Re: [R] Building static HTML help pages in R 2.10.x on Windows
Instead of an answer, may I add question c) can someone state that it is impossible to generate static HTML help pages under Windows? At 21:40 22.12.2009, Steve Rowley wrote: I upgraded to R2.10.1pat and discovered, along with everybody else, that static HTML pages are no longer the default. Fine; my tastes would go the other way, but I'm happy to adapt. However, I'd still like to build static HTML pages (for stable bookmarking, use when R is not running, etc.). I'm using the Windows installer, so the advice in the R Installation Admin guide (section 2.2, Help options) to use the configure option --enable-prebuilt-html doesn't seem to apply. I'm using install.packages() rather than R CMD INSTALL, so I don't quite understand how the --html arg to R CMD INSTALL can apply either. So, can anybody point me to an example of either: (a) how to build the static HTML help pages of all currently installed packages under Windows, or, failing that (b) how to do this on Windows ab initio, from a clean install? Thanks! -- Steve Rowley s...@alum.mit.edu http://alum.mit.edu/www/sgr/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] svm regression/classification
Hi everyone,
Can anyone please tell whether there is a difference between the code for using
svm in regression and code for using svm in classification?
This is my code for regression, should I change it to do classification?:
train - read.table(trainingset.txt,sep=;)
test - read.table(testset.txt,sep=;)
svmmodelfitness - function(myformula,mydata,mytestdata)
{
mymodel - svm(myformula,data=mydata)
mytest - predict(mymodel, mytestdata)
error - mytest - mytestdata[,1]
-sqrt(mean(error**2))
}
Many thanks,
Nancy
_
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[R] how to create a simple loop ?
I have a 5-row matrix called âdataâ. There are headers. it look like this : Row 1 Row2Row3Row4Row5 Line1 â¦â¦â¦â¦ Line2 â¦â¦â¦â¦ Line3 â¦â¦â¦â¦ ⦠Line 1838 â¦â¦â¦â¦ I want to calculate several simple arithmetic means for Row5, that is from Line173 to Line193, from Line434 to Line455, from Line699 to Line724, from Line955 to Line977 A simple way is to individually compute these means. The first one (Line173 to Line193) is then obtained by : mean(data[173:193,5], na.rm = TRUE) Thatâs right ! But, I aim to automate this calculation by creating a loop. I tried many things, but I have been unsuccessful at using the âforâ loop function. Please, donât explain things too hard as it is often the case that people wants to help but gets into too much sophistication. Someone can write that little code for this example ? Or suggest functions ? Thanks for your help. Cheers, Ãdouard. [[alternative(swapped) HTML version deleted]] This is MIME Epilogue __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] how to create a simple loop ?
Hi everyone. And, Merry Xmas ! I have a 5-row matrix called âdataâ. There are headers. it look like this : Row 1 Row2Row3Row4Row5 Line1 â¦â¦â¦â¦ Line2 â¦â¦â¦â¦ Line3 â¦â¦â¦â¦ ⦠Line 1838 â¦â¦â¦â¦ I want to calculate several simple arithmetic means for Row5, that is from Line173 to Line193, from Line434 to Line455, from Line699 to Line724, from Line955 to Line977 A simple way is to individually compute these means. The first one (Line173 to Line193) is then obtained by : mean(data[173:193,5], na.rm = TRUE) Thatâs right ! But, I aim to automate this calculation by creating a loop. I tried many things, but I have been unsuccessful at using the âforâ loop function. Please, donât explain things too hard as it is often the case that people wants to help but gets into too much sophistication. Someone can write that little code for this example ? Or suggest functions ? Thanks for your help. Cheers, Ãdouard. [[alternative(swapped) HTML version deleted]] This is MIME Epilogue __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to create a simple loop ?
On Dec 27, 2009, at 9:15 AM, Edouard Tallent wrote: Hi everyone. And, Merry Xmas ! I have a 5-row matrix called “data”. There are headers. it look like this : Row 1 Row2Row3Row4Row5 Line1 ………… Line2 ………… Line3 ………… … Line 1838 ………… I want to calculate several simple arithmetic means for Row5, that is from Line173 to Line193, from Line434 to Line455, from Line699 to Line724, from Line955 to Line977 A simple way is to individually compute these means. The first one (Line173 to Line193) is then obtained by : mean(data[173:193,5], na.rm = TRUE) That’s right ! But, I aim to automate this calculation by creating a loop. I tried many things, but I have been unsuccessful at using the ‘for’ loop function. Generally it would be better to include the failed efforts in the form of executable R code that would let the readership see, for instance, the list (or vector, or matrix) of intervals that you were trying to use in the for loops. Please, don’t explain things too hard as it is often the case that people wants to help but gets into too much sophistication. Someone can write that little code for this example ? ? No executable example offered. Or suggest functions ? A for loop would seem sensible. The sapply function might be used, or perhaps the apply function. It really depends on the details of how the intervals are represented (which you have not provided.) and provide commented, minimal, self-contained, reproducible code. ^^^ David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Identifying outliers in non-normally distributed data
Hello, I've been searching for a method for identify outliers for quite some time now. The complication is that I cannot assume that my data is normally distributed nor symmetrical (i.e. some distributions might have one longer tail) so I have not been able to find any good tests. The Walsh's Test (http://www.statistics4u.info/ fundsta...liertest.html#), as I understand assumes that the data is symmetrical for example. Also, while I've found some interesting articles: http://tinyurl.com/yc7w4oq (Missing Values, Outliers, Robust Statistics Non-parametric Methods) I don't really know what to use. Any ideas? Any R packages available for this? Thanks! PS. My data has 1000's of observations.. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Identifying outliers in non-normally distributed data
John wrote: Hello, I've been searching for a method for identify outliers for quite some time now. The complication is that I cannot assume that my data is normally distributed nor symmetrical (i.e. some distributions might have one longer tail) so I have not been able to find any good tests. The Walsh's Test (http://www.statistics4u.info/ fundsta...liertest.html#), as I understand assumes that the data is symmetrical for example. Also, while I've found some interesting articles: http://tinyurl.com/yc7w4oq (Missing Values, Outliers, Robust Statistics Non-parametric Methods) I don't really know what to use. Any ideas? Any R packages available for this? Thanks! PS. My data has 1000's of observations.. Take a look at package 'robustbase', it provides most of the standard robust measures and calculations. While you didn't say what kind of data you're trying to identify outliers in, if it is time series data the function Return.clean in PerformanceAnalytics may be useful. Regards, - Brian -- Brian G. Peterson http://braverock.com/brian/ Ph: 773-459-4973 IM: bgpbraverock __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] RGtk2 / gWidgets - addHandlerClicked Problem
In The following code, the table handler is executed twice when the
button is pressed (from the 2nd pressing on).
I want it to be executed only once. Does someone know, why this
happens and how I can change it?
library(gWidgets)
w - gwindow()
b - gbutton(press, cont=w)
tbl - gtable(1:10, cont=w)
addhandlerclicked(b, handler=function(h, ...){
cat(addhandlerclicked button\n)
svalue(tbl, index=T) - 1# change the table
value
})
addhandlerclicked(tbl, handler=function(h, ...){
cat(addhandlerclicked table\n)
})
Thanks!
Mark
–––
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Vorstraße 93 B01
28359 Bremen
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Make the output (from a Loop function) a Vector
On Dec 27, 2009, at 11:17 AM, Cat Morning wrote: Hi all, I have made a loop function which prints outputs. For example: for (i in 1:5) + print(i) [1] 1 [1] 2 [1] 3 [1] 4 [1] 5 However, I would like the output to given as a list or a vector, e..g c(1,2,3,4,5). Is it possible to do this? This does suggest that you need to do some more studying of whatever text you are using to learn R: v - c() for (i in 1:5) v - c(v,i) v [1] 1 2 3 4 5 Or if you wanted to see the results with each iteration: v - c() for (i in 1:5) print(v - c(v,i)) [1] 1 [1] 1 2 [1] 1 2 3 [1] 1 2 3 4 [1] 1 2 3 4 5 (The function I am using outputs many 1000s of results, so is not easy to change to a vector manually.) So you probably would not want the print() version. Many Thanks. [[alternative HTML version deleted]] Set your mail-client up to send plain-text. David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] RGtk2 / gWidgets - addHandlerClicked Problem
On Dec 27, 2009, at 11:29 AM, Mark Heckmann wrote:
In The following code, the table handler is executed twice when the
button is pressed (from the 2nd pressing on).
Can't reproduce. On a Mac 10.5.8, R 2.10.1, running the 64 bit GUI,
after choosing the gWidgetstcltk option for GUI toolkit when gwindow()
is first executed, I do not get a behavior that suggests that the
table handler gets executed twice with each button click. I get an X11
window with a button across the width of the top of the window. Each
time the button is clicked I get :
addhandlerclicked button
addhandlerclicked table
Just for fun I modified your tbl handler and got sensible incrementing
highlighting of the rows with:
addhandlerclicked(b, handler=function(h, ...){
+ cat(addhandlerclicked button\n)
+ svalue(tbl, index=T) - 1+svalue(tbl) # the earlier code did not
change values
+ })
I want it to be executed only once. Does someone know, why this
happens and how I can change it?
library(gWidgets)
w - gwindow()
b - gbutton(press, cont=w)
tbl - gtable(1:10, cont=w)
addhandlerclicked(b, handler=function(h, ...){
cat(addhandlerclicked button\n)
svalue(tbl, index=T) - 1# change the table
value
})
addhandlerclicked(tbl, handler=function(h, ...){
cat(addhandlerclicked table\n)
})
Thanks!
Mark
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Positions in datasets
Could someone help me understand this Basically I want to know the position of certain numbers in large output data sets. First consider the following simple example where we get the postions of ones (1) in the vector q. q - c(5,1,1,3,1,1,1,1) q [1] 5 1 1 3 1 1 1 1 for (i in 1:length(q)) if(q[i]==1) print(i) [1] 2 [1] 3 [1] 5 [1] 6 [1] 7 [1] 8 Well done! But now consider the following case where the input consists of different combinations of the three numbers 2, 3 and 7. They are put into a function 1/x +1/y +1/z +1/(x*y*z). All different combinations will yield the same result namely precisely 1, which is also clearly seen in the output. However when I try to get information on the position of the ones in the output, there are only two that are recognized, although all six items in the output are indeed ones. x - c(2,2,3,3,7,7); y - c(3,7,2,7,2,3); z - c(7,3,7,2,3,2) data.frame(x,y,z) x y z 1 2 3 7 2 2 7 3 3 3 2 7 4 3 7 2 5 7 2 3 6 7 3 2 p - numeric(length(x)) for (i in 1:length(x)) p[i] - ((1/x[i]) + (1/y[i]) + (1/z[i]) + (1/(x[i]*y[i]*z[i]))) p [1] 1 1 1 1 1 1 for (i in 1:length(p)) if(p[i]==1) print(i) [1] 4 [1] 6 I suppose there must exist some better way of accessing the position of certain numbers in a large data output. So apart from getting advice on that I would certainly also like to understand why the above only seems to work in some cases. Anders B Falk PhD Uppsala Sweden __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Positions in datasets
On Dec 27, 2009, at 12:11 PM, Anders Falk wrote: Could someone help me understand this Basically I want to know the position of certain numbers in large output data sets. First consider the following simple example where we get the postions of ones (1) in the vector q. q - c(5,1,1,3,1,1,1,1) q [1] 5 1 1 3 1 1 1 1 for (i in 1:length(q)) if(q[i]==1) print(i) [1] 2 [1] 3 [1] 5 [1] 6 [1] 7 [1] 8 Well done! But now consider the following case where the input consists of different combinations of the three numbers 2, 3 and 7. They are put into a function 1/x +1/y +1/z +1/(x*y*z). All different combinations will yield the same result namely precisely 1, which is also clearly seen in the output. However when I try to get information on the position of the ones in the output, there are only two that are recognized, although all six items in the output are indeed ones. x - c(2,2,3,3,7,7); y - c(3,7,2,7,2,3); z - c(7,3,7,2,3,2) data.frame(x,y,z) x y z 1 2 3 7 2 2 7 3 3 3 2 7 4 3 7 2 5 7 2 3 6 7 3 2 p - numeric(length(x)) for (i in 1:length(x)) p[i] - ((1/x[i]) + (1/y[i]) + (1/z[i]) + (1/(x[i]*y[i]*z[i]))) p [1] 1 1 1 1 1 1 for (i in 1:length(p)) if(p[i]==1) print(i) [1] 4 [1] 6 I suppose there must exist some better way of accessing the position of certain numbers in a large data output. data output is a bit vague, but if you are talking about vectors then: ?which So apart from getting advice on that I would certainly also like to understand why the above only seems to work in some cases. It's a FAQ, 7.31: http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f for (i in 1:length(p)) if(all.equal(p[i],1)) print(i) [1] 1 [1] 2 [1] 3 [1] 4 [1] 5 [1] 6 Anders B Falk PhD Uppsala Sweden __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] RGtk2 / gWidgets - addHandlerClicked Problem
On Dec 27, 2009, at 12:12 PM, Mark Heckmann wrote:
Hi David,
forgot to mention I use the RGtk2 GUI toolkit.
options(guiToolkit=RGtk2)
Under tcl I do not get this results neither. Under RGtk2 I do (Mac
OS 10.6.1, R 2.10.0 32-bit).
Any ideas?
I don't have anything constructive to offer. Any time I try to run a
package that depends on Gtk2+ I fail at some point in ways that seem
to depend on compilation options or resources that I do not have
correctly arranged in my libraries. My questions to the R-Mac-SIG list
list seem to be taken as evidence of irremediable *NIX cluelessness.
So I have decided to spend my time on other, more productive pursuits.
--
David
TIA!
Mark
Am 27.12.2009 um 18:05 schrieb David Winsemius:
On Dec 27, 2009, at 11:29 AM, Mark Heckmann wrote:
In The following code, the table handler is executed twice when
the button is pressed (from the 2nd pressing on).
Can't reproduce. On a Mac 10.5.8, R 2.10.1, running the 64 bit GUI,
after choosing the gWidgetstcltk option for GUI toolkit when
gwindow() is first executed, I do not get a behavior that suggests
that the table handler gets executed twice with each button click.
I get an X11 window with a button across the width of the top of
the window. Each time the button is clicked I get :
addhandlerclicked button
addhandlerclicked table
Just for fun I modified your tbl handler and got sensible
incrementing highlighting of the rows with:
addhandlerclicked(b, handler=function(h, ...){
+ cat(addhandlerclicked button\n)
+ svalue(tbl, index=T) - 1+svalue(tbl) # the earlier code did not
change values
+ })
I want it to be executed only once. Does someone know, why this
happens and how I can change it?
library(gWidgets)
w - gwindow()
b - gbutton(press, cont=w)
tbl - gtable(1:10, cont=w)
addhandlerclicked(b, handler=function(h, ...){
cat(addhandlerclicked button\n)
svalue(tbl, index=T) - 1# change the table
value
})
addhandlerclicked(tbl, handler=function(h, ...){
cat(addhandlerclicked table\n)
})
Thanks!
Mark
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
–––
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Vorstraße 93 B01
28359 Bremen
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Make the output (from a Loop function) a Vector
David Winsemius wrote: On Dec 27, 2009, at 11:17 AM, Cat Morning wrote: Hi all, I have made a loop function which prints outputs. For example: for (i in 1:5) + print(i) [1] 1 [1] 2 [1] 3 [1] 4 [1] 5 However, I would like the output to given as a list or a vector, e..g c(1,2,3,4,5). Is it possible to do this? This does suggest that you need to do some more studying of whatever text you are using to learn R: v - c() for (i in 1:5) v - c(v,i) v [1] 1 2 3 4 5 Or if you wanted to see the results with each iteration: v - c() for (i in 1:5) print(v - c(v,i)) [1] 1 [1] 1 2 [1] 1 2 3 [1] 1 2 3 4 [1] 1 2 3 4 5 (The function I am using outputs many 1000s of results, so is not easy to change to a vector manually.) Completely right, but just for completeness let me add that the loop is slow using your allocation method (add more memory to v in each iteration), better allocate the whole vector v at first as in: v - numeric(5) for (i in 1:5) print(v[i] - i) well, given your really need a loop ... Best, Uwe Ligges So you probably would not want the print() version. Many Thanks. [[alternative HTML version deleted]] Set your mail-client up to send plain-text. David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Positions in datasets
David Winsemius wrote: On Dec 27, 2009, at 12:11 PM, Anders Falk wrote: Could someone help me understand this Basically I want to know the position of certain numbers in large output data sets. First consider the following simple example where we get the postions of ones (1) in the vector q. q - c(5,1,1,3,1,1,1,1) q [1] 5 1 1 3 1 1 1 1 for (i in 1:length(q)) if(q[i]==1) print(i) [1] 2 [1] 3 [1] 5 [1] 6 [1] 7 [1] 8 Well done! But now consider the following case where the input consists of different combinations of the three numbers 2, 3 and 7. They are put into a function 1/x +1/y +1/z +1/(x*y*z). All different combinations will yield the same result namely precisely 1, which is also clearly seen in the output. However when I try to get information on the position of the ones in the output, there are only two that are recognized, although all six items in the output are indeed ones. x - c(2,2,3,3,7,7); y - c(3,7,2,7,2,3); z - c(7,3,7,2,3,2) data.frame(x,y,z) x y z 1 2 3 7 2 2 7 3 3 3 2 7 4 3 7 2 5 7 2 3 6 7 3 2 p - numeric(length(x)) for (i in 1:length(x)) p[i] - ((1/x[i]) + (1/y[i]) + (1/z[i]) + (1/(x[i]*y[i]*z[i]))) p [1] 1 1 1 1 1 1 for (i in 1:length(p)) if(p[i]==1) print(i) [1] 4 [1] 6 I suppose there must exist some better way of accessing the position of certain numbers in a large data output. data output is a bit vague, but if you are talking about vectors then: ?which So apart from getting advice on that I would certainly also like to understand why the above only seems to work in some cases. It's a FAQ, 7.31: http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f for (i in 1:length(p)) if(all.equal(p[i],1)) print(i) [1] 1 [1] 2 [1] 3 [1] 4 [1] 5 [1] 6 Completely right, but just for completeness let me add that you do never want to say 1:length(p) in your code, because it might happen that p becomes empty and your loop will iterate over 1:0, hence better always (then you'll never run into that problem) use seq_along as in: for (i in seq_along(p)) if(all.equal(p[i],1)) print(i) Best, Uwe Ligges Anders B Falk PhD Uppsala Sweden __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to create a simple loop ?
An alternative approach (clumsy but probably not as clumsy as a loop) would be to create a sixth column as a factor and aggregate on that. Simple-minded example : === mydata - data.frame(matrix(rnorm(100),nrow=20)) mydata[,6] - c(rep(a,5),rep(b,20-10),rep(c,5)) aggregate(mydata[,5], by=list(mydata[,6]), mean) Set all the unwanted values to X and subset on that before calculating. --- On Sun, 12/27/09, Edouard Tallent tallen...@lycos.com wrote: From: Edouard Tallent tallen...@lycos.com Subject: [R] how to create a simple loop ? To: r-help@r-project.org Received: Sunday, December 27, 2009, 9:15 AM Hi everyone. And, Merry Xmas ! I have a 5-row matrix called “data”. There are headers. it look like this : Row 1 Row2 Row3 Row4 Row5 Line1 … … … … Line2 … … … … Line3 … … … … … Line 1838 … … … … I want to calculate several simple arithmetic means for Row5, that is from Line173 to Line193, from Line434 to Line455, from Line699 to Line724, from Line955 to Line977 A simple way is to individually compute these means. The first one (Line173 to Line193) is then obtained by : mean(data[173:193,5], na.rm = TRUE) That’s right ! But, I aim to automate this calculation by creating a loop. I tried many things, but I have been unsuccessful at using the ‘for’ loop function. Please, don’t explain things too hard as it is often the case that people wants to help but gets into too much sophistication. Someone can write that little code for this example ? Or suggest functions ? Thanks for your help. Cheers, Édouard. [[alternative(swapped) HTML version deleted]] This is MIME Epilogue -Inline Attachment Follows- __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ Looking for the perfect gift? Give the gift of Flickr! http://www.flickr.com/gift/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to create a simple loop ?
try this:
mydata - matrix(runif(5000),ncol=5)
indices - list(c(173, 193),
+ c(434, 455),
+ c(699, 724),
+ c(955, 977))
result - lapply(indices, function(.indx){
+ mean(mydata[.indx[1]:.indx[2], 5])
+ })
result
[[1]]
[1] 0.5364535
[[2]]
[1] 0.4080824
[[3]]
[1] 0.5109079
[[4]]
[1] 0.4392921
On Sun, Dec 27, 2009 at 9:14 AM, Edouard Tallent tallen...@lycos.comwrote:
I have a 5-row matrix called data. There are headers.
it look like this :
Row 1 Row2Row3Row4Row5
Line1
Line2
Line3
Line 1838
I want to calculate several simple arithmetic means for Row5, that is from
Line173 to Line193, from Line434 to Line455, from Line699 to Line724, from
Line955 to Line977
A simple way is to individually compute these means. The first one
(Line173 to Line193) is then obtained by :
mean(data[173:193,5], na.rm = TRUE)
Thats right ! But, I aim to automate this calculation by creating a loop.
I tried many things, but I have been unsuccessful at using the for loop
function.
Please, dont explain things too hard as it is often the case that people
wants to help but gets into too much sophistication.
Someone can write that little code for this example ? Or suggest functions
?
Thanks for your help.
Cheers,
Édouard.
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+1 513 646 9390
What is the problem that you are trying to solve?
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Re: [R] Building static HTML help pages in R 2.10.x on Windows
Heinz Tuechler wrote: Instead of an answer, may I add question c) can someone state that it is impossible to generate static HTML help pages under Windows? No, it is not impossible, see my answers below. At 21:40 22.12.2009, Steve Rowley wrote: I upgraded to R2.10.1pat and discovered, along with everybody else, that static HTML pages are no longer the default. Fine; my tastes would go the other way, but I'm happy to adapt. However, I'd still like to build static HTML pages (for stable bookmarking, use when R is not running, etc.). I'm using the Windows installer, so the advice in the R Installation Admin guide (section 2.2, Help options) to use the configure option --enable-prebuilt-html doesn't seem to apply. I'm using install.packages() rather than R CMD INSTALL, so I don't quite understand how the --html arg to R CMD INSTALL can apply either. So, can anybody point me to an example of either: (a) how to build the static HTML help pages of all currently installed packages under Windows, At least two ways: Way 1: reinstall all those packages from sources using R CMD INSTALL --html Way 2: go to the man directory of a source package and apply R CMD Rdconv --type=html *.Rd to all Rd files. or, failing that (b) how to do this on Windows ab initio, from a clean install? install the packages from sources as described in (a) Way 1 rather than the prebuilt binaries from CRAN. Best wishes, Uwe Ligges Thanks! -- Steve Rowley s...@alum.mit.edu http://alum.mit.edu/www/sgr/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Scaling error
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say
the mean of the respective columns, V1-V3;
sca
V1V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop
function i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the
column/row in the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Building static HTML help pages in R 2.10.x on Windows
Slightly (but not completely) irrelevant comment. The next version of the R rpm packaged by Fedora WILL include static web pages by default (so I'm told by Tom [Spot] Callaway). This also goes for the R packages that they package as RPMs. This is irrelevant for Windows users of course, but others might be following this thread. Jon -- Jonathan Baron, Professor of Psychology, University of Pennsylvania Home page: http://www.sas.upenn.edu/~baron __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Scaling error
If out is what you want to achieve, why don't you multiply sca (called
m below) with the transpose of x and then transpose the resulting
matrix?
x=c(1,2,3,4,5,6,7,8,9)
dim(x)=c(3,3)
x=t(x)
x
m=c(2.5,1.7,3.6)
x*m #returns what you don't want
t(t(x)*m) #returns what you want
HTH
Daniel
-
cuncta stricte discussurus
-
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Muhammad Rahiz
Sent: Sunday, December 27, 2009 2:27 PM
To: r-help@r-project.org
Subject: [R] Scaling error
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say
the mean of the respective columns, V1-V3;
sca
V1V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop
function i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the
column/row in the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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and provide commented, minimal, self-contained, reproducible code.
[R] very beginner's question
Begging the list's indulgence, an extremely dumb beginner's question. I've got 24 months' worth of numbers - ranging from 2 events per month, to 66 events per month. I want to take a stab at making a reasonable guess as to what the next year's data would be, approximately, i.e., based on the 24 months I've got, I want to be able to tell someone: the 12 months after this will probably average about $number of events per month. Assuming I'm able to navigate R with a minimum degree of proficiency, where would I start with this? As you can doubtless tell, I'm not looking for anything sophisticated - just a reasonable estimate. Am I going to be able to do better than a projected per-month guess based on $total/$number_of_months? Thanks very much - _ Hotmail: Trusted email with powerful SPAM protection. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] very beginner's question
See ?ets in the forecast package. On Sun, Dec 27, 2009 at 2:51 PM, Facetious Nickname facetious_nickn...@hotmail.com wrote: Begging the list's indulgence, an extremely dumb beginner's question. I've got 24 months' worth of numbers - ranging from 2 events per month, to 66 events per month. I want to take a stab at making a reasonable guess as to what the next year's data would be, approximately, i.e., based on the 24 months I've got, I want to be able to tell someone: the 12 months after this will probably average about $number of events per month. Assuming I'm able to navigate R with a minimum degree of proficiency, where would I start with this? As you can doubtless tell, I'm not looking for anything sophisticated - just a reasonable estimate. Am I going to be able to do better than a projected per-month guess based on $total/$number_of_months? Thanks very much - _ Hotmail: Trusted email with powerful SPAM protection. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Scaling error
Hi,
Try this,
x - matrix(1:9, ncol=3, byrow=T)
sca - c(2.5, 1.7, 3.6)
x %*% diag(1/sca)
HTH,
baptiste
2009/12/27 Muhammad Rahiz muhammad.ra...@ouce.ox.ac.uk:
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1 V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say the
mean of the respective columns, V1-V3;
sca
V1 V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1 V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1 V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop function
i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the column/row in
the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194
Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Positions in datasets
Thank you both for your excellent help. Best Regards, Anders Falk David Winsemius wrote: On Dec 27, 2009, at 12:11 PM, Anders Falk wrote: Could someone help me understand this Basically I want to know the position of certain numbers in large output data sets. First consider the following simple example where we get the postions of ones (1) in the vector q. q - c(5,1,1,3,1,1,1,1) q [1] 5 1 1 3 1 1 1 1 for (i in 1:length(q)) if(q[i]==1) print(i) [1] 2 [1] 3 [1] 5 [1] 6 [1] 7 [1] 8 Well done! But now consider the following case where the input consists of different combinations of the three numbers 2, 3 and 7. They are put into a function 1/x +1/y +1/z +1/(x*y*z). All different combinations will yield the same result namely precisely 1, which is also clearly seen in the output. However when I try to get information on the position of the ones in the output, there are only two that are recognized, although all six items in the output are indeed ones. x - c(2,2,3,3,7,7); y - c(3,7,2,7,2,3); z - c(7,3,7,2,3,2) data.frame(x,y,z) x y z 1 2 3 7 2 2 7 3 3 3 2 7 4 3 7 2 5 7 2 3 6 7 3 2 p - numeric(length(x)) for (i in 1:length(x)) p[i] - ((1/x[i]) + (1/y[i]) + (1/z[i]) + (1/(x[i]*y[i]*z[i]))) p [1] 1 1 1 1 1 1 for (i in 1:length(p)) if(p[i]==1) print(i) [1] 4 [1] 6 I suppose there must exist some better way of accessing the position of certain numbers in a large data output. data output is a bit vague, but if you are talking about vectors then: ?which So apart from getting advice on that I would certainly also like to understand why the above only seems to work in some cases. It's a FAQ, 7.31: http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f for (i in 1:length(p)) if(all.equal(p[i],1)) print(i) [1] 1 [1] 2 [1] 3 [1] 4 [1] 5 [1] 6 Completely right, but just for completeness let me add that you do never want to say 1:length(p) in your code, because it might happen that p becomes empty and your loop will iterate over 1:0, hence better always (then you'll never run into that problem) use seq_along as in: for (i in seq_along(p)) if(all.equal(p[i],1)) print(i) Best, Uwe Ligges Anders B Falk PhD Uppsala Sweden __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Anders Falk Mobil: 0707-913910 email: anders.f...@vbsg.slu.se __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Building static HTML help pages in R 2.10.x on Windows
Heinz Tuechler wrote: At 21:40 22.12.2009, Steve Rowley wrote: (a) how to build the static HTML help pages of all currently installed packages under Windows, [...] At least two ways: Way 1: reinstall all those packages from sources using R CMD INSTALL --html Way 2: go to the man directory of a source package and apply R CMD Rdconv --type=html *.Rd to all Rd files. Ok, thanks. That's starting along a helpful path. The first way sounds dicey on Windows, since some of the packages require tools that I probably have installed (e.g., as part of Cygwin), but have never thought about how to hook together. The second way sounds useful if I want to download the source for all the packages in addition to the binary installers that I already have. Is there any way to do this from the Windows binary .zip files, or from the installations generated thereby? After all, R generates the HTML on the fly somehow, so the information is present; IWBNI there were a way to use that to generate the static HTML. (Looking through the installation dirs doesn't show very many .Rd files.) -- Steve Rowley s...@alum.mit.edu http://alum.mit.edu/www/sgr/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Is SEM package of R suitable for sem analysis
Well, I guess it will be extremely difficult to persuade your teacher to use the sem package in R. AFAIK, AMOS and LISREL have become the golden standard for SEM in China, and SEM has become a golden model for analysis in social science and psychology. I have been a cynic to SEM for a long time, because I strongly believe this model has been completely abused, and perhaps the easy-to-use AMOS has been helping people abuse SEM. A common phenomenon I see is, people do not care about the model at all - all they care about is whether AMOS can successfully compute the coefficients; if AMOS failed, they will try to (randomly) set constraints to the model, i.e. add/remove this arrow, drag some variables into/out of the model, set this coefficient/variance to 1. Anyway, I encourage you to ask your teacher why AMOS is more suitable. I have a couple of very ridiculous stories about the SEM software, in which I can only feel the blind faith in software. Sigh... The good thing is, R is open source, so is the sem package. You can see everything in it, and you can extend it as you wish (in case your teacher think it is less suitable). Regards, Yihui -- Yihui Xie xieyi...@gmail.com Phone: 515-294-6609 Web: http://yihui.name Department of Statistics, Iowa State University 3211 Snedecor Hall, Ames, IA On Sat, Dec 26, 2009 at 8:26 PM, Reeyarn_李智洋_10928113 reey...@gmail.com wrote: Dear Bruno and Joe, Thanks for advising! Reeyarn On Sat, Dec 26, 2009 at 9:32 PM, Bruno Falissard falissar...@wanadoo.fr wrote: A few years ago it could have been true, but now the package has improved (especially with the bootstrap procedure). At the moment there is no argument to recommend AMOS. On Sun, Dec 27, 2009 at 12:30 AM, Joe King j...@joepking.com wrote: I am going to take SEM this next quarter in my doctoral program. My suggestion is to use the program your professor suggests and try to re-create your models in R using the SEM package. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] inquiry
Dear John P. Burkett I would appreciate you to send me some scripts to run DEA with 20 similar DMU Best regards Betancourt -- Este mensaje le ha llegado mediante el servicio de correo electronico que ofrece Infomed para respaldar el cumplimiento de las misiones del Sistem a Nacional de Salud. La persona que envia este correo asume el compromiso de usar el servicio a tales fines y cumplir con las regulaciones establecidas Infomed: http://www.sld.cu/ [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] RGtk2 / gWidgets - addHandlerClicked Problem
Hi David,
forgot to mention I use the RGtk2 GUI toolkit.
options(guiToolkit=RGtk2)
Under tcl I do not get this results neither. Under RGtk2 I do (Mac OS
10.6.1, R 2.10.0 32-bit).
Any ideas?
TIA!
Mark
Am 27.12.2009 um 18:05 schrieb David Winsemius:
On Dec 27, 2009, at 11:29 AM, Mark Heckmann wrote:
In The following code, the table handler is executed twice when the
button is pressed (from the 2nd pressing on).
Can't reproduce. On a Mac 10.5.8, R 2.10.1, running the 64 bit GUI,
after choosing the gWidgetstcltk option for GUI toolkit when gwindow
() is first executed, I do not get a behavior that suggests that the
table handler gets executed twice with each button click. I get an
X11 window with a button across the width of the top of the window.
Each time the button is clicked I get :
addhandlerclicked button
addhandlerclicked table
Just for fun I modified your tbl handler and got sensible
incrementing highlighting of the rows with:
addhandlerclicked(b, handler=function(h, ...){
+ cat(addhandlerclicked button\n)
+ svalue(tbl, index=T) - 1+svalue(tbl) # the earlier code did not
change values
+ })
I want it to be executed only once. Does someone know, why this
happens and how I can change it?
library(gWidgets)
w - gwindow()
b - gbutton(press, cont=w)
tbl - gtable(1:10, cont=w)
addhandlerclicked(b, handler=function(h, ...){
cat(addhandlerclicked button\n)
svalue(tbl, index=T) - 1 # change the
table value
})
addhandlerclicked(tbl, handler=function(h, ...){
cat(addhandlerclicked table\n)
})
Thanks!
Mark
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Vorstraße 93 B01
28359 Bremen
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
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[R] help: creating a unified histogram
Good evening, I would like to put the histograms of several matrices on the same graph, together on a unified histogram (instead of having one bar per value on the x-axis, have multiple bars: one representing each matrix, with different colored bars for example to distinguish between the matrices). I couldn't find a function doing that involving hist, plot nor other plotting functions. Is there a function which does this? Thank you, Yael Yohai (Bioinformatics research) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] gWidgets / RGtk2 - how to change a handler from a toolbar?
I want to assign a default handler to a toolbar button and change the handler later. The addhandlerclicked() method does not apply to a gAction Object, I think... defHandler - function(h, ...) print(default) w - gwindow() aTest - gaction(label=Test, icon=open, handler=defHandler) tblList = list( test = aTest ) toolBar = gtoolbar(tblList, cont=w) At this point I would like to change the handler from the aTest object. Does someone know? TIA Mark ––– Mark Heckmann Dipl. Wirt.-Ing. cand. Psych. Vorstraße 93 B01 28359 Bremen Blog: www.markheckmann.de R-Blog: http://ryouready.wordpress.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] R and Finance - EAD, LGD, PD
Hi, I'm currently beginning to use R for financial analysis (mainly Basel II benchmarks) and I would like to know if any R-User can give me some initial directions on packages and tutorials which I can use to calculate capital requirements, default probabilities, and related stuff. Thanks in advance, Rick [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R and Finance - EAD, LGD, PD
Howdy- You may want to check out the R-sig-finance list and search through the postings here: http://n4.nabble.com/Rmetrics-f925806.html There's quite a few packages in the CRAN taskviews as well: http://cran.r-project.org/web/views/Finance.html -cj Ricardo Gonçalves Silva wrote: Hi, I'm currently beginning to use R for financial analysis (mainly Basel II benchmarks) and I would like to know if any R-User can give me some initial directions on packages and tutorials which I can use to calculate capital requirements, default probabilities, and related stuff. Thanks in advance, Rick [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help: creating a unified histogram
Hi Yael, Have you tried to find it on google R graph gallery ? bests milton On Sun, Dec 27, 2009 at 2:45 PM, Yael Yohai yael.yo...@gmail.com wrote: Good evening, I would like to put the histograms of several matrices on the same graph, together on a unified histogram (instead of having one bar per value on the x-axis, have multiple bars: one representing each matrix, with different colored bars for example to distinguish between the matrices). I couldn't find a function doing that involving hist, plot nor other plotting functions. Is there a function which does this? Thank you, Yael Yohai (Bioinformatics research) [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] problems in building R with libpng/cairo/jpeg
Hi, I'm installing R 2.10.1 under Linux but I don't know why my installation does not support png/cairo/jpeg: capabilities() jpeg png tifftcltk X11 aqua http/ftp sockets FALSEFALSEFALSEFALSEFALSEFALSE TRUE TRUE libxml fifo clediticonv NLS profmemcairo TRUE TRUE TRUE TRUE TRUEFALSEFALSE Here is some system information: *...@*** [~]# uname -srvmo Linux 2.6.28-10.7.intel.IGB.BHsmp #1 SMP Thu Aug 13 21:52:24 MDT 2009 x86_64 GNU/Linux *...@*** [~]# rpm -qa | grep -E 'libpng|cairo|pango|libjpeg' libjpeg-devel-6b-37 libjpeg-6b-37 pycairo-1.2.0-1.1 libpng-devel-1.2.10-7.1.el5_3.2 pango-1.14.9-6.el5.centos cairo-1.2.4-5.el5 libjpeg-devel-6b-37 libpng-1.2.10-7.1.el5_3.2 libpng-1.2.10-7.1.el5_3.2 pango-1.14.9-6.el5.centos cairo-devel-1.2.4-5.el5 pango-devel-1.14.9-6.el5.centos cairo-1.2.4-5.el5 libjpeg-6b-37 libpng-devel-1.2.10-7.1.el5_3.2 It seems that all necessary libraries have been installed, and the configure script can find libpng and jpeglib but cannot find pango and cairo (even using --with-cairo): *...@*** [~/etc/R]# ./configure --prefix=$HOME/bin/R checking build system type... x86_64-unknown-linux-gnu checking host system type... x86_64-unknown-linux-gnu loading site script './config.site' loading build-specific script './config.site' checking whether pkg-config knows about cairo and pango... no checking whether pkg-config knows about cairo... no checking if jpeglib version = 6b... yes checking for jpeg_destroy_compress in -ljpeg... yes checking for main in -lz... yes checking if libpng version = 1.0.5... yes checking for png_create_write_struct in -lpng... yes R is now configured for x86_64-unknown-linux-gnu Source directory: . Installation directory:/***/bin/R C compiler:gcc -std=gnu99 -g -O2 Fortran 77 compiler: gfortran -g -O C++ compiler: g++ -g -O2 Fortran 90/95 compiler:gfortran -g -O Obj-C compiler: Interfaces supported: X11 External libraries:readline Additional capabilities: PNG, JPEG, TIFF, NLS Options enabled: shared BLAS, R profiling, Java Recommended packages: yes configure: WARNING: you cannot build DVI versions of the R manuals configure: WARNING: you cannot build DVI versions of all the help pages configure: WARNING: you cannot build PDF versions of the R manuals configure: WARNING: you cannot build PDF versions of all the help pages After I make make install, jpeg, png and cairo are not supported. I'm a Linux novice. Any hints for my installation? Thanks! Regards, Yihui -- Yihui Xie xieyi...@gmail.com Phone: 515-294-6609 Web: http://yihui.name Department of Statistics, Iowa State University 3211 Snedecor Hall, Ames, IA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help: creating a unified histogram
Here is one way of doing it using the basic graphics:
# crate some data
x1 - rnorm(1,0,1)
x2 - rnorm(1,1,2)
# get data from histograms
bin.size - seq(-10,10,0.1) # bin size - may sure it spans the range
h1 - hist(x1, plot=FALSE, breaks=bin.size)
h2 - hist(x2, plot=FALSE, breaks=bin.size)
# create a matrix for 'barplot'
# limit xlim=c(-3, 4)
my.lim - c(-3, 4)
data.mat - rbind(h1$counts[h1$mids my.lim[1] h1$mids my.lim[2]],
h2$counts[h2$mids my.lim[1] h2$mids my.lim[2]])
z - barplot(data.mat, beside=TRUE, col=c('red', 'green'), space=c(0,0),
legend.text=c('x1', 'x2'))
# now create the axis using current setting of 'usr' and supplying
# your own values for x
my.ticks - seq(my.lim[1], my.lim[2], .5)
axis(1, at=approx(seq(my.lim[1], my.lim[2], length=ncol(z)), colMeans(z),
xout=my.ticks)$y,
labels=my.ticks)
On Sun, Dec 27, 2009 at 2:45 PM, Yael Yohai yael.yo...@gmail.com wrote:
Good evening,
I would like to put the histograms of several matrices on the same graph,
together on a unified histogram (instead of having one bar per value on the
x-axis, have multiple bars: one representing each matrix, with different
colored bars for example to distinguish between the matrices). I couldn't
find a function doing that involving hist, plot nor other plotting
functions. Is there a function which does this?
Thank you,
Yael Yohai
(Bioinformatics research)
[[alternative HTML version deleted]]
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http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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Re: [R] R on amazon's EC2 cloud?
Hello, I tried Amazon EC2 with R recently and wrote an entry about it to a blog I collaborate with: http://analisisydecision.es/probando-r-sobre-el-ec2-de-amazon/ (Unfortunately, it is in Spanish...) Best regards, Carlos J. Gil Bellosta http://www.datanalytics.com Blair Christian wrote: Hi All, I was wondering if anybody had experience running R on amazon's ec2 cloud? More specifically, has anybody created an amazon machine image (AMI) for use with it? I was wondering if there was a quantian type image available as an amazon machine image, maybe running debian or ubuntu? It supports open MPI among other libs which is nice. It would be nice to put together a hardware optimized image that the community could use (eg lapack with openmp blas support that kind of thing), maybe a debian with no X installed, but including R + all packages? http://aws.amazon.com/ec2/#pricing I'm at the point where it's almost easier/cost effective to outsource the hardware... I bring this up because I saw that they were going to start a spot market for cycles- useful for things like MCMC chains that need lots of runs... http://bit.ly/8A2e1g __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Scaling error
sweep(x, 2, m, FUN='/')
On Sun, Dec 27, 2009 at 2:26 PM, Muhammad Rahiz
muhammad.ra...@ouce.ox.ac.uk wrote:
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say the
mean of the respective columns, V1-V3;
sca
V1V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop
function i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the column/row
in the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194
Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
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and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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[R] CRAN (and crantastic) updates this week
CRAN (and crantastic) updates this week New packages * batch (1.0-0) Thomas Hoffmann http://crantastic.org/packages/batch Functions to allow you to easily pass command-line arguments into R (primary use is linux), and functions to aid in submitting your R code in parallel on a cluster and joining the results afterward (e.g. multiple parameter values for simulations running in parallel, splitting up a permutation test in parallel, etc.). See `parseCommandArgs(...)' for the main example of how to use this package. * bfast (1.1) Jan Verbesselt http://crantastic.org/packages/bfast BFAST integrates the decomposition of time series into trend, seasonal, and remainder components with methods for detecting and characterizing abrupt changes within the trend and seasonal components. BFAST can be used to analyze different types of satellite image time series and can be applied to other disciplines dealing with seasonal or non-seasonal time series, such as hydrology, climatology, and econometrics. The algorithm can be extended to label detected changes with information on the parameters of the fitted piecewise linear models. * bibtex (0.1-3) Romain Francois http://crantastic.org/packages/bibtex Utility to parse a bibtex file * BioStatR (1.0.0) Frederic Bertrand http://crantastic.org/packages/BioStatR This packages provides datasets for the book Exercices et problèmes de statistique avec le logiciel R. * boolfun (0.2.1) Frederic Lafitte http://crantastic.org/packages/boolfun This package can be used to assess cryptographic properties of Boolean functions (such as nonlinearity, algebraic immunity, resiliency, ...). * BoSSA (1.1) Pierre Lefeuvre http://crantastic.org/packages/BoSSA Sort sequence from genbank. Retrieve sequence information from genbank (designed for viruses sequences and retrieve information such as isolation dates and host). Detect group of sequences presenting phylogeography signal. Read PDB file (protein 3D structure file). * CCP (0.1) Uwe Menzel to http://crantastic.org/packages/CCP Significance tests for canonical correlation analysis, including asymptotic tests and a Monte Carlo method * cubature (1.0) Balasubramanian Narasimhan http://crantastic.org/packages/cubature Adaptive multivariate integration over hypercubes * doMPI (0.1-3) Steve Weston http://crantastic.org/packages/doMPI Provides a parallel backend for the %dopar% function using the Rmpi package. * GrassmannOptim (1.0) Kofi Placid Adragni http://crantastic.org/packages/GrassmannOptim Optimizing a function F(U), where U is a semi-orthogonal matrix and F is invariant under an orthogonal transformation of U * heavy (0.1-1) Felipe Osorio http://crantastic.org/packages/heavy Estimation in linear mixed effects models using heavy-tailed distributions * Imap (1.01) John R. Wallace http://crantastic.org/packages/Imap Zoom in and out of maps or any supplied lines or points, with control for color, poly fill, and aspect. * openintro (1.0) David Diez http://crantastic.org/packages/openintro This package is intended to be a supplement to the Open Intro open source book project. This package contains data sets used in the book along with functions used to make the book's figures. * r2dRue (1.0) Unknown http://crantastic.org/packages/r2dRue 2dRUE is a methodology to make a diagnostic of land condition in a large territory during a given time period. Was developed under the DeSurvey IP. * RcmdrPlugin.sos (0.1-0) Liviu Andronic http://crantastic.org/packages/RcmdrPlugin-sos Rcmdr interface to sos. The plug-in renders the sos searching functionality easily accessible via the Rcmdr menus. It also simplifies the task of performing multiple searches and subsequently obtaining the union or the intersection of the search results. * rngWELL (0.9) Christophe Dutang http://crantastic.org/packages/rngWELL It is a dedicated package to WELL pseudo random generators. But it is not intended to use it directly, you are strongly __encouraged__ to directly use the 'randtoolbox' package, which depends on this package. * SampleSizeMeans (1.0) Lawrence Joseph http://crantastic.org/packages/SampleSizeMeans A set of R functions for calculating sample size requirements using three different Bayesian criteria in the context of designing an experiment to estimate a normal mean or the difference between two normal means. Functions for calculation of required sample sizes for the Average Length Criterion, the Average Coverage Criterion and the Worst Outcome Criterion in the context of normal means are provided. Functions for both the fully Bayesian and the mixed Bayesian/likelihood approaches are provided. * SampleSizeProportions (1.0) Lawrence Joseph http://crantastic.org/packages/SampleSizeProportions A set of R functions for calculating
Re: [R] R and Finance - EAD, LGD, PD
i think rick's questions are more related to basel II instead of R and don't think there is such a R package. per my limited knowledge, there are many ways to calculate PD, EAD, and LGD, either on portfolio level or on account level. So it really depends on how you are going to estimate them. On the side of consumer credit risk, it makes more sense to estimate 3 models on the account level, which should be under the umbrella of GLM. While PD / LGD are well studied, EAD is not. There are multiple ways to estimate EAD, such as LEQ/CCF/EADF, depending on the characteristic of accounts. 2009/12/27 Cedrick W. Johnson cedr...@cedrickjohnson.com Howdy- You may want to check out the R-sig-finance list and search through the postings here: http://n4.nabble.com/Rmetrics-f925806.html There's quite a few packages in the CRAN taskviews as well: http://cran.r-project.org/web/views/Finance.html -cj Ricardo Gonçalves Silva wrote: Hi, I'm currently beginning to use R for financial analysis (mainly Basel II benchmarks) and I would like to know if any R-User can give me some initial directions on packages and tutorials which I can use to calculate capital requirements, default probabilities, and related stuff. Thanks in advance, Rick [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- == WenSui Liu Blog : statcompute.spaces.live.com Tough Times Never Last. But Tough People Do. - Robert Schuller == [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Lacunarity analisys using R
Hi R-people, I have done spatial and geostatistics for some time and now I am interested in concentration indexes. There is one index named Lacunarity. Is there any extension like that in R? Thank you all, José Bustos [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] gWidgets / RGtk2 - how to change a handler from a toolbar?
Mark Heckmann mark.heckmann at gmx.de writes: I want to assign a default handler to a toolbar button and change the handler later. The addhandlerclicked() method does not apply to a gAction Object, I think... defHandler - function(h, ...) print(default) w - gwindow() aTest - gaction(label=Test, icon=open, handler=defHandler) tblList = list( test = aTest ) toolBar = gtoolbar(tblList, cont=w) There should be a method to do this, but for now there isn't. A workaround would be to have the default handler call a function which can be redefined during the flow of the program: f - function(h,...) print(default) defHandler - function(h, ...) f(h,...) The RGtk2 way would be to remove the handler and add a new one, but even that isn't so easy, as the id isn't stored at the moment. --John At this point I would like to change the handler from the aTest object. Does someone know? TIA Mark ––– Mark Heckmann Dipl. Wirt.-Ing. cand. Psych. Vorstraße 93 B01 28359 Bremen Blog: www.markheckmann.de R-Blog: http://ryouready.wordpress.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] RGtk2 / gWidgets - addHandlerClicked Problem
Mark Heckmann mark.heckmann at gmx.de writes: In The following code, the table handler is executed twice when the button is pressed (from the 2nd pressing on). I want it to be executed only once. Does someone know, why this happens and how I can change it? .. snip .. Thanks! Mark Mark, it is a bug in how svalue- updates the table, as it does it twice: once to clear the selection and a second time to set the selection. I'll have to look into this one to see what I can do. --John ––– Mark Heckmann Dipl. Wirt.-Ing. cand. Psych. Vorstraße 93 B01 28359 Bremen Blog: www.markheckmann.de R-Blog: http://ryouready.wordpress.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] RGtk2 - retrieve ggraphics mouse coordinates during drag-and-drop event
Mark Heckmann mark.heckmann at gmx.de writes:
Hi all,
I have a gtable and a ggraphic widget.
I want to drag an element from the table onto the graphic.
When the drag object is released over the ggraphic widget, I want the
mouse coordinates inside the ggraphic to be returned.
Right now I do not know how to get the mouse ccordinates of the
ggraphic widget at any given time.
How can I access the ggraphics mouse coordinates?
The handler has h$x and h$y components to do this. In your code
(which I clipped to save space) you might
look at:
defHandlerTarget = function(h, ...){
theArgs - list(...)
w - theArgs[[1]]
allocation = w$GetAllocation()
## h$x, h$y give x,y coords for g
x = h$x/allocation$width
y = 1 - (allocation$height - h$y)/allocation$height
print(c(x,y))
}
If that doesn't help, let me know.
Below you find my sample code (windows only due to ggraphics).
(The ggraphics widget works with linux and mac too, although the mac can have
issues with some installations.)
TIA,
Mark
..snip..
–––
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Vorstraße 93 B01
28359 Bremen
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Is SEM package of R suitable for sem analysis
I don't know the situation of psychology. In sociology, SEM is regarded is advanced statistical technique, but I am not quite sure if it is golden model. Actually, SEM is not so common in journal papers. It is not about R. Sorry for being off-topic. Best 2009/12/28 Yihui Xie x...@yihui.name: Well, I guess it will be extremely difficult to persuade your teacher to use the sem package in R. AFAIK, AMOS and LISREL have become the golden standard for SEM in China, and SEM has become a golden model for analysis in social science and psychology. I have been a cynic to SEM for a long time, because I strongly believe this model has been completely abused, and perhaps the easy-to-use AMOS has been helping people abuse SEM. A common phenomenon I see is, people do not care about the model at all - all they care about is whether AMOS can successfully compute the coefficients; if AMOS failed, they will try to (randomly) set constraints to the model, i.e. add/remove this arrow, drag some variables into/out of the model, set this coefficient/variance to 1. Anyway, I encourage you to ask your teacher why AMOS is more suitable. I have a couple of very ridiculous stories about the SEM software, in which I can only feel the blind faith in software. Sigh... The good thing is, R is open source, so is the sem package. You can see everything in it, and you can extend it as you wish (in case your teacher think it is less suitable). Regards, Yihui -- Yihui Xie xieyi...@gmail.com Phone: 515-294-6609 Web: http://yihui.name Department of Statistics, Iowa State University 3211 Snedecor Hall, Ames, IA On Sat, Dec 26, 2009 at 8:26 PM, Reeyarn_李智洋_10928113 reey...@gmail.com wrote: Dear Bruno and Joe, Thanks for advising! Reeyarn On Sat, Dec 26, 2009 at 9:32 PM, Bruno Falissard falissar...@wanadoo.fr wrote: A few years ago it could have been true, but now the package has improved (especially with the bootstrap procedure). At the moment there is no argument to recommend AMOS. On Sun, Dec 27, 2009 at 12:30 AM, Joe King j...@joepking.com wrote: I am going to take SEM this next quarter in my doctoral program. My suggestion is to use the program your professor suggests and try to re-create your models in R using the SEM package. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Wincent Ronggui HUANG Doctoral Candidate Dept of Public and Social Administration City University of Hong Kong http://asrr.r-forge.r-project.org/rghuang.html __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Modified R Code
Dear R helpers,
I have following input files. (Actually they are more than 10 rates but here i
am considering only 2 rates to write my problem)
rate1.csv
min1 max1 min2 max2 min3 max3
1.051.30 1.30 1.65 1.65 1.99
rate2.csv
min1 max1 min2 max2 min3 max3
2.052.30 2.30 2.65 2.65 2.99
The simple R code I had used to read these files was as given below -
# OLD CODE
rates1 = read.csv('rate1.csv)
rates2 = read.csv('rate2.csv')
rate1_min1 = rates1$min1
rate1_max1 = rates1$max1
rate1_min2 = rates1$min2
rate1_max2 = rates1$max2
rate1_min3 = rates1$min3
rate1_max3 = rates1$max3
rate2_min1 = rates2$min1
rate2_max1 = rates2$max1
rate2_min2 = rates2$min2
rate2_max2 = rates2$max2
rate2_min3 = rates2$min3
rate2_max3 = rates2$max3
Since I am not aware how many rates I will be dealing with (it can be 2, 4, or
10), hence I can't hardcode my input like I had defined above.
So with the guidance of R - help, I had rerwitten the input code as given below.
# NEW CODE
n = 2 # It gives me no of rates
X = paste('rate', 1:n, '.csv', sep = ' ' )
# the output is rate1.csv rate2.csv
newrate = lapply(X, read.csv)
# the output is as given below
newrate
[ [1] ]
min1 max1 min2 max2 min3 max3
1 1.05 1.30 1.301.65 1.65 1.99
[ [2] ]
min1 max1 min2 max2 min3 max3
1 2.05 2.30 2.302.65 2.65 2.99
## _
## PROBLEM
# PROBLEM - A
If I apply the command (As given in OLD CODE above)
rate1_min1 = rates1$min1
# The output which I get is
min1
1 1.05
On similar lines I define
rate1_min1 = newrate[[1]] [1]
# The output which I get is
min1
1 1.05
rate1_max1 = newrate[[1]] [2]
will give me output
max1
1 1.30
and so on.
So I will have to define it 12 times to assign the respective min and max
values.
My problem is instead of hard coding like I have done in OLD CODE, I need to
assign these respective input values using a loop or some other way (as it
becomes cumbersome if no of rates exceed say 10 and also since I am not aware
how many rate files i will be dealing with) so that in the end I should be able
to assign (say) the values like
rate1_min1 = 1.05
rate1_max1 = 1.30
rate1_min2 = 1.30
rate1_max2 = 1.65
rate1_min3 = 1.65
rate1_max3 = 1.99
rate2_min1 = 2.05
rate2_max1 = 2.30
rate2_min2 = 2.30
rate2_max2 = 2.65
rate2_min3 = 2.65
rate2_max3 = 2.99
If there are say 10 rates, then this will continue till
rate10_min1 = ..
rate10_max1 = ..
.
so on.
##
# PROBLEM - B
# Suppose Rij = ith Rate and jth range. (There are 3 ranges i.e. j= 3).
data_label = expand.grid(c(R11, R12, R13), c(R21, R23, R23))
# gives the output like
data_label
Var1 Var2
1 R11 R21
2 R12 R21
3R13 R21
4 R11 R22
5 R12 R22
6 R13 R22
7 R11 R23
8 R12 R23
9R13 R23
If instead of two rates, suppose there are three rates, I will have to modify
my code as
data_label = expand.grid(c(R11, R12, R13), c(R21, R23, R23),
c(R31, R32, R33))
If I define say
n = no_of_rates # I will be taking this figure from some otehr csv file.
My PROBLEM = B is how do I write the above code pertaining to data_label in
terms of 'n'.
## ___
I understand I am giving the impression as I need some kind of spoon feeding. I
am giving below the original complete OLD CODE (consisting of 4 rates) I had
written in the beginning. Problem with me is to modify it for varaible number
of rates.
I sincerely apologize for the inconvenience I have caused so far by asking
queries. Please guide me.
Regards
Maithili
#
MY ORIGINAL CODE (Actual HARD CODE)
## ONS - PPA
# INPUT
rate_1 = read.csv('rate1_range.csv')
rate_2 = read.csv('rate2_range.csv')
rate_3 = read.csv('rate3_range.csv')
rate_4 = read.csv('rate4_range.csv')
prob_1 = read.csv('rate1_probs.csv')
prob_2 = read.csv('rate2_probs.csv')
prob_3 = read.csv('rate3_probs.csv')
prob_4 = read.csv('rate4_probs.csv')
rate1_min_1 = rate_1$rate1_range1_min
rate1_max_1 = rate_1$rate1_range1_max
rate1_min_2 = rate_1$rate1_range2_min
rate1_max_2 = rate_1$rate1_range2_max
rate1_min_3 = rate_1$rate1_range3_min
rate1_max_3 = rate_1$rate1_range3_max
rate2_min_1 = rate_2$rate2_range1_min
rate2_max_1 = rate_2$rate2_range1_max
rate2_min_2 = rate_2$rate2_range2_min
rate2_max_2 =
Re: [R] help: creating a unified histogram
On 12/28/2009 06:45 AM, Yael Yohai wrote: Good evening, I would like to put the histograms of several matrices on the same graph, together on a unified histogram (instead of having one bar per value on the x-axis, have multiple bars: one representing each matrix, with different colored bars for example to distinguish between the matrices). I couldn't find a function doing that involving hist, plot nor other plotting functions. Is there a function which does this? Hi Yael, See the last example for the barp function in the plotrix package. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Modified R Code
Dear R helpers,
I have following input files. (Actually they are more than 10 rates but here i
am considering only 2 rates to write my problem)
rate1.csv
min1 max1 min2 max2 min3 max3
1.051.30 1.30 1.65 1.65 1.99
rate2.csv
min1 max1 min2 max2 min3 max3
2.052.30 2.30 2.65 2.65 2.99
The simple R code I had used to read these files was as given below -
# OLD CODE
rates1 = read.csv('rate1.csv)
rates2 = read.csv('rate2.csv')
rate1_min1 = rates1$min1
rate1_max1 = rates1$max1
rate1_min2 = rates1$min2
rate1_max2 = rates1$max2
rate1_min3 = rates1$min3
rate1_max3 = rates1$max3
rate2_min1 = rates2$min1
rate2_max1 = rates2$max1
rate2_min2 = rates2$min2
rate2_max2 = rates2$max2
rate2_min3 = rates2$min3
rate2_max3 = rates2$max3
Since I am not aware how many rates I will be dealing with (it can be 2, 4, or
10), hence I can't hardcode my input like I had defined above.
So with the guidance of R - help, I had rerwitten the input code as given below.
# NEW CODE
n = 2 # It gives me no of rates
X = paste('rate', 1:n, '.csv', sep = ' ' )
# the output is rate1.csv rate2.csv
newrate = lapply(X, read.csv)
# the output is as given below
newrate
[ [1] ]
min1 max1 min2 max2 min3 max3
1 1.05 1.30 1.301.65 1.65 1.99
[ [2] ]
min1 max1 min2 max2 min3 max3
1 2.05 2.30 2.302.65 2.65 2.99
## _
## PROBLEM
# PROBLEM - A
If I apply the command (As given in OLD CODE above)
rate1_min1 = rates1$min1
# The output which I get is
min1
1 1.05
On similar lines I define
rate1_min1 = newrate[[1]] [1]
# The output which I get is
min1
1 1.05
rate1_max1 = newrate[[1]] [2]
will give me output
max1
1 1.30
and so on.
So I will have to define it 12 times to assign the respective min and max
values.
My problem is instead of hard coding like I have done in OLD CODE, I need to
assign these respective input values using a loop or some other way (as it
becomes cumbersome if no of rates exceed say 10 and also since I am not aware
how many rate files i will be dealing with) so that in the end I should be able
to assign (say) the values like
rate1_min1 = 1.05
rate1_max1 = 1.30
rate1_min2 = 1.30
rate1_max2 = 1.65
rate1_min3 = 1.65
rate1_max3 = 1.99
rate2_min1 = 2.05
rate2_max1 = 2.30
rate2_min2 = 2.30
rate2_max2 = 2.65
rate2_min3 = 2.65
rate2_max3 = 2.99
If there are say 10 rates, then this will continue till
rate10_min1 = ..
rate10_max1 = ..
.
so on.
##
# PROBLEM - B
# Suppose Rij = ith Rate and jth range. (There are 3 ranges i.e. j= 3).
data_label = expand.grid(c(R11, R12, R13), c(R21, R23, R23))
# gives the output like
data_label
Var1 Var2
1 R11 R21
2 R12 R21
3R13 R21
4 R11 R22
5 R12 R22
6 R13 R22
7 R11 R23
8 R12 R23
9R13 R23
If instead of two rates, suppose there are three rates, I will have to modify
my code as
data_label = expand.grid(c(R11, R12, R13), c(R21, R23, R23),
c(R31, R32, R33))
If I define say
n = no_of_rates # I will be taking this figure from some otehr csv file.
My PROBLEM = B is how do I write the above code pertaining to data_label in
terms of 'n'.
## ___
I sincerely apologize for the inconvenience I have caused so far by asking
queries. Please guide me.
Regards
Maithili
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[R] Help with Moving Average in R
Hello,guys: I want to use a moving average estimation in my analysis. When refering to this moving average, I mean a MA in a technical analysis definition, and not to the definition in Time Series Analysis. Actually, it is an AR estimation in TSA. So I use the function filter to compute it. For example, i compute the ma2 as below: x = 1:10 ma2 = filter(x,rep(1/2, 2),sides =1) ma2 [1] NA 1.5 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5 Note that the ma2 estimation use the current value as an input, and i want to avoid this. I mean I just want to use the past values x[t-2] and x[t-1] to get the ma2, and use that as the current estimation. So that is actually a ma3 with the coefficient c(1/2, 1/2, 0), so i use the command as below: MA2 = filter(x,c(rep(1/2,2),0),sides = 1) MA2 [1] NA NA 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5 But what I want is: [1] NA NA 1.5 2.5 3.5 4.5 5.5 6.5 7.5 8.5 And I think the command I used to get MA2 should give a result as what I want, but it just does not. I want to know the reason, and I wondor if anyone could introduce a more convinient way to compute that. Thank you all in advance Saji from Shanghai __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] MS-VAR
Dear R users, I would like to estimate a MS-VAR where the probabilities of regime shifts are dependent of an exogenous variable. Is it possible to do this using R? Best, Henrique C. de Andrade Doutorando em Economia Aplicada Universidade Federal do Rio Grande do Sul www.ufrgs.br/ppge __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Help with Moving Average in R
Saji Ren wrote: ... MA2 = filter(x,c(rep(1/2,2),0),sides = 1) MA2 [1] NA NA 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5 But what I want is: [1] NA NA 1.5 2.5 3.5 4.5 5.5 6.5 7.5 8.5 And I think the command I used to get MA2 should give a result as what I want, but it just does not. I want to know the reason, and I wondor if anyone could introduce a more convinient way to compute that. How about MA2 - filter(yts,c(0,rep(0.5,2)),sides=1) Berend -- View this message in context: http://n4.nabble.com/Help-with-Moving-Average-in-R-tp989627p989645.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
