[algogeeks] Re: output
Printf will print one value per item in the format string.
If you don't supply that many, it will look at the undefined memory where
that value should have been, so you will get gibberish.
Don
On Friday, December 6, 2013 9:17:36 AM UTC-5, segfault wrote:
Hi All,
I'm not able to get output of following c program :
#includestdio.h
main()
{
int a[] ={ 1,2,3,4,5,6,7};
char c[] = {'a','x','h','o','k'};
//printf(%u %u\n, a[3], a[0]); line 6
printf(%d %d %d %d \n, (a[3]-a[0]));
}
If line 6 is commented, output :
3 1562814827 1869117537 0
Confusion : why is there 4 output? (a[3]-a[0]) should give only one.
if line 6 is not commented, output :
1554221244 1554221232
3 1554221232 1309214001 64
Can anybody please explain why/how these outputs are coming?
Thanks,
Pawan.
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Re: [algogeeks] Re: Output
thanks
@Dave n Rushiraj
I think I have got the solution . 15-1 will be evaluated like 1(5-1).
it will be 16. Now the negation of 0001 will be 1110 and
this will be my mask.
so
for 56 -- 000111000 111...0 = 000...101000 = 40.
for 64 -- 000...100 111...0 = 000...100 = 64
for 127-- 000... 111 111...0 = 000...110 = 111
I hope this is correct .
Please correct me if I am wrong.
Thanks,
Rajesh
On Sat, Nov 24, 2012 at 8:36 PM, Dave dave_and_da...@juno.com wrote:
@Rajesh: In binary, mask = 111...10 (with 4-byte ints, this is 27
1-bits followed by 5 0-bits). The logical product of num with mask zeros
out the low order 5 bits while retaining the high order 27 bits. Thus, res
is num truncated to the largest multiple of 32 that does not exceed num. 56
= (1*32 + 24) goes to 1*32 = 32, 64 (=2*32 + 0) stays at 2*32 = 64, and 127
(=3*32 + 31) goes to 3*32 = 96.
Dave
On Saturday, November 24, 2012 2:45:24 AM UTC-6, rajesh pandey wrote:
void dosomething(int num)
{
int mask=~(15-1);
int res=nummask;
printf(%d,res);
}
int main()
{
dosomething(56);
dosomething(64);
dosomething(127);
return 0;
}
please explain the logic behind the output.
Thanks,
Rajesh
--
--
Re: [algogeeks] Re: Output
@pandey : here you are shifting 1 to right by 4 bit (as rushiraj said
correctly)
which becomes 0.1, then you are doing negation which becomes
11...0(mask)
now do you and operation
mask 56 = 40
mask 64 = 64
mask 127 = 111
you can notice that only 5th lsb (effective value 16) is zero which is
present in 56 and 127 but not in 64
so 64 remains the same but 56 and 127 got reduced by 16.
On Sat, Nov 24, 2012 at 8:36 PM, Dave dave_and_da...@juno.com wrote:
@Rajesh: In binary, mask = 111...10 (with 4-byte ints, this is 27
1-bits followed by 5 0-bits). The logical product of num with mask zeros
out the low order 5 bits while retaining the high order 27 bits. Thus, res
is num truncated to the largest multiple of 32 that does not exceed num. 56
= (1*32 + 24) goes to 1*32 = 32, 64 (=2*32 + 0) stays at 2*32 = 64, and 127
(=3*32 + 31) goes to 3*32 = 96.
Dave
On Saturday, November 24, 2012 2:45:24 AM UTC-6, rajesh pandey wrote:
void dosomething(int num)
{
int mask=~(15-1);
int res=nummask;
printf(%d,res);
}
int main()
{
dosomething(56);
dosomething(64);
dosomething(127);
return 0;
}
please explain the logic behind the output.
Thanks,
Rajesh
--
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Re: [algogeeks] Re: Output
sorry its left shift.. one mistake.. other than this ans is correct.. i have
done left shift on 1 by 4 bits that why result became ~(0.1)
ignore the right shift i have mentioned..
On Sun, Nov 25, 2012 at 4:48 PM, Rahul Kumar Patle
patlerahulku...@gmail.com wrote:
@pandey : here you are shifting 1 to right by 4 bit (as rushiraj said
correctly)
which becomes 0.1, then you are doing negation which becomes
11...0(mask)
now do you and operation
mask 56 = 40
mask 64 = 64
mask 127 = 111
you can notice that only 5th lsb (effective value 16) is zero which is
present in 56 and 127 but not in 64
so 64 remains the same but 56 and 127 got reduced by 16.
On Sat, Nov 24, 2012 at 8:36 PM, Dave dave_and_da...@juno.com wrote:
@Rajesh: In binary, mask = 111...10 (with 4-byte ints, this is 27
1-bits followed by 5 0-bits). The logical product of num with mask zeros
out the low order 5 bits while retaining the high order 27 bits. Thus, res
is num truncated to the largest multiple of 32 that does not exceed num. 56
= (1*32 + 24) goes to 1*32 = 32, 64 (=2*32 + 0) stays at 2*32 = 64, and 127
(=3*32 + 31) goes to 3*32 = 96.
Dave
On Saturday, November 24, 2012 2:45:24 AM UTC-6, rajesh pandey wrote:
void dosomething(int num)
{
int mask=~(15-1);
int res=nummask;
printf(%d,res);
}
int main()
{
dosomething(56);
dosomething(64);
dosomething(127);
return 0;
}
please explain the logic behind the output.
Thanks,
Rajesh
--
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Thanks and Regards:
Rahul Kumar Patle
M.Tech, School of Information Technology
Indian Institute of Technology, Kharagpur-721302,
Indiahttp://www.iitkgp.ac.in/
Mobile No: +91-8798049298, +91-9424738542
Alternate Email: rahulkumarpa...@hotmail.com
[image:
Linkedin]http://www.linkedin.com/profile/view?id=106245716trk=tab_pro
[image: Twitter] https://twitter.com/rahulkumarpatle
https://www.facebook.com/rkpatle
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Thanks and Regards:
Rahul Kumar Patle
M.Tech, School of Information Technology
Indian Institute of Technology, Kharagpur-721302,
Indiahttp://www.iitkgp.ac.in/
Mobile No: +91-8798049298, +91-9424738542
Alternate Email: rahulkumarpa...@hotmail.com
[image: Linkedin]http://www.linkedin.com/profile/view?id=106245716trk=tab_pro
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https://www.facebook.com/rkpatle
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[algogeeks] Re: Output
@Rajesh: In binary, mask = 111...10 (with 4-byte ints, this is 27
1-bits followed by 5 0-bits). The logical product of num with mask zeros
out the low order 5 bits while retaining the high order 27 bits. Thus, res
is num truncated to the largest multiple of 32 that does not exceed num. 56
= (1*32 + 24) goes to 1*32 = 32, 64 (=2*32 + 0) stays at 2*32 = 64, and 127
(=3*32 + 31) goes to 3*32 = 96.
Dave
On Saturday, November 24, 2012 2:45:24 AM UTC-6, rajesh pandey wrote:
void dosomething(int num)
{
int mask=~(15-1);
int res=nummask;
printf(%d,res);
}
int main()
{
dosomething(56);
dosomething(64);
dosomething(127);
return 0;
}
please explain the logic behind the output.
Thanks,
Rajesh
--
[algogeeks] Re: output
for the first o/p qs
as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
save the base address and den let p2 move forward with p1
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
char *save;
save = (char *)malloc(20);
save = p2;
if(p2==NULL)
cout\n NOT ENOUGH SPACE;
else
{
while(*p2++=*p1++);
printf(%s\n,save);
}
for the second qs o/p = 25
cz post incr means first use den incr thererfore 5*5
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Re: [algogeeks] Re: output
for the first, p2 has moved beyond null character, so do char *c=p and
then print string for c.
for second , since the same object is modified more than once between
two sequence points, so it gives compiler dependent answer.if it wud
have been i++||i++ , then the answer would have been defined as || is
a sequence point.
On Wed, Jul 25, 2012 at 8:42 PM, deepikaanand swinyanand...@gmail.com wrote:
for the first o/p qs
as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
save the base address and den let p2 move forward with p1
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
char *save;
save = (char *)malloc(20);
save = p2;
if(p2==NULL)
cout\n NOT ENOUGH SPACE;
else
{
while(*p2++=*p1++);
printf(%s\n,save);
}
for the second qs o/p = 25
cz post incr means first use den incr thererfore 5*5
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[algogeeks] Re: output
On Wednesday, 25 July 2012 20:20:02 UTC+5:30, jatin wrote:
anybdy has basic trie implementation (insertion and printing) ?
o/p
1)
main()
{
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf(%s\n,p2);
} ...it's giving me empty string
2)
i=5;
printf(%d,i++ * i++);
o/p and also tell the reason?
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[algogeeks] Re: output
For the first o/p even though i save it like u have done then too it's
showing me an empty string .
for 2nd as Vindya has stated it should give me error but my compiler is
showing me 30 as it's output(the ans shd be 25 if not error) ?
On Wednesday, 25 July 2012 20:42:56 UTC+5:30, deepikaanand wrote:
for the first o/p qs
as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
save the base address and den let p2 move forward with p1
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
char *save;
save = (char *)malloc(20);
save = p2;
if(p2==NULL)
cout\n NOT ENOUGH SPACE;
else
{
while(*p2++=*p1++);
printf(%s\n,save);
}
for the second qs o/p = 25
cz post incr means first use den incr thererfore 5*5
On Wednesday, 25 July 2012 20:42:56 UTC+5:30, deepikaanand wrote:
for the first o/p qs
as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
save the base address and den let p2 move forward with p1
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
char *save;
save = (char *)malloc(20);
save = p2;
if(p2==NULL)
cout\n NOT ENOUGH SPACE;
else
{
while(*p2++=*p1++);
printf(%s\n,save);
}
for the second qs o/p = 25
cz post incr means first use den incr thererfore 5*5
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[algogeeks] Re: output
On Wednesday, 25 July 2012 20:59:47 UTC+5:30, jatin wrote:
For the first o/p even though i save it like u have done then too it's
showing me an empty string .
for 2nd as Vindya has stated it should give me error but my compiler is
showing me 30 as it's output(the ans shd be 25 if not error) ?
ahh..ther's sumthng wrong with my compiler .. wen am running it online it's
givng me the correct answ.
On Wednesday, 25 July 2012 20:42:56 UTC+5:30, deepikaanand wrote:
for the first o/p qs
as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
save the base address and den let p2 move forward with p1
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
char *save;
save = (char *)malloc(20);
save = p2;
if(p2==NULL)
cout\n NOT ENOUGH SPACE;
else
{
while(*p2++=*p1++);
printf(%s\n,save);
}
for the second qs o/p = 25
cz post incr means first use den incr thererfore 5*5
On Wednesday, 25 July 2012 20:42:56 UTC+5:30, deepikaanand wrote:
for the first o/p qs
as p1 is moving towards the NULL('\0') character so is p2...to avoid dis
save the base address and den let p2 move forward with p1
char *p1=Name;
char *p2;
p2=(char *)malloc(20);
char *save;
save = (char *)malloc(20);
save = p2;
if(p2==NULL)
cout\n NOT ENOUGH SPACE;
else
{
while(*p2++=*p1++);
printf(%s\n,save);
}
for the second qs o/p = 25
cz post incr means first use den incr thererfore 5*5
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[algogeeks] Re: output
@ jatin then there is something wrong I executed d same prog which I have pasted here...it was giving me the correct answer and for the second qs has no absolute answer it depends on compiler -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/TOSg6xbES24J. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: output
Trie ??if u have it to mail kardio... On Wednesday, 25 July 2012 21:10:55 UTC+5:30, deepikaanand wrote: @ jatin then there is something wrong I executed d same prog which I have pasted here...it was giving me the correct answer and for the second qs has no absolute answer it depends on compiler -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/u5wkXT6ZDHIJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output
Well Guys, M here just to show wats hpning.. Have your own views.. 1 Everything is right till While loop.. I mean p1 pointing to the heap of the address of the String Name , P1 getting 20 bytes of memory chunk and so on.. So here we go now. As this Stupid looking while is culprit here as it is coping the content of one pointer to other as well as moving itself forward. So What happened when While exits, is p1 points to NULL and is copied successfully to p1 but due to post incrementation of p1 and p2 both are momentary lost and wen't beyond the '\0' character.. So when U print it it goes printing all the rest of 20 character bytes losing it front values. hope U guys have u r clear picture now. 2 Is compiler dependent but can be kinda predictable. Reason:- 1 STL says the two point rule as someone stated above. Coz they feared if this rule does not followed that big chaos might happen but here its simple and kinda predictable. 2 Anyone who have worked or know a bit of Embedded can easily tell how the hardware operated on this equation. Prem On Wed, Jul 25, 2012 at 9:10 PM, deepikaanand swinyanand...@gmail.comwrote: @ jatin then there is something wrong I executed d same prog which I have pasted here...it was giving me the correct answer and for the second qs has no absolute answer it depends on compiler -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/TOSg6xbES24J. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: output
sent... On Wednesday, July 25, 2012 9:18:46 PM UTC+5:30, jatin wrote: Trie ??if u have it to mail kardio... On Wednesday, 25 July 2012 21:10:55 UTC+5:30, deepikaanand wrote: @ jatin then there is something wrong I executed d same prog which I have pasted here...it was giving me the correct answer and for the second qs has no absolute answer it depends on compiler On Wednesday, July 25, 2012 9:18:46 PM UTC+5:30, jatin wrote: Trie ??if u have it to mail kardio... On Wednesday, 25 July 2012 21:10:55 UTC+5:30, deepikaanand wrote: @ jatin then there is something wrong I executed d same prog which I have pasted here...it was giving me the correct answer and for the second qs has no absolute answer it depends on compiler -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/fsXZTCbPuIgJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: output expalnation?
junk value cz b=6 will not get executed -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output expalnation?
Compilation error. Definition of b is skipped by Switch statement. so 'b' not declared/defined error will occur. Correct me if m wrong. Sanju :) On Mon, Sep 26, 2011 at 6:38 PM, deepikaanand swinyanand...@gmail.comwrote: junk value cz b=6 will not get executed -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Output?? Why??
upto null charchter.. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Output?? Why??
There is no null character in this string,as its length is 5 and the number of characters is 5(Geeks),and printf(%s,arr) should output the string till the null character On Thu, Aug 18, 2011 at 2:40 AM, bihari kumarvive...@gmail.com wrote: upto null charchter.. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Ayush -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Output?? Why??
i modified the code a lil bit
#includestdio.h
#includeconio.h
int main()
{ clrscr();
char arr[5] = geeks;
printf(%s\n, arr);
char b[1]=t;
printf(%s\n,b);
getchar();
return 0;
}
the output in dis case is somewhat diff..cud someone explain...
On Thu, Aug 18, 2011 at 3:28 AM, Ayush Kapoor ayush21011...@gmail.comwrote:
There is no null character in this string,as its length is 5 and the number
of characters is 5(Geeks),and printf(%s,arr) should output the string till
the null character
On Thu, Aug 18, 2011 at 2:40 AM, bihari kumarvive...@gmail.com wrote:
upto null charchter..
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Re: [algogeeks] Re: Output?? Why??
@payal: im getting compile time errors fr both the strings...
Chk dis :http://ideone.com/BRbkf
On Thu, Aug 18, 2011 at 4:12 AM, payal gupta gpt.pa...@gmail.com wrote:
i modified the code a lil bit
#includestdio.h
#includeconio.h
int main()
{ clrscr();
char arr[5] = geeks;
printf(%s\n, arr);
char b[1]=t;
printf(%s\n,b);
getchar();
return 0;
}
the output in dis case is somewhat diff..cud someone explain...
On Thu, Aug 18, 2011 at 3:28 AM, Ayush Kapoor ayush21011...@gmail.comwrote:
There is no null character in this string,as its length is 5 and the
number of characters is 5(Geeks),and printf(%s,arr) should output the
string till the null character
On Thu, Aug 18, 2011 at 2:40 AM, bihari kumarvive...@gmail.com wrote:
upto null charchter..
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Re: [algogeeks] Re: Output?? Why??
@Aditi: That's because you haven't changed the language to 'C' (while
working on ideone. It doesn't give an error in C)
On Thu, Aug 18, 2011 at 8:47 AM, aditi garg aditi.garg.6...@gmail.comwrote:
@payal: im getting compile time errors fr both the strings...
Chk dis :http://ideone.com/BRbkf
On Thu, Aug 18, 2011 at 4:12 AM, payal gupta gpt.pa...@gmail.com wrote:
i modified the code a lil bit
#includestdio.h
#includeconio.h
int main()
{ clrscr();
char arr[5] = geeks;
printf(%s\n, arr);
char b[1]=t;
printf(%s\n,b);
getchar();
return 0;
}
the output in dis case is somewhat diff..cud someone explain...
On Thu, Aug 18, 2011 at 3:28 AM, Ayush Kapoor ayush21011...@gmail.comwrote:
There is no null character in this string,as its length is 5 and the
number of characters is 5(Geeks),and printf(%s,arr) should output the
string till the null character
On Thu, Aug 18, 2011 at 2:40 AM, bihari kumarvive...@gmail.com wrote:
upto null charchter..
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Re: [algogeeks] Re: Output?? Why??
Thats new..
Its not working in C++, where as in C it works like a charm.
On 18 August 2011 08:57, vartika aggarwal vartika.aggarwa...@gmail.comwrote:
@Aditi: That's because you haven't changed the language to 'C' (while
working on ideone. It doesn't give an error in C)
On Thu, Aug 18, 2011 at 8:47 AM, aditi garg aditi.garg.6...@gmail.comwrote:
@payal: im getting compile time errors fr both the strings...
Chk dis :http://ideone.com/BRbkf
On Thu, Aug 18, 2011 at 4:12 AM, payal gupta gpt.pa...@gmail.com wrote:
i modified the code a lil bit
#includestdio.h
#includeconio.h
int main()
{ clrscr();
char arr[5] = geeks;
printf(%s\n, arr);
char b[1]=t;
printf(%s\n,b);
getchar();
return 0;
}
the output in dis case is somewhat diff..cud someone explain...
On Thu, Aug 18, 2011 at 3:28 AM, Ayush Kapoor
ayush21011...@gmail.comwrote:
There is no null character in this string,as its length is 5 and the
number of characters is 5(Geeks),and printf(%s,arr) should output the
string till the null character
On Thu, Aug 18, 2011 at 2:40 AM, bihari kumarvive...@gmail.com wrote:
upto null charchter..
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NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
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Re: [algogeeks] Re: Output?? Why??
Is it that there is no bounds checking in C while there is in C++ ?
On Thu, Aug 18, 2011 at 9:27 AM, Dipankar Patro dip10c...@gmail.com wrote:
Thats new..
Its not working in C++, where as in C it works like a charm.
On 18 August 2011 08:57, vartika aggarwal
vartika.aggarwa...@gmail.comwrote:
@Aditi: That's because you haven't changed the language to 'C' (while
working on ideone. It doesn't give an error in C)
On Thu, Aug 18, 2011 at 8:47 AM, aditi garg aditi.garg.6...@gmail.comwrote:
@payal: im getting compile time errors fr both the strings...
Chk dis :http://ideone.com/BRbkf
On Thu, Aug 18, 2011 at 4:12 AM, payal gupta gpt.pa...@gmail.comwrote:
i modified the code a lil bit
#includestdio.h
#includeconio.h
int main()
{ clrscr();
char arr[5] = geeks;
printf(%s\n, arr);
char b[1]=t;
printf(%s\n,b);
getchar();
return 0;
}
the output in dis case is somewhat diff..cud someone explain...
On Thu, Aug 18, 2011 at 3:28 AM, Ayush Kapoor
ayush21011...@gmail.comwrote:
There is no null character in this string,as its length is 5 and the
number of characters is 5(Geeks),and printf(%s,arr) should output the
string till the null character
On Thu, Aug 18, 2011 at 2:40 AM, bihari kumarvive...@gmail.comwrote:
upto null charchter..
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NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
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Re: [algogeeks] Re: Output?? Why??
Interesting thing I came across:
http://stackoverflow.com/questions/1239938/c-accesses-an-array-out-of-bounds-gives-no-error-why
On 18 August 2011 09:39, vartika aggarwal vartika.aggarwa...@gmail.comwrote:
Is it that there is no bounds checking in C while there is in C++ ?
On Thu, Aug 18, 2011 at 9:27 AM, Dipankar Patro dip10c...@gmail.comwrote:
Thats new..
Its not working in C++, where as in C it works like a charm.
On 18 August 2011 08:57, vartika aggarwal vartika.aggarwa...@gmail.com
wrote:
@Aditi: That's because you haven't changed the language to 'C' (while
working on ideone. It doesn't give an error in C)
On Thu, Aug 18, 2011 at 8:47 AM, aditi garg
aditi.garg.6...@gmail.comwrote:
@payal: im getting compile time errors fr both the strings...
Chk dis :http://ideone.com/BRbkf
On Thu, Aug 18, 2011 at 4:12 AM, payal gupta gpt.pa...@gmail.comwrote:
i modified the code a lil bit
#includestdio.h
#includeconio.h
int main()
{ clrscr();
char arr[5] = geeks;
printf(%s\n, arr);
char b[1]=t;
printf(%s\n,b);
getchar();
return 0;
}
the output in dis case is somewhat diff..cud someone explain...
On Thu, Aug 18, 2011 at 3:28 AM, Ayush Kapoor ayush21011...@gmail.com
wrote:
There is no null character in this string,as its length is 5 and the
number of characters is 5(Geeks),and printf(%s,arr) should output the
string till the null character
On Thu, Aug 18, 2011 at 2:40 AM, bihari kumarvive...@gmail.comwrote:
upto null charchter..
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NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
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Re: [algogeeks] Re: output???
Ok thats a diff thing but what i posted is somewhat different actually what happen is that .5 can be represented completely in binary form and the same case with 1.0 and .25 , .125 also but when we talk about .7 then it cant be represented in binary precisely even we upgrade it to double. thats why a==.5? works but not c==.7? On Sat, Aug 6, 2011 at 10:40 AM, saurabh singh saurab...@gmail.com wrote: a double has a higher precision than float i.e. it has larger number of bits for the mantisa part. when float is compared to double it is promoted to double by filling remaining bits in mantissa with 0. consider this code http://ideone.com/y1Ahu http://ideone.com/y1AhuIts equal bcoz the higher bits will be 0 for both double and float. similar result occurs for 0.25 0.75 0.10 etc,. On Sat, Aug 6, 2011 at 10:26 AM, sagar pareek sagarpar...@gmail.comwrote: @saurabh what? i didnt get you On Sat, Aug 6, 2011 at 10:22 AM, saurabh singh saurab...@gmail.comwrote: IEEE notation.. they appear to be the same but they are not same..0.5d has higher precision that does not necessarily means its larger.. On Sat, Aug 6, 2011 at 10:20 AM, sagar pareek sagarpar...@gmail.comwrote: see what piyush posted On Sat, Aug 6, 2011 at 4:35 AM, Shashank Jain shashan...@gmail.comwrote: sagar - i dint get u, d code thing! Shashank Jain IIIrd year Computer Engineering Delhi College of Engineering On Sat, Aug 6, 2011 at 2:31 AM, sagar pareek sagarpar...@gmail.comwrote: yup exactly On Sat, Aug 6, 2011 at 1:51 AM, Piyush Kapoor pkjee2...@gmail.comwrote: I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to
[algogeeks] Re: output???
its due to precision limit of double is larger than float, and by default real values are stored as double so constant 0.7 is stored more accurately(8 bytes) that float a=0.7 (4 bytes). and when comparing the two float is typecasted into double and so the ramaining bits are padded with 0 so 0.7 a; -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
@vikas first read what i wrote On Sat, Aug 6, 2011 at 12:59 AM, vikash vikash.ckiiit...@gmail.com wrote: its due to precision limit of double is larger than float, and by default real values are stored as double so constant 0.7 is stored more accurately(8 bytes) that float a=0.7 (4 bytes). and when comparing the two float is typecasted into double and so the ramaining bits are padded with 0 so 0.7 a; -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
yup exactly On Sat, Aug 6, 2011 at 1:51 AM, Piyush Kapoor pkjee2...@gmail.com wrote: I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
sagar - i dint get u, d code thing! Shashank Jain IIIrd year Computer Engineering Delhi College of Engineering On Sat, Aug 6, 2011 at 2:31 AM, sagar pareek sagarpar...@gmail.com wrote: yup exactly On Sat, Aug 6, 2011 at 1:51 AM, Piyush Kapoor pkjee2...@gmail.com wrote: I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
see what piyush posted On Sat, Aug 6, 2011 at 4:35 AM, Shashank Jain shashan...@gmail.com wrote: sagar - i dint get u, d code thing! Shashank Jain IIIrd year Computer Engineering Delhi College of Engineering On Sat, Aug 6, 2011 at 2:31 AM, sagar pareek sagarpar...@gmail.comwrote: yup exactly On Sat, Aug 6, 2011 at 1:51 AM, Piyush Kapoor pkjee2...@gmail.comwrote: I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
IEEE notation.. they appear to be the same but they are not same..0.5d has higher precision that does not necessarily means its larger.. On Sat, Aug 6, 2011 at 10:20 AM, sagar pareek sagarpar...@gmail.com wrote: see what piyush posted On Sat, Aug 6, 2011 at 4:35 AM, Shashank Jain shashan...@gmail.comwrote: sagar - i dint get u, d code thing! Shashank Jain IIIrd year Computer Engineering Delhi College of Engineering On Sat, Aug 6, 2011 at 2:31 AM, sagar pareek sagarpar...@gmail.comwrote: yup exactly On Sat, Aug 6, 2011 at 1:51 AM, Piyush Kapoor pkjee2...@gmail.comwrote: I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
@saurabh what? i didnt get you On Sat, Aug 6, 2011 at 10:22 AM, saurabh singh saurab...@gmail.com wrote: IEEE notation.. they appear to be the same but they are not same..0.5d has higher precision that does not necessarily means its larger.. On Sat, Aug 6, 2011 at 10:20 AM, sagar pareek sagarpar...@gmail.comwrote: see what piyush posted On Sat, Aug 6, 2011 at 4:35 AM, Shashank Jain shashan...@gmail.comwrote: sagar - i dint get u, d code thing! Shashank Jain IIIrd year Computer Engineering Delhi College of Engineering On Sat, Aug 6, 2011 at 2:31 AM, sagar pareek sagarpar...@gmail.comwrote: yup exactly On Sat, Aug 6, 2011 at 1:51 AM, Piyush Kapoor pkjee2...@gmail.comwrote: I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: output???
a double has a higher precision than float i.e. it has larger number of bits for the mantisa part. when float is compared to double it is promoted to double by filling remaining bits in mantissa with 0. consider this code http://ideone.com/y1Ahu http://ideone.com/y1AhuIts equal bcoz the higher bits will be 0 for both double and float. similar result occurs for 0.25 0.75 0.10 etc,. On Sat, Aug 6, 2011 at 10:26 AM, sagar pareek sagarpar...@gmail.com wrote: @saurabh what? i didnt get you On Sat, Aug 6, 2011 at 10:22 AM, saurabh singh saurab...@gmail.comwrote: IEEE notation.. they appear to be the same but they are not same..0.5d has higher precision that does not necessarily means its larger.. On Sat, Aug 6, 2011 at 10:20 AM, sagar pareek sagarpar...@gmail.comwrote: see what piyush posted On Sat, Aug 6, 2011 at 4:35 AM, Shashank Jain shashan...@gmail.comwrote: sagar - i dint get u, d code thing! Shashank Jain IIIrd year Computer Engineering Delhi College of Engineering On Sat, Aug 6, 2011 at 2:31 AM, sagar pareek sagarpar...@gmail.comwrote: yup exactly On Sat, Aug 6, 2011 at 1:51 AM, Piyush Kapoor pkjee2...@gmail.comwrote: I think it is because the numbers like 0.7 do not have a exact binary representation,so they are not exactly represented in float,while the constant is internally implemented as double.,Read this:: http://www.topcoder.com/tc?module=Staticd1=tutorialsd2=integersReals -- *Regards,* *Piyush Kapoor,* *2nd year,CSE IT-BHU* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: OUTPUT
p is a pointer to an array of 4 ints.
sizeof(p) gives the size of the pointer which is an int and sizeof(*p)
gives the size of the array it points (4*4=16)
On Jul 27, 3:44 pm, Kamakshii Aggarwal kamakshi...@gmail.com wrote:
#includestdio.h
# define MAXROW 3
#define MAXCOL 4
int main()
{
int (*p)[MAXCOL];
p=(int(*)[MAXCOL])malloc(MAXROW*sizeof(*p));
printf(%d %d,sizeof(p),sizeof(*p));
system(pause);
return 0;
}
THE O/P IS 4 16.
I am not getting the reason.plss help
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Re: [algogeeks] Re: OUTPUT
thanks ankit and ramya..:)
On Wed, Jul 27, 2011 at 5:42 PM, Ankit ankitchaudhar...@gmail.com wrote:
p is a pointer to an array of 4 ints.
sizeof(p) gives the size of the pointer which is an int and sizeof(*p)
gives the size of the array it points (4*4=16)
On Jul 27, 3:44 pm, Kamakshii Aggarwal kamakshi...@gmail.com wrote:
#includestdio.h
# define MAXROW 3
#define MAXCOL 4
int main()
{
int (*p)[MAXCOL];
p=(int(*)[MAXCOL])malloc(MAXROW*sizeof(*p));
printf(%d %d,sizeof(p),sizeof(*p));
system(pause);
return 0;
}
THE O/P IS 4 16.
I am not getting the reason.plss help
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kamakshi...@gmail.com
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Re: [algogeeks] Re: OUTPUT
one more question.
how to dynamically allocate memory for int *a[3]; ?
On Wed, Jul 27, 2011 at 5:57 PM, Kamakshii Aggarwal
kamakshi...@gmail.comwrote:
thanks ankit and ramya..:)
On Wed, Jul 27, 2011 at 5:42 PM, Ankit ankitchaudhar...@gmail.com wrote:
p is a pointer to an array of 4 ints.
sizeof(p) gives the size of the pointer which is an int and sizeof(*p)
gives the size of the array it points (4*4=16)
On Jul 27, 3:44 pm, Kamakshii Aggarwal kamakshi...@gmail.com wrote:
#includestdio.h
# define MAXROW 3
#define MAXCOL 4
int main()
{
int (*p)[MAXCOL];
p=(int(*)[MAXCOL])malloc(MAXROW*sizeof(*p));
printf(%d %d,sizeof(p),sizeof(*p));
system(pause);
return 0;
}
THE O/P IS 4 16.
I am not getting the reason.plss help
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Kamakshi
kamakshi...@gmail.com
--
Regards,
Kamakshi
kamakshi...@gmail.com
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Re: [algogeeks] Re: OUTPUT
int *a[3]; a= (int *[3]) malloc( 3*sizeof(*a)); Regards Ramya -- *Try to learn something about everything and everything about something* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: OUTPUT
what do you exactly mean by (int *[3]) ? On Wed, Jul 27, 2011 at 6:27 PM, ramya reddy rmy.re...@gmail.com wrote: int *a[3]; a= (int *[3]) malloc( 3*sizeof(*a)); Regards Ramya -- *Try to learn something about everything and everything about something* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Ankur Khurana Computer Science Netaji Subhas Institute Of Technology Delhi. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: OUTPUT
int * [3] represents that 'a' is a integer pointer array of size 3. -- Regards Ramya * * *Try to learn something about everything and everything about something* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: OUTPUT
I believe the method written is incorrect, it didnt work for me i guess this is the right way...worked for me: int **p; p=malloc(3*sizeof(int *)); -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/ATGevOaqMbUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: OUTPUT
i am not getting any of the ways..can u explain? On Wed, Jul 27, 2011 at 9:06 PM, Abhinav Arora abhinavdgr8b...@gmail.comwrote: I believe the method written is incorrect, it didnt work for me i guess this is the right way...worked for me: int **p; p=malloc(3*sizeof(int *)); -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/ATGevOaqMbUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Kamakshi kamakshi...@gmail.com -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: OUTPUT
Hmm, I don't get the question. how to dynamically allocate memory for int *a[3]; ? What do you mean by allocating memory for int *a[3]; Can you explain in some more details what exactly you want to do On Jul 27, 8:39 pm, Kamakshii Aggarwal kamakshi...@gmail.com wrote: i am not getting any of the ways..can u explain? On Wed, Jul 27, 2011 at 9:06 PM, Abhinav Arora abhinavdgr8b...@gmail.comwrote: I believe the method written is incorrect, it didnt work for me i guess this is the right way...worked for me: int **p; p=malloc(3*sizeof(int *)); -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/ATGevOaqMbUJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Kamakshi kamakshi...@gmail.com -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: OUTPUT
Look we wish to allocate memory for an array of 3 integer pointers.
so when we do dynamic allocation we always store the result in a pointer to
the required data type.
for example if you wish to dynamically allocate int arr[3[]
u will write :
int *p=malloc(3*sizeof(int));
So now when you do it for an array of integer pointers the result of malloc
should point to the first element of the dynamically allocated array. The
elements of the array are pointers hence the memory allocated will be saved
in a pointer that will correspond to the pointer to the first element. Since
the elements are pointers so the result of malloc will be saved to a pointer
to a pointer.
My sample program which i compiled in Dev C++ is as follows :
#includestdio.h
#includeconio.h
main()
{
int a,b,c;
int **p;
p=malloc(3*sizeof(int *));
a=b=c=1;
p[0]=a;
p[1]=b;
p[2]=c;
printf(%d %d %d,*p[0],*p[1],*p[2]);
getch();
}
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Re: [algogeeks] Re: OUTPUT
@abhinav:thanks.:)
On Wed, Jul 27, 2011 at 9:23 PM, Abhinav Arora abhinavdgr8b...@gmail.comwrote:
Look we wish to allocate memory for an array of 3 integer pointers.
so when we do dynamic allocation we always store the result in a pointer to
the required data type.
for example if you wish to dynamically allocate int arr[3[]
u will write :
int *p=malloc(3*sizeof(int));
So now when you do it for an array of integer pointers the result of malloc
should point to the first element of the dynamically allocated array. The
elements of the array are pointers hence the memory allocated will be saved
in a pointer that will correspond to the pointer to the first element. Since
the elements are pointers so the result of malloc will be saved to a pointer
to a pointer.
My sample program which i compiled in Dev C++ is as follows :
#includestdio.h
#includeconio.h
main()
{
int a,b,c;
int **p;
p=malloc(3*sizeof(int *));
a=b=c=1;
p[0]=a;
p[1]=b;
p[2]=c;
printf(%d %d %d,*p[0],*p[1],*p[2]);
getch();
}
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[algogeeks] Re: output
Hi!
The overall logic is that u should know the actual memory location
where the data is to be stored or have a reference to it,in ur case
a *a1 it is just a pointer variable .
and this pointer is not pointing to the location where the new object
would be allocated,so it is passed just as
a pointer variable to the function
f(a *b)
where this variable is overwritten by the ,actual address where the
object is being allocated through new a().
and in ur main ,the value of the pointer variable is still not
known,it just random ,that's why u are getting output as something
garbage.
passing the address of the pointer is allready being discussed,
but in other method u can just pass the address of the new object to
the calling function that will tell ur main(),that what is the actual
location of the object;and this time
it is not garbage.
a* f(a * b)
{
b = new a();
b-set(5);
return b;
}
int main()
{
a *a1;
a1=f(a1);
coutx = a1-get();
return 0;
}
On Jul 21, 5:10 pm, Saurabh saurabh24...@gmail.com wrote:
Can any one explain why the following program not giving the correct output.
#include iostream
using namespace std;
class a
{
int x;
public:
void set(int y)
{
x=y;
}
int get()
{
return x;
}
};
void f(a * b)
{
b = new a();
b-set(5);}
int main()
{
a *a1;
f(a1);
coutx = a1-get();
return 0;
}
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Regards
Saurabh
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[algogeeks] Re: Output
Yaa even if it is 8 bytes long . Compiler will treat the value 10 as 8
bytes only . It should be able to assign it to the pointer of the same
size (type) ..
Try to free the dynamically allocated memory just before return 0
and tell me the result after compilation . Try this :-
int main()
{
int* p;
p = (int*)malloc(sizeof(int));
*p = 10;
free(p); /* Try This */
return 0;
}
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Re: [algogeeks] Re: Output
http://groups.google.com/group/programming-puzzles/browse_thread/thread/4fecd0d904624a0d
this will clarify all doubts :)
On Wed, Jul 20, 2011 at 8:52 PM, SAMMM somnath.nit...@gmail.com wrote:
Yaa even if it is 8 bytes long . Compiler will treat the value 10 as 8
bytes only . It should be able to assign it to the pointer of the same
size (type) ..
Try to free the dynamically allocated memory just before return 0
and tell me the result after compilation . Try this :-
int main()
{
int* p;
p = (int*)malloc(sizeof(int));
*p = 10;
free(p); /* Try This */
return 0;
}
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B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee
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Re: [algogeeks] Re: Output
how to deal with it??
surender
On Wed, Jul 20, 2011 at 9:02 PM, sunny agrawal sunny816.i...@gmail.comwrote:
http://groups.google.com/group/programming-puzzles/browse_thread/thread/4fecd0d904624a0d
this will clarify all doubts :)
On Wed, Jul 20, 2011 at 8:52 PM, SAMMM somnath.nit...@gmail.com wrote:
Yaa even if it is 8 bytes long . Compiler will treat the value 10 as 8
bytes only . It should be able to assign it to the pointer of the same
size (type) ..
Try to free the dynamically allocated memory just before return 0
and tell me the result after compilation . Try this :-
int main()
{
int* p;
p = (int*)malloc(sizeof(int));
*p = 10;
free(p); /* Try This */
return 0;
}
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[algogeeks] Re: output
cant i invoke both simultaneously??
if i try to make two objects like
x const a;
x a;
then it gives error..can u explain plz.
On Jul 12, 9:55 pm, Sandeep Jain sandeep6...@gmail.com wrote:
*const* in C++ is not exactly same as *final* in java. SO unlike java adding
the keyword const to a function does not affect overriding.
Infact, adding in C++ const functions == that they will not modify any
member of the class.
non-const functions cannot be invoked by const objects.
Try making object 'a' as const i.e.
const x a;
and then invoke f(), it should invoke the correct version.
Note that C++ allows function overloading based on const-ness.
Refer (Const function
section)http://www.cprogramming.com/tutorial/const_correctness.html
Also, subscript operators generally come in pairs,
Referhttp://www.parashift.com/c++-faq-lite/operator-overloading.html#faq-1...http://www.parashift.com/c++-faq-lite/const-correctness.html#faq-18.12
Regards,
Sandeep Jain
On Tue, Jul 12, 2011 at 10:09 PM, dheeraj tyagi dheeraj2...@gmail.comwrote:
const means that it cannot be overloaded..i think due to that this is
happening.
On Tue, Jul 12, 2011 at 9:26 PM, segfault pawan1991ya...@gmail.comwrote:
#includeiostream
using namespace std;
class x{
public:
x() {}
int func() const{
coutit is const function\n;
}
int func() {
coutit is simple functin\n;
}
};
int main()
{
x a;
a.func();
return 0;
}
why cann't it take const function?
explain it
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Re: [algogeeks] Re: output
x const a1;
x a2;
try this.
On Tue, Jul 12, 2011 at 11:11 PM, shiv narayan narayan.shiv...@gmail.comwrote:
cant i invoke both simultaneously??
if i try to make two objects like
x const a;
x a;
then it gives error..can u explain plz.
On Jul 12, 9:55 pm, Sandeep Jain sandeep6...@gmail.com wrote:
*const* in C++ is not exactly same as *final* in java. SO unlike java
adding
the keyword const to a function does not affect overriding.
Infact, adding in C++ const functions == that they will not modify any
member of the class.
non-const functions cannot be invoked by const objects.
Try making object 'a' as const i.e.
const x a;
and then invoke f(), it should invoke the correct version.
Note that C++ allows function overloading based on const-ness.
Refer (Const function section)
http://www.cprogramming.com/tutorial/const_correctness.html
Also, subscript operators generally come in pairs, Referhttp://
www.parashift.com/c++-faq-lite/operator-overloading.html#faq-1...http://www.parashift.com/c++-faq-lite/const-correctness.html#faq-18.12
Regards,
Sandeep Jain
On Tue, Jul 12, 2011 at 10:09 PM, dheeraj tyagi dheeraj2...@gmail.com
wrote:
const means that it cannot be overloaded..i think due to that this is
happening.
On Tue, Jul 12, 2011 at 9:26 PM, segfault pawan1991ya...@gmail.com
wrote:
#includeiostream
using namespace std;
class x{
public:
x() {}
int func() const{
coutit is const function\n;
}
int func() {
coutit is simple functin\n;
}
};
int main()
{
x a;
a.func();
return 0;
}
why cann't it take const function?
explain it
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8197218001
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Re: [algogeeks] Re: output plzz
thanks sameer.
On Wed, Jun 29, 2011 at 10:19 AM, sameer.mut...@gmail.com
sameer.mut...@gmail.com wrote:
We are getting same output because in this problem we wre typecastin
unsigned integer to a signed integer...Hence normal operation results.
On 6/28/11, Kamakshii Aggarwal kamakshi...@gmail.com wrote:
#includestdio.h
int main()
{
int array[] = {23,34,12,17,204,99,16};
int TOTAL_ELEMENTS =(sizeof(array) / sizeof(array[0]));
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
but in this case we are getting the same o/p..can u please again explain
whats wrong with the above question.
On Sat, Jun 25, 2011 at 9:24 PM, nicks crazy.logic.k...@gmail.com
wrote:
that's grt...i didn't knew it !!
On Sat, Jun 25, 2011 at 4:43 AM, Anantha Krishnan
ananthakrishnan@gmail.com wrote:
Good.
On Sat, Jun 25, 2011 at 4:47 PM, RITESH SRIVASTAV
riteshkumar...@gmail.com wrote:
sizeof returns size_t values and size_t is typedef unsigned int
size_t;
but when you compare it with -1(int) ,d=-1 is converted to unsigned
int
which becomes very large (INT_MAX)
and d (INT_MAX) 7 so the loop is never executed.
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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kamakshi...@gmail.com
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Re: [algogeeks] Re: output plzz
how to print datatype of a literal in C/C++ ?
On Sat, Jun 25, 2011 at 4:27 PM, L prnk.bhatna...@gmail.com wrote:
This happens because 'd' is automatically cast into type 'size_t'
which is basically unsigned int type.
So, it compares with TOTAL_ELEMENTS. Explicitly cast it into
int, if you want it to work!
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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Re: [algogeeks] Re: output plzz
#includestdio.h
int main()
{
int array[] = {23,34,12,17,204,99,16};
int TOTAL_ELEMENTS =(sizeof(array) / sizeof(array[0]));
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
but in this case we are getting the same o/p..can u please again explain
whats wrong with the above question.
On Sat, Jun 25, 2011 at 9:24 PM, nicks crazy.logic.k...@gmail.com wrote:
that's grt...i didn't knew it !!
On Sat, Jun 25, 2011 at 4:43 AM, Anantha Krishnan
ananthakrishnan@gmail.com wrote:
Good.
On Sat, Jun 25, 2011 at 4:47 PM, RITESH SRIVASTAV
riteshkumar...@gmail.com wrote:
sizeof returns size_t values and size_t is typedef unsigned int
size_t;
but when you compare it with -1(int) ,d=-1 is converted to unsigned
int
which becomes very large (INT_MAX)
and d (INT_MAX) 7 so the loop is never executed.
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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kamakshi...@gmail.com
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Re: [algogeeks] Re: output plzz
We are getting same output because in this problem we wre typecastin
unsigned integer to a signed integer...Hence normal operation results.
On 6/28/11, Kamakshii Aggarwal kamakshi...@gmail.com wrote:
#includestdio.h
int main()
{
int array[] = {23,34,12,17,204,99,16};
int TOTAL_ELEMENTS =(sizeof(array) / sizeof(array[0]));
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
but in this case we are getting the same o/p..can u please again explain
whats wrong with the above question.
On Sat, Jun 25, 2011 at 9:24 PM, nicks crazy.logic.k...@gmail.com wrote:
that's grt...i didn't knew it !!
On Sat, Jun 25, 2011 at 4:43 AM, Anantha Krishnan
ananthakrishnan@gmail.com wrote:
Good.
On Sat, Jun 25, 2011 at 4:47 PM, RITESH SRIVASTAV
riteshkumar...@gmail.com wrote:
sizeof returns size_t values and size_t is typedef unsigned int
size_t;
but when you compare it with -1(int) ,d=-1 is converted to unsigned
int
which becomes very large (INT_MAX)
and d (INT_MAX) 7 so the loop is never executed.
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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[algogeeks] Re: output plzz
This happens because 'd' is automatically cast into type 'size_t'
which is basically unsigned int type.
So, it compares with TOTAL_ELEMENTS. Explicitly cast it into
int, if you want it to work!
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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[algogeeks] Re: output plzz
sizeof returns size_t values and size_t is typedef unsigned int
size_t;
but when you compare it with -1(int) ,d=-1 is converted to unsigned
int
which becomes very large (INT_MAX)
and d (INT_MAX) 7 so the loop is never executed.
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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Re: [algogeeks] Re: output plzz
Good.
On Sat, Jun 25, 2011 at 4:47 PM, RITESH SRIVASTAV
riteshkumar...@gmail.comwrote:
sizeof returns size_t values and size_t is typedef unsigned int
size_t;
but when you compare it with -1(int) ,d=-1 is converted to unsigned
int
which becomes very large (INT_MAX)
and d (INT_MAX) 7 so the loop is never executed.
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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Re: [algogeeks] Re: output plzz
that's grt...i didn't knew it !!
On Sat, Jun 25, 2011 at 4:43 AM, Anantha Krishnan
ananthakrishnan@gmail.com wrote:
Good.
On Sat, Jun 25, 2011 at 4:47 PM, RITESH SRIVASTAV
riteshkumar...@gmail.com wrote:
sizeof returns size_t values and size_t is typedef unsigned int
size_t;
but when you compare it with -1(int) ,d=-1 is converted to unsigned
int
which becomes very large (INT_MAX)
and d (INT_MAX) 7 so the loop is never executed.
On Jun 25, 3:23 pm, harshit pahuja hpahuja.mn...@gmail.com wrote:
#includestdio.h
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23,34,12,17,204,99,16};
int main()
{
int d;
for(d=-1;d = (TOTAL_ELEMENTS-2);d++)
printf(%d\n,array[d+1]);
return 0;
}
y der is nothing in the output .
-
Regards -
HARSHIT PAHUJA
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[algogeeks] Re: output....
Sanjay,
Whenever we encounter a break statement does not it means to take the
program counter outside of the current loop.
I am confused a little bit. Someone please clarify.
See the following program
#includestdio.h
#includestdlib.h
int main(){
int t=4;
for(int i=0;i5;i++){
if(1){
if(t==6) break;
}
t++;
}
printf(%d,t);
/* Prints 6 */
return 0;
}
~
Oll
On Jun 19, 6:05 pm, sanjay ahuja sanjayahuja.i...@gmail.com wrote:
i=4 is default case for but there is no break statement after default
case. There for all cases until break is encountered will be executed.
so i += 5; makes i=9
i -= 4; will make i=5
and then break
so i is 5
On Sun, Jun 19, 2011 at 6:29 PM, sahil sahil18...@gmail.com wrote:
#includestdio.h
void main()
{ int i = 4;
switch (i)
{
default: ;
case 3:
i += 5;
if ( i == 8)
{
i++;
if (i == 9) break;
i *= 2;
}
i -= 4;
break;
case 8:
i += 5;
break;
}
printf(i = %d\n, i);
}
output:
i=5
how..? can sme one explain...!!
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Analyst, Financing Prime Brokerage
Nomura Securities India Pvt. Ltd
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Re: [algogeeks] Re: output....
what's the problem...when t=6 the break statement gets executed and the
control comes out of the for loop..
hence prints 6..
On Mon, Jun 20, 2011 at 12:05 AM, Oppilas jatka.oppimi...@gmail.com wrote:
Sanjay,
Whenever we encounter a break statement does not it means to take the
program counter outside of the current loop.
I am confused a little bit. Someone please clarify.
See the following program
#includestdio.h
#includestdlib.h
int main(){
int t=4;
for(int i=0;i5;i++){
if(1){
if(t==6) break;
}
t++;
}
printf(%d,t);
/* Prints 6 */
return 0;
}
~
Oll
On Jun 19, 6:05 pm, sanjay ahuja sanjayahuja.i...@gmail.com wrote:
i=4 is default case for but there is no break statement after default
case. There for all cases until break is encountered will be executed.
so i += 5; makes i=9
i -= 4; will make i=5
and then break
so i is 5
On Sun, Jun 19, 2011 at 6:29 PM, sahil sahil18...@gmail.com wrote:
#includestdio.h
void main()
{ int i = 4;
switch (i)
{
default: ;
case 3:
i += 5;
if ( i == 8)
{
i++;
if (i == 9) break;
i *= 2;
}
i -= 4;
break;
case 8:
i += 5;
break;
}
printf(i = %d\n, i);
}
output:
i=5
how..? can sme one explain...!!
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Analyst, Financing Prime Brokerage
Nomura Securities India Pvt. Ltd
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Re: [algogeeks] Re: output....
Nick,
I had just tested the code for confirming my doubt whether break statement
takes the program counter outside of the first loop or not.
int i = 4;
switch (i) {
default: ;
case 3:
i += 5;
if ( i == 8){
i++;
* if (i == 9) break; /* Now after executing
this break should't the program counter go to priintf statement*
*/* and print 9*
* * i *= 2;
}
i -= 4;
break;
case 8:
i += 5;
break;
}
printf(i = %d\n, i);
}
On Mon, Jun 20, 2011 at 1:30 PM, nicks crazy.logic.k...@gmail.com wrote:
what's the problem...when t=6 the break statement gets executed and the
control comes out of the for loop..
hence prints 6..
On Mon, Jun 20, 2011 at 12:05 AM, Oppilas jatka.oppimi...@gmail.comwrote:
Sanjay,
Whenever we encounter a break statement does not it means to take the
program counter outside of the current loop.
I am confused a little bit. Someone please clarify.
See the following program
#includestdio.h
#includestdlib.h
int main(){
int t=4;
for(int i=0;i5;i++){
if(1){
if(t==6) break;
}
t++;
}
printf(%d,t);
/* Prints 6 */
return 0;
}
~
Oll
On Jun 19, 6:05 pm, sanjay ahuja sanjayahuja.i...@gmail.com wrote:
i=4 is default case for but there is no break statement after default
case. There for all cases until break is encountered will be executed.
so i += 5; makes i=9
i -= 4; will make i=5
and then break
so i is 5
On Sun, Jun 19, 2011 at 6:29 PM, sahil sahil18...@gmail.com wrote:
#includestdio.h
void main()
{ int i = 4;
switch (i)
{
default: ;
case 3:
i += 5;
if ( i == 8)
{
i++;
if (i == 9) break;
i *= 2;
}
i -= 4;
break;
case 8:
i += 5;
break;
}
printf(i = %d\n, i);
}
output:
i=5
how..? can sme one explain...!!
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Analyst, Financing Prime Brokerage
Nomura Securities India Pvt. Ltd
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Re: [algogeeks] Re: output....
change 1st line to i = 3 and execute. It will print 9. If i = 4, then the
default case gets executed and then goes to case 3, then i's val will be 9.
Later, it comes out of the switch block and prints the val as 9.
On Mon, Jun 20, 2011 at 4:10 PM, oppilas . jatka.oppimi...@gmail.comwrote:
Nick,
I had just tested the code for confirming my doubt whether break statement
takes the program counter outside of the first loop or not.
int i = 4;
switch (i) {
default: ;
case 3:
i += 5;
if ( i == 8){
i++;
* if (i == 9) break; /* Now after executing
this break should't the program counter go to priintf statement*
*/* and print 9*
* * i *= 2;
}
i -= 4;
break;
case 8:
i += 5;
break;
}
printf(i = %d\n, i);
}
On Mon, Jun 20, 2011 at 1:30 PM, nicks crazy.logic.k...@gmail.com wrote:
what's the problem...when t=6 the break statement gets executed and the
control comes out of the for loop..
hence prints 6..
On Mon, Jun 20, 2011 at 12:05 AM, Oppilas jatka.oppimi...@gmail.comwrote:
Sanjay,
Whenever we encounter a break statement does not it means to take the
program counter outside of the current loop.
I am confused a little bit. Someone please clarify.
See the following program
#includestdio.h
#includestdlib.h
int main(){
int t=4;
for(int i=0;i5;i++){
if(1){
if(t==6) break;
}
t++;
}
printf(%d,t);
/* Prints 6 */
return 0;
}
~
Oll
On Jun 19, 6:05 pm, sanjay ahuja sanjayahuja.i...@gmail.com wrote:
i=4 is default case for but there is no break statement after default
case. There for all cases until break is encountered will be executed.
so i += 5; makes i=9
i -= 4; will make i=5
and then break
so i is 5
On Sun, Jun 19, 2011 at 6:29 PM, sahil sahil18...@gmail.com wrote:
#includestdio.h
void main()
{ int i = 4;
switch (i)
{
default: ;
case 3:
i += 5;
if ( i == 8)
{
i++;
if (i == 9) break;
i *= 2;
}
i -= 4;
break;
case 8:
i += 5;
break;
}
printf(i = %d\n, i);
}
output:
i=5
how..? can sme one explain...!!
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Nomura Securities India Pvt. Ltd
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[algogeeks] Re: output for optimal binary search tree
Can you be clear here? There is no difference in printing a binary tree whether its optimized or not! Or am I missing something here? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
