Re: [algogeeks] Re: Math Puzzle
Shut up...its 3,, On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote: It might be 3, but it doesn't have to be 3. Don On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote: if P+Q+R= 0 then P2 /QR + Q2/PR + R2/PQ = ?? how to solve this?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Math Puzzle
Don is right if R = 0, P = 1 and Q = -1 then the given expression is UNDEFINED!!! On Thu, Sep 15, 2011 at 10:16 PM, abhinav gupta guptaabhinav...@gmail.comwrote: Shut up...its 3,, On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote: It might be 3, but it doesn't have to be 3. Don On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote: if P+Q+R= 0 then P2 /QR + Q2/PR + R2/PQ = ?? how to solve this?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Math Puzzle
u cnt divide a number by 0..that thing is self undrstod On Thu, Sep 15, 2011 at 9:49 AM, Piyush Grover piyush4u.iit...@gmail.comwrote: Don is right if R = 0, P = 1 and Q = -1 then the given expression is UNDEFINED!!! On Thu, Sep 15, 2011 at 10:16 PM, abhinav gupta guptaabhinav...@gmail.com wrote: Shut up...its 3,, On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote: It might be 3, but it doesn't have to be 3. Don On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote: if P+Q+R= 0 then P2 /QR + Q2/PR + R2/PQ = ?? how to solve this?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Math Puzzle
dude dats outside the domain of the qs...dont be oversmart. On Thu, Sep 15, 2011 at 9:49 AM, Don dondod...@gmail.com wrote: No, not at all. Here is a trivial counterexample: P = Q = R = 0 Don On Sep 15, 11:46 am, abhinav gupta guptaabhinav...@gmail.com wrote: Shut up...its 3,, On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote: It might be 3, but it doesn't have to be 3. Don On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote: if P+Q+R= 0 then P2 /QR + Q2/PR + R2/PQ = ?? how to solve this?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Math Puzzle
@abhinav... it's not about being over smart or to show someone or to prove someone anything. It's just that you should not take any assumptions by yourself or if you do you should specify clearly. If u r asked this question in an interview and you give the answer 3 without telling your assumption, u r done!! And if you are living in the programming world, you need to take care of all the possible scenarios otherwise u will end up throwing exceptions and segmentation faults. On Thu, Sep 15, 2011 at 10:32 PM, Don dondod...@gmail.com wrote: Right, and in every proof above, at some point there is a possible division by zero. Therefore the proof is not valid in cases where R or P or Q are zero, and there are infinitely many such cases. The problem states P+Q+R=0 as the only constraint. There are infinitely many cases which fit that constraint where the expression is not equal to 3. Don On Sep 15, 11:57 am, abhinav gupta guptaabhinav...@gmail.com wrote: u cnt divide a number by 0..that thing is self undrstod On Thu, Sep 15, 2011 at 9:49 AM, Piyush Grover piyush4u.iit...@gmail.comwrote: Don is right if R = 0, P = 1 and Q = -1 then the given expression is UNDEFINED!!! On Thu, Sep 15, 2011 at 10:16 PM, abhinav gupta guptaabhinav...@gmail.com wrote: Shut up...its 3,, On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote: It might be 3, but it doesn't have to be 3. Don On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote: if P+Q+R= 0 then P2 /QR + Q2/PR + R2/PQ = ?? how to solve this?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Math Puzzle
solution is =3 with the condition p!=0 and q!=0 and r!=0 Ashima M.Sc.(Tech)Information Systems 4th year BITS Pilani Rajasthan On Thu, Sep 15, 2011 at 10:38 PM, Piyush Grover piyush4u.iit...@gmail.comwrote: @abhinav... it's not about being over smart or to show someone or to prove someone anything. It's just that you should not take any assumptions by yourself or if you do you should specify clearly. If u r asked this question in an interview and you give the answer 3 without telling your assumption, u r done!! And if you are living in the programming world, you need to take care of all the possible scenarios otherwise u will end up throwing exceptions and segmentation faults. On Thu, Sep 15, 2011 at 10:32 PM, Don dondod...@gmail.com wrote: Right, and in every proof above, at some point there is a possible division by zero. Therefore the proof is not valid in cases where R or P or Q are zero, and there are infinitely many such cases. The problem states P+Q+R=0 as the only constraint. There are infinitely many cases which fit that constraint where the expression is not equal to 3. Don On Sep 15, 11:57 am, abhinav gupta guptaabhinav...@gmail.com wrote: u cnt divide a number by 0..that thing is self undrstod On Thu, Sep 15, 2011 at 9:49 AM, Piyush Grover piyush4u.iit...@gmail.comwrote: Don is right if R = 0, P = 1 and Q = -1 then the given expression is UNDEFINED!!! On Thu, Sep 15, 2011 at 10:16 PM, abhinav gupta guptaabhinav...@gmail.com wrote: Shut up...its 3,, On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote: It might be 3, but it doesn't have to be 3. Don On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote: if P+Q+R= 0 then P2 /QR + Q2/PR + R2/PQ = ?? how to solve this?? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- @ |3 # ! /\/ @ \./ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: math puzzle
3x+4y = 60 it's a straight line equation whose x intercept is 20 and y intercept is 15. Draw it in first quadrant (as x, y are positive integers) now x = (60 - 4y)/3 = 4(15-y)/3 now for y = 1, 2...15 you need to check whether (15-y) is divisible by 3 or not. It's simple y = 3, 6, 9, 12 -Piyush On Sun, Aug 28, 2011 at 6:38 PM, Dave dave_and_da...@juno.com wrote: @Sivaviknesh: The smallest values of x and y are 1. The largest value of y is (60 - 3) / 4 = 14. Solve for x: x = (60 - 4y) / 3. Since x is an integer, 60 - 4y must be a multiple of 3. Since 60 - 3y is a multiple of 3, (60 - 4y) - (60 - 3y) = y must be a multiple of 3. Thus, y = 3, 6, 9, 12. Then you can solve for the corresponding values of x. Dave On Aug 28, 7:46 am, sivaviknesh s sivavikne...@gmail.com wrote: *Find the number of solutions for 3x+4y=60, if x and y are positive integers.* Is there any standard method for solving these type of ques ..or only trial and error ??? -- Regards, $iva -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: math puzzle
maximum value of y satisfying this is y=15 and for that x=0; now decrease y by 3 and increase x by 4 ,you will have x and y satisfying the equation. keep on doing this till you reach minimum value of y i.e 0 this you can do 5 times decreasing y=15 by 3 every time so there will be 5 solutions . On 8/28/11, Piyush Grover piyush4u.iit...@gmail.com wrote: 3x+4y = 60 it's a straight line equation whose x intercept is 20 and y intercept is 15. Draw it in first quadrant (as x, y are positive integers) now x = (60 - 4y)/3 = 4(15-y)/3 now for y = 1, 2...15 you need to check whether (15-y) is divisible by 3 or not. It's simple y = 3, 6, 9, 12 -Piyush On Sun, Aug 28, 2011 at 6:38 PM, Dave dave_and_da...@juno.com wrote: @Sivaviknesh: The smallest values of x and y are 1. The largest value of y is (60 - 3) / 4 = 14. Solve for x: x = (60 - 4y) / 3. Since x is an integer, 60 - 4y must be a multiple of 3. Since 60 - 3y is a multiple of 3, (60 - 4y) - (60 - 3y) = y must be a multiple of 3. Thus, y = 3, 6, 9, 12. Then you can solve for the corresponding values of x. Dave On Aug 28, 7:46 am, sivaviknesh s sivavikne...@gmail.com wrote: *Find the number of solutions for 3x+4y=60, if x and y are positive integers.* Is there any standard method for solving these type of ques ..or only trial and error ??? -- Regards, $iva -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: math puzzle
sorry 6 solutions y=15,12,9,6,3,0 and x=0,4,8,12,16,20 respectively On 8/28/11, harshit sethi hshoneyma...@gmail.com wrote: maximum value of y satisfying this is y=15 and for that x=0; now decrease y by 3 and increase x by 4 ,you will have x and y satisfying the equation. keep on doing this till you reach minimum value of y i.e 0 this you can do 5 times decreasing y=15 by 3 every time so there will be 5 solutions . On 8/28/11, Piyush Grover piyush4u.iit...@gmail.com wrote: 3x+4y = 60 it's a straight line equation whose x intercept is 20 and y intercept is 15. Draw it in first quadrant (as x, y are positive integers) now x = (60 - 4y)/3 = 4(15-y)/3 now for y = 1, 2...15 you need to check whether (15-y) is divisible by 3 or not. It's simple y = 3, 6, 9, 12 -Piyush On Sun, Aug 28, 2011 at 6:38 PM, Dave dave_and_da...@juno.com wrote: @Sivaviknesh: The smallest values of x and y are 1. The largest value of y is (60 - 3) / 4 = 14. Solve for x: x = (60 - 4y) / 3. Since x is an integer, 60 - 4y must be a multiple of 3. Since 60 - 3y is a multiple of 3, (60 - 4y) - (60 - 3y) = y must be a multiple of 3. Thus, y = 3, 6, 9, 12. Then you can solve for the corresponding values of x. Dave On Aug 28, 7:46 am, sivaviknesh s sivavikne...@gmail.com wrote: *Find the number of solutions for 3x+4y=60, if x and y are positive integers.* Is there any standard method for solving these type of ques ..or only trial and error ??? -- Regards, $iva -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: math puzzle
3x+4y = 60 can be expressed as 15 -y = 3x+3y -45 i.e, 15-y = 3(x+y-15) which implies tht for every value of x,y in the above eq 15-y is divisible by 3 On Sun, Aug 28, 2011 at 10:03 PM, Dave dave_and_da...@juno.com wrote: @Harhsit: Normally, 0 is not considered positive. Dave On Aug 28, 10:45 am, harshit sethi hshoneyma...@gmail.com wrote: sorry 6 solutions y=15,12,9,6,3,0 and x=0,4,8,12,16,20 respectively On 8/28/11, harshit sethi hshoneyma...@gmail.com wrote: maximum value of y satisfying this is y=15 and for that x=0; now decrease y by 3 and increase x by 4 ,you will have x and y satisfying the equation. keep on doing this till you reach minimum value of y i.e 0 this you can do 5 times decreasing y=15 by 3 every time so there will be 5 solutions . On 8/28/11, Piyush Grover piyush4u.iit...@gmail.com wrote: 3x+4y = 60 it's a straight line equation whose x intercept is 20 and y intercept is 15. Draw it in first quadrant (as x, y are positive integers) now x = (60 - 4y)/3 = 4(15-y)/3 now for y = 1, 2...15 you need to check whether (15-y) is divisible by 3 or not. It's simple y = 3, 6, 9, 12 -Piyush On Sun, Aug 28, 2011 at 6:38 PM, Dave dave_and_da...@juno.com wrote: @Sivaviknesh: The smallest values of x and y are 1. The largest value of y is (60 - 3) / 4 = 14. Solve for x: x = (60 - 4y) / 3. Since x is an integer, 60 - 4y must be a multiple of 3. Since 60 - 3y is a multiple of 3, (60 - 4y) - (60 - 3y) = y must be a multiple of 3. Thus, y = 3, 6, 9, 12. Then you can solve for the corresponding values of x. Dave On Aug 28, 7:46 am, sivaviknesh s sivavikne...@gmail.com wrote: *Find the number of solutions for 3x+4y=60, if x and y are positive integers.* Is there any standard method for solving these type of ques ..or only trial and error ??? -- Regards, $iva -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Rishabbh A Dua -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
