '53', '34', '76', '53', '76', '34', '76', '53', '76', '57', '53', '76', '57', '76', '53', '76'] bList=['77', '34', '60', '84', '76', '34', '76', '34', '46', '59', '77', '34', '77', '82', '34', '33', '34', '82', '34', '77', '70', '58', '34', '49', '58', '49', '35', '49', '32', '61', '34', '58', '61', '58', '61', '35', '61', '70', '61', '70', '61', '34', '20', '61', '34', '58', '32', '34', '32', '58', '20', '35', '20', '34', '21', '59', '21', '34', '21', '34', '21', '34', '21', '34', '21', '34', '21', '34', '21', '34', '21', '34', '21', '34', '21', '34', '21', '59', '34', '21', '34', '21', '34', '21', '34', '21', '34', '32', '34', '61', '20', '61', '32', '34', '35', '34', '58', '34', '58', '32', '34', '58', '46', '20', '32', '61', '20', '34', '58', '34', '32', '58', '34', '32', '70', '32', '34', '30', '34', '32', '30', '61', '32', '35', '61', '32', '34', '30', '61', '58', '32', '20', '34', '20', '32', '61', '30', '20', '61', '20', '83', '35', '32', '34', '61', '34', '61', '34', '20', '32', '61', '32', '58', '32', '27', '32', '61', '59', '61', '70', '30', '59', '61', '32', '83', '30', '32', '34', '33', '80', '32', '35', '80', '59', '80', '70', '80', '81', '61', '81', '34', '32', '33', '30', '23', '27', '20', '33', '22', '27', '35', '22', '27', '22', '23', '22', '31', '22', '35', '22', '33', '22', '35', '33', '22', '31', '35', '22', '20', '2', '37', '34', '84', '33', '34', '33', '84', '36', '83', '33', '36', '69', '84', '38', '40', '38', '4', '37', '6', '1', '3', '35', '3', '38', '27', '3', '5', '3', '5', '27', '3', '27', '5', '27', '26', '3', '5', '28', '3', '28', '5', '28', '3', '28', '19', '28', '26', '37', '26', '37', '26', '37', '3', '37', '3', '26', '3', '26', '25', '19', '37', '24', '3', '5', '3', '1', '5', '1', '3', '23', '37', '24', '3', '24', '35', '23', '5', '3', '24', '3', '24', '1', '24', '3', '24', '3', '5', '3', '5', '2', '25', '5', '3', '24', '25', '5', '25', '3', '22', '3', '5', '3', '23', '3', '24', '3', '5', '3', '1', '5', '22', '1', '24', '3', '24', '3', '5', '3', '5'] cList=['19', '14', '39', '15', '43', '19', '43', '15', '13', '17', '14', '17', '43', '17', '1', '14', '2', '39', '1', '14', '39', '14', '13', '19', '14', '19', '14', '19', '39', '22', '39', '1', '39', '22', '39', '22', '39', '22', '39', '1', '17', '19', '39', '22', '14', '39', '22', '39', '1', '19', '4', '22', '14', '19', '17', '14', '19', '4', '22', '20', '1', '20', '22', '20', '1', '39', '1', '20', '38', '39', '20', '39', '22', '39', '1', '39', '1', '38', '22', '38', '39', '19', '14', '19', '3', '1', '3', '2', '3', '14', '3', '4', '14', '1', '14', '1', '14', '66', '14', '22', '14', '2', '14', '1', '14', '39', '14', '28', '14', '27', '19', '14', '29', '14', '21', '19', '43', '19', '23', '45', '29', '1', '21', '28', '8', '50', '53', '58'
[Tutor] failed to load functions,
Hi, sorry for the new post: if __name__=="__main__": for i in range(97,100): for j in range(97,100): if i != j: s1=chr(i)+"List" s2=chr(j)+"List" '''print(s1,s2)''' LongestCommonSubstring(s1,s2) I am surprised the results showed like below: $ python3 CommonSubstring.py Lis List Lis List Lis List Lis List Lis List Lis List and print(s1,s2) '''LongestCommonSubstring(s1,s2)''' showed me: aList bList aList cList bList aList bList cList cList aList cList bList exactly I wanted, but seems s1, s2 failed to go into functions. Thanks, ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] longest common substring
I wrote a crazy one, to find the common group: Please jump to the end part of this code: https://docs.google.com/open?id=0B93SVRfpVVg3MDUzYzI1MDYtNmI5MS00MmZkLTlmMTctNmE3Y2EyYzIyZTk2 Thanks again, ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] how can I save it from "for"
Look into the 'continue' and 'break' statements - both very handy when working
with loops
Or just increment/decrement the conditional until it evaluates to False
Bodsda
Sent from my BlackBerry® wireless device
-Original Message-
From: lina
Sender: tutor-bounces+bodsda=googlemail@python.org
Date: Sat, 12 Nov 2011 00:41:43
To: tutor
Subject: [Tutor] how can I save it from "for"
Hi, I don't know how to escape the
if longest >= 3:
subgroup=S1[x_longest-longest:x_longest]
print(subgroup)
form the loop.
xrange = range
subgroup=[]
def LongestCommonSubstring(S1, S2):
M = [[0]*(1+len(S2)) for i in xrange(1+len(S1))]
longest, x_longest = 0, 0
subgroups=[]
uniq={}
for x in xrange(1,1+len(S1)):
for y in xrange(1,1+len(S2)):
if S1[x-1] == S2[y-1]:
M[x][y] = M[x-1][y-1]+1
if M[x][y] > longest:
longest = M[x][y]
x_longest = x
else:
M[x][y] = 0
if longest >= 3:
subgroup=S1[x_longest-longest:x_longest]
print(subgroup)
return S1[x_longest-longest:x_longest]
if __name__=="__main__":
for i in range(97,107):
for j in range(97,107):
if i != j:
LongestCommonSubstring(a,b)
'''LongestCommonSubstring(chr(i),chr(j))'''
Thanks ahead,
___
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[Tutor] how can I save it from "for"
Hi, I don't know how to escape the
if longest >= 3:
subgroup=S1[x_longest-longest:x_longest]
print(subgroup)
form the loop.
xrange = range
subgroup=[]
def LongestCommonSubstring(S1, S2):
M = [[0]*(1+len(S2)) for i in xrange(1+len(S1))]
longest, x_longest = 0, 0
subgroups=[]
uniq={}
for x in xrange(1,1+len(S1)):
for y in xrange(1,1+len(S2)):
if S1[x-1] == S2[y-1]:
M[x][y] = M[x-1][y-1]+1
if M[x][y] > longest:
longest = M[x][y]
x_longest = x
else:
M[x][y] = 0
if longest >= 3:
subgroup=S1[x_longest-longest:x_longest]
print(subgroup)
return S1[x_longest-longest:x_longest]
if __name__=="__main__":
for i in range(97,107):
for j in range(97,107):
if i != j:
LongestCommonSubstring(a,b)
'''LongestCommonSubstring(chr(i),chr(j))'''
Thanks ahead,
___
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Re: [Tutor] Suggest Book
On Nov 11, 2011, at 9:29, Pankaj Jakhar wrote: > Hello > > Please suggest me the best book for Python from which I can learn basics to > advanced Python. > > Thank you. > > PankaJ Jakhar > I'm sure Alan or one of our veteran list members will have something to say, but at my school for a class called "intro to problem solving" or something like that CS1114, the book used is by T. Gaddis, "Introduction to Python". I think. I may be incorrect. I'll check it out on amazon. Alexander > ___ > Tutor - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] longest common substring
There's nothing wrong with writing your own code to find the longest common substring, but are you aware that python has a module in the standard library that already does this? In the difflib module, the SequenceMatcher class can compare two sequences and extract the longest common sequence of elements from it, like this: Code: import difflib a = [1, 2, 3, 7] b = [2, 3, 7] seq_matcher = difflib.SequenceMatcher(None, a, b) print seq_matcher.find_longest_match(0, len(a), 0, len(b)) Outputs: Match(a=1, b=0, size=3) See http://docs.python.org/library/difflib.html#sequencematcher-objects for lots of details. The SequenceMatcher class can do a lot more than finding the common substrings, as you might expect. The Module of the Week article for difflib may also be of interest: http://www.doughellmann.com/PyMOTW/difflib/index.html -- Jerry ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] longest common substring
On Fri, Nov 11, 2011 at 9:10 PM, Andreas Perstinger
wrote:
> On 2011-11-11 05:14, lina wrote:
>>
>> def LongestCommonSubstring(S1, S2):
>> M = [[0]*(1+len(S2)) for i in xrange(1+len(S1))] ## creat 4*5 matrix
>> longest, x_longest = 0, 0
>> for x in xrange(1,1+len(S1)): ## read each row
>> for y in xrange(1,1+len(S2)): ## read each coloumn
>> if S1[x-1] == S2[y-1]:
>> M[x][y] = M[x-1][y-1]+1
>> if M[x][y]> longest:
>> longest = M[x][y]
>> x_longest = x
>> else:
>> M[x][y] = 0
>> return S1[x_longest-longest:x_longest]
>
> That's still not the right version.
>
> If you compare your version to the one at wikibooks (
> http://en.wikibooks.org/wiki/Algorithm_Implementation/Strings/Longest_common_substring#Python
> ), you'll see that the else-branch is wrongly indented (one level too deep).
> It belongs to the first if-comparison:
>
> if S1 ...
> M[x][y] ...
> if M[x][y] ...
> ...
> else: ...
>
>
>> if __name__=="__main__":
>>
>> a=open("atom-pair_4.txt","r").readline().strip()
>>
>> b=open("atom-pair_8.txt","r").readline().strip()
>>
>>
>> print(LongestCommonSubstring(LongestCommonSubstring(a,a),LongestCommonSubstring(b,b)))
>
> ^^^
> ??? What do you try to accomplish here ???
> You call "LongestCommonSubstring" with identical strings, thus the result
> must be the same string.
> Why not
>
> print(LongestCommonSubstring(a, b))
>
> as you did the line below with "c" and "d"?
>
> Further more I think that your problems start with bad data files. In every
> file there is just one very long line which looks like a string
> representation of a list of two-digits strings. This complicates further
> processing because you have to deal with all the unnecessary commas, blanks
> and single quotes between your numbers and the square brackets at the
> beginning and the end of the line.
>
>
>> $ python3 LongestCommonSubstring.py
>> 2189
>> ['
>> ['82']
>>
>> The results are wrong.
>> c, d are the string from file atom-pair_4,txt, exactly the same as a,
>> d is the same as b.
>>
>> and even for (c,d) results are not correct, visually we can see some
>> similar groups, not mention the longest groups.
>
> And even if you use the correct function from wikibooks I can anticipate
> another problem :-)
> The implementation from wikibooks just returns the first common substring
> which it finds in the first string:
>
WikibooksLongestCommonSubstring("ABAB","BABA")
> 'ABA'
WikibooksLongestCommonSubstring("BABA", "ABAB")
> 'BAB'
>
> If there are more possible substrings with the same length (as in the
> example above) only the first one is returned.
>
> But in your example there are at least two different pathways (I've found
> three) which have the same length, as changing the order of the parameters
> will show you:
>
WikibooksLongestCommonSubstring(c, d)
> ['61', '70', '61']
WikibooksLongestCommonSubstring(d, c)
> ['83', '61', '83']
The residues of WikibooksLongestCommonSubstring(d, c) and
WikibooksLongestCommonSubstring(c,d) is different very largely,
I mean, it might be totally different.
so the possible subgroups are the union of groups of (d,c) and (c,d)?
I am really lack a programed-brain to think.
Thanks again,
>
> Bye, Andreas
>
> ___
> Tutor maillist - Tutor@python.org
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>
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Re: [Tutor] Suggest Book
I would recommend: Beginning Python: From Novice to Professional. See attached URL below. Website is also a good resource. http://trizpug.org/up-to-speed On Fri, Nov 11, 2011 at 9:29 AM, Pankaj Jakhar wrote: > Hello > > Please suggest me the best book for Python from which I can learn basics to > advanced Python. > > Thank you. > > PankaJ Jakhar > > > ___ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > > -- Troy S ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Suggest Book
Hello Please suggest me the best book for Python from which I can learn basics to advanced Python. Thank you. * PankaJ **Jakhar** * ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] longest common substring
Based on former advice, I made a correction/modification on the below code.
1] the set and subgroup does not work, here I wish to put all the
subgroup in a big set, the set like
$ python3 LongestCommonSubstring.py | uniq
{"1',"}
{"1', "}
{"1', '"}
{"1', '8"}
{"1', '82"}
{"1', '82'"}
{"1', '82',"}
{"1', '82', "}
{"1', '82', '"}
{"6', '61', '6"}
{"', '61', '63'"}
{"', '61', '63',"}
{"', '61', '63', "}
{"', '61', '63', '"}
{"', '61', '63', '6"}
{"', '61', '70', '61"}
{"', '61', '70', '61'"}
{"', '83', '61', '83',"}
{"', '83', '61', '83', "}
{"', '83', '61', '83', '"}
Please kindly notice I added a pipeline with uniq at the end, the true
prints were lots of replications, I don't know how to handle it in the
python code.
2] I still have trouble in reading files, mainly about not read "" etc.
Thanks with best regards,
#!/usr/bin/python3
import os.path
xrange = range
subgroups=[]
subgroup=[]
def LongestCommonSubstring(S1, S2):
M = [[0]*(1+len(S2)) for i in xrange(1+len(S1))]
longest, x_longest = 0, 0
for x in xrange(1,1+len(S1)):
for y in xrange(1,1+len(S2)):
if S1[x-1] == S2[y-1]:
M[x][y] = M[x-1][y-1]+1
if M[x][y] > longest:
longest = M[x][y]
x_longest = x
if longest >= 3:
subgroup=S1[x_longest-longest:x_longest]
subgroups=set([subgroup])
print(subgroups)
else:
M[x][y] = 0
return S1[x_longest-longest:x_longest]
if __name__=="__main__":
a=open("atom-pair_4.txt","r").readline().strip()
b=open("atom-pair_8.txt","r").readline().strip()
LongestCommonSubstring(a,b)
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Re: [Tutor] positional output
Hi Frankie, On 11 November 2011 12:59, Cranky Frankie wrote: > I'm trying to build a script to parse IBM AIX DB2 DDL to line up the > data types (it drives me crazy when the column data types are not > lined up). For example, typical create table DDL might be hundreds of > lines long but will look like this: > Just knocked this up: http://pastie.org/2847380 It reformats the example you posted, at least, and should leave lines that are not field definitions alone (thanks to looking for the start of the datatype after the space.) Hopefully you can get some inspiration form it. Walter ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] positional output
On Fri, Nov 11, 2011 at 1:59 PM, Cranky Frankie wrote: > Thank you for your help on this. Now for "the rest of the story." > > I'm trying to build a script to parse IBM AIX DB2 DDL to line up the > data types (it drives me crazy when the column data types are not > lined up). For example, typical create table DDL might be hundreds of > lines long but will look like this: > > -- > -- table create DDL > -- > CREATE TABLE FRANK.TEST ( > COLUMN1 DECIMAL(8), > COLUMN2 CHAR(20), > COLUMN3 TIMESTAMP, > COLUMN4 INTEGER, > COLUMN5 DATE NOT NULL WITH DEFAULT, > -- repeat for hundreds of columns > ); > COMMENT ON TABLE FRANK.TEST IS 'TEST TABLE'; > > This is just a small sample, there are many other possible lines, but > I'm only concerned about the column lines like COLUMN1 through COLUMN5 > above. > > I have a script on Windows that reads in the DDL file and writes out > each line to a new file. What I'm doing is using the split() function > to test for the presence of any DB2 standard data type, like CHAR, > INTEGER, SMALINT, etc. If I find one I want to use positional output > to make each like look like: > > COLUMN1 DECIMAL(8), > COLUMN2 CHAR(20), > COLUMN3 TIMESTAMP, > COLUMN4 INTEGER, > COLUMN5 DATE NOT NULL WITH DEFAULT, > > where all the COLUMNs would be in column 1 of the output file, the > data types would be in column 40, and the comma would be next. > > The problem is handling lines that have NOT NULL WITH DEFAULT at the > end. The thing is there could be other valid DDL in that position, and > there may or may not be a comma after the data type. What I want to do > is just take anything after the datatype, which would be element(1) in > the split() output, and just write it out. I thought I could use > rsplit() to do this, but you can't put the output of split() in > rsplit() - I tried. > > I need to do something like, after verifying that element(1) is a > valid DB2 datatype, just take everything else on the line after it, > which may be a single comma, or NOT NULL WITH DEFAULT, or something > else, and place it on the output line to be written out. > > So, to reiterate: I'm trying to build a script to line up the data > types in a create table DDL file. Splitting each line into individual > space separated elements, then checking for a valid data type, the > rebuilding the line positionally seems to be the way to go. If there's > an easyier way to do it I'm all ears. > > I don't have my script available at the moment but I could send it if > it would be helpful. > I would suggest using str.split(None, 1) to limit the amount of splits done to only 1, which means you get a list like ['COLUMN', 'DATA TYPE ETC']. Then you use the str.startswith function to check the second entry for data types, something like so (note startswith accepts a tuple of strings to look for: if splitted_line[1].startswith(data_types): print "%s %s" % (splitted_line[0].ljust(39), splitted_line[1]) HTH, Hugo ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] positional output
On 2011/11/11 02:59 PM, Cranky Frankie wrote:
Thank you for your help on this. Now for "the rest of the story."
I'm trying to build a script to parse IBM AIX DB2 DDL to line up the
data types (it drives me crazy when the column data types are not
lined up). For example, typical create table DDL might be hundreds of
lines long but will look like this:
Something like this ? I left out checking for valid types etc, just
something rudimentary to maybe point you in the right direction.
>>> a = """COLUMN1 DECIMAL(8),
... COLUMN2 CHAR(20),
... COLUMN3TIMESTAMP,
... COLUMN4 INTEGER,
... COLUMN5 DATE NOT NULL WITH DEFAULT,
... COLUMN6 CHAR(40)
... """
>>>
>>> for line in a.splitlines():
... newline = line.split()
... col_name = newline[0]
... col_type = newline[1].replace(',', '')
... field_sep = ',' if ',' in line else ''
... print '%-40s%s%s' % (col_name, col_type, field_sep)
...
COLUMN1 DECIMAL(8),
COLUMN2 CHAR(20),
COLUMN3 TIMESTAMP,
COLUMN4 INTEGER,
COLUMN5 DATE,
COLUMN6 CHAR(40)
If all you want to space it out nicely then .split(' ', 1) and '%-40s%s'
% (part1, part2) should work fine for you.
--
Christian Witts
Python Developer
//
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Re: [Tutor] longest common substring
On Fri, Nov 11, 2011 at 9:10 PM, Andreas Perstinger
wrote:
> On 2011-11-11 05:14, lina wrote:
>>
>> def LongestCommonSubstring(S1, S2):
>> M = [[0]*(1+len(S2)) for i in xrange(1+len(S1))] ## creat 4*5 matrix
>> longest, x_longest = 0, 0
>> for x in xrange(1,1+len(S1)): ## read each row
>> for y in xrange(1,1+len(S2)): ## read each coloumn
>> if S1[x-1] == S2[y-1]:
>> M[x][y] = M[x-1][y-1]+1
>> if M[x][y]> longest:
>> longest = M[x][y]
>> x_longest = x
>> else:
>> M[x][y] = 0
>> return S1[x_longest-longest:x_longest]
>
> That's still not the right version.
>
> If you compare your version to the one at wikibooks (
> http://en.wikibooks.org/wiki/Algorithm_Implementation/Strings/Longest_common_substring#Python
> ), you'll see that the else-branch is wrongly indented (one level too deep).
> It belongs to the first if-comparison:
>
> if S1 ...
> M[x][y] ...
> if M[x][y] ...
> ...
> else: ...
Thanks, I was so careless and most important failure to give a deep
understanding.
>
>
>> if __name__=="__main__":
>>
>> a=open("atom-pair_4.txt","r").readline().strip()
>>
>> b=open("atom-pair_8.txt","r").readline().strip()
>>
>>
>> print(LongestCommonSubstring(LongestCommonSubstring(a,a),LongestCommonSubstring(b,b)))
>
> ^^^
> ??? What do you try to accomplish here ???
> You call "LongestCommonSubstring" with identical strings, thus the result
> must be the same string.
Yes, the results is the same string,
actually I want to remove the distractions of "," and as you noticed,
the blanks and single quotes between numbers and the square brackets
at the two terminal of the line.
a=open("atom-pair_4.txt","r").readline().strip()
read so many unnecessary and I have a trouble of removing those distractions.
> Why not
>
> print(LongestCommonSubstring(a, b))
>
> as you did the line below with "c" and "d"?
>
> Further more I think that your problems start with bad data files. In every
> file there is just one very long line which looks like a string
> representation of a list of two-digits strings. This complicates further
> processing because you have to deal with all the unnecessary commas, blanks
> and single quotes between your numbers and the square brackets at the
> beginning and the end of the line.
>
>
>> $ python3 LongestCommonSubstring.py
>> 2189
>> ['
>> ['82']
>>
>> The results are wrong.
>> c, d are the string from file atom-pair_4,txt, exactly the same as a,
>> d is the same as b.
>>
>> and even for (c,d) results are not correct, visually we can see some
>> similar groups, not mention the longest groups.
>
> And even if you use the correct function from wikibooks I can anticipate
> another problem :-)
> The implementation from wikibooks just returns the first common substring
> which it finds in the first string:
>
WikibooksLongestCommonSubstring("ABAB","BABA")
> 'ABA'
WikibooksLongestCommonSubstring("BABA", "ABAB")
> 'BAB'
>
> If there are more possible substrings with the same length (as in the
> example above) only the first one is returned.
You are right, I did not think of this parts before.
and actually the initiative wish was to find possible paths, I mean,
possible substrings, all possible substrings. not the longest one, but
at least bigger than 3.
>
> But in your example there are at least two different pathways (I've found
> three) which have the same length, as changing the order of the parameters
> will show you:
>
WikibooksLongestCommonSubstring(c, d)
> ['61', '70', '61']
WikibooksLongestCommonSubstring(d, c)
> ['83', '61', '83']
>
> Bye, Andreas
Thanks for your time,
Best regards,
>
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Re: [Tutor] longest common substring
On 2011-11-11 05:14, lina wrote:
def LongestCommonSubstring(S1, S2):
M = [[0]*(1+len(S2)) for i in xrange(1+len(S1))] ## creat 4*5 matrix
longest, x_longest = 0, 0
for x in xrange(1,1+len(S1)): ## read each row
for y in xrange(1,1+len(S2)): ## read each coloumn
if S1[x-1] == S2[y-1]:
M[x][y] = M[x-1][y-1]+1
if M[x][y]> longest:
longest = M[x][y]
x_longest = x
else:
M[x][y] = 0
return S1[x_longest-longest:x_longest]
That's still not the right version.
If you compare your version to the one at wikibooks (
http://en.wikibooks.org/wiki/Algorithm_Implementation/Strings/Longest_common_substring#Python
), you'll see that the else-branch is wrongly indented (one level too
deep). It belongs to the first if-comparison:
if S1 ...
M[x][y] ...
if M[x][y] ...
...
else: ...
if __name__=="__main__":
a=open("atom-pair_4.txt","r").readline().strip()
b=open("atom-pair_8.txt","r").readline().strip()
print(LongestCommonSubstring(LongestCommonSubstring(a,a),LongestCommonSubstring(b,b)))
^^^
??? What do you try to accomplish here ???
You call "LongestCommonSubstring" with identical strings, thus the
result must be the same string.
Why not
print(LongestCommonSubstring(a, b))
as you did the line below with "c" and "d"?
Further more I think that your problems start with bad data files. In
every file there is just one very long line which looks like a string
representation of a list of two-digits strings. This complicates further
processing because you have to deal with all the unnecessary commas,
blanks and single quotes between your numbers and the square brackets at
the beginning and the end of the line.
$ python3 LongestCommonSubstring.py
2189
['
['82']
The results are wrong.
c, d are the string from file atom-pair_4,txt, exactly the same as a,
d is the same as b.
and even for (c,d) results are not correct, visually we can see some
similar groups, not mention the longest groups.
And even if you use the correct function from wikibooks I can anticipate
another problem :-)
The implementation from wikibooks just returns the first common
substring which it finds in the first string:
>>> WikibooksLongestCommonSubstring("ABAB","BABA")
'ABA'
>>> WikibooksLongestCommonSubstring("BABA", "ABAB")
'BAB'
If there are more possible substrings with the same length (as in the
example above) only the first one is returned.
But in your example there are at least two different pathways (I've
found three) which have the same length, as changing the order of the
parameters will show you:
>>> WikibooksLongestCommonSubstring(c, d)
['61', '70', '61']
>>> WikibooksLongestCommonSubstring(d, c)
['83', '61', '83']
Bye, Andreas
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[Tutor] positional output
Thank you for your help on this. Now for "the rest of the story." I'm trying to build a script to parse IBM AIX DB2 DDL to line up the data types (it drives me crazy when the column data types are not lined up). For example, typical create table DDL might be hundreds of lines long but will look like this: -- -- table create DDL -- CREATE TABLE FRANK.TEST ( COLUMN1 DECIMAL(8), COLUMN2 CHAR(20), COLUMN3TIMESTAMP, COLUMN4 INTEGER, COLUMN5 DATE NOT NULL WITH DEFAULT, -- repeat for hundreds of columns ); COMMENT ON TABLE FRANK.TEST IS 'TEST TABLE'; This is just a small sample, there are many other possible lines, but I'm only concerned about the column lines like COLUMN1 through COLUMN5 above. I have a script on Windows that reads in the DDL file and writes out each line to a new file. What I'm doing is using the split() function to test for the presence of any DB2 standard data type, like CHAR, INTEGER, SMALINT, etc. If I find one I want to use positional output to make each like look like: COLUMN1DECIMAL(8), COLUMN2CHAR(20), COLUMN3TIMESTAMP, COLUMN4 INTEGER, COLUMN5 DATE NOT NULL WITH DEFAULT, where all the COLUMNs would be in column 1 of the output file, the data types would be in column 40, and the comma would be next. The problem is handling lines that have NOT NULL WITH DEFAULT at the end. The thing is there could be other valid DDL in that position, and there may or may not be a comma after the data type. What I want to do is just take anything after the datatype, which would be element(1) in the split() output, and just write it out. I thought I could use rsplit() to do this, but you can't put the output of split() in rsplit() - I tried. I need to do something like, after verifying that element(1) is a valid DB2 datatype, just take everything else on the line after it, which may be a single comma, or NOT NULL WITH DEFAULT, or something else, and place it on the output line to be written out. So, to reiterate: I'm trying to build a script to line up the data types in a create table DDL file. Splitting each line into individual space separated elements, then checking for a valid data type, the rebuilding the line positionally seems to be the way to go. If there's an easyier way to do it I'm all ears. I don't have my script available at the moment but I could send it if it would be helpful. -- Frank L. "Cranky Frankie" Palmeri, Guilderland, NY, USA Risible Riding Raconteur & Writer Don't sweat the petty things, and don't pet the sweaty things. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Okay, this time I tried doing a little research but no luck in solving this one.
On 2011/11/11 04:00 AM, Nathaniel Trujillo wrote: Okay, I typed in python -c "import sys; print sys.version" at the command prompt. I didn't see a prompt ending with %. Instead I saw a prompt ending with >. But here is the message I got. Microsoft Windows [Version 6.1.7600] Copyright (c) 2009 Microsoft Corporation. All rights reserved. C:\Users\net2010>python -c "import sys; print sys.version" 'python' is not recognized as an internal or external command, operable program or batch file. C:\Users\net2010> Thanks for the help. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor R-Click on My Computer -> Properties -> Advanced -> Environment Variables -> Under "System Variables" find PATH, select it, and click Edit -> Add your Python path to the end eg. c:\python27 (you will need to seperate it from all the other entries using a semi-colon, like c:\program files;c:\windows;c:\python27) -> Click OK about 3 times till you've closed all the windows -> Open a new Command Prompt and run python -c "import sys; print sys.version" -- Christian Witts Python Developer // ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Okay, this time I tried doing a little research but no luck in solving this one.
On 11 November 2011 at 02:00 Nathaniel Trujillo wrote:- > Okay, I typed in python -c "import sys; print sys.version" at the command > prompt. I didn't see a prompt ending with %. Instead I saw a prompt ending > with >. But here is the message I got. > > Microsoft Windows [Version 6.1.7600] > Copyright (c) 2009 Microsoft Corporation. All rights reserved. > C:\Users\net2010>python -c "import sys; print sys.version" > 'python' is not recognized as an internal or external command, > operable program or batch file. > C:\Users\net2010> This is normal with Python on Windows. The Python installer doesn't add the program directory to the PATH, so you have to include the full pathname to run Python from the command line, something like this:- C:\Python27\python -c "import sys; print sys.version" -- Michael This mail was sent via Mail-SeCure System. This footnote confirms that this email message has been scanned by PineApp Mail-SeCure for the presence of malicious code, vandals & computer viruses. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] The python implementation of the "class relationship".
On 11/11/11 02:39, Jerry Zhang wrote: Composition implementation: you may need to do 5 job with C++, but only 2 job with python, the other 3 job is done by python implicitly. association implementation: You need 3 job with C++, but 1 with python. it seems python's object's lifecycle handling has reached this level, all you should do is just "associating and de-association". I have no idea what you mean by that. What kind of "job" are you talking about? Code_Zero. 1 job(by you) + 4(by python) does NOT work. Code_one. 2 job(by you) + 3(by python) works. That is the best one. Code_two. 3 job( by you) + 2 (by python) works too, Code_three. 4 job(by you) + 1(by python) works too. Since i am not familiar with python yet, my code most likely would gets into Code_two or Code_three(Code_Zero is also possible for new guys like me), though they also work, they are bad code. Again, I don't understand your references to Code_one, Code_two etc? -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
