Re: Records Mysql can handle??
http://www.mysql.com/doc/en/Table_size.html On Sunday, August 31, 2003, at 01:07 PM, Binay Agarwal wrote: Hi All, Can any body tell me how many records mysql can hold efficiently. i.e Is there any boundation on number of records mysql can handle? Please let me know ... Thanks Binay -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: UPDATE based on value in another table
On Monday, August 25, 2003, at 03:26 PM, Dan Jones wrote: [snip] To make this a tad clearer, I have two tables: Title and Author. Author consists of the Author's name and an AuthorID. Title includes an AuthorID from the Author table. Some of the Author's have been deleted from the Author table. I want to remove any AuthorID entries from the Title table that no longer exists in the Author table. [snip] My SQL book, a generic reference not specific to any particular database, indicates the way to do this is via UPDATE with a subquery, like so: UPDATE Title SET AuthorID=NULL WHERE NOT IN (SELECT AuthorID FROM Author); This gives me a syntax error ...near SELECT AuthorID FROM Author) Does MySQL not support UPDATE with subqueries or am I screwing up the syntax somehow? MySQL does not support UPDATE with subqueries. I think it's on the list somewhere. Like a prerelease version may have it. Would this work for you? SELECT Title.AurthorID AS title_author, Author.AuthorID AS author_author FROM title_author LEFT JOIN author_author WHERE author_author IS NULL; There's your list of AuthorID's that have been deleted from the Author Table, but that still exist in the Title table. If possible, you could go through and then do the update programatically based on this list? The big difference being that you have already figured out that these are the ones you need to remove instead of having to check each and every authorID -Cameron Wilhelm -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Fixing autoincrement
On Tuesday, August 12, 2003, at 09:59 PM, otherguy wrote: On Tuesday, August 12, 2003, at 09:46 PM, Andrew Rothwell wrote: Hello List, I have a movies database, that I had an autoincrementing field for counting purposes.What I did though was remove some of the rows out of the table, now my table is reporting an incorrect number of movies listed.What I am trying to do is after is have done the following command [snip] There is no 74 Is there a way to force the DB upon removal of a row (74) to renumber the autoincremented fields? Short answer, no. I have tried to flush tables, but that did not work - btw I am using the last stable 3 release - but I will be updating to the latest stable 4 release in the next day or so. THank you Andrew Long answer: that defeats the purpose of an auto-increment. The only good way to do this is to do it programatically, and even then (if there are multiple updates at a time) won't necessarily guarantee unique values (the point of the auto_increment field). I should have said something like programatically with an integer field (as oppose to auto_increment). If all you need is the current number of movies, might I suggest: SELECT COUNT(*) FROM tablename; -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Multiple items in an ALTER TABLE statement
http://www.mysql.com/doc/en/ALTER_TABLE.html states that: You can issue multiple ADD, ALTER, DROP, and CHANGE clauses in a single ALTER TABLE statement. This is a MySQL extension to SQL-92, which allows only one of each clause per ALTER TABLE statement. but it doesn't give the syntax for doing so. Maybe try: ALTER TABLE tmp DROP COLUMN col_1 DROP COLUMN col_2...;? -Cameron Wilhelm On Tuesday, August 12, 2003, at 07:22 PM, Adam Fortuno wrote: Was in the midst of doing something today and I attempted to drop a number of columns in a table with the following: ALTER TABLE tmp DROP COLUMN col_1, col_2, col_3, col_4; Unfortunately MySQL gave me an error reading: ERROR 1064: You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near 'col_2, col_3, col_4' at line 1 Can you not have multiple columns names in an alter statement? -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Fixing autoincrement
On Tuesday, August 12, 2003, at 09:46 PM, Andrew Rothwell wrote: Hello List, I have a movies database, that I had an autoincrementing field for counting purposes.What I did though was remove some of the rows out of the table, now my table is reporting an incorrect number of movies listed.What I am trying to do is after is have done the following command [snip] There is no 74 Is there a way to force the DB upon removal of a row (74) to renumber the autoincremented fields? Short answer, no. I have tried to flush tables, but that did not work - btw I am using the last stable 3 release - but I will be updating to the latest stable 4 release in the next day or so. THank you Andrew Long answer: that defeats the purpose of an auto-increment. The only good way to do this is to do it programatically, and even then (if there are multiple updates at a time) won't necessarily guarantee unique values (the point of the auto_increment field). If all you need is the current number of movies, might I suggest: SELECT COUNT(*) FROM tablename; -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Is query possible? (Newbie)
On Thursday, August 14, 2003, at 08:04 PM, Jennifer Goodie wrote: I have 2 tables used for an online calendar... first table fields: primary_key , start_date, event_name, event_description second table fields: primary_key, end_date Tables fields are shortened and can't be changed. My second table only contains events that have a end date. I want to create a query that will take all the fields in. If no end_date exists then set to NULL. Been playing with it all day. Hoping some advance function exists. I thought of using a temp table but there must be a better way. I am confused by your question. It think it is missing words. If you are trying to select all records from first_table that do not have a record in second_table you can use a left join and is null... SELECT * from first_table LEFT JOIN second_table USING (primary_key) WHERE second_table.primary_key IS NULL Maybe I'm missing something here, but I don't see why you would want to split your tables up that way. You can't be saving that much room, and I don't think it really goes with standard normalization conventions. If you don't want to join the two, you could use the query above to find out all of the event ID's that you need to add to the second field. The easiest way to deal with this would be to modify Jennifer's to: SELECT first_table.primary_key from first_table LEFT JOIN second_table USING (primary_key) WHERE second_table.primary_key IS NULL and export it, and then just straight import it into your second_table. If you leave what you're putting into the second_table.end_date blank, it should come through as NULL. Although, I would also definitely suggest joining the two tables. FWIW, you can do this fairly easily by: CREATE TABLE new_table SELECT first_table.primary_key AS primary_key, first_table.start_date AS start_date, first_table.event_name AS event_name, first_table.event_description AS event_description second_table.end_date AS end_date FROM first_table LEFT JOIN second_table USING (primary_key); Although this is using extremely redundant syntax, this should give you one table, where all of the end_dates that's aren't populated in second_table end up being NULL. From there you could run a query: SELECT * FROM new_table WHERE end_date IS NULL; Good luck, -Cameron Wilhelm -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: mysql and Access
The simplest way, if you have the ability to make an ODBC connection to the mySQL box, would be to create an ODBC linked table in access and then run an append or make-table query against the linked table, as per your situation requires. I assume that you could write a macro that would run the query on a daily or hourly basis or something. If you're not able to create an ODBC link to the mySQL database, then there will most likely be some manual intervention. It would not be hard to procedure-ize and mostly automate the export and import process, though (with a little help from their ISP). (I'm assuming that they have an ISP that is hosting the box, if they're not hosting the box locally. If they were hosting it locally, they'd most likely be able to create an ODBC connection to it.) So the short answer is: Yes, you can, but if you have to ask, (or if most of what I've written so far went over your head), you'll probably want to get some help doing it. -Cameron Wilhelm On Thursday, July 31, 2003, at 04:41 PM, Voodoo wrote: I'm building an integrated system with Access and mySQL. Some company has na internal system based on Access and a web site with a form that saves its variables in a mySQL db. Can I make a system that migrates automatically the data from the mySQL online db for the the local Access db? And how? Can somebody help me? Thanks for now Cheers Voodoo -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: A Complicated Join
I've been working on something similar to this for quite a while (few more steps, maybe), and this list helped me through it, so I suppose I can at least return the favor. You basically need to do the following (I'm using temporary tables to help me think through it - and because of the lack of views and sub-selects): 1) Find the groups each user belongs to CREATE TEMPORARY TABLE user_groups SELECT users.id AS id, users.username AS username, g-u.groupID AS group FROM users INNER JOIN g-u ON users.id = g-u.userID; 2) From there, you can find all the messages that belong to each user CREATE TEMPORARY TABLE user_messages SELECT user_groups.id AS id, user_groups.username AS username, user_groups.group AS group, messages.id AS messageID FROM user_groups INNER JOIN messages ON user_groups.group = messages.groupID; 3) From there, the tricky part is to find the messages that DON'T have replies. There are some tips in the mySQL documentation about JOINS (in the comments section) that might give some more details/information/clarification/examples/explanation about this. (note the left join) SELECT user_messages.username, user_messages.messageID FROM user_messages LEFT JOIN replies ON user_messages.messageID = replies.messageID WHERE replies.messageID IS NULL; That SHOULD give you a listing of all users names, and the messageID's they've not yet replied to. I obviously don't have a test bed, so I apologize for any typos or anything that doesn't work quite right. Hopefully this gives you what you need, or at least puts you on the right track. After you're done, you're going to want to drop the temporary tables: DROP TABLE user_groups; DROP TABLE user_messages; Note that the temporary tables are only accurate at the instant you create them. They don't reflect changes until you drop and re-create them. I'm not good enough with joins and whatnot to try to put more than two tables into one (don't even know if you can), but a total of five statements isn't bad, eh? If you need more explanation about the how, why, or intent of any of the above, or if something doesn't work right, feel free to ask for clarification. Good luck! -Cameron Wilhelm On Tuesday, July 29, 2003, at 09:39 PM, Eric Winer wrote: I've been browsing through posts here, but I haven't found anything relevant to my issue, so I guess I'll just post it myself: I have three tables: users, groups (which define collections of users), messages, and replies (replies are completely different from messages and warrant their own table). Each message is sent out to a single group of users, and each user recieving the message can submit one reply. Here is the relevant (simplified) table info: messages int id int userID (the person who sent the message) int groupID (the group that the message is sent to) text messageBody etc. replies int id int messageID (the message this is a reply to) int userID (the user who sent the reply) text replyBody etc. users -- int id text userName etc. groups int id text groupName etc. g-u -- int groupID int userID How can I write a query that returns the sender's username and message's id for every message which a specified user has been sent but has not yet replied to? If you could explain your answer reasonably, please do so - I would like to learn how to write such a query so I don't have to bug the mailing list again. I'm using mySQL 4.0.x, so I can't use subqueries. Thanks! -Eric Winer -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Single Record Locking - Permanent?
2 methods I can think of: 1) Move the records into a different table, and set permissions accordingly (allow updates on for managers on that table) 2) Control authentication and access in your program. -Cameron Wilhelm On Tuesday, July 15, 2003, at 11:03 AM, Dan Ullom wrote: Is it possible to lock single records for all but a certain set of users, permanently? The intention is to make old items permanently unchangeable by anyone but managers. Thanks, Dan Ullom TechCentric 314-991-2594 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Advanced Query Help (My brain hurts!)
Thank you! That gets me halfway there, and not to my surprise, it's not even that hard! I should've known that it wouldn't be. So the other part that I truly have no idea how to do the following: UPDATE this_other_table SET satus = WHERE zipcode IN (result set from union query blow); can someone provide me with some pointers in the right direction? (SELECT quota_zip2.zipcode FROM quota_zip2 INNER JOIN quota_control2 ON (quota_zip2.agent_code = quota_control2.agent_code) AND (quota_zip2.appl = quota_control2.appl) WHERE quota_control2.appl = CIRG GROUP BY quota_zip2.zipcode HAVING SUM(quota_control2.quota_actual) = SUM(quota_control2.quota_limit) ) UNION (SELECT quota_zip2.zipcode FROM quota_zip2 INNER JOIN quota_control2 ON (quota_zip2.agent_code = quota_control2.agent_code) AND (quota_zip2.appl = quota_control2.appl) WHERE quota_control2.appl = CILT GROUP BY quota_zip2.zipcode HAVING SUM(quota_control2.quota_actual) = SUM(quota_control2.quota_limit) ) ORDER BY zipcode; Thanks! -Cameron Wilhelm On Friday, June 27, 2003, at 06:42 PM, MyLists wrote: How about a UNION statement? If the two queries are independently returning what you need, then you can just append the two results by using UNION. Good Luck! Dennis - Original Message - From: otherguy [EMAIL PROTECTED] To: MySQL List [EMAIL PROTECTED] Cc: Terry Vanstory [EMAIL PROTECTED] Sent: Friday, June 27, 2003 8:50 PM Subject: Advanced Query Help (My brain hurts!) Hey guys, I'm about to dump a doozy on your collective knowledge and goodwill, and hope for some help or some pointers. I'm not great with advanced SQL, and I've gotten as far as my brain and the resources I've been using will allow me to get for the time being. I need help with two things: 1) How can I effectively combine the following two queries? The only difference between them is the `appl` condition. I effectively need to do an INNER JOIN on the zip code of the results of both queries so that only zip codes that exist in both result sets are returned: SELECT quota_zip2.zipcode, SUM(quota_control2.quota_actual) AS sum_actual, SUM(quota_control2.quota_limit) AS sum_limit FROM quota_zip2 INNER JOIN quota_control2 ON (quota_zip2.agent_code = quota_control2.agent_code) AND (quota_zip2.appl = quota_control2.appl) WHERE quota_control2.appl = CIRG GROUP BY quota_zip2.zipcode HAVING sum_actual = sum_limit ORDER BY quota_zip2.zipcode; SELECT quota_zip2.zipcode, SUM(quota_control2.quota_actual) AS sum_actual, SUM(quota_control2.quota_limit) AS sum_limit FROM quota_zip2 INNER JOIN quota_control2 ON (quota_zip2.agent_code = quota_control2.agent_code) AND (quota_zip2.appl = quota_control2.appl) WHERE quota_control2.appl = CILT GROUP BY quota_zip2.zipcode HAVING sum_actual = sum_limit ORDER BY quota_zip2.zipcode; I cannot change the where clause to WHERE `appl` = CIRG OR `appl` = CILT because there might be data that would result in a situation where the the sum_actual would meet or exceed the sum_limit for a zip code (using both `appl`'s in the where), whereas running them separately would result in the sum_actual not being met for one of the `appl`'s for that zip_code (it would have been exceeded for the other `appl`). 2) Once I have this query, how can I then update a third table based on it? I basically need to run: UPDATE listmaster SET status = WD WHERE zipcode = any zipcode in results of the query from above. I think that this would involve another inner join, but at this point I'm _WAY_ over my head. I've included a dump of sample tables and data at the end of this e-mail. For the record: 1) I know that this whole thing would be easier to do programatically (it would take a while, but even I could do it that way). Unfortunately due to complications of the environment over which I have absolutely no control, that's not an option. 2) This database is not of my design. 3) This will eventually go into a nightly maintenance job, so query execution time is not a big issue. Finally, in advance, I really appreciate any time and effort any of you are willing to put in. Hopefully there's someone out there that enjoys figuring stuff like this out who has more expertise than I do. Any assistance rendered will result in many thanks from me. Thanks again, -Cameron Wilhelm -=-=-=-=-=-=-=BEGIN DUMP OF SAMPLE DATA=-=-=-=-=-=-=-=-=- # Tables dumped 2003-06-27 19:08:11 -0600 # Created by CocoaMySQL (Copyright (c) 2002-2003 Lorenz Textor) # # Host: localhost Database: nbl_test # ** # Dump of table listmaster # -- CREATE TABLE `listmaster` ( `id` int(11) NOT NULL auto_increment, `zipcode` char(5) default NULL, `status` char(2) default NULL, PRIMARY KEY (`id`), UNIQUE KEY `id` (`id`) ) TYPE=MyISAM; INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (1,1,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (2,1,NC); INSERT
Re: Advanced Query Help (My brain hurts!)
On Saturday, June 28, 2003, at 03:43 PM, MyLists wrote: otherguy wrote: That gets me halfway there Does it? Yes, it does. No, I don't think it does, upon further consideration and testing... I thought it did b/c I read, and misinterpreted the UNION documentation In your original question, you'd indicated that you only wanted zips where *both* criteria were met -- enough CIRGs and enough CILTs. By using a UNION, you'll be getting zips where *either* is met. This is right. No. The key is that each independent query was returing the results he wanted - so, the UNION statement will simple append these two results into one long dataset - the WHERE clause, criteria, or even the number of records is really not affected. So is this. If I just needed to know that quota had been met for EITHER, then this would work perfectly for me. The key for my situation is that I need ONLY the records that exist in BOTH. Any other thoughts for this, or am I bumping up against the limits of SQL in general? Thanks again! -Cameron Wilhelm -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Advanced Query Help (My brain hurts!)
On Saturday, June 28, 2003, at 07:15 PM, Bruce Feist wrote: otherguy wrote: On Saturday, June 28, 2003, at 03:43 PM, MyLists wrote: That gets me halfway there BF: Does it? No, I don't think it does, upon further consideration and testing... I thought it did b/c I read, and misinterpreted the UNION documentation BF: In your original question, you'd indicated that you only wanted zips where *both* criteria were met -- enough CIRGs and enough CILTs. By using a UNION, you'll be getting zips where *either* is met. This is right. The key for my situation is that I need ONLY the records that exist in BOTH. Any other thoughts for this, or am I bumping up against the limits of SQL in general? Well, keep in mind that although SQL can do a lot in a single statement, it can't always do *everything* required for a business function in one statement. As I'm painfully aware of, but was hopeful about. [snip] Here's a sequence. [snip] I can't thank you enough for your time and effort. I should be able to tweak this enough to make it usable. Thanks again. Now I just have to beat up the system guys for making me do this :) Thank you, -Cameron Wilhelm -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Advanced Query Help (My brain hurts!)
Hey guys, I'm about to dump a doozy on your collective knowledge and goodwill, and hope for some help or some pointers. I'm not great with advanced SQL, and I've gotten as far as my brain and the resources I've been using will allow me to get for the time being. I need help with two things: 1) How can I effectively combine the following two queries? The only difference between them is the `appl` condition. I effectively need to do an INNER JOIN on the zip code of the results of both queries so that only zip codes that exist in both result sets are returned: SELECT quota_zip2.zipcode, SUM(quota_control2.quota_actual) AS sum_actual, SUM(quota_control2.quota_limit) AS sum_limit FROM quota_zip2 INNER JOIN quota_control2 ON (quota_zip2.agent_code = quota_control2.agent_code) AND (quota_zip2.appl = quota_control2.appl) WHERE quota_control2.appl = CIRG GROUP BY quota_zip2.zipcode HAVING sum_actual = sum_limit ORDER BY quota_zip2.zipcode; SELECT quota_zip2.zipcode, SUM(quota_control2.quota_actual) AS sum_actual, SUM(quota_control2.quota_limit) AS sum_limit FROM quota_zip2 INNER JOIN quota_control2 ON (quota_zip2.agent_code = quota_control2.agent_code) AND (quota_zip2.appl = quota_control2.appl) WHERE quota_control2.appl = CILT GROUP BY quota_zip2.zipcode HAVING sum_actual = sum_limit ORDER BY quota_zip2.zipcode; I cannot change the where clause to WHERE `appl` = CIRG OR `appl` = CILT because there might be data that would result in a situation where the the sum_actual would meet or exceed the sum_limit for a zip code (using both `appl`'s in the where), whereas running them separately would result in the sum_actual not being met for one of the `appl`'s for that zip_code (it would have been exceeded for the other `appl`). 2) Once I have this query, how can I then update a third table based on it? I basically need to run: UPDATE listmaster SET status = WD WHERE zipcode = any zipcode in results of the query from above. I think that this would involve another inner join, but at this point I'm _WAY_ over my head. I've included a dump of sample tables and data at the end of this e-mail. For the record: 1) I know that this whole thing would be easier to do programatically (it would take a while, but even I could do it that way). Unfortunately due to complications of the environment over which I have absolutely no control, that's not an option. 2) This database is not of my design. 3) This will eventually go into a nightly maintenance job, so query execution time is not a big issue. Finally, in advance, I really appreciate any time and effort any of you are willing to put in. Hopefully there's someone out there that enjoys figuring stuff like this out who has more expertise than I do. Any assistance rendered will result in many thanks from me. Thanks again, -Cameron Wilhelm -=-=-=-=-=-=-=BEGIN DUMP OF SAMPLE DATA=-=-=-=-=-=-=-=-=- # Tables dumped 2003-06-27 19:08:11 -0600 # Created by CocoaMySQL (Copyright (c) 2002-2003 Lorenz Textor) # # Host: localhost Database: nbl_test # ** # Dump of table listmaster # -- CREATE TABLE `listmaster` ( `id` int(11) NOT NULL auto_increment, `zipcode` char(5) default NULL, `status` char(2) default NULL, PRIMARY KEY (`id`), UNIQUE KEY `id` (`id`) ) TYPE=MyISAM; INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (1,1,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (2,1,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (3,1,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (4,1,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (5,2,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (6,2,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (7,2,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (8,2,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (9,3,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (10,3,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (11,3,NC); INSERT INTO `listmaster` (`id`,`zipcode`,`status`) VALUES (12,3,NC); # Dump of table quota_control2 # -- CREATE TABLE `quota_control2` ( `agent_code` char(6) default NULL, `appl` char(4) default NULL, `quota_limit` smallint(6) default NULL, `quota_actual` smallint(6) default NULL, UNIQUE KEY `agent_code` (`agent_code`,`appl`) ) TYPE=MyISAM; INSERT INTO `quota_control2` (`agent_code`,`appl`,`quota_limit`,`quota_actual`) VALUES (a1,CIRG,10,10); INSERT INTO `quota_control2` (`agent_code`,`appl`,`quota_limit`,`quota_actual`) VALUES (a2,CIRG,5,6); INSERT INTO `quota_control2` (`agent_code`,`appl`,`quota_limit`,`quota_actual`) VALUES (a2,CILT,5,0); INSERT INTO `quota_control2` (`agent_code`,`appl`,`quota_limit`,`quota_actual`) VALUES (a3,CILT,5,0); # Dump of table
Re: SSL and Windows
http://www.google.com/search?q=openssl+windowsie=UTF-8oe=UTF-8 On Monday, June 9, 2003, at 01:43 PM, Sparky Kopetzky wrote: Does anyone know how to turn the SSL on for mySql for Windows?? I need to encrypt and decrypt certain items in a database and the manual says add the OpenSSL package but there isn't one for Windows. Help! Thanks in advance!! Robin E. Kopetzky Black Mesa Computers/Internet Services www.blackmesa-isp.net -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: database permissions
On Wednesday, May 28, 2003, at 07:40 PM, [EMAIL PROTECTED] wrote: On Wednesday, May 28, 2003, at 06:31 AM, Jon Haugsand wrote: * [EMAIL PROTECTED] What the permissions/ownership be on my database directory? I think is the cause of my problem of only being able to startup mysqld as 'root'. On my system the mysqld deamon runs as mysql and files are owned by mysql. -- Jon Haugsand, [EMAIL PROTECTED] http://www.norges-bank.no How can I check that my 'mysql daemon' is running as user 'mysql' and not 'root'? I have already done 'chown -R mysql /pathto/databases It looks like you're using Apple Mail, so I'll assume you're on OS X. Open '/Applications/Utilities/Process Viewer' and type mysql (or some combination) into the find box. It'll give you the user (mysqld is the one you're looking at). There are other ways, but that's the easiest way if you're not interested in reading 'man ps'. If you are interested in sticking with the command line, here are a couple of ways you could check: ps -au ps -U httpd and of course: ps -au|grep mysqld (terminal screen will need to be wide for this, most likely) -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: database permissions
On Wednesday, May 28, 2003, at 08:16 PM, otherguy wrote: ps -U httpd I screwed this up. It's been a long day. Of course it should be: ps -U mysqld sorry about that -Cameron Wilhelm -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
