vDateField and generics views when migrating from oldforms

2009-10-17 Thread qhfgva

I have a .97 app that I'm trying to migrate to 1.1.

The current hangup is that forms that were generated by
generic.create_update were using oldforms under the covers and
automatically put the class="vDateField" in place that let the
javascript do it's magic and make the calendar selection widget
appear.

Is there a direct way to get this functionality with generic views
derived from "new" forms?

Or do I just need to make my own forms by hand that have these
attributes set as needed and then pass those to the generic views?

thanks.
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Re: data truncation: web page field input vs direct manipulation

2007-07-12 Thread qhfgva

Well, somewhere  between upgrading to trunk, using smart_unicode and
playing around with mysqldb connection settings I'm now getting my
data converted.  Thanks for your help.

On Jul 11, 12:13 am, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Wed, 2007-07-11 at 05:56 +0000, qhfgva wrote:
> > Well, I upgraded to the trunk version of django and now my error looks
> > like this:
>
> > UnicodeDecodeError: 'utf8' codec can't decode byte 0x94 in position 6:
> > unexpected code byte
>
> > Not sure if this is much of an improvement.
> [...]
> > > > Here's an example with a fancy right quote char:
>
> > > >>>> p.number = '53 5/8\x94H x 21\x94D x 47 1/4\x94L'
>
> If you are still using this example, then it's not too surprising you
> are seeing this error. Bytestrings (normal Python strings) must use
> UTF-8 encoding when passed to Django. Alternatively, you can use Unicode
> strings. What you can't do is pass in some arbitrarily encoded sequence
> of bytes and hope Django can guess the encoding. It can't do that.
>
> I can't even guess what byte encoding you are using in the above. I
> thought it might be cp-1252, but \x94 is closing double quotes there,
> not a right quote (that would be \x92). In any case, it's not UTF-8, so
> you are going to have problems. Read the section on string handling in
> docs/unicode.txt 
> (orhttp://www.djangoproject.com/documentation/unicode/#general-string-ha...) 
> for more details.
>
> Regards,
> Malcolm
>
> --
> Everything is _not_ based on faith... take my word for 
> it.http://www.pointy-stick.com/blog/


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Re: data truncation: web page field input vs direct manipulation

2007-07-10 Thread qhfgva

Well, I upgraded to the trunk version of django and now my error looks
like this:

UnicodeDecodeError: 'utf8' codec can't decode byte 0x94 in position 6:
unexpected code byte

Not sure if this is much of an improvement.

On Jul 10, 2:03 am, Horst Gutmann <[EMAIL PROTECTED]> wrote:
> qhfgva wrote:
> > Every time I think I understand string encoding I get reminded that I
> > don't.
>
> > I have a simple form where I can cut and paste in a value with an
> > "interesting" character in it (e.g. "Foo(r)" - in case that doesn't come
> > thru that's "F" "o" "o" followed by a registered trademark symbol).
> > It gets stored in the database just fine and can then be viewed.  If I
> > try to manipulate this value directly I get a truncation error.
>
> > Here's an example with a fancy right quote char:
>
> >>>> p.number = '53 5/8\x94H x 21\x94D x 47 1/4\x94L'
> >>>> p.save()
> > Traceback (most recent call last):
> >   File "", line 1, in ?
> >   File "c:\Python24\Lib\site-packages\django\db\models\base.py", line
> > 218, in save
> > db_values + [pk_val])
> >   File "c:\Python24\Lib\site-packages\django\db\backends\util.py",
> > line 12, in execute
> > return self.cursor.execute(sql, params)
> >   File "C:\Python24\Lib\site-packages\MySQLdb\cursors.py", line 165,
> > in execute
> > self._warning_check()
> >   File "C:\Python24\Lib\site-packages\MySQLdb\cursors.py", line 80, in
> > _warning_check
> > warn(w[-1], self.Warning, 3)
> >   File "C:\Python24\lib\warnings.py", line 61, in warn
> > warn_explicit(message, category, filename, lineno, module,
> > registry)
> >   File "C:\Python24\lib\warnings.py", line 96, in warn_explicit
> > raise message
> > _mysql_exceptions.Warning: Data truncated for column 'number' at row 1
>
> > I can cut an paste the actual string into the web form and it's
> > totally happy.  I've started to poke around the code to see if I can
> > determine what's going wrong, but I was hoping a helpful soul out
> > there could point my in the right direction.
>
> > thanks.
>
> What version of Django are you using? I also had some truncation errors
> thanks to Unicode strings (encoded in ASCII iirc) before, but they
> disappeared after the unicode-branch merge :-)
>
> - Horst


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data truncation: web page field input vs direct manipulation

2007-07-10 Thread qhfgva

Every time I think I understand string encoding I get reminded that I
don't.

I have a simple form where I can cut and paste in a value with an
"interesting" character in it (e.g. "Foo(r)" - in case that doesn't come
thru that's "F" "o" "o" followed by a registered trademark symbol).
It gets stored in the database just fine and can then be viewed.  If I
try to manipulate this value directly I get a truncation error.

Here's an example with a fancy right quote char:

>>> p.number = '53 5/8\x94H x 21\x94D x 47 1/4\x94L'
>>> p.save()
Traceback (most recent call last):
  File "", line 1, in ?
  File "c:\Python24\Lib\site-packages\django\db\models\base.py", line
218, in save
db_values + [pk_val])
  File "c:\Python24\Lib\site-packages\django\db\backends\util.py",
line 12, in execute
return self.cursor.execute(sql, params)
  File "C:\Python24\Lib\site-packages\MySQLdb\cursors.py", line 165,
in execute
self._warning_check()
  File "C:\Python24\Lib\site-packages\MySQLdb\cursors.py", line 80, in
_warning_check
warn(w[-1], self.Warning, 3)
  File "C:\Python24\lib\warnings.py", line 61, in warn
warn_explicit(message, category, filename, lineno, module,
registry)
  File "C:\Python24\lib\warnings.py", line 96, in warn_explicit
raise message
_mysql_exceptions.Warning: Data truncated for column 'number' at row 1

I can cut an paste the actual string into the web form and it's
totally happy.  I've started to poke around the code to see if I can
determine what's going wrong, but I was hoping a helpful soul out
there could point my in the right direction.

thanks.


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Re: limit_choices_to: getting access to current instance

2007-01-31 Thread qhfgva

Well, either I'm not able to follow your example or we are talking
about different things.  In any case here is what I got working as a
first draft.  As a big benefit to me is the fact that I now understand
these inner workings a little better.  I was hoping to get away with
simple wrappers to generic views but now I don't think that will be
the case but it also doesn't worry me.  :)

This is closely adapted from:  http://code.pui.ch/2007/01/07/using-
djangos-newforms/

from django import newforms as forms
from django.newforms import widgets
from django.template import loader, Context
from django.http import HttpResponse

def create_update_animal(request, animal_id=None):
animal = None
if animal_id:
animal = Animal.objects.get(id=animal_id)
animal_form = forms.models.form_for_instance(animal)
else:
animal_form = forms.models.form_for_model(Animal)

if animal:
available_protocols = Protocol.allowed_for_animal(animal)
else:
available_protocols = Protocol.active_list()

protocol_choices = [('','')] + [(p.id,p.number) for p in
available_protocols]
animal_form.base_fields['protocol'].widget.choices =
protocol_choices
if animal:
animal_form.base_fields['protocol'].widget.initial =
animal.protocol_id

if request.method == 'POST':
form = animal_form(request.POST)

if form.is_valid():
form.save()
return HttpResponseRedirect("/")
else:
form = animal_form()
t = loader.get_template('tracker/animal_form.html')

c = Context({ 'form': form, })

return HttpResponse(t.render(c))


If there is a way to do the above just using limit_choices_to, I'd
still like to understand that method.  Also if I'm doing anything
particularly hacky feel free to mock me (but also instruct me as to a
better way).

thanks.


On Jan 30, 5:04 pm, "quentinsf" <[EMAIL PROTECTED]> wrote:
> Sorry, the reference to 'Display' should have been to 'MyObject'


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Re: limit_choices_to: getting access to current instance

2007-01-29 Thread qhfgva

Thanks for the response.  I'm not sure if this exactly covers my case 
but I like this feature.  From the example given in the ticket:

def assigned_tasks():
   return get_assigned_tasks_id_list(blah, blah)

class TimeRecord(models.Model):
   task = models.ForeignKey(Task, limit_choices_to = {'id__in': 
assigned_tasks})


I would like the assigned_tasks function to be have a reference to and 
be able to calculate values based on the current instance of 
TimeRecord.Perhaps that is what blah or blah are but I'm guessing 
not.

Do I need to do something like work directly with newforms to achieve 
something like this?

On Jan 29, 6:54 am, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> 
wrote:
> See patch on ticket <http://code.djangoproject.com/ticket/2445>.
>
> On Jan 29, 8:31 am, "qhfgva" <[EMAIL PROTECTED]> wrote:
>
> > If my original post was not entirely clear, I'm interested in any
> > method available to limit_choices_to that lets you dynamically create
> > the list of available options as a function of the current model
> > instance.
>
> > thanks.
>
> > On Jan 28, 4:28 pm, "qhfgva" <[EMAIL PROTECTED]> wrote:
>
> > > I currently have a drop down for a model where I'd only like to show
> > > choices that are currently "active".  That's easy enough with:
>
> > > foo  = models.ForeignKey(Foo,
> > > limit_choices_to={'active__exact':True})
>
> > > But if someone is working with a model where the "foo" that they had
> > > previously selected has been subsequently set to inactive they should
> > > be able to keep that foo (they are "grandfathered" in).
>
> > > In effect I'd like limit_choices_to to have a list of foo.active ==
> > > True plus the current selection they have from the past if it is not
> > > an active choice.
>
> > > If I could make a method of Foo such as Foo.allowed_choice_for_x  and
> > > then pass it an instance of the current object, then it seems like I
> > > could easily generate the specific drop downlist on the fly but I'm
> > > not sure how to do that (or if it's possible).
>
> > > Thoughts?


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Re: limit_choices_to: getting access to current instance

2007-01-29 Thread qhfgva

If my original post was not entirely clear, I'm interested in any 
method available to limit_choices_to that lets you dynamically create 
the list of available options as a function of the current model 
instance.

thanks.

On Jan 28, 4:28 pm, "qhfgva" <[EMAIL PROTECTED]> wrote:
> I currently have a drop down for a model where I'd only like to show
> choices that are currently "active".  That's easy enough with:
>
> foo  = models.ForeignKey(Foo,
> limit_choices_to={'active__exact':True})
>
> But if someone is working with a model where the "foo" that they had
> previously selected has been subsequently set to inactive they should
> be able to keep that foo (they are "grandfathered" in).
>
> In effect I'd like limit_choices_to to have a list of foo.active ==
> True plus the current selection they have from the past if it is not
> an active choice.
>
> If I could make a method of Foo such as Foo.allowed_choice_for_x  and
> then pass it an instance of the current object, then it seems like I
> could easily generate the specific drop downlist on the fly but I'm
> not sure how to do that (or if it's possible).
>
> Thoughts?


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limit_choices_to: getting access to current instance

2007-01-28 Thread qhfgva

I currently have a drop down for a model where I'd only like to show 
choices that are currently "active".  That's easy enough with:

foo  = models.ForeignKey(Foo, 
limit_choices_to={'active__exact':True})

But if someone is working with a model where the "foo" that they had 
previously selected has been subsequently set to inactive they should 
be able to keep that foo (they are "grandfathered" in).

In effect I'd like limit_choices_to to have a list of foo.active == 
True plus the current selection they have from the past if it is not 
an active choice.

If I could make a method of Foo such as Foo.allowed_choice_for_x  and 
then pass it an instance of the current object, then it seems like I 
could easily generate the specific drop downlist on the fly but I'm 
not sure how to do that (or if it's possible).

Thoughts?


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Re: generic views and non-editable foreign keys

2007-01-18 Thread qhfgva


I think you have a small error in your example.  Should be:

class Thing(models.Model):
   #element = models.ForeignKey(Thing)
   element = models.ForeignKey(Element)
   name = models.CharField(maxlength=100)

Also I figured out my problem (I think).  I was passing ForeignKey
editable=False, apparently this was preventing the POSTed value from
being used.

So I guess I was misunderstanding the point of editable being False.
My hope was to set this value on create and have it be unchangeable
after that.  How do you even set the value of a column that has
editable=False?  In otherwords what is this parameter for?


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Re: generic views and non-editable foreign keys

2007-01-16 Thread qhfgva


Thanks for the link.  Using a wrapper is one of the things I had tried.
Here is what I tried.  I *think* I'm close, but I don't see the last
little bit that I'm missing:

 models.py
class Foo(models.Model):
   charfoo = models.CharField(maxlength=10)

class Goo(models.Model):
   chargoo = models.CharField(maxlength=10)
   foo = models.ForeignKey(Foo, editable=False)

 snippet from urls.py
   (r'^goo/create/foo_id/(?P\d+)/$',
'myproj.myapp.views.handle_goo_create'),

 views.py
def handle_goo_create(request, foo_id):
   return django.views.generic.create_update.create_object(request,
Goo,

post_save_redirect = "/goo/%(id)s/",

extra_context = {'foo_id' : foo_id})

 goo_form.html
{% extends "base.html" %}
{% block content %}

{% if form.has_errors %}
Please correct the following error{{ form.error_dict|pluralize
}}:
{% endif %}


   
   
   chargoo: {{form.chargoo}}
   {% if form.chargoo %}*** {{form.chargoo.errors|join:", "}}{%
endif %}
   
   


{% endblock %}



When I view this page with the URL:
http://localhost:8080/goo/create/foo_id/1/

I see that the foo_id value is populated in the form, but when posted I
get:

OperationalError at /goo/create/foo_id/1/
(1048, "Column 'foo_id' cannot be null")
Request Method: POST
Request URL:http://localhost:8080/goo/create/foo_id/1/
Exception Type: OperationalError
Exception Value:(1048, "Column 'foo_id' cannot be null")
Exception Location:
c:\Python23\lib\site-packages\MySQLdb\connections.py in
defaulterrorhandler, line 33


Any hints would be greatly appreciated.


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generic views and non-editable foreign keys

2007-01-13 Thread qhfgva


So far I've been using generic views for everything so I'm not sure if
I've reached the end of what those can do, or just need some better
understanding of how to use them.

I have a Foo model and a Goo model which among other attributes has a
non-editable ForeignKey reference back to Foo.  I'm having trouble
conceptualizing how I should handle getting the foo_id value set
automagically in a goo instance at the time it is created.

As a guess I was thinking that I could pass an instance of foo_id as
part of the extra_context value, but I'm not sure how I could grab this
value and put it in place in the urls.urlpatterns:

(r'^goo/create/$',  'django.views.generic.create_update.create_object',
{'model': Goo, 'post_save_redirect':"/goo/%(id)s/", extra_context:
{'foo_id' : ?}}),

And if I do figure out how to pass foo_id thru, I'm not sure how this
will interact with the template.  As a hidden parameter called foo_id
or id_foo_id?

Any hints on this would be greatly


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unescaped html in admin column

2006-05-25 Thread qhfgva

In order to fit more columns of data on the screen in the admin, I
tried the following:

# for use in list_display
def combined_cols(self):
return '%s%s%s' % (self.col1, self.col2,sel.col3)

Which displayed the '' in the output.

Is there some way to prevent the output from being html escaped in this
case?  Or is there some other way to format columns in a more condensed
form?


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does django go to 11?

2006-05-21 Thread qhfgva

I'm in the middle of converting a quixote app over to django.  Like
many people when I saw the admin app, there was no turning back.  I'm
trying to leverage the hell out of the admin component and so far the
magic genie has granted all my wishes.  I'm curious, however, how close
I'm getting to the "wall" (there has to be one, no?).  90% of my
current functionality is doable via the admin so far.  I'd be as happy
as a school girl if I can get the other 10% as well for "free" as it
were.  So here are some general django admin app questions:

- Is there a way to have input fields that are only available to
certain users/groups?
- Is there a way to have certain filters on as default?  (Instead of
set to "All")
- Is there a way to highlight certain rows with colors (e.g. if a row
meets a certain condition - e.g. a task past a due date highlighted in
red.)
- Is there a way to have certain rows not editable based on user/group
   (e.g the mangager_signoff column is true so non manager users can't
   modify this row any more)?
- Is there a reasonable way to add/remove buttons to/from the
save/delete buttons at the bottom of the create/update pages?

Thanks in advance.

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From: "qhfgva" <[EMAIL PROTECTED]>
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Subject: does django go to 11?
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Content-Type: text/plain

I'm in the middle of converting a quixote app over to django.  Like
many people when I saw the admin app, there was no turning back.  I'm
trying to leverage the hell out of the admin component and so far the
magic genie has granted all my wishes.  I'm curious, however, how close
I'm getting to the "wall" (there has to be one, no?).  90% of my
current functionality is doable via the admin so far.  I'd be as happy
as a school girl if I can get the other 10% as well for "free" as it
were.  So here are some general django admin app questions:

- Is there a way to have input fields that are only available to
certain users/groups?
- Is there a way to have certain filters on as default?  (Instead of
set to "All")
- Is there a way to highlight certain rows with colors (e.g. if a row
meets a certain condition - e.g. a task past a due date highlighted in
red.)
- Is there a way to have certain rows not editable based on user/group
   (e.g the mangager_signoff column is true so non manager users can't
   modify this row any more)?
- Is there a reasonable way to add/remove buttons to/from the
save/delete buttons at the bottom of the create/update pages?

Thanks in advance.


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Re: null=True conditionally

2006-05-20 Thread qhfgva

Thanks for your response, I'm not having luck with this.  It seems like
the admin interface is requiring ForeignKey fields even when marked as
null=True.

My validator that I wrote seems to be working, but since the fk field
is being required it defeats the purpose.

Here is my model.  Is there anything wrong or am I expecting behavior
that doesn't exist?

I want it to be the case that
- index_number is always required
- nih_contract must exist if index_number is of type 'nih' and must be
blank otherwise

==

#
--
class IndexNumber(models.Model):
contract_type = models.CharField(maxlength=40)
name  = models.CharField(maxlength=40)
def __str__(self):
return self.name
#
--
class NihContract(models.Model):
name = models.CharField(maxlength=40)

def __str__(self):
return self.name
#
--
def index_number_synched_with_nih_contract(field_data, all_data):
try:
contract_type =
IndexNumber.objects.get(id=(int(all_data['index_number'][0]))).contract_type
except:
raise validators.ValidationError('IndexNumber had no value!!!')

if field_data and contract_type != 'nih' or \
   not field_data and contract_type == 'nih':
raise validators.ValidationError("All (and only) NIH contracts
must have associated NIH contract number.")

class LabOrder(models.Model):
confirmation_number = models.CharField(maxlength=20, blank=True)
catalog_number  = models.CharField(maxlength=40, blank=True)
request_date= models.DateField(null=True)
asap= models.BooleanField()
notes   = models.CharField(maxlength=255, blank=True)
company = models.CharField(maxlength=40, blank=True)
product = models.CharField(maxlength=40, blank=True)
nih_contract= models.ForeignKey(NihContract, null=True,
validator_list=[index_number_synched_with_nih_contract])
cost_estimate   = models.FloatField(max_digits=7,
decimal_places=2)
index_number= models.ForeignKey(IndexNumber)
requestor   = models.ForeignKey(User)
received_date   = models.DateField(null=True)
received_by = models.CharField(maxlength=40, blank=True)
quantity= models.CharField(maxlength=40, blank=True)
approved= models.BooleanField(default=False)
size= models.CharField(maxlength=40,blank=True)
flag= models.BooleanField()


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null=True conditionally

2006-05-17 Thread qhfgva

Class Foo(Model):
blah = CharField(maxlength=20)
bar  = ForeignKey(Qwerty) # requred field
baz = CharField(maxlength=20, null=False)

In the above class I'd like to make baz a required field if bar is of a
certain value otherwise it can be blank.  If there a way to accomplish
this?

Thanks.


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Re: Limiting selection in admin pages [NEWBIE]

2006-05-15 Thread qhfgva

Thanks for the tip.  Your example didn't quite work for me.  I changed
it to:

'groups__name__exact'

Possibly it's because we are using different versions?  I'm using the
most recent trunk (magic-removal-branch).

One question if you don't mind answering.  I'm guessing that there is
juju going on here. name isn't a member of groups, it's a member of
just one specific group.  I'm assuming that the lookup mechanism is
smart enough to check the for the name property in the thing it is
chained off of and if that thing is a list then checking for that
property in each member of that list.  Is the that what's going on
here?  

Thanks again.


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