Re: display last 5 inserted image

2011-09-16 Thread Sivaramakrishnan S
Hi,
  I need to create the multitab tab using css in cakephp, How to create
that in cakephp

Thanks in advance,
shiva

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Re: Haml and sass in CakePHP

2011-09-16 Thread Walther
CakePHP isn't modeled after Ruby (Or Ruby on Rails). It is simply a
PHP framework that follows the MVC architecture, and Ruby on Rails is
a Ruby framework that also follows the MVC architecture. That is
pretty much their only simularity.

Perhaps you could be better helped if you actually added what warnings
and notices you get. People can't guess them out of the blue.

Also, remember that quite a bit has changed in CakePHP 2.0, so unless
that plugin has been specifically modified for CakePHP 2.0, you are
going to need to follow the migration guide to change it to work with
2.0.

On Sep 16, 3:56 am, Chris Cinelli
chris.cine...@formativelearning.com wrote:
 I forgot to mention that I tried to follow the instruction here 
 :https://github.com/goncaloesteves/phamlp/blob/master/Cake/Installatio...
 And I even substitute var $view = 'Haml'; = var $viewClass = 'Haml';

 But cake give warning and notice later.

 On Thu, Sep 15, 2011 at 6:28 PM, Chris Cinelli 







 chris.cine...@formativelearning.com wrote:
  I think almost everybody familiar with Ruby knows:
 http://haml-lang.com/
  and
 http://sass-lang.com/

  Since CakePHP is modeled  after Ruby and in the spirit of having to write
  less code with more syntactic juice it would be great to have them in cake.

  Fortunately someone already though to that. So here is this great piece of
  code that has CakePHP extension:
 https://github.com/goncaloesteves/phamlp

  But following the instruction in the Cake folder does not make it work in
  Cake 2.0.
  Someone know how to solve the problem?

  On a side node, I think that it would be great to add it to Cake as a
  default plugin. Ruby 3.1 added sass with compass (
 http://compass-style.org/) as default.

  Best,
     Chris

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Re: filtering model result bases on user rights

2011-09-16 Thread WebbedIT
Can you give us an overview of how you have declared the relationships
of those 4 tables?  I.e. r u using HABTM or hasMany - belongsTo?

On Sep 16, 4:28 am, Zaky Katalan-Ezra procsh...@gmail.com wrote:
 For the list result you join docs and docs token and check that the user
 tokens are IN the join result.
 To prevent url changes I suggest
 1. use uuid as document id.
 2. Create a function in the database that take user_id and doc_id and return
 true/false
 Call this function in  documents/view or edit.









 On Thu, Sep 15, 2011 at 5:59 PM, Timmay tim.smi...@gmail.com wrote:
  the example I gave is a simplified version of the real situation.

  The real situation is that a user has two sets of tokens (lets say A
  and B).
  These properties are stored in another table, named user_tokens.

  A document also has two sets of tokens (lets also call them A and B).
  These properties are stored in a table 'document_tokens'.

  A user is allowed to see the document if:
  the user and the document have at least one token in set A in common
  and
  the user and the document have at least one token in set B in common.

  On Sep 15, 10:42 am, Zaky Katalan-Ezra procsh...@gmail.com wrote:
   How do you save the permissions in the database?

   On Thu, Sep 15, 2011 at 10:53 AM, Timmay tim.smi...@gmail.com wrote:
Hi all,

I'm working on a multi user website with a collection of documents.
Every user is only allowed to see a subset of the documents.

I want the Documents model to only return the documents that a user is
allowed to see.
If a users requests one particular document, and he doesn't have
rights to see the document (e.g. he modified the url), I want the
model to return nothing.

Is there an easy way to achieve this?

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Re: CakeFest 2011

2011-09-16 Thread Walther
Octavian, I spoke with Larry the other day. He has something like 44
videos to transcode, edit and upload. It is going to take a while, but
it will be done.

On Sep 15, 10:47 pm, Octavian octaviansus...@gmail.com wrote:
 Any news? Are you still planning to put vids on Cake TV?

 Thanks

 On 8 sep, 04:55, Brett Wilton bdwil...@gmail.com wrote:







  Brilliant, look forward to watching a few.

  On 7/09/2011, at 11:56 PM, Larry E. Masters wrote:

   I will be compressing and uploading the recordings now that I am back in 
   the states.

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Re: Very strange behaviour of CAKEPHP on login

2011-09-16 Thread Sivaramakrishnan S
hi,
 I added [newly added book] tab for my app, still i need to display one more
tab below this tab, that tab name is [Most popular book].i used the same css
for this tab also, but it's not working for me.it's tab is overlap to the
previous one, any one can help me to fix this


Thanks in advance,
Shiva

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tab display in layout in problem

2011-09-16 Thread Sivaramakrishnan S
hi,
 I added [newly added book] tab for my app, still i need to display
one more tab below this tab, that tab name is [Most popular book].i
used the same css for this tab also, but it's not working for me.it's
tab is overlap to the previous one, any one can help me to fix this


Thanks in advance,
Shiva

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Re: Manual entry for habtm linking table.

2011-09-16 Thread WebbedIT
If using Cakes HABTM automagic the table should be named
classes_teachers and have the following fields

id (primary_key, auto_inc)
class_id
teacher_id

After that it's a case of
INSERT INTO classes_teachers (class_id, teacher_id) SELECT class_id,
teacher_id FROM import_table

HTH, Paul
@phpMagpie

On Sep 15, 9:24 pm, porangi.chris porangi.ch...@gmail.com wrote:
 hi,

 First time user of cake with CI background,  I have two tables
 teachers and classes that share a many to many relationship e.g.
 Teacher-Classes.

 I'm having to import the data from CSV files that have been exported
 from another system that we have limited access to.    I've got the
 classes working - I can scan through the file and add the class if it
 doesn't already exist but I need to add the links between class and
 teacher.

 I have an associative array with the two ids (tclass_id and
 teacher_id) ready but what query call would I make to insert this as a
 row in the teacher_class table?

 Thanks in advance for any help.

 Chris

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Re: Haml and sass in CakePHP

2011-09-16 Thread Chris
I think Sass won't be a problem as you could set it to compile to
webroot/css/

On 16 Sep., 08:59, Walther waltherl...@gmail.com wrote:
 CakePHP isn't modeled after Ruby (Or Ruby on Rails). It is simply a
 PHP framework that follows the MVC architecture, and Ruby on Rails is
 a Ruby framework that also follows the MVC architecture. That is
 pretty much their only simularity.

 Perhaps you could be better helped if you actually added what warnings
 and notices you get. People can't guess them out of the blue.

 Also, remember that quite a bit has changed in CakePHP 2.0, so unless
 that plugin has been specifically modified for CakePHP 2.0, you are
 going to need to follow the migration guide to change it to work with
 2.0.

 On Sep 16, 3:56 am, Chris Cinelli







 chris.cine...@formativelearning.com wrote:
  I forgot to mention that I tried to follow the instruction here 
  :https://github.com/goncaloesteves/phamlp/blob/master/Cake/Installatio...
  And I even substitute var $view = 'Haml'; = var $viewClass = 'Haml';

  But cake give warning and notice later.

  On Thu, Sep 15, 2011 at 6:28 PM, Chris Cinelli 

  chris.cine...@formativelearning.com wrote:
   I think almost everybody familiar with Ruby knows:
  http://haml-lang.com/
   and
  http://sass-lang.com/

   Since CakePHP is modeled  after Ruby and in the spirit of having to write
   less code with more syntactic juice it would be great to have them in 
   cake.

   Fortunately someone already though to that. So here is this great piece of
   code that has CakePHP extension:
  https://github.com/goncaloesteves/phamlp

   But following the instruction in the Cake folder does not make it work in
   Cake 2.0.
   Someone know how to solve the problem?

   On a side node, I think that it would be great to add it to Cake as a
   default plugin. Ruby 3.1 added sass with compass (
  http://compass-style.org/) as default.

   Best,
      Chris

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requestAction and named parameters size (in Cake 1.3)

2011-09-16 Thread CaStarCo
Hello, I have a simple doubt. I know that parameters passed on the url have
length limitations (because the browser or server limitations, usually for
security purposes)... but:

there are limitations to parameters size when we are using the requestAction
method?

Thanks in advance! :)

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Re: Making a Complex search

2011-09-16 Thread CaStarCo
I've solved it making two searches :p , I think there is no way to make
complex nested SELECT queries in Cake (and direct SQL is not much better,
it's possible, but it's too tricky, ugly and slow).

2011/9/13 WebbedIT p...@webbedit.co.uk

 Show us what you have tried so far ...  it will be easier to make
 sense of your SQL or Cake conditions



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Re: Very strange behaviour of CAKEPHP on login

2011-09-16 Thread WebbedIT
On Sep 16, 9:03 am, Sivaramakrishnan S siva...@nasoindia.com wrote:
 hi,
  I added [newly added book] tab for my app, still i need to display one more
 tab below this tab, that tab name is [Most popular book].i used the same css
 for this tab also, but it's not working for me.it's tab is overlap to the
 previous one, any one can help me to fix this

 Thanks in advance,
 Shiva

@Shiva: How is this linked to the OP?  If you have a new question ask
it in a new thread otherwise it gets very confusing.

@byqsri: Debug is always your friend.  echo debug($this-data); will
show you if the password is hashed, but Teddy is right that you're not
passing $this-data to the login command.

By turning your debug setting to 2 and echoing your $sql_dump you
could have seen something was wrong with the sql call to try and
authenticate the user.

If you were logging in as normal rather than creating a strange action
to do it on your behalf you would have had a form where you were
echoing the Auth error and it would have informed you there was no
username or password.

I reccomend you also install the excellent DebugKit plugin as it
beings the SQL, Request, Session and other useful data into one handy
neat panel so you can debug such issues yourself.

HTH, Paul
@phpMagpie

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Re: JSON output from search results

2011-09-16 Thread WebbedIT
Take JSON out of the equation and simply check to see if the model-
find() call is returning anything
echo debug($this-paginate());

Although from your post above it seems the problem is that you passing
partners (plural) to the view and echoing partner (singlular) in the
view.

Why are you linking what happens with index and view to what happens
in search?  They should all be different actions with different views?

HTH, Paul
@phpMagpie

P.S. I can highly reccomend CakeDC's search plugin

On Sep 15, 2:51 pm, steveo stevefis...@gmail.com wrote:
 Hey folks! I'm fairly new to CakePHP, but so far I love it! I had some
 troubles getting a search interface to work against my database, but
 after googling around I was finally able to put the pieces together
 and get it to work. I am not in the process of enabling REST
 interfaces and outputting in JSON/XML. I have everything working just
 fine in my index and view templates (where I can just add .json
 or .xml to the end of the URL and get the correct output. However, I
 am not able to get JSON/XML output from a search! It looks like my
 array is empty and I'm not sure how to pass the data over.

 I have the following code in my main controller:

 function search() {
             if(empty($this-data)) {
                 $this-render();
             } else {

                 $search_term=$this-data['Partner']['q'];
                 $conditions = array(partner_name LIKE = %
 {$search_term}%);
                 $partners=$this-Partner-find('all',
 array('conditions' = $conditions));
                 //var_dump($partners);
                 $this-Partner-recursive = -1;
                 $this-set('partners', $this-paginate());
                 $this-set('partners', $partners);
                 $this-render(index);
             }
         }

 Like I said, it works perfectly fine for the index and view, but not
 for search. Instead, I get the following error:

 Undefined variable: partner [APP/views/layouts/json/default.ctp, line
 1]null

 Now, the tricky part. The json/default.ctp works for index and view,
 so if I change the variable to partners, it will no longer work for
 index and view (in addition, changing to partners will not work for
 the json/xml output either). Since I am seeing null in the error
 message, I'm assuming that the partners variable is not getting passed
 to the search (or default) template. Anyone think they can help me?
 Thanks!!!

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Re: Very strange behaviour of CAKEPHP on login

2011-09-16 Thread Jeremy Burns | Class Outfit
It's also a CSS problem, not a Cake problem!

Jeremy Burns
Class Outfit

http://www.classoutfit.com

On 16 Sep 2011, at 10:13, WebbedIT wrote:

 On Sep 16, 9:03 am, Sivaramakrishnan S siva...@nasoindia.com wrote:
 hi,
  I added [newly added book] tab for my app, still i need to display one more
 tab below this tab, that tab name is [Most popular book].i used the same css
 for this tab also, but it's not working for me.it's tab is overlap to the
 previous one, any one can help me to fix this
 
 Thanks in advance,
 Shiva
 
 @Shiva: How is this linked to the OP?  If you have a new question ask
 it in a new thread otherwise it gets very confusing.
 
 @byqsri: Debug is always your friend.  echo debug($this-data); will
 show you if the password is hashed, but Teddy is right that you're not
 passing $this-data to the login command.
 
 By turning your debug setting to 2 and echoing your $sql_dump you
 could have seen something was wrong with the sql call to try and
 authenticate the user.
 
 If you were logging in as normal rather than creating a strange action
 to do it on your behalf you would have had a form where you were
 echoing the Auth error and it would have informed you there was no
 username or password.
 
 I reccomend you also install the excellent DebugKit plugin as it
 beings the SQL, Request, Session and other useful data into one handy
 neat panel so you can debug such issues yourself.
 
 HTH, Paul
 @phpMagpie
 
 -- 
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 others with their CakePHP related questions.
 
 
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Re: display last 5 inserted image

2011-09-16 Thread WebbedIT
@Zaky
 It's not a good idea to change the images size in the html.
 Change the image to the desired size when uploading.
 Media plugin can assist you with this issue.

I used to subscribe to the 'crop/resize before adding into the
database/uploading' principle but then I often fell foul of the client
changing what size they wanted their images to be shown at.  How do
you then go back through all uploaded images and change them?

I am now using the excellent SLIR2.0
http://code.google.com/p/smart-lencioni-image-resizer/

With this handy little script I upload the image once at full size and
within my img tag src I can pass in what dimensions and crop options
I want to apply.  The image returned is cached so when next requested
it does not use unneccessary resources.  BRILLIANT!

HTH, Paul
@phpMagpie

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Re: display last 5 inserted image

2011-09-16 Thread WebbedIT
@Shiva: You really need to start helping us to help you, your two line
posts give us no information on what you have tried already and until
you start showing that you're at least trying to solve these problems
yourself a lot of people will read your posts and never reply.

HTH, Paul
@phpMagpie

On Sep 16, 7:25 am, Sivaramakrishnan S siva...@nasoindia.com wrote:
 Hi,
       I need to create the multitab tab using css in cakephp, How to create
 that in cakephp

 Thanks in advance,
 shiva

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General question

2011-09-16 Thread heohni
Hi,

I have a section in my web project where I have to load from the
database the possible languages and their infos like flag image name,
ID, shortcut, etc.

Within my templates I have in the default.ctp this area:
div id=flags
?php echo $html-link($html-image('en.png', array('class' =
'map_icon')), array('controller' = 'lng/eng'), array('title' =
'English', 'escape' = false));?
...
...
...
/div

This way I have it hard coded, but as said I want to have it
dynamically.
I wonder how I can do this?

Do I have to use elements for this? Where do I have to place all my
database queries? In which controller?
Within the pages_controller? And how to get the database results into
the element template?

Please help me out, I am kind of lost right now...

Thanks!

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Re: Media plugin and user plugin

2011-09-16 Thread WebbedIT
More information required ...

- have you echoed $this-data on submit to see what data there is
- how are you calling save in the controller?
- have you looked at the sql dump to see what Cake is trying?

HTH, Paul
@phpMagpie

On Sep 15, 11:11 am, ZAky procsh...@gmail.com wrote:
 adding media plugin, 'Media.Coupler', behavior to users plugin model
 prevent creating new user.
 I want to save the profile image path in users table.
 Any suggestions?

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Re: Media plugin transferTo

2011-09-16 Thread BenJsno
You can maybe do it manualy : don't use Media.Transfer
But i don't know if you can use Media transfert methods in your
controller after saving the post.
something like that :

function add() {

$this-Post-create();
if ($this-Post-save($this-data)) {
[…]
$dirname = 
'files/'.$this-Session-read('Auth.User.id').'/'.$this-
Post-id;
$this-Post-saveField('dirname', $dirname);

// transfert

} else {
// Error
}

}

The simplest would be to let Media plugin transfert in Media folder,
the path would be store in DB with dirname and basename.


On 14 sep, 12:43, Zaky Katalan-Ezra procsh...@gmail.com wrote:
 Thank you

 Media plugin some how bind to the save function.
 So How do I tell the media plugin not to run after save and run only when I
 have the post_id?









 On Wed, Sep 14, 2011 at 11:47 AM, BenJsno bench...@yahoo.fr wrote:
  You have to save your post before upload the file.
  in your Post_controller :

         function add() {
                 [...]
                 if (!empty($this-data)) {

                         $this-Post-create();
                         if ($this-Post-save($this-data)) {
                                 [...]
                                 $new_id = $this-Post-id
                                 // you can maybe put this data temporarily
  in the session
                                 $this-Session-write('Post.last_id',
  $this-Post-id);
                         } else {
                                 [...]
                         }
                 }

                 [...]
         }

  Hope this helps you

  On 13 sep, 13:24, ZAky procsh...@gmail.com wrote:
   I save my posts files under /files/[user_id]/[post_id]/[image].
   This mean I need to know the just seved post id in Post-transfer_to.
   How do I achieve that?

   Thank you

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Re: Login to a CakePHP application from another site doesn't work

2011-09-16 Thread WebbedIT
There is a reason they are slightly more involved and in your eyes
excessive, because they ensure a level of security!

You should never accept POST data which did not originate from a form
on your site (and never accept data that is not POSTed) unless that
sites has been previously authenticated and has some sort of key/token
in place (i.e. as part of an API/RESTful app).

HTH, Paul
@phpMagpie

On Sep 15, 8:33 am, byqsri marco.rizze...@gmail.com wrote:
 For the thing that I must do I think that is excessive use OAuth or
 OpenID.
 Do a simple autologin  with javascript I think that is the better
 solution.
 Do CakePHP forbid to do a login from a page that isn't the loginAction
 of Auth component ?

 On 15 Set, 08:04, Zaky Katalan-Ezra procsh...@gmail.com wrote:







  Use oauth http://oauth.net/, openid http://openid.net/ ...

  On Wed, Sep 14, 2011 at 7:56 PM, byqsri marco.rizze...@gmail.com wrote:
   Hi
   I have my  web application in CakePHP .
   All works fine.
   Now I would do an autologin in my web application  from another site .
   To do this I have done a identical login form in my site and with
   javascrpt I post it to my web application.
   But it doesn't work . With this method I can't login to my web
   application . I always redirect tio login page.
   I have verify that the session is lost between the login and the
   redirect to initial page of my web application.
   Can someone help me about this?

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Re: General question

2011-09-16 Thread Teddy Zeenny
1. *Create controller and model:*

The controller and model to use depend on the table the languages are stored
in.  For example if the languages are in a table called languages, then
create a model named Language and a controller named LanguagesController.

2. *Create an action that returns the list of languages *

In LanguagesController, create an action called getLanguages for example.
Basically what it does is query the languages table (
$results=$this-Language-find('all');  )
and then it returns the result (  return $results;   )


3.*Create an element (for example call it language_list.ctp)*

First retrieve the information using requestAction
(for example: $languages=$this-requestAction('languages/getLanguages')  )
Then create the html needed for the languages
(for example: foreach($languages as $language){  //html here }


4.*Call the element from the default.ctp layout*
* *echo $this-element('language_list');

Now usually I wouldn't use requestAction as it would hit my performance, but
since the list of languages is part of the layout, I think it would be the
safest way to go.
In order to fix the performance costs of requestAction, I would recommend
the use of caching (especially that these languages will probably not change
very often)
You can for example cache the element i.e:

you can can add a parameter to the element call from default.ctp:

echo $this-element('language_list',array('cache'=array('time'='+1
week','key'='languages')));

That is how I would do it.  I'm sure there are other (and maybe better)
solutions, but this would definitely work.


On Fri, Sep 16, 2011 at 12:32 PM, heohni 
heidi.anselstet...@consultingteam.de wrote:

 Hi,

 I have a section in my web project where I have to load from the
 database the possible languages and their infos like flag image name,
 ID, shortcut, etc.

 Within my templates I have in the default.ctp this area:
 div id=flags
 ?php echo $html-link($html-image('en.png', array('class' =
 'map_icon')), array('controller' = 'lng/eng'), array('title' =
 'English', 'escape' = false));?
 ...
 ...
 ...
 /div

 This way I have it hard coded, but as said I want to have it
 dynamically.
 I wonder how I can do this?

 Do I have to use elements for this? Where do I have to place all my
 database queries? In which controller?
 Within the pages_controller? And how to get the database results into
 the element template?

 Please help me out, I am kind of lost right now...

 Thanks!

 --
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Re: General question

2011-09-16 Thread Thomas Ploch
Well, using requestAction is only recommended in combination with 
caching. So using the cached element with requestAction inside the 
element is the way to go in my oppinion.


The other possibility is loading the Language Model in AppController, 
setting the languages var in AppController::beforeFilter() and passing 
the var into the cached element.


Kind regards
Thomas

Am 16.09.2011 11:56, schrieb Teddy Zeenny:

1. *Create controller and model:*

The controller and model to use depend on the table the languages
are stored in.  For example if the languages are in a table called
languages, then create a model named Language and a controller
named LanguagesController.

2. *Create an action that returns the list of languages *

In LanguagesController, create an action called getLanguages for
example.
Basically what it does is query the languages table (
$results=$this-Language-find('all');  )
and then it returns the result (  return $results;   )


3.*Create an element (for example call it language_list.ctp)*

First retrieve the information using requestAction
(for example:
$languages=$this-requestAction('languages/getLanguages')  )
Then create the html needed for the languages
(for example: foreach($languages as $language){  //html here }


4.*Call the element from the default.ctp layout*
**echo $this-element('language_list');
Now usually I wouldn't use requestAction as it would hit my 
performance, but since the list of languages is part of the layout, I 
think it would be the safest way to go.
In order to fix the performance costs of requestAction, I would 
recommend the use of caching (especially that these languages will 
probably not change very often)

You can for example cache the element i.e:

you can can add a parameter to the element call from default.ctp:

echo $this-element('language_list',array('cache'=array('time'='+1 
week','key'='languages')));


That is how I would do it.  I'm sure there are other (and maybe 
better) solutions, but this would definitely work.



On Fri, Sep 16, 2011 at 12:32 PM, heohni 
heidi.anselstet...@consultingteam.de 
mailto:heidi.anselstet...@consultingteam.de wrote:


Hi,

I have a section in my web project where I have to load from the
database the possible languages and their infos like flag image name,
ID, shortcut, etc.

Within my templates I have in the default.ctp this area:
div id=flags
?php echo $html-link($html-image('en.png', array('class' =
'map_icon')), array('controller' = 'lng/eng'), array('title' =
'English', 'escape' = false));?
...
...
...
/div

This way I have it hard coded, but as said I want to have it
dynamically.
I wonder how I can do this?

Do I have to use elements for this? Where do I have to place all my
database queries? In which controller?
Within the pages_controller? And how to get the database results into
the element template?

Please help me out, I am kind of lost right now...

Thanks!

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Re: display last 5 inserted image

2011-09-16 Thread Sivaramakrishnan S
@phpMagpie: i am new to cakephp,so i didn't help u.. sorry for that.. i will
try to help u

Thanks,
Shiva

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Re: General question

2011-09-16 Thread heohni
OK great! That helps me a lot!
First I was surprised as I know that requestAction is kind of bad, but
I didn't know about the caching and this brings it into a total
different light.
I will try this, thanks a lot!!

On 16 Sep., 11:56, Teddy Zeenny teddyzee...@gmail.com wrote:
 1. *Create controller an!
d model:*

 The controller and model to use depend on the table the languages are stored
 in.  For example if the languages are in a table called languages, then
 create a model named Language and a controller named LanguagesController.

 2. *Create an action that returns the list of languages *

 In LanguagesController, create an action called getLanguages for example.
 Basically what it does is query the languages table (
 $results=$this-Language-find('all');  )
 and then it returns the result (  return $results;   )

 3.*Create an element (for example call it language_list.ctp)*

 First retrieve the information using requestAction
 (for example: $languages=$this-requestAction('languages/getLanguages')  )
 Then create the html needed for the languages
 (for example: foreach($languages as $language){  //html here }

 4.*Call the element from the default.ctp layout*
 *         *echo $this-element('language_list');

 Now usually I wouldn't use requestAction as it would hit my performance, but
 since the list of languages is part of the layout, I think it would be the
 safest way to go.
 In order to fix the performance costs of requestAction, I would recommend
 the use of caching (especially that these languages will probably not change
 very often)
 You can for example cache the element i.e:

 you can can add a parameter to the element call from default.ctp:

 echo $this-element('language_list',array('cache'=array('time'='+1
 week','key'='languages')));

 That is how I would do it.  I'm sure there are other (and maybe better)
 solutions, but this would definitely work.

 On Fri, Sep 16, 2011 at 12:32 PM, heohni 



 heidi.anselstet...@consultingteam.de wrote:
  Hi,

  I have a section in my web project where I have to load from the
  database the possible languages and their infos like flag image name,
  ID, shortcut, etc.

  Within my templates I have in the default.ctp this area:
  div id=flags
  ?php echo $html-link($html-image('en.png', array('class' =
  'map_icon')), array('controller' = 'lng/eng'), array('title' =
  'English', 'escape' = false));?
  ...
  ...
  ...
  /div

  This way I have it hard coded, but as said I want to have it
  dynamically.
  I wonder how I can do this?

  Do I have to use elements for this? Where do I have to place all my
  database queries? In which controller?
  Within the pages_controller? And how to get the database results into
  the element template?

  Please help me out, I am kind of lost right now...

  Thanks!

  --
  Our newest site for the community: CakePHP Video Tutorials
 http://tv.cakephp.org
  Check out the new CakePHP Questions sitehttp://ask.cakephp.organd help
  others with their CakePHP related questions.

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sub query and union all function in cakephp

2011-09-16 Thread Sivaramakrishnan S
hi,

  can we do subquery and union all functions of mysql  in cakephp?
i need to query that in my sample app, so any one help me,









Thanks in advance
Shiva

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subquery and unionall

2011-09-16 Thread Sivaramakrishnan S
hi,

Anyone knows a good way to make UNION query in CakePHP? I would like
to avoid using $this-query();.


for this code =


Select distinct bm.id,name, add
   From table1 bm,
   (Select id bid, count(id) cnt
   from table2
   where status = 'N'
   group by id
   union all
   Select id bid, count(id) cnt
   from table3
   where status = 'N'
   group by id
   order by cnt
   limit 10) ab Where id = 
bm.id

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Re: General question

2011-09-16 Thread Ryan Schmidt

On Sep 16, 2011, at 04:32, heohni wrote:

 I have a section in my web project where I have to load from the
 database the possible languages and their infos like flag image name,
 ID, shortcut, etc.

Languages do not have flags.

http://www.cs.tut.fi/~jkorpela/flags.html


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Re: Se Ya Cake..bake a dick cake frosting on your face...............

2011-09-16 Thread Matthew Kaufman
Pat-a-cake, pat-a-cake, baker's man ...

On 9/16/11, Dr. Tarique Sani tariques...@gmail.com wrote:
 FWIW

 http://www.google.com/trends?q=cakephp%2C+ruby+on+rails%2C+zend+framework%2C+symfonyctab=0geo=alldate=allsort=2

 All trends regarding any framework ultimately merge into more or less
 the same thing

 IOW - lets move on

 Tarique

 On Thu, Sep 15, 2011 at 7:56 PM, Janos Csikos ja...@csikos.co.uk wrote:
 Hi Guys,

 I'm Cake fan since 2006 and excited about the coming 2.0, but I have
 to say this CLASSIC trolling means something.

 I mean thats true there is no CakePHP jobs posted.
 That's true there is not the latest cake sites are listed in the just
 baked box on cakephp.org.
 And also true the drupal (and ror, zend, ) much more popular than cake:
 http://www.google.com/trends?q=cakephp%2C+django%2C+ruby+on+rails%2C+zend+frameworkctab=0geo=alldate=allsort=0



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 PHP for E-Biz: http://sanisoft.com
 =

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Re: Se Ya Cake..bake a dick cake frosting on your face...............

2011-09-16 Thread Salines
*FACTS:
In oDesk there is 3500 PHP jobs and a 1000 of them is in joomla/drupal.
There is also 88 zend projects 1 symphony and 63 Cakephp.
So what you can learn from this?



*From the above we learn that there are over 2,000 open jobs where they can use 
the CakePHP framework :)

Many employers are looking for a PHP developer for their projects, but they do 
not care whether you use a framework or CMS...

so no worries

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Re: General question

2011-09-16 Thread heohni
Thanks Ryan :-)

Another question.

All translations are coming from the database.
I thought i would need a helper function, but I don't think it makes
sense to place mysql statements in a helper?

Should I create a own model/controller for the translations?
With a controller function called getTranslation($id) and return the
word string.

But how do I call this controller function from the helper file?

Thanks in advance!!

On 16 Sep., 15:40, Ryan Schmidt google-2...@ryandesign.com wrote:
 On Sep 16, 2011, at 04:32, heohni wrote:

  I have a section in my web project where I have to load from the
  database the possible languages and their infos like flag image name,
  ID, shortcut, etc.

 Languages do not have flags.

 http://www.cs.tut.fi/~jkorpela/flags.html

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Re: Haml and Sass in CakePHP

2011-09-16 Thread Chris Cinelli
Maybe modeled after may be a little too strong but this is what the
book.cakephp.org said CakePHP is a free open-source rapid development
framework for PHP. Its a structure of libraries, classes and run-time
infrastructure for programmers creating web applications originally inspired
by the Ruby on Rails framework

There are a few links that says that same:

http://stackoverflow.com/questions/493950/how-different-is-cakephp-from-ruby-on-rails
(this has some harsh judgement toward CAhePHP though).
http://stackoverflow.com/questions/493950/how-different-is-cakephp-from-ruby-on-rails

http://blog.endpoint.com/2010/11/ruby-on-rails-cakephp-syntax-comparison.html(more
objective comparison).

Plus if you search for ruby in cakephp.org, you can find 1700 pages:
http://www.google.com/search?q=site%3Acakephp.comie=utf-8oe=utf-8aq=trls=org.mozilla:en-US:officialclient=firefox-a#sclient=psy-abhl=enclient=firefox-ahs=Fiwrls=org.mozilla:en-US%3Aofficialsource=hpq=site:cakephp.org+rubypbx=1oq=site:cakephp.org+rubyaq=faqi=aql=gs_sm=egs_upl=95311l96119l3l99330l5l3l0l0l0l2l777l1970l5-2.1l3l0bav=on.2,or.r_gc.r_pw.fp=23ce9c3efefc512cbiw=1200bih=784


I do not have to state again that HAML can speed up HTML programming
minimizing the code to be written and SASS make CSS less painful to develop
and maintain adding syntactical juice that make it more object oriented.

---

Anyway, going back to the problem before using var $viewClass = 'Haml'; I
got a missed view (I have a view called myotheraction.haml. After I
received these messages:

*Warning* (2): Missing argument 2 for HamlView::_render(), called in
/Users/chris/workspace/FL_NT-RC1/_product/lib/Cake/View/View.php on
line 364 and defined [*APP/View/haml.php*, line *257*]

*Notice* (8): Use of undefined constant VIEWS - assumed 'VIEWS'
[*APP/View/haml.php*, line *281*]

*Warning* (2): 
file_put_contents(/Users/chris/workspace/FL_NT-RC1/_product/app/View/Test/otheraction.ctp)
[function.file-put-contents
http://php.net/function.file-put-contents]: failed to open stream:
Permission denied [*APP/View/haml.php*, line *262*]

*Notice* (8): Undefined variable: ___dataForView [*APP/View/haml.php*,
line *265*]

*Warning* (2): Missing argument 2 for HamlView::_render(), called in
/Users/chris/workspace/FL_NT-RC1/_product/lib/Cake/View/View.php on
line 413 and defined [*APP/View/haml.php*, line *257*]

*Notice* (8): Undefined variable: ___dataForView [*APP/View/haml.php*,
line *268*]


Yes, The view.php in Cake 1.3 is pretty different than View.php in
Cake 2.0. Anybody can point out how it can be fixed?

Best,
   Chris

 On Sep 16, 2011 12:32 AM, Chris ch.ti...@googlemail.com wrote:
 I think Sass won't be a problem as you could set it to compile to
 webroot/css/

 On 16 Sep., 08:59, Walther waltherl...@gmail.com wrote:
 CakePHP isn't modeled after Ruby (Or Ruby on Rails). It is simply a
 PHP framework that follows the MVC architecture, and Ruby on Rails is
 a Ruby framework that also follows the MVC architecture. That is
 pretty much their only simularity.

 Perhaps you could be better helped if you actually added what warnings
 and notices you get. People can't guess them out of the blue.

 Also, remember that quite a bit has changed in CakePHP 2.0, so unless
 that plugin has been specifically modified for CakePHP 2.0, you are
 going to need to follow the migration guide to change it to work with
 2.0.

 On Sep 16, 3:56 am, Chris Cinelli







 chris.cine...@formativelearning.com wrote:
  I forgot to mention that I tried to follow the instruction here :
https://github.com/goncaloesteves/phamlp/blob/master/Cake/Installatio...
  And I even substitute var $view = 'Haml'; = var $viewClass = 'Haml';

  But cake give warning and notice later.

  On Thu, Sep 15, 2011 at 6:28 PM, Chris Cinelli 

  chris.cine...@formativelearning.com wrote:
   I think almost everybody familiar with Ruby knows:
  http://haml-lang.com/
   and
  http://sass-lang.com/

   Since CakePHP is modeled  after Ruby and in the spirit of having to
write
   less code with more syntactic juice it would be great to have them in
cake.

   Fortunately someone already though to that. So here is this great
piece of
   code that has CakePHP extension:
  https://github.com/goncaloesteves/phamlp

   But following the instruction in the Cake folder does not make it
work in
   Cake 2.0.
   Someone know how to solve the problem?

   On a side node, I think that it would be great to add it to Cake as a
   default plugin. Ruby 3.1 added sass with compass (
  http://compass-style.org/) as default.

   Best,
  Chris

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Re: General question

2011-09-16 Thread Teddy Zeenny
You can check out the cakephp i18n.
Check out both these links maybe they can help you.
http://book.cakephp.org/view/1228/Internationalization-Localization
http://book.cakephp.org/view/1328/Translate


On Fri, Sep 16, 2011 at 7:20 PM, heohni 
heidi.anselstet...@consultingteam.de wrote:

 Thanks Ryan :-)

 Another question.

 All translations are coming from the database.
 I thought i would need a helper function, but I don't think it makes
 sense to place mysql statements in a helper?

 Should I create a own model/controller for the translations?
 With a controller function called getTranslation($id) and return the
 word string.

 But how do I call this controller function from the helper file?

 Thanks in advance!!

 On 16 Sep., 15:40, Ryan Schmidt google-2...@ryandesign.com wrote:
  On Sep 16, 2011, at 04:32, heohni wrote:
 
   I have a section in my web project where I have to load from the
   database the possible languages and their infos like flag image name,
   ID, shortcut, etc.
 
  Languages do not have flags.
 
  http://www.cs.tut.fi/~jkorpela/flags.html

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Re: subquery and unionall

2011-09-16 Thread WebbedIT
You sent me a direct email, but I prefer to offer what support I can
in here.

Sorry, I can't help with this as I have never used a MySQL Union.  I
had to search on what a UNION was and cannot come up with a situation
where I would need to use it?!?

If I had two tables with identical fields I would merge the tables to
preserve a normalised database.

Paul

On Sep 16, 2:17 pm, Sivaramakrishnan S siva...@nasoindia.com wrote:
 hi,

 Anyone knows a good way to make UNION query in CakePHP? I would like
 to avoid using $this-query();.

 for this code =

 Select distinct bm.id,name, add
                                                    From table1 bm,
                                                    (Select id bid, count(id) 
 cnt
                                                    from table2
                                                    where status = 'N'
                                                    group by id
                                                    union all
                                                    Select id bid, count(id) 
 cnt
                                                    from table3
                                                    where status = 'N'
                                                    group by id
                                                    order by cnt
                                                    limit 10) ab Where id = 
 bm.id

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Re: Editing data

2011-09-16 Thread Mohd Hasnol
Hi,

If i use saveAll, it will add another A data. What happen? Thanks.

On Thu, Sep 15, 2011 at 4:54 PM, WebbedIT p...@webbedit.co.uk wrote:

 As #2will advised, your problem is:
 $this-B-save($this-data)

 Should be:
 $this-B-saveAll($this-data)


 http://book.cakephp.org/view/1032/Saving-Related-Model-Data-hasOne-hasMany-belongsTo

 HTH, Paul
 @phpMagpie

 On Sep 15, 2:59 am, Mohd Hasnol hasnolm...@gmail.com wrote:
  edit.ctp
 
  ?php echo $this-Form-create('B', array('action'='edit'));?
?php
   echo $this-Form-input('A.first_name');
   echo $this-Form-input('A.last_name');
   echo $this-Form-input('A.contact_no');
   echo $this-Form-input('A.email');
   echo $this-Form-input('B.username');
   echo $this-Form-input('B.password');?
  ?php   echo $this-Form-end('Submit');?
 
  inside B controller
 
  function edit($id = NULL) {
 $this-B-id = $id;
 
  if (empty($this-data)){
  $this-data = $this-B-read();
  } else {
  if ($this-B-save($this-data)) {
   $this-Session-setFlash('Data updated');
 
  }
  }
  }
 
 
 
 
 
 
 
  On Thu, Sep 15, 2011 at 5:05 AM, #2Will willjbar...@gmail.com wrote:
   Are you doing a saveAll rather than save in your controller?
 
   On Sep 14, 7:27 pm, Mohd Hasnol hasnolm...@gmail.com wrote:
inside edit.ctp
 
?php echo $this-Form-create('Useradmin',
 array('action'='edit'));?
?php
echo $this-Form-input('A.first_name');
echo $this-Form-input('A.last_name');
echo $this-Form-input('A.contact_no');
echo $this-Form-input('A.email');
echo $this-Form-input('B.username');
echo $this-Form-input('B.password');?
 
i only can edit username and password.
 
Thanks.
 
On Wed, Sep 14, 2011 at 9:50 AM, euromark 
 dereurom...@googlemail.com
   wrote:
 
 a less abstract code example would help
 you code post your real code. maybe this way we can figure out
 whats
 wrong with your code.
 
 On 14 Sep., 05:35, nOLL hasnolm...@gmail.com wrote:
  Hi,
 
  I have a form that use 2 models(A,B). For create and view
 function it
  was run perfectly, but there is a problem when editing the form.
 I
   use
  B controller for all the function(CRUD) and i only can edit the B
  table attributes but for A attributes the data remain the same.
 
  I follow thishttp://
 book.cakephp.org/view/1650/hasMany-through-The-Join-Model
  for the form.
 
  Whats the problem actually?
 
  Thanks,
  nOLL
 
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Re: JSON output from search results

2011-09-16 Thread steveo
Paul,

First off, I'm *very* new to CakePHP and not much of a PHP programmer
(more of a hack than anything!). I'm still grasping the whole MVC
architecture paradigm, so the plural/singular thing is still settling
in.

Basically, I created a CRUD interface from the CakePHP console to a
MySQL database, which worked perfectly! I then tried implementing the
CakeDC search plugin, but was completely frustrated with it and could
never get it to function (real-life examples are hard to find on it
and the blog example just didn't have enough detail for customizing
for my application).

Anyhow, the main part of the app consists of a partners controller -
http://mydomain.com/partners - which basically lists all partners in a
paginated view (there are about 3000 partners). I wanted a search
interface because paging through 3000 records to find the one you want
to edit would just not be possible.

I implemented the search, as described earlier in this thread, and it
has worked fine (although probably not implemented completely
cleanly). I wanted to just have the search post back to itself, which
I couldn't figure out, so I created a search template which is pretty
much a copy of the partners template.

So, http://mydomain.com/partners lists partners fine. Performing a
search posts to http://mydomain.com/partners/search and shows an
appropriate search result. All good.

I need to implement ReST now and have some endpoints which return JSON
(or XML) formatted results. Continuing on...

http://mydomain.com/partners.json (and /partners.xml) both output
expected results (although it is quite meaningless since it is just
the first 10 records). My index.ctp for the JSON output has just one
line of code: ?php echo json_encode($partners); ? (notice the
plural, which works).

My dilemma now is the search output:

http://mydomain.com/search.json gives the error Undefined variable:
partners (/views\/partners\/json\/search.ctp). The line of code in
this template is: ?php echo json_encode($partners); ? (which works
just fine for /partners.json). If I change it to ?php echo
json_encode($partner); ? (singular) is get the same error message,
just Undefined variable: partner (now singular). So as you can see
regardless of singular/plural in the search JSON output, I still get
an error!

steve

On Sep 16, 5:22 am, WebbedIT p...@webbedit.co.uk wrote:
 Take JSON out of the equation and simply check to see if the model-find() 
 call is returning anything

 echo debug($this-paginate());

 Although from your post above it seems the problem is that you passing
 partners (plural) to the view and echoing partner (singlular) in the
 view.

 Why are you linking what happens with index and view to what happens
 in search?  They should all be different actions with different views?

 HTH, Paul
 @phpMagpie

 P.S. I can highly reccomend CakeDC's search plugin

 On Sep 15, 2:51 pm, steveo stevefis...@gmail.com wrote:







  Hey folks! I'm fairly new to CakePHP, but so far I love it! I had some
  troubles getting a search interface to work against my database, but
  after googling around I was finally able to put the pieces together
  and get it to work. I am not in the process of enabling REST
  interfaces and outputting in JSON/XML. I have everything working just
  fine in my index and view templates (where I can just add .json
  or .xml to the end of the URL and get the correct output. However, I
  am not able to get JSON/XML output from a search! It looks like my
  array is empty and I'm not sure how to pass the data over.

  I have the following code in my main controller:

  function search() {
              if(empty($this-data)) {
                  $this-render();
              } else {

                  $search_term=$this-data['Partner']['q'];
                  $conditions = array(partner_name LIKE = %
  {$search_term}%);
                  $partners=$this-Partner-find('all',
  array('conditions' = $conditions));
                  //var_dump($partners);
                  $this-Partner-recursive = -1;
                  $this-set('partners', $this-paginate());
                  $this-set('partners', $partners);
                  $this-render(index);
              }
          }

  Like I said, it works perfectly fine for the index and view, but not
  for search. Instead, I get the following error:

  Undefined variable: partner [APP/views/layouts/json/default.ctp, line
  1]null

  Now, the tricky part. The json/default.ctp works for index and view,
  so if I change the variable to partners, it will no longer work for
  index and view (in addition, changing to partners will not work for
  the json/xml output either). Since I am seeing null in the error
  message, I'm assuming that the partners variable is not getting passed
  to the search (or default) template. Anyone think they can help me?
  Thanks!!!

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Re: JSON output from search results

2011-09-16 Thread steveo
Paul,

Adding some more information - I just found the first part of the
problem from the stack trace. When I invoke the /partners/search.json
URL, the search() function is not getting any data, so it just runs to
the first part of the IF statement and performs $this-render();
(which is why I get the undefined variable: partner (or partners)!!
So, I guess my question now is how to get the search result data to
output in JSON!!??

function search() {
if(empty($this-data)) {
$this-render();
} else {

$search_term=$this-data['Partner']['q'];
$conditions = array(partner_name LIKE = %
{$search_term}%);
$partners=$this-Partner-find('all',
array('conditions' = $conditions));
//var_dump($partners);
$this-Partner-recursive = -1;
$this-set('partners', $this-paginate());
$this-set('partners', $partners);
//$this-render(index);
}
}

On Sep 16, 1:48 pm, steveo stevefis...@gmail.com wrote:
 Paul,

 First off, I'm *very* new to CakePHP and not much of a PHP programmer
 (more of a hack than anything!). I'm still grasping the whole MVC
 architecture paradigm, so the plural/singular thing is still settling
 in.

 Basically, I created a CRUD interface from the CakePHP console to a
 MySQL database, which worked perfectly! I then tried implementing the
 CakeDC search plugin, but was completely frustrated with it and could
 never get it to function (real-life examples are hard to find on it
 and the blog example just didn't have enough detail for customizing
 for my application).

 Anyhow, the main part of the app consists of a partners controller 
 -http://mydomain.com/partners- which basically lists all partners in a
 paginated view (there are about 3000 partners). I wanted a search
 interface because paging through 3000 records to find the one you want
 to edit would just not be possible.

 I implemented the search, as described earlier in this thread, and it
 has worked fine (although probably not implemented completely
 cleanly). I wanted to just have the search post back to itself, which
 I couldn't figure out, so I created a search template which is pretty
 much a copy of the partners template.

 So,http://mydomain.com/partnerslists partners fine. Performing a
 search posts tohttp://mydomain.com/partners/searchand shows an
 appropriate search result. All good.

 I need to implement ReST now and have some endpoints which return JSON
 (or XML) formatted results. Continuing on...

 http://mydomain.com/partners.json(and /partners.xml) both output
 expected results (although it is quite meaningless since it is just
 the first 10 records). My index.ctp for the JSON output has just one
 line of code: ?php echo json_encode($partners); ? (notice the
 plural, which works).

 My dilemma now is the search output:

 http://mydomain.com/search.jsongives the error Undefined variable:
 partners (/views\/partners\/json\/search.ctp). The line of code in
 this template is: ?php echo json_encode($partners); ? (which works
 just fine for /partners.json). If I change it to ?php echo
 json_encode($partner); ? (singular) is get the same error message,
 just Undefined variable: partner (now singular). So as you can see
 regardless of singular/plural in the search JSON output, I still get
 an error!

 steve

 On Sep 16, 5:22 am, WebbedIT p...@webbedit.co.uk wrote:







  Take JSON out of the equation and simply check to see if the model-find() 
  call is returning anything

  echo debug($this-paginate());

  Although from your post above it seems the problem is that you passing
  partners (plural) to the view and echoing partner (singlular) in the
  view.

  Why are you linking what happens with index and view to what happens
  in search?  They should all be different actions with different views?

  HTH, Paul
  @phpMagpie

  P.S. I can highly reccomend CakeDC's search plugin

  On Sep 15, 2:51 pm, steveo stevefis...@gmail.com wrote:

   Hey folks! I'm fairly new to CakePHP, but so far I love it! I had some
   troubles getting a search interface to work against my database, but
   after googling around I was finally able to put the pieces together
   and get it to work. I am not in the process of enabling REST
   interfaces and outputting in JSON/XML. I have everything working just
   fine in my index and view templates (where I can just add .json
   or .xml to the end of the URL and get the correct output. However, I
   am not able to get JSON/XML output from a search! It looks like my
   array is empty and I'm not sure how to pass the data over.

   I have the following code in my main controller:

   function search() {
               if(empty($this-data)) {
                   $this-render();
               } else {

                   $search_term=$this-data['Partner']['q'];
                   $conditions = array(partner_name LIKE = %
   {$search_term}%);

Media Views for streaming mp3 with flash player

2011-09-16 Thread lebert
I have a page with a audio flash player that streams several mp3
files. This player uses an XML file that has the path of all those
files, which are in a audio folder in the webroot directory.

What I don't like is that it's pretty easy for a user to get to the
XML file (which is also in the webroot directory) and see the paths of
the mp3 files, and then download them instead of just using the flash
player.

I've seen that CakePHP has something called Media Views, where you can
set a folder outside the webroot and place your files there, so users
can't freely access them. The explanation in Cake's website (http://
book.cakephp.org/view/1094/Media-Views) is focused on files to
download, but I would like to know if I can use the Media Views to
stream my mp3 files with the audio player without making them
downloadable by the users. OR if there's any other alternative without
Media Views that would work as well :)

Thanks so much in advance!

CLARIFICATION

This is the code that I'm using that I would like to change:

- In my controller:

function index() {}

- In my view (index.ctp):

embed type=application/x-shockwave-flash flashvars=audioUrl=/
audios/01 Track 01.mp3 src=audio-player.swf/embed

=How can I change that using Media Views so that my mp3 file is in a
folder app/audios instead of app/webroot/audios?

THIS IS WHAT I'VE TRIED:

- In my controller (streams_controller.php):

function index() {}

function getFile() {

$this-view = 'Media';

$params = array(
'id' = '01 Track 01.mp3',
'name' = '01 Track 01',
'download' = false,
'extension' = 'mp3',
'path' = APP . 'audios' . DS,
'cache' = true
);

$this-set($params);
}

- In my view (index.ctp):

embed type=application/x-shockwave-flash flashvars=audioUrl=/
streams/getFile src=audio-player.swf/embed

STILL NO LUCK! What am I doing wrong?

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Re: Editing data

2011-09-16 Thread ecsyle
You need the id of A in your data set:

echo $this-Form-input('A.id');

On Sep 16, 10:48 am, Mohd Hasnol hasnolm...@gmail.com wrote:
 Hi,

 If i use saveAll, it will add another A data. What happen? Thanks.







 On Thu, Sep 15, 2011 at 4:54 PM, WebbedIT p...@webbedit.co.uk wrote:
  As #2will advised, your problem is:
  $this-B-save($this-data)

  Should be:
  $this-B-saveAll($this-data)

 http://book.cakephp.org/view/1032/Saving-Related-Model-Data-hasOne-ha...

  HTH, Paul
  @phpMagpie

  On Sep 15, 2:59 am, Mohd Hasnol hasnolm...@gmail.com wrote:
   edit.ctp

   ?php echo $this-Form-create('B', array('action'='edit'));?
     ?php
                        echo $this-Form-input('A.first_name');
                        echo $this-Form-input('A.last_name');
                        echo $this-Form-input('A.contact_no');
                        echo $this-Form-input('A.email');
                        echo $this-Form-input('B.username');
                        echo $this-Form-input('B.password');?
   ?php   echo $this-Form-end('Submit');?

   inside B controller

       function edit($id = NULL) {
          $this-B-id = $id;

           if (empty($this-data)){
               $this-data = $this-B-read();
           } else {
               if ($this-B-save($this-data)) {
                    $this-Session-setFlash('Data updated');

               }
           }
       }

   On Thu, Sep 15, 2011 at 5:05 AM, #2Will willjbar...@gmail.com wrote:
Are you doing a saveAll rather than save in your controller?

On Sep 14, 7:27 pm, Mohd Hasnol hasnolm...@gmail.com wrote:
 inside edit.ctp

 ?php echo $this-Form-create('Useradmin',
  array('action'='edit'));?
 ?php
                     echo $this-Form-input('A.first_name');
                     echo $this-Form-input('A.last_name');
                     echo $this-Form-input('A.contact_no');
                     echo $this-Form-input('A.email');
                     echo $this-Form-input('B.username');
                     echo $this-Form-input('B.password');?

 i only can edit username and password.

 Thanks.

 On Wed, Sep 14, 2011 at 9:50 AM, euromark 
  dereurom...@googlemail.com
wrote:

  a less abstract code example would help
  you code post your real code. maybe this way we can figure out
  whats
  wrong with your code.

  On 14 Sep., 05:35, nOLL hasnolm...@gmail.com wrote:
   Hi,

   I have a form that use 2 models(A,B). For create and view
  function it
   was run perfectly, but there is a problem when editing the form.
  I
use
   B controller for all the function(CRUD) and i only can edit the B
   table attributes but for A attributes the data remain the same.

   I follow thishttp://
  book.cakephp.org/view/1650/hasMany-through-The-Join-Model
   for the form.

   Whats the problem actually?

   Thanks,
   nOLL

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hi guys

2011-09-16 Thread aortizhi
I have this problem, i create a form that will display select field
here's my code:
?php
echo $this-Form-input('proveedore_id');
echo $this-Form-input('nombre_archivo');
echo $this-Form-input('token_separador');
echo $this-Form-input('Tabla Correspondiente', array('options' =
$campos,'id'='choose', 'onChange'='prueba()'));
?
?php
But i would like to know from my controller when an option is selected
to make query to my database, can someone help me?

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Pagination Problem

2011-09-16 Thread Caio Landau
I'm trying to do simple pagination with cake and getting the following
error: Warning (4096): Object of class JsHelper could not be
converted to string [CORE/cake/libs/view/helpers/html.php, line 444]

Here is my code:


//controllers/orders_controller.php
class OrdersController extends AppController {

var $components = array(Security);
var $helpers = array(Html, Form, Session, Number,
Paginator);
var $uses = array('Product', 'Order');
var $paginate = array('limit' = 10,'order' = array('Order.date'
= 'asc'),'recursive' = 2);

function view($id = null) {
if ($id == NULL) {
$this-set(orders, $this-paginate(Order));
$this-set(js, array(jquery-1.6.2.min,
viewOrders)); //Set a JS variable to be put on the head
} else {
$orders[0] = $this-Order-getOrder($id);
$this-set(orders, $orders);
}
}
}

The only place I'm calling the paginate function is here in the
controller. Not calling anything (yet) on the view/model. If I comment
the $this-set(orders, $this-paginate(Order)); line the error
stops. Any idea?

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Re: Haml and sass in CakePHP

2011-09-16 Thread Chris Cinelli
For those who are interested:
I fixed HAML for cakephp 2.0. Look at:
https://github.com/ChrisCinelli/phamlp in the Cake 2.0 folder.
scss seems having problems with mixins. Unfortunately I do not think the
problem is just Cake 2.0.
I am working on a faster assets manager. I will include changes to make sass
work there.

Best,
Chris


On Fri, Sep 16, 2011 at 12:32 AM, Chris ch.ti...@googlemail.com wrote:

 I think Sass won't be a problem as you could set it to compile to
 webroot/css/

 On 16 Sep., 08:59, Walther waltherl...@gmail.com wrote:
  CakePHP isn't modeled after Ruby (Or Ruby on Rails). It is simply a
  PHP framework that follows the MVC architecture, and Ruby on Rails is
  a Ruby framework that also follows the MVC architecture. That is
  pretty much their only simularity.
 
  Perhaps you could be better helped if you actually added what warnings
  and notices you get. People can't guess them out of the blue.
 
  Also, remember that quite a bit has changed in CakePHP 2.0, so unless
  that plugin has been specifically modified for CakePHP 2.0, you are
  going to need to follow the migration guide to change it to work with
  2.0.
 
  On Sep 16, 3:56 am, Chris Cinelli
 
 
 
 
 
 
 
  chris.cine...@formativelearning.com wrote:
   I forgot to mention that I tried to follow the instruction here :
 https://github.com/goncaloesteves/phamlp/blob/master/Cake/Installatio...
   And I even substitute var $view = 'Haml'; = var $viewClass = 'Haml';
 
   But cake give warning and notice later.
 
   On Thu, Sep 15, 2011 at 6:28 PM, Chris Cinelli 
 
   chris.cine...@formativelearning.com wrote:
I think almost everybody familiar with Ruby knows:
   http://haml-lang.com/
and
   http://sass-lang.com/
 
Since CakePHP is modeled  after Ruby and in the spirit of having to
 write
less code with more syntactic juice it would be great to have them in
 cake.
 
Fortunately someone already though to that. So here is this great
 piece of
code that has CakePHP extension:
   https://github.com/goncaloesteves/phamlp
 
But following the instruction in the Cake folder does not make it
 work in
Cake 2.0.
Someone know how to solve the problem?
 
On a side node, I think that it would be great to add it to Cake as a
default plugin. Ruby 3.1 added sass with compass (
   http://compass-style.org/) as default.
 
Best,
   Chris

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Scripts for layout and Html-meta confusion

2011-09-16 Thread Santiago Basulto
Hello people, i want to display canonical link attributes for some of
my pages. I can do it with:

echo $this-Html-meta('canonical', 'http:://example.com',
array('rel'='canonical', 'type'=null, 'title'=null,'inline' =
false));

I want the link tag to be displayed inside of my head tag. So i
set inline to false. The problem is that it's placed where the
$scripts_for_layout is echoed. But, i put my $scripts_for_layout at
the bottom of the page.

How can i echo $this-Html-meta at the top of the page (inside head
tag) and have the scripts_for_layout at the bottom?

Thank you!

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Re: CakeFest 2011

2011-09-16 Thread Brett Wilton
Look forward to it, he could punch out a couple at a time :-)

Also if you email the group when the odd one gets added would be appreciated.


On 16/09/2011, at 7:00 PM, Walther wrote:

 Octavian, I spoke with Larry the other day. He has something like 44
 videos to transcode, edit and upload. It is going to take a while, but
 it will be done.
 

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Re: hi guys

2011-09-16 Thread O.J. Tibi
Hi aortizhi,

I think it's not really something related to CakePHP. You're question is 
about JavaScript. If I was in your situation, I'd code my `prueba()` 
function to submit the form using AJAX. :)

OJ

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