newbie: mysql backend "Error was: cannot import name conversions" with subversion build of django

[harijay]

Hi I just started using the subversion build of django and mysql-
python with python 2.6.3
Both django (svn 12103) and _mysql (MySQLdb rev 635) work fine and can
be imported from the command line python without any error messages.
I created a new django testproject and then modified my settings.py to
use the mysql backend ( see DATABASE section below).

But when I start python manage.py runserver 8080 , I get an error
which I am reproducing here indicating that the backend was not
started.

Any ideas on what I need to change to have my django launch with the
mysql backend.
Thanks
harijay

The error I get is

^Chariharan-jayarams-macbook-pro-17:testdjnew hari$ python manage.py
runserver 8080
Validating models...
Unhandled exception in thread started by 
Traceback (most recent call last):
  File "/Users/hari/djtrunk/django/core/management/commands/
runserver.py", line 48, in inner_run
self.validate(display_num_errors=True)
  File "/Users/hari/djtrunk/django/core/management/base.py", line 249,
in validate
num_errors = get_validation_errors(s, app)
  File "/Users/hari/djtrunk/django/core/management/validation.py",
line 22, in get_validation_errors
from django.db import models, connection
  File "/Users/hari/djtrunk/django/db/__init__.py", line 74, in

connection = connections[DEFAULT_DB_ALIAS]
  File "/Users/hari/djtrunk/django/db/utils.py", line 75, in
__getitem__
backend = load_backend(db['ENGINE'])
  File "/Users/hari/djtrunk/django/db/utils.py", line 37, in
load_backend
raise ImproperlyConfigured(error_msg)
django.core.exceptions.ImproperlyConfigured:
'django.db.backends.mysql' isn't an available database backend.
Try using django.db.backends.XXX, where XXX is one of:
'dummy', 'mysql', 'oracle', 'postgresql', 'postgresql_psycopg2',
'sqlite3'
Error was: cannot import name conversions

My settings.py has nothing special after my new settings.py creation
other than the following database section:

DATABASES = {
'default': {
'ENGINE': 'django.db.backends.mysql', # Add
'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
'NAME': 'mytestdb',  # Or path to database
file if using sqlite3.
'USER': 'root',  # Not used with sqlite3.
'PASSWORD': 'mypass',  # Not used with
sqlite3.
'HOST': '',  # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '',  # Set to empty string for
default. Not used with sqlite3.
}
}


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Re: Help with a query :$

[Marc Aymerich]

On Tue, Jan 5, 2010 at 8:09 AM, greatlemer wrote:

> On Jan 5, 4:00 am, Marc Aymerich  wrote:
> > Hi!
> > I have a model like this:
> >
> > class company(models.model):
> > name = models.CharField(mx_length=20)
> >  class employee(models.model):
> > comany = models.ForeignKey(company)
> >  class user(models.model):
> > person = models.OneToOneField(person)
> >
> > One company can have multiple employees but one employee only can have
> one
> > user.
> >
> > I know how to get all employees for a company
> >
> > company.objects.get(name='companyname').employee_set.all()
> >
> > But.. How can I get all users for a company?
> >
> > I try with
> >
> >
> user.objects.get(employee=company.objects.get(name='companyname').employee_
> set.all())
> > company.objects.get(name='companyname').employee_set.all().user
> >
> > but this approach only works with a single object, like this:
> >
> >
> user.objects.get(employee=company.objects.get(name='companyname').employee_
> set.all()[2])
> > company.objects.get(name='companyname').employee_set.all()[2].user
> >
> > any idea in how can I get all users for a company?
> >
> > Thanks a lot!
> > Marc.
>
> You want to use filter [1] with something like:
> user.objects.filter(employee__company__name='companyname')
>
>
>[1]
> http://docs.djangoproject.com/en/dev/topics/db/queries/#retrieving-specific-objects-with-filters
> --
>
> G
>

Thank you very much!! :D


>
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Re: Help with a query :$

[greatlemer]

On Jan 5, 4:00 am, Marc Aymerich  wrote:
> Hi!
> I have a model like this:
>
> class company(models.model):
> name = models.CharField(mx_length=20)
>  class employee(models.model):
> comany = models.ForeignKey(company)
>  class user(models.model):
> person = models.OneToOneField(person)
>
> One company can have multiple employees but one employee only can have one
> user.
>
> I know how to get all employees for a company
>
> company.objects.get(name='companyname').employee_set.all()
>
> But.. How can I get all users for a company?
>
> I try with
>
> user.objects.get(employee=company.objects.get(name='companyname').employee_ 
> set.all())
> company.objects.get(name='companyname').employee_set.all().user
>
> but this approach only works with a single object, like this:
>
> user.objects.get(employee=company.objects.get(name='companyname').employee_ 
> set.all()[2])
> company.objects.get(name='companyname').employee_set.all()[2].user
>
> any idea in how can I get all users for a company?
>
> Thanks a lot!
> Marc.

You want to use filter [1] with something like:
user.objects.filter(employee__company__name='companyname')


[1] 
http://docs.djangoproject.com/en/dev/topics/db/queries/#retrieving-specific-objects-with-filters
--

G

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Re: Django Gantt Chart

[Waqqas Jabbar]

http://code.google.com/p/django-graphviz/

On Mon, Jan 4, 2010 at 9:42 PM, Hinnack wrote:

> what about:
> http://matplotlib.sourceforge.net/
>
> --
> Hinnack
>
> 2010/1/4 Daniel Hilton 
>
> 2010/1/4 Alessandro Ronchi :
>> > I need to make a simple chart with a list of projects and a grafic
>> > display of the end date with a link to the project page.
>> > It's simpler than a gantt chart.
>> >
>> > Is there any library / snippet I can use to simplify my work?
>> >
>>
>> Hmmm, as I'm about to do something similar I've also researched this.
>>
>> If you're just looking at displaying a list of objects(projects) then
>> you can use a generic view and then handle the display in the
>> template, which means the following links may be of help:
>>
>> http://www.jlion.com/docs/gantt.aspx
>> http://www.jsgantt.com/
>>
>> Niether of which are particularly pretty but the basics are there
>> ready to be reskinned.
>>
>> http://www.ext-scheduler.com/examples.html
>>
>> Is however, pretty awesome, if commercially licensed.
>>
>> This question on stackoverflow is pretty extensive as well:
>> http://stackoverflow.com/questions/1005587/gantt-chart-online
>>
>> If I don't find one I like, I'm thinking about writing a template tag
>> and some jQuery to make a nice dependency graph.
>> HTH,
>> Dan
>>
>>
>>
>>
>> > --
>> > Alessandro Ronchi
>> >
>> > http://www.soasi.com
>> > SOASI - Sviluppo Software e Sistemi Open Source
>> >
>> > http://hobbygiochi.com
>> > Hobby & Giochi, l'e-commerce del divertimento
>> >
>> > --
>> >
>> > You received this message because you are subscribed to the Google
>> Groups "Django users" group.
>> > To post to this group, send email to django-us...@googlegroups.com.
>> > To unsubscribe from this group, send email to
>> django-users+unsubscr...@googlegroups.com
>> .
>> > For more options, visit this group at
>> http://groups.google.com/group/django-users?hl=en.
>> >
>> >
>> >
>>
>>
>>
>> --
>> Dan Hilton
>> 
>> www.twitter.com/danhilton
>> www.DanHilton.co.uk
>> 
>>
>> --
>>
>> You received this message because you are subscribed to the Google Groups
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>>
>>
>>
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Search box: Nothing to repeat error

[Delacroy Systems]

I want to allow a user to search for a value and return the results
using the object_list generic view. How can I get this working?

business_search.html:
{% block content %}

Business name:

{% endblock content %}

urls.py:
(r'^?business=(?P\w+)/','businessnamesearch_view'),

views.py: (field in models.py to search on is named business)
def businessnamesearch_view(request, business_name):
business = Business.objects.filter
(business__icontains=business_name)
return object_list(request, queryset=business)

I have a template, business_list.html that works already.

I get the error:
Request Method: GET
Request URL:http://127.0.0.1:8000/business/?business=AB
Exception Type: error
Exception Value:nothing to repeat

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Re: TypeError: 'CharField' object is not callable

[E. Hakan Duran]

On Monday 04 January 2010 23:54:13 Marc Aymerich wrote:
> ...
> take a look at middle_initial of woman class ;)

Thank you very much for the fast and accurate response. Now it worked without 
problem.


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Re: TypeError: 'CharField' object is not callable

[Marc Aymerich]

On Tue, Jan 5, 2010 at 5:24 AM, hakova  wrote:

> Hi all,
>
> I am a 'very' inexperienced django user with no programming
> background, so please be gentle with me  :).
>
> I just typed the following models.py file under my project_name/
> app_name:
>
> # -*- coding: utf-8 -*-
> from django.db import models
>
> # Create your models here.
> class Couple(models.Model):
>coupleid = models.AutoField('Couple ID', primary_key=True)
>entry_date = models.DateField('Date Entered')
>home_address1 = models.CharField(max_length=200)
>home_address2 = models.CharField(max_length=200)
>home_phone = models.CharField(max_length=20)
>
> class Woman(models.Model):
>couple = models.ForeignKey(Couple)
>lastname = models.CharField(max_length=100)
>firstname = models.CharField(max_length=100)
>middle_initial = models.CharField = models.CharField(max_length=1)
>ssn = models.PositiveIntegerField('SSN')
>dob = models.DateField('Date of Birth')
>cell_phone = models.CharField(max_length=20)
>email = models.EmailField()
>picture = models.ImageField(upload_to="photos/")
>work_address1 = models.CharField(max_length=200)
>work_address2 = models.CharField(max_length=200)
>work_phone = models.CharField(max_length=20)
>fax = models.CharField(max_length=20)
>
> class Man(models.Model):
>couple = models.ForeignKey(Couple)
>lastname = models.CharField(max_length=100)
>firstname = models.CharField(max_length=100)
>middle_initial = models.CharField = models.CharField(max_length=1)
>ssn = models.PositiveIntegerField('SSN')
>dob = models.DateField('Date of Birth')
>cell_phone = models.CharField(max_length=20)
>email = models.EmailField()
>picture = models.ImageField(upload_to="photos/")
>work_address1 = models.CharField(max_length=200)
>work_address2 = models.CharField(max_length=200)
>work_phone = models.CharField(max_length=20)
>fax = models.CharField(max_length=20)
>
> Then I ran the command as described in tutorial 1:
> python manage.py sql app_name
>
> However, it gives me the error message listed on the subject line.
> Entire message is posted below:
>
> Traceback (most recent call last):
>  File "manage.py", line 11, in 
>execute_manager(settings)
>  File "/usr/lib/python2.6/site-packages/django/core/management/
> __init__.py", line 362, in execute_manager
>utility.execute()
>  File "/usr/lib/python2.6/site-packages/django/core/management/
> __init__.py", line 303, in execute
>self.fetch_command(subcommand).run_from_argv(self.argv)
>  File "/usr/lib/python2.6/site-packages/django/core/management/
> base.py", line 195, in run_from_argv
>self.execute(*args, **options.__dict__)
>  File "/usr/lib/python2.6/site-packages/django/core/management/
> base.py", line 221, in execute
>self.validate()
>  File "/usr/lib/python2.6/site-packages/django/core/management/
> base.py", line 249, in validate
>num_errors = get_validation_errors(s, app)
>  File "/usr/lib/python2.6/site-packages/django/core/management/
> validation.py", line 28, in get_validation_errors
>for (app_name, error) in get_app_errors().items():
>  File "/usr/lib/python2.6/site-packages/django/db/models/loading.py",
> line 131, in get_app_errors
>self._populate()
>  File "/usr/lib/python2.6/site-packages/django/db/models/loading.py",
> line 58, in _populate
>self.load_app(app_name, True)
>  File "/usr/lib/python2.6/site-packages/django/db/models/loading.py",
> line 74, in load_app
>models = import_module('.models', app_name)
>  File "/usr/lib/python2.6/site-packages/django/utils/importlib.py",
> line 35, in import_module
>__import__(name)
>  File "/home/~/../project_name/app_name/models.py", line 12, in
> 
>class Woman(models.Model):
>  File "/home/~/../project_name/app_name/models.py", line 19, in Woman
>cell_phone = models.CharField(max_length=20)
> TypeError: 'CharField' object is not callable
>
> Any ideas, pointers will be very much appreciated.
>
>
take a look at middle_initial of woman class ;)



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>
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TypeError: 'CharField' object is not callable

[hakova]

Hi all,

I am a 'very' inexperienced django user with no programming
background, so please be gentle with me  :).

I just typed the following models.py file under my project_name/
app_name:

# -*- coding: utf-8 -*-
from django.db import models

# Create your models here.
class Couple(models.Model):
coupleid = models.AutoField('Couple ID', primary_key=True)
entry_date = models.DateField('Date Entered')
home_address1 = models.CharField(max_length=200)
home_address2 = models.CharField(max_length=200)
home_phone = models.CharField(max_length=20)

class Woman(models.Model):
couple = models.ForeignKey(Couple)
lastname = models.CharField(max_length=100)
firstname = models.CharField(max_length=100)
middle_initial = models.CharField = models.CharField(max_length=1)
ssn = models.PositiveIntegerField('SSN')
dob = models.DateField('Date of Birth')
cell_phone = models.CharField(max_length=20)
email = models.EmailField()
picture = models.ImageField(upload_to="photos/")
work_address1 = models.CharField(max_length=200)
work_address2 = models.CharField(max_length=200)
work_phone = models.CharField(max_length=20)
fax = models.CharField(max_length=20)

class Man(models.Model):
couple = models.ForeignKey(Couple)
lastname = models.CharField(max_length=100)
firstname = models.CharField(max_length=100)
middle_initial = models.CharField = models.CharField(max_length=1)
ssn = models.PositiveIntegerField('SSN')
dob = models.DateField('Date of Birth')
cell_phone = models.CharField(max_length=20)
email = models.EmailField()
picture = models.ImageField(upload_to="photos/")
work_address1 = models.CharField(max_length=200)
work_address2 = models.CharField(max_length=200)
work_phone = models.CharField(max_length=20)
fax = models.CharField(max_length=20)

Then I ran the command as described in tutorial 1:
python manage.py sql app_name

However, it gives me the error message listed on the subject line.
Entire message is posted below:

Traceback (most recent call last):
  File "manage.py", line 11, in 
execute_manager(settings)
  File "/usr/lib/python2.6/site-packages/django/core/management/
__init__.py", line 362, in execute_manager
utility.execute()
  File "/usr/lib/python2.6/site-packages/django/core/management/
__init__.py", line 303, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/usr/lib/python2.6/site-packages/django/core/management/
base.py", line 195, in run_from_argv
self.execute(*args, **options.__dict__)
  File "/usr/lib/python2.6/site-packages/django/core/management/
base.py", line 221, in execute
self.validate()
  File "/usr/lib/python2.6/site-packages/django/core/management/
base.py", line 249, in validate
num_errors = get_validation_errors(s, app)
  File "/usr/lib/python2.6/site-packages/django/core/management/
validation.py", line 28, in get_validation_errors
for (app_name, error) in get_app_errors().items():
  File "/usr/lib/python2.6/site-packages/django/db/models/loading.py",
line 131, in get_app_errors
self._populate()
  File "/usr/lib/python2.6/site-packages/django/db/models/loading.py",
line 58, in _populate
self.load_app(app_name, True)
  File "/usr/lib/python2.6/site-packages/django/db/models/loading.py",
line 74, in load_app
models = import_module('.models', app_name)
  File "/usr/lib/python2.6/site-packages/django/utils/importlib.py",
line 35, in import_module
__import__(name)
  File "/home/~/../project_name/app_name/models.py", line 12, in

class Woman(models.Model):
  File "/home/~/../project_name/app_name/models.py", line 19, in Woman
cell_phone = models.CharField(max_length=20)
TypeError: 'CharField' object is not callable

Any ideas, pointers will be very much appreciated.

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Help with a query :$

[Marc Aymerich]

Hi!
I have a model like this:

class company(models.model):
name = models.CharField(mx_length=20)
 class employee(models.model):
comany = models.ForeignKey(company)
 class user(models.model):
person = models.OneToOneField(person)

One company can have multiple employees but one employee only can have one
user.

I know how to get all employees for a company

company.objects.get(name='companyname').employee_set.all()

But.. How can I get all users for a company?

I try with

user.objects.get(employee=company.objects.get(name='companyname').employee_set.all())
company.objects.get(name='companyname').employee_set.all().user

but this approach only works with a single object, like this:

user.objects.get(employee=company.objects.get(name='companyname').employee_set.all()[2])
company.objects.get(name='companyname').employee_set.all()[2].user

any idea in how can I get all users for a company?

Thanks a lot!
Marc.

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Re: ModelMultipleChoiceField for a ManyToManyField relation to attach Images to a blogpost by using BlogForm

[GoSantoni]

Hey Daniel,

Thanks for response, as always helpful and quick. Like you suggested I
changed the fields to the class. This resulted in a error because
BlogForm could not be found. So I decided not to bother the photologue
model but import the Images into the blog model. This resulted in:

* blog models.py **
from photos.models import Image, Pool

class blog(models.Model)

class Post(models.Model):
blog = models.ForeignKey(blog)
item= models.CharField(_('item'), max_length=200)
imagepost = models.ManyToManyField(Image, blank=True,
verbose_name=_('post'))

* blog forms.py **
class BlogForm(forms.ModelForm):

slug = forms.SlugField(max_length=20,
help_text = _("a short version of the title consisting only of
letters, numbers, underscores and hyphens."),
error_message = _("This value must contain only letters, numbers,
underscores and hyphens."),
imagepost = forms.ModelMultipleChoiceField
(queryset=Image.objects.all())

def __init__(self, user=None, *args, **kwargs):
self.user = user
super(BlogForm, self).__init__(*args, **kwargs)
self.fields["imagepost"].queryset = Image.objects.all()

class Meta:

model = Post
exclude = ('author', 'creator_ip', 'created_at', 'updated_at',
'publish')


This resolves is in a AttributeError 'module' object has no attribute
'objects'. This is strange because the photos view uses a similar
queryset: photos = Image.objects.filter(member=request.user) Again i
just like to render the titles/urls of the images to attach them to
the posts.

Cheers

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Re: Generic view object_detail on a m2m relationship

[邓超]

Try to make a loop in the template, I guess that may can work

2010/1/5 Delacroy Systems 

> This is how I did it in views.py:
>
> def businessshowservice_view(request, business_id):
>business = Business.objects.get(pk=business_id)
>services = Business.objects.get(pk=business_id).service_set.all()
>return object_list(request, queryset=services,
>   extra_context={'business' : business}
>)
>
> (now just have to figure out a way to get my stress back!)
>
> On Jan 4, 7:55 pm, Delacroy Systems  wrote:
> > I see that using object_detail is the 'incorrect' generic view to show
> > details. I am exploring other options, including writing a custom view
> > to give me what I want.
> >
> > On Jan 4, 8:29 am, Delacroy Systems  wrote:
> >
> > > I am trying to use the generic view, object_detail on a m2m
> > > relationship. I have multiple businesses that offer multiple services.
> > > I would like to show the services offered by each business. At the
> > > moment, I see all the services - not just the services that a
> > > particular business is offering.
> >
> > > In models.py:
> > > class Business(models.Model):
> > >   business = models.CharField(max_length=100)
> >
> > > class Service(models.Model):
> > >   service = models.CharField(max_length=100)
> > >   providers = models.ManyToManyField(Business, through =
> > > "BusinessService")
> >
> > > class BusinessService(models.Model):
> > >   business = models.ForeignKey(Business)
> > >   service = models.ForeignKey(Service)
> >
> > > In urls.py:
> > > def get_service():
> > > return Service.objects.all()
> >
> > > businessservice_list = {
> > > #'queryset' : BusinessService.objects.all(),
> > > 'queryset' : Business.objects.all(),
> > > 'extra_context': {'service_list': get_service}
> >
> > > ...skip some detail...
> > > (r'^showservice/(?P\d+)/$', list_detail.object_detail,
> > > businessservice_list),
> >
> > > In business_detail.html:
> > > {% block content %}
> > > Business Services
> > >   {% if object %}
> > > {{ object.business }}
> > > {{ service_list }}
> > >   {% endif %}
> > > {% endblock content%}
> >
> >
>
> --
>
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> "Django users" group.
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> http://groups.google.com/group/django-users?hl=en.
>
>
>


-- 
Deng Chao

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Creating multiple related objects to a given QuerySet without evaluating the QuerySet

[David]

I have a QuerySet of Books, and I want to create an Action for each
Book in that QuerySet. I want to avoid evaluating the Books QuerySet,
but the only way I can think of doing what I want to do evaluates it.
For example,

def create_actions(books, action)
 books is a QuerySet of Book"""
for book in books:
Action(book=book, action=action).save()

any suggestions on how I can do this without evaluating books?

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adding custom variables to the Meta class

[HARRY POTTRER]

I have an class that I created which takes a queryset, and a field on
the model that the queryset represents. Like this:

mc = MyClass(queryset=MyModel.objects.all(), lat_lng_field='lat_lng')

The class basically filters the queryset based on some geographical
values, but in order to do that, it needs to know which field the
coordinates are stored in.

Right now I have no choice but require you to pass in a string
representing the field name. But I think a better way would be to do
it kind of like this:

class MyModel(models.Model):
lat_lng = PointField()
name = CharFIeld(max_length=20)

class Meta:
verbose_name_plural = 'My Models'
lat_lng_field = 'lat_lng'

Then just modify MyClass to get the field name from the Model's Meta
class. Is this possible somehow? If not, whats the best way to go
about this without having to pass in the field name directly?

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Models, forms and inlineformset

[Stefan Nitsche]

Hi,

to begin with I would like to declare that I'm still on the beginner end of
the scale when it comes to Python and Django.

I have an app which has two models:

class Item(models.Model):
title = models.CharField()
description_markdown = models.TextField()

class ItemImage(models.Model):
item = models.ForeignKey(Item)
image = models.ImageField(upload_to='tmp')

What I want to do now is to create a page where users can submit an item and
upload an image (or images) at the same time. I can create a form using
ModelForm for the Item-model and I can create a form for the ItemImage-model
using inlineformset_factory, if I do this the submit page looks like it
should. However it doesn't behave the way I want it to when saving, but to
be honest I have no real idea of what I'm doing when it comes to the related
model/form.

If I understand it correctly when using inlineformset_factory I must give it
an instance so that it can map the foreignkey, correct? So how do one go
about and create a form where people can add "item" and "itemimages" at the
same time? I'm feeling totaly lost any pointers would be greatly
appreciated.

-- 
Stefan Nitsche
ste...@nitsche.se

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Trying to implement a unique default relationship between models

[Eric Chamberlain]

Hello,

I'm trying to implement a default relationship between models.

Each otherApp.Partner model can have zero or more Registration models.  
One Registration per otherApp.Partner can be flagged as the default 
(default_reg).

What I would like is for the default_reg boolean to be configurable from the 
Admin.  I've written up the code below.  Save properly updates the other 
Relationships, but the Admin form validation won't allow (unique error) another 
Registration to be set as the default, until the first Registration is 
unflagged.

How do I override the form validation or have it ignore the unique constraint, 
because it is handled in the model save method?

Or is there a better way to do this?


class BasePartnerModel(BaseRFModel):
""" Adds the partner key to the model. """
partner = ForeignKey('otherApp.Partner')

class Meta:
abstract = True


class Registration(BasePartnerModel):
""" When a user registers with us before registering with a partner, we 
need to send the
user's information to the partner.  This model tracks where to send the 
registration
information, and maps the results between the partner and us."""
# TrueNoneField from http://www.djangosnippets.org/snippets/1831/
default_reg = 
TrueNoneField(default=None,verbose_name=_('default'),help_text=_('Default 
registration if one is not specifed, if no default, first one is used.'))


def save(self, force_insert=False, force_update=False):
if self.default_reg is True:
# if this is the new default, set others to False

Registration.objects.filter(partner=self.partner).exclude(pk=self.pk).update(default_reg=None)

super(Registration, self).save(force_insert, force_update) # Call the 
"real" save() method.

class Meta:
unique_together = (('partner','default_reg'),)



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Re: Django, Apache, mod_wsgi, GET works, POST doesn't

[Bill Freeman]

Can you make it fail in the development server, with DEBUG turned on?

If so, you can get more helpful error display and/or do pdb.set_trace() and
poke around.

On Mon, Jan 4, 2010 at 4:25 PM, Patrick May  wrote:
> Hi,
>
> I have Django running under Apache with mod_wsgi.  I've got a simple URL 
> handler that looks like this:
>
> def handler(request):
>    response = None
>
>    if request.method == 'POST' or request.method == 'PUT':
>        response = HTTPResponse(status=201)
>    elif request.method == 'GET':
>        response = HttpResponse("Success")
>    else:
>        raise Http404
>
>    return response
>
> My django.wsgi looks like this:
>
> import os
> import sys
>
> sys.path.append('/Users/Patrick/codestreet/src/rest')
>
> os.environ['DJANGO_SETTINGS_MODULE'] = 'server.settings'
>
> import django.core.handlers.wsgi
>
> application = django.core.handlers.wsgi.WSGIHandler()
>
> When I connect to the URL for the handler with a GET like this:
>
>        request = urllib2.Request(self.URL)
>
> it works fine, returning a 200.  However, when I connect with a POST like 
> this:
>
>        request = urllib2.Request(self.URL,self.data)
>
> I get an exception thrown with a 500 code and this in the Apache error log:
>
> [Mon Jan 04 16:20:08 2010] [error] [client ::1] mod_wsgi (pid=48698): 
> Exception occurred processing WSGI script 
> '/Users/Patrick/codestreet/src/rest/django.wsgi'.
> [Mon Jan 04 16:20:08 2010] [error] [client ::1] IOError: failed to write data
>
> Do I have something misconfigured?
>
> Thanks,
>
> Patrick
>
> --
>
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>
>
>

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Re: Django, Apache, mod_wsgi, GET works, POST doesn't

[Daniel Roseman]

On Jan 4, 9:25 pm, Patrick May  wrote:
> Hi,
>
> I have Django running under Apache with mod_wsgi.  I've got a simple URL 
> handler that looks like this:
>
> def handler(request):
>     response = None
>
>     if request.method == 'POST' or request.method == 'PUT':
>         response = HTTPResponse(status=201)
>     elif request.method == 'GET':
>         response = HttpResponse("Success")
>     else:
>         raise Http404
>
>     return response
>
> My django.wsgi looks like this:
>
> import os
> import sys
>
> sys.path.append('/Users/Patrick/codestreet/src/rest')
>
> os.environ['DJANGO_SETTINGS_MODULE'] = 'server.settings'
>
> import django.core.handlers.wsgi
>
> application = django.core.handlers.wsgi.WSGIHandler()
>
> When I connect to the URL for the handler with a GET like this:
>
>         request = urllib2.Request(self.URL)
>
> it works fine, returning a 200.  However, when I connect with a POST like 
> this:
>
>         request = urllib2.Request(self.URL,self.data)
>
> I get an exception thrown with a 500 code and this in the Apache error log:
>
> [Mon Jan 04 16:20:08 2010] [error] [client ::1] mod_wsgi (pid=48698): 
> Exception occurred processing WSGI script 
> '/Users/Patrick/codestreet/src/rest/django.wsgi'.
> [Mon Jan 04 16:20:08 2010] [error] [client ::1] IOError: failed to write data
>
> Do I have something misconfigured?
>
> Thanks,
>
> Patrick

Assuming the code you've posted is a real cut and paste, you have
"HTTPResponse" for POST but "HttpResponse" for GET. Python is case-
sensitive, so only "HttpResponse" will work.
--
DR.

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Django, Apache, mod_wsgi, GET works, POST doesn't

[Patrick May]

Hi,

I have Django running under Apache with mod_wsgi.  I've got a simple URL 
handler that looks like this:

def handler(request):
response = None

if request.method == 'POST' or request.method == 'PUT':
response = HTTPResponse(status=201)
elif request.method == 'GET':
response = HttpResponse("Success")
else:
raise Http404

return response

My django.wsgi looks like this:

import os
import sys

sys.path.append('/Users/Patrick/codestreet/src/rest')
 
os.environ['DJANGO_SETTINGS_MODULE'] = 'server.settings'

import django.core.handlers.wsgi

application = django.core.handlers.wsgi.WSGIHandler()

When I connect to the URL for the handler with a GET like this:

request = urllib2.Request(self.URL)

it works fine, returning a 200.  However, when I connect with a POST like this:

request = urllib2.Request(self.URL,self.data)

I get an exception thrown with a 500 code and this in the Apache error log:

[Mon Jan 04 16:20:08 2010] [error] [client ::1] mod_wsgi (pid=48698): Exception 
occurred processing WSGI script 
'/Users/Patrick/codestreet/src/rest/django.wsgi'.
[Mon Jan 04 16:20:08 2010] [error] [client ::1] IOError: failed to write data

Do I have something misconfigured?

Thanks,

Patrick

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Re: Changing the database name by subdomain name

[Daniel Roseman]

On Jan 4, 4:28 pm, bluellyr  wrote:
> Hi!
>
> I'm using the Django 1.0.2 and trying to connect to a diferent
> database name using the subdomain by reference,
> when I accesshttp://.mydomain.comI want to connect to the ""
> database and when accessing to thehttp://.mydomain.comI want to connect 
> to the "" database.
>
> There is a way to do this?
>
> I'm trying but I can not find nothing about how to get the subdomain
> from the url.
>
> thanks

Have different vhosts for each subdomain, each using a separate
settings.py file with its own database name.
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Re: Photo + thumbnail

[nameless]

Thank you. I have just writed this code.
It works but I want to avoit to save 2 times with "super(book,
self).save()" ( see below ):


from django.db import models
from PIL import Image
import glob, os

thumb_size = 90, 90

class book(models.Model):
title = models.CharField(max_length=200)
photo = models.ImageField(upload_to='photo_book')
thumb = models.ImageField(upload_to='thumb_book', blank=True,
null=True)



def save(self):
super(book, self).save()
file_path = self.photo.url
if (file_path):
im = Image.open(file_path)
im.thumbnail(thumb_size, Image.ANTIALIAS)
root, immagin = os.path.split(file_path)
immagin, ext = os.path.splitext(immagin)
im.save("thumb_book/" + immagin + ".thumbnail.jpg",
"JPEG")
self.thumb = "thumb_book/" + immagin + ".thumbnail.jpg"
super(book, self).save()




On Jan 4, 5:03 pm, Justin Myers  wrote:
> I'm not able to test this idea directly myself at the moment, but it
> appears you're storing an absolute path (i.e., starting from the
> filesystem root) in self.thumb. I'm pretty sure FileFields (and, by
> extension, ImageFields) store relative paths from settings.MEDIA_ROOT.
>
> (To make sure I'm thinking about this properly (since again, I can't
> double-check this right now), you might want to see what the value of
> the thumb field is in the database first. If I'm right, you should see
> a path that consists of a relative path followed by an absolute one,
> such as "2010/0104//home/username/webapps/media/2010/0104/
> something.thumbnail.jpg".)
>
> An absolute path is certainly helpful for actually operating on the
> file, but before
> self.thumb = imfile + ".thumbnail.jpg"
> you'll need something like
> imfile, ext = os.path.splitext(self.photo)  # NOT .path, so this
> is a relative path, not an absolute one
> to make this work properly.
>
> Hope that helps.
> -Justin
>
> On Jan 4, 5:15 am, nameless  wrote:
>
> > I have writed this code but it doesn't work. What is the error ?
>
> > from django.db import models
> > from django.forms import ModelForm
> > from PIL import Image
> > import glob, os
>
> > thumb_size = 90, 90
>
> > class book(models.Model):
> > title = models.CharField(max_length=200)
> > photo = models.ImageField(upload_to='bookphoto')
> > thumb = models.ImageField(upload_to='bookthumb')
>
> > def save(self):
>
> > file_path = self.photo.path
> > if (file_path):
> > imfile, ext = os.path.splitext(file_path)
> > im = Image.open(file_path)
> > im.thumbnail(thumb_size, Image.ANTIALIAS)
> > im.save(imfile + ".thumbnail.jpg", "JPEG")
> > self.thumb = imfile + ".thumbnail.jpg"
> > super(book, self).save()
>
> > class BookForm(ModelForm):
>
> > class Meta:
> > model = book
> > exclude = ('thumb',)
>
> > Please help me, I am going crazy :-\
>
> > --
>
> > On Jan 2, 5:17 pm, Xia Kai(夏恺)  wrote:
>
> > > Hi,
>
> > > This is a fantastic app, though it might be too fat for a minimalist like
> > > me.   ^_^
>
> > > I would recommend override the default save method of the model and resize
> > > the original photo using PIL. For the overriding part, you could consult 
> > > the
> > > documentation:http://docs.djangoproject.com/en/dev/topics/db/models/#overriding-pre...
>
> > > 
> > > Xia Kai(夏恺)
> > > xia...@gmail.comhttp://blog.xiaket.org
>
> > > --
> > > From: "Chris Moffitt" 
> > > Sent: Saturday, January 02, 2010 11:59 PM
> > > To: 
> > > Subject: Re: Photo + thumbnail
>
> > > > You'll probably want to use one of Django's thumbnail apps. Here's the 
> > > > one
> > > > I
> > > > recommend:
> > > >http://code.google.com/p/sorl-thumbnail/*
>
> > > > -*Chris
>
> > > > On Sat, Jan 2, 2010 at 9:48 AM, nameless  wrote:
>
> > > >> Hi everyone I have a simple question.
> > > >> This is my model:
>
> > > >> class book(models.Model):
> > > >>title = models.CharField(max_length=50)
> > > >>photo = models.ImageField(upload_to='images/avatar/')
> > > >>thumb = models.ImageField(upload_to='images/thumb/')
>
> > > >> I want in photo original photo and in thumb the same photo but
> > > >> resized.
> > > >> How do I do that in simplest way ?
>
> > > >> Thank you and Good year  ^_^

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Re: Unhelpful template traceback

[Margie Roginski]

I had also noticed that errors from templates were quite hard to
debug.  Some time ago I saw this thread on on this group:

http://groups.google.com/group/django-users/browse_thread/thread/ee29c542dcc0dc95/aaa3f89a2a77fa3f?lnk=gst=template_debug#aaa3f89a2a77fa3f

I applied the very simple patch, which is listed in
http://code.djangoproject.com/ticket/11451

(Here's my own notes on what the patch is)
File: /site-packages/django/template/debug.py

# raise wrapped # remove this line, add next line, see ticket
11451
 raise wrapped, None, wrapped.exc_info[2]

After applying this patch I found the the traceback errors made much
more sense.  The tracebacks are complete now and point me to a line
that is meaningful.

I believe this is some sort of issue only with python 2.6, so if you
are not on 2.6, it is probably not a solution for you, but if you are
on 2.6, give it a try.

Margie




On Jan 4, 9:08 am, Thomas Steinacher  wrote:
> The actual error is not my point. I know that it's somewhere in a
> reverse/url method, but there is no way I can test it. The point is
> that there is no helpful template traceback in the deployment error e-
> mails. Maybe I should direct this to django-developers instead or file
> a ticket?
>
> On Jan 4, 6:05 pm, Victor Loureiro Lima 
> wrote:
>
> > You are probably calling {{ model.property.url }} or {{
> > model.get_absolute_url }} on some property/model (either FileField or
> > ImageField in case of property) of some model of yours that doesnt know how
> > to reverse back to its URL, so the template gives an error because it doesnt
> > know how to render its own value. You should check if the models is correct
> > and if its possible to access it thru the regex of URL.
>
> >  Maybe if you iterate thru all objects trying to get_absolute_url them you
> > could reproduce some sort of error.
>
> > That would be my guess =)
>
> > Victor Lima
>
> > 2010/1/4 Thomas Steinacher 
>
> > > Hey guys,
>
> > > I sometimes get errors which occur rarely, so it is very difficult to
> > > reproduce them in a development environment. The traceback always
> > > looks similar to the traceback attached below (which is just an
> > > example).
>
> > > My question: How can I make the Django error mails show the template
> > > file name and line number where the error occurred? It is really
> > > annoying as I currently see no way to debug this type of errors other
> > > than guessing, which is very difficult, especially when templates are
> > > very complex.
>
> > > Thanks,
>
> > > Thomas
>
> > > File "/home/mysite/django-mysite3/django/template/loader.py", line
> > > 173, in render_to_string
> > >  return t.render(context_instance)
>
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 184, in render
> > >  return self._render(context)
>
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 178, in _render
> > >  return self.nodelist.render(context)
>
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 787, in render
> > >  bits.append(self.render_node(node, context))
>
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 800, in render_node
> > >  return node.render(context)
>
> > > File "/home/mysite/django-mysite3/django/template/defaulttags.py",
> > > line 384, in render
> > >  raise e
>
> > > NoReverseMatch: Reverse for 'view_user_pictures' with arguments '()'
> > > and keyword arguments '{'username': ''}' not found.
>
> > > --
>
> > > You received this message because you are subscribed to the Google Groups
> > > "Django users" group.
> > > To post to this group, send email to django-us...@googlegroups.com.
> > > To unsubscribe from this group, send email to
> > > django-users+unsubscr...@googlegroups.com > >  groups.com>
> > > .
> > > For more options, visit this group at
> > >http://groups.google.com/group/django-users?hl=en.

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Re: unicode encoding problem

[Karen Tracey]

On Mon, Jan 4, 2010 at 11:05 AM, Bill Freeman  wrote:

> I find the error slightly confusing because the mentioned character, \xc2,
> which is capital A with circumflex, doesn't occur in the quoted part of the
> text.  Line 46 not included in your post, perhaps?  Apparently the pound
> signs, \xa3, aren't bothering it because they're in u"", or maybe it would
> just complain later, or get the wrong character.
>
>
No, it is the bytes contained in the unicode literals (u"") that trigger the
error. And you have illustrated why the error is necessary by guessing
(incorrectly) at the encoding in use.

The byte \xc2 is not capital A with circumflex. All that can be said about
the byte \xc2, in the absence of information about what encoding is in use,
is that it is not an ASCII character. Saying anything more about it assumes
an encoding.  Saying it is capital A with circumflex assumes latin-1
encoding. In fact it appears that this file is encoded in utf-8, making \xc2
the first byte in the 2-byte sequence encoding the Unicode pound sign U+00A3
(see http://www.fileformat.info/info/unicode/char/00a3/index.htm).  But I
could make that guess because I could see the pound sign in the email -- the
Python interpreter has no such hints to go by, all it has is the bytes
contained in the file it is trying to interpret.

Python needs to know the file encoding in order to correctly create a
unicode object from the bytes contained in the unicode literals.  It refuses
to guess or assume, so you get an error if a unicode literal contains a
non-ASCII byte and there is no encoding declaration in the file.


>

I would be tempted to avoid having non-ASCII characters in source code
> by putting \xa3 where you have pound signs, but that's me.



What you would need to do to avoid the error is to change the unicode
literals to bytestring literals (remove the u prefix).  Then the Python
interpreter would not complain, because it does not need to know the
encoding  when building a bytestring.  But then you are prone to running
into trouble when the bytestring is passed to code that assumes an encoding
for it that does not match the actual encoding.  You might get
UnicodeDecodeErrors or you might get corrupted data.  Unless you are careful
and really know what you are doing, taking this approach to avoid this error
is not a good idea.  Far better to correctly identify the file encoding via
the encoding declaration and use unicode literals where appropriate.

Karen

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Two HTML widgets for one DB field?

[skaw...@gmail.com]

Hello all.

I'm pretty new to Django, so please forgive my ignorance.

What I'm wondering is if it's possible to have two HTMl widgets on the
admin pages that map to the same DB field. To be specific, I have an
image field for one of my DB tables. Sometimes, I might want to upload
an image from my local machine (ImageField), but other times, the
image might already be on the server and I'd like to input a file path
(FilePathField). At the end of the day, both of these widgets save a
file path to the DB.

Is it possible to display both of these widgets on the admin page?
Perhaps something along the lines of both displayed, but only 1 can be
enabled at a time?

Thanks,
Jason

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Re: Generic view object_detail on a m2m relationship

[Delacroy Systems]

This is how I did it in views.py:

def businessshowservice_view(request, business_id):
business = Business.objects.get(pk=business_id)
services = Business.objects.get(pk=business_id).service_set.all()
return object_list(request, queryset=services,
   extra_context={'business' : business}
)

(now just have to figure out a way to get my stress back!)

On Jan 4, 7:55 pm, Delacroy Systems  wrote:
> I see that using object_detail is the 'incorrect' generic view to show
> details. I am exploring other options, including writing a custom view
> to give me what I want.
>
> On Jan 4, 8:29 am, Delacroy Systems  wrote:
>
> > I am trying to use the generic view, object_detail on a m2m
> > relationship. I have multiple businesses that offer multiple services.
> > I would like to show the services offered by each business. At the
> > moment, I see all the services - not just the services that a
> > particular business is offering.
>
> > In models.py:
> > class Business(models.Model):
> >   business = models.CharField(max_length=100)
>
> > class Service(models.Model):
> >   service = models.CharField(max_length=100)
> >   providers = models.ManyToManyField(Business, through =
> > "BusinessService")
>
> > class BusinessService(models.Model):
> >   business = models.ForeignKey(Business)
> >   service = models.ForeignKey(Service)
>
> > In urls.py:
> > def get_service():
> >     return Service.objects.all()
>
> > businessservice_list = {
> >     #'queryset' : BusinessService.objects.all(),
> >     'queryset' : Business.objects.all(),
> >     'extra_context': {'service_list': get_service}
>
> > ...skip some detail...
> > (r'^showservice/(?P\d+)/$', list_detail.object_detail,
> > businessservice_list),
>
> > In business_detail.html:
> > {% block content %}
> >     Business Services
> >           {% if object %}
> >                 {{ object.business }}
> >                 {{ service_list }}
> >           {% endif %}
> > {% endblock content%}
>
>

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Re: django-audiorecorder ?

[Frédéric Burlet]

On Saturday 02 January 2010 10:55:11 Waqqas Jabbar wrote:
> Hi,
> 
> There are audio players available for djagon, but is there any django
> project the provide audio recording capability?
> My search has not produce any good results.
> 
> There are some python based libraries liky PyAudio (
> http://people.csail.mit.edu/hubert/pyaudio/) or Gstreamer python binding,
> that can be used. Can anyone give me some ideas on how to make one of my
>  own ?
> 
> I want to record only short clip.Can javascript be used for audio recording
> on client computer and the upload the file?
> 
> peace
> waqqas
> 
> --

Hi,

If your purpose is to record/read live stream via a website, I think it's then
better to provide either a java applet or a flash application that help the
user to record audio or video via your website.

For flash applications, you can use red5[1] which is an open source flash
server implemented in java. It allows you to record/read live streams through
flash applications (If you are brave or feisty... you could implement this
server in python ;)

[1] http://osflash.org/red5

If you need to implement a client in flash, you can use openlazlo[2] or use
an-already-existing client. I know that the dokeos[3] project has one but I
never tried to compile it or install it myself.

[2] http://www.openlaszlo.org/
[3] http://dokeos.svn.sourceforge.net/viewvc/dokeos/trunk/videoconference/

Hope this helps.

Fred.


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Re: Unhelpful template traceback

[Victor Loureiro Lima]

Yes, maybe thats more like the case.

Victor Lima

2010/1/4 Thomas Steinacher 

> The actual error is not my point. I know that it's somewhere in a
> reverse/url method, but there is no way I can test it. The point is
> that there is no helpful template traceback in the deployment error e-
> mails. Maybe I should direct this to django-developers instead or file
> a ticket?
>
> On Jan 4, 6:05 pm, Victor Loureiro Lima 
> wrote:
> > You are probably calling {{ model.property.url }} or {{
> > model.get_absolute_url }} on some property/model (either FileField or
> > ImageField in case of property) of some model of yours that doesnt know
> how
> > to reverse back to its URL, so the template gives an error because it
> doesnt
> > know how to render its own value. You should check if the models is
> correct
> > and if its possible to access it thru the regex of URL.
> >
> >  Maybe if you iterate thru all objects trying to get_absolute_url them
> you
> > could reproduce some sort of error.
> >
> > That would be my guess =)
> >
> > Victor Lima
> >
> > 2010/1/4 Thomas Steinacher 
> >
> >
> >
> > > Hey guys,
> >
> > > I sometimes get errors which occur rarely, so it is very difficult to
> > > reproduce them in a development environment. The traceback always
> > > looks similar to the traceback attached below (which is just an
> > > example).
> >
> > > My question: How can I make the Django error mails show the template
> > > file name and line number where the error occurred? It is really
> > > annoying as I currently see no way to debug this type of errors other
> > > than guessing, which is very difficult, especially when templates are
> > > very complex.
> >
> > > Thanks,
> >
> > > Thomas
> >
> > > File "/home/mysite/django-mysite3/django/template/loader.py", line
> > > 173, in render_to_string
> > >  return t.render(context_instance)
> >
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 184, in render
> > >  return self._render(context)
> >
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 178, in _render
> > >  return self.nodelist.render(context)
> >
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 787, in render
> > >  bits.append(self.render_node(node, context))
> >
> > > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > > 800, in render_node
> > >  return node.render(context)
> >
> > > File "/home/mysite/django-mysite3/django/template/defaulttags.py",
> > > line 384, in render
> > >  raise e
> >
> > > NoReverseMatch: Reverse for 'view_user_pictures' with arguments '()'
> > > and keyword arguments '{'username': ''}' not found.
> >
> > > --
> >
> > > You received this message because you are subscribed to the Google
> Groups
> > > "Django users" group.
> > > To post to this group, send email to django-us...@googlegroups.com.
> > > To unsubscribe from this group, send email to
> > > django-users+unsubscr...@googlegroups.com
> 
> > > .
> > > For more options, visit this group at
> > >http://groups.google.com/group/django-users?hl=en.
>
> --
>
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>
>
>

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Re: Generic view object_detail on a m2m relationship

[Delacroy Systems]

I see that using object_detail is the 'incorrect' generic view to show
details. I am exploring other options, including writing a custom view
to give me what I want.

On Jan 4, 8:29 am, Delacroy Systems  wrote:
> I am trying to use the generic view, object_detail on a m2m
> relationship. I have multiple businesses that offer multiple services.
> I would like to show the services offered by each business. At the
> moment, I see all the services - not just the services that a
> particular business is offering.
>
> In models.py:
> class Business(models.Model):
>   business = models.CharField(max_length=100)
>
> class Service(models.Model):
>   service = models.CharField(max_length=100)
>   providers = models.ManyToManyField(Business, through =
> "BusinessService")
>
> class BusinessService(models.Model):
>   business = models.ForeignKey(Business)
>   service = models.ForeignKey(Service)
>
> In urls.py:
> def get_service():
>     return Service.objects.all()
>
> businessservice_list = {
>     #'queryset' : BusinessService.objects.all(),
>     'queryset' : Business.objects.all(),
>     'extra_context': {'service_list': get_service}
>
> ...skip some detail...
> (r'^showservice/(?P\d+)/$', list_detail.object_detail,
> businessservice_list),
>
> In business_detail.html:
> {% block content %}
>     Business Services
>           {% if object %}
>                 {{ object.business }}
>                 {{ service_list }}
>           {% endif %}
> {% endblock content%}

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Re: Unhelpful template traceback

[Thomas Steinacher]

The actual error is not my point. I know that it's somewhere in a
reverse/url method, but there is no way I can test it. The point is
that there is no helpful template traceback in the deployment error e-
mails. Maybe I should direct this to django-developers instead or file
a ticket?

On Jan 4, 6:05 pm, Victor Loureiro Lima 
wrote:
> You are probably calling {{ model.property.url }} or {{
> model.get_absolute_url }} on some property/model (either FileField or
> ImageField in case of property) of some model of yours that doesnt know how
> to reverse back to its URL, so the template gives an error because it doesnt
> know how to render its own value. You should check if the models is correct
> and if its possible to access it thru the regex of URL.
>
>  Maybe if you iterate thru all objects trying to get_absolute_url them you
> could reproduce some sort of error.
>
> That would be my guess =)
>
> Victor Lima
>
> 2010/1/4 Thomas Steinacher 
>
>
>
> > Hey guys,
>
> > I sometimes get errors which occur rarely, so it is very difficult to
> > reproduce them in a development environment. The traceback always
> > looks similar to the traceback attached below (which is just an
> > example).
>
> > My question: How can I make the Django error mails show the template
> > file name and line number where the error occurred? It is really
> > annoying as I currently see no way to debug this type of errors other
> > than guessing, which is very difficult, especially when templates are
> > very complex.
>
> > Thanks,
>
> > Thomas
>
> > File "/home/mysite/django-mysite3/django/template/loader.py", line
> > 173, in render_to_string
> >  return t.render(context_instance)
>
> > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > 184, in render
> >  return self._render(context)
>
> > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > 178, in _render
> >  return self.nodelist.render(context)
>
> > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > 787, in render
> >  bits.append(self.render_node(node, context))
>
> > File "/home/mysite/django-mysite3/django/template/__init__.py", line
> > 800, in render_node
> >  return node.render(context)
>
> > File "/home/mysite/django-mysite3/django/template/defaulttags.py",
> > line 384, in render
> >  raise e
>
> > NoReverseMatch: Reverse for 'view_user_pictures' with arguments '()'
> > and keyword arguments '{'username': ''}' not found.
>
> > --
>
> > You received this message because you are subscribed to the Google Groups
> > "Django users" group.
> > To post to this group, send email to django-us...@googlegroups.com.
> > To unsubscribe from this group, send email to
> > django-users+unsubscr...@googlegroups.com > groups.com>
> > .
> > For more options, visit this group at
> >http://groups.google.com/group/django-users?hl=en.

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Re: Unhelpful template traceback

[Victor Loureiro Lima]

You are probably calling {{ model.property.url }} or {{
model.get_absolute_url }} on some property/model (either FileField or
ImageField in case of property) of some model of yours that doesnt know how
to reverse back to its URL, so the template gives an error because it doesnt
know how to render its own value. You should check if the models is correct
and if its possible to access it thru the regex of URL.

 Maybe if you iterate thru all objects trying to get_absolute_url them you
could reproduce some sort of error.

That would be my guess =)

Victor Lima

2010/1/4 Thomas Steinacher 

> Hey guys,
>
> I sometimes get errors which occur rarely, so it is very difficult to
> reproduce them in a development environment. The traceback always
> looks similar to the traceback attached below (which is just an
> example).
>
> My question: How can I make the Django error mails show the template
> file name and line number where the error occurred? It is really
> annoying as I currently see no way to debug this type of errors other
> than guessing, which is very difficult, especially when templates are
> very complex.
>
> Thanks,
>
> Thomas
>
>
>
> File "/home/mysite/django-mysite3/django/template/loader.py", line
> 173, in render_to_string
>  return t.render(context_instance)
>
> File "/home/mysite/django-mysite3/django/template/__init__.py", line
> 184, in render
>  return self._render(context)
>
> File "/home/mysite/django-mysite3/django/template/__init__.py", line
> 178, in _render
>  return self.nodelist.render(context)
>
> File "/home/mysite/django-mysite3/django/template/__init__.py", line
> 787, in render
>  bits.append(self.render_node(node, context))
>
> File "/home/mysite/django-mysite3/django/template/__init__.py", line
> 800, in render_node
>  return node.render(context)
>
> File "/home/mysite/django-mysite3/django/template/defaulttags.py",
> line 384, in render
>  raise e
>
> NoReverseMatch: Reverse for 'view_user_pictures' with arguments '()'
> and keyword arguments '{'username': ''}' not found.
>
> --
>
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
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>
>
>

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Re: Changing the database name by subdomain name

[Shawn Milochik]

It seems like you should have two instances of Django running. Each one will be 
listening on a different port, and run a different settings.py file.

In short, copy your settings.py file, and change the copy to use the alternate 
database.

Then, run two copies of Django, like this (may vary based on how your server is 
set up):

./manage.py runfcgi host=127.0.0.1 port=8100 --settings=myproject.settings
./manage.py runfcgi host=127.0.0.1 port=8200 --settings=myproject._settings

Of course, your Web server (Apache, nginx, whatever) needs to have another 
entry added for the new port number and url.

Shawn


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Re: Django Gantt Chart

[Hinnack]

what about:
http://matplotlib.sourceforge.net/

--
Hinnack

2010/1/4 Daniel Hilton 

> 2010/1/4 Alessandro Ronchi :
> > I need to make a simple chart with a list of projects and a grafic
> > display of the end date with a link to the project page.
> > It's simpler than a gantt chart.
> >
> > Is there any library / snippet I can use to simplify my work?
> >
>
> Hmmm, as I'm about to do something similar I've also researched this.
>
> If you're just looking at displaying a list of objects(projects) then
> you can use a generic view and then handle the display in the
> template, which means the following links may be of help:
>
> http://www.jlion.com/docs/gantt.aspx
> http://www.jsgantt.com/
>
> Niether of which are particularly pretty but the basics are there
> ready to be reskinned.
>
> http://www.ext-scheduler.com/examples.html
>
> Is however, pretty awesome, if commercially licensed.
>
> This question on stackoverflow is pretty extensive as well:
> http://stackoverflow.com/questions/1005587/gantt-chart-online
>
> If I don't find one I like, I'm thinking about writing a template tag
> and some jQuery to make a nice dependency graph.
> HTH,
> Dan
>
>
>
>
> > --
> > Alessandro Ronchi
> >
> > http://www.soasi.com
> > SOASI - Sviluppo Software e Sistemi Open Source
> >
> > http://hobbygiochi.com
> > Hobby & Giochi, l'e-commerce del divertimento
> >
> > --
> >
> > You received this message because you are subscribed to the Google Groups
> "Django users" group.
> > To post to this group, send email to django-us...@googlegroups.com.
> > To unsubscribe from this group, send email to
> django-users+unsubscr...@googlegroups.com
> .
> > For more options, visit this group at
> http://groups.google.com/group/django-users?hl=en.
> >
> >
> >
>
>
>
> --
> Dan Hilton
> 
> www.twitter.com/danhilton
> www.DanHilton.co.uk
> 
>
> --
>
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>
>

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Unhelpful template traceback

[Thomas Steinacher]

Hey guys,

I sometimes get errors which occur rarely, so it is very difficult to
reproduce them in a development environment. The traceback always
looks similar to the traceback attached below (which is just an
example).

My question: How can I make the Django error mails show the template
file name and line number where the error occurred? It is really
annoying as I currently see no way to debug this type of errors other
than guessing, which is very difficult, especially when templates are
very complex.

Thanks,

Thomas



File "/home/mysite/django-mysite3/django/template/loader.py", line
173, in render_to_string
  return t.render(context_instance)

File "/home/mysite/django-mysite3/django/template/__init__.py", line
184, in render
  return self._render(context)

File "/home/mysite/django-mysite3/django/template/__init__.py", line
178, in _render
  return self.nodelist.render(context)

File "/home/mysite/django-mysite3/django/template/__init__.py", line
787, in render
  bits.append(self.render_node(node, context))

File "/home/mysite/django-mysite3/django/template/__init__.py", line
800, in render_node
  return node.render(context)

File "/home/mysite/django-mysite3/django/template/defaulttags.py",
line 384, in render
  raise e

NoReverseMatch: Reverse for 'view_user_pictures' with arguments '()'
and keyword arguments '{'username': ''}' not found.

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Changing the database name by subdomain name

[bluellyr]

Hi!

I'm using the Django 1.0.2 and trying to connect to a diferent
database name using the subdomain by reference,
when I access http://.mydomain.com I want to connect to the ""
database and when accessing to the
http://.mydomain.com I want to connect to the "" database.

There is a way to do this?

I'm trying but I can not find nothing about how to get the subdomain
from the url.

thanks

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Re: unicode encoding problem

[Alexander Dutton]

Hi Bill, Simon,

On 04/01/10 16:05, Bill Freeman wrote:
> I find the error slightly confusing because the mentioned character,
> \xc2, which is capital A with circumflex, doesn't occur in the quoted
> part of the text.

\xc2 is the first byte of a character encoded in UTF-8 as two bytes.
The character you were expecting is U+00C2, being a Unicode codepoint
(as opposed to an encoding thereof).

For what it's worth, my experience of the method given in the PEP has
been positive.

Regards,

Alex

PS. Sorry for the multiple copies, Bill. The Reply-list button in TB3 is
(still) broken

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Re: unicode encoding problem

[Bill Freeman]

I find the error slightly confusing because the mentioned character, \xc2,
which is capital A with circumflex, doesn't occur in the quoted part of the
text.  Line 46 not included in your post, perhaps?  Apparently the pound
signs, \xa3, aren't bothering it because they're in u"", or maybe it would
just complain later, or get the wrong character.

I would be tempted to avoid having non-ASCII characters in source code
by putting \xa3 where you have pound signs, but that's me.  Karen's
suggestion that an answer is in the PEP mentioned by the error message
is correct, but may be more subtle than you're prepared for at the moment.
I'm assuming that your editor is using Latin-1, so both the pound signs
and the A with circumflex would be correctly interpreted.

However, even if you specify an encoding for strings, and a default
encoding for files, I think that you will eventually have trouble with using
non-ASCII for non-string purposes (class or method name, variable or
attribute names).

Bill

On Sun, Jan 3, 2010 at 6:48 PM, Simon Davies  wrote:
> I know I'm missing something really simple really but I  keep getting
> this error:
>
> SyntaxError: Non-ASCII character '\xc2' in file /home/simon/
> djangoprojects/bikerescue/bikeshop/models.py on line 46, but no
> encoding declared; see http://www.python.org/peps/pep-0263.html for
> details.  This is the model in question and I have the __unicode__
> function in there
>
> class Item(models.Model):
>        title = models.CharField(max_length=100)
>        description = models.CharField(max_length=500)
>        price = models.FloatField(max_length=10, verbose_name=u'Price (£)')
>
>        def __unicode__(self):
>                return self.title
>
>        def _get_disp_price(self):
>                return u"£" + self.price
>
>        disp_price = property(_get_disp_price)
>
> I 've put the unicode u in both places where its required so why is it
> still tripping up.
>
> Many thanks
>
> Simon
>
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Re: Photo + thumbnail

[Justin Myers]

I'm not able to test this idea directly myself at the moment, but it
appears you're storing an absolute path (i.e., starting from the
filesystem root) in self.thumb. I'm pretty sure FileFields (and, by
extension, ImageFields) store relative paths from settings.MEDIA_ROOT.

(To make sure I'm thinking about this properly (since again, I can't
double-check this right now), you might want to see what the value of
the thumb field is in the database first. If I'm right, you should see
a path that consists of a relative path followed by an absolute one,
such as "2010/0104//home/username/webapps/media/2010/0104/
something.thumbnail.jpg".)

An absolute path is certainly helpful for actually operating on the
file, but before
self.thumb = imfile + ".thumbnail.jpg"
you'll need something like
imfile, ext = os.path.splitext(self.photo)  # NOT .path, so this
is a relative path, not an absolute one
to make this work properly.

Hope that helps.
-Justin

On Jan 4, 5:15 am, nameless  wrote:
> I have writed this code but it doesn't work. What is the error ?
>
> from django.db import models
> from django.forms import ModelForm
> from PIL import Image
> import glob, os
>
> thumb_size = 90, 90
>
> class book(models.Model):
> title = models.CharField(max_length=200)
> photo = models.ImageField(upload_to='bookphoto')
> thumb = models.ImageField(upload_to='bookthumb')
>
> def save(self):
>
> file_path = self.photo.path
> if (file_path):
> imfile, ext = os.path.splitext(file_path)
> im = Image.open(file_path)
> im.thumbnail(thumb_size, Image.ANTIALIAS)
> im.save(imfile + ".thumbnail.jpg", "JPEG")
> self.thumb = imfile + ".thumbnail.jpg"
> super(book, self).save()
>
> class BookForm(ModelForm):
>
> class Meta:
> model = book
> exclude = ('thumb',)
>
> Please help me, I am going crazy :-\
>
> --
>
> On Jan 2, 5:17 pm, Xia Kai(夏恺)  wrote:
>
> > Hi,
>
> > This is a fantastic app, though it might be too fat for a minimalist like
> > me.   ^_^
>
> > I would recommend override the default save method of the model and resize
> > the original photo using PIL. For the overriding part, you could consult the
> > documentation:http://docs.djangoproject.com/en/dev/topics/db/models/#overriding-pre...
>
> > 
> > Xia Kai(夏恺)
> > xia...@gmail.comhttp://blog.xiaket.org
>
> > --
> > From: "Chris Moffitt" 
> > Sent: Saturday, January 02, 2010 11:59 PM
> > To: 
> > Subject: Re: Photo + thumbnail
>
> > > You'll probably want to use one of Django's thumbnail apps. Here's the one
> > > I
> > > recommend:
> > >http://code.google.com/p/sorl-thumbnail/*
>
> > > -*Chris
>
> > > On Sat, Jan 2, 2010 at 9:48 AM, nameless  wrote:
>
> > >> Hi everyone I have a simple question.
> > >> This is my model:
>
> > >> class book(models.Model):
> > >>title = models.CharField(max_length=50)
> > >>photo = models.ImageField(upload_to='images/avatar/')
> > >>thumb = models.ImageField(upload_to='images/thumb/')
>
> > >> I want in photo original photo and in thumb the same photo but
> > >> resized.
> > >> How do I do that in simplest way ?
>
> > >> Thank you and Good year  ^_^

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Re: Passing a parameter into a queryset for a generic view

[Bill Freeman]

There may be an easier way, but I'd write a view, even if
I then called the generic view from there.

As you've probably figured out, your definition of the queryset
occurs once at import, when object_id isn't even defined, let
alone coming from each request in turn.

Bill

On Sun, Jan 3, 2010 at 4:15 PM, Delacroy Systems
 wrote:
> I want to display all the services for a particular business using the
> generic view "object_detail". What I would like to do is pass the
> value of an id from the url to the queryset (into object_id) in
> urls.py - or a better way to do this using the "object_detail" generic
> view.
>
> models.py:
> class BusinessService(models.Model):
>  business = models.ForeignKey(Business)
>  service = models.ForeignKey(Service)
>
> urls.py:
> businessservice_list = {
>    'queryset' : BusinessService.objects.filter(
>                     business=object_id),
> }
> ...skip some detail...
> (r'^showservice/(?P\d+)/$', list_detail.object_detail,
> businessservice_list),
>
> businessservice_detail.html:
> {% extends "portal/base.html" %}
> {% block pagename %}Business Services{% endblock pagename %}
> {% block content %}
>    Business Services
>                {{ businessservice.business }}
>                
>                        {% for business in object_list %}
>                {{ businessservice.service }}
>                        {% endfor %}
>                
> {% endblock content%}
>
> --
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Re: Session cache backend or cache API failure

[Ales Zoulek]

Hello,

I've the same problem there..

Did you find out any solution? Or at least the source of the problem?


Regards,


Ales

--
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Jabber: ales.zou...@gmail.com
--


On Sat, Oct 3, 2009 at 3:24 AM, Calvin Spealman wrote:

>
> I've spent all day diagnosing this with no success. I would get random
> errors in logs with the traceback below, showing a failure to create a
> new session. Memcache logs show all 1 tries succeeding (I have
> also confirmed the empty sessions are still held in cache after). From
> what I can see, session.backends.cache tries 10,000 keys that are all
> successful, but it thinks they fail and ignores the success. This only
> happens in about 1% of requests.
>
> <31 add 980bdad78f56a4d24e0eebf43625918a 1 1209600 6
> > NOT FOUND 980bdad78f56a4d24e0eebf43625918a
> >31 STORED
> <31 get a0948fa9c0add4b803ba85d5939b5a2c
> > NOT FOUND a0948fa9c0add4b803ba85d5939b5a2c
> >31 END
> <31 get a0948fa9c0add4b803ba85d5939b5a2c
> > NOT FOUND a0948fa9c0add4b803ba85d5939b5a2c
> >31 END
> <31 add a0948fa9c0add4b803ba85d5939b5a2c 1 1209600 6
> > NOT FOUND a0948fa9c0add4b803ba85d5939b5a2c
> >31 STORED
> <31 get 74b1dcca57f28779305180995d362136
> > NOT FOUND 74b1dcca57f28779305180995d362136
> >31 END
> <31 get 74b1dcca57f28779305180995d362136
> > NOT FOUND 74b1dcca57f28779305180995d362136
> >31 END
> <31 add 74b1dcca57f28779305180995d362136 1 1209600 6
> > NOT FOUND 74b1dcca57f28779305180995d362136
> >31 STORED
> <31 connection closed.
>
>  File "/opt/faircompanies/env/lib/python2.5/site-packages/
> flup-1.0.3.dev_20090612-py2.5.egg/flup/server/fcgi_base.py", line 558,
> in run
>protocolStatus, appStatus = self.server.handler(self)
>  File "/opt/faircompanies/env/lib/python2.5/site-packages/
> flup-1.0.3.dev_20090612-py2.5.egg/flup/server/fcgi_base.py", line
> 1118, in handler
>result = self.application(environ, start_response)
>  File "/opt/faircompanies/env/lib/python2.5/django/core/handlers/
> wsgi.py", line 239, in __call__
>response = self.get_response(request)
>  File "/opt/faircompanies/env/lib/python2.5/django/core/handlers/
> base.py", line 67, in get_response
>response = middleware_method(request)
>  File "/opt/faircompanies/fc/django_authopenid/middleware.py", line
> 11, in process_request
>request.openid = request.session.get('openid', None)
>  File "/opt/faircompanies/env/lib/python2.5/django/contrib/sessions/
> backends/base.py", line 63, in get
>return self._session.get(key, default)
>  File "/opt/faircompanies/env/lib/python2.5/django/contrib/sessions/
> backends/base.py", line 172, in _get_session
>self._session_cache = self.load()
>  File "/opt/faircompanies/env/lib/python2.5/django/contrib/sessions/
> backends/cache.py", line 16, in load
>self.create()
>  File "/opt/faircompanies/env/lib/python2.5/django/contrib/sessions/
> backends/cache.py", line 33, in create
>raise RuntimeError("Unable to create a new session key.")
> RuntimeError: Unable to create a new session key
>
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Re: Beta testers for a syntax highlighting widget

[Bill Freeman]

I've downloaded and may try the widget.

But, unless I'm mistaking the example you show on your page:

1. You're not going to pry me away from emacs for editing python,
or css, or html, or javascript.  I'm sure that others have their
favorite editors as well.

2. Even if you could provide the perfect emacs-like experience, I'm
not going to edit code through the web.  I edit files locally, check them
in to mercurial, push them to our server, ssh to the web server and
pull the changes there.  Were you intending to add revision control
check in and authentication?  Even if I'm forced to use someone else's
computer, I can either ssh into the webserver to work securely on the
files, or I demur.

3. So it seems the remaining usage is what TinyMCE, et al, get used
for: Allowing users to create page content.  (I'm sure not going to let
them code views or templates.)  The few of them that want to edit in
html mode could well benefit from syntax highlighting, auto indent, etc.
But they probably want to switch back and forth between code view
and how it looks view, as people to with kupu, TinyMCE, etc., and they
still will want to be able to edit in how it looks mode.  So it seems to
me that what's really called for is an extension to html mode of some
existing editor widget.

Bill

On Sun, Jan 3, 2010 at 11:07 AM, aditya  wrote:
> Anyone? Limited testing will do, I just want to make sure I haven't
> overlooked something.
>
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Re: django-audiorecorder ?

[Bill Freeman]

Boy, I sure hope that you can't record audio at my house just be
virtue of my having visited a web page.

You might be able to offer a Java app (hopefully not applet) that
the user can install and run (the user may not have python),
producing a file that they can then upload to you.  Or even record
directly to you if they give the script net access permission.  Of
course you have to configure their mixer as well, possibly guessing
which input has the source you want.  You could mess things up for
the naive.

(People who install and run stuff they've downloaded from a random
website deserve what they get.)

But so long as it's a short clip, even MS sound recorder will do, and
I assume that MACs have something like that.  Most linux's too, have
(at least one) suitable tool.  So if it were me, I'd simple provide
instructions as to how to create a file to upload.

Bill

On Sat, Jan 2, 2010 at 4:55 AM, Waqqas Jabbar  wrote:
> Hi,
>
> There are audio players available for djagon, but is there any django
> project the provide audio recording capability?
> My search has not produce any good results.
>
> There are some python based libraries liky PyAudio
> (http://people.csail.mit.edu/hubert/pyaudio/) or Gstreamer python binding,
> that can be used. Can anyone give me some ideas on how to make one of my own
> ?
>
> I want to record only short clip.Can javascript be used for audio recording
> on client computer and the upload the file?
>
> peace
> waqqas
>
>
> --
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Re: Django Gantt Chart

[Daniel Hilton]

2010/1/4 Alessandro Ronchi :
> I need to make a simple chart with a list of projects and a grafic
> display of the end date with a link to the project page.
> It's simpler than a gantt chart.
>
> Is there any library / snippet I can use to simplify my work?
>

Hmmm, as I'm about to do something similar I've also researched this.

If you're just looking at displaying a list of objects(projects) then
you can use a generic view and then handle the display in the
template, which means the following links may be of help:

http://www.jlion.com/docs/gantt.aspx
http://www.jsgantt.com/

Niether of which are particularly pretty but the basics are there
ready to be reskinned.

http://www.ext-scheduler.com/examples.html

Is however, pretty awesome, if commercially licensed.

This question on stackoverflow is pretty extensive as well:
http://stackoverflow.com/questions/1005587/gantt-chart-online

If I don't find one I like, I'm thinking about writing a template tag
and some jQuery to make a nice dependency graph.
HTH,
Dan




> --
> Alessandro Ronchi
>
> http://www.soasi.com
> SOASI - Sviluppo Software e Sistemi Open Source
>
> http://hobbygiochi.com
> Hobby & Giochi, l'e-commerce del divertimento
>
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>
>
>



-- 
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www.twitter.com/danhilton
www.DanHilton.co.uk


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Re: help about json

[Shawn Milochik]

Here you go:

http://catb.org/~esr/faqs/smart-questions.html

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help about json

[CCC]

hi,all
happy new  year!
im my template i have some field ,but i hope that users can
customerize the form (for example,
 they can add some more other fields,)i know it use json ,but i need
some source or link,
anyone can help
thanks

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Django Gantt Chart

[Alessandro Ronchi]

I need to make a simple chart with a list of projects and a grafic
display of the end date with a link to the project page.
It's simpler than a gantt chart.

Is there any library / snippet I can use to simplify my work?

-- 
Alessandro Ronchi

http://www.soasi.com
SOASI - Sviluppo Software e Sistemi Open Source

http://hobbygiochi.com
Hobby & Giochi, l'e-commerce del divertimento

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Backwards incompatible change to Email Backends in Django Trunk

[Russell Keith-Magee]

Hi all,

If you have been using the new email backend feature in trunk, you
should be aware that SVN revision 12084 introduces a small, but
backwards-incompatible change.

If you are using Django 1.1 (i.e., Django stable), or you haven't
manually specified EMAIL_BACKEND in your settings file, you will not
be affected by this change. This change only affects users who are
using a recent Django Trunk checkout, AND have manually specified
EMAIL_BACKEND in their settings file. These users will need to make a
small configuration change.

When the email backend feature was committed in revision 11709, the
EMAIL_BACKEND setting was specified at the level of a module. That is,
if you were using the file-based backend, you would have specified:

EMAIL_BACKEND = 'django.core.mail.backends.filebased'

As of revision 12084, this has been modified to be a class-level
specification. You must now specify:

EMAIL_BACKEND = 'django.core.mail.backends.filebased.EmailBackend'

Rather than specifying the module that contains the email backend
class, you need to specify the full name of the backend class. This
means you need to append ".EmailBackend" to any existing EMAIL_BACKEND
setting.

This has been done to normalize the way that pluggable backends are
defined in Django. At the time that the email backend was committed,
no formal policy had been set regarding conventions for specifying
backends. A policy emerged as a result of the introduction of
session-based messages. Since email backends have not yet been part of
a formal Django release, we have decided to make this change to
maintain consistency between the backends that will be introduced in
v1.2.

Apologies for any inconvenience this causes to those of you on the
bleeding edge.

Yours,
Russ Magee %-)

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Re: debugging cache

[Eric Abrahamsen]

On Dec 24, 2009, at 10:28 PM, brook wrote:

>
>
> On Dec 23, 5:13 am, Eric Abrahamsen  wrote:
>>
>> I'm using memcached with the cache_page decorator, and it simply  
>> wasn't caching
>> views.
>
>> CACHE_MIDDLEWARE_KEY_PREFIX = 'blah'
>> CACHE_MIDDLEWARE_ANONYMOUS_ONLY = True
>> CACHE_BACKEND = 'memcached://XX.XX.XX.XXX:6905/'
>>
>> I have no cache-related middlewares installed.
>>
>
> If you are using the "per-view" caching technique (using the
> cache_page decorator), and you haven't got caching middleware enabled,
> then CACHE_MIDDLEWARE_PREFIX and CACHE_MIDDLEWARE_ANONYMOUS_ONLY won't
> do anything. These are related to "per-site" caching, as detailed in
> the documentation: 
> http://docs.djangoproject.com/en/1.1/topics/cache/#the-per-site-cache
>
> You might consider using database caching[1] in your development
> environment, to make inspecting the cache easier. You can then look at
> the caching table in your database to check whether it is being
> populated as expected. That way you can start to narrow down where the
> problem lies (django's caching, or memcached).

Thanks for the tip! The database is being populated as expected by the  
cache framework, so the problem must lie with memcached somehow.

Could there be some permissions issues going on here? Some conflict  
between the apache user and my user, which started memcached?

Any hints appreciated, in the meantime I'll continue poking.

E


>
> [1] http://docs.djangoproject.com/en/1.1/topics/cache/#database- 
> caching
>
> --
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Re: Cannot reach development server in a rackspace cloud server

[simonecare...@gmail.com]

Ehi Marc, thank you very much.

By doing a nmap scan I noticed the port 8000 is filtered.

so I tryed flushing iptables and it worked...now i've just to set up
again filtering over other ports.

Thank you again,
Simone.

On Jan 4, 12:27 pm, Marc Aymerich  wrote:
> On Mon, Jan 4, 2010 at 12:04 PM, simonecare...@gmail.com <
>
>
>
>
>
> simonecare...@gmail.com> wrote:
> > > python2.5 manage.py runserver 0.0.0.0:8000, but i can't point my web
> > > browser to that address.
>
> > Of course I mean MY.IP.ADDRESS:8000. :)
>
> > On Jan 4, 12:01 pm, "simonecare...@gmail.com"
> >  wrote:
> > > Hi everyone,
>
> > > i've just setted up a new Centos 5.4 based cloud server at Rackspace.
> > > Installed Python2.5 and virtualenv, devel-tools, and all went ok but I
> > > can't reach the development server.
>
> > > I started a new django project, then launched
>
> > > python2.5 manage.py runserver 0.0.0.0:8000, but i can't point my web
> > > browser to that address.
>
> > > Any ideas?
>
> take a look with: netstat -ltnp|grep python
> can you ping YOUR.IP.ADDRESS ??
> what say nmap YOU.IP.ADDRESS -p 8000 (client side) ?
> check your /etc/hosts (client side)
> check your /etc/hosts.deny (server and client side)
> maybe something with iptables: iptables -F
> in server side.. can you connect with: links2http://localhost:8000 ?
> Maybe Firewalls on the way?
>
>
>
> > > Also tried to disable SELinux, but nothing changed.
>
> > > Thanks,
> > > Simone.
>
> > --
>
> > You received this message because you are subscribed to the Google Groups
> > "Django users" group.
> > To post to this group, send email to django-us...@googlegroups.com.
> > To unsubscribe from this group, send email to
> > django-users+unsubscr...@googlegroups.com > groups.com>
> > .
> > For more options, visit this group at
> >http://groups.google.com/group/django-users?hl=en.

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Re: Cannot reach development server in a rackspace cloud server

[Marc Aymerich]

On Mon, Jan 4, 2010 at 12:04 PM, simonecare...@gmail.com <
simonecare...@gmail.com> wrote:

> > python2.5 manage.py runserver 0.0.0.0:8000, but i can't point my web
> > browser to that address.
>
> Of course I mean MY.IP.ADDRESS:8000. :)
>
>
>
> On Jan 4, 12:01 pm, "simonecare...@gmail.com"
>  wrote:
> > Hi everyone,
> >
> > i've just setted up a new Centos 5.4 based cloud server at Rackspace.
> > Installed Python2.5 and virtualenv, devel-tools, and all went ok but I
> > can't reach the development server.
> >
> > I started a new django project, then launched
> >
> > python2.5 manage.py runserver 0.0.0.0:8000, but i can't point my web
> > browser to that address.
> >
> > Any ideas?
> >
>

take a look with: netstat -ltnp|grep python
can you ping YOUR.IP.ADDRESS ??
what say nmap YOU.IP.ADDRESS -p 8000 (client side) ?
check your /etc/hosts (client side)
check your /etc/hosts.deny (server and client side)
maybe something with iptables: iptables -F
in server side.. can you connect with: links2 http://localhost:8000  ?
Maybe Firewalls on the way?



> > Also tried to disable SELinux, but nothing changed.
> >
> > Thanks,
> > Simone.
>
> --
>
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> "Django users" group.
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> .
> For more options, visit this group at
> http://groups.google.com/group/django-users?hl=en.
>
>
>

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Re: Photo + thumbnail

[nameless]

I have writed this code but it doesn't work. What is the error ?

from django.db import models
from django.forms import ModelForm
from PIL import Image
import glob, os

thumb_size = 90, 90

class book(models.Model):
title = models.CharField(max_length=200)
photo = models.ImageField(upload_to='bookphoto')
thumb = models.ImageField(upload_to='bookthumb')

def save(self):

file_path = self.photo.path
if (file_path):
imfile, ext = os.path.splitext(file_path)
im = Image.open(file_path)
im.thumbnail(thumb_size, Image.ANTIALIAS)
im.save(imfile + ".thumbnail.jpg", "JPEG")
self.thumb = imfile + ".thumbnail.jpg"
super(book, self).save()

class BookForm(ModelForm):

class Meta:
model = book
exclude = ('thumb',)

Please help me, I am going crazy :-\



--

On Jan 2, 5:17 pm, Xia Kai(夏恺)  wrote:
> Hi,
>
> This is a fantastic app, though it might be too fat for a minimalist like
> me.   ^_^
>
> I would recommend override the default save method of the model and resize
> the original photo using PIL. For the overriding part, you could consult the
> documentation:http://docs.djangoproject.com/en/dev/topics/db/models/#overriding-pre...
>
> 
> Xia Kai(夏恺)
> xia...@gmail.comhttp://blog.xiaket.org
>
> --
> From: "Chris Moffitt" 
> Sent: Saturday, January 02, 2010 11:59 PM
> To: 
> Subject: Re: Photo + thumbnail
>
> > You'll probably want to use one of Django's thumbnail apps. Here's the one
> > I
> > recommend:
> >http://code.google.com/p/sorl-thumbnail/*
>
> > -*Chris
>
> > On Sat, Jan 2, 2010 at 9:48 AM, nameless  wrote:
>
> >> Hi everyone I have a simple question.
> >> This is my model:
>
> >> class book(models.Model):
> >>title = models.CharField(max_length=50)
> >>photo = models.ImageField(upload_to='images/avatar/')
> >>thumb = models.ImageField(upload_to='images/thumb/')
>
> >> I want in photo original photo and in thumb the same photo but
> >> resized.
> >> How do I do that in simplest way ?
>
> >> Thank you and Good year  ^_^

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Re: Photo + thumbnail

[nameless]

I have writed this code but it doesn't work. What is the error ?


from django.db import models
from django.forms import ModelForm
from PIL import Image
import glob, os


thumb_size = 90, 90


class book(models.Model):
title = models.CharField(max_length=200)
photo = models.ImageField(upload_to='bookphoto')
thumb = models.ImageField(upload_to='bookthumb')



def save(self):

file_path = self.photo.path
if (file_path):
imfile, ext = os.path.splitext(file_path)
im = Image.open(file_path)
im.thumbnail(thumb_size, Image.ANTIALIAS)
im.save(immagin + ".thumbnail.jpg", "JPEG")
self.thumb = imfile + ".thumbnail.jpg"
super(book, self).save()


class BookForm(ModelForm):

class Meta:
model = book
exclude = ('thumb',)



Please help me, I am going crazy :-\


--

On Jan 2, 5:17 pm, Xia Kai(夏恺)  wrote:
> Hi,
>
> This is a fantastic app, though it might be too fat for a minimalist like
> me.   ^_^
>
> I would recommend override the default save method of the model and resize
> the original photo using PIL. For the overriding part, you could consult the
> documentation:http://docs.djangoproject.com/en/dev/topics/db/models/#overriding-pre...
>
> 
> Xia Kai(夏恺)
> xia...@gmail.comhttp://blog.xiaket.org
>
> --
> From: "Chris Moffitt" 
> Sent: Saturday, January 02, 2010 11:59 PM
> To: 
> Subject: Re: Photo + thumbnail
>
> > You'll probably want to use one of Django's thumbnail apps. Here's the one
> > I
> > recommend:
> >http://code.google.com/p/sorl-thumbnail/*
>
> > -*Chris
>
> > On Sat, Jan 2, 2010 at 9:48 AM, nameless  wrote:
>
> >> Hi everyone I have a simple question.
> >> This is my model:
>
> >> class book(models.Model):
> >>    title = models.CharField(max_length=50)
> >>    photo = models.ImageField(upload_to='images/avatar/')
> >>    thumb = models.ImageField(upload_to='images/thumb/')
>
> >> I want in photo original photo and in thumb the same photo but
> >> resized.
> >> How do I do that in simplest way ?
>
> >> Thank you and Good year  ^_^

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Re: Cannot reach development server in a rackspace cloud server

[simonecare...@gmail.com]

> python2.5 manage.py runserver 0.0.0.0:8000, but i can't point my web
> browser to that address.

Of course I mean MY.IP.ADDRESS:8000. :)



On Jan 4, 12:01 pm, "simonecare...@gmail.com"
 wrote:
> Hi everyone,
>
> i've just setted up a new Centos 5.4 based cloud server at Rackspace.
> Installed Python2.5 and virtualenv, devel-tools, and all went ok but I
> can't reach the development server.
>
> I started a new django project, then launched
>
> python2.5 manage.py runserver 0.0.0.0:8000, but i can't point my web
> browser to that address.
>
> Any ideas?
>
> Also tried to disable SELinux, but nothing changed.
>
> Thanks,
> Simone.

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Cannot reach development server in a rackspace cloud server

[simonecare...@gmail.com]

Hi everyone,

i've just setted up a new Centos 5.4 based cloud server at Rackspace.
Installed Python2.5 and virtualenv, devel-tools, and all went ok but I
can't reach the development server.

I started a new django project, then launched

python2.5 manage.py runserver 0.0.0.0:8000, but i can't point my web
browser to that address.

Any ideas?

Also tried to disable SELinux, but nothing changed.

Thanks,
Simone.

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Re: reverse drops the project from the url returned

[Graham Dumpleton]

Another way that people can screw up SCRIPT_NAME determination in a
server is not to use WSGIScriptAlias, but use WSGIScriptAliasMatch and
not use it properly.

So, please post the actual Apache configuration snippet you are using
to map you Django application with mod_wsgi so can verify that the
configuration you are using is in fact correct.

Normally WebFaction recipes should create it correctly, but if you
have hand crafted it and followed one of the incorrect blog posts out
there about it, you could have problems.

Graham

On Jan 4, 6:23 pm, Graham Dumpleton 
wrote:
> On Jan 4, 12:45 pm, davathar  wrote:
>
>
>
>
>
> > Here's more information I've been able to find.  Evidently there's a
> > problem in some configurations wheremod_wsgieither isn't receiving
> > or isn't passing SCRIPT_NAME.
>
> > When I use this test script in the wsgi file I get an empty string as
> > the value for SCRIPT_NAME.  And from what I gather that's where /
> > helpdesk should be so it can be passed to django so it's aware of the
> > full path.
>
> > **
> > import cStringIO
>
> > def application(environ, start_response):
> >     headers = []
> >     headers.append(('Content-Type', 'text/plain'))
> >     write = start_response('200 OK', headers)
>
> >     input = environ['wsgi.input']
> >     output = cStringIO.StringIO()
>
> >     keys = environ.keys()
> >     keys.sort()
> >     for key in keys:
> >         print >> output, '%s: %s' % (key, repr(environ[key]))
> >     print >> output
>
> >     output.write(input.read(int(environ.get('CONTENT_LENGTH', '0'
>
> >     return [output.getvalue()]
> > *
>
> > So it may not be as much a django issue as an apache/wsgi one.  I'm
> > not skilled enough to make that distinction though.  For now I'm just
> > going to serve the app from the root and move it when I learn more or
> > the issue is fixed.
>
> > I tested the admin module and I get the same problem.  Wherever the /
> > helpdesk is present in the URL everything serves properly.  But when I
> > post a form, it's dropped from the path and I get "There is no
> > application mounted at the root of this domain. " because I have
> > nothing mounted at the root.  I assume that message is served by
> > apache.
>
> > My host Webfaction uses multiple apache applications where the first
> > one is shared for the server.  I don't get direct access to the
> > settings for this.  Only control panel access which may make some
> > changes indirectly.  I think it uses  settings or maybe
> > SymLinks? to forward the request to another instance of apache that is
> > installed with Django on my share of the server.  I have total control
> > of that apache.  So, perhaps the first apache isn't passing any value
> > to the second one to indicate the first "mount point" is present.
> > This would be the "SCRIPT_NAME" from what I gather.
>
> Unless you are on an old server build, WebFaction uses nginx as front
> end, not Apache.
>
> In either case, the front end mount point isn't passed across. For it
> all to work properly, the front end mount point must match the backend
> mount point. You cannot mount on front end as /helpdesk and then have
> it proxy to / on backend for example. The backend must be mounted at /
> helpdesk as well.
>
> In respect of prior discussion, did you disable mod_rewrite in backend
> Apache?
>
> Graham
>
>
>
> > Yet another manifestation of the issue can be found by leaving off the
> > trailing slash at the end of the url : example.com/helpdesk/support/
> > case/1  will automatically redirect to example.com/support/case/1/  as
> > django adds the slash but drops the /helpdesk
>
> > ...com/helpdesk results in "There is no application mounted at the
> > root of this domain. "
>
> > com/helpdesk/ renders the app since my root urls.py contains "(r'^
> > $', 'helpdesk.support.views.home')," to call the support app home
> > view.
>
> > I hope some of this information helps.  In the mean time all the work
> > I've had to do to "move" my code to the root has completely convinced
> > me of the wisdom of decoupling.  ;-)  And at the same time the reason
> > I'm even having the trouble is because of the use of functions like
> > reverse to avoid hard coding views and templates to urls!
>
> > Thanks for your feedback.
>
> > On Jan 3, 5:50 pm, Karen Tracey  wrote:
>
> > > On Sun, Jan 3, 2010 at 5:15 PM, davathar  wrote:
> > > > Ramiro, thanks for the links.  That other thread does seem to describe
> > > > the same problem and results in it being identified as a bug in the
> > > > core urlresolvers.  Unfortunately the work around of "RewriteRule ^/
> > > > studio$ /studio/ [R] " doesn't work for me for some reason.  Maybe I'm
> > > > misapplying it.
>
> > > > Either way.  I'm going to drop this for now and see what happens with
> > > > the ticket that was opened.  It seems like this would be a very big
> > > > issue if 

Re: jquery, keyup event on a text input

[NMarcu]

I found the problem...thread closed

On Jan 4, 12:18 pm, NMarcu  wrote:
> Hello,
> I have this:
>
>  value="Controller 1"/>
>
> and the script:
>
>           
>                 $(document).ready(function() {
>                     $("#device_name").keyup(function() {
>                         alert("Something");
>                     });
>                 });
>             
>
> ...what I do wrong, because never do the alert, when I edit the text?

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jquery, keyup event on a text input

[NMarcu]

Hello,
I have this:



and the script:

  
$(document).ready(function() {
$("#device_name").keyup(function() {
alert("Something");
});
});


...what I do wrong, because never do the alert, when I edit the text?

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Re: Django tutorial: TemplateDoesNotExist at /admin/

[nameless]

I have reinstalled django and now work ^_^



-

On Jan 3, 5:52 pm, Daniel Roseman  wrote:
> On Jan 3, 1:52 pm, nameless  wrote:
>
>
>
> > I am using tutorial on django official documentation. But when I point
> > tohttp://127.0.0.1:8000/admin/, I get this error:
>
> > TemplateDoesNotExist at /admin/
>
> > admin/login.html
>
> > Request Method:         GET
> > Request URL:    http://127.0.0.1:8000/admin/
> > Exception Type:         TemplateDoesNotExist
> > Exception Value:
>
> > admin/login.html
>
> > Exception Location:     /usr/local/lib/python2.6/dist-packages/django/
> > template/loader.py in find_template_source, line 74
> > Python Executable:      /usr/bin/python
> > Python Version:         2.6.2
> > Python Path:    ['/home/nameless/Django-1.1.1/social', '/usr/lib/
> > python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-
> > tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/
> > usr/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages/
> > Numeric', '/usr/lib/python2.6/dist-packages/PIL', '/usr/lib/python2.6/
> > dist-packages/gst-0.10', '/var/lib/python-support/python2.6', '/usr/
> > lib/python2.6/dist-packages/gtk-2.0', '/var/lib/python-support/
> > python2.6/gtk-2.0', '/usr/local/lib/python2.6/dist-packages']
> > Server time:    Sun, 3 Jan 2010 07:47:21 -0600
> > Template-loader postmortem
>
> > Django tried loading these templates, in this order:
>
> >     * Using loader
> > django.template.loaders.filesystem.load_template_source:
> >     * Using loader
> > django.template.loaders.app_directories.load_template_source:
>
> > I am using Ubuntu 9.10 please help :-\
>
> Did you add 'django.contrib.admin' to INSTALLED_APPS in your
> settings.py?
> --
> DR.

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Re: How to check the validity of a field(unique property) from template?

[Daniel Roseman]

On Jan 4, 8:18 am, NMarcu  wrote:
> Hello all,
>
>     I want to check the fields from web interface before those to be
> added in db. If one field already exist to get a message like:
> "Already exist". I want to not perform the add action, if all fields
> are not validated.

This isn't something that you do in the template. It should happen in
the view.
--
DR.

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How to check the validity of a field(unique property) from template?

[NMarcu]

Hello all,

I want to check the fields from web interface before those to be
added in db. If one field already exist to get a message like:
"Already exist". I want to not perform the add action, if all fields
are not validated.

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