Re: Regular Expression Help.
Hi Frank, On Wed, 25 Mar 2015 10:31:40 +0530 Frank Vino vinofra...@gmail.com wrote: Hi Team, How to understand Regular Expression in a easy way? This page has links to some recommended tutorials about learning regular expressions: http://perl-begin.org/topics/regular-expressions/ *NOTE*: I originated perl-begin.org and still maintain it, but everyone is welcome to contribute to it. Regards, Shlomi Fish -- - Shlomi Fish http://www.shlomifish.org/ List of Text Processing Tools - http://shlom.in/text-proc When it comes to terminators, you have a better shot at Arnold Schwarzenegger than at Summer Glau. (Via The Big Bang Theory) — http://www.shlomifish.org/humour/bits/facts/Summer-Glau/ Please reply to list if it's a mailing list post - http://shlom.in/reply . -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular Expression Help.
Hi Frank, when first learning regexps I read the section In the World of Regular Expressions in the Lama-Book [1]. If you find this introduction to slow, you might also take a look at chromatic's Modern Perl, which is available for free [2]. Regards, Simon Am 25.03.2015 um 06:01 schrieb Frank Vino: Hi Team, How to understand Regular Expression in a easy way? Thanks, Frank [1] Learning Perl, Sixth Edition by Randal L. Schwartz, brian d foy, and Tom Phoenix [2] http://onyxneon.com/books/modern_perl/ -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular Expression Help.
On Wed, 25 Mar 2015 10:31:40 +0530 Frank Vino vinofra...@gmail.com wrote: Hi Team, How to understand Regular Expression in a easy way? Thanks, Frank Sorry Frank but there's no easy way. ☹ Some things to remember: Some punctuation marks have special meaning, like periods, question marks, and asterisks. But if there is a backslash before them, then they match themselves. This is true for all punctuation marks. And the opposite is true for ASCII letters and numbers. A backslash before them may give them special meaning but if there is none, then they match themselves. -- Don't stop where the ink does. Shawn -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular Expression Help.
Thanks a lot Simon -Frank On Wed, Mar 25, 2015 at 5:44 PM, Simon Reinhardt si...@keinstein.org wrote: Hi Frank, when first learning regexps I read the section In the World of Regular Expressions in the Lama-Book [1]. If you find this introduction to slow, you might also take a look at chromatic's Modern Perl, which is available for free [2]. Regards, Simon Am 25.03.2015 um 06:01 schrieb Frank Vino: Hi Team, How to understand Regular Expression in a easy way? Thanks, Frank [1] Learning Perl, Sixth Edition by Randal L. Schwartz, brian d foy, and Tom Phoenix [2] http://onyxneon.com/books/modern_perl/ -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular Expression Help.
Frank, Just go through below site, it helps to build regex and test same easily. http://www.regexr.com/ ~Rahul On Wed, Mar 25, 2015 at 10:42 AM, Akshay Mohit akshaymohit2...@gmail.com wrote: Just start using it and you will find it very easy to understand. -Akshay On Wed, Mar 25, 2015 at 10:31 AM, Frank Vino vinofra...@gmail.com wrote: Hi Team, How to understand Regular Expression in a easy way? Thanks, Frank
Re: Regular Expression Help.
Just start using it and you will find it very easy to understand. -Akshay On Wed, Mar 25, 2015 at 10:31 AM, Frank Vino vinofra...@gmail.com wrote: Hi Team, How to understand Regular Expression in a easy way? Thanks, Frank
Re: Regular expression help pls !
Not sure I get it, but would
/^fc3\/2\b/
(assuming you're looking for fc3/2 and not fc3/23) work?
hth
paolino
On 23 Aug 2013, at 17:06, jet speed speedj...@googlemail.com wrote:
Chaps,
Please i need help on the regular expression, i have the sample code below.
I only want to match the entries from the array to the file and print the
matching line
for example if i only want to match fc3/23, in my code it prints both the
lines fc3/2 and fc3/23. How to restrict to exact matches and print only ex:
fc3/23
out.txt
--
fc3/2 10:00:00:00 host1
fc3/23 10:00:00:00 host2
fc10/1 10:00:00:00 host3
fc10/11 10:00:00:00 host4
fc3/1 10:00:00:00 host5
fc3/14 10:00:00:00 host6
fc12/1 10:00:00:00 host7
fc12/1210:00:00:00 host8
sample code
-
my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
my $f2 = 'out.txt';
for my $element(@check) {
open my $fh2, '', $f2 or die could not open $f2: $!;
while (my $line = $fh2) {
chomp $line;
if ($line = / ^(fc\d+\/\d+/) {
$match=$;
}
if ($element =~ $match) {
print $line \n;
}
}
}
required output
fc3/23 10:00:0:00 host2
fc10/1 10:00:0:00 host3
fc3/14 10:00:00:00 host6
fc12/1210:00:00:00 host8
Thanks
Sj
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Re: Regular expression help pls !
On Fri, 23 Aug 2013 17:06:41 +0100
jet speed speedj...@googlemail.com wrote:
my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
my @check = qw( fc3/23 fc10/1 fc3/14 fc12/12 );
my $f2 = 'out.txt';
for my $element(@check) {
open my $fh2, '', $f2 or die could not open $f2: $!;
while (my $line = $fh2) {
chomp $line;
# put the for loop inside the while
open my $fh2, '', $f2 or die could not open $f2: $!;
while (my $line = $fh2) {
chomp $line;
for my $element(@check) {
if( $line =~ /^\Q$element\E\s/ ){
print $line \n;
last;
}
}
}
--
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Shawn
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Re: Regular expression help pls !
On Fri, 23 Aug 2013 17:06:41 +0100
jet speed speedj...@googlemail.com wrote:
Chaps,
Please i need help on the regular expression, i have the sample code
below. I only want to match the entries from the array to the file
and print the matching line
for example if i only want to match fc3/23, in my code it prints both
the lines fc3/2 and fc3/23. How to restrict to exact matches and
print only ex: fc3/23
[...]
if ($line = / ^(fc\d+\/\d+/) {
First off, you mean =~ to match against a regex - that's a fairly
meaningless assignment there. Was that a typo or is that how it
actually is in your code?
Secondly, that regex shouldn't even compile - you've missed a closing
parenthesis.
Perl should have told you something like:
Unmatched ( in regex; marked by
You meant:
if ($line =~ /^(fc\d+\/\d+)/) {
Although I would write that a little more clearly - using qr lets you
pick delimiters that avoid you having to escape the slash in the
middle, and using the x modifier makes the regex whitespace
insensitive, so you can space things out for readability - and also,
assign the match to a meaningful var immediately:
if (my ($port) = $line =~ qr{^ (fc \d+ / \d+ ) }x) {
# matched, $port contains e.g. fc3/23
}
Also, iterating through the file once for each port you want to look
for is a rather inefficient approach - reverse the logic, and loop
through each line in the file, checking it against each of your ports
of interest within the loop - for example:
open my $fh, '', $filename or die Failed to open $filename - $!;
while (my $line = $fh) {
chomp $line;
if (my ($port) = $line =~ qr{^ (fc \d+ / \d+ ) }x) {
if (grep { $port eq $_ } @check) {
# $port matched one of the ones you wanted.
print $line\n;
}
}
}
Hope that helps?
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Re: Regular expression help pls !
See sample code below
Chaps,
Please i need help on the regular expression, i have the sample code
below.
I only want to match the entries from the array to the file and print
the
matching line
for example if i only want to match fc3/23, in my code it prints both
the
lines fc3/2 and fc3/23. How to restrict to exact matches and print
only ex:
fc3/23
out.txt
--
fc3/2 10:00:00:00 host1
fc3/23 10:00:00:00 host2
fc10/1 10:00:00:00 host3
fc10/11 10:00:00:00 host4
fc3/1 10:00:00:00 host5
fc3/14 10:00:00:00 host6
fc12/1 10:00:00:00 host7
fc12/1210:00:00:00 host8
sample code
-
my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
my $f2 = 'out.txt';
for my $element(@check) {
open my $fh2, '', $f2 or die could not open $f2: $!;
while (my $line = $fh2) {
chomp $line;
if ($line = / ^(fc\d+\/\d+/) {
$match=$;
}
if ($element =~ $match) {
print $line \n;
}
}
}
required output
fc3/23 10:00:0:00 host2
fc10/1 10:00:0:00 host3
fc3/14 10:00:00:00 host6
fc12/1210:00:00:00 host8
Thanks
Sj
This worked for me:
#!/usr/bin/perl
use strict; # Always a good idea!
use warnings;# likewise!
# You need quotes around your literals in the line that creates
# and assigns @check:
my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
my $f2 = 'out.txt';
# The following lines create a reqexp variable that will match any
# of the strings in @check. Note in the map that I placed a space
# after $_. This takes care of the problem where fc3/2 matched
# fc3/23. When this is done, for this sample, the generated regular
# expression looks like:
#(?:fc3/23 )|(?:fc10/1 )|(?:fc3/14 )|(?:fc12/12 )
# This attempts to match against all of the strings that were in
@check.
# The use of (?: instead of ( to start each group will make the
# parenthesis non-capturing, which is a bit quicker when you don't
need
# to capture the actual matches.
#
my @tmpcheck = map {(?:$_ )} @check;
my $regexp_str = join |, @tmpcheck;
my $regexp = qr/$regexp_str/;
open my $fh2, '', $f2 or die could not open $f2: $!;
while (my $line = $fh2) {
print $line if $line =~ $regexp;# Print only lines that match
}
# Note that I did not chomp the newline and put it back on when
printing.
# The presence of the newline does not effect the match in this
case, so
# that was not necessary.
Best of luck.
Nathan
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Re: Regular expression help pls !
On Aug 23, 2013, at 9:06 AM, jet speed wrote:
Chaps,
Please i need help on the regular expression, i have the sample code below.
I only want to match the entries from the array to the file and print the
matching line
for example if i only want to match fc3/23, in my code it prints both the
lines fc3/2 and fc3/23. How to restrict to exact matches and print only ex:
fc3/23
out.txt
--
fc3/2 10:00:00:00 host1
fc3/23 10:00:00:00 host2
fc10/1 10:00:00:00 host3
fc10/11 10:00:00:00 host4
fc3/1 10:00:00:00 host5
fc3/14 10:00:00:00 host6
fc12/1 10:00:00:00 host7
fc12/1210:00:00:00 host8
sample code
-
The code below does not compile. Please make sure you post valid programs if
you want help.
my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
You need to put quotes around strings:
my @check = ('fc3/23', 'fc10/1', 'fc3/14', 'fc12/12');
my $f2 = 'out.txt';
for my $element(@check) {
You should indent blocks (for, while) for readability.
open my $fh2, '', $f2 or die could not open $f2: $!;
Here, you are opening the file for each iteration. Reading files is much slower
than iterating over an array. Therefore, if you have to 1) read a file and 2)
iterate over an array, you should reverse the order of operations: Read a line
from the file and then iterate over the array for each line in the file.
while (my $line = $fh2) {
chomp $line;
if ($line = / ^(fc\d+\/\d+/) {
This line has three syntax errors:
1. You want the binding operator =~ instead of assignment =
2. You don't want a space between / and ^
3. The final / and closing ) should be swapped.
I am assuming you mean:
if ($line =~ /^(fc\d+\/\d+)/ {
$match=$;
Since your regular expression captures the entire match, you should use the
capturing variable $1 instead of the whatever-matched variable $. It is
actually faster.
Every line of your input will match the above regular expression, so the only
effect is to extract the first field. You can do that by splitting the line on
whitespace:
my( $first, @rest ) = split(/ /,$line);
}
if ($element =~ $match) {
You need slashes or the m operator to define a regular expression:
if( $element =~ /$match/ ) {
If you want to match the entire string, you need to add beginning and ending
anchors:
if( $element =~ /^$match$/ ) {
But if that is what you want, just use eq:
if( $element eq $match ) {
print $line \n;
}
}
}
required output
fc3/23 10:00:0:00 host2
fc10/1 10:00:0:00 host3
fc3/14 10:00:00:00 host6
fc12/1210:00:00:00 host8
Thanks
Sj
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Re: Regular expression help pls !
Chaps,
I am testing all your code one by one, Appreciate your time and detailed
inputs.
Many Thanks
Sj
On Fri, Aug 23, 2013 at 6:01 PM, Jim Gibson jimsgib...@gmail.com wrote:
On Aug 23, 2013, at 9:06 AM, jet speed wrote:
Chaps,
Please i need help on the regular expression, i have the sample code
below.
I only want to match the entries from the array to the file and print
the matching line
for example if i only want to match fc3/23, in my code it prints both
the lines fc3/2 and fc3/23. How to restrict to exact matches and print only
ex: fc3/23
out.txt
--
fc3/2 10:00:00:00 host1
fc3/23 10:00:00:00 host2
fc10/1 10:00:00:00 host3
fc10/11 10:00:00:00 host4
fc3/1 10:00:00:00 host5
fc3/14 10:00:00:00 host6
fc12/1 10:00:00:00 host7
fc12/1210:00:00:00 host8
sample code
-
The code below does not compile. Please make sure you post valid programs
if you want help.
my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
You need to put quotes around strings:
my @check = ('fc3/23', 'fc10/1', 'fc3/14', 'fc12/12');
my $f2 = 'out.txt';
for my $element(@check) {
You should indent blocks (for, while) for readability.
open my $fh2, '', $f2 or die could not open $f2: $!;
Here, you are opening the file for each iteration. Reading files is much
slower than iterating over an array. Therefore, if you have to 1) read a
file and 2) iterate over an array, you should reverse the order of
operations: Read a line from the file and then iterate over the array for
each line in the file.
while (my $line = $fh2) {
chomp $line;
if ($line = / ^(fc\d+\/\d+/) {
This line has three syntax errors:
1. You want the binding operator =~ instead of assignment =
2. You don't want a space between / and ^
3. The final / and closing ) should be swapped.
I am assuming you mean:
if ($line =~ /^(fc\d+\/\d+)/ {
$match=$;
Since your regular expression captures the entire match, you should use
the capturing variable $1 instead of the whatever-matched variable $. It
is actually faster.
Every line of your input will match the above regular expression, so the
only effect is to extract the first field. You can do that by splitting the
line on whitespace:
my( $first, @rest ) = split(/ /,$line);
}
if ($element =~ $match) {
You need slashes or the m operator to define a regular expression:
if( $element =~ /$match/ ) {
If you want to match the entire string, you need to add beginning and
ending anchors:
if( $element =~ /^$match$/ ) {
But if that is what you want, just use eq:
if( $element eq $match ) {
print $line \n;
}
}
}
required output
fc3/23 10:00:0:00 host2
fc10/1 10:00:0:00 host3
fc3/14 10:00:00:00 host6
fc12/1210:00:00:00 host8
Thanks
Sj
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Re: regular expression help
From: Dr.Ruud rvtol+use...@isolution.nl On 2012-09-20 09:08, Octavian Rasnita wrote: my ( $file_name ) = $data =~ /([^\\]+)$/g; No need for that g-modifier. -- Ruud Yes, you are right. I added it by mistake. Octavian -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: regular expression help
From: Irfan Sayed irfan_sayed2...@yahoo.com i have string 'c:\p4\car\abc\xyz.csproj' i just need to match the xyz.csproj i tried few option but does not help. can someone please suggest regards irfan my $data = 'c:\p4\car\abc\xyz.csproj'; my ( $file_name ) = $data =~ /([^\\]+)$/g; print $file_name; It will print: xyz.csproj ( and ) captures the matched string but because in this case they capture the whole regular expression, you can omit using them like: my ( $file_name ) = $data =~ /[^\\]+$/g; [^\\] means that it matches everything which is not a \ char, and because \ is a special char, it should be escaped with another \ before it (this is why there are 2 \ chars). There is a + char after the [^\\] meaning that [^\\] doesn't match just a single char, but one or more. And at the end there is a $ sign meaning that after this string that mached, it is the end of the string, so this regex will match any substring which doesn't contain a \ char which appear at the end of the string. HTH, and of course, use strict and warnings. Octavian -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: regular expression help
got it myself :) thanks a lot $line_to_add =~ m/([a-zA-Z]+\.csproj)/; regards From: Irfan Sayed irfan_sayed2...@yahoo.com To: Perl Beginners beginners@perl.org Sent: Thursday, September 20, 2012 12:07 PM Subject: regular expression help i have string 'c:\p4\car\abc\xyz.csproj' i just need to match the xyz.csproj i tried few option but does not help. can someone please suggest regards irfan
Re: regular expression help
On 09/20/2012 04:39 PM, Irfan Sayed wrote:
got it myself :)
thanks a lot
$line_to_add =~ m/([a-zA-Z]+\.csproj)/;
Hi Irfan,
Your solution will only match files that consist of ASCII alphabetic
characters followed by '.csproj'. It will also match these:
* 'c:\p4\car\abc\foo.csproj\file.txt'
* 'c:\p4\car\abc\123xyx.csproj'
* 'c:\p4\car\abc\xyz.csprojabc'
Octavian's solution is much more general. Run this program to see why:
#!/usr/bin/perl
use strict;
use warnings;
my @paths = (
'c:\p4\car\abc\xyz.csproj',
'c:\p4\car\abc\foo.csproj\file.txt',
'c:\p4\car\abc\123xyx.csproj',
'c:\p4\car\abc\xyz.csprojabc',
);
foreach my $path ( @paths ) {
my ($irfan) = $path =~ m/([a-zA-Z]+\.csproj)/;
$irfan ||= 'no match';
my ($octavian) = $path =~ /([^\\]+)$/;
$octavian ||= 'no match';
print EOINFO;
Path: $path
Irfan: $irfan
Octavian: $octavian
EOINFO
}
__END__
Path: c:\p4\car\abc\xyz.csproj
Irfan: xyz.csproj
Octavian: xyz.csproj
Path: c:\p4\car\abc\foo.csproj\file.txt
Irfan: foo.csproj
Octavian: file.txt
Path: c:\p4\car\abc\123xyx.csproj
Irfan: xyx.csproj
Octavian: 123xyx.csproj
Path: c:\p4\car\abc\xyz.csprojabc
Irfan: xyz.csproj
Octavian: xyz.csprojabc
A more idiomatic way to do this is to use the File::Spec module. Inspect
the output of this program for inspiration:
#!/usr/bin/perl
use strict;
use warnings;
use File::Spec; # for splitpath
my $path = 'c:\p4\car\abc\xyz.csproj';
my ( $volume, $directories, $file) = File::Spec-splitpath( $path );
print EOINFO;
Volume: $volume
Directories: $directories
File: $file
EOINFO
exit 0;
__END__
Cheers,
Michael
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Technology/Softdev/ME Small Change Team
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Re: regular expression help
On Thu, 20 Sep 2012 17:13:07 +0930 Michael Brader mbra...@internode.com.au wrote: A more idiomatic way to do this is to use the File::Spec module. Inspect the output of this program for inspiration: There's also File::Basename: http://perldoc.perl.org/File/Basename.html Regards, Shlomi Fish -- - Shlomi Fish http://www.shlomifish.org/ Optimising Code for Speed - http://shlom.in/optimise Chuck Norris was never a newbie! He will kill anyone who implies otherwise. In a very not newbie-like manner. Please reply to list if it's a mailing list post - http://shlom.in/reply . -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: regular expression help
thanks a lot for all the responses :) regards From: Shlomi Fish shlo...@shlomifish.org To: Michael Brader mbra...@internode.com.au Cc: beginners@perl.org Sent: Thursday, September 20, 2012 2:53 PM Subject: Re: regular expression help On Thu, 20 Sep 2012 17:13:07 +0930 Michael Brader mbra...@internode.com.au wrote: A more idiomatic way to do this is to use the File::Spec module. Inspect the output of this program for inspiration: There's also File::Basename: http://perldoc.perl.org/File/Basename.html Regards, Shlomi Fish -- - Shlomi Fish http://www.shlomifish.org/ Optimising Code for Speed - http://shlom.in/optimise Chuck Norris was never a newbie! He will kill anyone who implies otherwise. In a very not newbie-like manner. Please reply to list if it's a mailing list post - http://shlom.in/reply . -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: regular expression help
On 2012-09-20 09:08, Octavian Rasnita wrote: my ( $file_name ) = $data =~ /([^\\]+)$/g; No need for that g-modifier. -- Ruud -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular Expression help!
I ended up confused after reading your email.
Please specify INPUT + OUTPUT/condition.
You have already specify INPUT which is:
LOGICAL UNIT NUMBER 587
UID:60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID:60:06:01:60:50:40:21:00:D0:23:D5:C2:BA:D9:DE:11
LOGICAL UNIT NUMBER 763
UID:60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11
What is the desired OUTPUT/condition?
Is it something like this?
587 wwn is 60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
128 wwn is 60:06:01:60:50:40:21:00:D0:23:D5:C2:BA:D9:DE:11
763 wwn is 60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11
On Wed, May 11, 2011 at 8:38 AM, jet speed speedj...@googlemail.com wrote:
Hi All,
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find with regulare expression #if ($_=~
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
However i am not sure how to get both $1 and $2 togather.
Ideally i would like to have an output printed
print $1 wwn is $2 \n;
Any help on this would be much appreciated.
FILE
---
LOGICAL UNIT NUMBER 587
UID: 60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID: 60:06:01:60:50:40:21:00:D0:23:D5:C2:BA:D9:DE:11
LOGICAL UNIT NUMBER 763
UID: 60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11
---
#!/usr/bin/perl
open(FILE, clrlist) || die Can't open clrlist : $!\n;
while (FILE) {
#if ($_=~ /\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
if ($_=~
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})\n[a-z0-9+]\s*(\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*)/i)
{
print $1 ;
print $2;
}
}
-
Sj
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Re: Regular Expression help!
On 11-05-11 11:38 AM, jet speed wrote:
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find with regulare expression #if ($_=~
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
However i am not sure how to get both $1 and $2 togather.
Ideally i would like to have an output printed
print $1 wwn is $2 \n;
Any help on this would be much appreciated.
You are trying to do too much in one regular expression. Process the
file one line at a time.
#!/usr/bin/env perl
use strict;
use warnings;
my $lun = 0;
while( DATA ){
if( /^\s*LOGICAL\s+UNIT\s+NUMBER\s+(\d+)/ ){
$lun = $1;
}elsif( /^UID:\s*(\S+)/ ){
print $lun wwn is $1 \n;
}
}
__DATA__
LOGICAL UNIT NUMBER 587
UID:60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID:60:06:01:60:50:40:21:00:D0:23:D5:C2:BA:D9:DE:11
LOGICAL UNIT NUMBER 763
UID:60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11
--
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Confusion is the first step of understanding.
Programming is as much about organization and communication
as it is about coding.
The secret to great software: Fail early often.
Eliminate software piracy: use only FLOSS.
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Re: Regular Expression help!
On 11/05/2011 16:38, jet speed wrote:
Hi All,
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find with regulare expression #if ($_=~
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
However i am not sure how to get both $1 and $2 togather.
Ideally i would like to have an output printed
print $1 wwn is $2 \n;
Any help on this would be much appreciated.
FILE
---
LOGICAL UNIT NUMBER 587
UID:60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID:60:06:01:60:50:40:21:00:D0:23:D5:C2:BA:D9:DE:11
LOGICAL UNIT NUMBER 763
UID:60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11
---
#!/usr/bin/perl
open(FILE, clrlist) || die Can't open clrlist : $!\n;
while (FILE) {
#if ($_=~ /\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
if ($_=~
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})\n[a-z0-9+]\s*(\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*)/i)
{
print $1 ;
print $2;
}
}
-
I think I understand what you hope to achieve, but your code will not
compile as it stands.
First of all, instead of
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i
you should write simply
/LOGICAL UNIT NUMBER (\d{1,4})/i
Your second regex is similar, but anything like
/\d{2}*/
gives the error 'Nested quantifiers in regex'. You can specify either
{2} (exactly two occurrences) or * (zero or more occurrences) but not both!
Also, you are trying to match a string of 16 hex bytes using /\d/. That
matches only 0..9 in ASCII (and a lot more in Unicode, but that isn't a
problem here). For hex, use either /[0-9A-X]/i or /[[:xdigit:]]/.
But the main problem is that you are trying to match two lines
simultaneously. Your regex contains /\n/, but you are reading from the
file only one line at a time. Each line will contain *either*
LOGICAL UNIT NUMBER 587\n
*or*
UID:
60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11\n
so you need to code accordingly.
On top of that, your second regex includes /[a-z0-9+]/i when I think you
meant /[a-z0-9]+/i, and it doesn't allow for the colon after 'UID'. Once
more, this should be /UID:\s*/ or something similar. Without seeing your
data I cannot help further.
For those who would help, I believe the program looks as below.
I hope this helps,
Rob
use strict;
use warnings;
while (DATA) {
#if ($_=~ /\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
if ($_=~
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})\n[a-z0-9+]\s*(\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*\d{2}*)/i)
{
print $1 ;
print $2;
}
}
__DATA__
LOGICAL UNIT NUMBER 587
UID:60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID:60:06:01:60:50:40:21:00:D0:23:D5:C2:BA:D9:DE:11
LOGICAL UNIT NUMBER 763
UID:60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11
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Re: Regular Expression help!
On May 11, 8:38 am, speedj...@googlemail.com (jet speed) wrote:
Hi All,
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find with regulare expression #if ($_=~
/\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
However i am not sure how to get both $1 and $2 togather.
Ideally i would like to have an output printed
print $1 wwn is $2 \n;
Any help on this would be much appreciated.
FILE
---
LOGICAL UNIT NUMBER 587
UID: 60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID: 60:06:01:60:50:40:21:00:D0:23:D5:C2:BA:D9:DE:11
LOGICAL UNIT NUMBER 763
UID: 60:06:01:60:50:40:21:00:25:C6:3F:A7:CA:2D:DF:11
---
#!/usr/bin/perl
open(FILE, clrlist) || die Can't open clrlist : $!\n;
while (FILE) {
#if ($_=~ /\w{7}\s\w{4}\s\w{6}\s(\d{1,4})/i) { #workts for 1st line
...
Also, you may want to consider the /x modifier to avoid
regex blindness, [a visual Bermuda Triangle that will
cause anyone viewing it to avert their eyes and quickly
paddle the other way].
Even with an easy regex, the view improves considerably
with /x :
if ( / \w{7} \s \w{4} \s# insert comment here...
\d{1,4} # more comments...
/ix )
Or just:
/ \w{7} \s \w{4} \s /ix; # whitespace enhanced
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Re: Regular Expression help!
Hi All, Thanks for your time and valuable inputs, Appreciate it. I will try your suggestions and test it in my program. Sj
Re: Regular expression help !!
2011/4/27 jet speed speedj...@googlemail.com
Hi,
Please could you advice, how can i write a regular expression for the
line below to capture 0079 and 69729260057253303030373
0079 Not Visible 69729260057253303030373
i tried this one, no luck
/(^\d{4})\s\w+\s\w+\s+\d+/ig)
What about
/^(\d+)\D+(\d+)$/ ?
Appreciate your help with this.
Not sure wether this is actually what you need, though
Sj
cheers
paolino
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Re: Regular expression help !!
2011/4/27 jet speed speedj...@googlemail.com: Hi, Please could you advice, how can i write a regular expression for the line below to capture 0079 and 69729260057253303030373 0079 Not Visible 69729260057253303030373 This might help? $ perl -le ' $str=0079 Not Visible 69729260057253303030373; @re = $str =~ /^(\d+).*?(\d+)$/; print @re' 0079 69729260057253303030373 -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular expression help !!
On 27/04/2011 11:47, jet speed wrote:
Please could you advice, how can i write a regular expression for the
line below to capture 0079 and 69729260057253303030373
0079 Not Visible 69729260057253303030373
i tried this one, no luck
/(^\d{4})\s\w+\s\w+\s+\d+/ig)
It works fine! You are simply not capturing the second sequence of
digits. This
use strict;
use warnings;
for ('0079 Not Visible 69729260057253303030373') {
print /(^\d{4})\s\w+\s\w+\s+(\d+)/ig ? $1 $2 : 'no match';
}
prints '0079 69729260057253303030373'.
But, depending on your data, there may be no need to match the line so
precisely. This does the same thing
use strict;
use warnings;
for ('0079 Not Visible 69729260057253303030373') {
my @n = (split)[0,-1];
print @n;
}
HTH,
Rob
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Re: Regular expression help !!
Hi all,
Thanks for all our inputs,
The regular expression below works fine if do it for single line, i am
trying to caputre the match $1, and $2 into array. only the first line
is pushed to the array. what am i doing wrong ?
how to get all the $1 and $2 match values for each line into arrary ?
Kindly advice.
# more wwnlist
0079 Not Visible 69729260057253303030373
007A Not Visible 69729260057253303030374
007B Not Visible 69729260057253303030374
007C Not Visible 69729260057253303030374
007D Not Visible 69729260057253303030374
007E Not Visible 69729260057253303030374
more wwnmod.pl
#!/usr/bin/perl
#0079 Not Visible 69729260057253303030373
open(FILE, wwnlist) || die Can't open wwnlist : $!\n;
while (FILE) {
if ($_=~/\b(\d{4})\s[a-z]{1,3}\s[a-z]{1,7}\s*(\d{1,32})\b/i) {
push (@dev, $1);
push (@wwn, $2);
}
}
print @dev \n;
print @wwn \n;
./wwnmod.pl
0079
69729260057253303030373
Regards
Sj
On 4/27/11, Rob Dixon rob.di...@gmx.com wrote:
On 27/04/2011 11:47, jet speed wrote:
Please could you advice, how can i write a regular expression for the
line below to capture 0079 and 69729260057253303030373
0079 Not Visible 69729260057253303030373
i tried this one, no luck
/(^\d{4})\s\w+\s\w+\s+\d+/ig)
It works fine! You are simply not capturing the second sequence of
digits. This
use strict;
use warnings;
for ('0079 Not Visible 69729260057253303030373') {
print /(^\d{4})\s\w+\s\w+\s+(\d+)/ig ? $1 $2 : 'no match';
}
prints '0079 69729260057253303030373'.
But, depending on your data, there may be no need to match the line so
precisely. This does the same thing
use strict;
use warnings;
for ('0079 Not Visible 69729260057253303030373') {
my @n = (split)[0,-1];
print @n;
}
HTH,
Rob
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Re: Regular expression help !!
On 4/27/11 Wed Apr 27, 2011 8:32 AM, jet speed
speedj...@googlemail.com scribbled:
Hi all,
Thanks for all our inputs,
The regular expression below works fine if do it for single line, i am
trying to caputre the match $1, and $2 into array. only the first line
is pushed to the array. what am i doing wrong ?
how to get all the $1 and $2 match values for each line into arrary ?
Kindly advice.
# more wwnlist
0079 Not Visible 69729260057253303030373
007A Not Visible 69729260057253303030374
007B Not Visible 69729260057253303030374
007C Not Visible 69729260057253303030374
007D Not Visible 69729260057253303030374
007E Not Visible 69729260057253303030374
more wwnmod.pl
#!/usr/bin/perl
#0079 Not Visible 69729260057253303030373
open(FILE, wwnlist) || die Can't open wwnlist : $!\n;
while (FILE) {
if ($_=~/\b(\d{4})\s[a-z]{1,3}\s[a-z]{1,7}\s*(\d{1,32})\b/i) {
push (@dev, $1);
push (@wwn, $2);
}
}
print @dev \n;
print @wwn \n;
./wwnmod.pl
0079
69729260057253303030373
[
The metasymbol \d matches the characters [0-9], not the extended hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
So your regular expression test will become:
if ($_=~/\b([0-9A-Z]{4})\s[a-z]{1,3}\s[a-z]{1,7}\s*(\d{1,32})\b/i) {
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Re: Regular expression help !!
On Wed, Apr 27, 2011 at 04:32:57PM +0100, jet speed wrote:
Hi all,
Thanks for all our inputs,
The regular expression below works fine if do it for single line, i am
trying to caputre the match $1, and $2 into array. only the first line
is pushed to the array. what am i doing wrong ?
how to get all the $1 and $2 match values for each line into arrary ?
Kindly advice.
# more wwnlist
0079 Not Visible 69729260057253303030373
007A Not Visible 69729260057253303030374
007B Not Visible 69729260057253303030374
007C Not Visible 69729260057253303030374
007D Not Visible 69729260057253303030374
007E Not Visible 69729260057253303030374
if ($_=~/\b(\d{4})\s[a-z]{1,3}\s[a-z]{1,7}\s*(\d{1,32})\b/i) {
\d doesn't match hex digits or, at least not all of them.
Instead of your first \d you could use [0-9A-F] which actually matches exactly
the characters you want. \d will also match many characters you probably
don't want to match, unfortunately.
However, I might be tempted to go with Rob's second solution, unless you are
sure each line matches that regexp exactly. And if you are, is it always Not
Visible in there, or can it really be any three and seven letter words? If
not, why not use Not Visible in your regexp?
--
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Re: Regular expression help !!
On 11-04-27 12:47 PM, Jim Gibson wrote:
The metasymbol \d matches the characters [0-9], not the extended hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
You can use the POSIX xdigit character class instead:
#!/usr/bin/env perl
use strict;
use warnings;
use Data::Dumper;
# Make Data::Dumper pretty
$Data::Dumper::Sortkeys = 1;
$Data::Dumper::Indent = 1;
# Set maximum depth for Data::Dumper, zero means unlimited
local $Data::Dumper::Maxdepth = 0;
while( DATA ){
my @hex_numbers = ( m{ ( [[:xdigit:]]+ ) }gmsx )[ 0, -1 ];
print '@hex_numbers: ', Dumper \@hex_numbers;
}
__DATA__
0079 Not Visible 69729260057253303030373
007A Not Visible 69729260057253303030374
007B Not Visible 69729260057253303030374
007C Not Visible 69729260057253303030374
007D Not Visible 69729260057253303030374
007E Not Visible 69729260057253303030374
See `perldoc perlreref` and search for /xdigit/
--
Just my 0.0002 million dollars worth,
Shawn
Confusion is the first step of understanding.
Programming is as much about organization and communication
as it is about coding.
The secret to great software: Fail early often.
Eliminate software piracy: use only FLOSS.
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Re: Regular expression help !!
On Wed, Apr 27, 2011 at 2:48 PM, Shawn H Corey shawnhco...@ncf.ca wrote:
On 11-04-27 12:47 PM, Jim Gibson wrote:
The metasymbol \d matches the characters [0-9], not the extended
hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
You can use the POSIX xdigit character class instead:
Or the Unicode character propriety[0] \p{Hex} (or \p{Hex_Digit} or whichever
form you prefer the most).
Or, since the data seems to always come in the same form, instead of using a
regex, you could pull out unpack [1]:
use 5.010;
while (DATA) {
say join ',', (unpack A5 A24 A*)[0,-1];
}
You can learn more about pack/unpack in perlpacktut[2]
Or you could use substr[3]:
while (DATA) {
chomp;
say join ',', substr($_, 0, 4), substr($_, 29);
}
Brian.
[0] http://perldoc.perl.org/perluniprops.html
[1] http://perldoc.perl.org/functions/unpack.html
[2] http://perldoc.perl.org/perlpacktut.html
[3] http://perldoc.perl.org/functions/substr.html
Re: Regular expression help !!
On 2011-04-27 18:47, Jim Gibson wrote: The metasymbol \d matches the characters [0-9], Beware: the \d matches 250+ code points. So don't use \d if you only mean [0-9]. not the extended hexadecimal set that includes A-Z. To match those, construct your own character class: [0-9A-Z] Or use [[:xdigit:]], though that also matches the lowercase a-f. (I assume that you meant A-F) -- Ruud -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular expression help !!
Excellent Guys, I would like thank each one of you for inputs. Much appreciated. i got blinded by just the numbers 0079, i didn't cater for the next line which is hex 007A, as one of you rightly pointed out [ 0-9A-Z] , does the trick. its amazing to see different technique to achieve the same result. Thanks again. Sj
Re: Regular expression help
DT == Dave Tang d.t...@imb.uq.edu.au writes: DT a,b,c,d,e,f1,f2,g1,g2 which spoil my split(/,/). DT Could someone provide some guidance? use a CSV module. parsing csv files is a pain with regexes (even if doable). there are very stable and fast csv modules on cpan so get one and use it. uri -- Uri Guttman -- u...@stemsystems.com http://www.sysarch.com -- - Perl Code Review , Architecture, Development, Training, Support -- - Gourmet Hot Cocoa Mix http://bestfriendscocoa.com - -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular expression help
On Wed, Aug 26, 2009 at 02:23, Dave Tangd.t...@imb.uq.edu.au wrote:
Dear list,
I am trying to import entries in a csv file into a relational database,
however there are entries such as:
a,b,c,d,e,f1,f2,g1,g2 which spoil my split(/,/).
snip
Sounds like a job for [Text::CSV][1]. Of course, you an always write
a quick parser:
#!/usr/bin/perl
use strict;
use warnings;
my $line = q/a,b,c,d,e,f1,f2,g1,g2/;
my $in_string;
my @rec = ();
for my $token ($line =~ /([,]|[^,]+)/g) {
if ($in_string) {
if ($token eq q//) {
$in_string = 0;
push @rec, ;
next;
}
} elsif ($token eq q/,/) {
push @rec, ;
next;
} elsif ($token eq q//) {
$in_string = 1;
next;
}
$rec[-1] .= $token;
}
print join(|, @rec), \n;
[1] : http://search.cpan.org/dist/Text-CSV/lib/Text/CSV.pm
--
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The most important skill a programmer can have is the ability to read.
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Re: Regular expression help
On Wed, 26 Aug 2009 16:41:39 +1000, Chas. Owens chas.ow...@gmail.com
wrote:
On Wed, Aug 26, 2009 at 02:23, Dave Tangd.t...@imb.uq.edu.au wrote:
Dear list,
I am trying to import entries in a csv file into a relational database,
however there are entries such as:
a,b,c,d,e,f1,f2,g1,g2 which spoil my split(/,/).
snip
Sounds like a job for [Text::CSV][1]. Of course, you an always write
a quick parser:
I did some searching on cpan as Uri suggested and decided on this module.
Thank you very much for the code! I have some questions on the code.
#!/usr/bin/perl
use strict;
use warnings;
my $line = q/a,b,c,d,e,f1,f2,g1,g2/;
my $in_string;
my @rec = ();
for my $token ($line =~ /([,]|[^,]+)/g) {
I changed the single pipe (|) to double pipes (||) and $token also
contained empty strings. Could you explain the difference between the
pipes?
if ($in_string) {
if ($token eq q//) {
$in_string = 0;
push @rec, ;
next;
}
} elsif ($token eq q/,/) {
push @rec, ;
next;
} elsif ($token eq q//) {
$in_string = 1;
next;
}
$rec[-1] .= $token;
Is this a commonly used method where you push empty values into an array
(if $token is a , or ) and append stuff to the last array element (which
is an empty string)?
}
print join(|, @rec), \n;
[1] : http://search.cpan.org/dist/Text-CSV/lib/Text/CSV.pm
Thanks again Chas.
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Re: Regular expression help
On Wed, Aug 26, 2009 at 03:46, Dave Tangd.t...@imb.uq.edu.au wrote:
snip
for my $token ($line =~ /([,]|[^,]+)/g) {
I changed the single pipe (|) to double pipes (||) and $token also contained
empty strings. Could you explain the difference between the pipes?
snip
The pipe character in regexes creates an alternation. An alternation
matches if one of the expressions matches. By adding another pipe,
you told the regex engine that it should match [,] or nothing or
[^,]. The empty strings you saw were the nothings being matched. I
can only assume you changed it to || out of some mistaken belief that
the pipe character in a regex is an or statement (like the ||
operator). While it does operator in a similar fashion, it is not an
or operator.
if ($in_string) {
if ($token eq q//) {
$in_string = 0;
push @rec, ;
next;
}
} elsif ($token eq q/,/) {
push @rec, ;
next;
} elsif ($token eq q//) {
$in_string = 1;
next;
}
$rec[-1] .= $token;
Is this a commonly used method where you push empty values into an array (if
$token is a , or ) and append stuff to the last array element (which is an
empty string)?
It is commonly used by me, I don't know about others. The string at
the end of the record array is not necessarily empty. In the case of
'foo,bar', the tokens are ('', foo, ,, bar, ''). This means
$rec[-1] starts empty (my @rec = ();), then foo is concatenated
onto it, then ,, then bar, finally it sees the second '' token
and pushes a new empty string onto the array. It looks like there is
a bug though. It should only push a new string onto the array when it
sees a comma.
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RE: regular expression help
Hi Irfan This code solve your problem my $p=\ProductName\ = \8:EXFO RTU System 1.2.42\; my ($val)=$p=~ m/\d+.\d+.(\d+)\/; my $inval=$val+1; $p=~s/$val/$inval/; print===$p\n; thanks Ajay -Original Message- From: Irfan Sayed [mailto:irfan_sayed2...@yahoo.com] Sent: Wednesday, June 17, 2009 4:10 PM To: beginners@perl.org Subject: regular expression help Hi All, need help on regular expression. i have string like this ProductName = 8:EXFO RTU System 1.2.42 now i want regular expression in such a way that it will change the line to : ProductName = 8:EXFO RTU System 1.2.43 i tried in the following way. $_ =~ s/:(.*)\s(.*)\s(.*)\s\d*.\d*.\d*/:(.*)\s(.*)\s(.*)\s$chver)/; where $chver is variable which contains value as 1.2.43 it is not giving result as exprected. plz advice regards irf -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: regular expression help
it is not just 1.2.43 it may be anything it may be like 2.3.56 or 2.0.12 and so on... plz advice From: Ajay Kumar ajay.kum...@synopsys.com To: Irfan Sayed irfan_sayed2...@yahoo.com Cc: beginners@perl.org beginners@perl.org Sent: Wednesday, June 17, 2009 5:01:41 PM Subject: RE: regular expression help Hi Irfan This code solve your problem my $p=\ProductName\ = \8:EXFO RTU System 1.2.42\; my ($val)=$p=~ m/\d+.\d+.(\d+)\/; my $inval=$val+1; $p=~s/$val/$inval/; print===$p\n; thanks Ajay -Original Message- From: Irfan Sayed [mailto:irfan_sayed2...@yahoo.com] Sent: Wednesday, June 17, 2009 4:10 PM To: beginners@perl.org Subject: regular expression help Hi All, need help on regular expression. i have string like this ProductName = 8:EXFO RTU System 1.2.42 now i want regular expression in such a way that it will change the line to : ProductName = 8:EXFO RTU System 1.2.43 i tried in the following way. $_ =~ s/:(.*)\s(.*)\s(.*)\s\d*.\d*.\d*/:(.*)\s(.*)\s(.*)\s$chver)/; where $chver is variable which contains value as 1.2.43 it is not giving result as exprected. plz advice regards irf -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: regular expression help
Irfan Sayed wrote: Hi All, Hello, need help on regular expression. i have string like this ProductName = 8:EXFO RTU System 1.2.42 now i want regular expression in such a way that it will change the line to : ProductName = 8:EXFO RTU System 1.2.43 $ perl -le' $_ = q[ProductName = 8:EXFO RTU System 1.2.42]; print; s/(\d+)(\D*)$/ $1 + 1 . $2 /e; print; ' ProductName = 8:EXFO RTU System 1.2.42 ProductName = 8:EXFO RTU System 1.2.43 John -- Those people who think they know everything are a great annoyance to those of us who do.-- Isaac Asimov -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
Re: Regular Expression Help
Ley, Chung wrote:
Hi,
I have a program that will take in a string that will resolve to a path
where the output is going to store.
The path can includes variables in this format %VariableName%.
The acceptable variableNames that the program will support are fixed to
a list such as Person, Class, Dept. This list may grow in the
future; but for now it is fixed.
So, some of the acceptable strings are:
C:\Windows\%Person%\%Class%
C:\MyHomeDir\%Dept%\%Person%
C:\MyHomeDir\%Dept%_%Person%
and etc...
I like to develop a validate method to return false when the string in
between the % pair don't belong to the acceptable list, and was trying
to do that with an expression.
- Look for the string that is in between the % by the closest pair.
- The % pair must start at the odd occurrence and finish on the
next even occurrence... Don't know how to describe this exactly, but
I don't want it to pack this up (InBetween) from this
(C:\MyHomeDir\%Dept%InBetween%Person) even though it is in between a %
pair.
- Then compare the string within the % pair to see if it belongs to
the acceptable list or not.
Is using a regular expression the right approach here? or I should just
iterate thru?
If the names are environment variable names, which is implied by your
syntax, then you can substitute the values of those variables as shown
in the program below.
HTH,
Rob
use strict;
use warnings;
my $str = '%windir%\system32';
$str =~ s/%(.*?)%/$ENV{uc $1}/g;
print $str;
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Re: Regular Expression Help
my $input =q(C:\Windows\%Person%\%Class%); my @vars = $input =~ /%([^%]+)%/g; local $, = $/; print @vars; On Tue, Apr 15, 2008 at 10:20 PM, Ley, Chung [EMAIL PROTECTED] wrote: Hi, I have a program that will take in a string that will resolve to a path where the output is going to store. The path can includes variables in this format %VariableName%. The acceptable variableNames that the program will support are fixed to a list such as Person, Class, Dept. This list may grow in the future; but for now it is fixed. So, some of the acceptable strings are: C:\Windows\%Person%\%Class% C:\MyHomeDir\%Dept%\%Person% C:\MyHomeDir\%Dept%_%Person% and etc... I like to develop a validate method to return false when the string in between the % pair don't belong to the acceptable list, and was trying to do that with an expression. - Look for the string that is in between the % by the closest pair. - The % pair must start at the odd occurrence and finish on the next even occurrence... Don't know how to describe this exactly, but I don't want it to pack this up (InBetween) from this (C:\MyHomeDir\%Dept%InBetween%Person) even though it is in between a % pair. - Then compare the string within the % pair to see if it belongs to the acceptable list or not. Is using a regular expression the right approach here? or I should just iterate thru? Thanks... --Chung Ley
RE: Regular Expression Help
Thank you! This looks much cleaner. From: Jialin Li [mailto:[EMAIL PROTECTED] Sent: Tuesday, April 15, 2008 8:56 PM To: Ley, Chung Cc: beginners@perl.org Subject: Re: Regular Expression Help my $input =q(C:\Windows\%Person%\%Class%); my @vars = $input =~ /%([^%]+)%/g; local $, = $/; print @vars; On Tue, Apr 15, 2008 at 10:20 PM, Ley, Chung [EMAIL PROTECTED] wrote: Hi, I have a program that will take in a string that will resolve to a path where the output is going to store. The path can includes variables in this format %VariableName%. The acceptable variableNames that the program will support are fixed to a list such as Person, Class, Dept. This list may grow in the future; but for now it is fixed. So, some of the acceptable strings are: C:\Windows\%Person%\%Class% C:\MyHomeDir\%Dept%\%Person% C:\MyHomeDir\%Dept%_%Person% and etc... I like to develop a validate method to return false when the string in between the % pair don't belong to the acceptable list, and was trying to do that with an expression. - Look for the string that is in between the % by the closest pair. - The % pair must start at the odd occurrence and finish on the next even occurrence... Don't know how to describe this exactly, but I don't want it to pack this up (InBetween) from this (C:\MyHomeDir\%Dept%InBetween%Person) even though it is in between a % pair. - Then compare the string within the % pair to see if it belongs to the acceptable list or not. Is using a regular expression the right approach here? or I should just iterate thru? Thanks... --Chung Ley
Re: Regular Expression Help
Ley, Chung wrote: Hi, Hello, I have a program that will take in a string that will resolve to a path where the output is going to store. The path can includes variables in this format %VariableName%. The acceptable variableNames that the program will support are fixed to a list such as Person, Class, Dept. This list may grow in the future; but for now it is fixed. If you know what the variable names will be in advance then you could use a regular expression like /%(?:Person|Class|Dept)%/. John -- Perl isn't a toolbox, but a small machine shop where you can special-order certain sorts of tools at low cost and in short order.-- Larry Wall -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: Regular Expression Help
Ashish Srivastava wrote:
I have a string which have multiple placeholder, for example:
$str = 'Hello [[Name]], Your login id is [[Login]] !!!;
I want to replace all placeholder with some identifier. In above example:
identifier are Name and Login.
The regular expression for this requirment is pretty staightward:
$str =~ s/\[\[([\d\w\-]+)\]\]/$1/g;
Now the problem is there could be Nested Placeholders. For example:
$str = 'Error is: id]]-[[message'
so in above example if idenfiers are defined as:
id = 1001
Message = Crash
1001-Crash = System overloaded
so output of my required regular expression for subsitution should be:
Error is: System overloaded
$ perl -le'
my %t = (
id = 1001,
message = Crash,
1001-Crash = System overloaded,
);
my $str = q/Error is: id]]-[[message/;
print $str;
1 while $str =~ s/\[\[([\w-]+)]]/$t{$1}/g;
print $str;
'
Error is: id]]-[[message
Error is: System overloaded
John
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Re: Regular Expression Help
Ashish ,
you might have the [ in a recurring sequence using [*
On 11/1/06, John W. Krahn [EMAIL PROTECTED] wrote:
Ashish Srivastava wrote:
I have a string which have multiple placeholder, for example:
$str = 'Hello [[Name]], Your login id is [[Login]] !!!;
I want to replace all placeholder with some identifier. In above
example: identifier are Name and Login.
The regular expression for this requirment is pretty staightward:
$str =~ s/\[\[([\d\w\-]+)\]\]/$1/g;
Now the problem is there could be Nested Placeholders. For example:
$str = 'Error is: id]]-[[message'
so in above example if idenfiers are defined as:
id = 1001
Message = Crash
1001-Crash = System overloaded
so output of my required regular expression for subsitution should be:
Error is: System overloaded
$ perl -le'
my %t = (
id = 1001,
message = Crash,
1001-Crash = System overloaded,
);
my $str = q/Error is: id]]-[[message/;
print $str;
1 while $str =~ s/\[\[([\w-]+)]]/$t{$1}/g;
print $str;
'
Error is: id]]-[[message
Error is: System overloaded
John
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Re: Regular Expression Help
Thank You John and Anshul for response. It was great help.
Regards,
Ashish Srivastava
- Original Message
From: Anshul Saxena [EMAIL PROTECTED]
To: John W. Krahn [EMAIL PROTECTED]
Cc: Perl Beginners beginners@perl.org
Sent: Wednesday, 1 November, 2006 11:01:38 PM
Subject: Re: Regular Expression Help
Ashish ,
you might have the [ in a recurring sequence using [*
On 11/1/06, John W. Krahn [EMAIL PROTECTED] wrote:
Ashish Srivastava wrote:
I have a string which have multiple placeholder, for example:
$str = 'Hello [[Name]], Your login id is [[Login]] !!!;
I want to replace all placeholder with some identifier. In above
example: identifier are Name and Login.
The regular expression for this requirment is pretty staightward:
$str =~ s/\[\[([\d\w\-]+)\]\]/$1/g;
Now the problem is there could be Nested Placeholders. For example:
$str = 'Error is: id]]-[[message'
so in above example if idenfiers are defined as:
id = 1001
Message = Crash
1001-Crash = System overloaded
so output of my required regular expression for subsitution should be:
Error is: System overloaded
$ perl -le'
my %t = (
id = 1001,
message = Crash,
1001-Crash = System overloaded,
);
my $str = q/Error is: id]]-[[message/;
print $str;
1 while $str =~ s/\[\[([\w-]+)]]/$t{$1}/g;
print $str;
'
Error is: id]]-[[message
Error is: System overloaded
John
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Re: regular expression help
Jonathan Weber wrote: Hi. I have some HTML files with lines like the following: a name=w12234 /a h2A Title/h2 I'm using a regular expression to find these and capture the name attribute (w12234 in the example) and the contents of the h2 tag (A Title). $_ =~ /a name=(w\d+)\s*\/a\s*h2(+)\/h2/ That's my regex, except I'm having trouble with the _ part. No matter what I seem to try, it won't match incidences where there's a newline somewhere in the string. I tried all manner of things, including [.\n], which if I understand correctly should match *everything*. I'm doing this on Windows; does the carriage return/line feed business have anything to do with this? Hi Jonathan. Some points: - The character wildcard '.' is just a dot within a character class, so [.\n] will match only a dot or a newline - The /s modifier will force '.' to match absolutely anything, including a newline. So you could write: $_ =~ /a name=(w\d+)\s*\/a\s*h2(.+)\/h2/s; but that isn't what you want as /.+/ will eat up all of the rest of the string until the last /h2 it finds. You could get away with /.+?/ but nicer is /[^]+/ which will match any number of any character except for an open angle bracket - If you're matching against $_ then you can omit it altogether: /a name=(w\d+)\s*\/a\s*h2(.+)\/h2/; does the same thing - Enclosing a regex in slashes allows you to omit an implied m// operator, which you have (i.e. /regex/ is the same as m/regex/). Putting the m back lets you use whatever delimiters you want, so you don't have to escape the contained slashes and can make it more readable: m#a name=(w\d+)\s*/a\s*h2([^]+)/h2#; - Regexes aren't the best way of parsing HTML, unless the document is very simple and predictable. Take a look at somthing like HTML::TreeBuilder if you're doing this a lot on varying or non-trivial documents. - This program does what you want: use strict; use warnings; my $string = HTML; a name=w12234 /a h2A Title/h2 HTML $string =~ m#a name=(w\d+)\s*/a\s*h2([^]+)/h2#; print $1, \n; print $2, \n; OUTPUT w12234 A Title I hope this helps. Rob -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: regular expression help
Jonathan Weber schreef: a name=w12234 /a h2A Title/h2 I'm using a regular expression to find these and capture the name attribute (w12234 in the example) and the contents of the h2 tag (A Title). $_ =~ /a name=(w\d+)\s*\/a\s*h2(+)\/h2/ That's my regex, except I'm having trouble with the _ part. No matter what I seem to try, it won't match incidences where there's a newline somewhere in the string. I tried all manner of things, including [.\n], which if I understand correctly should match *everything*. Not [.\n] (because that contains a literal dot), but (?:.|\n). Or do a s/\n/ /g first. But you don't need all that, see `perldoc perlre` about the s-modifier. And much better: use a proper HTML parser, see CPAN. -- Affijn, Ruud Gewoon is een tijger. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: regular expression help
On 24 Jul 2006, at 5:48 PM, Rob Dixon wrote: - The character wildcard '.' is just a dot within a character class, so [.\n] will match only a dot or a newline Ah, I hadn't realized that characters in [ ] are literals. That clears up a lot of the problem. - Regexes aren't the best way of parsing HTML, unless the document is very simple and predictable. Take a look at somthing like HTML::TreeBuilder if you're doing this a lot on varying or non-trivial documents. Yeah, I realize that it's not the best way to go about it, but I had many documents that were all the same, plus I figured this was a good excuse to learn regexes. Thanks for the help! Jonathan -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Regular expression help
On 4/25/05, John W. Krahn [EMAIL PROTECTED] wrote:
Owen wrote:
I found a message from Randal Schwartz, Message-ID:
[EMAIL PROTECTED]#1/1
which gave a regular expression for a valid Unix name,
/^(?=.*?\D)[a-z\d]+$/
That works but why does it work?
/
^ # Start of a string
(?=# 0 or 1 instance of
.*? # anything but a newline
\D # Non digit
) #
[a-z\d]+# All match a-z and any digit at
$ # End of a string
/
I tried breaking it down like above but it still doesn't say Must not be
all numbers and letters must be all lowercase
Any help in turning that re into plain words would be appreciated
(?=.*?\D) is a zero-width assertion so it doesn't affect the match which is
/^[a-z\d]+$/ -- match a string whose only characters are a-z0-9. When you add
the zero-width assertion it ensures that there is at least one \D character in
the match.
John
I think this may be part of the confusion, too:
(?=# 0 or 1 instance of
.*? # anything but a newline
/.*?/ is not that same as /.?/. /.?/ matches zero or 1 of any
character but the newline. /.*?/, however, matches zero or more, just
like /.*/. It's non-greedy, though, so it will stop matching at the
first occurance of \D instead of the last. In this case it boils down
roughly to /(?=[^\D]{0,}\D/.
HTH,
--jay
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RE: Regular expression help
Owen mailto:[EMAIL PROTECTED] wrote: : I found a message from Randal Schwartz, Message-ID: : [EMAIL PROTECTED]#1/1 : which gave a regular expression for a valid Unix name, : : /^(?=.*?\D)[a-z\d]+$/ : : That works but why does it work? : : / : ^ # Start of a string :(?=# 0 or 1 instance of (?=# Zero-width positive look ahead assertion. : .*? # anything but a newline :) # : : [a-z\d]+# All match a-z and any digit at [a-z\d]+# Match a-z (lowercase only) and any digit : $ # End of a string : / : : I tried breaking it down like above but it still doesn't say : Must not be all numbers and letters must be all lowercase : : Any help in turning that re into plain words would be : appreciated AFAIK, a (?= ... ) construct affects the contents of $, $`, and $'. Can you show any code immediately following this regular expression and the whole line with it? HTH, Charles K. Clarkson -- Mobile Homes Specialist 254 968-8328 -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: Regular expression help
Owen wrote: I found a message from Randal Schwartz, Message-ID: [EMAIL PROTECTED]#1/1 which gave a regular expression for a valid Unix name, /^(?=.*?\D)[a-z\d]+$/ That works but why does it work? / ^ # Start of a string (?= # 0 or 1 instance of .*? # anything but a newline \D # Non digit ) # [a-z\d]+ # All match a-z and any digit at $ # End of a string / I tried breaking it down like above but it still doesn't say Must not be all numbers and letters must be all lowercase Any help in turning that re into plain words would be appreciated (?=.*?\D) is a zero-width assertion so it doesn't affect the match which is /^[a-z\d]+$/ -- match a string whose only characters are a-z0-9. When you add the zero-width assertion it ensures that there is at least one \D character in the match. John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
Re: regular expression help
Stone [S], on Thursday, March 10, 2005 at 16:46 (-0800) typed:
S That won't work either. When you say ([1-9]\d?) you're telling it
S (If there is a match) capture the stuff in parentheses and store it.
S When you say \1 you're telling the script you know that first
S batch of stuff you captured? Well I want that here. But it's not
S the pattern, it's the literal substring of the match.
When I read your first line of reply, I realise, that you have right
again. Tomorrow was hard day for me, and also after some glassess of
wine I simply forget to some small details. And also I have to thank
you for nice and long explanation :) Ok, so I'm sorry, if I
confused someone, here is my explanation:
I don't like simple regular expressions, as was posted in first
message:
$field =~ /^[1-9]\d?\.[1-9]\d?\.[1-9]\d?$/;
that's too clear. I wanted change it (short), so I post 2 bad
examples. Clear shorting is:
$field =~ /^([1-9]\d?\.){2}[1-9]\d?$/;
but that's too much simple too :)
So let's continue how we can represent those rulez, this is a bit
tricky:
$field =~ /^([1-9]\d(?:\.[1-9]\d){2})$/;
and this is not shorter, but this way works too :):
$field =~ /^(?:(\d)(??{ $1 0 $1 = 9 ? : (?!) })\d\.){2}
(\d)(??{ $2 0 $2 = 9 ? : (?!) })\d/x;
Ok, that's enough, now we can benchmark all those:
use strict;
use warnings;
use Benchmark 'cmpthese';
my $field = '19.12.12';
cmpthese -5, {
simple = sub {
if ( $field =~ /^[1-9]\d?\.[1-9]\d?\.[1-9]\d?$/ ) {}
},
short = sub {
if ( $field =~ /^([1-9]\d\.){2}[1-9]\d$/ ) {}
},
shortwoc = sub {
if ( $field =~ /^(?:[1-9]\d\.){2}[1-9]\d$/ ) {}
},
tricky = sub {
if ( $field =~ /^([1-9]\d(?:\.[1-9]\d){2})$/ ) {}
},
trickywoc = sub {
if ( $field =~ /^(?:[1-9]\d(?:\.[1-9]\d){2})$/ ) {}
},
long = sub {
if ( $field =~ /^(?:(\d)(??{ $1 0 $1 = 9 ? : (?!)
})\d\.){2}
(\d)(??{ $2 0 $2 = 9 ? : (?!)
})\d/x ) {}
},
using_var = sub {
my $reg = '[1-9]\d';
if ( $field =~ /^(?:$reg\.){2}$reg$/ ) {}
}
};
__END__
Ratelong using_var short tricky simple shortwoc trickywoc
long30584/s -- -95%-95%-95%-98% -98% -98%
using_var 582064/s 1803%---11%-14%-56% -60% -62%
short 650382/s 2027% 12% -- -3%-51% -56% -58%
tricky 673134/s 2101% 16% 3% ---49% -54% -57%
simple1328337/s 4243% 128%104% 97% -- -10% -14%
shortwoc 1470620/s 4708% 153%126%118% 11% -- -5%
trickywoc 1550263/s 4969% 166%138%130% 17% 5%--
second benchmark:
my $field = '19.12.02';
Ratelong using_var shortwoc short simple tricky trickywoc
long28809/s -- -95% -98%-98%-98%-98% -98%
using_var 606756/s 2006%-- -63%-63%-64%-64% -66%
shortwoc 1627591/s 5550% 168% -- -1% -3% -5% -9%
short 1651154/s 5631% 172% 1% -- -2% -3% -8%
simple1681601/s 5737% 177% 3% 2% -- -2% -6%
tricky1707274/s 5826% 181% 5% 3% 2% -- -5%
trickywoc 1790738/s 6116% 195% 10% 8% 6% 5%--
so conlusion is: I definitely would pick up
tricky WithOut Capturing: $field =~ /^(?:[1-9]\d(?:\.[1-9]\d){2})$/
I hope I don't have any bugs here :)
Have a nice day.
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Re: regular expression help
I hope I don't have any bugs here :)
Just one. :)
Your expressions all say \d instead of \d? for the second digit in
each set, while the simple one correctly has \d?. So your
expressions had an unfair advantage and as a result finish faster.
Add \d? to your expressions, and you should find that simple,
besides probably being the easiest to read, is also the most efficient
of the expressions listed. (Note that I removed the obviously
inefficient ones.)
use strict;
use warnings;
use Benchmark 'cmpthese';
my $field = '19.12.12';
cmpthese -5, {
simple = sub {
if ( $field =~ /^[1-9]\d?\.[1-9]\d?\.[1-9]\d?$/ ) {}
},
short = sub {
if ( $field =~ /^([1-9]\d?\.){2}[1-9]\d?$/ ) {}
},
shortwoc = sub {
if ( $field =~ /^(?:[1-9]\d?\.){2}[1-9]\d?$/ ) {}
},
trickywoc = sub {
if ( $field =~ /^(?:[1-9]\d?(?:\.[1-9]\d?){2})$/ ) {}
},
};
__END__ Rate short shortwoc trickywocsimple
short 677138/s-- -23% -25% -40%
shortwoc 880536/s 30%-- -2% -22%
trickywoc 901095/s 33%2%-- -20%
simple1127127/s 66% 28% 25%--
second benchmark:
my $field = '19.12.02';
Rate short shortwoc trickywocsimple
short 927396/s-- -10% -12% -29%
shortwoc 1027728/s 11%-- -3% -22%
trickywoc 1055892/s 14%3%-- -19%
simple1310837/s 41% 28% 24%--
Have a nice day.
You too. I learned a lot from this, so thanks.
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Re: regular expression help
Stone [S], on Friday, March 11, 2005 at 01:52 (-0800) made these points: S Just one. :) S Your expressions all say \d instead of \d? for the second digit in S each set, while the simple one correctly has \d?. So your S expressions had an unfair advantage and as a result finish faster. right, forget about 1.1.1 rule :) S Add \d? to your expressions, and you should find that simple, S besides probably being the easiest to read, is also the most efficient S of the expressions listed. (Note that I removed the obviously S inefficient ones.) yes, and it is logical at end. The regexp using parentheses is always slower, than longer, which doesn't. It have to remember values inside them. thanks to you, I discover some new things too :) -- ...m8s, cu l8r, Brano. ['It takes a giant to fight a giant' - H. Prym] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ http://learn.perl.org/first-response
RE: regular expression help
CM Analyst wrote:
I am quite new to programming and Perl, so please bear
with me.
I have a requirement to check the format of a field
before a record can be saved. The format of the field
needs to be double digit value separated by a .
(period) like 00.00.00. This I managed to do using
the following:
use strict;
use warnings;
my $field;
print This program will verify field value.\n;
print Enter field value: ;
$field = STDIN;
chomp ($field);
if ( $field =~ /^[0-9]{2}\.[0-9]{2}\.[0-9]{2}$/ )
Simplest is change the {2} to {1,2} for all your entries. Now you mush
have from 1 to 2 digits.
Wags ;)
{
print Value is OK;
}
else
{
print Value is Wrong. Please enter a double digit
value like 00.00.00;
}
###
However, the requirement has changed in that we while
we want to allow the 00.00.00 format we do not a 0
(zero) to be a leading value.
How can this be accomplished?
Please advise.
Regards.
Amad
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Re: regular expression help
Simplest is change the {2} to {1,2} for all your entries. Now you
mush have from 1 to 2 digits.
Wags ;)
I think what he really wants is to throw a fit when there is a leading zero
for which your solution won't cut it. Here is how I see it:
$field =~ /^[1-9]\d?\.[1-9]\d?\.[1-9]\d?$/
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RE: regular expression help
Peter Rabbitson wrote:
Simplest is change the {2} to {1,2} for all your entries. Now you
mush have from 1 to 2 digits. Wags ;)
I think what he really wants is to throw a fit when there is a
leading zero for which your solution won't cut it. Here is how I see
it:
$field =~ /^[1-9]\d?\.[1-9]\d?\.[1-9]\d?$/
Correct. I missed read the msg.
Wags ;)
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Re: regular expression help
Peter Rabbitson [PR], on Thursday, March 10, 2005 at 14:00 (-0500)
wrote:
PR I think what he really wants is to throw a fit when there is a leading zero
PR for which your solution won't cut it. Here is how I see it:
PR $field =~ /^[1-9]\d?\.[1-9]\d?\.[1-9]\d?$/
yes, and for complexity:
$field =~ /^([1-9]\d?)\.{2}\1$/;
untested :)
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Re: regular expression help
yes, and for complexity:
$field =~ /^([1-9]\d?)\.{2}\1$/;
I know you said that's untested, but I don't think it's correct.
You're saying:
1. ^ - Start
2. ([1-9]\d?) -Any character 1-9 followed by zero or one digit characters.
3. \.{2} - Two periods.
4. \1 - The same sequence of characters as in #2. (\1 references the
actual parenthetical match, not the expression.)
5. $ - The end.
So your expression would match things like:
1..1
11..11
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Re: regular expression help
Stone [S], on Thursday, March 10, 2005 at 12:51 (-0800) wrote the
following:
yes, and for complexity:
$field =~ /^([1-9]\d?)\.{2}\1$/;
S I know you said that's untested, but I don't think it's correct.
yes, I'm sorry for that, should be this correct:
$field =~ /^(?:([1-9]\d?)\.){2}\1$/;
untested too :)
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Re: regular expression help
$field =~ /^(?:([1-9]\d?)\.){2}\1$/;
That won't work either. When you say ([1-9]\d?) you're telling it
(If there is a match) capture the stuff in parentheses and store it.
When you say \1 you're telling the script you know that first
batch of stuff you captured? Well I want that here. But it's not
the pattern, it's the literal substring of the match.
Let's simplify it a little bit and consider this example:
10.15 =~ /^([1-9]\d?)\.\1$/;
In this case it would not match. It works like this:
1. [1-9]\d? matches 10.
2. () stores that value 10 as \1 (or actually as $1, but within the
pattern you dereference it with \1). Note that it doesn't store the
pattern [1-9]\d?, but the actual substring 10. So at this point,
the \1 becomes 10 and looks like this:
/^[1-9]\d?\.10$/
Obviously 15 !~ 10, so there is no match.
You would use that if you wanted to find things like 1.1 or 10.10.
With your expression:
10.15.20 =~ /^(?:([1-9]\d?)\.){2}\1$/;
1. [1-9]\d? - Matches 10.
2. () - Stores 10 as $1.
3. Pattern now looks like /^(?:([1-9]\d?)\.){2}10$/
4. {2} - Requires a second match of (?:([1-9]\d?)\.).
5. [1-9]\d? - Matches 15.
6. () - Stores 15 as $1 (overwriting the previous value). (I may
be mistaken on what exactly happens here, but this is effectively the
case. If so, someone more knowledgable will hopefully correct me.)
7. Pattern now looks like /^(?:([1-9]\d?)\.){2}15$/
8. 20 !~ 15, so pattern does not match.
So your expression will match 10.10.10 or even 10.15.15, but it won't
match 10.15.20.
HTH
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Re: Regular expression help
snip
__DATA__
M:356 358 386 R:#132 W1:319 NRT:32 R:#132
snip
but I would really like it to capture the first part of the element so
that the result would be;
M:356 358 386 R:#132 W1:319 NRT:32 R:#132
$y[0]
$y[1] M 356 358 386
$y[2] R #132
$y[3] W1 319
$y[4] NRT 32
$y[5] R #132
I'd do a little add on for the string, so it much easier for split.
# usuw;
my $line = M:356 358 386 R:#132 W1:319 NRT:32 R:#132;
print $line . \n;
$line =~ s/(\s)(\w{1,}:)/\x00$2/g; # So I add extra delimiters here.
print $line . \n;
my @d = split /\x00/, $line;
print $_ for @d;
But only if you sure that char is not exist with the data string,
you can use. Otherwise, use other approach, or other delimiter.
Also, why is $y[0] undefined or null, scalar (@y) is 6.
I don't know how to tell, but I think you want \s , but not \b.
HTH,
Bee
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Re: Regular expression help
Bee wrote:
I'd do a little add on for the string, so it much easier for split.
# usuw;
my $line = M:356 358 386 R:#132 W1:319 NRT:32 R:#132;
print $line . \n;
$line =~ s/(\s)(\w{1,}:)/\x00$2/g; # So I add extra delimiters here.
print $line . \n;
my @d = split /\x00/, $line;
print $_ for @d;
But only if you sure that char is not exist with the data string,
you can use. Otherwise, use other approach, or other delimiter.
Other approaches:
my @y;
push @y, $1 $2 while $line =~ /(\w+):([^A-Z]+)(?: |$)/g;
or
my @y = map { tr/:/ /; $_ } $line =~ /(\w+:[^A-Z]+)(?: |$)/g;
Also, why is $y[0] undefined or null, scalar (@y) is 6.
That's explained in perldoc -f split.
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RE: Regular expression help
Hi Rob,
You are totally right your exemple (' data11 '' data12' 'data13') should
raise an error and this is normal. I will nethertheless look carefully for
the Text::CSV module.
Thanks
Michel
-Message d'origine-
De: Rob Anderson [mailto:[EMAIL PROTECTED]
Date: lundi 18 août 2003 17:34
À: [EMAIL PROTECTED]
Objet: Re: Regular expression help
Eurospace Szarindar [EMAIL PROTECTED] wrote in
message news:[EMAIL PROTECTED]
Thanks you, it works fine. Could you explain me why have you added the \1 ?
Hi,
A quick breakdown...
/(['])(((''|)|[^'])*?)\1(\s|$)/g
^^
1
2
^^
3
1) This is picking up either a single or double quote
2) This is scoping up any quotes pairs, and is being carefull not
to match quotes on thier own.
3) In a regex \1, \2 etc.. will match the same sequence of characters
matched
earlier in the same-numbered pair of parentheses, in this case, it means
that were making sure the opening and closing quotes are the same by
mathching
that same character as in part 1.
Explaining it like this has made me spot a problem. The regex you really
want is
m/(['])(((''|)|[^\1])*?)\1(\s|$)/g
This way our 'scoping up' part matches any paired quotes or anything other
than
our closing quote.
The following test data wouldn't have worked...
' data11 '' data12' 'data13'
I will have a look at Text::CSV
Please do, my mistake above shows you why you shouldn't reinvent this stuff
if you can
get away with it. :-)
Ta
Rob
Michel
-Message d'origine-
De: Rob Anderson [mailto:[EMAIL PROTECTED]
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Re: Regular expression help
Eurospace Szarindar [EMAIL PROTECTED] wrote in
message news:[EMAIL PROTECTED]
Hi,
I tried to write a script to extrat data from the given DATA but I can
find
the right regular expression to do that.
Hi Szarindar,
Firstly why are you using this format and trying to parse it yourself? If
you've got control of your data, use something like Text::CSV. The guy who
maintains your code will thank you for it.
otherwise, this seems to work (you'll have to print with $2 though)...
/(['])(((''|)|[^'])*?)\1(\s|$)/g
HTH
Rob Anderson
RULE: I need to catch everything between quotes (single or double) and if
inside exists a repeated quote (single or double) it is not seen as end of
the match.
#!/usr/bin/perl -w
use strict;
my $begin = '[\,\']'; #
my $end = '[\,\']'; #
my $pattern = ${begin}(.*?)${end}
while (DATA) {
print line content $_ \n
while ( /$pattern/g ){
print line $. found : $1\n
}
}
__DATA__
' data11 '' data12' 'data13'
data21 data22 data23
data31 '' data32 data34
data41 data42 data43 __--data44
'' ''
Result should be
1:( data11 '' data12)
2:(data13)
3:( data21 data22)
4:(data23)
5:(data31 '' data32)
6:()
7:(data34)
8:(data41)
9:(data42)
10:(data43)
11:(__--data44)
12:()
13:('')
14:()
15:('')
It could be resolved by replacing the \{2} or \'{2} by a [EMAIL PROTECTED] and
alterwards relacing it back to the previous value but it is not very
smart.
great thanks in advance
Michel
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RE: Regular expression help
Thanks you, it works fine. Could you explain me why have you added the \1 ?
I will have a look at Text::CSV
Michel
-Message d'origine-
De: Rob Anderson [mailto:[EMAIL PROTECTED]
Date: lundi 18 août 2003 16:39
À: [EMAIL PROTECTED]
Objet: Re: Regular expression help
Eurospace Szarindar [EMAIL PROTECTED] wrote in
message news:[EMAIL PROTECTED]
Hi,
I tried to write a script to extrat data from the given DATA but I can
find
the right regular expression to do that.
Hi Szarindar,
Firstly why are you using this format and trying to parse it yourself? If
you've got control of your data, use something like Text::CSV. The guy who
maintains your code will thank you for it.
otherwise, this seems to work (you'll have to print with $2 though)...
/(['])(((''|)|[^'])*?)\1(\s|$)/g
HTH
Rob Anderson
RULE: I need to catch everything between quotes (single or double) and if
inside exists a repeated quote (single or double) it is not seen as end of
the match.
#!/usr/bin/perl -w
use strict;
my $begin = '[\,\']'; #
my $end = '[\,\']'; #
my $pattern = ${begin}(.*?)${end}
while (DATA) {
print line content $_ \n
while ( /$pattern/g ){
print line $. found : $1\n
}
}
__DATA__
' data11 '' data12' 'data13'
data21 data22 data23
data31 '' data32 data34
data41 data42 data43 __--data44
'' ''
Result should be
1:( data11 '' data12)
2:(data13)
3:( data21 data22)
4:(data23)
5:(data31 '' data32)
6:()
7:(data34)
8:(data41)
9:(data42)
10:(data43)
11:(__--data44)
12:()
13:('')
14:()
15:('')
It could be resolved by replacing the \{2} or \'{2} by a [EMAIL PROTECTED] and
alterwards relacing it back to the previous value but it is not very
smart.
great thanks in advance
Michel
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Re: Regular expression help
Eurospace Szarindar [EMAIL PROTECTED] wrote in
message news:[EMAIL PROTECTED]
Thanks you, it works fine. Could you explain me why have you added the \1 ?
Hi,
A quick breakdown...
/(['])(((''|)|[^'])*?)\1(\s|$)/g
^^
1
2
^^
3
1) This is picking up either a single or double quote
2) This is scoping up any quotes pairs, and is being carefull not
to match quotes on thier own.
3) In a regex \1, \2 etc.. will match the same sequence of characters
matched
earlier in the same-numbered pair of parentheses, in this case, it means
that were making sure the opening and closing quotes are the same by
mathching
that same character as in part 1.
Explaining it like this has made me spot a problem. The regex you really
want is
m/(['])(((''|)|[^\1])*?)\1(\s|$)/g
This way our 'scoping up' part matches any paired quotes or anything other
than
our closing quote.
The following test data wouldn't have worked...
' data11 '' data12' 'data13'
I will have a look at Text::CSV
Please do, my mistake above shows you why you shouldn't reinvent this stuff
if you can
get away with it. :-)
Ta
Rob
Michel
-Message d'origine-
De: Rob Anderson [mailto:[EMAIL PROTECTED]
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RE: Regular Expression help
if($array[$x] =~ /\d{1,3}?/)
{
...do something
}
Unfortunately this if statement never appears to come true.
That's because you have two quantifiers specified, the {1,3} and the ?.
for (@array) {
if ( m/^\d+$/ ) { #regex breaks on decimal numbers
do something...
}
}
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RE: Regular Expression help
see my comments at bottom...
-Original Message-
From: Shaun Bramley [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, September 24, 2002 4:39 PM
To: [EMAIL PROTECTED]
Subject: Regular Expression help
Hi all.
I am hoping that someone can help me determine what is wronf with my regualr
expression.
background info: @array contains 'text', numbers, INT, or TINYINT.
I am trying to identify if the array element is a number.
What I have right now is:
if($array[$x] =~ /\d{1,3}?/)
{
.do something
}
Unfortunately this if statement never appears to come true.
thank you
Shaun
-Response Follows--
I'm not clear on what your problem is. Could you give some examples of what
in the array you want to do something, and some examples that you don't?
Perhaps show us more of the code than just the regexp?
I quickly wrote up the following code (using your regexp):
push @array,'1';
push @array,'xyzzy';
push @array,'1.234';
push @array,0x1234;
push @array,3;
for ($x=-1;$x++$#array;) {
if ($array[$x] =~ /\d{1,3}?/) {
print Yes:
} else {
print No :
}
print $array[$x].\n;
}
which produces:
Yes: 1
No : xyzzy
Yes: 1.234
Yes: 0x1234
Yes: 3
which appears to me to be correct.
/\/\ark
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RE: regular expression help....
David --- Senior Programmer Analyst --- Wgo Wagner wrote:
Your log shows a space between the time and hyphen and hyphen and
Micro. You dont' have that in the regex and even more so, there is no
hyphen before Adapter log.
You might want:
/^(\d\d-\d\d-\d{4})\s+(\d\d:\d\d:\d\d\.\d\d).+Adapter
log\s+(opened|closed)/i
Anchor with the ^ and you will have date in $1, time in $2 and
opened or closed in $3.
A shot.
Wags ;)
you can avoid putting tons of \d in your reg by using:
my($d,$t) = (split(/\s+/))[0,1];
print $d,$t\n;
__END__
but a reg. expression should be much faster.
david
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RE: regular expression help....
Your log shows a space between the time and hyphen and hyphen and
Micro. You dont' have that in the regex and even more so, there is no hyphen
before Adapter log.
You might want:
/^(\d\d-\d\d-\d{4})\s+(\d\d:\d\d:\d\d\.\d\d).+Adapter
log\s+(opened|closed)/i
Anchor with the ^ and you will have date in $1, time in $2 and
opened or closed in $3.
A shot.
Wags ;)
-Original Message-
From: Steve [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, September 11, 2002 08:12
To: [EMAIL PROTECTED]
Subject: regular expression help
I have the following line in a log file:
09-07-2002 11:39:25.95 - Microsoft Dial Up Adapter log opened.
The date and time will always change but the after that it's always
consistent (well opened will sometimes be closed) I need to get the entire
date in a variable and the entire time in a variable. I will compare the
difference between open and close and place THAT into a cumulative variable.
Anyway this the rexexp I have to get the date and time but it's not
matching:
/(\d\d-\d\d-\d{4}) (\d\d:\d\d:\d\d\.\d\d)-(Adapter log)/
Now if I just do it like /(Adapter log)/ I get a match on Adapter log,
which leads me to think that the problem is somewhere with my digit
matching.
Thanks
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Re: Regular Expression Help sought
s/((^|\n\n).+?)\n/$1 /g; s/ substitute ( put this is $1 (^ the start of the file | or \n\n) two newlines ..+? followed by 1 or more characters up until a ) stop putting it in $1 \n newline / with $1 /the text captured above followed by a space g;keep doing it until you can't match anymore Sunish Kapoor [EMAIL PROTECTED] 07/04/02 04:27pm Dear Katy, It works great after the changed the regular expression to as given by u below..! Thanks a ton for the help.but may I request for a small explanation of the line $file =~ s/((^|\n\n).+?)\n/$1 /g; Sunish Katy Brownfield wrote: Or, instead of changing the input file, change the regular expression to also detect the beginning of the string. $file =~ s/((^|\n\n).+?)\n/$1 /g; Katy Timothy Johnson wrote: I think you'll need 2 blank lines. -Original Message- From: Sunish Kapoor To: Nigel Peck Cc: [EMAIL PROTECTED] Sent: 7/3/02 6:51 PM Subject: Re: Regular Expression Help sought Dear Nigel, Thanks a ton for the script..It works fine though it skips the first record even though I make the file begin with a blank line by simply hitting enter ! Regards Sunish Nigel Peck wrote: My first attempt, which may be a bit simplified, would be to substitute any newline, which occured at the end of a line which was preceeded by 2 consecutive newlines, with a space. This relies on the format of the file being as shown for every company. It also may miss the first company in the file if the file doesn't start with a blank line. So undef $/; $file = FILE; $file =~ s/(\n\n.+?)\n/$1 /g; print $file; [untested] HTH Nigel [EMAIL PROTECTED] 07/03/02 10:52pm Hi All, I am new to Perl and need help to solve this one ! I have a txt file and the contents of the file are as below : ---CONTENTS OF TEXT FILE-- Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---CONTENTS OF TEXT FILE-- The names of three companies as above are: Abdullah Ahmed Hassan Trading Abu Ali Trading Cont Est Abu Al Dahab Trading Contg Est I want the data this way . ---DATA WANTED THIS WAY Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---DATA WANTED THIS WAY I want PERL to make the name of the company to come in one line as it has done for all three records. I request your help solving this. Regards Sunish Kapoor ITM Business Solutions Unit 4 Nine Trees Trading Estate Morthen Road Rotherham S66 9JG Reception Tel: 01709 703288 Fax: 01709 701549 Help Desk Tel:01709 530424 Fax: 01709 702159 CONFIDENTIALITY NOTICE: This message is intended only for the use of the individual or entity to which it is addressed, and may contain information that is privileged, confidential and exempt from disclosure under applicable law. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED
Re: Regular Expression Help sought
One thing I would add is that the inner pair of parentheses is used to isolate ^|\n\n from the rest of the pattern so it is clear what the | is operating on. /cat|blue fish/ matches cat or blue fish but /(cat|blue) fish/ matches cat fish or blue fish. (The parentheses also capture the thing that was matched in $2, but we don't need it. (?:^|\n\n) would prevent it from capturing the match, but capturing doesn't hurt anything in this case and the pattern is easier to read.) Katy Nigel Peck wrote: s/((^|\n\n).+?)\n/$1 /g; s/ substitute ( put this is $1 (^ the start of the file | or \n\n) two newlines ..+? followed by 1 or more characters up until a ) stop putting it in $1 \n newline / with $1 /the text captured above followed by a space g;keep doing it until you can't match anymore Sunish Kapoor [EMAIL PROTECTED] 07/04/02 04:27pm Dear Katy, It works great after the changed the regular expression to as given by u below..! Thanks a ton for the help.but may I request for a small explanation of the line $file =~ s/((^|\n\n).+?)\n/$1 /g; Sunish Katy Brownfield wrote: Or, instead of changing the input file, change the regular expression to also detect the beginning of the string. $file =~ s/((^|\n\n).+?)\n/$1 /g; Katy Timothy Johnson wrote: I think you'll need 2 blank lines. -Original Message- From: Sunish Kapoor To: Nigel Peck Cc: [EMAIL PROTECTED] Sent: 7/3/02 6:51 PM Subject: Re: Regular Expression Help sought Dear Nigel, Thanks a ton for the script..It works fine though it skips the first record even though I make the file begin with a blank line by simply hitting enter ! Regards Sunish Nigel Peck wrote: My first attempt, which may be a bit simplified, would be to substitute any newline, which occured at the end of a line which was preceeded by 2 consecutive newlines, with a space. This relies on the format of the file being as shown for every company. It also may miss the first company in the file if the file doesn't start with a blank line. So undef $/; $file = FILE; $file =~ s/(\n\n.+?)\n/$1 /g; print $file; [untested] HTH Nigel [EMAIL PROTECTED] 07/03/02 10:52pm Hi All, I am new to Perl and need help to solve this one ! I have a txt file and the contents of the file are as below : ---CONTENTS OF TEXT FILE-- Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---CONTENTS OF TEXT FILE-- The names of three companies as above are: Abdullah Ahmed Hassan Trading Abu Ali Trading Cont Est Abu Al Dahab Trading Contg Est I want the data this way . ---DATA WANTED THIS WAY Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---DATA WANTED THIS WAY I want PERL to make the name of the company to come in one line as it has done for all three records. I request your help solving this. Regards Sunish Kapoor ITM Business Solutions Unit 4 Nine Trees Trading Estate Morthen Road Rotherham S66 9JG
Re: Regular Expression Help sought
Dear Nigel, Thanks a ton for the script..It works fine though it skips the first record even though I make the file begin with a blank line by simply hitting enter ! Regards Sunish Nigel Peck wrote: My first attempt, which may be a bit simplified, would be to substitute any newline, which occured at the end of a line which was preceeded by 2 consecutive newlines, with a space. This relies on the format of the file being as shown for every company. It also may miss the first company in the file if the file doesn't start with a blank line. So undef $/; $file = FILE; $file =~ s/(\n\n.+?)\n/$1 /g; print $file; [untested] HTH Nigel [EMAIL PROTECTED] 07/03/02 10:52pm Hi All, I am new to Perl and need help to solve this one ! I have a txt file and the contents of the file are as below : ---CONTENTS OF TEXT FILE-- Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---CONTENTS OF TEXT FILE-- The names of three companies as above are: Abdullah Ahmed Hassan Trading Abu Ali Trading Cont Est Abu Al Dahab Trading Contg Est I want the data this way . ---DATA WANTED THIS WAY Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---DATA WANTED THIS WAY I want PERL to make the name of the company to come in one line as it has done for all three records. I request your help solving this. Regards Sunish Kapoor ITM Business Solutions Unit 4 Nine Trees Trading Estate Morthen Road Rotherham S66 9JG Reception Tel: 01709 703288 Fax: 01709 701549 Help Desk Tel:01709 530424 Fax: 01709 702159 CONFIDENTIALITY NOTICE: This message is intended only for the use of the individual or entity to which it is addressed, and may contain information that is privileged, confidential and exempt from disclosure under applicable law. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: Regular Expression Help sought
I think you'll need 2 blank lines. -Original Message- From: Sunish Kapoor To: Nigel Peck Cc: [EMAIL PROTECTED] Sent: 7/3/02 6:51 PM Subject: Re: Regular Expression Help sought Dear Nigel, Thanks a ton for the script..It works fine though it skips the first record even though I make the file begin with a blank line by simply hitting enter ! Regards Sunish Nigel Peck wrote: My first attempt, which may be a bit simplified, would be to substitute any newline, which occured at the end of a line which was preceeded by 2 consecutive newlines, with a space. This relies on the format of the file being as shown for every company. It also may miss the first company in the file if the file doesn't start with a blank line. So undef $/; $file = FILE; $file =~ s/(\n\n.+?)\n/$1 /g; print $file; [untested] HTH Nigel [EMAIL PROTECTED] 07/03/02 10:52pm Hi All, I am new to Perl and need help to solve this one ! I have a txt file and the contents of the file are as below : ---CONTENTS OF TEXT FILE-- Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---CONTENTS OF TEXT FILE-- The names of three companies as above are: Abdullah Ahmed Hassan Trading Abu Ali Trading Cont Est Abu Al Dahab Trading Contg Est I want the data this way . ---DATA WANTED THIS WAY Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---DATA WANTED THIS WAY I want PERL to make the name of the company to come in one line as it has done for all three records. I request your help solving this. Regards Sunish Kapoor ITM Business Solutions Unit 4 Nine Trees Trading Estate Morthen Road Rotherham S66 9JG Reception Tel: 01709 703288 Fax: 01709 701549 Help Desk Tel:01709 530424 Fax: 01709 702159 CONFIDENTIALITY NOTICE: This message is intended only for the use of the individual or entity to which it is addressed, and may contain information that is privileged, confidential and exempt from disclosure under applicable law. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Regular Expression Help sought
Or, instead of changing the input file, change the regular expression to also detect the beginning of the string. $file =~ s/((^|\n\n).+?)\n/$1 /g; Katy Timothy Johnson wrote: I think you'll need 2 blank lines. -Original Message- From: Sunish Kapoor To: Nigel Peck Cc: [EMAIL PROTECTED] Sent: 7/3/02 6:51 PM Subject: Re: Regular Expression Help sought Dear Nigel, Thanks a ton for the script..It works fine though it skips the first record even though I make the file begin with a blank line by simply hitting enter ! Regards Sunish Nigel Peck wrote: My first attempt, which may be a bit simplified, would be to substitute any newline, which occured at the end of a line which was preceeded by 2 consecutive newlines, with a space. This relies on the format of the file being as shown for every company. It also may miss the first company in the file if the file doesn't start with a blank line. So undef $/; $file = FILE; $file =~ s/(\n\n.+?)\n/$1 /g; print $file; [untested] HTH Nigel [EMAIL PROTECTED] 07/03/02 10:52pm Hi All, I am new to Perl and need help to solve this one ! I have a txt file and the contents of the file are as below : ---CONTENTS OF TEXT FILE-- Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---CONTENTS OF TEXT FILE-- The names of three companies as above are: Abdullah Ahmed Hassan Trading Abu Ali Trading Cont Est Abu Al Dahab Trading Contg Est I want the data this way . ---DATA WANTED THIS WAY Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---DATA WANTED THIS WAY I want PERL to make the name of the company to come in one line as it has done for all three records. I request your help solving this. Regards Sunish Kapoor ITM Business Solutions Unit 4 Nine Trees Trading Estate Morthen Road Rotherham S66 9JG Reception Tel: 01709 703288 Fax: 01709 701549 Help Desk Tel:01709 530424 Fax: 01709 702159 CONFIDENTIALITY NOTICE: This message is intended only for the use of the individual or entity to which it is addressed, and may contain information that is privileged, confidential and exempt from disclosure under applicable law. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Regular Expression Help sought
Dear Katy, It works great after the changed the regular expression to as given by u below..! Thanks a ton for the help.but may I request for a small explanation of the line $file =~ s/((^|\n\n).+?)\n/$1 /g; Sunish Katy Brownfield wrote: Or, instead of changing the input file, change the regular expression to also detect the beginning of the string. $file =~ s/((^|\n\n).+?)\n/$1 /g; Katy Timothy Johnson wrote: I think you'll need 2 blank lines. -Original Message- From: Sunish Kapoor To: Nigel Peck Cc: [EMAIL PROTECTED] Sent: 7/3/02 6:51 PM Subject: Re: Regular Expression Help sought Dear Nigel, Thanks a ton for the script..It works fine though it skips the first record even though I make the file begin with a blank line by simply hitting enter ! Regards Sunish Nigel Peck wrote: My first attempt, which may be a bit simplified, would be to substitute any newline, which occured at the end of a line which was preceeded by 2 consecutive newlines, with a space. This relies on the format of the file being as shown for every company. It also may miss the first company in the file if the file doesn't start with a blank line. So undef $/; $file = FILE; $file =~ s/(\n\n.+?)\n/$1 /g; print $file; [untested] HTH Nigel [EMAIL PROTECTED] 07/03/02 10:52pm Hi All, I am new to Perl and need help to solve this one ! I have a txt file and the contents of the file are as below : ---CONTENTS OF TEXT FILE-- Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---CONTENTS OF TEXT FILE-- The names of three companies as above are: Abdullah Ahmed Hassan Trading Abu Ali Trading Cont Est Abu Al Dahab Trading Contg Est I want the data this way . ---DATA WANTED THIS WAY Abdullah Ahmed Hassan Trading Location Ruwi Souk St, Ruwi Bus Hrs 0930-1300:1630-2200 P.O. Box 197 Ruwi Code 112 Phone 708940 Fax 794156 Key Staff Abdullah Ahmed Hassan Mohammad Hussain Ahmed Hassan Irfan Ahmed Mohammad Asim Activities :3410 Email : [EMAIL PROTECTED] Abu Ali Trading Cont Est Location Azaiba B us H rs 0700-1200; 1500-1900 P.O. Box 1695 C. P. 0. Code 111 Phone 595324 Key Staff K. Sasi, Prop Ali Suleiman Al Ghubshi, Sponsor Activities 2700 Abu Al Dahab Trading Contg Est Location 23rd July St, Opp Al Ghobish Furniture Showroom Bus Hrs 0800-1300 (Sat-Thu); 1600-1900 (Sat- Fri) P.O. Box 1254 Salalah Code 211 Phone 297879 Fax 297879 Key Staff Syed Tajudeen Madani, Gen Mgr Activities 2660 ---DATA WANTED THIS WAY I want PERL to make the name of the company to come in one line as it has done for all three records. I request your help solving this. Regards Sunish Kapoor ITM Business Solutions Unit 4 Nine Trees Trading Estate Morthen Road Rotherham S66 9JG Reception Tel: 01709 703288 Fax: 01709 701549 Help Desk Tel:01709 530424 Fax: 01709 702159 CONFIDENTIALITY NOTICE: This message is intended only for the use of the individual or entity to which it is addressed, and may contain information that is privileged, confidential and exempt from disclosure under applicable law. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Regular Expression Help
On Feb 5, David Mamanakis said:
I am building a parsing routine, and am using a regular expression, which
works, EXCEPT when I need to EXCLUDE certain things...
$right =~ s/A/X/g;
However, I may need to exclude this replacement in some of the values of
$right...
Anything found between and SHOULD NOT be replaced. \.*\
Anything found between and ; SHOULD NOT be replaced. \.*\;
Anything found between {$ and } SHOULD NOT be replaced. \{$.*\}
Anything found between and = SHOULD NOT be replaced. \.*\=
Here's a crafty trick (from DALnet #perl a couple of minutes ago)...
$text =~ m{(.*?|.*?;|{\$.*?}|.*?=)|A}{$1 || X}seg;
Basically, if it's a special case, it's matched and put in $1, and if it's
A, it's matched but $1 is undefined. Then, on the right-hand side, we
use $1 if it has a value, and X otherwise.
The /s is so that . matches newlines, the /e is so that $1 || X is
evaluated as code, and the /g is for all matches.
It kinda sounds like you're working with HTML and some template thing,
though... you might want to use a full HTML parser instead.
--
Jeff japhy Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for Regular Expressions in Perl published by Manning, in 2002 **
stu what does y/// stand for? tenderpuss why, yansliterate of course.
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Re: Regular Expression Help
Jeff 'Japhy' Pinyan wrote:
On Feb 5, David Mamanakis said:
I am building a parsing routine, and am using a regular expression, which
works, EXCEPT when I need to EXCLUDE certain things...
$right =~ s/A/X/g;
However, I may need to exclude this replacement in some of the values of
$right...
Anything found between and SHOULD NOT be replaced. \.*\
Anything found between and ; SHOULD NOT be replaced. \.*\;
Anything found between {$ and } SHOULD NOT be replaced. \{$.*\}
Anything found between and = SHOULD NOT be replaced. \.*\=
Here's a crafty trick (from DALnet #perl a couple of minutes ago)...
$text =~ m{(.*?|.*?;|{\$.*?}|.*?=)|A}{$1 || X}seg;
^
^
s
Basically, if it's a special case, it's matched and put in $1, and if it's
A, it's matched but $1 is undefined. Then, on the right-hand side, we
use $1 if it has a value, and X otherwise.
The /s is so that . matches newlines, the /e is so that $1 || X is
evaluated as code, and the /g is for all matches.
It kinda sounds like you're working with HTML and some template thing,
though... you might want to use a full HTML parser instead.
John
--
use Perl;
program
fulfillment
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Re: Regular Expression Help
On Feb 5, John W. Krahn said:
Jeff 'Japhy' Pinyan wrote:
$text =~ m{(.*?|.*?;|{\$.*?}|.*?=)|A}{$1 || X}seg;
^
^
s
Sorry, thanks for the correction. :)
--
Jeff japhy Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for Regular Expressions in Perl published by Manning, in 2002 **
stu what does y/// stand for? tenderpuss why, yansliterate of course.
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RE: regular expression help
Escape the brackets like so. s/\(locked\)//; John -Original Message- From: David Samuelsson (PAC) [mailto:[EMAIL PROTECTED]] Sent: 22 January 2002 09:37 To: '[EMAIL PROTECTED]' Subject: regular expression help Hello! if i have this line ROXETTE_PC_SW_R1D08 (locked) and just want to remove the (locked) part from it with an regexp how would that look? i can do: s/(locked)// that leaves the pesky () how can i get rid off those? //Dave -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] --Confidentiality--. This E-mail is confidential. It should not be read, copied, disclosed or used by any person other than the intended recipient. Unauthorised use, disclosure or copying by whatever medium is strictly prohibited and may be unlawful. If you have received this E-mail in error please contact the sender immediately and delete the E-mail from your system. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: regular expression help
Try: s/\s+\(locked\)// The parens are meta-symbols in regexes and need to be escaped if you want to match them. The above will additionally make sure that the blanks before (locked) are also removed. HTH, Marcus | -Original Message- | From: David Samuelsson (PAC) [mailto:[EMAIL PROTECTED]] | Sent: Tuesday, January 22, 2002 10:37 AM | To: '[EMAIL PROTECTED]' | Subject: regular expression help | | | Hello! | | if i have this line ROXETTE_PC_SW_R1D08 (locked) | | and just want to remove the (locked) part from it with an | regexp how would that look? | | i can do: s/(locked)// that leaves the pesky () how can i | get rid off those? | | //Dave | | | | | -- | To unsubscribe, e-mail: [EMAIL PROTECTED] | For additional commands, e-mail: [EMAIL PROTECTED] | -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: regular expression help
| Hello! | | If I have this line ROXETTE_PC_SW_R1D08 (locked) | and just want to remove the (locked) part from it | with an regexp how would that look? | | I can do: s/(locked)// that leaves the pesky () how | can I get rid off those? Try: s/\s+\(locked\)// The parens are meta-symbols in regexes and need to be escaped if you want to match them. The above will additionally make sure that the blanks before (locked) are also removed. Hi, The input looks something like: ROXETTE_PC_SW_R1D08 (locked) you *might* consider just taking the leftmost characters. In a regex that'd look like: my ($symbol) = /^(\w*)/; Jonathan Paton __ Do You Yahoo!? Everything you'll ever need on one web page from News and Sport to Email and Music Charts http://uk.my.yahoo.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: Regular expression help!!
Hi You can try the following: $line = insert_job: DUKS_rtcf_daily_log_purge job_type: c; ($rest) = $line =~ m/(\W\w.*)/; Regards Robert -Original Message- From: Woz [mailto:[EMAIL PROTECTED]] Sent: 25 October 2001 11:17 To: [EMAIL PROTECTED] Subject: Regular expression help!! Hi, I'm relatively new to the wonders of Perl programming and I've yet to quite get my head around regular expressions. I'm attempting to generate a search and replace expression that will turn the following string insert_job: DUKS_rtcf_daily_log_purge job_type: c into DUKS_rtcf_daily_log_purge job_type: c i.e. remove from the beginning of the line up the space following the first : All my efforts so far remove upto the second : though and leave just 'c'. Any ideas? Any help much appreciated! Thanks, Warren -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: Regular expression help!!
Wow, that was fast! Thanks very much, that works well. For my next question (:-)) how can I make it strip the leading space that it leaves on the resulting string. i.e. I want it to strip 'insert_job: ' from the string - note the trailing space. At the moment I have: - ($Value)=$_=~m/(\W\w\S.*)/; ($Value)=$Value=~m/(\S.*)/; but I'm sure there's a far more elegant solution that combines it all into one. Many many thanks for your help. Warren note to self - buy O'Reillys book on regular expressions! -Original Message- From: Robert Graham Sent: Thu 25/10/2001 10:27 To: Woz; [EMAIL PROTECTED] Cc: Subject: RE: Regular expression help!! Hi You can try the following: $line = insert_job: DUKS_rtcf_daily_log_purge job_type: c; ($rest) = $line =~ m/(\W\w.*)/; Regards Robert -Original Message- From: Woz [mailto:[EMAIL PROTECTED]] Sent: 25 October 2001 11:17 To: [EMAIL PROTECTED] Subject: Regular expression help!! Hi, I'm relatively new to the wonders of Perl programming and I've yet to quite get my head around regular expressions. I'm attempting to generate a search and replace expression that will turn the following string insert_job: DUKS_rtcf_daily_log_purge job_type: c into DUKS_rtcf_daily_log_purge job_type: c i.e. remove from the beginning of the line up the space following the first : All my efforts so far remove upto the second : though and leave just 'c'. Any ideas? Any help much appreciated! Thanks, Warren -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: Regular expression help!!
You can use the following to remove the space in front $Value =~ /s/^\s+//; And for the sake of interest $Value =~ s/\s+$//; will remove any trailing spaces from a string Regards Robert Graham -Original Message- From: Woz [mailto:[EMAIL PROTECTED]] Sent: 25 October 2001 12:04 To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: RE: Regular expression help!! Wow, that was fast! Thanks very much, that works well. For my next question (:-)) how can I make it strip the leading space that it leaves on the resulting string. i.e. I want it to strip 'insert_job: ' from the string - note the trailing space. At the moment I have: - ($Value)=$_=~m/(\W\w\S.*)/; ($Value)=$Value=~m/(\S.*)/; but I'm sure there's a far more elegant solution that combines it all into one. Many many thanks for your help. Warren note to self - buy O'Reillys book on regular expressions! -Original Message- From: Robert Graham Sent: Thu 25/10/2001 10:27 To: Woz; [EMAIL PROTECTED] Cc: Subject: RE: Regular expression help!! Hi You can try the following: $line = insert_job: DUKS_rtcf_daily_log_purge job_type: c; ($rest) = $line =~ m/(\W\w.*)/; Regards Robert -Original Message- From: Woz [ mailto:[EMAIL PROTECTED] mailto:[EMAIL PROTECTED] ] Sent: 25 October 2001 11:17 To: [EMAIL PROTECTED] Subject: Regular expression help!! Hi, I'm relatively new to the wonders of Perl programming and I've yet to quite get my head around regular expressions. I'm attempting to generate a search and replace expression that will turn the following string insert_job: DUKS_rtcf_daily_log_purge job_type: c into DUKS_rtcf_daily_log_purge job_type: c i.e. remove from the beginning of the line up the space following the first : All my efforts so far remove upto the second : though and leave just 'c'. Any ideas? Any help much appreciated! Thanks, Warren -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Regular Expression Help
Stephan == Stephan Gross [EMAIL PROTECTED] writes:
Stephan I'm matching a SQL date like this:
Stephan$ftime =~ /(\d+)-(\d+)-(\d+)\s+(\d+):(\d+):(\d+)/;
Stephan If $ftime is 2001-05-13 11:53:00, then $1 is 2001, $2 is 05, etc.
Stephan However, I also want to match if the user types in a partial string. For
Stephan example, if $ftime is 2001-12-18, I want $1, $2 and $3 to be 2001, 12
Stephan and 18 but $4 to be null. In reality, my regex fails entirely and $1 is
Stephan null.
Stephan How can I get $1, $2, $3, $4, $5 and $6 to contain as many matches as my
Stephan input string has? Do I have to use 6 separate regexes?
if (my @matches = grep defined, $ftime =~
/(\d+)(?:-(\d+)(?:-(\d+)(?:\s+(\d+)(?::(\d+)(?::(\d+))?)?)?)?)?/) {
... $matches[0]..$matches[6] are now set as many as are defined...
}
Your first example was broken in that you weren't testing the overall
match, and if that had failed, you would have gotten the *previous* match.
Bad News.
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