Re: [HACKERS] Does Type Have = Operator?

2016-05-17 Thread David E. Wheeler
Sorry for the pgTAP off-topicness here, hackers. Please feel free to ignore.

On May 17, 2016, at 8:10 AM, Jim Nasby  wrote:

> Speaking specifically to is(), what I'd find most useful is if it at least 
> hinted that there might be some type shenanigans going on, because I've run 
> across something like your example more than once and it always takes a lot 
> to finally figure out WTF is going on.

Agreed. Same for the relation testing functions. Maybe some additional 
diagnostics could be added in the event of failure.

> I think it'd also be useful to be able to specify an equality operator to 
> is(), though that means not using IS DISTINCT.

You can use cmp_ok().

  http://pgxn.org/dist/pgtap/doc/pgtap.html#cmp_ok.

> Something else to keep in mind here is that is() is defined as is(anyelement, 
> anyelement, text), which means you've lost your original type information 
> when you use it. I don't think you could actually do anything useful here 
> because of that.

pg_typeof() will give it to you.

Best,

David



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Re: [HACKERS] Does Type Have = Operator?

2016-05-17 Thread David E. Wheeler
On May 17, 2016, at 7:58 AM, Jim Nasby  wrote:

> Probably in an attempt to bypass parse overhead on ingestion.
> 
> Possibly because JSONB silently eats duplicated keys while JSON doesn't 
> (though in that case even casting to JSONB is probably not what you want).

It’s also when you’d want text equivalent semantics.

Best,

David



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Re: [HACKERS] Does Type Have = Operator?

2016-05-17 Thread Jim Nasby

On 5/11/16 7:05 PM, David E. Wheeler wrote:

On May 11, 2016, at 10:34 AM, Kevin Grittner  wrote:


I'm not clear enough on your intended usage to know whether these
operators are a good fit, but they are sitting there waiting to be
used if they do fit.


Huh. I haven’t had any problems with IS DISTINCT FROM for rows, except for the 
situation in which a failure is thrown because the types vary, say between TEXT 
and CITEXT. That can drive the tester crazy, since it says something like:

Results differ beginning at row 3:
have: (44,Anna)
want: (44,Anna)

But overall I think that’s okay; the tester really does want to make sure the 
type is correct.


Speaking specifically to is(), what I'd find most useful is if it at 
least hinted that there might be some type shenanigans going on, because 
I've run across something like your example more than once and it always 
takes a lot to finally figure out WTF is going on.


I think it'd also be useful to be able to specify an equality operator 
to is(), though that means not using IS DISTINCT.


Something else to keep in mind here is that is() is defined as 
is(anyelement, anyelement, text), which means you've lost your original 
type information when you use it. I don't think you could actually do 
anything useful here because of that.

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Re: [HACKERS] Does Type Have = Operator?

2016-05-17 Thread Jim Nasby

On 5/12/16 4:25 PM, David E. Wheeler wrote:

On May 12, 2016, at 12:02 PM, Tom Lane  wrote:


Andrew mentions in the extension you pointed to that providing a default
comparison operator would enable people to do UNION, DISTINCT, etc on JSON
columns without thinking about it.  I'm not convinced that "without
thinking about it" is a good thing here.  But if we were going to enable
that, I'd feel better about making it default to jsonb semantics ...


If you want the JSONB semantics, why wouldn’t you use JSONB instead of JSON?


Probably in an attempt to bypass parse overhead on ingestion.

Possibly because JSONB silently eats duplicated keys while JSON doesn't 
(though in that case even casting to JSONB is probably not what you want).

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Re: [HACKERS] Does Type Have = Operator?

2016-05-12 Thread Andrew Dunstan



On 05/12/2016 03:02 PM, Tom Lane wrote:

"David E. Wheeler"  writes:

Some might argue that it ought to compare JSON objects, effectively be the 
equivalent of ::jsonb = ::jsonb, rather than ::text = ::text. But as Andrew 
points out to me offlist, “if that's what they want why aren't they using 
jsonb in the first place?�
So I think that, up to the introduction of JSONB, it was important not to side 
one way or the other and put a JSON = operator in core. But now what we have 
JSONB, perhaps it makes sense to finally take sides and intoduce JSON = that 
does plain text comparison. Thoughts?

Meh.  Right now, if you want to compare values of type JSON, you have to
either cast them to text or to jsonb, and that effectively declares which
comparison semantics you want.  I'm not sure that prejudging that is a
good thing for us to do, especially when the argument that text semantics
are what you would probably want is so weak.

Andrew mentions in the extension you pointed to that providing a default
comparison operator would enable people to do UNION, DISTINCT, etc on JSON
columns without thinking about it.  I'm not convinced that "without
thinking about it" is a good thing here.  But if we were going to enable
that, I'd feel better about making it default to jsonb semantics ...




I think you've been a little liberal with quoting the docs ;-) The 
reason I made it an extension is precisely because it's not 
unambiguously clear what json equality should mean.


cheers

andrew


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Re: [HACKERS] Does Type Have = Operator?

2016-05-12 Thread David E. Wheeler
On May 12, 2016, at 12:02 PM, Tom Lane  wrote:

> Andrew mentions in the extension you pointed to that providing a default
> comparison operator would enable people to do UNION, DISTINCT, etc on JSON
> columns without thinking about it.  I'm not convinced that "without
> thinking about it" is a good thing here.  But if we were going to enable
> that, I'd feel better about making it default to jsonb semantics ...

If you want the JSONB semantics, why wouldn’t you use JSONB instead of JSON?

Best,

David



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Re: [HACKERS] Does Type Have = Operator?

2016-05-12 Thread Tom Lane
"David E. Wheeler"  writes:
> Some might argue that it ought to compare JSON objects, effectively be the 
> equivalent of ::jsonb = ::jsonb, rather than ::text = ::text. But as Andrew 
> points out to me offlist, “if that's what they want why aren't they using 
> jsonb in the first place?”

> So I think that, up to the introduction of JSONB, it was important not to 
> side one way or the other and put a JSON = operator in core. But now what we 
> have JSONB, perhaps it makes sense to finally take sides and intoduce JSON = 
> that does plain text comparison. Thoughts?

Meh.  Right now, if you want to compare values of type JSON, you have to
either cast them to text or to jsonb, and that effectively declares which
comparison semantics you want.  I'm not sure that prejudging that is a
good thing for us to do, especially when the argument that text semantics
are what you would probably want is so weak.

Andrew mentions in the extension you pointed to that providing a default
comparison operator would enable people to do UNION, DISTINCT, etc on JSON
columns without thinking about it.  I'm not convinced that "without
thinking about it" is a good thing here.  But if we were going to enable
that, I'd feel better about making it default to jsonb semantics ...

regards, tom lane


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Re: [HACKERS] Does Type Have = Operator?

2016-05-12 Thread David E. Wheeler
On May 12, 2016, at 11:19 AM, Fabrízio de Royes Mello  
wrote:

> Yeah.. it's ugly but you can do something like that:

I could, but I won’t, since this is pgTAP and users of the library might have 
defined their own json operators. 

Andrew Dunstan has done the yeoman’s work of creating such operators, BTW:

  https://bitbucket.org/adunstan/jsoncmp

Some might argue that it ought to compare JSON objects, effectively be the 
equivalent of ::jsonb = ::jsonb, rather than ::text = ::text. But as Andrew 
points out to me offlist, “if that's what they want why aren't they using jsonb 
in the first place?”

So I think that, up to the introduction of JSONB, it was important not to side 
one way or the other and put a JSON = operator in core. But now what we have 
JSONB, perhaps it makes sense to finally take sides and intoduce JSON = that 
does plain text comparison. Thoughts?

Best,

David

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Re: [HACKERS] Does Type Have = Operator?

2016-05-12 Thread Fabrízio de Royes Mello
On Wed, May 11, 2016 at 9:09 PM, David E. Wheeler 
wrote:
>
> On May 11, 2016, at 11:01 AM, Fabrízio de Royes Mello <
fabriziome...@gmail.com> wrote:
>
> > I know... but you can do that just in case the current behaviour fail
by cathing it with "begin...exception...", so you'll minimize the looking
for process on catalog.
>
> Yeah, I guess. Honestly 90% of this issue would go away for me if there
was a `json = json` operator. I know there are a couple different ways to
interpret JSON equality, though.
>

Yeah.. it's ugly but you can do something like that:

CREATE OR REPLACE FUNCTION json_equals_to_json(first JSON, second JSON)
RETURNS boolean AS
$$
BEGIN
   RETURN first::TEXT IS NOT DISTINCT FROM second::TEXT;
END
$$
LANGUAGE plpgsql IMMUTABLE;

CREATE OPERATOR = (
   LEFTARG = json,
   RIGHTARG = json,
   PROCEDURE = json_equals_to_json
);


Regards,

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Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread David E. Wheeler
On May 11, 2016, at 11:01 AM, Fabrízio de Royes Mello  
wrote:

> I know... but you can do that just in case the current behaviour fail by 
> cathing it with "begin...exception...", so you'll minimize the looking for 
> process on catalog.

Yeah, I guess. Honestly 90% of this issue would go away for me if there was a 
`json = json` operator. I know there are a couple different ways to interpret 
JSON equality, though.

David



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Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread David E. Wheeler
On May 11, 2016, at 10:34 AM, Kevin Grittner  wrote:

> I'm not clear enough on your intended usage to know whether these
> operators are a good fit, but they are sitting there waiting to be
> used if they do fit.

Huh. I haven’t had any problems with IS DISTINCT FROM for rows, except for the 
situation in which a failure is thrown because the types vary, say between TEXT 
and CITEXT. That can drive the tester crazy, since it says something like:

Results differ beginning at row 3:
have: (44,Anna)
want: (44,Anna)

But overall I think that’s okay; the tester really does want to make sure the 
type is correct.

Thanks,

David




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Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread Fabrízio de Royes Mello
On Wed, May 11, 2016 at 2:07 AM, David E. Wheeler 
wrote:
>
> On May 10, 2016, at 5:56 PM, Fabrízio de Royes Mello <
fabriziome...@gmail.com> wrote:
>
> > Searching for the operator in pg_operator catalog isn't enought?
>
> Seems like overkill, but will do if there’s nothing else.
>

I know... but you can do that just in case the current behaviour fail by
cathing it with "begin...exception...", so you'll minimize the looking for
process on catalog.

Regards,

--
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Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread Kevin Grittner
On Wed, May 11, 2016 at 12:23 PM, David E. Wheeler
 wrote:

> Oh, well crap. Maybe I’d be better off just comparing the plain
> text of the expressions as Tom suggested.

At the other extreme are the row comparison operators that only
consider values equal if they have the same storage value.  See the
last paragraph of:

http://www.postgresql.org/docs/9.5/static/functions-comparisons.html#COMPOSITE-TYPE-COMPARISON

| To support matching of rows which include elements without a
| default B-tree operator class, the following operators are
| defined for composite type comparison: *=, *<>, *<, *<=, *>, and
| *>=. These operators compare the internal binary representation
| of the two rows. Two rows might have a different binary
| representation even though comparisons of the two rows with the
| equality operator is true. The ordering of rows under these
| comparison operators is deterministic but not otherwise
| meaningful. These operators are used internally for materialized
| views and might be useful for other specialized purposes such as
| replication but are not intended to be generally useful for
| writing queries.

I'm not clear enough on your intended usage to know whether these
operators are a good fit, but they are sitting there waiting to be
used if they do fit.

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Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread David E. Wheeler
On May 11, 2016, at 10:19 AM, Kevin Grittner  wrote:

> As long as you don't assume too much about *what* is equal.
> 
> test=# select '(1,1)(2,2)'::box = '(-4.5,1000)(-2.5,1000.5)'::box;
> ?column?
> --
> t
> (1 row)

Oh, well crap. Maybe I’d be better off just comparing the plain text of the 
expressions as Tom suggested.

David



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Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread Kevin Grittner
On Wed, May 11, 2016 at 12:01 PM, David G. Johnston
 wrote:

> Its hard to imagine defining "=" to mean something different in logic,
> though, without intentionally trying to be cryptic.

As long as you don't assume too much about *what* is equal.

test=# select '(1,1)(2,2)'::box = '(-4.5,1000)(-2.5,1000.5)'::box;
 ?column?
--
 t
(1 row)

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Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread David G. Johnston
On Wed, May 11, 2016 at 9:54 AM, Robert Haas  wrote:

> On Tue, May 10, 2016 at 9:16 PM, David G. Johnston
>  wrote:
> > Brute force: you'd have to query pg_amop and note the absence of a row
> with
> > a btree (maybe hash too...) family strategy 3 (1 for hash) [equality]
> where
> > the left and right types are the same and match the type in question.
>
> The core system uses this kind of thing to find equality operators in
> a number of cases.
>
> We often assume that the operator which implements equality for the
> type's default btree operator class is the canonical one for some
> purpose.  Ditto for the default hash operator class.
>

​Yeah, the user-facing documentation covers it pretty deeply if not in one
central location.

But apparently the core system also uses the fact that "=", if present, is
an equality operator and, less so, that no other operator is expected​

​to be used for equality.

I suspect that such an expectation is not enforced though - e.g., someone
could define "==" to mean equality ​if they so choose (the lesser
property).  Its hard to imagine defining "=" to mean something different in
logic, though, without intentionally trying to be cryptic.

David J.


Re: [HACKERS] Does Type Have = Operator?

2016-05-11 Thread Robert Haas
On Tue, May 10, 2016 at 9:16 PM, David G. Johnston
 wrote:
> Brute force: you'd have to query pg_amop and note the absence of a row with
> a btree (maybe hash too...) family strategy 3 (1 for hash) [equality] where
> the left and right types are the same and match the type in question.

The core system uses this kind of thing to find equality operators in
a number of cases.

We often assume that the operator which implements equality for the
type's default btree operator class is the canonical one for some
purpose.  Ditto for the default hash operator class.

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Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread David E. Wheeler
On May 10, 2016, at 5:56 PM, Fabrízio de Royes Mello  
wrote:

> Searching for the operator in pg_operator catalog isn't enought?

Seems like overkill, but will do if there’s nothing else.

Best,

David



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Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread David E. Wheeler
On May 10, 2016, at 6:14 PM, Tom Lane  wrote:

> Given that you're coercing both one input value and the result to text,
> I don't understand why you don't just compare the text representations.

Because sometimes the text is not equal when the casted text is. Consider

'foo'::citext = 'FOO':citext

> I'm also not very clear on what you mean by "comparing column defaults".
> A column default is an expression (in the general case anyway), not just
> a value of the type.

Yeah, the pgTAP column_default_is() function takes a string representation of 
an expression.

> Maybe if you'd shown us the is() function, as well as a typical usage
> of _def_is(), this would be less opaque.

Here’s is():

CREATE OR REPLACE FUNCTION is (anyelement, anyelement, text)
RETURNS TEXT AS $$
DECLARE
result BOOLEAN;
output TEXT;
BEGIN
-- Would prefer $1 IS NOT DISTINCT FROM, but that's not supported by 
8.1.
result := NOT $1 IS DISTINCT FROM $2;
output := ok( result, $3 );
RETURN output || CASE result WHEN TRUE THEN '' ELSE E'\n' || diag(
   'have: ' || CASE WHEN $1 IS NULL THEN 'NULL' ELSE 
$1::text END ||
E'\nwant: ' || CASE WHEN $2 IS NULL THEN 'NULL' ELSE 
$2::text END
) END;
END;
$$ LANGUAGE plpgsql;

_def_is() is called by another function, which effectively is:

CREATE OR REPLACE FUNCTION _cdi ( NAME, NAME, NAME, anyelement, TEXT )
RETURNS TEXT AS $$
BEGIN

RETURN _def_is(
pg_catalog.pg_get_expr(d.adbin, d.adrelid),
pg_catalog.format_type(a.atttypid, a.atttypmod),
$4, $5
)
  FROM pg_catalog.pg_namespace n, pg_catalog.pg_class c, 
pg_catalog.pg_attribute a,
   pg_catalog.pg_attrdef d
 WHERE n.oid = c.relnamespace
   AND c.oid = a.attrelid
   AND a.atthasdef
   AND a.attrelid = d.adrelid
   AND a.attnum = d.adnum
   AND n.nspname = $1
   AND c.relname = $2
   AND a.attnum > 0
   AND NOT a.attisdropped
   AND a.attname = $3;
END;
$$ LANGUAGE plpgsql;

That function si called like this:

_cdi( :schema, :table, :column, :default, :description );

Best,

David





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Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread Peter Eisentraut

On 5/10/16 9:16 PM, David G. Johnston wrote:

Brute force: you'd have to query pg_amop and note the absence of a row
with a btree (maybe hash too...) family strategy 3 (1 for hash)
[equality] where the left and right types are the same and match the
type in question.


While these are good thoughts, the implementation of DISTINCT actually 
looks for an operator that is literally named "=".


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Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread Euler Taveira
On 10-05-2016 22:28, David G. Johnston wrote:
> Technically "is not distinct from" would be more correct.
> 
Ooops. Fat fingered the statement. Also, forgot to consider null case.

euler=# \pset null 'NULL'
Null display is "NULL".
euler=# select x.a, y.b, x.a IS NOT DISTINCT FROM y.b AS "INDF", x.a =
y.b AS "=" FROM (VALUES (3), (6), (NULL)) AS x (a), (VALUES (3), (6),
(NULL)) AS y (b);
  a   |  b   | INDF |  =
--+--+--+--
3 |3 | t| t
3 |6 | f| f
3 | NULL | f| NULL
6 |3 | f| f
6 |6 | t| t
6 | NULL | f| NULL
 NULL |3 | f| NULL
 NULL |6 | f| NULL
 NULL | NULL | t| NULL
(9 rows)


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Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread David G. Johnston
On Tuesday, May 10, 2016, Euler Taveira  wrote:
>
> Also, IS DISTINCT FROM is an alias for = operator per standard IIRC.
>

Technically "is not distinct from" would be more correct.   Alias implies
exact while in the presence of nulls the two behave differently.

"is distinct from" ~ "<>" which is the canonical form (alias) for "!="

http://www.postgresql.org/docs/9.5/interactive/functions-comparison.html

David J.


Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread Euler Taveira
On 10-05-2016 21:12, David E. Wheeler wrote:
> This makes sense, of course, and I could fix it by comparing text
> values instead of json values when the values are JSON. But of course
> the lack of a = operator is not limited to JSON. So I’m wondering if
> there’s an interface at the SQL level to tell me whether a type has
> an = operator? That way I could always use text values in those
> situations.
> 
There isn't an equality notation at catalogs. You could try "SELECT
oprname FROM pg_operator WHERE oprcode::text ~ 'eq'" but it is too
fragile. You could also try oprname, oprrest or oprjoin but the result
is worse than the former solution. You definitely need a hack.

Also, IS DISTINCT FROM is an alias for = operator per standard IIRC.


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Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread David G. Johnston
On Tuesday, May 10, 2016, David E. Wheeler  wrote:

>
> This makes sense, of course, and I could fix it by comparing text values
> instead of json values when the values are JSON. But of course the lack of
> a = operator is not limited to JSON. So I’m wondering if there’s an
> interface at the SQL level to tell me whether a type has an = operator?
> That way I could always use text values in those situations.
>
>
http://www.postgresql.org/docs/9.5/interactive/catalog-pg-amop.html
http://www.postgresql.org/docs/9.5/interactive/xindex.html

Brute force: you'd have to query pg_amop and note the absence of a row with
a btree (maybe hash too...) family strategy 3 (1 for hash)
[equality] where the left and right types are the same and match the type
in question.

There is likely more to it - though absence is pretty much a given I'd be
concerned about false negatives due to ignoring other factors like
"amoppurpose".

In theory you should be able to trade off convenience for correctness by
calling:

to_regoperator('=(type,type)')

But I've never tried it and it assumes that = is the equality operator and
that its presence is sufficient.  I'm also guessing on the text type name
syntax.

http://www.postgresql.org/docs/9.5/interactive/functions-info.html

This option is a young one from what I remember.

David J.


Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread Tom Lane
"David E. Wheeler"  writes:
> pgTAP has a function that compares two values of a given type, which it uses 
> for comparing column defaults. It looks like this:

> CREATE OR REPLACE FUNCTION _def_is( TEXT, TEXT, anyelement, TEXT )
> RETURNS TEXT AS $$

Given that you're coercing both one input value and the result to text,
I don't understand why you don't just compare the text representations.

I'm also not very clear on what you mean by "comparing column defaults".
A column default is an expression (in the general case anyway), not just
a value of the type.

Maybe if you'd shown us the is() function, as well as a typical usage
of _def_is(), this would be less opaque.

regards, tom lane


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Re: [HACKERS] Does Type Have = Operator?

2016-05-10 Thread Fabrízio de Royes Mello
Em terça-feira, 10 de maio de 2016, David E. Wheeler 
escreveu:

> Hackers,
>
> pgTAP has a function that compares two values of a given type, which it
> uses for comparing column defaults. It looks like this:
>
> CREATE OR REPLACE FUNCTION _def_is( TEXT, TEXT, anyelement, TEXT )
> RETURNS TEXT AS $$
> DECLARE
> thing text;
> BEGIN
> IF $1 ~ '^[^'']+[(]' THEN
> -- It's a functional default.
> RETURN is( $1, $3, $4 );
> END IF;
>
> EXECUTE 'SELECT is('
>  || COALESCE($1, 'NULL' || '::' || $2) || '::' || $2 || ',
> '
>  || COALESCE(quote_literal($3), 'NULL') || '::' || $2 ||
> ', '
>  || COALESCE(quote_literal($4), 'NULL')
> || ')' INTO thing;
> RETURN thing;
> END;
> $$ LANGUAGE plpgsql;
>
> The is() function does an IS DISTINCT FROM to compare the two values
> passed to it. This has been working pretty well for years, but one place it
> doesn’t work is with JSON values. I get:
>
> LINE 1: SELECT NOT $1 IS DISTINCT FROM $2
>   ^
> HINT:  No operator matches the given name and argument type(s). You
> might need to add explicit type casts.
> QUERY:  SELECT NOT $1 IS DISTINCT FROM $2
>
> This makes sense, of course, and I could fix it by comparing text values
> instead of json values when the values are JSON. But of course the lack of
> a = operator is not limited to JSON. So I’m wondering if there’s an
> interface at the SQL level to tell me whether a type has an = operator?
> That way I could always use text values in those situations.
>
>
Searching for the operator in pg_operator catalog isn't enought?

Regards,



-- 
Fabrízio de Royes Mello
Consultoria/Coaching PostgreSQL
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