SQL query problem
Hi, I have built a site with Dreamweaver and I have a problem with a query. I am trying to pass a parameter from one page to another to drill down. Basically, I have one product entry that is in multiple categories on my website. So, say it's a dress, it is therefore related to category 1 which is 'Girls', but it is also more specifically related to category 2 which is 'Girls Dresses'. The way I have set this up is to have a column called MultiCategoryID that holds both the number 1 and 2 like this: /1/2/ When a user clicks a link to look at dresses, the parameter 2 is passed, but my query on the result page is wrong in some way because no records are displaying even though there is content to display. This is what I have so far: SELECT * FROM Products WHERE MultiCategoryID LIKE '/catdrill/' ORDER BY ProductID DESC The parameter settings are: Name: catdrill Type: Numeric Value: Request(MCID) MCID is the url parameter being passed Default value: 2 Only when I test the Default value with an exact match of /1/2/ does any product display. What have I done wrong here? Is there a way to get it to recognise that I want it to pick specific numbers between the slashes rather than the whole lot? I have tried to change the slashes to full stops just in case they are causing problems, but it's still giving the same problem. Thanks. Mat
Re: SQL query problem
Dear Mat, Your mail is not very clear. But I have a feeling that using '%' wildcard in the like operand should help you Regards, Ravi. On 11/14/07, Matthew Stuart [EMAIL PROTECTED] wrote: Hi, I have built a site with Dreamweaver and I have a problem with a query. I am trying to pass a parameter from one page to another to drill down. Basically, I have one product entry that is in multiple categories on my website. So, say it's a dress, it is therefore related to category 1 which is 'Girls', but it is also more specifically related to category 2 which is 'Girls Dresses'. The way I have set this up is to have a column called MultiCategoryID that holds both the number 1 and 2 like this: /1/2/ When a user clicks a link to look at dresses, the parameter 2 is passed, but my query on the result page is wrong in some way because no records are displaying even though there is content to display. This is what I have so far: SELECT * FROM Products WHERE MultiCategoryID LIKE '/catdrill/' ORDER BY ProductID DESC The parameter settings are: Name: catdrill Type: Numeric Value: Request(MCID) MCID is the url parameter being passed Default value: 2 Only when I test the Default value with an exact match of /1/2/ does any product display. What have I done wrong here? Is there a way to get it to recognise that I want it to pick specific numbers between the slashes rather than the whole lot? I have tried to change the slashes to full stops just in case they are causing problems, but it's still giving the same problem. Thanks. Mat
SQL-Query problem
Hello all, Have a little problem with to make a sql-query as I want to have it... The problem is I need to check in 3 tables and count out and get it presentated per n_id like n_id counted 01 5 02 10 03 2 My tables look as follows... In sub: id n_id In us: id email In sub_del: n_id id I have already a query that count it out totally. SELECT (SELECT count(sub_id) from sub) - (SELECT count(us.id) FROM us LEFT JOIN sub ON sub.id = us.id)+(SELECT count(*) FROM sub_del); But my problem is that I want to be able to get out the result per sub.n_id instaead. Please help! /Joppe -- ___ Sign-up for Ads Free at Mail.com http://promo.mail.com/adsfreejump.htm -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
SQL Query problem
Hi All, I have a query problem here. Say I have a table with employee records of three different departments. If each department manager wants to see employee info of their own department. Three different queries will be needed. Is there a way that I can write one single query and let SQL decide which department info to display at the run time? Thanks. __ Do you Yahoo!? Yahoo! Mail SpamGuard - Read only the mail you want. http://antispam.yahoo.com/tools -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: SQL Query problem
On Friday 20 February 2004 15:19, Claire Lee wrote: Hi All, I have a query problem here. Say I have a table with employee records of three different departments. If each department manager wants to see employee info of their own department. Three different queries will be needed. Is there a way that I can write one single query and let SQL decide which department info to display at the run time? Thanks. What language are you doing this in? You should be able to provide the appropriate 'where' clause when generating the query. -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
sql Query problem?
Hi, I have a sql query problem... user points table, which I am sorting(order by) points. Now if I want to have some 5 records above and below a certain member, how could I write the sql query for the same? say I want 5 records above and below NICKNAME_14! thanks and regards, point nickname -- 999 NICKNAME_6 980 NICKNAME_23 970 NICKNAME_8 960 NICKNAME_9 940 NICKNAME_11 940 NICKNAME_41 932 NICKNAME_26 930 NICKNAME_12 930 NICKNAME_42 922 NICKNAME_38 920 NICKNAME_13 900 NICKNAME_2 900 NICKNAME_25 900 NICKNAME_5 === 900 NICKNAME_14 900 NICKNAME_3 880 NICKNAME_30 860 NICKNAME_57 860 NICKNAME_39 860 NICKNAME_21 859 NICKNAME_36 850 NICKNAME_20 840 NICKNAME_35 840 NICKNAME_19 836 NICKNAME_45 830 NICKNAME_33 830 NICKNAME_18 820 NICKNAME_17 810 NICKNAME_32 800 NICKNAME_24 800 NICKNAME_15 764 NICKNAME_54 700 NICKNAME_27 625 NICKNAME_59 600 NICKNAME_28 563 NICKNAME_55 500 NICKNAME_29 270 NICKNAME_49 270 NICKNAME_48 262 NICKNAME_56 260 NICKNAME_44 260 NICKNAME_51 260 NICKNAME_47 256 NICKNAME_50 250 NICKNAME_58 246 NICKNAME_43 226 NICKNAME_60 140 NICKNAME_53 Nishant [EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
RE: Complex SQL query problem...
FYI - this query seemed to work. select * from nodes left join nodes as n2 on n2.parent_id = nodes.node_id left join jobs on jobs.parent_id = nodes.node_id left join colors on colors.parent_id = nodes.node_id where nodes.node_id = ? and ((n2.parent_id is not NULL) or (jobs.parent_id is not NULL) or (colors.parent_id is not NULL)) I need to do some more testing to be sure. Rich -Original Message- From: Edward Peloke [mailto:[EMAIL PROTECTED]] Sent: Monday, September 23, 2002 08:46 To: Richard Bolen Subject: RE: Complex SQL query problem... After I sent this it hit me that it may not work if the first table (jobs) contained no rows...I believe this would only work if the tables left joined were empty not the jobs table. sorry... I apologize did not respond Friday but I left work at 4. Eddie -Original Message- From: Richard Bolen [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 4:19 PM To: Edward Peloke Subject: RE: Complex SQL query problem... Does this handle the case where the ID is in the submissions table but not the jobs table? How would this look if there was a third table also? Thanks again for you help! Rich -Original Message- From: Edward Peloke [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 15:59 To: MySQL Mailing List (E-mail) Subject: RE: Complex SQL query problem... try a left join select count(*) from jobs left join submissions on jobs.standard_id=submissions.color_id where jobs.standard_id=ID_VALUE and submissions.color_id is null Eddie -Original Message- From: Richard Bolen [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 2:37 PM To: MySQL Mailing List (E-mail) Subject: Complex SQL query problem... I'm trying to use a sql query to determine if an ID exists in any of 3 different tables in the database. I need to do this in one SQL query (ideally only using the ID once in the query). I'm using mysql 3.23.47. Here's an example of a query I came up with: select count(*) from jobs, submissions where ID_VALUE in (jobs.standard_id, submissions.color_id) I'm just trying to determine if the ID exists. This query works *IF AND ONLY IF* there is at least one record in each of the tables. If any of the table are empty, this query always returns a count of 0 (even if there is a match in one of the non-empty tables). Does anyone know why this is happening or could someone suggest a alternate query? Thanks, Rich Rich Bolen Senior Software Developer GretagMacbeth Advanced Technologies Center 79 T. W. Alexander Drive - Bldg. 4401 - Suite 250 PO Box 14026 Research Triangle Park, North Carolina 27709-4026 USA Phone: 919-549-7575 x239, Fax: 919-549-0421 http://www.gretagmacbeth.com/ - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
RE: Complex SQL query problem...
great! hope it works ! -Original Message- From: Richard Bolen [mailto:[EMAIL PROTECTED]] Sent: Monday, September 23, 2002 9:17 AM To: MySQL Mailing List (E-mail) Cc: Edward Peloke Subject: RE: Complex SQL query problem... FYI - this query seemed to work. select * from nodes left join nodes as n2 on n2.parent_id = nodes.node_id left join jobs on jobs.parent_id = nodes.node_id left join colors on colors.parent_id = nodes.node_id where nodes.node_id = ? and ((n2.parent_id is not NULL) or (jobs.parent_id is not NULL) or (colors.parent_id is not NULL)) I need to do some more testing to be sure. Rich -Original Message- From: Edward Peloke [mailto:[EMAIL PROTECTED]] Sent: Monday, September 23, 2002 08:46 To: Richard Bolen Subject: RE: Complex SQL query problem... After I sent this it hit me that it may not work if the first table (jobs) contained no rows...I believe this would only work if the tables left joined were empty not the jobs table. sorry... I apologize did not respond Friday but I left work at 4. Eddie -Original Message- From: Richard Bolen [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 4:19 PM To: Edward Peloke Subject: RE: Complex SQL query problem... Does this handle the case where the ID is in the submissions table but not the jobs table? How would this look if there was a third table also? Thanks again for you help! Rich -Original Message- From: Edward Peloke [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 15:59 To: MySQL Mailing List (E-mail) Subject: RE: Complex SQL query problem... try a left join select count(*) from jobs left join submissions on jobs.standard_id=submissions.color_id where jobs.standard_id=ID_VALUE and submissions.color_id is null Eddie -Original Message- From: Richard Bolen [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 2:37 PM To: MySQL Mailing List (E-mail) Subject: Complex SQL query problem... I'm trying to use a sql query to determine if an ID exists in any of 3 different tables in the database. I need to do this in one SQL query (ideally only using the ID once in the query). I'm using mysql 3.23.47. Here's an example of a query I came up with: select count(*) from jobs, submissions where ID_VALUE in (jobs.standard_id, submissions.color_id) I'm just trying to determine if the ID exists. This query works *IF AND ONLY IF* there is at least one record in each of the tables. If any of the table are empty, this query always returns a count of 0 (even if there is a match in one of the non-empty tables). Does anyone know why this is happening or could someone suggest a alternate query? Thanks, Rich Rich Bolen Senior Software Developer GretagMacbeth Advanced Technologies Center 79 T. W. Alexander Drive - Bldg. 4401 - Suite 250 PO Box 14026 Research Triangle Park, North Carolina 27709-4026 USA Phone: 919-549-7575 x239, Fax: 919-549-0421 http://www.gretagmacbeth.com/ - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Complex SQL query problem...
I'm trying to use a sql query to determine if an ID exists in any of 3 different tables in the database. I need to do this in one SQL query (ideally only using the ID once in the query). I'm using mysql 3.23.47. Here's an example of a query I came up with: select count(*) from jobs, submissions where ID_VALUE in (jobs.standard_id, submissions.color_id) I'm just trying to determine if the ID exists. This query works *IF AND ONLY IF* there is at least one record in each of the tables. If any of the table are empty, this query always returns a count of 0 (even if there is a match in one of the non-empty tables). Does anyone know why this is happening or could someone suggest a alternate query? Thanks, Rich Rich Bolen Senior Software Developer GretagMacbeth Advanced Technologies Center 79 T. W. Alexander Drive - Bldg. 4401 - Suite 250 PO Box 14026 Research Triangle Park, North Carolina 27709-4026 USA Phone: 919-549-7575 x239, Fax: 919-549-0421 http://www.gretagmacbeth.com/ - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
RE: Complex SQL query problem...
try a left join select count(*) from jobs left join submissions on jobs.standard_id=submissions.color_id where jobs.standard_id=ID_VALUE and submissions.color_id is null Eddie -Original Message- From: Richard Bolen [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 2:37 PM To: MySQL Mailing List (E-mail) Subject: Complex SQL query problem... I'm trying to use a sql query to determine if an ID exists in any of 3 different tables in the database. I need to do this in one SQL query (ideally only using the ID once in the query). I'm using mysql 3.23.47. Here's an example of a query I came up with: select count(*) from jobs, submissions where ID_VALUE in (jobs.standard_id, submissions.color_id) I'm just trying to determine if the ID exists. This query works *IF AND ONLY IF* there is at least one record in each of the tables. If any of the table are empty, this query always returns a count of 0 (even if there is a match in one of the non-empty tables). Does anyone know why this is happening or could someone suggest a alternate query? Thanks, Rich Rich Bolen Senior Software Developer GretagMacbeth Advanced Technologies Center 79 T. W. Alexander Drive - Bldg. 4401 - Suite 250 PO Box 14026 Research Triangle Park, North Carolina 27709-4026 USA Phone: 919-549-7575 x239, Fax: 919-549-0421 http://www.gretagmacbeth.com/ - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
RE: Complex SQL query problem...
Sorry about emailing you directly Eddie. I meant to reply to the list with my last email. Anyway - your suggestion worked wonderfully. Many many thanks. -Original Message- From: Edward Peloke [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 15:59 To: MySQL Mailing List (E-mail) Subject: RE: Complex SQL query problem... try a left join select count(*) from jobs left join submissions on jobs.standard_id=submissions.color_id where jobs.standard_id=ID_VALUE and submissions.color_id is null Eddie -Original Message- From: Richard Bolen [mailto:[EMAIL PROTECTED]] Sent: Friday, September 20, 2002 2:37 PM To: MySQL Mailing List (E-mail) Subject: Complex SQL query problem... I'm trying to use a sql query to determine if an ID exists in any of 3 different tables in the database. I need to do this in one SQL query (ideally only using the ID once in the query). I'm using mysql 3.23.47. Here's an example of a query I came up with: select count(*) from jobs, submissions where ID_VALUE in (jobs.standard_id, submissions.color_id) I'm just trying to determine if the ID exists. This query works *IF AND ONLY IF* there is at least one record in each of the tables. If any of the table are empty, this query always returns a count of 0 (even if there is a match in one of the non-empty tables). Does anyone know why this is happening or could someone suggest a alternate query? Thanks, Rich Rich Bolen Senior Software Developer GretagMacbeth Advanced Technologies Center 79 T. W. Alexander Drive - Bldg. 4401 - Suite 250 PO Box 14026 Research Triangle Park, North Carolina 27709-4026 USA Phone: 919-549-7575 x239, Fax: 919-549-0421 http://www.gretagmacbeth.com/ - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
A small SQL query problem
A small SQL query problem concerning articles and article_comments :) You experts will have no problem with this :) In brief: - I have no problems displaying the title, date, author, summary of the articles or anything. Its just doing an sql query that gets my 3 latest articles AND counts how many comments each article has, and doing it in ONE query instead of two separate ones... :( In *not* brief: --- I have 2 tables. One contains articles, basically like this: --- | id | title | summary | text | date | author | --- The other containts comments to the articles, basically looks like this: --- | id | article_id | text | author | --- Now, on my main page I want to display the first 3 articles like this: TITLETITLETITLETITLETITLE (date) written by AUTHOR SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY Read the whole story (comments: ##) My actual problem is how to get the number of comments (##)! I have no problems displaying the title, date, author, summary or anything. Its just doing an sql query that counts how many comments the article has, and doing it in ONE query instead of two separate ones... :( - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail mysql-unsubscribe-##L=##[EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
RE: A small SQL query problem
* Torkil Johnsen [...] I have no problems displaying the title, date, author, summary of the articles or anything. Its just doing an sql query that gets my 3 latest articles AND counts how many comments each article has, and doing it in ONE query instead of two separate ones... :( [...] One contains articles, basically like this: --- | id | title | summary | text | date | author | --- The other containts comments to the articles, basically looks like this: --- | id | article_id | text | author | --- Now, on my main page I want to display the first 3 articles like this: TITLETITLETITLETITLETITLE (date) written by AUTHOR SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY Read the whole story (comments: ##) My actual problem is how to get the number of comments (##)! Try something like this: SELECT a.title,a.date,a.author,a.summary,COUNT(c.id) as comments FROM articles as a,article_comments as c WHERE a.id = c.article_id GROUP BY a.title,a.date,a.author,a.summary ORDER BY a.date DESC LIMIT 3 -- Roger - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail mysql-unsubscribe-##L=##[EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: A small SQL query problem
Thanks for the suggestion! I modified your query to something that works for me (I was inaccurate with the column names before, sorry... :) SELECT a.article_id,a.title,a.date,a.summary,COUNT(c.id) as comments FROM articles as a,article_comments as c WHERE a.article_id = c.article_id GROUP BY a.article_id,a.title,a.date,a.summary ORDER BY a.date DESC LIMIT 3 This works PERFECTLY Except: If an article has NO comments, it is not returned at all! So: When my articles table contains only 3 articles, and I make a query that has LIMIT 3, you would think that this query would return all articles, but it does not: Only the ones that actually has one or more comments. I tried this with 3 articles where 2 of them had comments: Only 2 rows returned. When I gave one comment on the last article: 3 rows returned. Seems like if COUNT(c.id) returns 0, then the row is not returned at all. Suggestions? * Torkil Johnsen [...] I have no problems displaying the title, date, author, summary of the articles or anything. Its just doing an sql query that gets my 3 latest articles AND counts how many comments each article has, and doing it in ONE query instead of two separate ones... :( [...] One contains articles, basically like this: --- | id | title | summary | text | date | author | --- The other containts comments to the articles, basically looks like this: --- | id | article_id | text | author | --- Now, on my main page I want to display the first 3 articles like this: TITLETITLETITLETITLETITLE (date) written by AUTHOR SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY SUMMARY Read the whole story (comments: ##) My actual problem is how to get the number of comments (##)! **ROGER Try something like this: SELECT a.title,a.date,a.author,a.summary,COUNT(c.id) as comments FROM articles as a,article_comments as c WHERE a.id = c.article_id GROUP BY a.title,a.date,a.author,a.summary ORDER BY a.date DESC LIMIT 3 -- Roger - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail mysql-unsubscribe-##L=##[EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: A small SQL query problem
[EMAIL PROTECTED] wrote: Thanks for the suggestion! I modified your query to something that works for me (I was inaccurate with the column names before, sorry... :) SELECT a.article_id,a.title,a.date,a.summary,COUNT(c.id) as comments FROM articles as a,article_comments as c WHERE a.article_id = c.article_id GROUP BY a.article_id,a.title,a.date,a.summary ORDER BY a.date DESC LIMIT 3 This works PERFECTLY Except: If an article has NO comments, it is not returned at all! So: When my articles table contains only 3 articles, and I make a query that has LIMIT 3, you would think that this query would return all articles, but it does not: Only the ones that actually has one or more comments. I tried this with 3 articles where 2 of them had comments: Only 2 rows returned. When I gave one comment on the last article: 3 rows returned. Seems like if COUNT(c.id) returns 0, then the row is not returned at all. That's because there's no row in the comment table to join on. You want to use a LEFT JOIN here. So the revised query might look like: SELECT a.article_id,a.title,a.date,a.summary,COUNT(c.id) AS comments FROM articles AS a LEFT JOIN article_comments AS c ON a.article_id = c.article_id GROUP BY a.article_id,a.title,a.date,a.summary ORDER BY a.date DESC LIMIT 3 -- John Klein, Database Applications Developer | Omnia Mutantur, Systems Group - Harvard Law School | Nihil Interit - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
RE: A small SQL query problem
* Torkil Johnsen This works PERFECTLY Except: If an article has NO comments, it is not returned! Use a LEFT JOIN: SELECT a.title,a.date,a.author,a.summary,COUNT(c.id) as comments FROM articles as a LEFT JOIN article_comments as c ON a.id = c.article_id GROUP BY a.title,a.date,a.author,a.summary ORDER BY a.date DESC LIMIT 3 This also eliminates the WHERE clause in this case, as the criteria is used in the ON clause of the LEFT JOIN. URL: http://www.mysql.com/doc/J/O/JOIN.html -- Roger - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
sql query problem
Dear group members, I have a serious problem with an SQL query that has kept me busy for over a week. Doing my compusory service at a non-profit environmental organisation I was asked to experiment with SQL queries within the ArcView GIS program. My problem is quite simple indeed and only refers to the SQL query: There is a table with quite a lot of columns. But only two of them are really important for my query: One field is a date field and the other one is a group name. My aim is to create a query that only selects the item with the most recent date. That is simple and can be handled by max(date). But only the most recent item from each group shall be given as a result of my query. That's also fine. With the query select groupname,max(date) from databasename Group By groupname I got what I wanted and was happy. BUT: As soon as I told the database to read out more fields it no longer worked to get the most recent item from the particular groups. Instead there were many items having the same group which I wanted to supress with max(date) My query was in the form of select groupname,field1,fieldn,max(date) from databasename Group By groupname, field1,fieldn Has anyone an idea how to overcome this problem? Thanks a lot in advance, Fabian Groene ___ 1.000.000 DM gewinnen - kostenlos tippen - http://millionenklick.web.de [EMAIL PROTECTED], 8MB Speicher, Verschluesselung - http://freemail.web.de - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: sql query problem
On Thursday 16 August 2001 10:52, Fabian Groene wrote: (snip) My problem is quite simple indeed and only refers to the SQL query: There is a table with quite a lot of columns. But only two of them are really important for my query: One field is a date field and the other one is a group name. My aim is to create a query that only selects the item with the most recent date. That is simple and can be handled by max(date). But only the most recent item from each group shall be given as a result of my query. That's also fine. If I understand you correctly you have a table somewhat like this: +-++---+ | item| gdate | gname | +-++---+ | this| 2001-10-01 | ABC | | that| 2001-01-01 | ABC | | the | 2000-09-01 | Hello | | other | 2000-06-01 | Hello | | no idea | 2000-10-10 | Hello | +-++---+ (but probably more complex). For each group with in the column 'gname' you want to extract the item (or what other data you have) with the most recent date. So your desired result would be: +-++---+ | item| gdate | gname | +-++---+ | this| 2001-10-01 | ABC | | no idea | 2000-10-10 | Hello | +-++---+ (Or am I missing something?) With the query select groupname,max(date) from databasename Group By groupname I got what I wanted and was happy. For the above example the query and result set looks like this: mysql select gname, max(gdate) from groups group by gname; +---++ | gname | max(gdate) | +---++ | ABC | 2001-10-01 | | Hello | 2000-10-10 | +---++ Which, I agree, _looks_ right. BUT: As soon as I told the database to read out more fields it no longer worked to get the most recent item from the particular groups. Instead there were many items having the same group which I wanted to supress with max(date) My query was in the form of select groupname,field1,fieldn,max(date) from databasename Group By groupname, field1,fieldn So you ended up with something like this? mysql select gname, max(gdate), item, gdate from groups group by gname, item, gdate; +---++-++ | gname | max(gdate) | item| gdate | +---++-++ | ABC | 2001-01-01 | that| 2001-01-01 | | ABC | 2001-10-01 | this| 2001-10-01 | | Hello | 2000-10-10 | no idea | 2000-10-10 | | Hello | 2000-06-01 | other | 2000-06-01 | | Hello | 2000-09-01 | the | 2000-09-01 | +---++-++ Has anyone an idea how to overcome this problem? Yes and no. An obvious (but misleading solution) would be this: mysql select gname, max(gdate), item, gdate from groups group by gname; +---++--++ | gname | max(gdate) | item | gdate | +---++--++ | ABC | 2001-10-01 | this | 2001-10-01 | | Hello | 2000-10-10 | the | 2000-09-01 | +---++--++ (not sure whether that's valid SQL; applications like Oracle or PostgreSQL certainly would't accept the statement as it is). Looks almost right, but for the group Hello we have completely the wrong item and date :-( Unfortunately I don't think what you want to do can be done in MySQL. It's something I've run into once or twice and haven't been able to resolve. Thus far I've coded round it on the application side. Ideas anyone? The usual solution would be a subselect a la: select gname, item, gdate from groups where gdate in (select max(gdate) from groups group by gname) Alas no subselects yet in MySQL (see: http://www.mysql.com/doc/M/i/Missing_Sub-selects.html ) HTH in some way anyway Ian Barwick -- Ian Barwick - Developer - [EMAIL PROTECTED] akademie.de asp GmbH - http://www.akademie.de To query tables in a MySQL database is more fun than eating spam - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: SQL query problem
On Fri, 22 Jun 2001, Thomas J Keller wrote: select zip, city, county from zipcodes where zip between 68400 and 68500; here is a portion of the garbled output: |68442 | STELLA | RICHARDSON |43 | STERLING | JOHNSON |444 | STRANG | FILLMORE |5 | SWANTON | SALINE +---+--+-+ Not too sure what could be wrong, but I did something like this: mysql select * from country where contid between 10 and 20; ++--++ | id | country | contid | ++--++ | 9 | Benin| 10 | | 10 | Bermuda | 11 | | 11 | Birmania | 12 | | 12 | Bolivia | 13 | | 13 | Botswana | 14 | | 14 | Bulgaria | 15 | | 15 | Burkina faso | 16 | | 16 | Burundi | 17 | | 17 | Buthan | 18 | | 18 | Cambogia | 19 | | 19 | Camerun | 20 | ++--++ 11 rows in set (0.00 sec) It works! My table is: mysql desc country; +-+-+--+-+-++-+ | Field | Type| Null | Key | Default | Extra | Privileges | +-+-+--+-+-++-+ | id | int(5) | | PRI | NULL| auto_increment | select,insert,update,references | | country | varchar(35) | | MUL | || select,insert,update,references | | contid | int(5) | | UNI | 0 || select,insert,update,references | +-+-+--+-+-++-+ Similar to yours. Does your table hold any data less that 65000? Try select zip, city, county from zipcodes where zip=68400 and zip= 68500; Regards Adrian - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
SQL query problem
I am using two versions of MySQL, on two different platforms, and having the same problem on both. One very odd aspect of this problem is that it behaves precisely the same way on both platforms, down to which records are garbled onscreen and how they are garbled. Anyone with any ideas? Thanks in advance Platforms: RedHat Linux 6.1 MySQL Ver. 3.23.28gamma (locally compiled) FreeBSD 3.4-STABLE MySQL Ver. 3.22.32 Problem: when I use the following query, I get garbled data in the MySQL command line client: select zip, city, county from zipcodes where zip between 68400 and 68500; here is a portion of the garbled output: |68442 | STELLA | RICHARDSON |43 | STERLING | JOHNSON |444 | STRANG | FILLMORE |5 | SWANTON | SALINE || SYRACUSE | OTOE |7 | TABLE ROCK | PAWNEE || TALMAGE | OTOE |50 | TECUMSEH | JOHNSON || ONG | CLAY |3 | TOBIAS | SALINE || UNADILLA | OTOE || UNION| CASS |6 | UTICA| SEWARD |68457 | VERDON | RICHARDSON || VIRGINIA | GAGE || WACO | YORK |8461 | WALTON | LANCASTER |8462 | WAVERLY | LANCASTER || WEEPING WATER| CASS |4 | WESTERN | SALINE |5 | WILBER | SALINE || WYMORE | GAGE || YORK | YORK +---+--+-+ BUT, if I use: select zip, city, county from zipcodes where zip = 68465; for example I get: |68465 | WILBER | SALINE This holds for any specific zipcode in the database. There is one range, 68500 through 58600 which display correctly. Oddly enough, that is the range for the city I am in. The zipcodes database looks like this: mysql desc zipcodes; +---++--+-+-+---+-+ | Field | Type | Null | Key | Default | Extra | Privileges | +---++--+-+-+---+-+ | zip | int(11)| | PRI | 0 | | select,insert,update,references | | latitude | float(7,4) | YES | | NULL| | select,insert,update,references | | longitude | float(8,4) | YES | | NULL| | select,insert,update,references | | city | text | YES | | NULL| | select,insert,update,references | | state | text | YES | | NULL| | select,insert,update,references | | county| text | YES | | NULL| | select,insert,update,references | +---++--+-+-+---+-+ 6 rows in set (0.00 sec) This is a commercial database product named ZipPLUS. I also tried this: mysql check table zipcodes; ++---+--+--+ | Table | Op| Msg_type | Msg_text | ++---+--+--+ | build.zipcodes | check | status | OK | ++---+--+--+ 1 row in set (0.91 sec) - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
SQL query problem with mysql.
hi, i'm writing a book (wrox publishers) which uses mysql for the sample database. i seem to have encountered a problem with an SQL query. its a simple voting application, with a candidate table, and a vote table: create table candidate ( candidatenumber integer not null auto_increment, firstname varchar(32) not null, lastname varchar(32) not null, politicalparty varchar(32) not null, primary key(candidatenumber)); create table votes ( votenumber integer not null auto_increment, candidatenumber integer, countynumber integer, primary key(votenumber), foreign key(candidatenumber) references candidate, foreign key(countynumber) references county); i want to do a query that shows firstname, lastname, the number of votes for that guy, and the total number of votes cast as illustrated: George, Bush, 2, 10 Al, Gore, 2, 10 Pat, Buchannan, 1, 10 Ralph, Nader, 5, 10 for example ralph nader received 5 votes out of a total of 10 cast. Al gore received 2 votes out of 10 ... you get the idea. here is my query: SELECT Candidate.FIRSTNAME, Candidate.LASTNAME, count(Votes.VoteNumber) , count(select * from Votes) FROM Candidate LEFT OUTER JOIN Votes ON Candidate.CANDIDATENUMBER = Votes.CANDIDATENUMBER GROUP BY Candidate.FIRSTNAME, Candidate.LASTNAME everything works except for the nasty count(select (*) from votes) which seems to work on other db's. if i take it away then it works fine. any ideas on how i could obtain a count of the number of votes cast? thank you for your consideration. Larry Kim [EMAIL PROTECTED] [EMAIL PROTECTED] - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
RE: SQL query problem with mysql.
I would make the select statement look like this SELECT Candidate.FIRSTNAME, Candidate.LASTNAME, count(Votes.VoteNumber) , count(select votenumber from Votes) FROM Candidate LEFT OUTER JOIN Votes ON Candidate.CANDIDATENUMBER = Votes.CANDIDATENUMBER GROUP BY Candidate.FIRSTNAME, Candidate.LASTNAME By doing this you are using less resources the SQL server. Usually whenever you do any select statement the sql engine will go retrieve all of the rows you specify, even in a count. This will cause the SQL enginge to get every row in this table. I also remember hearing someone mention that with MySQL it is generally not a good idea to do a query with an (*) in it because it could produce speratic data. So by doing a count on a particular column this would alleviate that problem. Aaron Weiker Programmer CISP - Changing Internet Speed Performance Phone: 419.724.5351 [EMAIL PROTECTED] Pager: 419.218.0013 http://www.cisp.cc Cell:419.304.0323 web search: http://www.allthesites.com -Original Message- From: Larry Kim [mailto:[EMAIL PROTECTED]] Sent: Monday, March 05, 2001 4:55 AM To: [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: SQL query problem with mysql. hi, i'm writing a book (wrox publishers) which uses mysql for the sample database. i seem to have encountered a problem with an SQL query. its a simple voting application, with a candidate table, and a vote table: create table candidate ( candidatenumber integer not null auto_increment, firstname varchar(32) not null, lastname varchar(32) not null, politicalparty varchar(32) not null, primary key(candidatenumber)); create table votes ( votenumber integer not null auto_increment, candidatenumber integer, countynumber integer, primary key(votenumber), foreign key(candidatenumber) references candidate, foreign key(countynumber) references county); i want to do a query that shows firstname, lastname, the number of votes for that guy, and the total number of votes cast as illustrated: George, Bush, 2, 10 Al, Gore, 2, 10 Pat, Buchannan, 1, 10 Ralph, Nader, 5, 10 for example ralph nader received 5 votes out of a total of 10 cast. Al gore received 2 votes out of 10 ... you get the idea. here is my query: SELECT Candidate.FIRSTNAME, Candidate.LASTNAME, count(Votes.VoteNumber) , count(select * from Votes) FROM Candidate LEFT OUTER JOIN Votes ON Candidate.CANDIDATENUMBER = Votes.CANDIDATENUMBER GROUP BY Candidate.FIRSTNAME, Candidate.LASTNAME everything works except for the nasty count(select (*) from votes) which seems to work on other db's. if i take it away then it works fine. any ideas on how i could obtain a count of the number of votes cast? thank you for your consideration. Larry Kim [EMAIL PROTECTED] [EMAIL PROTECTED] - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: SQL query problem with mysql.
I think you really need another couple tables, even though your just writing a sample. You probably need a table named 'election' and one named 'electionparticipants' Your election table would contain things like the date of the election, the total number of votes cast, etc. The electionparticipants table would be a simple join table between candidate and election. Without those two tables, you're going to have some issues trying to do what you want. - Original Message - From: "Larry Kim" [EMAIL PROTECTED] To: [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Monday, March 05, 2001 3:54 AM Subject: SQL query problem with mysql. hi, i'm writing a book (wrox publishers) which uses mysql for the sample database. i seem to have encountered a problem with an SQL query. its a simple voting application, with a candidate table, and a vote table: create table candidate ( candidatenumber integer not null auto_increment, firstname varchar(32) not null, lastname varchar(32) not null, politicalparty varchar(32) not null, primary key(candidatenumber)); create table votes ( votenumber integer not null auto_increment, candidatenumber integer, countynumber integer, primary key(votenumber), foreign key(candidatenumber) references candidate, foreign key(countynumber) references county); i want to do a query that shows firstname, lastname, the number of votes for that guy, and the total number of votes cast as illustrated: George, Bush, 2, 10 Al, Gore, 2, 10 Pat, Buchannan, 1, 10 Ralph, Nader, 5, 10 for example ralph nader received 5 votes out of a total of 10 cast. Al gore received 2 votes out of 10 ... you get the idea. here is my query: SELECT Candidate.FIRSTNAME, Candidate.LASTNAME, count(Votes.VoteNumber) , count(select * from Votes) FROM Candidate LEFT OUTER JOIN Votes ON Candidate.CANDIDATENUMBER = Votes.CANDIDATENUMBER GROUP BY Candidate.FIRSTNAME, Candidate.LASTNAME everything works except for the nasty count(select (*) from votes) which seems to work on other db's. if i take it away then it works fine. any ideas on how i could obtain a count of the number of votes cast? thank you for your consideration. Larry Kim [EMAIL PROTECTED] [EMAIL PROTECTED] - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: SQL query problem with mysql.
hi, i'm writing a book (wrox publishers) which uses mysql for the sample database. i seem to have encountered a problem with an SQL query. its a simple voting application, with a candidate table, and a vote table: create table candidate ( candidatenumber integer not null auto_increment, firstname varchar(32) not null, lastname varchar(32) not null, politicalparty varchar(32) not null, primary key(candidatenumber)); create table votes ( votenumber integer not null auto_increment, candidatenumber integer, countynumber integer, primary key(votenumber), foreign key(candidatenumber) references candidate, foreign key(countynumber) references county); i want to do a query that shows firstname, lastname, the number of votes for that guy, and the total number of votes cast as illustrated: George, Bush, 2, 10 Al, Gore, 2, 10 Pat, Buchannan, 1, 10 Ralph, Nader, 5, 10 for example ralph nader received 5 votes out of a total of 10 cast. Al gore received 2 votes out of 10 ... you get the idea. here is my query: SELECT Candidate.FIRSTNAME, Candidate.LASTNAME, count(Votes.VoteNumber) , count(select * from Votes) FROM Candidate LEFT OUTER JOIN Votes ON Candidate.CANDIDATENUMBER = Votes.CANDIDATENUMBER GROUP BY Candidate.FIRSTNAME, Candidate.LASTNAME everything works except for the nasty count(select (*) from votes) which seems to work on other db's. if i take it away then it works fine. any ideas on how i could obtain a count of the number of votes cast? thank you for your consideration. Larry Kim [EMAIL PROTECTED] [EMAIL PROTECTED] Sir, MySQL doesn't (yet) support subqueries. Generally, you get around this by using TEMPORARY tables. The following, in slightly different form, ran successfully on the MS Titanic (aka my Wintel box). CREATE TEMPORARY TABLE counts SELECT Candidate.FIRSTNAME, Candidate.LASTNAME, count(*) FROM Candidate LEFT JOIN Votes ON Candidate.CANDIDATENUMBER = Votes.CANDIDATENUMBER GROUP BY Candidate.FIRSTNAME, Candidate.LASTNAME; CREATE TEMPORARY TABLE total_votes SELECT Count(*) AS total_votes FROM votes; SELECT * FROM counts, total_votes; You can also use INSERT INTO counts SELECT "Total", Count(*) FROM votes; SELECT * FROM counts; in place of the last two statements, which will give you the same data in a different format. Your readers may find the second solution easier to understand. The TEMPORARY tables are automatically removed when the connection ends. Note that the FOREIGN KEY clause in your CREATE TABLE statement has no effect in MySQL. It is only there for compatibility with other RDBMSs. In order to maximize speed, MySQL provides no relational integrity constraints other than those applied to primary keys. Foreign keys are not enforced. It is possible that before your book goes to the printer, MySQL will have added subqueries, and one developer or another will have created code that makes it possible to add table types that support integrity constraints. These things are all in the works from various sources. Bob Hall Know thyself? Absurd direction! Bubbles bear no introspection. -Khushhal Khan Khatak - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
SQL query problem
Okay, here's one for the guru's out there :) I have a list of entries with unique id numbers X, and a set of sort methods (S1 ... Sy). Now, if I want to get an entry at position P (0...z) in the list of entries ordered by method S1 then I'd make the following query: SELECT X FROM table WHERE ORDER BY S1 LIMIT P,1 But now I want the inverse - given an id X and a sort method, I want the position. something like: SELECT POSITION(X) FROM table WHERE . ORDER BY S1 Is there a way to do this? -Sander - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: SQL query problem
On Tue, Jan 23, 2001 at 05:39:47PM +0100, Sander Pilon wrote: Okay, here's one for the guru's out there :) I have a list of entries with unique id numbers X, and a set of sort methods (S1 ... Sy). Now, if I want to get an entry at position P (0...z) in the list of entries ordered by method S1 then I'd make the following query: SELECT X FROM table WHERE ORDER BY S1 LIMIT P,1 But now I want the inverse - given an id X and a sort method, I want the position. something like: SELECT POSITION(X) FROM table WHERE . ORDER BY S1 Is there a way to do this? You could try something like.. SELECT COUNT(X) FROM table WHERE AND X (yourX) ORDER BY S1 where X is the name of the field (literally), and yourX is the value you're interested in. After that, just add 1. NOTE: This does not guarantee that yourX actually exists in the table; if it doesn't, this will happily return the position yourX WOULD HAVE BEEN at, had it existed. To find out if it exists, you'll have to do a separate query. G'luck, Peter -- The rest of this sentence is written in Thailand, on - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
