[PHP-DB] Php mariadb unique field selection for index of query result.

2023-02-07 Thread cds1984.diagnostic.net.au via php-db
Hi,
Quick question.

I may be missing something but for years I've been processing the output of a 
query into a new array using the unique(normally primary key) field in the 
table as the index so I can pull data matches simply further into the script 
without another loop through all the returned data.

Is there an option I'm missing to assign a field as the output array index from 
a PHP based query?

Thanks,

--
Richard Scotford

RE: [PHP-DB] MySQLnd support for ed25519

2021-09-08 Thread Jonathan Aquilina via php-db
Mysql 8 is already the stable version and has been for a while. I for 
development use it on windows and its v8



-Original Message-
From: Ruprecht Helms  
Sent: 08 September 2021 16:02
To: php-db@lists.php.net
Subject: Re: [PHP-DB] MySQLnd support for ed25519

Hi Dimi,

I think mysql 8 is the new version of mysql. I don't know if there a exists a 
stable release or only a beta.
My thoughts are that the last php-version maybe can handle the mentioned 
authentication method or you have to try to compile the handling for the 
mysql-plugin in the php-mysqldriver.

Maybe the question about enhancing the php is relation on the 
Linuxdistribution.  Here I mean an additional rpm if you use Redhat, Fedora, 
Centos, Suse...
or .deb if you use Debian, Ubuntu or such of these.

To mix a tarball with one of these packages I think it is to difficult in this 
case.

Regards,
Ruprecht

Am 08.09.21 um 15:20 schrieb dimi_php:
> Hi Ruprecht,
>
> yes, if a provider not changed the default authentication 
> (mysql_nativ_password) there is nothing customers have to do, because 
> the default authentication on mysql 5.7 and 10.5 is the same (SHA-1 based).
> Mysql changed this starting from version 8, were the default authentication 
> now is the plugin caching_sha2_password.
> Mariadb not changed the default, but recommends to use a safer authentication 
> method like the ed25519-plugin.
>
> I would like to use it, but then i have the problem that PHP (the 
> Mysql nativ driver) cames with an error like "The server requested 
> authentication method unknown to the client".
>
> So i would be glad if this authentication method would be implemented.
>
> Regards,
> Dimi

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[PHP-DB] Getting PDO-OCI to work in PHP 7

2019-05-28 Thread Stokes, John M via php-db
I have made multiple attempts to get PDO-OCI to work in PHP 7. Sometimes it
fails to compile at all, other times appears to compile correctly, but I
can't connect to any Oracle databases. Thus far, this has kept me stuck on
PHP 5.x.

The relevant part of my configure statement is:
./configure \
...
--with-mysqli=/usr/bin/mysql_config \
--with-pdo-mysql=/usr \
--with-pdo-odbc=unixODBC,/usr \
--with-pdo-oci=instantclient,/usr/lib/oracle/18.3/client64/lib/ \
--with-unixODBC=/usr \
...

The latest error is when I run "make":
...snip...
In file included from /root/php-7.2.4/ext/ldap/php_ldap.h:30:0,
 from main/internal_functions.c:50:
/usr/include/oracle/18.3/client64/ldap.h:988:18: error: conflicting types
for ‘ber_scanf’
 LDAPFUNCDECL int ber_scanf ( BerElement *ber, char * fmt, ... );
  ^
In file included from /root/php-7.2.4/ext/ldap/php_ldap.h:27:0,
 from main/internal_functions.c:50:
/usr/include/lber.h:335:1: note: previous declaration of ‘ber_scanf’ was
here
 ber_scanf LDAP_P((
 ^
make: *** [main/internal_functions.lo] Error 1

Can anyone offer me some ideas?
Thanks in advance.

-John

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[PHP-DB] Simple MySQL sample code runs out of memory

2011-10-27 Thread php
Running PHP 5.3.5 on FreeBSD 8.2 connecting to a MySQL 5.1.55
server.

Why does this code (below) run out of memory?  It queries
test_table for all rows, all fields and sorts them by the numeric
'contract' field.  It then iterates through the rows, and tallies
the number of rows per contract.  That's not the end goal of the
processing, but the processing does not require storing multiple
rows in memory (except in the MySQL result buffer).  One row at a
time in memory is all I need.

The schema is not huge:

+--+-+--+-+-+---+
| Field| Type| Null | Key | Default | Extra |
+--+-+--+-+-+---+
| contract | int(11) | YES  | | NULL|   |
| A| int(8) unsigned | NO   | | 0   |   |
| B| datetime| YES  | | NULL|   |
| C| int(8) unsigned | YES  | | 0   |   |
| D| char(8) | YES  | | NULL|   |
| E| char(8) | YES  | | |   |
| F| int(4)  | YES  | | 0   |   |
| G| int(1)  | YES  | | 0   |   |
| H| char(8) | YES  | | 00:00   |   |
| I| varchar(100)| YES  | | XXX |   |
+--+-+--+-+-+---+


?php

require_once( '../include/mysql_funcs.php' );

$db_host = $test_db_host;
$db_user = $test_db_user;
$db_name = $test_db_name;
$db_pwd  = $test_db_pwd;

if (!($db_conn = mysql_connect( $db_host, $db_user, $db_pwd )))
die( Can't connect to MySQL server\n );

if (!mysql_select_db( $db_name, $db_conn ))
die( Can't connect to database $db_name\n );

$qry = select * from test_table order by contract;

if ($result = mysql_query( $qry, $db_conn )) {

$row = mysql_fetch_array( $result );
while ($row) {
$c = $row[ 'contract' ];
$n = 0;
while ($row  ($c == $row[ 'contract' ])) {
$n++;
$row = mysql_fetch_array( $result );
}
echo sprintf( |%13d |%7d |\n, $c, $n );
} // while

} else {

die( mysql_error() . \n );

}

?


The output ends with:
...
|39582 |518 |
|39583 |384 |
|39584 |429 |
|39585 |433 |
|39586 |359 |
PHP Fatal error:  Allowed memory size of 134217728 bytes exhausted (tried to 
allocate 20 bytes) in xx2.php on line 26

Line 26 seems to be the innermost mysql_fetch_array call.

The sum of the right-hand column for all the output produced
prior to running out of memory is 274547.  There are 295287 total
rows in the table.

What can I change to prevent this code from running out of memory
even with an arbitrarily large number of rows returned from the
'select' query?

Thank you for your time!



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Re: [PHP-DB] Simple MySQL sample code runs out of memory

2011-10-27 Thread php
On Thu, Oct 27, 2011 at 09:17:21PM -0500, tamouse mailing lists wrote: 
 
 That said, I think there must be a way to do this in SQL.

Absolutely, there's a way to do this in SQL;

select contract, sum(1) from test_table group by contract


But as I said, simply counting is not the intent of the actual
processing that will be done.

I need to find a method that can iterate through a large number
of records and process each record (in whatever way I choose to
define) without running out of RAM.  I only need to access one
record at a time, so I thought this would be pretty trivial,
and was surprised to find that the routine ran out of memory.

This simple counting exercise is merely a test of the loop
algorithm so that I can do a 'cmp' or 'diff' comparison of the
output of the PHP versus the output of the SQL to verify that in
fact the PHP algorithm is indeed finding and processing each
record (and thus arriving at the same per-contract counts that
the SQL statement does).

I will experiment with your suggestions.

Thank you,

Jim


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Re: [PHP-DB] Simple MySQL sample code runs out of memory

2011-10-27 Thread php
On Thu, Oct 27, 2011 at 09:50:14PM -0500, tamouse mailing lists wrote:
 
 Still, an inner and outer loop don't really seem necessary here, as
 you're spinning through one set of data, there doesn't seem a need to
 run through it that way. A more traditional method is to do something
 like:
 
 $last_contract = '';
 while ($row = $msql_fetch_assoc($results) {
 if ($last_contract == $row['contract]) {
 // do what ever you'd do with the same contract
 } else {
$last_contract = $row['contract'];
// do what ever you'd do with the new contract
 }
 }
 
 assuming you are ordering by contract as in the example select.

Thanks for that suggestion, also.

Something more fundamental is going on.

Here is simpler code which still reproduces the problem.

?php

require_once( '../include/mysql_funcs.php' );

$test_db_host = localhost;
$test_db_user = msm;
$test_db_pwd  = EetGiOj6;
$test_db_name = test_msm;

$db_host = $test_db_host;
$db_user = $test_db_user;
$db_name = $test_db_name;
$db_pwd  = $test_db_pwd;

if (!($db_conn = mysql_connect( $db_host, $db_user, $db_pwd )))
die( Can't connect to MySQL server\n );

if (!mysql_select_db( $db_name, $db_conn ))
die( Can't connect to database $db_name\n );

$qry = select * from test_spot_table order by contract;

if ($result = mysql_query( $qry, $db_conn )) {

$n = 0;
while ($row = mysql_fetch_array( $result )) {
$n++;
} // while
echo $n\n;

} else {

die( mysql_error() . \n );

}

?


I get:

PHP Fatal error:  Allowed memory size of 134217728 bytes exhausted (tried to 
allocate 20 bytes) in xx3.php on line 26

What's up with that?

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Re: [PHP-DB] Simple MySQL sample code runs out of memory

2011-10-27 Thread php
On Thu, Oct 27, 2011 at 10:43:48PM -0500, Karl DeSaulniers wrote:
 Maybe this..
 HTH,
 
 ?php
 ...
 
 $result = mysql_query( $qry, $db_conn ) or  die( mysql_error() . \n );
 
 $num_rows = mysql_numrows($result);
 if(!$result || ($num_rows = 0)){
 echo Error displaying info;
 }
 else if($num_rows  0){
 for($i=0; $i$num_rows; $i++){
$c = mysql_result($result,$i,contract);
 
echo sprintf( |%13d |%7d |\n, $c, $i );
 }
 }
 
 ?
 
 Best,
 Karl

Wow, working code!  Thanks.  I did try it:

?php

require_once( '../include/mysql_funcs.php' );

$test_db_host = localhost;
$test_db_user = msm;
$test_db_pwd  = EetGiOj6;
$test_db_name = test_msm;

$db_host = $test_db_host;
$db_user = $test_db_user;
$db_name = $test_db_name;
$db_pwd  = $test_db_pwd;

if (!($db_conn = mysql_connect( $db_host, $db_user, $db_pwd )))
die( Can't connect to MySQL server\n );

if (!mysql_select_db( $db_name, $db_conn ))
die( Can't connect to database $db_name\n );

$qry = select * from test_spot_table order by contract_seq;

$result = mysql_query( $qry, $db_conn ) or  die( mysql_error() . \n );

$num_rows = mysql_numrows($result);
if(!$result || ($num_rows = 0)){
   echo Error displaying info;
}
else if($num_rows  0){
   for($i=0; $i$num_rows; $i++){
  $c = mysql_result($result,$i,contract);

  echo sprintf( |%13d |%7d |\n, $c, $i );
   }
}

?

But it does the same thing:

PHP Fatal error:  Allowed memory size of 134217728 bytes exhausted (tried to 
allocate 20 bytes) in /usr/local/www/apache22/data/bogus_copy/xx4.php on line 31

Line 31 is:

31$c = mysql_result($result,$i,contract);


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[PHP-DB] Re: WAMP server Problem and Correct way to install PHP and MySQL???

2009-05-04 Thread php news feed

when you click on the wamp icon in your taskbar you will get an popup menu:
by clicking on phpMyAdmin your browser will open with phpMyAdmin. From
there you can check the database and create databases and tables as you go.

If phpmyadmin could not open. : page times out then click on the wamp icon
again, move to Apache, then Service, and then click on Test port 80, then
you should get something like
--
Your port 80 is actually used by :

Server: Apache/2.2.11 (Win32) PHP/5.2.8


Press Enter to exit...
--
if you get an error on port 80 that it is in use, check that IIS is not
running on your pc and if you use skype check that you selected in the
options so that skype doesnt make use of port 80

If you downloaded a new WAMP version, i would suggest that you make one
minor change in the php.ini file.
Put a semi-colon before error_reporting  =  E_ALL so that it looks like
this ;error_reporting  =  E_ALL and remove the colon before
error_reporting = E_ALL  ~E_NOTICE. This is just one of my personal
adjustments to the wamp default php.ini file.

Then for installing Apache. Like Sashikanth Gurram said WAMP is Windows
Apache MySql PHP. So apache gets installed with wamp. The linux version of
wamp is LAMP just for interrest sake.

O yes. almost forgot. The WAMP icon should have a completely white
background, not yellow. if its yellow go and check the PHP Logs, Apache Logs
and MySql Logs to determine which service is not running.

I do hope this help.

Sashikanth Gurram sashi...@vt.edu wrote in message 
news:497a0a60.9000...@vt.edu...

Hello everyone,

I have installed WAMP server on my PC. Then I have installed the MySQL and 
PHP software by downloading them from the site. The PHP programs I have 
written used to work fine but when I tried to connect to the MySQL 
database or create a new database using the PHP programming nothing 
happens in the browser. I do not know what happened. After several 
attempts I finally uninstalled the MySQL and PHP programs and then when I 
tried to connect to the MySQL usin PHP it worked fine I do not know the 
reason for this. Can anyone tell me what the reason is?


Further more I would like to install PHP and MySQL along with a server 
like APACHE. But I do not know where to download the APACHE server from. 
Also When I install PHP and MySQL how do I link PHP and MySQL so that they 
work in tandem.


Would be great if anyone can clear these doubts. I know that these are 
very basic questions but I am a starter.


Thanks,
Sashi

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Re: [PHP-DB] First and Last ID of a table

2007-07-11 Thread tg-php
SELECT MIN(id), MAX(id) FROM mytable

:)

Hope that helps!

-TG

= = = Original message = = =

I have a table where I need to figure out the very first ID and the  
very last ID, so here is what I wrote:

$first_query = SELECT id FROM mytable ORDER BY id LIMIT 1;
$first_result = mysql_query($first_query,$con);
$first_id = mysql_result($first_result,0,'id');

$last_query = SELECT id FROM mytable ORDER BY id DESC LIMIT 1;
$last_result = mysql_query($last_query,$con);
$last_id = mysql_result($last_result,0,'id');

I'm just wondering if there was any way to do this more efficiently,  
like with one query instead of two. Or is this about as simple as I  
can do it?

Thanks.



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Re: [PHP-DB] First and Last ID of a table

2007-07-11 Thread tg-php
Sounds about right... you can also do something like this (syntax should be 
right):

SELECT MIN(id) as minid, MAX(id) as maxid FROM mytable


$array['minid'] and $array['maxid']


Basically it's going to be whatever the heading of that column is.  Using as 
gives it an alias for less ugly headings.

If you did SELECT COUNT(Qty) FROM SomeTable

Then you might get:

$array['Count of Qty'] or something goofy like that.  I forget the exact 
circumstances but there's times you get goofy stuff like that.

If you run the SQL through some DB client (like mysql's command line stuff or I 
use WinSQL Lite in Windows to connect to our MySQL database across the network) 
you can usually see what the heading name is going to end up being, if you 
don't explicitly set it with an AS clause.

AS also works on table names:

SELECT l.LeadID, ld.FirstName FROM Leads as l, LeadData as ld
WHERE l.LeadID = ld.LeadID

(actually a lot of the time you can leave out the as and just do Leads l)

Fun times..

-TG


= = = Original message = = =

[EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]
 SELECT MIN(id), MAX(id) FROM mytable

As an aside, is you are using associative arrays, be sure to use the 
following keys:

$array['MIN(id)'] and $array['MAX(id)']

Just something I figured out recently :)

Matt 

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Re: [PHP-DB] sql statement - complex order by

2007-07-02 Thread tg-php
Try this:

SELECT * FROM productgroup WHERE groupid = $productid
ORDER BY label = 'Cats' DESC, title

The test SQL I did to make sure I understood it was this (against our Users 
table):

select * from users order by first = 'Bob' DESC, first, last

It put all the Bobs first, sorting them by first/last, then put everyone else 
after the Bobs sorted by first/last.

If you don't put DESC on the 'Cats', it looks like it'll put the 'Cats' at the 
bottom of the list.

Also refer to the user comments here:
http://dev.mysql.com/doc/refman/4.1/en/sorting-rows.html

good luck!

-TG

= = = Original message = = =

SELECT * FROM productgroup WHERE groupid = $productid
AND label =  'Cats' ORDER BY title

SELECT * FROM productgroup WHERE groupid = $productid
AND label != 'Cats' ORDER BY label,title

I'd like to find a way to combine these 2 statements. I want to list out 
all the products, ordered by title but listing out all the Cats products 
first. Any way to do that without having separate statements?

Thanks...

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Re: [PHP-DB] Search for whole words in MySQL 3.23

2007-06-13 Thread tg-php
I suck at regex, but looks like 3.23 may actually support it.  And most regex 
implementations have a word boundary code for doing exactly what you're talking 
about.

Referring to this page: http://dev.mysql.com/doc/refman/4.1/en/regexp.html

I found this example.. hopefully it'll help you (and work ok in 3.23):

[[::]], [[::]]

These markers stand for word boundaries. They match the beginning and end of 
words, respectively. A word is a sequence of word characters that is not 
preceded by or followed by word characters. A word character is an alphanumeric 
character in the alnum class or an underscore (_).

mysql SELECT 'a word a' REGEXP '[[::]]word[[::]]';   - 1
mysql SELECT 'a xword a' REGEXP '[[::]]word[[::]]';  - 0


-TG

= = = Original message = = =

Hi all,

I'm setting up a database search on a site, where I will essentially be
BOOLEAN searching about 6 database fields. Unfortunately, the database I'm
using is MySQL version 3.23 (completely out of my control), so I cannot use
IN BOOLEAN MODE to simplify the process on my end. I've been able to put
together a function that does almost everything that I want, but I'm running
into a problem - searching for whole words that may or may not be in the
beginning or end of the database field. For example, syntax like this:

...WHERE `field` LIKE '%searchterm%'...

has the limitation that if the search term is 'car', it will also bring back
'scar', 'cartoon', etc.

While if the syntax is:

...WHERE `field` LIKE '% searchterm %'... (with spaces)

it misses words that are the first or last words of the field, or words that
are at the end of sentences, before commas, etc.

I've looked around and haven't been able to find a way to search only for
complete words within a block of text. Any help?

Thanks in advance,
Zeth


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Re: [PHP-DB] Values in a date field

2007-03-17 Thread tg-php
Assuming you're using MySQL, try MONTH().  As in:

SELECT MONTH(SomeDateField) FROM SomeTable

http://dev.mysql.com/doc/refman/4.1/en/date-and-time-functions.html



If this isn't a database question, but a general PHP question, try this:

// For numeric month without leading zero, use n
echo date(n, strtotime($subscription_begins));

http://us3.php.net/manual/en/function.date.php

-TG

= = = Original message = = =

I have a $subscription_begins variable.  It the date type.  -MM-DD

How may I find out the month value (1 to 12) of this variable?

Ron


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Re: [PHP-DB] SQL Query - Using variable from another SQL Query

2007-02-12 Thread tg-php
Try this as your SQL. It should give you all the results, then you can use PHP 
to sort it all out.

SELECT * FROM egw_cal WHERE cal_category='501' and cal_id in (SELECT cal_id 
FROM egw_cal_dates where cal_start  $tstamp)

-TG



= = = Original message = = =

Hello Everyone

Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.

The query event_time brings back the calendar id for each event that is 
pending in the future.
ie 12, 13, 14, 26  (There could be 100 of them out there)

The second query events needs to meet both reqirements.  
 1 - cal_category='501' 
 2 - cal_id= a number from the event_time query

I think i need to do a loop inside of a loop

Thanks...

Matt 


Here is my code: 

?php

$todays_year = date(Y);

$todays_month = date(m);

$todays_day = date(d);

$tstamp = mktime(0, 0, 0, $todays_month, $todays_day, $todays_year);

$event_time = mysql_query(SELECT cal_id FROM egw_cal_dates where cal_start  
$tstamp, $db);

$events = mysql_query(SELECT * FROM egw_cal WHERE cal_category='501' and 
cal_id='$event_time'\n, $db);



if ($event = mysql_fetch_array($events)) 

echo center\n;

echo HR\n;

do 

echo BFont 
Size='10'$event[cal_title]nbsp;nbsp;nbsp;nbsp;-nbsp;nbsp;nbsp;$event[cal_location]/B/Font\n;

echo BR\n;

echo $event[cal_description];

echo BR\n;

echo HR\n;

 while ($event = mysql_fetch_array($events));

 else 

echo No Public Events Are Currently Scheduled...;



?


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Re: [PHP-DB] 2 queries -- 1 array

2007-01-12 Thread tg-php
Not sure if this is exactly what you're looking for, Matt, but I think it is.

?php
$query = SELECT t1.NAME, t1.BUSINESS, t1.ADDRESS, t1.CITY, t1.PHONE, 
t2.CONTACT_NAME, t2.CONTACT_VALUE FROM Table1 as t1, Table2 as t2 WHERE t1.ID = 
t2.CONTACT_ID
$result = mysql_query($query);

while ($row = mysql_fetch_assoc($result)) {
  // to make it easier to read, I'll assign the values to variables for this 
demonstration
  $name = $row['NAME'];
  $business = $row['BUSINESS'];
  $address = $row['ADDRESS'];
  $city = $row['CITY'];
  $phone = $row['PHONE'];
  $contactname = $row['CONTACT_NAME'];
  $contactvalue = $row['CONTACT_VALUE'];

  $bigarray[$name][$contactname] = $contactvalue;
}


$JoeBrownPrevsys = $bigarray['Joe Brown']['Prevsys'];
?


If that's not right, please re-describe the problem and let's see what we can 
figure out.

If you have questions about what/how/why/etc...  feel free to ask.

-TG

= = = Original message = = =

Hello,


I need to query two different tables and create one BIG array.

I can query both tables, but can't find a way to combine the results in one 
array.
The problem comes in with the second table.  It has a weird layout.

The second table only has four fields. They are:  contact_id, contact_owner, 
contact_name, and contact_value

  a.. The 'contact_id' needs to be linked to 'id' field from the first table.
  b.. The contact_name is a field I need to use to reference what i'm looking 
for.
example... contact_name HAS values of RANO, PrevSys, 
Supplier, Dynamic
each of them has the same contact_id different 
contact_names with different contact_values


To query the second table I do something like this:

SELECT contact_value FROM egw_addressbook_extra WHERE contact_name='Supplier' 
and contact_id=' XXX'

The xxx is the ID from the first table.

-
Table 1:

IDNAMEBUSINESS   
ADDRESSCITY PHONE 
1  John SmithSmith's Phone Co. 100 Main 
St  Someplace   555-
2  Joe Brown Brown's Shoe Store105 
Grant St.This City  555-0001




Table 2:

CONTACT_IDCONTACT_NAME  
  CONTACT_VALUECONTACT_OWNER
  1 PrevSys 
 NONE   
 4
  1 RANO
 100102 
  4  
  1 Supplier
   TrueValue
   4
  1 Dynamic 
 192.168.0.0
 4
  2 PrevSys 
 OLD POS SYS
 4
  2 RANO
 100105 
4  
  2 Supplier
   Orgill   
 4
  2 Dynamic 
 192.168.100.0  
 4


I want to query both  tables and create a array.  The extra fields from table 
two need to have their own field in the array.
I need to call those extra fields in the array by the contact_name field...

example   $myrow[supplier] $myrow[PrepSys] $myrow[name]


I have tried alot of stuff to get this done, but i think i was very off task.

Some help/guide is needed I'm new

Thanks...

Matt


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Re: [PHP-DB] 2 queries -- 1 array

2007-01-12 Thread tg-php
Ok, in your original message you said something about using the name as 
dominant key (or whatever you want to call it).  All the SQL does is gather all 
the data together in an associated fashion.  You can use the array you build to 
organize the data.   I'm still not 100% sure what you're doing, so I can't say 
this is the best way, but let's look at the exampe I gave and change it to 
hopefully suit your last description:

$name = $row['NAME'];
$business = $row['BUSINESS'];
$address = $row['ADDRESS'];
$city = $row['CITY'];
$phone = $row['PHONE'];
$contactname = $row['CONTACT_NAME'];
$contactvalue = $row['CONTACT_VALUE'];

// $bigarray[$name][$contactname] = $contactvalue;

$bigarray[$contactname][$name] = $contactvalue;

foreach ($bigarray['Supplier'] as $name = $value) {
  echo Supplier: $name has CONTACT_VALUE = $valuebr\n;
}

There may be an elegant way to do what you want in SQL too, I'm just not fully 
groking the situation I think.

-TG

   $name = $row['NAME'];
   $business = $row['BUSINESS'];
   $address = $row['ADDRESS'];
   $city = $row['CITY'];
   $phone = $row['PHONE'];
   $contactname = $row['CONTACT_NAME'];
   $contactvalue = $row['CONTACT_VALUE'];

   $bigarray[$name][$contactname] = $contactvalue;


= = = Original message = = =

yeah..that is what i'm trying to do, but

I need to query WHERE contact_name='Supplier' and bring back the value for
contact_value
   query WHERE contact_name='RANO' and bring back the value for
contact_value
   query WHERE contact_name='Dynamic' and bring back the value
for contact_value
   query WHERE contact_name='PrevSys' and bring back the value
for contact_value
Which are all different rows in the second table
with the same ID field
thats how they are linked to the first table

thanks...

Matt

- Original Message -
From: [EMAIL PROTECTED]
To: php-db@lists.php.net
Cc: [EMAIL PROTECTED]
Sent: Friday, January 12, 2007 4:26 PM
Subject: Re: [PHP-DB] 2 queries -- 1 array


 Not sure if this is exactly what you're looking for, Matt, but I think it
is.

 ?php
 $query = SELECT t1.NAME, t1.BUSINESS, t1.ADDRESS, t1.CITY, t1.PHONE,
t2.CONTACT_NAME, t2.CONTACT_VALUE FROM Table1 as t1, Table2 as t2 WHERE
t1.ID = t2.CONTACT_ID
 $result = mysql_query($query);

 while ($row = mysql_fetch_assoc($result)) 
   // to make it easier to read, I'll assign the values to variables for
this demonstration
   $name = $row['NAME'];
   $business = $row['BUSINESS'];
   $address = $row['ADDRESS'];
   $city = $row['CITY'];
   $phone = $row['PHONE'];
   $contactname = $row['CONTACT_NAME'];
   $contactvalue = $row['CONTACT_VALUE'];

   $bigarray[$name][$contactname] = $contactvalue;
 


 $JoeBrownPrevsys = $bigarray['Joe Brown']['Prevsys'];
 ?


 If that's not right, please re-describe the problem and let's see what we
can figure out.

 If you have questions about what/how/why/etc...  feel free to ask.

 -TG

 = = = Original message = = =

 Hello,


 I need to query two different tables and create one BIG array.

 I can query both tables, but can't find a way to combine the results in
one array.
 The problem comes in with the second table.  It has a weird layout.

 The second table only has four fields. They are:  contact_id,
contact_owner, contact_name, and contact_value

   a.. The 'contact_id' needs to be linked to 'id' field from the first
table.
   b.. The contact_name is a field I need to use to reference what i'm
looking for.
 example... contact_name HAS values of RANO, PrevSys,
Supplier, Dynamic
 each of them has the same contact_id different
contact_names with different contact_values


 To query the second table I do something like this:

 SELECT contact_value FROM egw_addressbook_extra WHERE
contact_name='Supplier' and contact_id=' XXX'

 The xxx is the ID from the first table.

 -
 Table 1:

 IDNAMEBUSINESS
ADDRESSCITY PHONE
 1  John SmithSmith's Phone Co. 100
Main St  Someplace   555-
 2  Joe Brown Brown's Shoe Store105
Grant St.This City  555-0001




 Table 2:

 CONTACT_IDCONTACT_NAME
CONTACT_VALUECONTACT_OWNER
   1 PrevSys
NONE4
   1 RANO
100102   4
   1 Supplier
TrueValue   4
   1 Dynamic
192.168.0.0 4
   2

Re: [PHP-DB] Filter array results... no copies

2007-01-11 Thread tg-php
If all you want is a unique list of adr_one_region codes, then use the 
DISTINCT keyword in your SQL:

SELECT DISTINCT adr_one_region FROM egw_addressbook WHERE cat_id='8' ORDER BY 
adr_one_region


-TG

= = = Original message = = =

Hello everyone

I'm back working on the website again... I'm having lots of fun.
I have a sql query that looks at one field in a database. (result2 query)
Then i have mysql_fetch_array statement.

I then use this array to print links on the page.
Works fine except I don't want duplicate links.

It creates links for the states.  If we have four customers from Pennsylvania.  
This current process gives me four different PA links on my page.  

I need a statement that says...if its already printed...don't print it...

Thanks...

Here is my code:

html

body

?php

$db = mysql_connect(HOST, USERNAME, PASSWORD);

mysql_select_db(DATABASE,$db);


if ($_GET[area]==) 

$master = mysql_query(SELECT * FROM egw_addressbook

WHERE cat_id='8' ORDER BY org_name, $db);



 else 

$master = mysql_query(SELECT * FROM egw_addressbook

WHERE cat_id='8' and adr_one_region='$_GET[area]' ORDER BY org_name, $db);





$result2 = mysql_query(SELECT adr_one_region FROM egw_addressbook

WHERE cat_id='8' ORDER BY adr_one_region, $db);



if ($area = mysql_fetch_array($result2)) 

echo Sort by State: ;



do 

echo a 
href='index.php?area=$area[adr_one_region]'$area[adr_one_region]/a\n;

echo  - ;

 while ($area = mysql_fetch_array($result2));

echo a href='index.php?area='ALL/a\n;

 else 

echo ERROR;





if ($myrow = mysql_fetch_array($master)) 

echo CENTER\n;

echo table border=0\n;

echo img src=file.jpg width='611' height='136'\n;

echo BR\n;

echo BR\n;



do 

printf(tr td/tdtdb%s/b/tdtd/tdtd/tdtd%s/td/tr\n, 
$myrow[org_name], $myrow[fn]); 

printf(tr td/tdtd%s/tdtd/tdtd/tdtd%s/td/tr\n, 
$myrow[adr_one_street], $myrow[tel_work]);

printf(tr td/tdtd%s, %s 
%s/tdtd/tdtd/tdtd/tdtd/td/tr\n, 
$myrow[adr_one_locality], $myrow[adr_one_region], 
$myrow[adr_one_postalcode]);



 while ($myrow = mysql_fetch_array($master));

echo /table\n;

echo /CENTER\n;

 else 

echo Sorry, no records were found!; 



?

/body

/html


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[PHP-DB] Displaying next ten items

2006-12-28 Thread Ron Piggott (PHP)

I am wondering what the mySQL commands are to display the next 10
records / previous 10 records.  

I am wondering how you pass a variable through a PHP script so the
script knows which next or previous 10 entries to display.  (Especially
since this is all variable driven)  Would you do something like ?next=21
and ?previous=1 as part of the URL link to know where your query should
begin?  I do know the LIMIT = mySQL command to limit 10 items to be
displayed.

How do you tell when there aren't 10 more entries left to display?  IE
If there are 46 records in a table and you are displaying 40 to 46 you
don't want to offer a link to display records 50 to 59.  

Ron


[PHP-DB] 10 rows

2006-12-28 Thread Ron Piggott (PHP)
I would normally just pass the offset through the get var.


I understand what you are saying in concept ... but what would a sample
command be like?

a href=http://www.host.com/script.php?next=21;Next Link/a
a href=http://www.host.com/script.php?previous=1;Previous Link/a

Ron


Re: [PHP-DB] Order By [blank]

2006-12-21 Thread tg-php
This is a little weird looking, but should do the job.  Remember that items in 
your 'order by' can be manipulated conditionally.  In this case, I'm looking 
for NULL as well as '' (empty) and changing it to something that should come 
after all your normal alphabetical values, but it doesn't change what appears 
in your results.  This only affects the sorting:

select * from sometable order by if(ifnull(somecolumn, '') = '', 
'', somecolumn)

Hope that helps.

-TG

= = = Original message = = =

I have this column in mysql:

A
F
D
[ empty ]
A
C

If I do an order by on that column, this is what I get:

[ empty ]
A
A
C
D
F

What I would like is this:

A
A
C
D
F
[ empty ]

Is there any way to achieve this in a single MySQL query? Using DESC  
in this case doesn't work, because while it puts the empty row in the  
last place, it does the rest as well. I could also do 2 queries where  
it calls it once in order WHERE  !='', and then do another query to  
get the empty ones, but that seems a bit cumbersome.

-- 
Kevin Murphy
Webmaster: Information and Marketing Services
Western Nevada Community College
www.wncc.edu
775-445-3326




-- 
Kevin Murphy
Webmaster: Information and Marketing Services
Western Nevada Community College
www.wncc.edu
775-445-3326


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Re: [PHP-DB] Order By [blank]

2006-12-21 Thread tg-php
This is a little weird looking, but should do the job.  Remember that items in 
your 'order by' can be manipulated conditionally.  In this case, I'm looking 
for NULL as well as '' (empty) and changing it to something that should come 
after all your normal alphabetical values, but it doesn't change what appears 
in your results.  This only affects the sorting:

select * from sometable order by if(ifnull(somecolumn, '') = '', 
'', somecolumn)

Hope that helps.

-TG

= = = Original message = = =

I have this column in mysql:

A
F
D
[ empty ]
A
C

If I do an order by on that column, this is what I get:

[ empty ]
A
A
C
D
F

What I would like is this:

A
A
C
D
F
[ empty ]

Is there any way to achieve this in a single MySQL query? Using DESC  
in this case doesn't work, because while it puts the empty row in the  
last place, it does the rest as well. I could also do 2 queries where  
it calls it once in order WHERE  !='', and then do another query to  
get the empty ones, but that seems a bit cumbersome.

-- 
Kevin Murphy
Webmaster: Information and Marketing Services
Western Nevada Community College
www.wncc.edu
775-445-3326




-- 
Kevin Murphy
Webmaster: Information and Marketing Services
Western Nevada Community College
www.wncc.edu
775-445-3326


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Re: [PHP-DB] Order By [blank]

2006-12-21 Thread tg-php
You shouldn't have to do that. the IFNULL() handles all that.  If the item is 
null, it returns an emptry string ''.  If it's blank/empty, it returns an empty 
string. This is just used for the comparison = ''.  This determines if it's 
empty or null and if so, returns 'ZZ', if not, it 
returns the unaltered value.  And again, this returned value is only used for 
the sorting.  The values you get from select * will be unaltered.

Is this more efficient than doing two SELECTs and a UNION?  I have no idea.  
But I like to keep things as clean as possible and in my reading and 
experience, letting the server handle an IFNULL() function should be quicker 
than doing four value checks (is null, is not null, = '' and != ''), collecting 
the values of two SELECTS then checking to see if it's able to UNION them 
together.

Also, less code/typing typically means less chance of typos.


BTW: In my example, realistically you could probably shorten the morphed value 
to ZZ or ZZZ unless you think you'll values in your database that will 
start with  and get bumped lower on the sorting.

-TG

= = = Original message = = =

In case the blank is a null or is really a blank:

select * from blank where tchar_10 is not null and tchar_10 != ''
union all
select * from blank where tchar_10 is null or tchar_10 = ''

- Dave

On 12/21/06, [EMAIL PROTECTED] [EMAIL PROTECTED]
wrote:

 This is a little weird looking, but should do the job.  Remember that
 items in your 'order by' can be manipulated conditionally.  In this case,
 I'm looking for NULL as well as '' (empty) and changing it to something that
 should come after all your normal alphabetical values, but it doesn't change
 what appears in your results.  This only affects the sorting:

 select * from sometable order by if(ifnull(somecolumn, '') = '',
 '', somecolumn)

 Hope that helps.

 -TG

 = = = Original message = = =

 I have this column in mysql:

 A
 F
 D
 [ empty ]
 A
 C

 If I do an order by on that column, this is what I get:

 [ empty ]
 A
 A
 C
 D
 F

 What I would like is this:

 A
 A
 C
 D
 F
 [ empty ]

 Is there any way to achieve this in a single MySQL query? Using DESC
 in this case doesn't work, because while it puts the empty row in the
 last place, it does the rest as well. I could also do 2 queries where
 it calls it once in order WHERE  !='', and then do another query to
 get the empty ones, but that seems a bit cumbersome.

 --
 Kevin Murphy
 Webmaster: Information and Marketing Services
 Western Nevada Community College
 www.wncc.edu
 775-445-3326




 --
 Kevin Murphy
 Webmaster: Information and Marketing Services
 Western Nevada Community College
 www.wncc.edu
 775-445-3326


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Re: [PHP-DB] MSSQL Server

2006-12-21 Thread tg-php
I had some issues a couple years ago connecting to the MS SQL Server where I 
was employed at the time.

I was probably  just doing something wrong, but what I ended up using that 
worked for me was using the ADODB database abstraction layer.  Helped me 
connect to MS SQL , Oracle and some other random data sources I had to from 
time to time.

http://adodb.sourceforge.net/

Sorry I don't have time to look for good examples, but maybe the documentation 
will help out some and get you on the right path.

-TG

= = = Original message = = =

I cannot connect to my MSSQL server.

I use the following connection string:

php:
--
$connection = mssql_connect http://php.net/mssql_connect('server','user',
'password') or die ('server connection failed');

$database = mssql_select_db http://php.net/mssql_select_db(database_name
, $connection) or die ('DB selection failed');
?
--



The MSSQL server is setup to use Windows and Server Authentication. I have a
*local* dummy account setup for testing and when using this account I can
connect with no problems, but when I try and use my domain/network account I
cannot connect at all. (my network account has full access to the server,
database and tables) I can even login to the SQL Management Studio using
Windows Authentication and my network account, but still cannot connect
using PHP.

Any ideas?


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Re: [PHP-DB] search result error message

2006-12-21 Thread tg-php
Sorry, don't have time to test and noodle through why yours may or may not be 
working, but I see some differences in how you're doing it and how we tend to 
do it here.

After doing the connection and database selection, this is how we handle stuff 
(simplified):

$query = select * from sometable;

$result = mysql_query($query);

$count = mysql_affected_rows();

while ($row = mysql_fetch_assoc($result)) {
  // do some stuff
  $address = $row['address'];  // example of how to get/use data returned
}

Nothing inside the while construct should execute if you get zero results.

You really don't need to use the mysql_affected_rows() either unless you want 
to test for zero results and display an error message, like I believe you 
wanted to do.

-TG

= = = Original message = = =

Hi,

The below mentioned code works fine. Connects to the database, fetches the
result, and displays neatly in a table. If there is no data then it jumps to
the if condition and displays the error message. BUT if the 'if' condition
is running and no data is present the Table headings and the bottm of empty
table is still displayed above the error message. Can you please check and
share with me as in where exactly the logic is wrong.

-- -- Code --- 

h2Your favorites search result/h2divYou are here:  index.htm Home  
Your favorites/div~~
div class=internalContentArea sgtable 
~~~div class=tableHeadSub-category search result/div~~
~div
~table width='100%' id='table1' cellspacing=0theadtr
th scope=colShop name/th

/tr/theadtbody
?php
// database information
   $host = 'xxx';  
   $user = 'xxx';
   $password = 'xxx';
   $dbName = 'xxx';

mysql_connect(localhost,$user,$password);
@mysql_select_db($dbName ) or die( Sorry But There Seems To Be A Problem
Connecting To The Database);

$query=SELECT * FROM shop;
$result=mysql_query($query);

$num=mysql_numrows($result);

mysql_close();

$i=0;

while ($i  $num) 

$shopname=mysql_result($result,$i,shopname);
echo 
tr
td$shopname/td
/tr;
$i++;


?/tbody/table index.htm  Back to search div 
/div

? 
if ($num == 0)

echo 
div
  div class='alert'The search criteria you entered did not generate any
result,  index.htm please try again ./div
~/div;

?
~
/div.
-- 
View this message in context: 
http://www.nabble.com/search-result-error-message-tf2867391.html#a8014018
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[PHP-DB] ORDER BY

2006-10-18 Thread Ron Piggott (PHP)
Is it possible to do an ORDER BY column_a column_b ASC  ?  IE Can you
specify two columns to cause the output to be displayed in a specific
order?  Ron


[PHP-DB] Verifying syntax executed correctly

2006-10-17 Thread Ron Piggott (PHP)

If I give this command through PHP to mySQL

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( Unable to select database);
$query = UPDATE `table` SET `last_activity_field` = '$current_date'
WHERE `reference` = '$account_reference' LIMIT 1;;
mysql_query($query);
mysql_close();

is there a way to know if it executed successfully?

Ron


[PHP-DB] month

2006-10-15 Thread Ron Piggott (PHP)
Is there a slick and easy way to convert January to 01 ? (and February
to 02, etc)  Ron


Re: [PHP-DB] month

2006-10-15 Thread Ron Piggott (PHP)
I have completely missed it and need to try again.  


[PHP-DB] Files uploaded through a form

2006-10-07 Thread Ron Piggott (PHP)
The way my web hosting server was configured is that files uploaded
through a web form to be processed by PHP are owned by 'www'.  I am
wondering if I am able to change the owner of the file to my ftp user
name before I use the move_uploaded_file command to the directory I need
the file to move to.  

I am also wondering what the IF syntax is to see if the file upload was
successful.  Somehow I would like to know if 

move_uploaded_file( $userfile , $destination_file_name);

worked successfully before I update my table.

Ron


[PHP-DB] ECHO $variable

2006-10-07 Thread Ron Piggott (PHP)
In one of my scripts I have

input type=text name=message_title size=40 maxlength=80 value=?echo
$saved_message_title;?

where

$saved_message_title is 1 Peter 5:7 Cast all your cares on Him for He
cares about you
--- note the  

When this is displayed on the screen it reads

1 Peter 5:7 

I am assuming the  closes the value=

How may I echo this to the screen and have the full text be displayed,
not just 1 Peter 5:7 ?

Ron


[PHP-DB] SELECT date query

2006-10-06 Thread Ron Piggott (PHP)
I am wondering if someone would help me write a SELECT date query ...

Weekly mailings go out every Wednesday.  I am setting up an
administration function and table to store the mailing name, PDF to be
contained within the mailing and the date for it to be used.

The SELECT query I want to create is for the next 12 records which are
going to be used to be displayed.  The first record would be next
Wednesday (not October 11th, but calendar wise based on when the script
ran) and then the following 11 Wednesdays.

SELECT * FROM christian_discipleship WHERE created_for_date =
'$next_wednesday' ORDER BY created_for_date ASC LIMIT 12

I am not sure how to generate the value for $next_wednesday

Any ideas?

Ron


RE: [PHP-DB] Search engine

2006-09-28 Thread Ron Piggott (PHP)

What I haven't figured out is how to crawl my site.  If I knew how to
crawl my site I could write a basic search engine and develop it over
time.  This is the crucial issue I need help with.  

I have a really basic search engine I wrote last year.  I told my web
site what pages the user could search ... as in I keyed in the URL's 

I am giving my site a face lift and making some serious changes to
it ... I have my database out of date ... I would like to crawl my site
once a day to update what changes I made during the past 24 hours and
delete HTML files which no longer exist.  

If someone knew how to retrieve various a href= then I could start
with something and build on it over time ... 

Ron

On Thu, 2006-09-28 at 11:44 +0100, Shaun A Riches wrote:

 What about the MySQL LIKE command? Research it.
 
 This is assuming your data is stored properly without redundant data
 and in a MySQL database.
 
 ___
 Shaun Riches
 Computer Science Student
 
 
 
 -Original Message-
 From: Ron Piggott (PHP) [mailto:[EMAIL PROTECTED]
 Sent: Thu 28/09/2006 03:44
 To: PHP DB
 Subject: [PHP-DB] Search engine
 
 
 
 ___
 Shaun Riches
 Computer Science Student
 
 
 
 -Original Message-
 From: Ron Piggott (PHP) [mailto:[EMAIL PROTECTED]
 Sent: Thu 28/09/2006 03:44
 To: PHP DB
 Subject: [PHP-DB] Search engine
 
 Has anyone wrote a search engine for the web site?  I am wondering if
 someone has the time to help me walk through doing this.  Ron
 
 
 
 


[PHP-DB] Searching PHP strings

2006-09-28 Thread Ron Piggott (PHP)
I have been playing tonight for a few minutes.

The following code:

?

$lineArray = file(/home/actsmin/www/home_page.html);

// make an empty variable first
$content =  ;

// concat all array element
foreach($lineArray as $eachLine) {

if ( eregi(a href= , $eachLine) == 1 ) {

#line contains a link

echo strlen(stristr($eachLine, a href=)) . \r\n;
echo trim(stristr($eachLine, a href=)) . \r\n;

}

$content .= $eachLine;
}

?

Produces me output like:

137

a 
href=http://www.actsministrieschristianevangelism.org/christianliving/quiet_time_quotations_and_reflection_topics.html;here/a.p

What I want to do now is to remove the 

a href= 

and just be left with 

http://www.actsministrieschristianevangelism.org/christianliving/quiet_time_quotations_and_reflection_topics.html

and remove all the text which follows this --- On this line it is

here/a.p

Would someone help me do this?

Ron


[PHP-DB] I still have a bit more of the string to get rid of ...

2006-09-28 Thread Ron Piggott (PHP)
Where '$eachLine' is a line of HTML code the following command

echo str_replace(a href=\, , trim(stristr($eachLine, a
href=))) . \r\n;

give me this result:

http://www.actsministrieschristianevangelism.org/christianliving/quiet_time_quotations_and_reflection_topics.html;here.

I want to get rid of everything including and following the  

What do I do next?


[PHP-DB] $_SERVER

2006-09-27 Thread Ron Piggott (PHP)
Is there a predefined variable that will tell me the resolution of the
browser that is looking at my site?

EXAMPLE 1024 X 768 OR 800 X 600

Ron


[PHP-DB] Search engine

2006-09-27 Thread Ron Piggott (PHP)
Has anyone wrote a search engine for the web site?  I am wondering if
someone has the time to help me walk through doing this.  Ron


RE: [PHP-DB] Re: Page refresh and database updation

2006-09-26 Thread php
You can redirect the page to the result page after the data is saved, using 
header(Location: successpage.php).  I've used this on several sites.  It's a 
little extra work but does prevent the reposting of data.

Another option is to use AJAX to send the data to the webserver and then have 
the javascript open the result page after the update is complete.  I do this on 
several of my webpages and it works great.

Tamkhane, Pravin wrote:
 Hi All,
 I am a PHP newbie. I am using HTTP POST request to send some data to 
 Apache and then using MySql to store that information. Once information 
 is stored in MySql DB successfully, I display a result page. But the 
 problem I am facing is that, if I refresh the result page displayed 
 after database updation, the information is stored again in database 
 which I don't want to. Please guide me on how I can avoid duplication of 
 information in database on refreshing the page. Thanks in advance!
 
 Regards,
 Pravin
You probly want to use a seperate script to build the results, or even a 
PEAR template mechanism.

/cs

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[PHP-DB] ViewSonic VX724

2006-09-18 Thread Ron Piggott (PHP)
I realized this is off topic; I am not sure where I would look online.  

Today I purchased a VX724 LCD monitor for my computer.  I am running
Fedora Core (Linux).  I am not sure where I would find a driver for my
monitor.  ViewSonic's tech support told me they don't support the
monitor directly and I would need to build my own driver.  I am
wondering if this has already been done.  The monitor does work on my
computer, but the color scheme is off.  If someone could help send me in
the right direction I would appreciate it.  

Ron


[PHP-DB] Displaying a PDF file

2006-09-14 Thread Ron Piggott (PHP)
I am creating a submit button on the fly.  The purpose of this is to
open up a new browser window and then display the contents of a PDF
file. 

The code for this button reads:

input type='button' value='Psalm 91' 

onclick=window.open('index.php?request=view_prayer_ministry_documentdocument_reference=1','prayer_ministry_document_viewer','width=800,height=600,toolbars=no,resizable=yes,scrollbars=yes');

The window name is prayer_ministry_document_viewer
I am trying to access document_reference 1 which is in a mySQL table. 

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( Unable to select database);
$query=SELECT * FROM prayer_ministry_documents WHERE reference = 
'$document_reference';
$document_result=mysql_query($query);
mysql_close();

$document_file_name = mysql_result($document_result,0,document_file_name);

#now here I start to get the contents of the PDF file to display

$lineArray = file($document_file_name);

// make an empty variable first
$document_contents_to_display =  ;

// concat all array element
foreach($lineArray as $eachLine) {
$eachLine = wordwrap($eachLine);
$document_contents_to_display .= $eachLine;
}

#when I try to display it the PDF it displays it as text with the various ASCII 
characters ---
#what I am doing wrong / what is the correct way to do this
#I know I could simply specify the file name / path following the window.open 
... but I am trying to see if I am able to accomplish the same results this 
way.  

echo $document_contents_to_display;

?



Ron


[PHP-DB] Forms with letter verification

2006-07-29 Thread Ron Piggott (PHP)
You know forms which have a security field where the user reads back the
letters that are displayed?  I am wondering if someone has the time to
coach me in writing this --- or if you know of a web page that shows how
to create this feature.  I have already created a set of graphical
letters.  Ron


Re: [PHP-DB] running program after insert w/MySQL 4.1

2006-07-07 Thread tg-php
cron or Windows Task Manager would work if you want to check the status of the 
data periodically, but I believe you can also use Access to hit a web address 
(it doesn't have to display anything) so you could, at time of insert, have 
Access activate a PHP script on your web server that does the database check.

You could probably get the last inserted ID number as well and pass that to the 
PHP script if you want to check specific records right after they're inserted.

-TG

= = = Original message = = =

I have an Access database connecting via ODBC to a local MySQL machine 
and doing inserts.  It does these inserts throughout the day.

After each insert, I need a PHP program run.

Alas, MySQL 4.1 doesn't do triggers, etc., and upgrading to 5.x looks 
non-trivial.

What else can I do?  Is there any way to trigger something via the ODBC 
connection?

A cron job?

I'm open to suggestions.

kind regards,

bill


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Re: [PHP-DB] Problem with list#2

2006-07-07 Thread tg-php
You may get duplicate messages sometimes when someone responds directly to you 
as well as copying the message to the main mailing list.  Like in this ccase, 
my To: field is the PHP DB list, and my CC: field is your personal email 
address.

If that's not the issue, then try what Dave suggested and unsubscribe using one 
of your email addresses and see if that solves the problem.

-TG

On 7/7/06, Karl James [EMAIL PROTECTED] wrote:

 Team,



 I am still receiving duplicate emails.

 I check with my ISP and they tell me it is

 Not their problem. I tried to check the headers

 But I am not able to see anything that indicates

 What email address its being sent to because

 I have two of them.



 Can anyone help suggest on how to resolve this.

 I would send a screen shot but its not advise to

 In forums. Off list I can for sure if any one wants

 To see what's going on.



 Karl James (TheSaint)
 mailto:[EMAIL PROTECTED] [EMAIL PROTECTED]
 mailto:[EMAIL PROTECTED] [EMAIL PROTECTED]

 www.theufl.com


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RE: [PHP-DB] LIMIT

2006-07-05 Thread tg-php
Here are some thoughts on the couple of methods shown:

1. 
SELECT count(*) as MyCount FROM aTable  # Fast query done on server size
SELECT * FROM aTable LIMIT 5  # Fast limited data return query done server side

2.
SELECT * FROM aTable  # Potentially slow query, lots of data stored in PHP
mysql_num_rows()  # Quick PHP-side function to tell how many results returned

3. 
SELECT SQL_CALC_FOUND_ROWS * FROM $table LIMIT 5  # Fast server side query that 
does the same as SELECT count(*) and SELECT LIMIT 5 at the same time
SELECT FOUND_ROWS()  # Fast server side query


Seems like #1 and #3 are your best options.  Both are pretty easy on your 
system.  #3 is definitely pretty slick, thanks to whoever originally posted 
that.  But I'm wondering if it'll be fully compatible in the future.  #1 is 
pretty SQL 101 type stuff, so it should remain functional and be usable on 
other database platforms as well.  That's the one I'd go for, just for the sake 
of keeping things simple if nothing else.

Seems like a waste to do two database queries, but as long as you're not 
closing and re-opening the connection in between, it should cause very minimal 
impact on your system.   Sometimes two queries are better than one.

-TG


= = = Original message = = =

I see they call mysql_query twice which doesn't look like I'm gaining
anything over running the 2 queries:
SELECT count(*) as MyCount FROM aTable
SELECT * FROM aTable LIMIT 5

But I suppose I need to time it for my app.

http://us3.php.net/mysql_num_rows

mancini at nextcode dot org
14-Nov-2005 02:24
here is a really fast mysql_num_rows alternative that makes use of the
SELECT FOUND_ROWS() MySQL function , it only reads a single row and it is
really helpfull if you are counting multiple tables with thousands of rows

?php
function get_rows ($table) 
   $temp = mysql_query(SELECT SQL_CALC_FOUND_ROWS * FROM $table LIMIT
1);
   $result = mysql_query(SELECT FOUND_ROWS());
   $total = mysql_fetch_row($result);
   return $total[0];

?

+++
alex dot feinberg 4t gm41l
28-Apr-2005 04:56
Re dzver at abv dot bg's note...

I just ran some tests using MySQL Super Smack. Surprisingly, a SELECT *
followed by a SELECT COUNT(*) actually was close in speed to a SELECT
SQL_CALC_FOUND_ROWS * followed by a SELECT FOUND_ROWS(), but the
SQL_CALC_FOUND_ROWS solution was still a bit faster.

Perhaps it varies by table structure? Either way, it might be worth checking
which is faster for your application.

Regards,
Dwight

 -Original Message-
 From: Dwight Altman [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, July 05, 2006 9:53 AM
 To: 'php-db@lists.php.net'
 Subject: RE: [PHP-DB] LIMIT
 
 So how do I get this information on the PHP side?
 
 mysql SELECT SQL_CALC_FOUND_ROWS * FROM tbl_name
 - WHERE id  100 LIMIT 10;
 mysql SELECT FOUND_ROWS();
 
 I count 2 queries above (unless there is some caching magic).  Whatever.
 I was hoping to add another column (like FOUND_ROWS) to an existing query
 and be able to pull out the FOUND_ROWS when I loop over the result set.
 Something like:
 SELECT *, FOUND_ROWS FROM aTable LIMIT 5
 
 But since that single query doesn't work, how do I apply the MySQL
 solution and extract it on the PHP side?
 
 http://dev.mysql.com/doc/refman/4.1/en/information-functions.html
 http://www.mysqlfreaks.com/statements/101.php
 
 
 Regards,
 Dwight
 
  -Original Message-
  From: Chris [mailto:[EMAIL PROTECTED]
  Sent: Friday, June 30, 2006 9:46 AM
  To: php-db@lists.php.net
  Subject: Re: [PHP-DB] LIMIT
 
  If you're using MySQL then:
 
  SELECT SQL_CALC_FOUND_ROWS * FROM aTable LIMIT 5
  SELECT FOUND_ROWS()
 
  It's in the mysql documentation under SELECT syntax I believe.
 
  Chris
 
  Dwight Altman wrote:
   Is there a way to get the number of rows that would have been returned
  had
   there not been a LIMIT clause in a SELECT statement?
  
   For example, if
   Query #1) SELECT * FROM aTable
   would normally return 100 rows.  But
   Query #2) SELECT * FROM aTable LIMIT 5
   will return 5 rows.  Is there a way to find out that 100 rows would
 have
   been returned if there was no LIMIT clause, by using only Query #2 and
  maybe
   a PHP function on the $result?
  
   Regards,
   Dwight
  
  
  
 
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[PHP-DB] Cron unlink

2006-07-02 Thread Ron Piggott (PHP)
Does anyone have experience in getting unlink to work within the context
of a cron?

I created my own garbage collection function and I am trying to delete
some session files through a cron that runs every 10 minutes.

The session files are owned by 'www'
The cron is ran by 'actsmin'

The 'unlink' command works within the context of a php script when
activated by a user on the web site.  

Is there another file deletion command within PHP other than unlink?

Here is the error message I am e-mailed by the cron when it doesn't
successfully delete a session file:


 Warning: unlink(/path/to/sessions/files/): 
 Is a directory in /path/to/php/script/cron/calls/script.php on line 47

Any suggestions?

Ron

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[PHP-DB] ftp_connect($ftp_server);

2006-07-01 Thread Ron Piggott (PHP)
Every now and then the following command fails --- the FTP connection is
refused by the server:

$conn_id = ftp_connect($ftp_server);

Is there a way to delete a file within PHP without having to FTP to the
server?

Ron

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Re: [PHP-DB] Conditional updating...

2006-06-25 Thread Grae Wolfe - PHP
Thank you for the thought, however, I don't have a shell that I can run in, 
hence, I have to rely on help from others.


JupiterHost.Net [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]


 Grae Wolfe - PHP wrote:
   Sorry I have been out of touch...  I thought I had this problem beat, 
 but I was wrong.  I decided that the best thing to do was to filter the 
 variables as the $sql statement was being created.  I tried using the 
 following code, and got a message back that it was invalid and my Query 
 couldn't execute...  Can anyone tell me where I screwed this one up??

 Print out $sql and then try to manually do it in your mysql (or whatver DB 
 engine) shell.

 I imagine you have a syntax error and that will tell you exactly what and 
 where it is :)

 And I hope you're only criteria for the value of each colum isn't that its 
 just not empty.

 If so you will be vilnerable to SQL injection attacks and your data will 
 be compromised. You should at the very least quote the values with a valid 
 SQL quoting function. (IE not just wraping it in quotes but one that 
 actually escapes certain characters and wraps it in quotes as need be)

 Do not rely on that automaticaly being done (IE think how crappliy 
 unreliable and dangerous relying on Magic Quotes is, oi what pile *that* 
 is...) 

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Re: [PHP-DB] Conditional updating...

2006-06-23 Thread Grae Wolfe - PHP
  Sorry I have been out of touch...  I thought I had this problem beat, but 
I was wrong.  I decided that the best thing to do was to filter the 
variables as the $sql statement was being created.  I tried using the 
following code, and got a message back that it was invalid and my Query 
couldn't execute...  Can anyone tell me where I screwed this one up??

$sql = UPDATE $table SET;


if(!empty($first_name))
  $sql .='first_name='.$first_name.',';


if(!empty($last_name))
  $sql .='last_name='.$last_name.',';


if(!empty($hs_last_name))
  $sql .='hs_last_name='.$hs_last_name.',';


if(!empty($street_address1))
  $sql .='street_address1='.$street_address1.',';


if(!empty($street_address2))
  $sql .='street_address2='.$street_address2.',';


if(!empty($city))
  $sql .='city='.$city.',';


if(!empty($state))
  $sql .='state='.$state.',';


if(!empty($zip))
  $sql .='zip='.$zip.',';


if(!empty($phone1))
  $sql .='phone1='.$phone1.',';


if(!empty($phone2))
  $sql .='phone2='.$phone2.',';


if(!empty($email_address))
  $sql .='email_address='.$email_address.',';


if(!empty($current_info))
  $sql .='current_info='.$current_info.',';


if(!empty($today))
  $sql .='date_registered='.$today;


WHERE first_name='$first_name' AND last_name='$last_name';



Jeffrey [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]
 Perhaps I have misunderstood something here. But it seems to me that 
 anyone who just happens to put John Smith's name in could alter Mr. 
 Smith's data.

 If users can update their own data, should you not have a log in process 
 to ensure that only the original user can update his data? Them once he 
 has logged in, you can populate all fields with data from the DB.

 Jeffrey

 Grae Wolfe - PHP wrote:
 That was the first thing that I was going to do, but there is a concern 
 there for security of the data being input...  This is a registration 
 site, and I don't want to provide information on John Smith to anyone 
 who just happens to put his name in.


 Alejandro Tesone [EMAIL PROTECTED] wrote in message 
 news:[EMAIL PROTECTED]

Why don't you try populating the fields the user intends to modify
with the information you already have?

Alex T

On 6/17/06, Grae Wolfe - PHP [EMAIL PROTECTED] wrote:

Good day!
  I have been working on this little free project for a while, and now 
 I
have hit another major hiccup.  Is there a simple way to only update 
fields
that have something in them?
  The problem that I am having is that if someone fills out information 
 and
submits it, it saves to the DB just fine.  However, if they come back 
later
and just put in, for example, a new phone number, it replaces all of the
other information with blanks.
  Here is my current $sql query:

$sql = UPDATE $table
SET
first_name='$first_name',
last_name='$last_name',
hs_last_name='$hs_last_name',
guest_name='$guest_name',
street_address1='$street_address1',
street_address2='$street_address2',
city='$city',
state='$state',
zip='$zip',
phone1='$phone1',
phone2='$phone2',
email_address='$email_address',
farmers_barn='$farmers_barn',
wrhs_tour='$wrhs_tour',
crystal_rose='$crystal_rose',
registration_comments='$registration_comments',
date_registered='$today'
WHERE first_name='$first_name' AND last_name='$last_name';



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[PHP-DB] Conditional updating...

2006-06-17 Thread Grae Wolfe - PHP
Good day!
  I have been working on this little free project for a while, and now I 
have hit another major hiccup.  Is there a simple way to only update fields 
that have something in them?
  The problem that I am having is that if someone fills out information and 
submits it, it saves to the DB just fine.  However, if they come back later 
and just put in, for example, a new phone number, it replaces all of the 
other information with blanks.
  Here is my current $sql query:

$sql = UPDATE $table
SET
first_name='$first_name',
last_name='$last_name',
hs_last_name='$hs_last_name',
guest_name='$guest_name',
street_address1='$street_address1',
street_address2='$street_address2',
city='$city',
state='$state',
zip='$zip',
phone1='$phone1',
phone2='$phone2',
email_address='$email_address',
farmers_barn='$farmers_barn',
wrhs_tour='$wrhs_tour',
crystal_rose='$crystal_rose',
registration_comments='$registration_comments',
date_registered='$today'
WHERE first_name='$first_name' AND last_name='$last_name'; 



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Re: [PHP-DB] Conditional updating...

2006-06-17 Thread Grae Wolfe - PHP
That was the first thing that I was going to do, but there is a concern 
there for security of the data being input...  This is a registration site, 
and I don't want to provide information on John Smith to anyone who just 
happens to put his name in.


Alejandro Tesone [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]
 Why don't you try populating the fields the user intends to modify
 with the information you already have?

 Alex T

 On 6/17/06, Grae Wolfe - PHP [EMAIL PROTECTED] wrote:
 Good day!
   I have been working on this little free project for a while, and now 
 I
 have hit another major hiccup.  Is there a simple way to only update 
 fields
 that have something in them?
   The problem that I am having is that if someone fills out information 
 and
 submits it, it saves to the DB just fine.  However, if they come back 
 later
 and just put in, for example, a new phone number, it replaces all of the
 other information with blanks.
   Here is my current $sql query:

 $sql = UPDATE $table
 SET
 first_name='$first_name',
 last_name='$last_name',
 hs_last_name='$hs_last_name',
 guest_name='$guest_name',
 street_address1='$street_address1',
 street_address2='$street_address2',
 city='$city',
 state='$state',
 zip='$zip',
 phone1='$phone1',
 phone2='$phone2',
 email_address='$email_address',
 farmers_barn='$farmers_barn',
 wrhs_tour='$wrhs_tour',
 crystal_rose='$crystal_rose',
 registration_comments='$registration_comments',
 date_registered='$today'
 WHERE first_name='$first_name' AND last_name='$last_name';



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[PHP-DB] Forms with letter security

2006-06-16 Thread Ron Piggott (PHP)
I have a set of graphical letters A to Z.  I want some displayed and
then keyed into a security field to verify a person is submitting the
form.  I have seen these used before on shopping carts.  

I know about creating salts to select which letters to choose.

What I am wondering is if there is a way to join the letters together
instead of having 6 different images displayed.

Ron

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Re: [PHP-DB] Select distinct field won't return distinct value

2006-06-06 Thread tg-php
Correct me if I'm wrong, but it sounds like you have something like this:

123  Joe
124  Joe
125  Sue
126  John
127  Joe
128  Frank
129  Sue

And you want to output something like:

Joe  123, 124, 127
Sue  125, 129
John 126
Frank 128

But what you're getting is:

Joe 123
Joe 124
..etc

You have two ways you can solve this:

1. Do two SQL queries:

SELECT DISTINCT cus_name FROM customers

while ($result) {  // forgive the pseudo-code
  SELECT cus_id FROM customers WHERE cus_name = $result['cus_name']
  while ($result2) {
echo $output;
  }
}

Or..

2. Collect data into an array and process 'distinctness' on output

SELECT cus_name, cus_id FROM customers

while ($result) {
  $cus_arr[$cus_name][] = $cus_id;
}

foreach ($cus_arr as $cus_name = $cus_idarr) {
  echo $cus_name as ids: . implode(, , $cusidarr) . br\n;
}

There may be some tricky ways in SQL to get the data the way you want it, but 
ultimately it's not worth the bending over backwards for (do I remember right 
that you can do it with crosstab queries?  don't even know if MySQL will do 
those properly).   Easier just to do it with one of the methods above.

Good luck!

-TG

= = = Original message = = =

I want select distinct field and return value of that field, but I have
problem which is: select distinct returns duplicate value. eg, I wan select
distinct customer name and id from the customer table. one customer may have
different cus_ids since cus_ids are auto increment and depend on the
purchased items. so what I want is to select distinct customer name so that
I can print customer name and customer id once.

here is algorithm;

select distinct cus_name, cus_id from customers order by cus_name asc
While row is not empty do
echoa href=\page?cus=cus_id\costomer name/abr /;



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Re: [PHP-DB] Automatically +1 every 30 mins to a value in the database.

2006-06-02 Thread tg-php
An alternative to cron jobs or scheduled tasks (if they're not an option) is to 
have a marker somewhere (probably in your database) that records a timestamp 
for the last 'gold' update then when someone does get around to accessing the 
database through normal operations, have it figure out how many 30 minute 
periods have occurred between the timestamp and now and update the gold then.

The cron job is preferrable but if you're looking for alternate ideas, there's 
one for ya.

Good luck!

-TG

= = = Original message = = =

Hi there. 
I've posted this up on both this list, and the mysql list as I'm not sure
whether this is something that I'd need to do with the php or mysql.

Basically, I am making an add-on to my small website which is a mini online
game. Every user will have gold, and every 30mins I'd like their amount of
gold to go up by 1 (or say a variable say $goldupdateamount).

I'd like to know which would be the best way of doing this, and if there is
a command in php which would achieve this.

Regards, 
Alex.


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[PHP-DB] Combining Fields

2006-05-31 Thread Grae Wolfe - PHP
Good Day!
  I am trying to use my limited knowledge to create a VERY simple process to 
display some of the information in my table, allow a particular record to be 
selected, then opened on a page with text boxes to edit the information, 
after which the UPDATE command will be used to update the database.
  That being said, I have a way that I think this will work, but I don't 
have a unique record number in my table for each of the entries.  I have 
tried getting PHPMyAdmin to set this up, but I cannot seem to make it work. 
SO - I need to try to create that ID on the fly.  I figured I could just 
combine the first and last names to make this ID, but I am not sure what the 
syntax should be.  Here is the code I have dealing with defining the 
variables...

Any help or thoughts would be splendid!

while ($row = mysql_fetch_array($result)) {
 $id = $row['last_name'],$row['first_name'];
 $fname = $row['first_name'];
 $lname = $row['last_name'];

 $option_block .= option value=\$id\$lname, $fname/option;


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Re: [PHP-DB] Combining Fields

2006-05-31 Thread Grae Wolfe - PHP
Thank you Brad - That is what I was looking for, but now that I see how it 
behaves, I am thinking that it isn't going to work the way I wanted.  I need 
to then be able to pass the ID back to MySQL so that it will retrieve just 
the one record for editing.

I guess I need to go back to making the DB create an auto-incrementing ID 
number.  Hmmm...

Thanks!!


Brad Bonkoski [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]


 Grae Wolfe - PHP wrote:

Good Day!
  I am trying to use my limited knowledge to create a VERY simple process 
 to display some of the information in my table, allow a particular record 
 to be selected, then opened on a page with text boxes to edit the 
 information, after which the UPDATE command will be used to update the 
 database.
  That being said, I have a way that I think this will work, but I don't 
 have a unique record number in my table for each of the entries.  I have 
 tried getting PHPMyAdmin to set this up, but I cannot seem to make it 
 work. SO - I need to try to create that ID on the fly.  I figured I could 
 just combine the first and last names to make this ID, but I am not sure 
 what the syntax should be.  Here is the code I have dealing with defining 
 the variables...

Any help or thoughts would be splendid!

while ($row = mysql_fetch_array($result)) {
 $id = $row['last_name'],$row['first_name'];
 $fname = $row['first_name'];
 $lname = $row['last_name'];

 $option_block .= option value=\$id\$lname, $fname/option;



 Use the dot (.) for appending variables...
 so it would be:
 $id = $row['last_name'].$row['first_name'];
 ...or course if you want that would look like this: 'SmithAdam'
 if you want 'Smith,Adam' as your id then:
 $id = $row['last_name'].,.$row['first_name'];
 -Brad 

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Re: [PHP-DB] Combining Fields

2006-05-31 Thread Grae Wolfe - PHP
Again, my many thanks - I didn't know about the 'explode' function - that 
may be a huge help.

Hopefully, I am on the right track now...  thanks!



Brad Bonkoski [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]


 Grae Wolfe - PHP wrote:

Thank you Brad - That is what I was looking for, but now that I see how it 
behaves, I am thinking that it isn't going to work the way I wanted.  I 
need to then be able to pass the ID back to MySQL so that it will 
retrieve just the one record for editing.

I guess I need to go back to making the DB create an auto-incrementing ID 
number.  Hmmm...

Thanks!!


 Well, the unique ID would probably be the *best* way to go, but you could 
 also get the record with the below solution, of course this requires every 
 combination of first and last name is unique...
 if you do:
 $id = Smith,Adam
 Then:
 list($fname, $lname) = explode(,,$id);
 select * from table where first_name = '$fname' and last_name='$lname'
 would do the trick...
 Of course this has many what-ifs asociated with it...all of which would 
 be taken care of with an auto-incrementing/primary key ID field for wach 
 record ;-)

 -Brad

Brad Bonkoski [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]

Grae Wolfe - PHP wrote:


Good Day!
 I am trying to use my limited knowledge to create a VERY simple process 
 to display some of the information in my table, allow a particular 
 record to be selected, then opened on a page with text boxes to edit 
 the information, after which the UPDATE command will be used to update 
 the database.
 That being said, I have a way that I think this will work, but I don't 
 have a unique record number in my table for each of the entries.  I 
 have tried getting PHPMyAdmin to set this up, but I cannot seem to make 
 it work. SO - I need to try to create that ID on the fly.  I figured I 
 could just combine the first and last names to make this ID, but I am 
 not sure what the syntax should be.  Here is the code I have dealing 
 with defining the variables...

Any help or thoughts would be splendid!

while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];

$option_block .= option value=\$id\$lname, $fname/option;




Use the dot (.) for appending variables...
so it would be:
$id = $row['last_name'].$row['first_name'];
...or course if you want that would look like this: 'SmithAdam'
if you want 'Smith,Adam' as your id then:
$id = $row['last_name'].,.$row['first_name'];
-Brad

 

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[PHP-DB] Processing a web form / loop etc.

2006-05-30 Thread Ron Piggott (PHP)


I have a web form that accepts up to 3 suggested categories.  In the
form they are part of I have named these variables 

$suggested_category_1
$suggested_category_2
$suggested_category_3

I have come up with this simple code to store the suggestion in a table:

if ( $suggested_category_1   ) {
#the user could leave the suggestion blank because what is already
provided is sufficient

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( Unable to select database);
$query = INSERT INTO table_name VALUES ( '$variable' ,
'$reference_number', '$suggested_category_1');
mysql_query($query);
mysql_close();

}

Is there any way to create a loop to check all three instead of me
repeating this code twice more changing $suggested_category_1 to _2 and
_3 ?

Ron

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Re: [PHP-DB] Processing a web form / loop etc.

2006-05-30 Thread Ron Piggott (PHP)
Hi Stutt

Thanks.  

I hadn't included much of the code for easy reading.

I just had to use the $_POST[$val] to get the actual values.  

Thanks for your help. 

Ron



for ($num = 1; $num = 3; $num++)
{
$varname = 'suggested_category_'.$num;
$val = $$varname;
// Stick your code here replacing references to the 
$suggested_category_1 var with $val
}

Incidentally, I do hope that code was simplified for brevity. There 
should be extensive use of mysql_real_escape_string in there.

-Stut

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Re: [PHP-DB] MySQL/PHP Left Join Question

2006-05-25 Thread tg-php
One thing I've done in situations like this is just load your returned DB data 
into an array.  Something like this would do:


$dvdarr[$result['call_number']]['Title'] = $result['title'];
$dvdarr[$result['call_number']]['Publisher'] = $result['publisher'];
$dvdarr[$result['call_number']]['Comments'][] = $result['comment'];


Put that in a loop of your results.  Notice the [] on the comments.  That'll 
collect all your comments under the umbrella of 'Comments'.

Then when you go to do your output, you'd do something like this:

forach ($dvdarr as $callnumber = $dvddata) {
  $title = $dvddata['Title'];
  $publisher = $dvddata['Publisher'];
  $comments = $dvddata['Comments'];
  foreach ($comments as $comment) {
// do whatever
  }
}


There are other ways to handle this.. this might be one of the easier ones (if 
I'm understanding your problem correctly).

-TG

= = = Original message = = =

Hello, all.  I don't know if this is a php-mysql question or just a
mysql, but here goes:

I have a list of DVDs that my library loans out, and I'd like to allow
people to add comments to each item.  Since this list gets regenerated
periodically (it's extracted from another system, the library
catalog), there isn't a consistent ID in the dvd tables, so I'm using
the call number (which will look like DVD 2324) as the key.  Anyhow, I
join the tables like this to get all the DVDs and all the comments
associated with the DVDs:

SELECT distinct dvds.title, dvds.publisher, dvds.publication_date,
dvds.call_number,
comment.id, comment.parent_id, comment.comment, comment.name
FROM dvds
LEFT JOIN comment
ON dvds.call_number=comment.parent_id
WHERE dvds.title LIKE 'A%'
ORDER BY dvds.title

With this, I'll get results like

DVD 101A.I.   This movie rocked
DVD 101A.I.   This Movie stunk
DVD 102Adaptation  . . .
DVD 103After Hours . . .

When I loop in PHP through the records, of course, I want just the one
DVD with however many comments associated with it.  Is it possible to
do this (i.e., screen out DVD dupes) in MySQL, or do I have to do it
in PHP?

If this is a dumb question, my humblest apologies, and I'd be
interested if there was a better way to handle this . . . .

Andrew


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Re: [PHP-DB] Adding url to google

2006-05-12 Thread tg-php
Sounds like you're asking how to programmatically add your web site to Google's 
search.  I didn't dig very deep, but it doesn't look like Googles API provides 
for the ability to submit (only search) and by Google's addurl page 
(http://www.google.com/addurl/?continue=/addurl) it appears that they don't 
want you to be able to automate the adding of URLs or else they wouldn't be 
using CAPTCHA methods to prevent bots from spamming them.

You may look into software like SubmitWolf or some of the others that automate 
submissions and try to figure out how they do it (if at all) but I'm guessing 
it's not going to really be feasible for you to do this... not easily at least.

-TG



= = = Original message = = =

Hi all,

I am developing the site using php and mysql. I have to add the url at
google site through php code.

If any one have idea about it, please help me.

Regards
Manoj


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[PHP-DB] Too stupid to UPDATE...

2006-05-12 Thread Grae Wolfe - PHP
I am trying to write a script to handle event registration.  Most of the 
people that will be registering are already in the database, but not all, 
and those that are may not have current information.

Here is my latest effort, or at least a snippet of it...  Can anyone point 
out where I went stupid, or if there is a better way of doing this? 
THANKS!!!

===---  BEGIN SNIPPET  ---===

$db = @mysql_select_db($dbname, $connection) or die(Couldn't Select 
Database.);

$link = mysql_connect($server, $user, $pass);
mysql_select_db($dbname, $link);

$result = mysql_query(SELECT * FROM $table WHERE first_name='$first_name' 
AND hs_last_name='$hs_last_name' AND last_name='$last_name', $link);
$num_rows = mysql_num_rows($result);

if($num_rows) {

$sql = UPDATE $table SET first_name=\$first_name\, 
last_name=\$last_name\, hs_last_name=\$hs_last_name\, 
guest_name=\$guest_name\, street_address1=\$street_address1\, 
street_address2=\$street_address2\, city=\$city\, state=\$state\, 
zip=\$zip\, phone1=\$phone1\, phone2=\$phone2\, 
email_address=\$email_address\, number_attending=\$number_attending\, 
payment=\$payment\, registration_comments=\$registration_comments\, 
date_registered=\$today\ WHERE first_name=\$first_name\ AND 
last_name=\last_name\;

$result = @mysql_query($sql,$connection) or die(Couldn't Execute Query.);

 }
 else {

$sql = INSERT INTO $table
(first_name, last_name, hs_last_name, guest_name, street_address1, 
street_address2, city, state, zip, phone1, phone2, email_address, 
number_attending, payment, registration_comments, date_registered)
VALUES
(\$first_name\, \$last_name\, \$hs_last_name\, \$guest_name\, 
\$street_address1\, \$street_address2\, \$city\, \$state\, \$zip\, 
\$phone1\, \$phone2\, \$email_address\, \$number_attending\, 
\$payment\, \$registration_comments\, \$today\)
;

$result = @mysql_query($sql,$connection) or die(Couldn't Execute Query.);

===---  END SNIPPET  ---=== 

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Re: [PHP-DB] Too stupid to UPDATE...

2006-05-12 Thread tg-php
Don't have time to totally disect it, but you might change the if($num_rows) 
to if($num_rows  0) just to make sure.

Also, try echoing out your SQL statement to check and make sure things like 
$table got a real value or other silly things.

Lastly, I usually use single quotes for SQL statements.. in this case, it would 
simplify your PHP SQL statement by removing the necessity to escape all the 
double quotes \

If you echo the SQL and it looks ok, try running it manually through mysql's 
command line or via a program like WinSQL Lite on Windows to try to isolate if 
it's the query or your PHP.

Good luck!

-TG

= = = Original message = = =

I am trying to write a script to handle event registration.  Most of the 
people that will be registering are already in the database, but not all, 
and those that are may not have current information.

Here is my latest effort, or at least a snippet of it...  Can anyone point 
out where I went stupid, or if there is a better way of doing this? 
THANKS!!!

===---  BEGIN SNIPPET  ---===

$db = @mysql_select_db($dbname, $connection) or die(Couldn't Select 
Database.);

$link = mysql_connect($server, $user, $pass);
mysql_select_db($dbname, $link);

$result = mysql_query(SELECT * FROM $table WHERE first_name='$first_name' 
AND hs_last_name='$hs_last_name' AND last_name='$last_name', $link);
$num_rows = mysql_num_rows($result);

if($num_rows) 

$sql = UPDATE $table SET first_name=\$first_name\, 
last_name=\$last_name\, hs_last_name=\$hs_last_name\, 
guest_name=\$guest_name\, street_address1=\$street_address1\, 
street_address2=\$street_address2\, city=\$city\, state=\$state\, 
zip=\$zip\, phone1=\$phone1\, phone2=\$phone2\, 
email_address=\$email_address\, number_attending=\$number_attending\, 
payment=\$payment\, registration_comments=\$registration_comments\, 
date_registered=\$today\ WHERE first_name=\$first_name\ AND 
last_name=\last_name\;

$result = @mysql_query($sql,$connection) or die(Couldn't Execute Query.);

 
 else 

$sql = INSERT INTO $table
(first_name, last_name, hs_last_name, guest_name, street_address1, 
street_address2, city, state, zip, phone1, phone2, email_address, 
number_attending, payment, registration_comments, date_registered)
VALUES
(\$first_name\, \$last_name\, \$hs_last_name\, \$guest_name\, 
\$street_address1\, \$street_address2\, \$city\, \$state\, \$zip\, 
\$phone1\, \$phone2\, \$email_address\, \$number_attending\, 
\$payment\, \$registration_comments\, \$today\)
;

$result = @mysql_query($sql,$connection) or die(Couldn't Execute Query.);

===---  END SNIPPET  ---=== 


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[PHP-DB] Sending filing attachments using PHP

2006-05-11 Thread Ron Piggott (PHP)
Does any one know how to send a file attachment using PHP?  

I have been using the mail() command to send e-mail in various scripts,
but have spotted a file attachment syntax to use on the php web page.

Ron

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[PHP-DB] auto_increment

2006-05-01 Thread Ron Piggott (PHP)


How do I change the auto_increment / auto_index value?  Ron

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Re: [PHP-DB] auto_increment

2006-05-01 Thread Ron Piggott (PHP)
I am using mySQL

On Mon, 2006-05-01 at 13:21 +, replies-lists-
[EMAIL PROTECTED] wrote:
 
  Original Message 
  Date: Monday, May 01, 2006 09:14:36 AM -0400
  From: Ron Piggott (PHP) [EMAIL PROTECTED]
  Subject: [PHP-DB] auto_increment
  
  How do I change the auto_increment / auto_index value?  Ron
 
 -- End Original Message --
 
 that depends on the database you're using -- and probably best asked on
 the appropriate db-specific mailing list.
 
 

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[PHP-DB] Web forms

2006-04-14 Thread Ron Piggott (PHP)
I am creating some web based functions for the staff and volunteers to
use.  Access to these functions is designated by those who need it.

I have two tables.  

One table describes the component --- It has a component reference
number column.  

The second table indicates who has access to what --- containing the
component reference number from the component table (described above)
and also the member reference number.  

Essentially if you are logged in your reference number is in a session
variable and using PHP  mySQL the script is checking to see which
components to allow you access to in your menu and only displaying those
menu options.

So far I have been updating this table using phpmyadmin.  I have begun
writing a script to do this in a more smooth fashion.

The script I am writing produces a form in a table.

Column 1 shows the component name.  Column 2 is a check box for the user
to check in if the person whose permissions are being modified should
have access to this component.  I have named the check box the component
reference number --- 1 for example.  There are about 16 components are
growing.  

I am not sure how to check if $1 = on indicating the check box was
checked in.  I know you would use an IF ( ) { } statement --- but I want
to automate this so when new components are added in I want have to
modify the script which actually updates who has access to what
component.

What I have done so far is selected all the components and started a
WHILE loop --- $i will go from 0 to 15 so I am able to look at each
check box to see if it was selected or not and then I am going to use
the INSERT INTO or DELETE commands to update the table, etc.

How can I find out if $1 and $2 and $3 and ... $15 are on?

Ron

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[PHP-DB] Search / Replace using PHP

2006-03-30 Thread Ron Piggott (PHP)
Is there a command in PHP that is equal to the search  replace function
in a word processor?

If I want to search for 'this' and replace it with 'that' what would the
syntax be?

Ron

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[PHP-DB] Ye old $_SESSION variables :)

2006-03-12 Thread Ron Piggott (PHP)
I am wondering if

form method=POST 

causes the

session_id();

to change or be reset.

Some how my $_SESSION[''] variables are dumping when I use the POST
command above.  

More importantly I am not sure what to do about it.  

Any ideas?

Ron

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Re: [PHP-DB] Excel to CSV

2006-03-11 Thread tg-php
The other response is half correct..   I havn't seen anything to read data from 
Excel with PHP (although it's technically possible, just kind of complicated) 
so the easiest solution is to use Excel and just have it load the file and save 
it in CSV format.

The part that's not entirely correct is the PHP can't talk to Excel part.  
It's cumbersome, but PHP can use a COM connection to control Excel (or Word or 
MapPoint or Access or Outlook..etc).  This means you'd have to have Excel 
loaded on the server that was running PHP, which may not be an option.

For an example of PHP + COM with Excel, check out:

http://www.php.net/manual/en/class.com.php

Look down the page for the entry posted by flintjt at hotmail dot com

If COM doesn't work for you and you don't mind getting your hands dirty, I 
believe you can get the Excel file format spec.. maybe through the OpenOffice 
sources.. and figure out how to read XLS files that way.

The Excel Object Model might help you with the proper properties/methods/etc:
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/dv_wrcore/html/wrgrfexcelworkbookobject.asp

Good luck.

-TG

= = = Original message = = =

Dear All,

Have you any script/example how to Save As Excel file to CSV using PHP?

Thanks  Regards,

Anita

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[PHP-DB] unescape a string

2006-03-10 Thread Ron Piggott (PHP)
Is there a way to unescape a string once the command

mysql_real_escape_string($variable);

has been used on it?  (This is to display it to the screen, instead of
sending it to the database.)

Ron

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[PHP-DB] Renaming a table once it has been created

2006-03-08 Thread Ron Piggott (PHP)
Is there a way to re-name a table once you have created it?  Ron

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Re: [PHP-DB] Installing PEAR

2006-03-03 Thread tg-php
I remember the quick install/test I did using PEAR and I kind of had a similar 
experience, but I figured out what the issue was for me.

PEAR installed perfectly but doing the pear install thing where it pulls the 
package down and puts it where it needs to put it, I was doing what you were 
doing pear packagename and it wasn't working.

What fixed it for me was adding the version number to the end of the name.  
Looks like PEAR DB is at 1.7.6, so try something like:

pear install db1.7.6


But it also sounds like maybe you're not getting the pear install to work 
properly too.  So maybe you need to fix something else before you get to this 
point.  Just wanted to mention it to prevent a potential extra frustration for 
you.

Back to work for me.. working late on a Friday sucks.. so forgive me if I'm not 
entirely helpful.. just wanted to pass that nugget along in case it was useful.

-TG


= = = Original message = = =

I know this may be a bit off-topic, but I would like to use the PEAR library
to implement some of my database functions. Unfortunately, the PEAR
documentation is woefully incomplete and as a result i've been unable to
install it properly. Here's the procedure i went through:
 
PHP Version: 5.1.2
Apache Version: 2.0.55
MySQL Version: 5.0.18
Windows XP Pro
 
1. launch the go-pear batch file
2. select system-wide installation
3. use default install directories: (Seems fine to me since PHP is installed
into C:\PHP)
Installation Base ($prefix) C:\PHP
Binaries DirectoryC:\PHP
PHP code Directory ($php_dir)  C:\PHP\pear
Documentation Directory  C:\PHP\pear\docs
Data Directory C:\PHP\pear\data
Tests DirectoryC:\PHP\pear\tests
Name of Configuration FileC:\WINDOWS\pear.ini
Path to CLI php.exe C:\PHP\.
 
4. The batch file tells me pear is installed
5. I add the environment variable via the PEAR_ENV.reg file
6. add the line require db.php and load to this message:
Warning: require(DB.php) [function.require
http://localhost/function.require ]: failed to open stream: No such file
or directory in C:\wwwroot\phpinfo.php on line 2
Fatal error: require() [function.require http://localhost/function.require
]: Failed opening required 'DB.php' (include_path='.;C:\PHP\pear') in
C:\wwwroot\phpinfo.php on line 2 
7. Figure DB might not be installed by default, so follow the website's
instructions by attempting to call it from the command line:
pear install db = not recognized as internal or external command, bla bla
bla
c:\php\pear install db = see above
c:\php\pear\pear install db = see above
8. get annoyed, go back to phpinfo file, remove erroneous line and look for
references to PEAR, come up with the following (only) line:
  include_path~.;C:\PHP\pear~.;
C:\PHP\pear
9. Go crazy, hit cute, fuzzy animals.
 
I apolagize for the length of my e-mail, but I know that being thorough
helps most of the time. Does anyone have any advice or ideas?


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Re: [PHP-DB] Duplicate rows

2006-03-01 Thread tg-php
Depends on how you determine if something's a duplicate or not.  For example, 
if it's just one column that can be used, you can do something like this:

select ItemName, count(ItemName) from ItemListTable group by ItemName
having count(ItemName)  1


That'll show you if ItemName is repeated.   Then you can go back through and 
just search for ItemName and remove the ones you don't want.

You can do pretty much the same thing as above but CONCATenating multple 
columns if that's what you need to do to determine uniqueness.

I know you're dealing with 15k rows still, so you probably want something a 
little more automated.

Without more info though, it's hard to say exactly what can be done.

Hope that helps a little bit.

-TG

= = = Original message = = =

My dear beloved friends,

I have a catalog of products that a product provider gave, sadly for me, in
this CSV file there are many duplicated rows.
I edited the file in my Linux system with the uniq -u command, and it
worked somewhat fine, it eliminated some duplicated rows, originally the
file had 24K rows, and now it has been reduced to 15k rows.

Anyhow, there are still duplicated rows, and since this is a catalog, it
should not have duplicated rows!!!
Now the catalog has been has been loaded into the DB.

How can I continue eliminating duplicated rows?
As far as I remember the is a sentence in SQL to only show ONE row of
duplicated rows, maybe if I do a select using this sentence and then put
this new recordset in another table, it will work!!

Any ideas?

---
Miguel Guirao Aguilera
Logistica R8 TELCEL
Tel. (999) 960.7994


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Re: [PHP-DB] Duplicate rows

2006-03-01 Thread tg-php
Haha.. oh yeah.. DISTINCT works too..  in this case you'd get a list of all 
totally 100% unique records.

If you had an auto_increment column though, you'd want to exclude it from the 
list.

-TG

= = = Original message = = =

SELECT DISTINCT * FROM `tablename`


On Wednesday 01 March 2006 7:24 am, Miguel Guirao wrote:
 My dear beloved friends,

 I have a catalog of products that a product provider gave, sadly for me, in
 this CSV file there are many duplicated rows.
 I edited the file in my Linux system with the uniq -u command, and it
 worked somewhat fine, it eliminated some duplicated rows, originally the
 file had 24K rows, and now it has been reduced to 15k rows.

 Anyhow, there are still duplicated rows, and since this is a catalog, it
 should not have duplicated rows!!!
 Now the catalog has been has been loaded into the DB.

 How can I continue eliminating duplicated rows?
 As far as I remember the is a sentence in SQL to only show ONE row of
 duplicated rows, maybe if I do a select using this sentence and then put
 this new recordset in another table, it will work!!

 Any ideas?

 ---
 Miguel Guirao Aguilera
 Logistica R8 TELCEL
 Tel. (999) 960.7994


 Este mensaje es exclusivamente para el uso de la persona o entidad a quien
 esta dirigido; contiene informacion estrictamente confidencial y legalmente
 protegida, cuya divulgacion es sancionada por la ley. Si el lector de este
 mensaje no es a quien esta dirigido, ni se trata del empleado o agente
 responsable de esta informacion, se le notifica por medio del presente, que
 su reproduccion y distribucion, esta estrictamente prohibida. Si Usted
 recibio este comunicado por error, favor de notificarlo inmediatamente al
 remitente y destruir el mensaje. Todas las opiniones contenidas en este
 mail son propias del autor del mensaje y no necesariamente coinciden con
 las de Radiomovil Dipsa, S.A. de C.V. o alguna de sus empresas controladas,
 controladoras, afiliadas y subsidiarias. Este mensaje intencionalmente no
 contiene acentos.

 This message is for the sole use of the person or entity to whom it is
 being sent.  Therefore, it contains strictly confidential and legally
 protected material whose disclosure is subject to penalty by law.  If the
 person reading this message is not the one to whom it is being sent and/or
 is not an employee or the responsible agent for this information, this
 person is herein notified that any unauthorized dissemination, distribution
 or copying of the materials included in this facsimile is strictly
 prohibited.  If you received this document by mistake please notify 
 immediately to the subscriber and destroy the message. Any opinions
 contained in this e-mail are those of the author of the message and do not
 necessarily coincide with those of Radiomovil Dipsa, S.A. de C.V. or any of
 its control, controlled, affiliates and subsidiaries companies. No part of
 this message or attachments may be used or reproduced in any manner
 whatsoever.


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[PHP-DB] Writing to a file

2006-02-25 Thread Ron Piggott (PHP)
I wonder if someone would tell me the command in PHP that allows me to
write to a file --- for example test.txt  Just for this example I
would like the word apple to be the contents of test.txt

Now if I want to re-create test.txt --- erasing all the contents and
start over and this time have the word orange in it how would you do
this?  

What commands do you use?

Thanks for your help.

Ron

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[PHP-DB] Numbers to words

2006-02-09 Thread Ron Piggott (PHP)
Is there a command within PHP that would convert numbers to words:

echo 1;

# 1 appears on screen

echo command('1');

# one appears on screen --- what would the command be?

Ron

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[PHP-DB] Re: Numbers to words

2006-02-09 Thread Ron Piggott (PHP)
I did some searching and found the function on the PHP web site.  Ron

?
/**
* convert long integer into American English words.
* e.g. -12345 - minus twelve thousand forty-five
* Handles negative and positive integers
* on range -Long.MAX_VALUE .. Long.MAX_VALUE;
* It cannot handle Long.MIN_VALUE;
*/

function num2words( $num ){
   $ZERO = zero;
   $MINUS = minus;
   $lowName = array(
 /* zero is shown as  since it is never used in combined forms
*/
 /* 0 .. 19 */
 , one, two, three, four, five,
 six, seven, eight, nine, ten,
 eleven, twelve, thirteen, fourteen, fifteen,
 sixteen, seventeen, eighteen, nineteen);

   $tys = array(
 /* 0, 10, 20, 30 ... 90 */
 , , twenty, thirty, forty, fifty,
 sixty, seventy, eighty, ninety);

   $groupName = array(
 /* We only need up to a quintillion, since a long is about 9 *
10 ^ 18 */
 /* American: unit, hundred, thousand, million, billion,
trillion, quadrillion, quintillion */
 , hundred, thousand, million, billion,
 trillion, quadrillion, quintillion);

   $divisor = array(
 /* How many of this group is needed to form one of the
succeeding group. */
 /* American: unit, hundred, thousand, million, billion,
trillion, quadrillion, quintillion */
 100, 10, 1000, 1000, 1000, 1000, 1000, 1000) ;

   $num = str_replace(,,,$num);
   $num = number_format($num,2,'.','');
   $cents = substr($num,strlen($num)-2,strlen($num)-1);
   $num = (int)$num;

   $s = ;

   if ( $num == 0 ) $s = $ZERO;
   $negative = ($num  0 );
   if ( $negative ) $num = -$num;

   // Work least significant digit to most, right to left.
   // until high order part is all 0s.
   for ( $i=0; $num0; $i++ ) {
   $remdr = (int)($num % $divisor[$i]);
   $num = $num / $divisor[$i];
   // check for 1100 .. 1999, 2100..2999, ... 5200..5999
   // but not 1000..1099,  2000..2099, ...
   // Special case written as fifty-nine hundred.
   // e.g. thousands digit is 1..5 and hundreds digit is 1..9
   // Only when no further higher order.
   if ( $i == 1 /* doing hundreds */  1 = $num  $num = 5 ){
   if ( $remdr  0 ){
   $remdr += $num * 10;
   $num = 0;
   } // end if
   } // end if
   if ( $remdr == 0 ){
   continue;
   }
   $t = ;
   if ( $remdr  20 ){
   $t = $lowName[$remdr];
   }
   else if ( $remdr  100 ){
   $units = (int)$remdr % 10;
   $tens = (int)$remdr / 10;
   $t = $tys [$tens];
   if ( $units != 0 ){
   $t .= - . $lowName[$units];
   }
   }else {
   $t = $inWords($remdr);
   }
   $s = $t .   . $groupName[$i] .. $s;
   $num = (int)$num;
   } // end for
   $s = trim($s);
   if ( $negative ){
   $s = $MINUS .   . $s;
   }

   $s .=  and $cents/100;

   return $s;
} // end inWords
?

On Thu, 2006-02-09 at 22:18 -0500, Ron Piggott (PHP) wrote:
 Is there a command within PHP that would convert numbers to words:
 
 echo 1;
 
 # 1 appears on screen
 
 echo command('1');
 
 # one appears on screen --- what would the command be?
 
 Ron

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Re: [PHP-DB] screen resolution!

2006-02-05 Thread PHP Superman
Or you can have a page which detects resolution by javascript and redirects
to another PHP page with the resolution data

On 2/4/06, Bastien Koert [EMAIL PROTECTED] wrote:


 As the other poster mentioned you need JS to detect the screen
 widththe
 usual approach is to use js to detect the screen res and the include the
 appropriate CSS file to match the screen res.

 Bastien


 From: JeRRy [EMAIL PROTECTED]
 To: php-db@lists.php.net
 Subject: [PHP-DB] screen resolution!
 Date: Sun, 5 Feb 2006 02:44:19 +1100 (EST)
 
 Hi,
 
I have written a website in PHP using MYSQL.  But I have come accross
 an
 un-common problem.  Normally when I create a website it's done on a
 desktop
 PC.  But this time for the first time I did it on laptop meaning the
 screen
 resolution is different.
 
Is there any sort of script/code I can use to create another section
 of
 my site in a desired screen resolution without me having to do it all
 manually?
 
I know of many scripts online that I can DETERMINE visitors screen
 resolutions and recommend the correct one but don't know one that will
 adjust the website to suit that visitors screen resolution.  Am aware of
 scripts that redirect to another web page but that requires you to write
 the website again to cater for that.
 
Is there a quicker way/solution?
 
Thanks!
 
J

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Hi Everyone, I am running PHP 5 on Windosws XP SP2 with MySQL5, Bye Now!


Re: [PHP-DB] Getting PHP 5 w/mysqli to communicate with MySQL 5

2006-01-22 Thread PHP Superman
did you turn on display_errors and set error reporting to E_ALL in php.ini?
if not you should

On 1/20/06, Allen Schultz [EMAIL PROTECTED] wrote:

 Sorry, I was in a rush to work guys.

 All these were downloaded pre-compliled for Win32.
 Apache 2.0.55
 PHP 5.1.1 w/php_mysqli.dll (improved mysql)
 MySQL 5.0.18

 This script:

 htmlhead/headbody
 ?php
 $link = mysqli_connect('localhost','root','xx');
 if (mysqli_connect_errno()) {
 echo error;
 exit();
 } else { echo no error; }
 ?
 /body/html

 turns into this:

 htmlhead/headbody
 no error
 /body/html

 And this script:

 htmlhead/headbody
 ?php
 $link = mysqli_connect('localhost','root','xx');
 if (mysqli_connect_errno()) {
 echo error;
 exit();
 }
 if (!mysqli_select_db($link,pers)) {
 echo pers not found; }
 else {
 if ($result = mysqli_multi_query($link, select helloworld();)) {
$row = mysqli_fetch_array($result, MYSQLI_NUM);
echo $row[0];
 } else { echo problem :(; }
 }
 ?
 /body/html

 turns to this:

 htmlhead/headbody
 /body/html

 In summary again, It seems to want to connect to the database, but
 doesnt see anything after connecting using mysqli functions. That
 helloworld() function in the database exists.
 I'm following this page for a tutorial to find out why I cant use the
 database:

 http://mysql.gilfster.com/page.php?parent_id=4page_id=4.0.2

 On 1/19/06, Julien Bonastre [EMAIL PROTECTED] wrote:
  If you only compiled php with the mysqli libraries then you need to use
  them
 
  What exactly are you have troubles with? A code snippet or version
  examples would be good. Also is your database mysql5 engine I take it?

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[PHP-DB] auto_increment and INSERT INTO

2006-01-21 Thread Ron Piggott (PHP)
I have various tables where a column is set to auto_increment in my
table structure.  I have been using the following INSERT query format: 

INSERT INTO table VALUES ('$auto_increment_variable','$variable_1',
'$variable_2')

and then in applications where I have needed to know the value of the
$auto_increment_variable I have immediately queried the table for
$variable_1 and $variable_2 and used

$reference = mysql_result($result,$i,reference);

to determine what numeric value was assigned.

Is there a way I may find out what value was assigned to the
$auto_increment_variable when the INSERT INTO query is issued?

Thanks.

Ron

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Re: [PHP-DB] auto_increment and INSERT INTO

2006-01-21 Thread Ron Piggott (PHP)
That is the function I was looking for.  Thanks.  Ron

On Sat, 2006-01-21 at 23:47 -0500, [EMAIL PROTECTED] wrote:
 Try:
 
 ?php
   mysql_query(INSERT INTO table VALUES ('$variable_1', '$variable_2'););
   $auto_increment_variable = mysql_insert_id();
 ?
 
 
 -TG
 
 
 
 
 = = = Original message = = =
 
 I have various tables where a column is set to auto_increment in my
 table structure.  I have been using the following INSERT query format: 
 
 INSERT INTO table VALUES ('$auto_increment_variable','$variable_1',
 '$variable_2')
 
 and then in applications where I have needed to know the value of the
 $auto_increment_variable I have immediately queried the table for
 $variable_1 and $variable_2 and used
 
 $reference = mysql_result($result,$i,reference);
 
 to determine what numeric value was assigned.
 
 Is there a way I may find out what value was assigned to the
 $auto_increment_variable when the INSERT INTO query is issued?
 
 Thanks.
 
 Ron
 
 
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[PHP-DB] SELECT

2006-01-20 Thread Ron Piggott (PHP)
Yesterday I asked how to get the date  time 90 minutes ago and I
received several responses.  Thanks.

I don't think this select statement is working correctly.  (Correctly
being what I am intending it to do)

I took a look at the table this morning.  One record remains that was
created 2006-01-19 at 23:55:37.  These are the values of date_created
and time_created.  The current values are approximately 2006-01-20 and
05:50:00

This is the select statement I am writing about:

SELECT * FROM `table` WHERE `date_created` = '$date_90_minutes_ago' AND
`time_created` = '$time_90_minutes_ago'

Intellectually I know the problem: 05:50:00 is much earlier than
23:55:37 ... thus my AND is not allowing both conditions to exist
together.

Is there a way that I may modify this SELECT statement so the present
conditions continue to exist and add a second part to the SELECT
statement that if the time is 01:30:00 or higher that records from the
previous day are selected?  This continues to allow the 90 minute time
frame for users logged into my web site ... I am not sure how you would
add an OR function to the above without messing up what presently
works :)

(I am writing a SESSION function for my web site using mySQL and a cron.
The select statement I quoted above is part of the cron.)

Ron

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Re: [PHP-DB] Storing money values in MySQL

2006-01-20 Thread tg-php
Thanks Balazs and David.. I think that's exactly what I was looking for.  I 
searched for hours (and I consider myself a fairly decent researcher) and was 
just getting frustrated..hah..   I think my problem was I was searching for 
money and float problems and such and not monetary.  I think that's the 
keyword that would have done it for me.

I appreciate the help guys!  Best of luck to both of you (and anyone else I 
inadvertantly missed who may have responded).

-TG

= = = Original message = = =

Me again,

Sorry for the rtfm stuff, I googled around and found this:

http://bugs.mysql.com/bug.php?id=10719

and another thing, maybe worth a try; MySQL stores decimal numbers as
strings...did you try to input decimals as string? I mean not:

UPDATE SomeTable SET AmtOwed = 10.74

but:

UPDATE SomeTable SET AmtOwed = '10.74'

Bye,

Balazs


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[PHP-DB] Length of variable

2006-01-20 Thread Ron Piggott (PHP)
Is there a way I may find out how many characters 

$variable

is long after it has been submitted through a web form?

Ron

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[PHP-DB] Date Time 90 minutes ago

2006-01-19 Thread Ron Piggott (PHP)
Would someone be able to help me with the DATE command syntax to know
what the date and time was 90 minutes ago?  I am trying to assign these
values into two variables:

$date_90_minutes_ago
$time_90_minutes_ago

I am not sure how to handle midnight where if the time is 00:10:00
ninety minutes earlier is a day before.  Thanks.  Ron

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RE: [PHP-DB] Date Time 90 minutes ago

2006-01-19 Thread tg-php
Bastien's example is probably the quickest and easiest.  I just wanted to point 
out that you can use math within the mktime() function as well in case the 
relative date/time you need isn't right now.

$month = 1;
$day = 19;
$year = 2006;
$hour = 17;
$minute = 08;
$second = 05;

echo date(Y-m-d H:i:s, mktime($hour, $minute - 90, $second, $month, $day, 
$year));

It will even adjust for leap years I believe.  You can add/subtract/etc any of 
those items and it's smart enough to figure out what the correct resulting 
date/time would be.

-TG


= = = Original message = = =

?php
echo date(Y-m-d H:i:s,strtotime(90 minutes ago));
?

bastien


From: Ron Piggott (PHP) [EMAIL PROTECTED]
Reply-To: [EMAIL PROTECTED]
To: PHP DB php-db@lists.php.net
Subject: [PHP-DB] Date  Time 90 minutes ago
Date: Thu, 19 Jan 2006 16:57:33 -0500

Would someone be able to help me with the DATE command syntax to know
what the date and time was 90 minutes ago?  I am trying to assign these
values into two variables:

$date_90_minutes_ago
$time_90_minutes_ago

I am not sure how to handle midnight where if the time is 00:10:00
ninety minutes earlier is a day before.  Thanks.  Ron

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[PHP-DB] Storing money values in MySQL

2006-01-19 Thread tg-php
Again.. your forgiveness. This is a MySQL question. If the MySQL mailing lists 
would include a [MySQL Help] tag in their subject lines, I'd use them.  What I 
receive from them is difficult to distinguish from spam half the time so I gave 
up.

We had a problem a few months ago and now I can't find my notes relating to it. 
 The problem we had involved storing money data as either float or decimal and 
having the 'cents' round improperly.   And it wasn't just a matter of 10.05 
becoming 10.06, it was something along the lines of 10.05 becoming 10.12.

This was when just a straight UPDATE was performed.  I remember doing it 
manually, not even through PHP, using absolutely no math functions, just a 
totally straight:

UPDATE SomeTable SET AmtOwed = 10.74

Someone made a recommendation of never use SOMETYPE for money.. you should use 
SOMEOTHERTYPE instead.

I've spent the better part of the afternoon trying to find my notes, recreate 
the bug in our database, search online for the discussion I had then or other 
information about this.  So far I'm coming up empty.

We're retooling some of our database and trying to make it more efficient and 
accurate and this is on the list of things to doublecheck.  If anyone has any 
comments, criticisms, information, etc... I'd love to hear them.

We're running MySQL 4.1.11-standard.

Thanks!

-TG

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Re: [PHP-DB] Refreshing text question!

2006-01-18 Thread tg-php
Two ways I can think of to update part of a page without doing a full refresh:

1. Use an IFRAME so you're technically updating a page, but it's the page 
within the frame (not my favorite but works ok)

2. Or you can use asynchronous javascript (AJAX) to update just that one 
section of the page without doing a refresh.  Here's Rasmus' great primer on 
AJAX, should be easy enough to follow:

http://www.time.gov/timezone.cgi?Eastern/d/-5/java

One note I'd like to make that doesn't seem to be mentioned in a lot of AJAX 
tutorials.  If the page your AJAX is calling doesn't have the standard do not 
cache tags, you sometimes won't get the results you want.. especially with 
Internet Explorer (in my experience).

Here's a block I copy/pasted from somewhere that seems to work fine (covers 
most of the bases and all):

header(Expires: Mon, 26 Jul 1997 05:00:00 GMT); // Date in the past
header(Last-Modified:  . gmdate(D, d M Y H:i:s) .  GMT); // always 
modified
header(Cache-Control: no-store, no-cache, must-revalidate); // HTTP/1.1
header(Cache-Control: post-check=0, pre-check=0, false); // HTTP/1.1
header(Pragma: no-cache); // HTTP/1.0

good luck!

-TG

= = = Original message = = =

Hi,
   
  No, no that is not what i am after, I know how to do that but it's not what I 
want.
   
  I wrote some code a year or so ago with words, they refreshed every 5 or so 
seconds WITHOUT REFRESHING THE PAGE.  It was written in JavaScript as i can 
remember.  But I can't find where I did it. I want to have the code or a 
similar one without the need to re-write it.  
   
  The code does not require the page refreshing at all, just loops in a script 
and outputs.  I might have to do some web surfing on it, pity I can't remeber 
where it is.
   
  If anyone could help that would be great.
   
  It's for a PHP site using MySQL.  I am considering having the slogans in a 
database this time rather than just a text file.
   
  J

Julien Bonastre [EMAIL PROTECTED] wrote:
  Yes I can help you there..

There is a technique you can use which is actually more browser 
friendly then the Javascript alternative you mentioned..

You can use the META tags in your page as such:


  

will refresh page in 10 seconds


  CONTENT=10;url=http://www.operation-scifi.com;

will reload page in 10 seconds and direct browser to one of my first 
highschool webpages..





For a quick reference I found this via the I'm Feeling Lucky of Google: 
http://webdesign.about.com/cs/metatags/a/aa080300a.htm

Otherwise the good ole' W3C at www.w3c.org will have some great doco's 
on it too



enjoy ;-)


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[PHP-DB] FTPing within PHP

2006-01-18 Thread Ron Piggott (PHP)
I am wondering if I may delete a file by FTPing within PHP.

I found the followed on the PHP web site:

fopen(ftp://user:[EMAIL PROTECTED]/somefile.txt, w);

Is there a way for me to delete somefile.txt ?

The FTP program on my computer gives the command

DELE /path/somefile.txt

Is there a way for me to send this command through?

I also need to know the command to disconnect --- and wonder if someone
could tell me it.

Ron

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RE: [PHP-DB] MySQL date casting..

2006-01-17 Thread tg-php
Unfortunately, no.  The dates and times are stored as text. So here's what I 
get:

2006-01-10 07:00 PM
2006-01-10 08:00 PM
2006-01-10 09:00 AM
2006-01-10 09:00 PM


(notice the AM out of order)

For anyone interested, here's the big ugly version..  if anyone knows of a 
function that I can use instead of all this garbage, let me know:


select ApptDate, ApptTime, CONCAT(ApptDate, ' ', IF(SUBSTRING(ApptTime, 7, 2) = 
'PM', CONCAT(SUBSTRING(ApptTime, 1, 2) + 12, ':', SUBSTRING(ApptTime, 4, 2), 
':00'), IF(SUBSTRING(ApptTime, 7, 2) = 'AM', CONCAT(SUBSTRING(ApptTime, 1, 2), 
':', SUBSTRING(ApptTime, 4, 2), ':00'), '00:00:00'))) AS ProperDateTime
from SomeTable

I'm not worried about blank or -00-00 type dates in this case so don't 
really account for them.  And again, this is meant to work on separate date and 
time fields in the following formats:

ApptDate: -MM-DD (we at least did that part 'normal')
ApptTime: HH:MM [AM|PM]

Thanks for the response though Stephen... always worth going over the simple 
stuff first. :)

-TG


= = = Original message = = =

Could you not just add:

ORDER BY ApptDate, ApptTime

To the end of your SQL - this will order the set by date then time. You can
also add ASC or DESC for Ascending or Dscending as desired.

N.B. the ORDER BY  statement must be the last part of you query!


-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] 
Sent: 17 January 2006 16:42
To: php-db@lists.php.net
Subject: [PHP-DB] MySQL date casting..

Forgive me that this isn't really PHP related, but solely MySQL.. but the
MySQL mailing lists drive me nuts and figured someone here would have a
quick answer.

I'm trying to sort by a date and time field(s) (two separate fields).  It's
a dumb system but until we do the next revision, it's going to stay the way
it is (boss' orders) so bear with me.

Example:

ApptDate~ApptTime
2005-11-02~01:00 PM
2005-10-27~07:00 PM
2005-06-25~10:30 AM
-00-00~N/A
-00-00~N/A
-00-00~N/A
-00-00~06:30 PM

See? Dumb.. hah.. 

So I thought I could do something like this:

select ApptDate, ApptTime, DATE_FORMAT(CONCAT(ApptDate, ' ', ApptTime),
'%Y-%m-%d %H:%i:%s') from Table


But it doesn't like 06:00 PM.. returns null on the items that have a valid
date and time because the time format isn't what it wants.  If I try it with
a 06:00:00 PM time, it makes it 6am.

Using STR_TO_DATE() does exactly the same thing.


You'd think STR_TO_DATE() would behave more like PHP's strtotime() but
apparently not.


I can code a big complicated conditional SQL statement, but I'm hoping
there's a way to convert at least the valid date/time pairs into a happily
ORDER BY'd column.  I can handle the -00-00 and N/A entries with
exceptions if I need to.


And I would really like to do this without pre-loading the data into PHP and
sorting it with PHP's sort functions.


Any MySQL gurus who can show me what I'm missing here?  Thanks in advance!

-TG


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Re: [PHP-DB] MySQL date casting..

2006-01-17 Thread tg-php
Ahh! Thank you Philip!  That's what I was looking for!  I see what I did wrong 
now.

I was using the date format strings wrong.  I was using it like I'd use it for 
DATE_FORMAT() instead of as an input filter.

This is what I was trying to do:
select STR_TO_DATE('2003-11-05 06:00 PM', '%Y-%m-%d %H:%i:%s')


duh... hah.  Thanks!  I knew it was something simple.

-TG

--
What's wrong with [using] this?

mysql select str_to_date('2005-10-27 07:00 PM', '%Y-%m-%d %l:%i %p');
+-+
| str_to_date('2005-10-27 07:00 PM', '%Y-%m-%d %l:%i %p') |
+-+
| 2005-10-27 19:00:00 |
+-+
1 row in set (0.04 sec)



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RE: [PHP-DB] Formatting a form box

2006-01-12 Thread tg-php
What? Nobody said This has nothing to do with PHP and databases?  Sheesh... 
someone must be sleeping. :)  Ok, so it sorta does relate..

But yeah... no2br() will do it for you.  Textarea input types DO send a newline 
and/or carriage return (didn't test and might be system specific), so if you 
just take your form $_POST data and use nl2br() before you store it in the 
database (or probably after... should be able to store a newline/carriage 
return in the database) it should produce the results you desire.

test.php:

form action=test.php method=post
textarea name=testarea
/textarea
input type=submit
/form
?php

if (isset($_POST['testarea'])) {

  echo nl2br($_POST['testarea']);

}
?

Look at the source code after you submit if you have any doubts/questions.

-TG

= = = Original message = = =

use the nl2br() function to convert the newlines to br


bastien

From: Alex Major [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Formatting a form box
Date: Thu, 12 Jan 2006 16:33:01 +

Hi there,
On one of my forms, there is a section where users can put images etc..and
then it is displayed on my php pages. My question is how do I make it so
that the html formatting is automatically done. For example when someone is
typing something, and wants to start a new paragraph although they press
return when typing when the data is displayed from the MySQL database on a
website it's just continuous text. For it to start a new paragraph they 
have
to put p in when they are typing in this box. They do not know all the
html formatting codes, and so I need someway of making so that it is easy
for them to have formatted text without doing all the html.
Also things like changing colours, bold, italic and things would be good.
Something like on forums, where when you enter a new post you have all the
formatting options.

Hope this makes sense,
Regards,
Alex.


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Re: [PHP-DB] Scrolling News

2005-12-22 Thread PHP Superman
Hi,
just to tell you scrolling text boxes are javascript, PHP is server side not
client side, PHP can only get the data from the table and javascript will
display it



On 12/22/05, Alex Major [EMAIL PROTECTED] wrote:

 Hi there.
 I'm trying to make a scrolling news box for my website. Basically I would
 like this news box to get information from a column in my database called
 'news_title' and display it in a scrolling news box.
 The reason I'd like it to do this is because there is already a news page
 on
 my website, which stores 'news_date' ,  'news_poster' ,  'news_title' ,
 'news_description' , 'news_content' in a table on my database. I'd just
 like
 to increase the functionality of this by having this news box on my front
 page, which scrolls the 'news_title'.

 Any suggestions for how to go about doing this? I'm still very new to php.

 Regards,
 Alex.

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[PHP-DB] CLOSE button or a href link

2005-12-21 Thread Ron Piggott (PHP)
I am building a Christian ministry web site.

One of the things we are establishing is an online offering basket to
receive donations.  One of our disbursements is a benevolent fund to
help others.

I have a 'how we operate our benevolent fund' web page online at
http://www.actsministrieschristianevangelism.org/financial/how_we_operate_our_benevolent_fund.html

I also have this file set to load from our online offering basket web
page at
http://www.actsministrieschristianevangelism.org/financial/online_offering_basket.html
 as a pop up window by clicking a submit button.

What I really want to have happen is for the CLOSE WINDOW button to
appear when this is loaded as a pop up window from our
online_offering_basket.html file and if the web page is loaded directly
then the link to our Online Offering Basket appear for the user to get
back into our web site.  

Do you know how to do this?

Ron

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Re: [PHP-DB] Date Formatting Question

2005-12-14 Thread tg-php
You got the right idea, but you're making it more complicated than it needs to 
be.

your $sDate after using explode() is going to contain an array.  strtotime 
doesn't take an array, it takes a string.

$monthName = date(F, strtotime($row_events['Sdate']));
$monthNumber = date(m,  strtotime($row_events['Sdate']));
// or n if you want 1 instead of 01 for January

echo select name='sMonth'\n;
for ($i = 1; $i = 12; $i++) 

  // using date() below to get month name, day and year irrelevant
  $selectMonthText = date(F, mktime(0, 0, 0, $i, 1, 2000));

  if ($i == $monthNumber) 
$selected =  SELECTED;
   else 
$selected = ;
  
  echo option value='$i'$selected$selectMonthText/option\n;

echo /select\n;


-TG


= = = Original message = = =

I am trying to format the month portion of a date that I am trying to
pull from MySQL to be placed into a drop down menu to modify the date.
I have tried several ways and none seem to be working.  

I am pulling the date out of MySQL with: 
$sDate = explode(-, $row_events['Sdate']);

And then attempting to insert each portion of the array into a drop down
menu with:
echo select name=Smonth;
echo option selected$sDate[1]/option;
which is where I am running into the problem.  I pull out the month as 2
digit numeric 01, 02, 03 etc., but I want it displayed as January,
February, March, etc.,

I have tried the following with no success:
Date(F,strtotime($sDate));  
Strftime(%B:,$sDate);
Date(F,$sDate);


I would use MySQL to format the date, but I have three date fields to
modify and it would be easier to do it in PHP

Any pointers would be appreciated.


Mark Bomgardner
Technology Specialist
KLETC


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Re: [PHP-DB] Minor Change

2005-12-12 Thread tg-php
This isn't really a MySQL error (sorta), it's a PHP error.  You probably forgot 
to update a variable name when you updated everything else.

Here's an example sequence for querying using PHP/MySQL:

$TestQY = SELECT * from SomeTable;
$TestRS = mysql_query($TestQY) or die(Error executing query);
while ($TestRW = mysql_fetch_assoc($TestRS)) {
  $somearr[] = $TestRW;  // do something with data
}

Since you're getting a Not a valid MySQL result resouce error with the 
mysql_fetch_assoc() function, I'd search for all your mysql_fetch_assoc() 
statements and double check their $TestRS.  That error is saying that your 
$TestRS isn't a valid MySQL result set.  That could mean that $TestRS isn't 
defined (maybe you're still using $TestOldRS and forgot to change a variable 
name) or possibly that $TestQY is empty or bad somehow so mysql_query() isn't 
generating a proper MySQL result set (try echoing out your $TestQY to see what 
it is.. then try executing it manually on the MySQL server and see if you get 
an error).

You can try the or die() syntax I use above to see if mysql_query() is 
bombing out so you'll get notice before it even gets to the mysql_fetch_assoc().

Lastly.. someone recommended echoing out mysql_error(). Your response makes it 
sound like you think that this fixes your problem.  It's not going to fix 
anything, just possibly give you some information about what failed.  If you 
get a MySQL error message from mysql_error(), please post it. It might help us 
determine what the problem is.

It may not contain anything (under certain failing circumstances) so I'd step 
through the things I've listed above.  They may shed some light on where the 
error is and then we can figure out how to fix it.   Probably a typo in a 
query, variable name or table name I'm guessing.

Let us know if you find anything else out.

-TG

= = = Original message = = =

After adding echo mysql_error(); I get the same result.  I tried changing  
the query to include 109fh7 (a table which doesn't exist) and got the same  
result as with 109fh6.  Changing to 109fh5 does pull up that table.  The  
line to which the error message refers is while ($row = mysql_fetch_assoc  
($data_set))  That is what always come up when there is an error in the  
query.

**
On Mon, 12 Dec 2005 14:13:10 -0500, Micah Stevens  
[EMAIL PROTECTED] wrote:


 You're getting an error, after the query, put:

 echo mysql_error();

 to find out what's happening.

 On Monday 12 December 2005 11:05 am, [EMAIL PROTECTED] wrote:
 I made tiny changes to my php file and sql table and the table won't  
 come
 up.  I updated the table name (and php file name) from 109fh5 to 109fh6.
 In the table, I changed 6 cells, leaving a couple blank.  Then I changed
 only the digit 5 to make it a 6 (109fh6) in the following:

 $get_data_query = select rep, party, state, cd, minority, afr_am,  
 asian,
 am_indian, hispanic, med_hsehold_income, poverty from 109fh6 order by
 $sort_field $sort_order;

 Now I get Warning: mysql_fetch_assoc(): supplied argument is not a  
 valid
 MySQL result resource in etc.

 I've done this many times without a problem (this is the 6th time in  
 this
 sequence).  What could be wrong after such a minor change?

 Ken



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Re: [PHP-DB] Need a Help!

2005-12-12 Thread tg-php
Couple of things you can do:

1. Drop the song ID and only get the artist information  SELECT 
distinct(Artist) from songtable.  It doesn't look like your SELECT statement 
needs a song, but you include the song ID as $id anyway. Any reason for that or 
can you drop it so you only get artist?

2. Pre-parse the results of your current query so you only get one artist 
and/or compile a list of song ID's while you're at it.  Instead of doing your 
option in the database query result WHILE statement, do it outside:

while (results) {
  $artistinfo[$artist][] = $id;
}

Then:

echo select name='blah';
foreach ($artistinfo as $artist = $songsarr) {
  echo optgroup label='$artist';
  foreach ($songsarr as $songid) {
echo option value='$id'$id or whatever/option;
  }
  echo /optgroup;
}
echo /select;

3. Use a different DB structure.  I prefer this structure myself:

Table ARTISTS:
ArtistID
ArtistName
OtherArtistInfo

Table SONGS:
SongID
ArtistID
OtherSongInfo

Or, instead of having ArtistID, if more than one artist may be linked to a 
song, you can do:
Table xrefArtistsSongs:
ArtistID
SongID

Not sure why you'd want to do that for a song unless you're counting covers of 
songs and want all artists who've covered it to point to the same SongID data.

This way you can:

SELECT * from ARTISTS

for your ARTISTS select box

Then once an artist is selected, do a:

SELECT * from SONGS where ARTISTID = $artistid


Just some ideas.

Forgive the pseudo-code and mixed capitalizations.. I think you get the idea 
I'm trying to convey.

-TG

= = = Original message = = =

I have table and insert data using song_id, that means one artist can have
many song_ids. my question is how can I query distinct artist with his/her
song_id while I will not get duplicate data like duplicate artist?
my code is like this

$content .=form id=\form1\ method=\post\ action=\\
  select name=\Quick\ onchange=\MM_jumpMenu('parent',this,0)\
option value=\#\Select Artist/option;


$result= $db-sql_query(SELECT distinct(artist), id FROM
.$prefix._lyrics order by artist asc);
if ($db-sql_numrows($result)) 
 while($row = $db-sql_fetchrow($result)) 
 extract($row);
 $content .=option value='modules.php
?name=$module_nameamp;file=artistamp;c_id=$id'$artist/option;
   


$content .=/select
/form;

that code is fine except it gives me duplicate artist, so I want get rid off
that duplicate. any help


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[PHP-DB] Garbage collection (my session files)

2005-12-10 Thread Ron Piggott (PHP)
I have specified a directory for the session files to be stored in.  But
by doing so the garbage collection function isn't automatically deleting
them.  Is there a way I can do so --- Either with a cron or something
like this?  Ron

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[PHP-DB] SELECT

2005-12-10 Thread Ron Piggott (PHP)
I am trying to put together a SELECT syntax.  I am querying a response
database and I only want to obtain each user's name once even if they
have given more than 1 response.  

$query=SELECT * FROM  conversation_table WHERE conversation_reference =
$conversation_currently_displayed;

$response_created_by = mysql_result($result,$i,response_created_by);

My ideal is that if users 1, 2, 4  5 are in dialogue with each other
the above SELECT $query will only give the results of their identity
once with the mysql_request() function

Thanks for your help.

Ron

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[PHP-DB] Ending session

2005-12-09 Thread Ron Piggott (PHP)
How do you actually end $_session variables so the session actually
ends?

I found the session_write_close() command.  I am not sure if this is the
correct command or not.  

One prime example I am using is a $_session variable to track which user
account is active.  I want to have a log off button which closes the
session off.  

Ron

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