[PHP] String is not zero-terminated in zend_execute_API.c
Hello List,
i am running PHP 5.3.8-FPM (with ondemand patch) in debug mode and got this
error every time I post an reply in vBulletin Board:
Warnung: String is not zero-terminated
(Z.ý4 ý4 ú}µóU) (source:
/usr/src/php-5.3.8/Zend/zend_execute_API.c:447) in
[path]/includes/functions_newpost.php(668) : eval()'d code (Zeile 34)
functions_newpost.php:
29 if (!$allowicons)
30 {
31 return false;
32 }
33
34 $membergroups = fetch_membergroupids_array($vbulletin-userinfo);
35 $infractiongroups = explode(',', str_replace(' ', '',
$vbulletin-userinfo['infractiongroupids']));
36
37 ($hook = vBulletinHook::fetch_hook('posticons_start')) ?
eval($hook) : false;
38
function fetch_membergroupids_array($user, $getprimary = true)
{
if (!empty($user['membergroupids']))
{
$membergroups = explode(',', str_replace(' ', '',
$user['membergroupids']));
}
else
{
$membergroups = array();
}
if ($getprimary)
{
$membergroups[] = $user['usergroupid'];
}
return array_unique($membergroups);
}
I hope you can help, or may i open an bugreport to bugs.php.net ?
Greetings,
Daniel
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Re: [PHP] String eval assistance
On 16 March 2011 00:25, Jack jacklistm...@gmail.com wrote:
Here you're trying to access it as an array, which it's not, so the
'response'
key doesn't exist. In addition, you're looking for UPPER-CASE, whereas
that's
not the case in your example variable.
Finally, you're checking to make sure that the string IS INDEED found, but
then printing that it was declined (!== false). Instead, you may
want:
?php
$results['response'] = '3434approd34';
if (stripos($results['response'],'APPROVED') !== false) {
// It's been found
} else {
// Oh, crap.
}
?
maybe I should do this some other way because I'm getting false positives.
I was using if(strpos($results['response'], 'APPROVED') !== false) {
And its found if the value of $results = 3434APPROVED34 and it also is
found if its $results = 3434APPOVED34, so this may not be the best way to
accomplish this.
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Can you create a small list of actual values and their results.
What version of PHP are you using?
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Re: [PHP] String eval assistance
I'm not sure as to why strpos does what it does here, at least its not
immediately obvious, but, a solution to this would be to use a regular
expression search, it would be more exact, it has never failed me, and it will
be faster; I recall reading that preg functions were faster at then str ones,
though I can't recall where...
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Richard Quadling rquadl...@gmail.com wrote:
On 16 March 2011 00:25, Jack jacklistm...@gmail.com wrote: Here you're
trying to access it as an array, which it's not, so the 'response' key
doesn't exist. In addition, you're looking for UPPER-CASE, whereas that's
not the case in your example variable. Finally, you're checking to make sure
that the string IS INDEED found, but then printing that it was declined (!==
false). Instead, you may want: ?php $results['response'] =
'3434approd34'; if (stripos($results['response'],'APPROVED') !== false) {
// It's been found } else { // Oh, crap. } ?
maybe I should do this some other way because I'm getting false positives.
I was using if(strpos($results['response'], 'APPROVED') !== false) { And its
found if the value of $results = 3434APPROVED34 and it also is found if its
$results = 3434APPOVED34, so this may not be the best way to accomplish
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Can you create a small list of actual values and their results. What version of
PHP are you using? -- Richard Quadling Twitter : EE : Zend @RQuadling :
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Re: [PHP] String eval assistance
On 16/03/2011, at 10:34 AM, Jack wrote:
Hello All,
I got some help on this yesterday, but somehow it's not consistant
?
$results = 3434approd34;
if(strpos($results['response'], 'APPROVED') !== false) {
print declined;
} else {
print approved;
}
?
The thing is I cant get a consistant response, if it has approved anywhere
in the results string, then it should be approved and if the results is
APPROVD without the E it shold be delined.
Am I doing something wrong.
Thanks!
Jack
Yes, you're doing something wrong. strpos() returns false if it can't find the
needle. You should be using if(strpos() === false) { declined; }
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RE: [PHP] String length output in php-generated response
-Original Message-
From: Florin Jurcovici [mailto:florin.jurcov...@gmail.com]
Sent: 06 February 2011 15:57
I'm trying to build myself a small JSON-RPC server using PHP.
Using wireshark, here's the conversation:
Request:
[...snip...]
Response:
HTTP/1.1 200 OK
Date: Sun, 06 Feb 2011 15:04:08 GMT
Server: Apache/2.2.14 (Ubuntu)
Accept-Ranges: bytes
X-Powered-By: PHP/5.3.2-1ubuntu4.7
Keep-Alive: timeout=15, max=100
Connection: Keep-Alive
Transfer-Encoding: chunked
Content-Type: application/json; charset=UTF-8
6f
{id:2,result:{service:test.service,method:method,
id:2,params:[{code:client}]},error:null}
0
That's nothing to do with PHP -- it's http chunked encoding, as
indicated by the Transfer-Encoding: chunked header, and is handled
by Apache and your browser. It's totally expected and totally
harmless. Read about it here:
http://www.w3.org/Protocols/rfc2616/rfc2616-sec3.html#sec3.6
Cheers!
Mike
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Re: [PHP] String length output in php-generated response
On 6 February 2011 15:57, Florin Jurcovici florin.jurcov...@gmail.com wrote: said it, Bush junior proved it Is this actually part of the output? -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] String length output in php-generated response
Hi.
I'm trying to build myself a small JSON-RPC server using PHP.
Using wireshark, here's the conversation:
Request:
POST /.../service.php?nocache=1297004648751 HTTP/1.1
User-Agent: Opera/9.80 (X11; Linux i686; U; en) Presto/2.7.62
Version/11.01
Host: localhost
Accept: text/html, application/xml;q=0.9, application/xhtml+xml,
image/png, image/jpeg, image/gif, image/x-xbitmap, */*;q=0.1
Accept-Language: en-US,en;q=0.9
Accept-Charset: iso-8859-1, utf-8, utf-16, *;q=0.1
Accept-Encoding: deflate, gzip, x-gzip, identity, *;q=0
Referer: http://localhost/ssd/php/testrpc/build/
Connection: Keep-Alive, TE
TE: deflate, gzip, chunked, identity, trailers
Content-Length: 80
Content-Type: application/json
Pragma: no-cache
Cache-Control: no-cache
X-Qooxdoo-Response-Type: application/json
Content-Transfer-Encoding: binary
{service:test.service,method:method,id:1,params:[{code:client}]}
said it, Bush junior proved it
Response:
HTTP/1.1 200 OK
Date: Sun, 06 Feb 2011 15:04:08 GMT
Server: Apache/2.2.14 (Ubuntu)
Accept-Ranges: bytes
X-Powered-By: PHP/5.3.2-1ubuntu4.7
Keep-Alive: timeout=15, max=100
Connection: Keep-Alive
Transfer-Encoding: chunked
Content-Type: application/json; charset=UTF-8
6f
{id:2,result:{service:test.service,method:method,id:2,params:[{code:client}]},error:null}
0
The code to handle the request is:
?php
$request = json_decode($GLOBALS['HTTP_RAW_POST_DATA']);
$response = (object) array(
id = $request-id,
result = $request,
error = null
);
header(Content-Type: application/json; charset=UTF-8, true);
print json_encode($response);
?
The 6f above is the length of the output in hex (I tried with
various lengths of the string, it is always correct), the 0 at the end
is probably some C-like string termination mark.
Now, it seems the client (some JavaScript running in Firefox) has no
problem decoding the answer, in spite of the hex length placed at the
beginning. However, I can't rely on browsers playing nicely with
incorrect JSON, so I would very much like to generate an output
without the length of the response written as hex at the beginning,
and without the terminating 0. What am I doing wrong? Why does the
length of the string get written?
I tried concatenation of an empty string at the beginning and at the
end, supposing that for some reason json_encode() doesn't produce a
plain string, and hoping that concatenating it to a proper string
would produce a plain string, but it didn't help either.
Before posting to the list, I tried searching for the problem on the
web, and also experimented by outputting plain, hand-written strings.
It didn't really help. Maybe it's a setup problem? My problem is, php
is absolutely new to me, so I don't even know how to start diagnosing
the problem (I started experimenting just a few hours ago).
To decide whether it's a setup problem, here's the development platform:
OS: Kubuntu 10.04.1 LTS
Apache: Apache/2.2.14 (Ubuntu)
PHP: 1.0.5-dev
json version: 1.2.1
I don't think the browser is relevant, since it behaves the same in
Opera and Firefox, and it doesn't happen in the browser, it happens on
the server, since that's what wireshark shows.
TIA,
flj
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Re: [PHP] String Encodings - loose guidelines
Marc Guay wrote: 1.) Saving strings to a database One thing I always forget to remember is to send tge SET NAMES utf8 command to MySQL after making a connection. This will save you 1000 headaches if you're working with non-latin characters. I can't count the number of times I've thrown htmlentities, htmlspecialchars, utf8_encode/decode/, stripslashes, etc, etc around trying to figure out why those É's aren't being saved or read properly. I imagine this might fall into the category of best practice. Marc Thanks for the heads up! Donovan -- D Brooke -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] String Encodings - loose guidelines
Hello, I don't yet have a complete understanding of string encodings for the various environments they may need to pass through or be in. I have found bits and pieces within Larry's book, the online docs, and by googling... and my app seems to be working fine, but I don't yet feel confident on best practices. So, I thought I'd see if I could spark some feedback to the following: 1.) Saving strings to a database 2.) print/echo'ing string fields from a database. a. Allowing HTML? b. Not allowing HTML? 3.) print/echo'ing string fields into form textareas. 4.) Simply encoding strings to send over a GET request. 5.) Simply displaying strings from the $_REQUEST array. 6.) string encoding for redirects I understand that some of the above may depend on what database is being used. However, here is basically what I'm using successfully so far (disclaimer: obviously I am not sure of things here which is why I am asking the question ;-) ): 1.) $t_string = mysql_real_escape_string($f_varied_chars); //if using MySQL (optionally could use htmlspecialchars()?) to not allow html? 2.) print $db_string; a. Nothing different.. or perhaps htmlspecialchars_decode()? b. use htmlspecialchars upon saving to database, or using print htmlentities($db_string);?? 3.) textarea..?PHP print htmlspecialchars($db_string); ?/textarea? 4.) $t_string = urlencode($t_varied_chars); //(not sure if htmlentities would be needed in certain situations) a href=page.php?f_string=$t_stringx/a 5.) print urldecode($_GET['t_string']); //(not sure if html_entity_decode() would be needed in certain situations where you would want to display html?) 6.) ob_end_clean(); // destroy buffer $t_string = urlencode(text with varied chars); $t_url = page.php?f_string=$t_string; header (Location: $t_url); exit; TIA, Donovan -- D Brooke -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String Encodings - loose guidelines
1.) Saving strings to a database One thing I always forget to remember is to send tge SET NAMES utf8 command to MySQL after making a connection. This will save you 1000 headaches if you're working with non-latin characters. I can't count the number of times I've thrown htmlentities, htmlspecialchars, utf8_encode/decode/, stripslashes, etc, etc around trying to figure out why those É's aren't being saved or read properly. I imagine this might fall into the category of best practice. Marc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String passed to object constructor turning into aninstance of that object?
David Harkness wrote:
I've never used the old-style constructors, but perhaps the semantics of
parent:: changed and you need to instead use $this- as in
$this-Tag(option, $name);
That's a total guess. I don't have 5.2 handy to try it out, but both work in
5.3 using a simple example. Can you post the constructor of one of the Tag
subclasses that work? Maybe we can find a common denominator.
The most similar is Column, but all of them do very similar things -
it's just the one class that seems to take a string and mutate it into
what looks like an array with a string at [0] and something closely
resembling what the whole object instance *should* be at [1].
class Table extends Tag {
function Table() {
parent::Tag('table');
$this-addAttribute('cellspacing', 0);
$this-addAttribute('cellpadding', 0);
$this-addAttribute('border', 0);
$this-columns = array();
$this-rows = array();
}
class Row extends Tag {
function Row($table='') {
parent::Tag('tr');
$this-table = '';
}
class Column extends Tag {
function Column($data) {
parent::Tag('td', $data);
$this-tagContent = $data;
}
class FormObject extends Tag {
function FormObject($name='') {
parent::Tag();
$this-addAttribute(name, $name);
$this-name = $name;
}
-kgd
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Re: [PHP] String passed to object constructor turning into aninstance of that object?
Nathan Nobbe wrote:
2. try modifying Tag SelectBoxOption to have __construct() instead of
Tag() SelectBoxOption(), then call parent::__construct() from inside
of SelectBoxOption::__construct(); see if that clears up your problem
under
5.2 (read: this will only be a partial solution as it only addresses one
child of Tag).
Mmm. I hoped this would help, but all it seems to have done was cascade
errors across the rest of Tag's object children. :(
to be expected, but did it fix the problem w/ SelectBoxOption?
I'm not sure, but I don't think so; the original symptom was Object of
class SelectBoxOption could not be converted to string - the original
code didn't include a toString() method in SelectBoxOption, and since
the code works on an older PHP, it must be using the parent object's
toString(). (Which some children of Tag do explicitly, but
SelectBoxOption doesn't for whatever reason.)
In trying to add the toString() method, I found that the calls used by
other tags to retrieve the HTML tag name, value, etc weren't working.
So I looked up at the constructor to see if the pieces passed in were
getting passed and stored correctly - and quite obviously they're not
($name mutates into what looks like an array with a string at [0] and
something closely resembling what the whole object instance *should* be
at [1], and $value just seems to disappear).
Putting aside actually fixing the constructor correctly, after a bit of
poking I found that $this-tagContent-. works to retrieve the data
and actually output the option tag correctly.
var_dump tells me that the real data is actually in there... it's
just not instantiated correctly. $name apparently arrives at the
constructor for SelectOptionBox like this:
string(8) Abegweit
object(SelectBoxOption)#65 (5) {
[attributes]=
array(1) {
[0]=
object(TagAttribute)#66 (3) {
[name]=
string(5) value
[value]=
string(1) 4
[hasValue]=
bool(true)
}
}
[tagContent]=
string(8) Abegweit
[tag]=
string(6) option
[showEndTag]=
bool(false)
[children]=
array(0) {
}
}
I'll try converting all of the constructors to your recommendation as
above, but given that the problem is only happening with this one class, I'm
not sure that will do much.
hopefully that clears it up ..
Well, I ran out of Call to undefined ParentClass::parentclass in
path/to/file/for/subclass.php errors (at least on the page I'm testing
with) but $name is still going in on the calling side as a string,
and coming out as a funky array.
and hopefully you're using version control :D
Bah! Real man never make mistaaake!
... ooops. g
(I've got the live site, on the old server, as reference, plus the
regular backups of that machine.)
-kgd
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[PHP] String passed to object constructor turning into an instance of that object?
I'm in the process of migrating customer websites off an old legacy
server that's pushing EOL, and starting to show hardware failures.
One site is throwing errors on what, so far as I can tell, should be
perfectly working code.
The original code works fine on both CentOS 3 (PHP 4.3.2) and CentOS 4
(4.3.9); the new server is still a bit outdated (Debian etch plus
some backports and updates from lenny; PHP 5.2.0).
The site was designed by staff at a previous hosting company and uses a
combination of the Fusebox app framework (which seems to work OK, after
a few relatively minor fixes) and a custom OOP structure.
I'm not really sure what the actual problem is, but I've reached the
point where this:
class SelectBoxOption extends Tag {
function SelectBoxOption($name, $value, $selected=false) {
parent::Tag(option, $name);
$this-addAttribute(value, $value);
if($selected) {
$this-addAttribute(selected, '', false);
}
if ($name == ) { echo nbsp;nbsp;nbsp;missing name!br\n; }
// else { print nbsp;nbsp;nbsp;name $namebr\n; }
if ($value == ) { echo nbsp;nbsp;nbsp;missing value!br\n; }
}
will parse and execute, but:
- the page will contain missing value! for each option in the
select this is generating
- it will *not* contain missing name!
- the option tags in the final output don't have content or value
(they should have both).
If I uncomment that else, I get:
adding option name1 with value1
name value1
Catchable fatal error: Object of class SelectBoxOption could not be
converted to string in
webroot/includes/classes/core/display/form/input/SelectBoxOption.php
on line 12
I found the place this object is created, and added some debugging
output before *and* after that call:
echo adding option .$row-$nameField. with .
$row-$valueField.br\n;
$this-add(new SelectBoxOption($row-$nameField,
$row-$valueField, $selected));
echo added option .$row-$nameField. with .
$row-$valueField.br\n;
which behaves correctly and spits out the name and value (retrieved from
a database - thankfully I haven't had to track *that* down... yet).
Can anyone explain why a string passed by value (apparently) would
suddenly mutate into a SelectBoxOption object? I've confirmed that this
is exactly what happens by adding this:
if (is_a($name,'SelectBoxOption')) {
print name isn't a SelectBoxOption, silly rabbit!br\n;
}
as the very next set of lines after function SelectBoxOption(.
I wondered while typing this if $name and $value might have ended up as
special variables somewhere, but renaming them with an opt_ prefix
didn't change anything.
-kgd
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RE: [PHP] String passed to object constructor turning into an instance of that object?
-Original Message-
From: Kris Deugau [mailto:kdeu...@vianet.ca]
Sent: Thursday, December 16, 2010 11:57 AM
To: php-general@lists.php.net
Subject: [PHP] String passed to object constructor turning into an
instance of
that object?
I'm in the process of migrating customer websites off an old legacy server
that's pushing EOL, and starting to show hardware failures.
One site is throwing errors on what, so far as I can tell, should be
perfectly
working code.
The original code works fine on both CentOS 3 (PHP 4.3.2) and CentOS 4
(4.3.9); the new server is still a bit outdated (Debian etch plus some
backports and updates from lenny; PHP 5.2.0).
The site was designed by staff at a previous hosting company and uses a
combination of the Fusebox app framework (which seems to work OK, after
a few relatively minor fixes) and a custom OOP structure.
I'm not really sure what the actual problem is, but I've reached the point
where this:
class SelectBoxOption extends Tag {
function SelectBoxOption($name, $value, $selected=false) {
parent::Tag(option, $name);
$this-addAttribute(value, $value);
if($selected) {
$this-addAttribute(selected, '', false);
}
if ($name == ) { echo nbsp;nbsp;nbsp;missing name!br\n; }
// else { print nbsp;nbsp;nbsp;name $namebr\n; }
if ($value == ) { echo nbsp;nbsp;nbsp;missing value!br\n; }
}
will parse and execute, but:
- the page will contain missing value! for each option in the
select this is generating
- it will *not* contain missing name!
- the option tags in the final output don't have content or value
(they should have both).
If I uncomment that else, I get:
adding option name1 with value1
name value1
Catchable fatal error: Object of class SelectBoxOption could not be
converted to string in
webroot/includes/classes/core/display/form/input/SelectBoxOption.php
on line 12
What's the actual line #12 in the file SelectBoxOption.php? The
SelectBoxOption code you presented has 11 lines unless it's a CNP error.
Regards,
Tommy
I found the place this object is created, and added some debugging
output before *and* after that call:
echo adding option .$row-$nameField. with .
$row-$valueField.br\n;
$this-add(new SelectBoxOption($row-$nameField,
$row-$valueField, $selected));
echo added option .$row-$nameField. with .
$row-$valueField.br\n;
which behaves correctly and spits out the name and value (retrieved from
a database - thankfully I haven't had to track *that* down... yet).
Can anyone explain why a string passed by value (apparently) would
suddenly mutate into a SelectBoxOption object? I've confirmed that this
is exactly what happens by adding this:
if (is_a($name,'SelectBoxOption')) {
print name isn't a SelectBoxOption, silly rabbit!br\n;
}
as the very next set of lines after function SelectBoxOption(.
I wondered while typing this if $name and $value might have ended up as
special variables somewhere, but renaming them with an opt_ prefix
didn't change anything.
-kgd
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Re: [PHP] String passed to object constructor turning into an instance of that object?
Tommy Pham wrote:
class SelectBoxOption extends Tag {
function SelectBoxOption($name, $value, $selected=false) {
parent::Tag(option, $name);
$this-addAttribute(value, $value);
if($selected) {
$this-addAttribute(selected, '', false);
}
if ($name == ) { echo nbsp;nbsp;nbsp;missing name!br\n; }
// else { print nbsp;nbsp;nbsp;name $namebr\n; }
if ($value == ) { echo nbsp;nbsp;nbsp;missing value!br\n; }
}
will parse and execute, but:
- the page will contain missing value! for each option in the
select this is generating
- it will *not* contain missing name!
- the option tags in the final output don't have content or value
(they should have both).
If I uncomment that else, I get:
adding option name1 with value1
name value1
Catchable fatal error: Object of class SelectBoxOption could not be
converted to string in
webroot/includes/classes/core/display/form/input/SelectBoxOption.php
on line 12
What's the actual line #12 in the file SelectBoxOption.php? The
SelectBoxOption code you presented has 11 lines unless it's a CNP error.
Whups, thought I noted that. I trimmed a couple of blank lines; line
12 in the file is that print in the else.
I found trying to print $name triggers the same error anywhere in that
function, too; as I noted further down it seems the string that's
passed in is getting mutated into an object. (Whose missing toString
function is what led me here - but it works fine in PHP 4.3...)
-kgd
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Re: [PHP] String passed to object constructor turning into aninstance of that object?
Nathan Nobbe wrote:
Why not test for the type of $name at each point of interest in the
SelectBoxOption
constructor? If you're passing a string value to the constructor it almost
has to be getting changed by the Tag constructor, right ?
class SelectBoxOption extends Tag {
function SelectBoxOption($name, $value, $selected=false) {
var_dump(is_string($name));
parent::Tag(option, $name);
var_dump(is_string($name));
Ah, that gives... well, it slightly alters the confusion.
Using var_dump(is_string($name)) gives... two results?
bool(true)
bool(false)
And dumping $name itself gives:
string(8) Abegweit
object(SelectBoxOption)#65 (5) { [attributes]= array(1) { [0]=
object(TagAttribute)#66 (3) { [name]= string(5) value [value]=
string(1) 4 [hasValue]= bool(true) } } [tagContent]= string(8)
Abegweit [tag]= string(6) option [showEndTag]= bool(false)
[children]= array(0) { } }
O_o
Just to confirm, I checked a test instance of the site on CentOS 4, with
PHP 4.3, and I get one bool(true) for each option - not two as is
happening with PHP 5.2.
-kgd
(I haven't worked with PHP for quite a while, and I never really spent a
lot of time getting deep into complex data structures and object
hierarchies like this when I was using it. But this behaviour does NOT
match what I know of passing values and object references around in any
other language.)
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Re: [PHP] String passed to object constructor turning into aninstance of that object?
On Thu, Dec 16, 2010 at 3:21 PM, Kris Deugau kdeu...@vianet.ca wrote:
Nathan Nobbe wrote:
Why not test for the type of $name at each point of interest in the
SelectBoxOption
constructor? If you're passing a string value to the constructor it
almost
has to be getting changed by the Tag constructor, right ?
class SelectBoxOption extends Tag {
function SelectBoxOption($name, $value, $selected=false) {
var_dump(is_string($name));
parent::Tag(option, $name);
var_dump(is_string($name));
Ah, that gives... well, it slightly alters the confusion.
Using var_dump(is_string($name)) gives... two results?
bool(true)
bool(false)
And dumping $name itself gives:
string(8) Abegweit
object(SelectBoxOption)#65 (5) { [attributes]= array(1) { [0]=
object(TagAttribute)#66 (3) { [name]= string(5) value [value]=
string(1) 4 [hasValue]= bool(true) } } [tagContent]= string(8)
Abegweit [tag]= string(6) option [showEndTag]= bool(false)
[children]= array(0) { } }
O_o
Just to confirm, I checked a test instance of the site on CentOS 4, with
PHP 4.3, and I get one bool(true) for each option - not two as is
happening with PHP 5.2.
probly something screwy going on w/ the old style of naming constructors. 2
things,
1. can you post the Tag constructor as it reads now?
2. try modifying Tag SelectBoxOption to have __construct() instead of
Tag() SelectBoxOption(), then call parent::__construct() from inside
of SelectBoxOption::__construct(); see if that clears up your problem under
5.2 (read: this will only be a partial solution as it only addresses one
child of Tag).
-kgd
(I haven't worked with PHP for quite a while, and I never really spent a
lot of time getting deep into complex data structures and object hierarchies
like this when I was using it. But this behaviour does NOT match what I
know of passing values and object references around in any other language.)
Probly because the term 'reference' in php means something rather different
than it does in say java for example.
Re: [PHP] String passed to object constructor turning into aninstance of that object?
It's acting as if Tag's constructor a) declares $name as a reference using $name, and b) is assigning itself ($this) to $name for some (probably bad) reason. That's the only way I can see that $name inside SelectBoxOption's constructor could change from a string to an object. A peek at Tag's constructor could really clear things up. David
Re: [PHP] String passed to object constructor turning into an instance of that object?
Nathan Nobbe wrote:
probly something screwy going on w/ the old style of naming constructors. 2
things,
1. can you post the Tag constructor as it reads now?
function Tag($tag='', $tagContent='') {
$this-tagContent = $tagContent;
$this-tag = $tag;
$this-showEndTag = false;
$this-attributes = array();
$this-children = array();
}
2. try modifying Tag SelectBoxOption to have __construct() instead of
Tag() SelectBoxOption(), then call parent::__construct() from inside
of SelectBoxOption::__construct(); see if that clears up your problem under
5.2 (read: this will only be a partial solution as it only addresses one
child of Tag).
Mmm. I hoped this would help, but all it seems to have done was cascade
errors across the rest of Tag's object children. :( Copying the old
constructor back in resolved that, but I'm not sure whether that
reintroduces the root problem.
Other objects derived from Tag seem to work just fine; I came into this
chunk of the code trying to find out why a SelectBoxOption didn't seem
to have a toString function - and then why trying to access what should
be the value and name the same way as with other objects derived at some
level from Tag blew up instead of working happily.
I'll try converting all of the constructors to your recommendation as
above, but given that the problem is only happening with this one class,
I'm not sure that will do much.
(A don't-break-crusty-old-code option for php.ini would be handy...)
The class hierarchy I've dug up so far looks like this (and appears to
have been entirely defined by the original developer):
Object
Fieldset
RadioButtonGroup
Tag
Column
FormObject
FormInput
CheckBox
DateSelector
Editor
FileField
FormButton
HiddenField
PasswordField
RadioButton
SelectBox
PopulatedSelectBox
RecursiveSelectBox
TextArea
TextField
Form
Row
Table
SelectBoxOption
-kgd
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Re: [PHP] String passed to object constructor turning into an instance of that object?
On Thu, Dec 16, 2010 at 4:04 PM, Kris Deugau kdeu...@vianet.ca wrote:
Nathan Nobbe wrote:
probly something screwy going on w/ the old style of naming constructors.
2
things,
1. can you post the Tag constructor as it reads now?
function Tag($tag='', $tagContent='') {
$this-tagContent = $tagContent;
$this-tag = $tag;
$this-showEndTag = false;
$this-attributes = array();
$this-children = array();
}
seems innocuous ..
2. try modifying Tag SelectBoxOption to have __construct() instead of
Tag() SelectBoxOption(), then call parent::__construct() from inside
of SelectBoxOption::__construct(); see if that clears up your problem
under
5.2 (read: this will only be a partial solution as it only addresses one
child of Tag).
Mmm. I hoped this would help, but all it seems to have done was cascade
errors across the rest of Tag's object children. :(
to be expected, but did it fix the problem w/ SelectBoxOption?
Copying the old constructor back in resolved that, but I'm not sure whether
that reintroduces the root problem.
Other objects derived from Tag seem to work just fine; I came into this
chunk of the code trying to find out why a SelectBoxOption didn't seem to
have a toString function - and then why trying to access what should be the
value and name the same way as with other objects derived at some level from
Tag blew up instead of working happily.
I'll try converting all of the constructors to your recommendation as
above, but given that the problem is only happening with this one class, I'm
not sure that will do much.
hopefully that clears it up .. and hopefully you're using version control :D
-nathan
Re: [PHP] String passed to object constructor turning into an instance of that object?
I've never used the old-style constructors, but perhaps the semantics of parent:: changed and you need to instead use $this- as in $this-Tag(option, $name); That's a total guess. I don't have 5.2 handy to try it out, but both work in 5.3 using a simple example. Can you post the constructor of one of the Tag subclasses that work? Maybe we can find a common denominator. David
Re: [PHP] String passed to object constructor turning into aninstance of that object?
On Thu, Dec 16, 2010 at 3:21 PM, Kris Deugau kdeu...@vianet.ca wrote:
Nathan Nobbe wrote:
Why not test for the type of $name at each point of interest in the
SelectBoxOption
constructor? If you're passing a string value to the constructor it
almost
has to be getting changed by the Tag constructor, right ?
class SelectBoxOption extends Tag {
function SelectBoxOption($name, $value, $selected=false) {
var_dump(is_string($name));
parent::Tag(option, $name);
var_dump(is_string($name));
Ah, that gives... well, it slightly alters the confusion.
Using var_dump(is_string($name)) gives... two results?
bool(true)
bool(false)
so you put one check before the call to parent::Tag() one directly after
right? That means *somehow* $name is getting set to an instance of
SelectBoxOption in the parent constructor which makes little to no sense..
especially after looking at implementation from your later post. Main
things are $name is local in the child constructor and there is no pass by
reference on the $name parameter in the parent constructor definition.
if this code runs w/o error on your 5.2 box, then there's something spurious
going on in that old library;
?php
class Tag
{
function Tag($sTag='', $sValue='')
{
$this-_sTag = $sTag;
$this-_sValue = $sValue;
}
}
class Child extends Tag
{
function Child($name)
{
var_dump($name);
parent::Tag('option', $name);
var_dump($name);
}
}
$oChild = new Child('content');
?
expected output:
string(7) content
string(7) content
I'd still recommend moving to the php5 notation throughout the library,
especially if doing that fixes the problem w/ SelectBoxOption. This
shouldn't break any client code, since clients should all be calling new
Class() and not be explicitly invoking the php4 style constructors. The
php4 style constructors should only be getting called explicitly from within
the library itself.
-nathan
Re: [PHP] String Parse Help for novice
At 9:29 PM -0400 6/13/10, Robert Cummings wrote:
?php
function my_parse_url( $url )
{
$parsed = parse_url( $url );
$parsed['file'] = basename( $parsed['path'] );
$parsed['pathbits'] = explode( '/', ltrim( dirname(
$parsed['path'] ), '/' ) );
return $parsed;
}
$url = my_parse_url( 'http://foo.fee.com/blah/bleh/bluh/meh.php' );
print_r( $url );
?
Cheers,
Rob.
Rob:
Very neat.
It also handles url's like this:
http://mydomain.com/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
See Demo here:
http://www.webbytedd.com/b4/parse-url/index.php
Cheers,
tedd
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Re: [PHP] String Parse Help for novice
tedd wrote:
At 9:29 PM -0400 6/13/10, Robert Cummings wrote:
?php
function my_parse_url( $url )
{
$parsed = parse_url( $url );
$parsed['file'] = basename( $parsed['path'] );
$parsed['pathbits'] = explode( '/', ltrim( dirname(
$parsed['path'] ), '/' ) );
return $parsed;
}
$url = my_parse_url( 'http://foo.fee.com/blah/bleh/bluh/meh.php' );
print_r( $url );
?
Cheers,
Rob.
Rob:
Very neat.
It also handles url's like this:
http://mydomain.com/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
See Demo here:
http://www.webbytedd.com/b4/parse-url/index.php
It's useful to leverage the work of others. So using parse_url() gets
you all the parsing stuff for a url without having to worry about the
spec (such as embedded user, password, port, parameters, and fragment.
Then we just augment to provide the extra functionality :)
Cheers,
Rob.
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[PHP] String Parse Help for novice
Hello List. I need to parse the PATH portion of URL. I have assigned the path portion to a variable using the following: $thepath = parse_url($url); Now I need to break each portion of the path down into its own variable. The problem is, the path can vary considerably as follows: /mydirectory/mysubdirectory/anothersubdirectory/mypage.php vs. /mydirectory/mypage.php How do I get the either of the above url paths broken out so the variables equal the following $dir1 = mydirectory $dir2 = mysubdirectory $dir3 = anothersubdirectory $page = mypage.php ...etc... if there were 5 more subdirectories... they would be dynamically assigned to a variable. Thanks for any help. --Rick -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String Parse Help for novice
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the filename
in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] String Parse Help for novice
On Jun 13, 2010, at 5:13 PM, Rick Dwyer wrote: Hello List. I need to parse the PATH portion of URL. I have assigned the path portion to a variable using the following: $thepath = parse_url($url); Now I need to break each portion of the path down into its own variable. The problem is, the path can vary considerably as follows: /mydirectory/mysubdirectory/anothersubdirectory/mypage.php vs. /mydirectory/mypage.php How do I get the either of the above url paths broken out so the variables equal the following $dir1 = mydirectory $dir2 = mysubdirectory $dir3 = anothersubdirectory $page = mypage.php ...etc... if there were 5 more subdirectories... they would be dynamically assigned to a variable. Thanks for any help. --Rick -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Hi Rick, Just a thought, but cant you do something to separate them according to the / (forward slash)? maybe preg_replace or something. Sorry not much more help. Karl DeSaulniers Design Drumm http://designdrumm.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String Parse Help for novice
On Jun 13, 2010, at 5:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename
in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Hi Ash,
What about the // in the beginning?
Karl DeSaulniers
Design Drumm
http://designdrumm.com
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Re: [PHP] String Parse Help for novice
On Sun, 2010-06-13 at 17:27 -0500, Karl DeSaulniers wrote:
On Jun 13, 2010, at 5:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename
in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Hi Ash,
What about the // in the beginning?
Karl DeSaulniers
Design Drumm
http://designdrumm.com
As your example string didn't have a double slash I didn't write code
for that, but it's easy enough to remove 0-length strings from the
$directories array.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] String Parse Help for novice
On Jun 13, 2010, at 5:31 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 17:27 -0500, Karl DeSaulniers wrote:
On Jun 13, 2010, at 5:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as
follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename
in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Hi Ash,
What about the // in the beginning?
Karl DeSaulniers
Design Drumm
http://designdrumm.com
As your example string didn't have a double slash I didn't write code
for that, but it's easy enough to remove 0-length strings from the
$directories array.
Thanks,
Ash
http://www.ashleysheridan.co.uk
:) Rick's example, but how in your example do we look for a double
forward slash?
THX
Karl DeSaulniers
Design Drumm
http://designdrumm.com
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Re: [PHP] String Parse Help for novice
OK, I get the following error:
Warning: basename() expects parameter 1 to be string, array given in
When I use the following:
$thepath = parse_url($url);
$filename = basename($thepath);
Is my variable thepath not automatically string?
--Rick
On Jun 13, 2010, at 6:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
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Re: [PHP] String Parse Help for novice
On Jun 13, 2010, at 5:35 PM, Rick Dwyer wrote: OK, I get the following error: Warning: basename() expects parameter 1 to be string, array given in When I use the following: $thepath = parse_url($url); $filename = basename($thepath); Is my variable thepath not automatically string? --Rick try echo($url); and see Karl DeSaulniers Design Drumm http://designdrumm.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String Parse Help for novice
On Sun, 2010-06-13 at 17:35 -0500, Karl DeSaulniers wrote:
On Jun 13, 2010, at 5:31 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 17:27 -0500, Karl DeSaulniers wrote:
On Jun 13, 2010, at 5:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as
follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename
in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Hi Ash,
What about the // in the beginning?
Karl DeSaulniers
Design Drumm
http://designdrumm.com
As your example string didn't have a double slash I didn't write code
for that, but it's easy enough to remove 0-length strings from the
$directories array.
Thanks,
Ash
http://www.ashleysheridan.co.uk
:) Rick's example, but how in your example do we look for a double
forward slash?
THX
Karl DeSaulniers
Design Drumm
http://designdrumm.com
You don't look for one, that's the point. The explode() breaks the
string into an array at every occurrence of a '/' character. This will
leave zero length strings in the array if there is a double // (which
wasn't in any given example in this thread that I saw) When you use the
array, just don't do anything with empty elements!
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] String Parse Help for novice
On Jun 13, 2010, at 5:35 PM, Rick Dwyer wrote: OK, I get the following error: Warning: basename() expects parameter 1 to be string, array given in When I use the following: $thepath = parse_url($url); $filename = basename($thepath); Is my variable thepath not automatically string? --Rick Oops I meant echo($the_path); or echo both and see. Karl DeSaulniers Design Drumm http://designdrumm.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String Parse Help for novice
On Sun, 2010-06-13 at 18:35 -0400, Rick Dwyer wrote:
OK, I get the following error:
Warning: basename() expects parameter 1 to be string, array given in
When I use the following:
$thepath = parse_url($url);
$filename = basename($thepath);
Is my variable thepath not automatically string?
--Rick
On Jun 13, 2010, at 6:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Because you've given it an array. Your original question never mentioned
you were using parse_url() on the original array string. parse_url()
breaks the string into its component parts, much like my explode
example.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] String Parse Help for novice
On Jun 13, 2010, at 5:40 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 17:35 -0500, Karl DeSaulniers wrote:
On Jun 13, 2010, at 5:31 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 17:27 -0500, Karl DeSaulniers wrote:
On Jun 13, 2010, at 5:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the
path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as
follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename
in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Hi Ash,
What about the // in the beginning?
Karl DeSaulniers
Design Drumm
http://designdrumm.com
As your example string didn't have a double slash I didn't write
code
for that, but it's easy enough to remove 0-length strings from the
$directories array.
Thanks,
Ash
http://www.ashleysheridan.co.uk
:) Rick's example, but how in your example do we look for a double
forward slash?
THX
Karl DeSaulniers
Design Drumm
http://designdrumm.com
You don't look for one, that's the point. The explode() breaks the
string into an array at every occurrence of a '/' character. This
will leave zero length strings in the array if there is a double //
(which wasn't in any given example in this thread that I saw) When
you use the array, just don't do anything with empty elements!
Thanks,
Ash
http://www.ashleysheridan.co.uk
Ahh.. that makes sense. Thanks Ash.
Karl DeSaulniers
Design Drumm
http://designdrumm.com
Re: [PHP] String Parse Help for novice
OK, sorry for any confusion.
Here is all my code:
$url = http . ((!empty($_SERVER['HTTPS'])) ? s : ) . ://.
$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
$thepath = parse_url($url);
So, given that the URL can vary as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
--Rick
On Jun 13, 2010, at 6:42 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:35 -0400, Rick Dwyer wrote:
OK, I get the following error:
Warning: basename() expects parameter 1 to be string, array given
in
When I use the following:
$thepath = parse_url($url);
$filename = basename($thepath);
Is my variable thepath not automatically string?
--Rick
On Jun 13, 2010, at 6:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as
follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Because you've given it an array. Your original question never
mentioned
you were using parse_url() on the original array string. parse_url()
breaks the string into its component parts, much like my explode
example.
Thanks,
Ash
http://www.ashleysheridan.co.uk
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Re: [PHP] String Parse Help for novice
On Sun, 2010-06-13 at 18:52 -0400, Rick Dwyer wrote:
OK, sorry for any confusion.
Here is all my code:
$url = http . ((!empty($_SERVER['HTTPS'])) ? s : ) . ://.
$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
$thepath = parse_url($url);
So, given that the URL can vary as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
--Rick
On Jun 13, 2010, at 6:42 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:35 -0400, Rick Dwyer wrote:
OK, I get the following error:
Warning: basename() expects parameter 1 to be string, array given
in
When I use the following:
$thepath = parse_url($url);
$filename = basename($thepath);
Is my variable thepath not automatically string?
--Rick
On Jun 13, 2010, at 6:23 PM, Ashley Sheridan wrote:
On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as
follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
--Rick
$filename = basename($path);
$parts = explode('/', $path);
$directories = array_pop($parts);
Now you have your directories in the $directories array and the
filename in $filename.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Because you've given it an array. Your original question never
mentioned
you were using parse_url() on the original array string. parse_url()
breaks the string into its component parts, much like my explode
example.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Take out the parse_url line and use the code I gave you, or keep the
parse_url line and drop my explode line.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] String Parse Help for novice
Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own
variable. The problem is, the path can vary considerably as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
?php
function my_parse_url( $url )
{
$parsed = parse_url( $url );
$parsed['file'] = basename( $parsed['path'] );
$parsed['pathbits'] = explode( '/', ltrim( dirname( $parsed['path']
), '/' ) );
return $parsed;
}
$url = my_parse_url( 'http://foo.fee.com/blah/bleh/bluh/meh.php' );
print_r( $url );
?
Cheers,
Rob.
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Re: [PHP] String Parse Help for novice
On Sun, Jun 13, 2010 at 9:29 PM, Robert Cummings rob...@interjinn.comwrote:
Rick Dwyer wrote:
Hello List.
I need to parse the PATH portion of URL. I have assigned the path
portion to a variable using the following:
$thepath = parse_url($url);
Now I need to break each portion of the path down into its own variable.
The problem is, the path can vary considerably as follows:
/mydirectory/mysubdirectory/anothersubdirectory/mypage.php
vs.
/mydirectory/mypage.php
How do I get the either of the above url paths broken out so the
variables equal the following
$dir1 = mydirectory
$dir2 = mysubdirectory
$dir3 = anothersubdirectory
$page = mypage.php
...etc... if there were 5 more subdirectories... they would be
dynamically assigned to a variable.
Thanks for any help.
?php
function my_parse_url( $url )
{
$parsed = parse_url( $url );
$parsed['file'] = basename( $parsed['path'] );
$parsed['pathbits'] = explode( '/', ltrim( dirname( $parsed['path'] ),
'/' ) );
return $parsed;
}
$url = my_parse_url( 'http://foo.fee.com/blah/bleh/bluh/meh.php' );
print_r( $url );
?
Cheers,
Rob.
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Clean and lean, Robert ;) Nice!
Adam
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Re: [PHP] php string syntax question with html
On Thu, 2010-03-11 at 08:03 +0100, Rene Veerman wrote: $var = 'bla'.$var2.'doh'.$var3['index'].'argh'.$var4[$var4index]; is so much more readable in any editor that does syntax highlighting, and parses quicker too. On Thu, Mar 11, 2010 at 1:15 AM, David Mehler dave.meh...@gmail.com wrote: Hello, I've got what is probably a very simple question, probably something having to do with quotes single vs. double, but the answer is frustrating elusive, I keep getting a syntax error. I'm trying to customize a wordpress theme a friend sent me. We're both using apache as web server and php5, but his has got to be configed differently than mine. The theme deals with multiple stylesheet inclusion among other things. The original line is: $styleSheets[0][sheet]='link href=/wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; That code puts the link in the head portion of the document. The issue is his / is not where mine is, i'm using a virtual host and need a line similar to this: $styleSheets[0][sheet]='link href=$_SERVER['DOCUMENT_ROOT'] . /wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; I've tried this with both double quotes before the link declaration, but keep getting a parse error. Help appreciated. Thanks. Dave. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Good catch Paul with the quotes around the array element! My editor highlights those strings even without me having to keep breaking out with concatenation Rene Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] php string syntax question with html
Ah, ok.. Turns out mine does too ;) So for light apps, it can be considered a coder's preference then.. On Thu, Mar 11, 2010 at 9:16 AM, Ashley Sheridan a...@ashleysheridan.co.ukwrote: My editor highlights those strings even without me having to keep breaking out with concatenation Rene
[PHP] php string syntax question with html
Hello, I've got what is probably a very simple question, probably something having to do with quotes single vs. double, but the answer is frustrating elusive, I keep getting a syntax error. I'm trying to customize a wordpress theme a friend sent me. We're both using apache as web server and php5, but his has got to be configed differently than mine. The theme deals with multiple stylesheet inclusion among other things. The original line is: $styleSheets[0][sheet]='link href=/wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; That code puts the link in the head portion of the document. The issue is his / is not where mine is, i'm using a virtual host and need a line similar to this: $styleSheets[0][sheet]='link href=$_SERVER['DOCUMENT_ROOT'] . /wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; I've tried this with both double quotes before the link declaration, but keep getting a parse error. Help appreciated. Thanks. Dave. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php string syntax question with html
Try this: 'link href='.$_SERVER['DOCUMENT_ROOT'] .'/wp-content/themes/themestyle/white.css rel=stylesheet type=text/css /'; On Wed, Mar 10, 2010 at 7:15 PM, David Mehler dave.meh...@gmail.com wrote: Hello, I've got what is probably a very simple question, probably something having to do with quotes single vs. double, but the answer is frustrating elusive, I keep getting a syntax error. I'm trying to customize a wordpress theme a friend sent me. We're both using apache as web server and php5, but his has got to be configed differently than mine. The theme deals with multiple stylesheet inclusion among other things. The original line is: $styleSheets[0][sheet]='link href=/wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; That code puts the link in the head portion of the document. The issue is his / is not where mine is, i'm using a virtual host and need a line similar to this: $styleSheets[0][sheet]='link href=$_SERVER['DOCUMENT_ROOT'] . /wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; I've tried this with both double quotes before the link declaration, but keep getting a parse error. Help appreciated. Thanks. Dave. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Nephtali: PHP web framework that functions beautifully http://nephtaliproject.com
Re: [PHP] php string syntax question with html
On Wed, 2010-03-10 at 19:33 -0500, Adam Richardson wrote:
Try this:
'link href='.$_SERVER['DOCUMENT_ROOT']
.'/wp-content/themes/themestyle/white.css rel=stylesheet type=text/css
/';
On Wed, Mar 10, 2010 at 7:15 PM, David Mehler dave.meh...@gmail.com wrote:
Hello,
I've got what is probably a very simple question, probably something
having to do with quotes single vs. double, but the answer is
frustrating elusive, I keep getting a syntax error.
I'm trying to customize a wordpress theme a friend sent me. We're both
using apache as web server and php5, but his has got to be configed
differently than mine. The theme deals with multiple stylesheet
inclusion among other things. The original line is:
$styleSheets[0][sheet]='link
href=/wp-content/themes/theme/style/white.css rel=stylesheet
type=text/css /';
That code puts the link in the head portion of the document. The
issue is his / is not where mine is, i'm using a virtual host and need
a line similar to this:
$styleSheets[0][sheet]='link href=$_SERVER['DOCUMENT_ROOT'] .
/wp-content/themes/theme/style/white.css rel=stylesheet
type=text/css /';
I've tried this with both double quotes before the link declaration,
but keep getting a parse error.
Help appreciated.
Thanks.
Dave.
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You're using single quotes in your string, so you can't have PHP parse
the string for variables to extend into their corresponding values. If
you wish to do that, use either double-quoted strings or heredoc/nowdoc
syntax:
$styleSheets[0][sheet]=link href=
\{$_SERVER['DOCUMENT_ROOT']}/wp-content/themes/theme/style/white.css\
rel=\stylesheet\ type=\text/css\ /;
or
$styleSheets[0][sheet]= EOS
link
href={$_SERVER['DOCUMENT_ROOT']}/wp-content/themes/theme/style/white.css
rel=stylesheet type=text/css /
EOS;
In both cases note the {} surrounding the variable. This is because PHP
needs to be told that you are trying to access an array element,
otherwise it will match only as far as $_SERVER and think that the
[ character starts regular text. This also works with object properties
and method return values:
echo {$some_obect-some_value} and {$some_object-some_method()};
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] php string syntax question with html
On Thu, Mar 11, 2010 at 01:17:57AM +, Ashley Sheridan wrote:
snip
You're using single quotes in your string, so you can't have PHP parse
the string for variables to extend into their corresponding values. If
you wish to do that, use either double-quoted strings or heredoc/nowdoc
syntax:
$styleSheets[0][sheet]=link href=
\{$_SERVER['DOCUMENT_ROOT']}/wp-content/themes/theme/style/white.css\
rel=\stylesheet\ type=\text/css\ /;
or
$styleSheets[0][sheet]= EOS
link
href={$_SERVER['DOCUMENT_ROOT']}/wp-content/themes/theme/style/white.css
rel=stylesheet type=text/css /
EOS;
In both cases note the {} surrounding the variable. This is because PHP
needs to be told that you are trying to access an array element,
otherwise it will match only as far as $_SERVER and think that the
[ character starts regular text. This also works with object properties
and method return values:
echo {$some_obect-some_value} and {$some_object-some_method()};
Um, not exactly. This will parse correctly: $_SERVER[DOCUMENT_ROOT].
You just can't use single quotes inside the brackets to denote the array
index, when the whole string is surrounded by double quotes. A more
pedestrian example:
$message = The value of foo is $_POST[bar]\n;
You are, however, right about object properties. I know of no other way
to parse them inside a quoted string, other than using braces.
Paul
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Re: [PHP] php string syntax question with html
$var = 'bla'.$var2.'doh'.$var3['index'].'argh'.$var4[$var4index]; is so much more readable in any editor that does syntax highlighting, and parses quicker too. On Thu, Mar 11, 2010 at 1:15 AM, David Mehler dave.meh...@gmail.com wrote: Hello, I've got what is probably a very simple question, probably something having to do with quotes single vs. double, but the answer is frustrating elusive, I keep getting a syntax error. I'm trying to customize a wordpress theme a friend sent me. We're both using apache as web server and php5, but his has got to be configed differently than mine. The theme deals with multiple stylesheet inclusion among other things. The original line is: $styleSheets[0][sheet]='link href=/wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; That code puts the link in the head portion of the document. The issue is his / is not where mine is, i'm using a virtual host and need a line similar to this: $styleSheets[0][sheet]='link href=$_SERVER['DOCUMENT_ROOT'] . /wp-content/themes/theme/style/white.css rel=stylesheet type=text/css /'; I've tried this with both double quotes before the link declaration, but keep getting a parse error. Help appreciated. Thanks. Dave. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string concatenation with fgets
aurfal...@gmail.com wrote:
So here is my final test code, notice the check for ' ' in the if.
Since I'm on Linux, this has to do with whats between the last LF and
EOF which is nothing but this nothing will get printed out.
$file = fopen(somefile.txt, r);
while (! feof($file))
{
$tmp = trim(fgets($file));
if ($tmp != '')
{
$names = $tmp;
}
print $names.sometext\n;
}
fclose($file);
--
Thanks!
-Shawn
http://www.spidean.com
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Re: [PHP] string concatenation with fgets
Hi Shawn,
Your code looks cleaner then mine so i tried it and got the last entry
in the txt file printed twice.
On Nov 30, 2009, at 7:07 AM, Shawn McKenzie wrote:
aurfal...@gmail.com wrote:
So here is my final test code, notice the check for ' ' in the if.
Since I'm on Linux, this has to do with whats between the last LF and
EOF which is nothing but this nothing will get printed out.
$file = fopen(somefile.txt, r);
while (! feof($file))
{
$tmp = trim(fgets($file));
if ($tmp != '')
{
$names = $tmp;
}
print $names.sometext\n;
}
fclose($file);
--
Thanks!
-Shawn
http://www.spidean.com
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Re: [PHP] string concatenation with fgets
On Mon, 2009-11-30 at 09:04 -0800, aurfal...@gmail.com wrote:
Hi Shawn,
Your code looks cleaner then mine so i tried it and got the last entry
in the txt file printed twice.
On Nov 30, 2009, at 7:07 AM, Shawn McKenzie wrote:
aurfal...@gmail.com wrote:
So here is my final test code, notice the check for ' ' in the if.
Since I'm on Linux, this has to do with whats between the last LF and
EOF which is nothing but this nothing will get printed out.
$file = fopen(somefile.txt, r);
while (! feof($file))
{
$tmp = trim(fgets($file));
if ($tmp != '')
{
$names = $tmp;
}
print $names.sometext\n;
}
fclose($file);
--
Thanks!
-Shawn
http://www.spidean.com
Remove the if statement and just print out $tmp. The while loop is going
over one extra time than you need, and on that final iteration, $tmp is
an empty string. The if statement only changes $name if $tmp is empty,
so it leaves it as it was, hence you getting the last line printed
twice. Printing out an empty string in this example won't do anything,
and the if statement is also pretty useless as it just copies the value
to another variable on a condition that will only result in the
side-effect you've noticed.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] string concatenation with fgets
Hi Ash,
Actually I need the if because the code will print out an empty line
and add sometext to it.
So without the if check for an empty line, at the end of the loop I'll
get sometext. For example, if the file I am processing called
somename.txt has
a
b
c
in it. I'll have;
asometext
bsometext
csometext
but w/o the if check, I'll also have
sometext
as well.
On Nov 30, 2009, at 9:24 AM, Ashley Sheridan wrote:
On Mon, 2009-11-30 at 09:04 -0800, aurfal...@gmail.com wrote:
Hi Shawn,
Your code looks cleaner then mine so i tried it and got the last
entry
in the txt file printed twice.
On Nov 30, 2009, at 7:07 AM, Shawn McKenzie wrote:
aurfal...@gmail.com wrote:
So here is my final test code, notice the check for ' ' in the if.
Since I'm on Linux, this has to do with whats between the last
LF and
EOF which is nothing but this nothing will get printed out.
$file = fopen(somefile.txt, r);
while (! feof($file))
{
$tmp = trim(fgets($file));
if ($tmp != '')
{
$names = $tmp;
}
print $names.sometext\n;
}
fclose($file);
--
Thanks!
-Shawn
http://www.spidean.com
Remove the if statement and just print out $tmp. The while loop is
going over one extra time than you need, and on that final
iteration, $tmp is an empty string. The if statement only changes
$name if $tmp is empty, so it leaves it as it was, hence you getting
the last line printed twice. Printing out an empty string in this
example won't do anything, and the if statement is also pretty
useless as it just copies the value to another variable on a
condition that will only result in the side-effect you've noticed.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] string concatenation with fgets
On Mon, 2009-11-30 at 09:40 -0800, aurfal...@gmail.com wrote:
Hi Ash,
Actually I need the if because the code will print out an empty line
and add sometext to it.
So without the if check for an empty line, at the end of the loop I'll
get sometext. For example, if the file I am processing called
somename.txt has
a
b
c
in it. I'll have;
asometext
bsometext
csometext
but w/o the if check, I'll also have
sometext
as well.
On Nov 30, 2009, at 9:24 AM, Ashley Sheridan wrote:
On Mon, 2009-11-30 at 09:04 -0800, aurfal...@gmail.com wrote:
Hi Shawn,
Your code looks cleaner then mine so i tried it and got the last
entry
in the txt file printed twice.
On Nov 30, 2009, at 7:07 AM, Shawn McKenzie wrote:
aurfal...@gmail.com wrote:
So here is my final test code, notice the check for ' ' in the if.
Since I'm on Linux, this has to do with whats between the last
LF and
EOF which is nothing but this nothing will get printed out.
$file = fopen(somefile.txt, r);
while (! feof($file))
{
$tmp = trim(fgets($file));
if ($tmp != '')
{
$names = $tmp;
}
print $names.sometext\n;
}
fclose($file);
--
Thanks!
-Shawn
http://www.spidean.com
Remove the if statement and just print out $tmp. The while loop is
going over one extra time than you need, and on that final
iteration, $tmp is an empty string. The if statement only changes
$name if $tmp is empty, so it leaves it as it was, hence you getting
the last line printed twice. Printing out an empty string in this
example won't do anything, and the if statement is also pretty
useless as it just copies the value to another variable on a
condition that will only result in the side-effect you've noticed.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Then put the print statement inside the if, not the assignation,
otherwise you will always get that last line!
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] string concatenation with fgets
So here is my final test code, notice the check for ' ' in the if.
Since I'm on Linux, this has to do with whats between the last LF and
EOF which is nothing but this nothing will get printed out.
$file = fopen(somefile.txt, r);
while (! feof($file))
{
$names = trim(fgets($file));
if ($names == '')
{
break;
}
print $names.sometext\n;
}
fclose($file);
- aurf
On Nov 24, 2009, at 5:52 PM, ryan wrote:
Is this what you want
$file = fopen(test.txt, r);
while (!feof($file)) {
$line = trim(fgets($file));
print $line.sometext\n;
}
fclose($file);
outputs
asometext
bsometext
csometext
Ref to http://us3.php.net/manual/en/function.fgets.php. Reading
ends when /length/ - 1 bytes have been read, on a newline (which is
included in the return value), or on EOF (whichever comes first). If
no length is specified, it will keep reading from the stream until
it reaches the end of the line.
aurfal...@gmail.com wrote:
Hi all,
I'm trying to append some text to what I read from a file.
My code;
$file = fopen(foo.txt, r);
while (!feof($file)) {
$line = fgets($file);
print $line.sometext;
}
fclose($file);
foo,txt;
a
b
c
d
e
f
g
And when I run the script, it looks like;
a
sometextb
sometextc
sometextd
...
Any ideas?
Thanks in advance,
- aurf
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[PHP] string concatenation with fgets
Hi all,
I'm trying to append some text to what I read from a file.
My code;
$file = fopen(foo.txt, r);
while (!feof($file)) {
$line = fgets($file);
print $line.sometext;
}
fclose($file);
foo,txt;
a
b
c
d
e
f
g
And when I run the script, it looks like;
a
sometextb
sometextc
sometextd
...
Any ideas?
Thanks in advance,
- aurf
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Re: [PHP] string concatenation with fgets
Is this what you want
$file = fopen(test.txt, r);
while (!feof($file)) {
$line = trim(fgets($file));
print $line.sometext\n;
}
fclose($file);
outputs
asometext
bsometext
csometext
Ref to http://us3.php.net/manual/en/function.fgets.php. Reading ends
when /length/ - 1 bytes have been read, on a newline (which is included
in the return value), or on EOF (whichever comes first). If no length is
specified, it will keep reading from the stream until it reaches the end
of the line.
aurfal...@gmail.com wrote:
Hi all,
I'm trying to append some text to what I read from a file.
My code;
$file = fopen(foo.txt, r);
while (!feof($file)) {
$line = fgets($file);
print $line.sometext;
}
fclose($file);
foo,txt;
a
b
c
d
e
f
g
And when I run the script, it looks like;
a
sometextb
sometextc
sometextd
...
Any ideas?
Thanks in advance,
- aurf
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Re: [PHP] string concatenation with fgets
--- On Wed, 11/25/09, aurfal...@gmail.com aurfal...@gmail.com wrote:
From: aurfal...@gmail.com aurfal...@gmail.com
Subject: [PHP] string concatenation with fgets
To: php-general@lists.php.net
Date: Wednesday, November 25, 2009, 7:00 AM
Hi all,
I'm trying to append some text to what I read from a file.
My code;
$file = fopen(foo.txt, r);
while (!feof($file)) {
$line = fgets($file);
print $line.sometext;
}
fclose($file);
foo,txt;
a
b
c
d
e
f
g
And when I run the script, it looks like;
a
sometextb
sometextc
sometextd
...
Any ideas?
So, what output you actually wants from your program?
Is it like this
asometextbsometextcsometext..
or, like this
asometext
bsometext
csometext
---
নির্মাল্য লাহিড়ী [Nirmalya Lahiri]
+৯১-৯৪৩৩১১৩৫৩৬ [+91-9433113536]
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Re: [PHP] string concatenation with fgets
On Nov 24, 2009, at 5:55 PM, Nirmalya Lahiri wrote:
--- On Wed, 11/25/09, aurfal...@gmail.com aurfal...@gmail.com wrote:
From: aurfal...@gmail.com aurfal...@gmail.com
Subject: [PHP] string concatenation with fgets
To: php-general@lists.php.net
Date: Wednesday, November 25, 2009, 7:00 AM
Hi all,
I'm trying to append some text to what I read from a file.
My code;
$file = fopen(foo.txt, r);
while (!feof($file)) {
$line = fgets($file);
print $line.sometext;
}
fclose($file);
foo,txt;
a
b
c
d
e
f
g
And when I run the script, it looks like;
a
sometextb
sometextc
sometextd
...
Any ideas?
So, what output you actually wants from your program?
Is it like this
asometextbsometextcsometext..
or, like this
asometext
bsometext
csometext
Hi,
Sorry, I was incomplete :)
I would like;
asometext
bsometext
csometext
Basically, I would like to add whatever text to the end of what I find
in the file.
So if the file contains
a
b
c
I would like;
asometext
bsometext
csometext...
- aurf
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Re: [PHP] string concatenation with fgets
On Nov 24, 2009, at 5:52 PM, ryan wrote:
Is this what you want
$file = fopen(test.txt, r);
while (!feof($file)) {
$line = trim(fgets($file));
print $line.sometext\n;
}
fclose($file);
outputs
asometext
bsometext
csometext
Ref to http://us3.php.net/manual/en/function.fgets.php. Reading
ends when /length/ - 1 bytes have been read, on a newline (which is
included in the return value), or on EOF (whichever comes first). If
no length is specified, it will keep reading from the stream until
it reaches the end of the line.
aurfal...@gmail.com wrote:
Hi all,
I'm trying to append some text to what I read from a file.
My code;
$file = fopen(foo.txt, r);
while (!feof($file)) {
$line = fgets($file);
print $line.sometext;
}
fclose($file);
foo,txt;
a
b
c
d
e
f
g
And when I run the script, it looks like;
a
sometextb
sometextc
sometextd
...
Any ideas?
Thanks in advance,
- aurf
OMG, very very cool, thanks Ryan.
- aurf
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[PHP] Re: PHP String convention
Nick Cooper wrote:
Hi,
I was just wondering what the difference/advantage of these two
methods of writing a string are:
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
1) breaks PHPUnit when used in classes (need to bug report that)
2) [concatenation] is faster (but you wouldn't notice)
comes down to personal preference and what looks best in your (teams)
IDE I guess; legibility (and possibly portability) is probably the
primary concern.
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Re: [PHP] PHP String convention
2009/10/28 Warren Vail war...@vailtech.net:
The curly braces look like something from the smarty template engine.
Warren Vail
Odd. I always thought the curly braces in the Smarty engine looked
like something from PHP. :)
Torben
-Original Message-
From: Kim Madsen [mailto:php@emax.dk]
Sent: Wednesday, October 28, 2009 10:18 AM
To: Nick Cooper
Cc: Jim Lucas; php-general@lists.php.net
Subject: Re: [PHP] PHP String convention
Hi Nick
Nick Cooper wrote on 2009-10-28 17:29:
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
Yes, you're right about that. 10 years ago I went to a seminar were
Rasmus Lerforf was speaking and asked him exactly that question. The
single qoutes are preferred and are way faster because it doesn´t have
to parse the string, only the glued variables.
Also we discussed that if you´re doing a bunch of HTML code it's
considerably faster to do:
tr
td?= $data ?/td
/tr
Than
print
\n\ttr
\n\t\ttd$data/td
\n\t/tr;
or
print '
tr
td'.$data.'/td
/tr';
I remember benchmark testing it afterwards back then and there was
clearly a difference.
--
Kind regards
Kim Emax - masterminds.dk
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Re: [PHP] Re: PHP String convention
2009/11/4 Nathan Rixham nrix...@gmail.com:
Nick Cooper wrote:
Hi,
I was just wondering what the difference/advantage of these two
methods of writing a string are:
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
1) breaks PHPUnit when used in classes (need to bug report that)
2) [concatenation] is faster (but you wouldn't notice)
comes down to personal preference and what looks best in your (teams) IDE I
guess; legibility (and possibly portability) is probably the primary
concern.
I would tend to agree here; the concat is faster but you may well only
notice in very tight loops. The curly brace syntax can increase code
readability, depending on the complexity of the expression. I use
them both depending on the situation.
Remember the rules of optimization:
1) Don't.
2) (Advanced users only): Optimize later.
Write code so that it's readable, and then once it's working, identify
the bottlenecks and optimize where needed. If you understand code
analysis and big-O etc then you will start to automatically write
mostly-optimized code anyway and in general, I doubt that you'll often
identify the use of double quotes as a bottleneck--it almost always
turns out that other operations and code structures are far more
expensive and impact code speed much more.
That said, you don't really lose anything by using concatenation from
the start, except perhaps some legibility, so as Nathan said it often
really just comes down to personal preference and perhaps the house
coding conventions.
Regards,
Torben
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[PHP] PHP String convention
Hi,
I was just wondering what the difference/advantage of these two
methods of writing a string are:
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
I always use method 2 but have been noticing method 1 more and more in
source code. Is this just user preference?
I would use a generic search engine but not sure what the first method
is called so don't know where to begin my search.
Thanks for any help.
Nick
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RE: [PHP] PHP String convention
[snip]I was just wondering what the difference/advantage of these two methods of writing a string are:[/snip] Method 2 is faster, YMMV. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP String convention
Nick Cooper wrote:
Hi,
I was just wondering what the difference/advantage of these two
methods of writing a string are:
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
I always use method 2 but have been noticing method 1 more and more in
source code. Is this just user preference?
I would use a generic search engine but not sure what the first method
is called so don't know where to begin my search.
Thanks for any help.
Nick
I think it is a matter of personal preference. I prefer method 1 myself.
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Re: [PHP] PHP String convention
2009/10/28 Jim Lucas:
Nick Cooper wrote:
Hi,
I was just wondering what the difference/advantage of these two
methods of writing a string are:
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
I always use method 2 but have been noticing method 1 more and more in
source code. Is this just user preference?
I would use a generic search engine but not sure what the first method
is called so don't know where to begin my search.
Thanks for any help.
Nick
I think it is a matter of personal preference. I prefer method 1 myself.
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
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Re: [PHP] PHP String convention
On Wed, 2009-10-28 at 16:29 +, Nick Cooper wrote:
2009/10/28 Jim Lucas:
Nick Cooper wrote:
Hi,
I was just wondering what the difference/advantage of these two
methods of writing a string are:
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
I always use method 2 but have been noticing method 1 more and more in
source code. Is this just user preference?
I would use a generic search engine but not sure what the first method
is called so don't know where to begin my search.
Thanks for any help.
Nick
I think it is a matter of personal preference. I prefer method 1 myself.
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
This was on the list a few days back. Basically, the braces are there to
force PHP to recognise the full variable name, so that you could type:
$string = {$foo}bar;
$string = foo{$bar[0][1]};
$string = {$foo-bar};
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] PHP String convention
Nick Cooper wrote:
2009/10/28 Jim Lucas:
Nick Cooper wrote:
Hi,
I was just wondering what the difference/advantage of these two
methods of writing a string are:
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
I always use method 2 but have been noticing method 1 more and more in
source code. Is this just user preference?
I would use a generic search engine but not sure what the first method
is called so don't know where to begin my search.
Thanks for any help.
Nick
I think it is a matter of personal preference. I prefer method 1 myself.
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
They tell PHP to view the text between the curly braces as a variable that needs
interpreting.
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Re: [PHP] PHP String convention
Hi Nick
Nick Cooper wrote on 2009-10-28 17:29:
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
Yes, you're right about that. 10 years ago I went to a seminar were
Rasmus Lerforf was speaking and asked him exactly that question. The
single qoutes are preferred and are way faster because it doesn´t have
to parse the string, only the glued variables.
Also we discussed that if you´re doing a bunch of HTML code it's
considerably faster to do:
tr
td?= $data ?/td
/tr
Than
print
\n\ttr
\n\t\ttd$data/td
\n\t/tr;
or
print '
tr
td'.$data.'/td
/tr';
I remember benchmark testing it afterwards back then and there was
clearly a difference.
--
Kind regards
Kim Emax - masterminds.dk
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RE: [PHP] PHP String convention
The curly braces look like something from the smarty template engine.
Warren Vail
-Original Message-
From: Kim Madsen [mailto:php@emax.dk]
Sent: Wednesday, October 28, 2009 10:18 AM
To: Nick Cooper
Cc: Jim Lucas; php-general@lists.php.net
Subject: Re: [PHP] PHP String convention
Hi Nick
Nick Cooper wrote on 2009-10-28 17:29:
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
Yes, you're right about that. 10 years ago I went to a seminar were
Rasmus Lerforf was speaking and asked him exactly that question. The
single qoutes are preferred and are way faster because it doesn´t have
to parse the string, only the glued variables.
Also we discussed that if you´re doing a bunch of HTML code it's
considerably faster to do:
tr
td?= $data ?/td
/tr
Than
print
\n\ttr
\n\t\ttd$data/td
\n\t/tr;
or
print '
tr
td'.$data.'/td
/tr';
I remember benchmark testing it afterwards back then and there was
clearly a difference.
--
Kind regards
Kim Emax - masterminds.dk
--
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Re: [PHP] PHP String convention
On Wed, 2009-10-28 at 18:18 +0100, Kim Madsen wrote:
Hi Nick
Nick Cooper wrote on 2009-10-28 17:29:
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
Yes, you're right about that. 10 years ago I went to a seminar were
Rasmus Lerforf was speaking and asked him exactly that question. The
single qoutes are preferred and are way faster because it doesn´t have
to parse the string, only the glued variables.
Also we discussed that if you´re doing a bunch of HTML code it's
considerably faster to do:
tr
td?= $data ?/td
/tr
Than
print
\n\ttr
\n\t\ttd$data/td
\n\t/tr;
or
print '
tr
td'.$data.'/td
/tr';
I remember benchmark testing it afterwards back then and there was
clearly a difference.
--
Kind regards
Kim Emax - masterminds.dk
Or, far easier still to do:
print EOC
tr
td$data/td
/tr
tr
td$data/td
/tr
EOC;
than:
tr
td?= $data ?/td
/tr
tr
td?= $data ?/td
/tr
Also, the use of short tags in the second example will almost certainly cause
problems later on if you want to do anything with XML output from PHP.
Thanks,
Ash
http://www.ashleysheridan.co.uk
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Re: [PHP] PHP String convention
Kim Madsen wrote:
Hi Nick
Nick Cooper wrote on 2009-10-28 17:29:
Thank you for the quick replies. I thought method 2 must be faster
because it doesn't have to search for variables in the string.
So what is the advantages then of method 1 over 3, do the curly braces
mean anything?
1) $string = foo{$bar};
2) $string = 'foo'.$bar;
3) $string = foo$bar;
I must admit reading method 1 is easier, but writing method 2 is
quicker, is that the only purpose the curly braces serve?
Yes, you're right about that. 10 years ago I went to a seminar were
Rasmus Lerforf was speaking and asked him exactly that question. The
single qoutes are preferred and are way faster because it doesn´t have
to parse the string, only the glued variables.
Also we discussed that if you´re doing a bunch of HTML code it's
considerably faster to do:
tr
td?= $data ?/td
/tr
Than
print
\n\ttr
\n\t\ttd$data/td
\n\t/tr;
or
print '
tr
td'.$data.'/td
/tr';
I remember benchmark testing it afterwards back then and there was
clearly a difference.
10 years is a long time... there have been benchmarks posted to this
list in the past year or so indicating that in the PHP5 release there is
no real difference in speed between the use of single or double quotes.
If I recall correctly double quotes may even be eking out a small
advantage over single quotes nowadays.
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
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Re: [PHP] String scrambling
!niBgo /* $str = Bingo!; str_shuffle($str); */ :)
Re: [PHP] String scrambling
On Fri, 2009-09-11 at 11:03 +0100, Tom Chubb wrote: !niBgo /* $str = Bingo!; str_shuffle($str); */ :) No, that won't work at all, it's in comments ;) Thanks, Ash http://www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String scrambling
On Thu, Sep 10, 2009 at 8:57 PM, Ron Piggott ron@actsministries.org wrote: Is there a function in PHP which scrambles strings? Example: $string = Hello; Output might be: ehlol Ron http://www.php.net/manual/en/function.str-shuffle.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] String Formulas
How can I take a mathematical formula that is in a string and have the result, product, sum, etc. returned? I did a search on the Web and couldn't find any suitable solutions. Thanks! Floyd -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] String to Date Conversion Problem
Hi, Guys: I am trying to turn a prepared line into a date format, and the string looks something like this: 23 JUL 09 - THURSDAY, and I am trying to change the string to a mm/dd/ format that looks like 07/23/2009. I tried to use strtotime() but it gave me nothing. Here is the code: list($date,$month,$year,$dash,$day) = split( ,$line,5); echo date2 . strtotime($date . \s . $month . \s . $year). /date2; Could anyone on the list please give me a hint on what I might have done wrong here? Thanks for your help. Alice _ All-in-one security and maintenance for your PC. Get a free 90-day trial! http://www.windowsonecare.com/purchase/trial.aspx?sc_cid=wl_wlmail
Re: [PHP] String to Date Conversion Problem
Hi Alice,
Based on the string format that you mentioned (DD MMM YY - DAY) you
should be able to transform to any other date using the following:
$parts = explode(' ', '23 JUL 09 - THURSDAY');
echo date('m/d/Y', strtotime({$parts[1]} {$parts[0]} {$parts[2]}));
Cheers
Stuart
On 31 Jul 2009, at 15:19, Alice Wei wrote:
Hi, Guys:
I am trying to turn a prepared line into a date format, and the
string looks something like this: 23 JUL 09 - THURSDAY, and I am
trying to change the string to a mm/dd/ format that looks like
07/23/2009.
I tried to use strtotime() but it gave me nothing.
Here is the code:
list($date,$month,$year,$dash,$day) = split( ,$line,5);
echo date2 . strtotime($date . \s . $month . \s .
$year). /date2;
Could anyone on the list please give me a hint on what I might have
done wrong here?
Thanks for your help.
Alice
_
All-in-one security and maintenance for your PC. Get a free 90-day
trial!
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smime.p7s
Description: S/MIME cryptographic signature
RE: [PHP] String to Date Conversion Problem
Looks like what I did by using mm/dd/ was extra, which was probably why it
didn't work.
Thanks, looks like this is up and running now.
Alice
CC: php-general@lists.php.net
From: stu...@stuconnolly.com
To: aj...@alumni.iu.edu
Subject: Re: [PHP] String to Date Conversion Problem
Date: Fri, 31 Jul 2009 15:45:44 +0100
Hi Alice,
Based on the string format that you mentioned (DD MMM YY - DAY) you
should be able to transform to any other date using the following:
$parts = explode(' ', '23 JUL 09 - THURSDAY');
echo date('m/d/Y', strtotime({$parts[1]} {$parts[0]} {$parts[2]}));
Cheers
Stuart
On 31 Jul 2009, at 15:19, Alice Wei wrote:
Hi, Guys:
I am trying to turn a prepared line into a date format, and the
string looks something like this: 23 JUL 09 - THURSDAY, and I am
trying to change the string to a mm/dd/ format that looks like
07/23/2009.
I tried to use strtotime() but it gave me nothing.
Here is the code:
list($date,$month,$year,$dash,$day) = split( ,$line,5);
echo date2 . strtotime($date . \s . $month . \s .
$year). /date2;
Could anyone on the list please give me a hint on what I might have
done wrong here?
Thanks for your help.
Alice
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Re: [PHP] String variable
On Sun, Jan 11, 2009 at 8:59 AM, MikeP mpel...@princeton.edu wrote:
Hello,
I am trying yo get THIS:
where ref_id = '1234'
from this.
$where=where ref_id=.'$Reference[$x][ref_id]';
but i certainly have a quote problem.
Any help?
Thanks
Mike
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Looks like you're missing the single tics around ref_id. In your
example you'd want one of these:
$where=where ref_id=.'{$Reference[$x]['ref_id']};
$where=where ref_id=.$Reference[$x]['ref_id'];
$where=sprintf(where ref_id=%d, (int)$Reference[$x]['ref_id']); --
use this one or else! (sql injection)
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Re: [PHP] String variable
On Sun, 2009-01-11 at 08:59 -0500, MikeP wrote:
Hello,
I am trying yo get THIS:
where ref_id = '1234'
from this.
$where=where ref_id=.'$Reference[$x][ref_id]';
but i certainly have a quote problem.
Any help?
Thanks
Mike
It should look like this:
$where=where ref_id='{$Reference[$x][ref_id]}';
Ash
www.ashleysheridan.co.uk
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Re: [PHP] String variable
On Sun, 2009-01-11 at 14:36 +, Ashley Sheridan wrote:
On Sun, 2009-01-11 at 08:59 -0500, MikeP wrote:
Hello,
I am trying yo get THIS:
where ref_id = '1234'
from this.
$where=where ref_id=.'$Reference[$x][ref_id]';
but i certainly have a quote problem.
Any help?
Thanks
Mike
It should look like this:
$where=where ref_id='{$Reference[$x][ref_id]}';
Ash
www.ashleysheridan.co.uk
Sorry, it should look like this:
$where=where ref_id='{$Reference[$x][ref_id]}';
I missed taking an extra quote mark out
Ash
www.ashleysheridan.co.uk
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Re: [PHP] String variable
Ashley Sheridan wrote:
On Sun, 2009-01-11 at 14:36 +, Ashley Sheridan wrote:
On Sun, 2009-01-11 at 08:59 -0500, MikeP wrote:
Hello,
I am trying yo get THIS:
where ref_id = '1234'
from this.
$where=where ref_id=.'$Reference[$x][ref_id]';
but i certainly have a quote problem.
Any help?
Thanks
Mike
It should look like this:
$where=where ref_id='{$Reference[$x][ref_id]}';
Ash
www.ashleysheridan.co.uk
Sorry, it should look like this:
$where=where ref_id='{$Reference[$x][ref_id]}';
I missed taking an extra quote mark out
Ash
www.ashleysheridan.co.uk
actually unless ref_id is a constant (which i doublt) you may be best
going with:
$where = WHERE ref_id=' . $Reference[$x]['ref_id'] . ';
keep the php and sql seperate and you'll find it much easier to see in
you're editor
(imho) :)
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Re: [PHP] String variable
2009/1/11 Ashley Sheridan a...@ashleysheridan.co.uk:
On Sun, 2009-01-11 at 14:36 +, Ashley Sheridan wrote:
On Sun, 2009-01-11 at 08:59 -0500, MikeP wrote:
Hello,
I am trying yo get THIS:
where ref_id = '1234'
from this.
$where=where ref_id=.'$Reference[$x][ref_id]';
but i certainly have a quote problem.
Any help?
Thanks
Mike
It should look like this:
$where=where ref_id='{$Reference[$x][ref_id]}';
Ash
www.ashleysheridan.co.uk
Sorry, it should look like this:
$where=where ref_id='{$Reference[$x][ref_id]}';
I missed taking an extra quote mark out
Closer, but still not quite there. For encapsulation in the string, it
should look like:
$where = where ref_is='{$Reference[$x]['ref_id']}';
Someone else mentioned casting to int first as well to sanitize, which
is also a good idea.
Torben
Ash
www.ashleysheridan.co.uk
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[PHP] string comparison
hi i am writing a small application where a user enters a phrase in the textfield and i would like to display all the files present in the root directory which consists of the keyword or keywords entered by the user. i have used a few comparison functions but i am not getting the expected result. $my_file = file_get_contents(filename.html); what ever the user enters whether it is a single word or few words i would like to compare with $my_file in a case insensitive manner. can anyone suggest the best method and how to go about. thanks.
Re: [PHP] string comparison
On Sun, 2008-07-13 at 21:47 +0530, Sudhakar wrote: hi i am writing a small application where a user enters a phrase in the textfield and i would like to display all the files present in the root directory which consists of the keyword or keywords entered by the user. i have used a few comparison functions but i am not getting the expected result. $my_file = file_get_contents(filename.html); what ever the user enters whether it is a single word or few words i would like to compare with $my_file in a case insensitive manner. can anyone suggest the best method and how to go about. I don't suggest using file_get_contents. It would probably be more efficient (at least less memory intensive) to use fopen() and fread(). Just be sure you overlap each read by $the_size_of_the_largest phrase_or_keyword - 1. Then use stripos() for matching... of course that won't work so well if whitespace doesn't need to match exactly in phrases. In which case you'll need to resort to other techniques. Cheers, Rob. -- http://www.interjinn.com Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string comparison
On Jul 13, 2008, at 9:17 AM, Sudhakar wrote:
hi
i am writing a small application where a user enters a phrase in the
textfield and i would like to display all the files present in the
root
directory which consists of the keyword or keywords entered by the
user.
i have used a few comparison functions but i am not getting the
expected
result.
I use this script to list archive files from a directory based on
keyword. I'd guess a modified version using the keywords from users
might work:
// create archives box
if ($handle = opendir('../diaryarchives/')) {
while (false !== ($file =
readdir($handle))) {
$pos = strpos($file, diary_);
$pagemarked = diary._;
if ($pos !== false) {
//print $filebr;
$file_name = ereg_replace
($pagemarked,,$file);
$file_name = ereg_replace
(.php,,$file_name);
//print * $file_namebr;
//print $filebr;
$archive_list_gather[] = 'lia href=/diaryarchives/'.
$file.''.$file_name.'/a/li';
}
}
closedir($handle);
}
rsort($archive_list_gather);
foreach($archive_list_gather as $value) {
$archive_list .= $value;
}
// build archives box
$archives_box = 'div id=diary-archives
h3 class=sideimg src=/images/h3s_diaryarchives.gif
alt=Diary Archives width=225 height=20 //h3
ul
'.$archive_list.'
/ul
/div';
// publish archives box
$filename = PATHA.'/diaryarchivesbox.php';
publishpages($archives_box, $filename);
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[PHP] String to date
I need to convert a date retrieved from user input to a mysql date. Here the problem, I need to convert one of three possible combinations, either 01/01/2008,01-01-2008 or 01.01.2008. I can't use explode because it's limited to one character to explode on. I would prefer not to use regexp, but think I am going to have to. The one part of the code that works below is using 01/01/2008 format. Any suggestions echo $olddate = '06/06/2008'; echo br /; echo $olddate2 = '06-16-2008'; echo br /; echo $olddate3 = '06.26.2008'; echo br /; echo $newdate = date(Y-m-d,strtotime($olddate)); echo br /; echo $newdate2 = date(Y-m-d,strtotime($olddate2)); echo br /; echo $newdate3 = date(Y-m-d,strtotime($olddate3)); markb -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String to date
On Mon, Jun 30, 2008 at 4:58 PM, Mark Bomgardner [EMAIL PROTECTED] wrote: I need to convert a date retrieved from user input to a mysql date. Here the problem, I need to convert one of three possible combinations, either 01/01/2008,01-01-2008 or 01.01.2008. I can't use explode because it's limited to one character to explode on. I would prefer not to use regexp, but think I am going to have to. The one part of the code that works below is using 01/01/2008 format. Any suggestions echo $olddate = '06/06/2008'; echo br /; echo $olddate2 = '06-16-2008'; echo br /; echo $olddate3 = '06.26.2008'; echo br /; echo $newdate = date(Y-m-d,strtotime($olddate)); echo br /; echo $newdate2 = date(Y-m-d,strtotime($olddate2)); echo br /; echo $newdate3 = date(Y-m-d,strtotime($olddate3)); markb -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Your date field should always be the same in the database. The just use the date function to format that date when displaying to the user...don't alter the date format as it may make the date field unusable for queries or throw errors when attempting to insert. -- Bastien Cat, the other other white meat
Re: [PHP] String to date
Mark Bomgardner [EMAIL PROTECTED] wrote: I need to convert a date retrieved from user input to a mysql date. Here the problem, I need to convert one of three possible combinations, either 01/01/2008,01-01-2008 or 01.01.2008. I can't use explode because it's limited to one character to explode on. I would prefer not to use regexp, but think I am going to have to. The one part of the code that works below is using 01/01/2008 format. Any suggestions echo $olddate = '06/06/2008'; echo br /; echo $olddate2 = '06-16-2008'; echo br /; echo $olddate3 = '06.26.2008'; echo br /; echo $newdate = date(Y-m-d,strtotime($olddate)); echo br /; echo $newdate2 = date(Y-m-d,strtotime($olddate2)); echo br /; echo $newdate3 = date(Y-m-d,strtotime($olddate3)); markb You've given us no code you are actually using (we can all write dummy test code). IMO, you need to either change your input form to give you the results in a certain way (split up the M,D,Y or only accept it in a specific format or any other way) OR You run the strpos and look for / . or - or or ? and then use the data on that field. Wolf -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] String to date
-Original Message- From: Mark Bomgardner [mailto:[EMAIL PROTECTED] Sent: Monday, June 30, 2008 3:58 PM To: php-general@lists.php.net Subject: [PHP] String to date I need to convert a date retrieved from user input to a mysql date. Here the problem, I need to convert one of three possible combinations, either 01/01/2008,01-01-2008 or 01.01.2008. I can't use explode because it's limited to one character to explode on. I would prefer not to use regexp, but think I am going to have to. The one part of the code that works below is using 01/01/2008 format. Any suggestions echo $olddate = '06/06/2008'; echo br /; echo $olddate2 = '06-16-2008'; echo br /; echo $olddate3 = '06.26.2008'; echo br /; echo $newdate = date(Y-m-d,strtotime($olddate)); echo br /; echo $newdate2 = date(Y-m-d,strtotime($olddate2)); echo br /; echo $newdate3 = date(Y-m-d,strtotime($olddate3)); Step 1.) Replace all - with /. Step 2.) Replace all . with /. Step 3.) Err.. wait.. you're done. Todd Boyd Web Programmer -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String to date
couldn't strtotime() do this without any mods? I personally would try that first... On 6/30/08, Mark Bomgardner [EMAIL PROTECTED] wrote: I need to convert a date retrieved from user input to a mysql date. Here the problem, I need to convert one of three possible combinations, either 01/01/2008,01-01-2008 or 01.01.2008. I can't use explode because it's limited to one character to explode on. I would prefer not to use regexp, but think I am going to have to. The one part of the code that works below is using 01/01/2008 format. Any suggestions echo $olddate = '06/06/2008'; echo br /; echo $olddate2 = '06-16-2008'; echo br /; echo $olddate3 = '06.26.2008'; echo br /; echo $newdate = date(Y-m-d,strtotime($olddate)); echo br /; echo $newdate2 = date(Y-m-d,strtotime($olddate2)); echo br /; echo $newdate3 = date(Y-m-d,strtotime($olddate3)); markb -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] String searching
I need to find the position of the first character in the string (searching from the end) that is not one of the characters in a set. In this case the set is [0-9a-zA-z-_] I guess to be even more specific, I want to split a string into to parts the first part can contain anything and the second part must be only in the set described above. What is the easiest way to do this? -- Chris W KE5GIX Protect your digital freedom and privacy, eliminate DRM, learn more at http://www.defectivebydesign.org/what_is_drm; Ham Radio Repeater Database. http://hrrdb.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] String searching
On Sat, May 17, 2008 at 2:17 AM, Chris W [EMAIL PROTECTED] wrote:
I need to find the position of the first character in the string
(searching from the end) that is not one of the characters in a set. In
this case the set is [0-9a-zA-z-_]
To find the position of a specific character, RTFM on strpos().
For those not existing in your condition, I'd recommend
everythingbut(), but it's yet to be included in the core. ;-P
I guess to be even more specific, I want to split a string into to parts
the first part can contain anything and the second part must be only in
the set described above.
You can split a string by doing something as simple as this:
?php
$str = abcdefghijklmnopqrstuvwxyz;
$d = $str[5]; // $d == position - 1, because count always begins with 0
?
So to walk backward through the string, while it's not very clean,
you could do:
?php
$str = ABCDEF01234567789;
for($i=strlen($str);$i0;$i--) {
if(preg_match('/[g-z]/i',$str[$i])) {
// Handle your this is a bad character condition(s).
// break; /* Or, optionally, continue. */
}
}
?
Not pretty, but if my mind is still working at 2:30a (EDT), it
should help you out.
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Re: [PHP] String searching
Chris W wrote: I need to find the position of the first character in the string (searching from the end) that is not one of the characters in a set. In this case the set is [0-9a-zA-z-_] I guess to be even more specific, I want to split a string into to parts the first part can contain anything and the second part must be only in the set described above. What is the easiest way to do this? There's something here, imaginatively called blah(), which does what you require: http://www.phpguru.org/preg/example.phps -- Richard Heyes ++ | Access SSH with a Windows mapped drive | |http://www.phpguru.org/sftpdrive| ++ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string
John Taylor-Johnston wrote: $name = John Taylor; I want to verify if $name contains john, if yes echo found; Cannot remember which to use: http://ca.php.net/manual/en/ref.strings.php Either http://php.net/strpos or http://php.net/stripos if your version of PHP supports it. -Stut -- http://stut.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] string
$name = John Taylor; I want to verify if $name contains john, if yes echo found; Cannot remember which to use: http://ca.php.net/manual/en/ref.strings.php Sorry, John -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RES: [PHP] string
?php
$name = John Taylor;
if (strpos($name,'John') 0){
//you could use stripos for case insensitive search
echo found;
}
?
-Mensagem original-
De: John Taylor-Johnston [mailto:[EMAIL PROTECTED]
Enviada em: segunda-feira, 7 de abril de 2008 10:25
Para: PHP-General
Assunto: [PHP] string
$name = John Taylor;
I want to verify if $name contains john, if yes echo found;
Cannot remember which to use:
http://ca.php.net/manual/en/ref.strings.php
Sorry,
John
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RE: [PHP] string
Do a preg match to find one or preg_match_all to find all the john in the string. ?php $name = John Taylor; $pattern = '/^John/'; preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE, 3); print_r($matches); ? $name = John Taylor; I want to verify if $name contains john, if yes echo found; Cannot remember which to use: http://ca.php.net/manual/en/ref.strings.php Sorry, John -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: RES: [PHP] string
Thiago Pojda wrote:
?php
$name = John Taylor;
if (strpos($name,'John') 0){
//you could use stripos for case insensitive search
echo found;
}
?
This will not do what you expect it to. Since 'John' is the first thing
in the string strpos will return 0 causing the condition to evaluate to
false.
As per the documentation for strpos you should compare the value *and
type* of the variable returned by strpos against false to check for
non-existance.
if (strpos($name, 'John') !== false) { ... }
-Stut
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-Mensagem original-
De: John Taylor-Johnston [mailto:[EMAIL PROTECTED]
Enviada em: segunda-feira, 7 de abril de 2008 10:25
Para: PHP-General
Assunto: [PHP] string
$name = John Taylor;
I want to verify if $name contains john, if yes echo found;
Cannot remember which to use:
http://ca.php.net/manual/en/ref.strings.php
Sorry,
John
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RES: RES: [PHP] string
Never late to learn new stuff, you're right Stut.
Thanks!
-Mensagem original-
De: Stut [mailto:[EMAIL PROTECTED]
Enviada em: segunda-feira, 7 de abril de 2008 10:42
Para: Thiago Pojda
Cc: 'John Taylor-Johnston'; 'PHP-General'
Assunto: Re: RES: [PHP] string
Thiago Pojda wrote:
?php
$name = John Taylor;
if (strpos($name,'John') 0){
//you could use stripos for case insensitive search
echo found;
}
?
This will not do what you expect it to. Since 'John' is the
first thing in the string strpos will return 0 causing the
condition to evaluate to false.
As per the documentation for strpos you should compare the value *and
type* of the variable returned by strpos against false to check
for non-existance.
if (strpos($name, 'John') !== false) { ... }
-Stut
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-Mensagem original-
De: John Taylor-Johnston [mailto:[EMAIL PROTECTED]
Enviada em: segunda-feira, 7 de abril de 2008 10:25
Para: PHP-General
Assunto: [PHP] string
$name = John Taylor;
I want to verify if $name contains john, if yes echo found; Cannot
remember which to use:
http://ca.php.net/manual/en/ref.strings.php
Sorry,
John
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