Re: [PHP] return
On Monday, April 1, 2002, at 02:13 PM, Jordan K. Martin wrote:
Makes sense. I didn't think much when writing that piece...but...what
is
the for? wouldn't it work the same without it?
function test ($var)
{
$var = addslashes($var)
}
$foo = He's dreaming;
test($foo);
print($foo);
No, this won't work because you're not returning a value. You need to
either have a return statement in this function that says return $var;
or you need to use the sign, which lets you change the value of a
variable outside the namespace of the function. Or scope. I forget
which it is.
Try your above code -- it shouldn't work.
Erik
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
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Re: [PHP] return
Nope, that code makes no sense. $_POST is an array containing the POST
variables. You make a copy of that array an put it in $foo thereby
overwriting the passed in $foo. Then you return $$foo which actually ends
up returning a variable named $Array. It does not look like you have a
$Array variable in scope, and it is surely not what the misguided coder
behind this code was trying to achieve. In short, this is completely
bogus.
-Rasmus
On Sun, 31 Mar 2002, Gary wrote:
Can someone explain to me the reason for using return.
function _getValue($foo)
{
$foo = $_POST;
return ${$foo};
}
TIA
Gary
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Re: [PHP] return
But to answer your question
The purpose of return, is to return a value..
function test($var)
{
return addslashes($var);
}
$foo = Yes, I'am Very Awsome;
$foo = test($foo);
echo($foo);
// echo's, Yes I\'am Very Awsome
Understand?
- Original Message -
From: Rasmus Lerdorf [EMAIL PROTECTED]
To: Gary [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Sunday, March 31, 2002 11:43 PM
Subject: Re: [PHP] return
Nope, that code makes no sense. $_POST is an array containing the POST
variables. You make a copy of that array an put it in $foo thereby
overwriting the passed in $foo. Then you return $$foo which actually ends
up returning a variable named $Array. It does not look like you have a
$Array variable in scope, and it is surely not what the misguided coder
behind this code was trying to achieve. In short, this is completely
bogus.
-Rasmus
On Sun, 31 Mar 2002, Gary wrote:
Can someone explain to me the reason for using return.
function _getValue($foo)
{
$foo = $_POST;
return ${$foo};
}
TIA
Gary
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Re: [PHP] return
Eric,
Isnt there really no need for the 'return' though?
$test ($var)
{
addslashes($var)
}
$foo = He's dreaming;
$foo = test($foo);
print($foo);
//should also print He\'s dreaming
Am I incorrect in thinking this?
-Jordan K. Martin
http://www.newimagedesign.com
Eric Coleman [EMAIL PROTECTED] wrote in message
018e01c1d93d$cd404be0$0201a8c0@zaireweb">news:018e01c1d93d$cd404be0$0201a8c0@zaireweb...
But to answer your question
The purpose of return, is to return a value..
function test($var)
{
return addslashes($var);
}
$foo = Yes, I'am Very Awsome;
$foo = test($foo);
echo($foo);
// echo's, Yes I\'am Very Awsome
Understand?
- Original Message -
From: Rasmus Lerdorf [EMAIL PROTECTED]
To: Gary [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Sunday, March 31, 2002 11:43 PM
Subject: Re: [PHP] return
Nope, that code makes no sense. $_POST is an array containing the POST
variables. You make a copy of that array an put it in $foo thereby
overwriting the passed in $foo. Then you return $$foo which actually
ends
up returning a variable named $Array. It does not look like you have a
$Array variable in scope, and it is surely not what the misguided coder
behind this code was trying to achieve. In short, this is completely
bogus.
-Rasmus
On Sun, 31 Mar 2002, Gary wrote:
Can someone explain to me the reason for using return.
function _getValue($foo)
{
$foo = $_POST;
return ${$foo};
}
TIA
Gary
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Re: [PHP] return
Well, you could do it without a return, but first, addslashes() returns
the modified string, it does not do in-place replacement. And second, you
would need to pass the string in by reference, like this:
function test ( $var)
{
$var = addslashes($var)
}
$foo = He's dreaming;
test($foo);
print($foo);
-Rasmus
On Mon, 1 Apr 2002, Jordan wrote:
Eric,
Isnt there really no need for the 'return' though?
$test ($var)
{
addslashes($var)
}
$foo = He's dreaming;
$foo = test($foo);
print($foo);
//should also print He\'s dreaming
Am I incorrect in thinking this?
-Jordan K. Martin
http://www.newimagedesign.com
Eric Coleman [EMAIL PROTECTED] wrote in message
018e01c1d93d$cd404be0$0201a8c0@zaireweb">news:018e01c1d93d$cd404be0$0201a8c0@zaireweb...
But to answer your question
The purpose of return, is to return a value..
function test($var)
{
return addslashes($var);
}
$foo = Yes, I'am Very Awsome;
$foo = test($foo);
echo($foo);
// echo's, Yes I\'am Very Awsome
Understand?
- Original Message -
From: Rasmus Lerdorf [EMAIL PROTECTED]
To: Gary [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Sunday, March 31, 2002 11:43 PM
Subject: Re: [PHP] return
Nope, that code makes no sense. $_POST is an array containing the POST
variables. You make a copy of that array an put it in $foo thereby
overwriting the passed in $foo. Then you return $$foo which actually
ends
up returning a variable named $Array. It does not look like you have a
$Array variable in scope, and it is surely not what the misguided coder
behind this code was trying to achieve. In short, this is completely
bogus.
-Rasmus
On Sun, 31 Mar 2002, Gary wrote:
Can someone explain to me the reason for using return.
function _getValue($foo)
{
$foo = $_POST;
return ${$foo};
}
TIA
Gary
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Re: [PHP] return
On Mon, 1 Apr 2002, Jordan wrote:
Isnt there really no need for the 'return' though?
Try this program and see what happens:
?
function triple1($x) { $x = $x * 3; return $x; }
function triple2($x) { $x = $x * 3; }
function triple3($x) { global $x; $x = $x * 3; }
$x = 5; $x = triple1($x) print 'ptriple1: ' . $x;
$x = 5; print 'ptriple1 return: ' . triple1($x);
$x = 5; $x = triple2($x) print 'ptriple2: ' . $x;
$x = 5; print 'ptriple2 return: ' . triple2($x);
$x = 5; $x = triple3($x) print 'ptriple3: ' . $x;
$x = 5; print 'ptriple3 return: ' . triple3($x);
?
miguel
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Re: [PHP] return
On Sun, 31 Mar 2002, Miguel Cruz wrote:
On Mon, 1 Apr 2002, Jordan wrote:
Isnt there really no need for the 'return' though?
Try this program and see what happens:
Ah, Rasmus brings up a good point. Try this one instead.
?
function triple1($x) { $x = $x * 3; return $x; }
function triple2($x) { $x = $x * 3; }
function triple3($x) { global $x; $x = $x * 3; }
function triple4($x) { $x = $x * 3; }
$x = 5; $x = triple1($x) print 'ptriple1: ' . $x;
$x = 5; print 'ptriple1 return: ' . triple1($x);
$x = 5; $x = triple2($x) print 'ptriple2: ' . $x;
$x = 5; print 'ptriple2 return: ' . triple2($x);
$x = 5; $x = triple3($x) print 'ptriple3: ' . $x;
$x = 5; print 'ptriple3 return: ' . triple3($x);
$x = 5; $x = triple4($x) print 'ptriple4: ' . $x;
$x = 5; print 'ptriple4 return: ' . triple4($x);
?
miguel
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Re: [PHP] return
Gary,
To add to the conversation ...
You created a function to pass something through it, to process something and
now you want to get something back, right? That's what return does. It gets
something back for your effort.
You could simply:
echo addslashes($var);
But let's say you do it a hundred times in the course of a script. You don't
want to take up a hundred lines of code doing:
echo addslashes($var);
... so you create a function like Eric has below, which takes up 3 or 4 lines of
code, but has the capacity to repeat the same line of code 100 times.
John
The purpose of return, is to return a value..
function test($var)
{
return addslashes($var);
}
$foo = Yes, I'am Very Awsome;
$foo = test($foo);
echo($foo);
// echo's, Yes I\'am Very Awsome
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Re: [PHP] Return the column names of MySQL table?
I believe it is: describe tablename; - Original Message - From: Kevin Stone [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, March 19, 2002 4:43 PM Subject: [PHP] Return the column names of MySQL table? Forgive me for the off topic question. This is a MySQL question.. has nothing to do with PHP directly. However I was not able to find an answer in the MySQL documentation, on Usenet, or the MySQL mailing list archives. Also MySQL.com's mail manager is on the fritz so I can't even subscribe to the MySQL email list. Anyway since many of you are familiar with SQL this is as good a place to ask this question as any. I simply need to return a list of column names of a MySQL table. What's the syntax to do that? Thanks, Kevin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Return the column names of MySQL table?
On Tuesday, March 19, 2002, at 05:43 PM, Kevin Stone wrote: I simply need to return a list of column names of a MySQL table. What's the syntax to do that? SHOW COLUMNS FROM tablename; Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Return the column names of MySQL table?
Hi,
Try the following,
?
mysql_connect(DBServer,DBUser,DBPassword);
$queryColumn = mysql(DBName,desc tableName);
$columnCount = //Find out the number of column in the table.
$index=0;
while($index $columnCount)
{
$columnName = mysql_result($queryColumn,$index,Field);
echo pColumn name ($index) : $columnName/p;
$index++;
}
?
On Tue, 19 Mar 2002, Kevin Stone wrote:
Forgive me for the off topic question. This is a MySQL question.. has
nothing to do with PHP directly. However I was not able to find an
answer in the MySQL documentation, on Usenet, or the MySQL mailing list
archives. Also MySQL.com's mail manager is on the fritz so I can't
even subscribe to the MySQL email list. Anyway since many of you are
familiar with SQL this is as good a place to ask this question as any.
I simply need to return a list of column names of a MySQL table. What's
the syntax to do that?
Thanks,
Kevin
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kishor
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Re: [PHP] Return values from shell_exec command into db
On Wednesday 06 March 2002 18:23, Sven Jacobs wrote: Hey I want to run a shell script, all the values that are returned normal by that script I want to put as var. For example tracert X.X.X.X 1 10 ms 10 ms 10 ms blablabla.bla.com [X.X.X.X] 2 10 ms10 ms10 ms RFC1918-Host [X.X.X.X] 3 10 ms10 ms10 ms BUOPS [X.X.X.X] The 3 values I want tot put in a table when I run the script $output = `tracert x.x.x.x`; $output now contains the results of whatever command you executed. It's all nicely explained in the manual, Program Execution functions. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* strategy, n.: A comprehensive plan of inaction. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Return Adress
Hey, there... I ran into this yesterday along with learning a heap more PHP. Adding a Reply-To: [EMAIL PROTECTED] header seemed to work fine. Hope this helps, Bill -Original Message- From: Jean-Arthur Silve [mailto:[EMAIL PROTECTED]] Sent: Thursday, August 09, 2001 5:23 AM To: [EMAIL PROTECTED] Subject: [PHP] Return Adress Hi ! I ve got a problem with the mail function : My http server (Apache) is running as user web and php is compiled as a module. When I send a mail with the mail function and, for example, the recipient does not exists, the return message is sent to [EMAIL PROTECTED] I would like the error messages are sent to another email adress. I tried with the mail header Return-path: [EMAIL PROTECTED] but the error messages keep going to [EMAIL PROTECTED] My code is : $head=From: .$EMAILADMIN.\nReturn-Path: [EMAIL PROTECTED]\n; mail($to,$sub,$msg,$head); Is there a way to force the error messages to go to another email adress ? Another header ? If it's sendmail that change the return address, is there a way to prevent this ? Thanks ! jean-arthur --- EuroVox 4, place Félix Eboue 75583 Paris Cedex 12 Tel : 01 44 67 05 05 Fax : 01 44 67 05 19 Web : http://www.eurovox.fr -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Return Adress
You also should use \r\n instead of just \n to be really spec. Double-check RFC spelling of Reply-To: or Reply-to: Capitalization matters for email headers. -- WARNING [EMAIL PROTECTED] address is an endangered species -- Use [EMAIL PROTECTED] Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm Volunteer a little time: http://chatmusic.com/volunteer.htm - Original Message - From: [EMAIL PROTECTED] Newsgroups: php.general To: [EMAIL PROTECTED] Sent: Thursday, August 09, 2001 11:27 AM Subject: RE: [PHP] Return Adress Hey, there... I ran into this yesterday along with learning a heap more PHP. Adding a Reply-To: [EMAIL PROTECTED] header seemed to work fine. Hope this helps, Bill -Original Message- From: Jean-Arthur Silve [mailto:[EMAIL PROTECTED]] Sent: Thursday, August 09, 2001 5:23 AM To: [EMAIL PROTECTED] Subject: [PHP] Return Adress Hi ! I ve got a problem with the mail function : My http server (Apache) is running as user web and php is compiled as a module. When I send a mail with the mail function and, for example, the recipient does not exists, the return message is sent to [EMAIL PROTECTED] I would like the error messages are sent to another email adress. I tried with the mail header Return-path: [EMAIL PROTECTED] but the error messages keep going to [EMAIL PROTECTED] My code is : $head=From: .$EMAILADMIN.\nReturn-Path: [EMAIL PROTECTED]\n; mail($to,$sub,$msg,$head); Is there a way to force the error messages to go to another email adress ? Another header ? If it's sendmail that change the return address, is there a way to prevent this ? Thanks ! jean-arthur --- EuroVox 4, place Félix Eboue 75583 Paris Cedex 12 Tel : 01 44 67 05 05 Fax : 01 44 67 05 19 Web : http://www.eurovox.fr -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] return value from recursive function
maybe it is just me and my preferred syntax/style...
if ($i 4) {
abc_recurse();
}
return 'xyz'; # NOTICE REMOVED ()'s
Did not look to closely at your shortcut symantics to verify legitimacy
Also, unless I am mistaken, people generally advise against having a function do
output. A more appropriate syntax might be
?
function abc_recurse($r) {
global $r;
static $i = 1;
$r.=$i;
$i++;
if ($i 4) {
abc_recurse($r);
}
return $r.'xyz';
}
$returnvalue = abc_recurse(0);
echo $returnvalue;
?
messy but a quick example.
-Original Message-
From: Jaskirat [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 29, 2001 8:47 PM
To: [EMAIL PROTECTED]
Subject: [PHP] return value from recursive function
Hi,
How to get return value from a recursive function .. here is the test code
which I was trying
?
function abc_recurse()
{
static $i = 1;
echo $i;
$i++;
if ($i == 4) return (xyz);
abc_recurse();
}
$returnvalue = abc_recurse();
echo $returnvalue;
?
Its printing 123 where as I was expecting 123xyz
what is happening to $returnvalue
TIA
Jaski
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RE: [PHP] return
Here's my code:
?
function expDate($date) {
$month = substr($date, 0, 2);
$len = strlen($date);
$year = substr($date, $len-2, $len);
return $month;
return $year;
}
expDate(11/2002);
print $month $year;
?
I know this isn't the correct usage of return, but how to I
get the $month and $year variables so I can print them
after I've called the expDate() function? Currently, nothing
is printed to the browser.
You cannot use return twice like that. The function will
exit immediately after the first valid return call it hits.
To do what you want, you can do this:
function expDate($date, $returnMonth, $returnYear ) {
$month = substr($date, 0, 2);
$len = strlen($date);
$year = substr($date, $len-2, $len);
$returnMonth = $month;
$returnYear = $year;
}
$month = 0;
$year = 0;
expDate( 11/2002, $month, $year );
print $month $year;
--
The operator passes a variable by reference.
Alternately, you can do:
function expDate($date, $returnMonth, $returnYear ) {
global $month;
global $year;
$month = substr($date, 0, 2);
$len = strlen($date);
$year = substr($date, $len-2, $len);
}
$month = 0;
$year = 0;
expDate( 11/2002 );
print $month $year;
--
Though, I try to use global as little as possible.
Chris
RE: [PHP] return
On 16-Jul-01 Tyler Longren wrote:
Here's my code:
?
function expDate($date) {
$month = substr($date, 0, 2);
$len = strlen($date);
$year = substr($date, $len-2, $len);
return $month;
return $year;
}
expDate(11/2002);
print $month $year;
?
I know this isn't the correct usage of return, but how to I get the $month
and $year variables so I can print them after I've called the expDate()
function? Currently, nothing is printed to the browser.
return array($month, $year);
-- or --
function expDate($date,$month,$year) {
...
}
expDate(11/2002,$month,$year);
print ...
-- or --
list($month, $year)=explode(/, 11/2002);
Regards,
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steal the neighbor's newspaper, that's the time to do it.
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Re: [PHP] return
So sprach »Tyler Longren« am 2001-07-16 um 15:25:08 -0500 :
function? Currently, nothing is printed to the browser.
No wonder, because you don't assign the returned value of expDate to
anything..
well, if you want to return two values, I'd suggest to use an array,
like so:
function expDate($date){
$month = 08; // whatever
$year = 15; // whatever
$return_value = array(
month = $month,
year = $year
);
return $return_value;
}
$date = expDate(4711);
print $date[month] . . $date[year];
Alexander Skwar
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Re: [PHP] return
So sprach »Alexander 'Digital Projects' Skwar« am 2001-07-16 um 22:38:44 +0200 : anything.. correction: Whoops - there's a . missing anything... Alexander Skwar -- How to quote: http://learn.to/quote (german) http://quote.6x.to (english) Homepage: http://www.digitalprojects.com | http://www.iso-top.de iso-top.de - Die günstige Art an Linux Distributionen zu kommen Uptime: 5 hours 31 minutes -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] return parse error
At 03:56 AM 4/13/2001, Peter Harkins wrote:
This generates a parse error:
mysql_connect("localhost", "root", "rootpw") or
return("bar");
But all the following work fine:
mysql_connect("localhost", "root", "rootpw") or die("bar");
mysql_connect("localhost", "root", "rootpw") or
print("bar");
if (!mysql_connect("localhost", "root", "rootpw")) {
return("bar");
}
Why? mysql_connect returns false on failure either way... I
notice die
return isn't a function but a language construct. This is why the third
working line with the curlybraces works, and without them it doesn't.
include() is a language construct too. the particulars of using language
constructs (like return() and include()) with control structure syntax are
explained on the page for include().
http://us2.php.net/manual/en/function.include.php
-j (aka sneak)
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Re: [PHP] return parse error
Small additional info about "expression" and "language construct".
Expression is anything that have value.
Therefore, if language construct returns value = valid expression.
Following code works:
($val) ? include('abc.php') : include('def.php');
Following code does NOT work:
($val) ? echo('abc') : echo('def');
both "include" and "echo" is language construct, but "include" returns value.
Thus "include" is valid expression while "echo" is not.
"return" does not return value. (It returns value to caller, but not return
value for expression context)
User defined functions always return value, even if there is no "return"
statement = functions are always valid expression.
Hope this helps.
--
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"Jeffrey Paul" [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
At 03:56 AM 4/13/2001, Peter Harkins wrote:
This generates a parse error:
mysql_connect("localhost", "root", "rootpw") or
return("bar");
But all the following work fine:
mysql_connect("localhost", "root", "rootpw") or die("bar");
mysql_connect("localhost", "root", "rootpw") or
print("bar");
if (!mysql_connect("localhost", "root", "rootpw")) {
return("bar");
}
Why? mysql_connect returns false on failure either way... I
notice die
return isn't a function but a language construct. This is why the third
working line with the curlybraces works, and without them it doesn't.
include() is a language construct too. the particulars of using language
constructs (like return() and include()) with control structure syntax are
explained on the page for include().
http://us2.php.net/manual/en/function.include.php
-j (aka sneak)
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he who lives these words shall not taste death
becoming nothing yeah yeah
forever liquid cool
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Re: [PHP] Return Image for PHP Link
I'm not 100% sure this works, but maybe try something like this: img src="? include 'myphpcode.php'; ?>"> If that doesn't work, you can always have the php generate the entire tag ? $image = "myimagefile.gif"; // What ever you need print "img src=\"$image\">"; ?> Hope this helps :-) "Karl J. Stubsjoen" wrote: Hello, I'd like the source of an image tag to point to PHP code. I'd like that PHP code to generate an image (accordingly) and print/output the results back to the calling image. So: img src="myphpcode.php"> Where, myphpcode.php returns a valid image. I've done this before, but it is not fresh in my brain. Any help would be appreciated! Karl -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- 209 Media http://www.209media.com> Ron Wills [EMAIL PROTECTED]> Programmer -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Return ODBC Results to an array
You can use mysql_fetch_array() for each row returned in the cursor. Sorin Ifrim - Original Message - From: Karl J. Stubsjoen [EMAIL PROTECTED] To: PHP Mailing List [EMAIL PROTECTED] Sent: Tuesday, February 13, 2001 7:32 PM Subject: [PHP] Return ODBC Results to an array Is there a way to return the results of a query straight into an array? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Return ODBC Results to an array
For ODBC, the function is odbc_fetch_into(). Sorin Ifrim - Original Message - From: Karl J. Stubsjoen [EMAIL PROTECTED] To: PHP Mailing List [EMAIL PROTECTED] Sent: Tuesday, February 13, 2001 7:32 PM Subject: [PHP] Return ODBC Results to an array Is there a way to return the results of a query straight into an array? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Return ODBC Results to an array
Karl, http://www.php.net/manual/en/function.odbc-fetch-into.php Best regards, Andrew -- Andrew Hill - OpenLink Software Director Technology Evangelism eBusiness Infrastructure Technology http://www.openlinksw.com -Original Message- From: Karl J. Stubsjoen [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 13, 2001 12:33 PM To: PHP Mailing List Subject: [PHP] Return ODBC Results to an array Is there a way to return the results of a query straight into an array? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
