Re: How lo load a model from a model?
Is there a benefit/drawback to using
ClassRegistry::init('Objekt')->translateStrings($results); in this
situation?
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Re: How lo load a model from a model?
Use:
$this->load('Objeckt); instead of App::uses()
Em terça-feira, 6 de março de 2012 08h14min42s UTC-3, heohni escreveu:
>
> Hi,
>
> class DetailsController extends AppController{
> var $name = 'Detail';
>
> public function index($id){
> if($id){
> $results = $this->Detail->find('first', $conditions['Gesamtobjekt']);
>
> App::uses('Objekt', 'Model');
> $results = $this->Objekt->translateStrings($results);debug($results);
> }
> }
> }
>
> What do I have to do, to get the $this->Objekt->translateStrings working?
> Right niow, I only get
> *Fatal error*: Call to a member function translateStrings()
> Message.
>
> What do I miss?
> I tried to get an info from the book, but I only find how to write the
> App::uses but I didn't find any further note..
>
> Please advice!
>
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Re: How lo load a model from a model?
Put in a Behaviour and apply the behaviour to each model that needs to use it.
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 6 Mar 2012, at 11:37:03, heohni wrote:
> No there is not.
> But I just found out that I can use it this way:
>
> $results = Objekt::translateStrings($results);
>
> But - the function translateStrings() is using inside a call to
> $this->ExtractUet() and now it happens that I get the message
> Fatal error: Call to undefined method DetailsController::ExtractUet()
>
> What do I have to do? In order to use the complete translateStrings
> functionality?
>
>
> Am Dienstag, 6. März 2012 12:17:28 UTC+1 schrieb Jeremy Burns:
> Is there a model association between the two models? If so, you can daisy
> chain them:
>
> $results = $this->Detail->Objekt->translateStrings($results);debug($results);
>
>
> Jeremy Burns
> Class Outfit
>
> http://www.classoutfit.com
>
> On 6 Mar 2012, at 11:14:42, heohni wrote:
>
>> Hi,
>>
>> class DetailsController extends AppController{
>> var $name = 'Detail';
>>
>> public function index($id){
>> if($id){
>> $results = $this->Detail->find('first', $conditions['Gesamtobjekt']);
>>
>> App::uses('Objekt', 'Model');
>> $results = $this->Objekt->translateStrings($results);debug($results);
>> }
>> }
>> }
>>
>> What do I have to do, to get the $this->Objekt->translateStrings working?
>> Right niow, I only get
>> Fatal error: Call to a member function translateStrings()
>> Message.
>>
>> What do I miss?
>> I tried to get an info from the book, but I only find how to write the
>> App::uses but I didn't find any further note..
>>
>> Please advice!
>>
>> --
>> Our newest site for the community: CakePHP Video Tutorials
>> http://tv.cakephp.org
>> Check out the new CakePHP Questions site http://ask.cakephp.org and help
>> others with their CakePHP related questions.
>>
>>
>> To unsubscribe from this group, send email to
>> cake-php+unsubscr...@googlegroups.com For more options, visit this group at
>> http://groups.google.com/group/cake-php
>
>
> --
> Our newest site for the community: CakePHP Video Tutorials
> http://tv.cakephp.org
> Check out the new CakePHP Questions site http://ask.cakephp.org and help
> others with their CakePHP related questions.
>
>
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Re: How lo load a model from a model?
No there is not.
But I just found out that I can use it this way:
$results = Objekt::translateStrings($results);
But - the function translateStrings() is using inside a call to
$this->ExtractUet() and now it happens that I get the message
*Fatal error*: Call to undefined method DetailsController::ExtractUet()
What do I have to do? In order to use the complete translateStrings
functionality?
Am Dienstag, 6. März 2012 12:17:28 UTC+1 schrieb Jeremy Burns:
>
> Is there a model association between the two models? If so, you can daisy
> chain them:
>
> $results =
> $this->Detail->Objekt->translateStrings($results);debug($results);
>
>
> Jeremy Burns
> Class Outfit
>
> http://www.classoutfit.com
>
> On 6 Mar 2012, at 11:14:42, heohni wrote:
>
> Hi,
>
> class DetailsController extends AppController{
> var $name = 'Detail';
>
> public function index($id){
> if($id){
> $results = $this->Detail->find('first', $conditions['Gesamtobjekt']);
>
> App::uses('Objekt', 'Model');
> $results = $this->Objekt->translateStrings($results);debug($results);
> }
> }
> }
>
> What do I have to do, to get the $this->Objekt->translateStrings working?
> Right niow, I only get
> *Fatal error*: Call to a member function translateStrings()
> Message.
>
> What do I miss?
> I tried to get an info from the book, but I only find how to write the
> App::uses but I didn't find any further note..
>
> Please advice!
>
> --
> Our newest site for the community: CakePHP Video Tutorials
> http://tv.cakephp.org
> Check out the new CakePHP Questions site http://ask.cakephp.org and help
> others with their CakePHP related questions.
>
>
> To unsubscribe from this group, send email to
> cake-php+unsubscr...@googlegroups.com For more options, visit this group
> at http://groups.google.com/group/cake-php
>
>
>
--
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http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others
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Re: How lo load a model from a model?
Is there a model association between the two models? If so, you can daisy chain
them:
$results = $this->Detail->Objekt->translateStrings($results);debug($results);
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 6 Mar 2012, at 11:14:42, heohni wrote:
> Hi,
>
> class DetailsController extends AppController{
> var $name = 'Detail';
>
> public function index($id){
> if($id){
> $results = $this->Detail->find('first', $conditions['Gesamtobjekt']);
>
> App::uses('Objekt', 'Model');
> $results = $this->Objekt->translateStrings($results);debug($results);
> }
> }
> }
>
> What do I have to do, to get the $this->Objekt->translateStrings working?
> Right niow, I only get
> Fatal error: Call to a member function translateStrings()
> Message.
>
> What do I miss?
> I tried to get an info from the book, but I only find how to write the
> App::uses but I didn't find any further note..
>
> Please advice!
>
> --
> Our newest site for the community: CakePHP Video Tutorials
> http://tv.cakephp.org
> Check out the new CakePHP Questions site http://ask.cakephp.org and help
> others with their CakePHP related questions.
>
>
> To unsubscribe from this group, send email to
> cake-php+unsubscr...@googlegroups.com For more options, visit this group at
> http://groups.google.com/group/cake-php
--
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How lo load a model from a model?
Hi,
class DetailsController extends AppController{
var $name = 'Detail';
public function index($id){
if($id){
$results = $this->Detail->find('first', $conditions['Gesamtobjekt']);
App::uses('Objekt', 'Model');
$results = $this->Objekt->translateStrings($results);debug($results);
}
}
}
What do I have to do, to get the $this->Objekt->translateStrings working?
Right niow, I only get
*Fatal error*: Call to a member function translateStrings()
Message.
What do I miss?
I tried to get an info from the book, but I only find how to write the
App::uses but I didn't find any further note..
Please advice!
--
Our newest site for the community: CakePHP Video Tutorials
http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others
with their CakePHP related questions.
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
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