from:"Laszlo"

[R] mzR and Rcpp version bug

2014-04-02 Thread Zsurzsa Laszlo

Good morning everyone,


I'm having the following error when I try to load the *mzR* libary. Does
someone have a clue where to search for a solution. I tried to re-install *mzR
*and *Rcpp* also, but with no effect.

-
 library(mzR)
Lade nötiges Paket: Rcpp
Error : .onLoad in loadNamespace() für 'mzR' fehlgeschlagen, Details:
  Aufruf: value[[3L]](cond)
  Fehler: failed to load module Ramp from package mzR
kann Vektor der Größe 13.2 GB nicht allozieren
Zusätzlich: Warnmeldungen:
1: In fun(libname, pkgname) :
   mzR has been built against a different Rcpp version
 than is installed on your system. This might lead to errors
 when loading mzR. If you encounter such issues, please send
 a report, including the output of sessionInfo() to the Bioc
 mailing list -- http://www.bioconductor.org/help/mailing-list.
2: In Module(m, pkg, mustStart = TRUE) :
  Reached total allocation of 8183Mb: see help(memory.size)
3: In Module(m, pkg, mustStart = TRUE) :
  Reached total allocation of 8183Mb: see help(memory.size)
4: In Module(m, pkg, mustStart = TRUE) :
  Reached total allocation of 8183Mb: see help(memory.size)
5: In Module(m, pkg, mustStart = TRUE) :
  Reached total allocation of 8183Mb: see help(memory.size)
Fehler: Laden von Paket oder Namensraum für 'mzR' fehlgeschlagen
 sessionInfo()
R version 3.0.3 (2014-03-06)
Platform: x86_64-w64-mingw32/x64 (64-bit)

locale:
[1] LC_COLLATE=German_Germany.1252  LC_CTYPE=German_Germany.1252
 LC_MONETARY=German_Germany.1252 LC_NUMERIC=C
[5] LC_TIME=German_Germany.1252

attached base packages:
[1] stats graphics  grDevices utils datasets  methods   base

other attached packages:
[1] Rcpp_0.11.1

loaded via a namespace (and not attached):
[1] Biobase_2.20.1 BiocGenerics_0.6.0 parallel_3.0.3
-


Best Regards, László-András Zsurzsa
Master of Informatics Student,
Technical University Munich, Germany

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Re: [R] Shiny - can one create one RUN button?

2013-09-13 Thread Zsurzsa Laszlo

Maybe this link can help you:

http://rstudio.github.io/shiny/tutorial/#more-widgets

This is an example with submit button.

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Fri, Sep 13, 2013 at 12:21 AM, Dimitri Liakhovitski 
dimitri.liakhovit...@gmail.com wrote:

 Hello!

 I am learning to use Shiny.

 Imagine my ui.r file contains two different inputs that I can change:

 sidebarPanel(
   numericInput(input1, My input 1:, 5),
   numericInput(input2, My input 2:, 10)
 )


 And I am generating (in server.r file) the sum of those two using
 reactive({...

 If I change just one of the inputs, I immediately get the changed result -
 because the whole expression is reactive.

 Question: is there any way to delay the production of the output until one
 wants it to be produced (i.e., only after one selected all the correct
 inputs needed) and have something like a RUN button?

 Thank you!

 --
 Dimitri Liakhovitski

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Re: [R] XLSX package + Excel creation question

2013-09-04 Thread Zsurzsa Laszlo

http://stackoverflow.com/questions/18511249/excel-cell-coloring-using-xlsx

This is the initial post on stackoverflow. Please look at this maybe I'm
clearer here.

Thank you in advance,

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Fri, Aug 30, 2013 at 3:48 PM, jim holtman jholt...@gmail.com wrote:

 You can also look at the XLConnect package.
 Jim Holtman
 Data Munger Guru

 What is the problem that you are trying to solve?
 Tell me what you want to do, not how you want to do it.


 On Thu, Aug 29, 2013 at 9:40 AM, Zsurzsa Laszlo zsurzsalas...@gmail.com
 wrote:
  I understand you response but it does not solve the problem. I'am aware
  that one can simply color every cell in an excel file by using his own
  algorithm.
 
  The question was if I can write my data to a *single* cells and use
  different formatting for every piece of data.
 
 
 -
  - László-András Zsurzsa,-
  - Msc. Infromatics, Technical University Munich, Germany -
  - Scientific Employee, TUM -
 
 -
 
 
  On Thu, Aug 29, 2013 at 3:36 PM, Rainer Hurling rhur...@gwdg.de wrote:
 
  Am 29.08.2013 15:03 (UTC+1) schrieb Zsurzsa Laszlo:
   First of all thank you for the quick resposen.
  
   I know I can color and set up every cell. I will take a look again *
   CellStyle* but is it possbile for example to write an array to a
 single
   cell that has different colors for some data. Basically the color
 depends
   on the data.
 
  As far as I know there is no ready to use functionality to mask groups
  of selected cells. You have to write your own function, which selects
  the right cells and changes their style with setCellStyle(cell,
 cellStyle).
 
  Some hints are given in the examples section of ?CellStyle.
 
  
  
 
 -
   - László-András Zsurzsa,
-
   - Msc. Infromatics, Technical University Munich, Germany -
   - Scientific Employee, TUM
   -
  
 
 -
  
  
   On Thu, Aug 29, 2013 at 2:55 PM, Rainer Hurling rhur...@gwdg.de
 wrote:
  
   Am 29.08.2013 12:08 (UTC+1) schrieb Zsurzsa Laszlo:
   Dear R users,
  
   I have a question about the xlsx package. It's possible to create
 excel
   files and color cells and etc.
  
   yes, with package xlsx you can colourize you data sheets, even the
   fonts. See for example ?CellStyle .
  
   A good demonstration of the capabilities is on
  
  
 
 http://tradeblotter.wordpress.com/2013/05/02/writing-from-r-to-excel-with-xlsx/
  
  
   My question would be that is it possible to color only some part of
 the
   data hold in a cell. Let's assume I've got the following data :
   167,153,120,100 and I want to color to red everything that is bigger
  then
   120. How can I achive this using R.
  
   Example file setup with a few lines in attachment. (SEL_MASS column
 can
   be
   used for example)
  
   Attachment missing ...
  
   HTH,
   Rainer
  
  
   Thank you in advance,
  
  
 
 -
   - László-András Zsurzsa,
   -
   - Msc. Infromatics, Technical University Munich, Germany -
   - Scientific Employee, TUM
  -
  
  
 
 -
  
  
 [[alternative HTML version deleted]]
  
  
  
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   R-help@r-project.org mailing list
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   PLEASE do read the posting guide
  http://www.R-project.org/posting-guide.html
   and provide commented, minimal, self-contained, reproducible code.
  
 
 
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  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 


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and provide commented, minimal, self-contained, reproducible code.

Re: [R] XLSX package + Excel creation question

2013-09-04 Thread Zsurzsa Laszlo

Thank you for the reply, I wount post any other link anymore. I did not
know it's not allowed.

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-

On Wed, Sep 4, 2013 at 1:22 PM, Keith Jewell
keith.jew...@campdenbri.co.ukwrote:

I'll skip over the courtesy implications of double posting/pointing to
stackoverflow.

The stackoverflow thread makes it look as if you need to learn more Excel.
Do you really not know what an Excel template is?

It sounds as if you want what Excel calls conditional formatting which
you can specify as custom number formats, see http://www.ozgrid.com/Excel/
**CustomFormats.htm http://www.ozgrid.com/Excel/CustomFormats.htm.

Excel's help on custom number formats says:

To specify number formats that will be applied only if a number meets a
condition that you specify, enclose the condition in square brackets. The
condition consists of a comparison operator (comparison operator: A sign
that is used in comparison criteria to compare two values. Operators
include: = Equal to, Greater than, Less than, = Greater than or equal
to, = Less than or equal to, and Not equal to.) and a value. For
example, the following format displays numbers that are less than or equal
to 100 in a red font and numbers that are greater than 100 in a blue font.
[Red][=100];[Blue][100]
--

R package xlsx allows such formats (?DataFormat) as does R package
XLConnect (?setDataFormat).

HTH

Keith J

On 04/09/2013 09:57, Zsurzsa Laszlo wrote:

http://stackoverflow.com/**questions/18511249/excel-cell-**
coloring-using-xlsxhttp://stackoverflow.com/questions/18511249/excel-cell-coloring-using-xlsx

This is the initial post on stackoverflow. Please look at this maybe I'm
clearer here.

Thank you in advance,

--**--**
-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
--**--**
-

On Fri, Aug 30, 2013 at 3:48 PM, jim holtmanjholt...@gmail.com wrote:

You can also look at the XLConnect package.
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.

On Thu, Aug 29, 2013 at 9:40 AM, Zsurzsa Laszlozsurzsalas...@gmail.com*
*
wrote:

I understand you response but it does not solve the problem. I'am aware
that one can simply color every cell in an excel file by using his own
algorithm.

The question was if I can write my data to a *single* cells and use
different formatting for every piece of data.

--**--**
-

- László-András Zsurzsa,
-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -

--**--**
-

On Thu, Aug 29, 2013 at 3:36 PM, Rainer Hurlingrhur...@gwdg.de
wrote:

Am 29.08.2013 15:03 (UTC+1) schrieb Zsurzsa Laszlo:

First of all thank you for the quick resposen.

I know I can color and set up every cell. I will take a look again *
CellStyle* but is it possbile for example to write an array to a

single

cell that has different colors for some data. Basically the color

depends

on the data.

As far as I know there is no ready to use functionality to mask groups
of selected cells. You have to write your own function, which selects
the right cells and changes their style with setCellStyle(cell,

cellStyle).

Some hints are given in the examples section of ?CellStyle.

--**--**
-

- László-András Zsurzsa,

- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM

--**--**
-

On Thu, Aug 29, 2013 at 2:55 PM, Rainer Hurlingrhur...@gwdg.de

wrote:

Am 29.08.2013 12:08 (UTC+1) schrieb Zsurzsa Laszlo:

Dear R users,

I have a question about the xlsx package. It's possible to create

excel

files and color cells and etc.

yes, with package xlsx you can colourize you data sheets, even the
fonts. See for example ?CellStyle .

A good demonstration of the capabilities is on

http://tradeblotter.wordpress.**com/2013/05/02/writing-from

Re: [R] Help If

2013-08-29 Thread Zsurzsa Laszlo

Hey

if  (( (1==1)  (2==2) ) || (3==3)) {  print( hello world) }

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Thu, Aug 29, 2013 at 11:11 AM, Zsurzsa Laszlo zsurzsalas...@gmail.comwrote:

 Hey

 if  (( (1==1)  (2==2) ) || (3==3)) {  print( hello world) }


 -
 - László-András Zsurzsa,-
 - Msc. Infromatics, Technical University Munich, Germany -
 - Scientific Employee, TUM -

 -


 On Thu, Aug 29, 2013 at 10:16 AM, Mª Teresa Martinez Soriano 
 teresama...@hotmail.com wrote:

 Hi to everyone and sorry for my question,  I would like to use IF in an
 example like this:


 If((condition1 and condition2) Or (condition 3 and condition4)) {print
 uhvef}


 BUt I don´t know how to write it correctly,

 Thanks in advance
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and provide commented, minimal, self-contained, reproducible code.

[R] XLSX package + Excel creation question

2013-08-29 Thread Zsurzsa Laszlo

Dear R users,


I have a question about the xlsx package. It's possible to create excel
files and color cells and etc.

My question would be that is it possible to color only some part of the
data hold in a cell. Let's assume I've got the following data :
167,153,120,100 and I want to color to red everything that is bigger then
120. How can I achive this using R.

Example file setup with a few lines in attachment. (SEL_MASS column can be
used for example)




Thank you in advance,
-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Re: [R] XLSX package + Excel creation question

2013-08-29 Thread Zsurzsa Laszlo

First of all thank you for the quick resposen.

I know I can color and set up every cell. I will take a look again *
CellStyle* but is it possbile for example to write an array to a single
cell that has different colors for some data. Basically the color depends
on the data.

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Thu, Aug 29, 2013 at 2:55 PM, Rainer Hurling rhur...@gwdg.de wrote:

 Am 29.08.2013 12:08 (UTC+1) schrieb Zsurzsa Laszlo:
  Dear R users,
 
  I have a question about the xlsx package. It's possible to create excel
  files and color cells and etc.

 yes, with package xlsx you can colourize you data sheets, even the
 fonts. See for example ?CellStyle .

 A good demonstration of the capabilities is on

 http://tradeblotter.wordpress.com/2013/05/02/writing-from-r-to-excel-with-xlsx/

 
  My question would be that is it possible to color only some part of the
  data hold in a cell. Let's assume I've got the following data :
  167,153,120,100 and I want to color to red everything that is bigger then
  120. How can I achive this using R.
 
  Example file setup with a few lines in attachment. (SEL_MASS column can
 be
  used for example)

 Attachment missing ...

 HTH,
 Rainer

 
  Thank you in advance,
 
 -
  - László-András Zsurzsa,-
  - Msc. Infromatics, Technical University Munich, Germany -
  - Scientific Employee, TUM -
 
 -


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__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Re: [R] XLSX package + Excel creation question

2013-08-29 Thread Zsurzsa Laszlo

I understand you response but it does not solve the problem. I'am aware
that one can simply color every cell in an excel file by using his own
algorithm.

The question was if I can write my data to a *single* cells and use
different formatting for every piece of data.

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Thu, Aug 29, 2013 at 3:36 PM, Rainer Hurling rhur...@gwdg.de wrote:

 Am 29.08.2013 15:03 (UTC+1) schrieb Zsurzsa Laszlo:
  First of all thank you for the quick resposen.
 
  I know I can color and set up every cell. I will take a look again *
  CellStyle* but is it possbile for example to write an array to a single
  cell that has different colors for some data. Basically the color depends
  on the data.

 As far as I know there is no ready to use functionality to mask groups
 of selected cells. You have to write your own function, which selects
 the right cells and changes their style with setCellStyle(cell, cellStyle).

 Some hints are given in the examples section of ?CellStyle.

 
 
 -
  - László-András Zsurzsa,-
  - Msc. Infromatics, Technical University Munich, Germany -
  - Scientific Employee, TUM -
 
 -
 
 
  On Thu, Aug 29, 2013 at 2:55 PM, Rainer Hurling rhur...@gwdg.de wrote:
 
  Am 29.08.2013 12:08 (UTC+1) schrieb Zsurzsa Laszlo:
  Dear R users,
 
  I have a question about the xlsx package. It's possible to create excel
  files and color cells and etc.
 
  yes, with package xlsx you can colourize you data sheets, even the
  fonts. See for example ?CellStyle .
 
  A good demonstration of the capabilities is on
 
 
 http://tradeblotter.wordpress.com/2013/05/02/writing-from-r-to-excel-with-xlsx/
 
 
  My question would be that is it possible to color only some part of the
  data hold in a cell. Let's assume I've got the following data :
  167,153,120,100 and I want to color to red everything that is bigger
 then
  120. How can I achive this using R.
 
  Example file setup with a few lines in attachment. (SEL_MASS column can
  be
  used for example)
 
  Attachment missing ...
 
  HTH,
  Rainer
 
 
  Thank you in advance,
 
 
 -
  - László-András Zsurzsa,
  -
  - Msc. Infromatics, Technical University Munich, Germany -
  - Scientific Employee, TUM
 -
 
 
 -
 
 
[[alternative HTML version deleted]]
 
 
 
  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 


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and provide commented, minimal, self-contained, reproducible code.

Re: [R] Help R

2013-08-29 Thread Zsurzsa Laszlo

Do you have NA/NAN in your data set? If yes our check with an IF or
substitute them with a value that fits your need.

I hope I understood correctly your problem.

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Thu, Aug 29, 2013 at 3:49 PM, Mª Teresa Martinez Soriano 
teresama...@hotmail.com wrote:

 Hi to everyone,

 I would like to replace some values in a data.frame (D)

  str(D)
 'data.frame':   116 obs. of  10 variables:
  $ X. : int  1108 1591 3408 3872 5823 8099 10640 12600 14680 14698 ...
  $ media  : num  22 86.6 807 103.2 73 ...
  $ IE.2003: num  32 92 166 237 161 ...
  $ IE.2004: num  63 122.8 290 117.8 73.6 ...
  $ IE.2005: num  60 277 302 154 134 ...
  $ IE.2006: num  39 87 322 113 70 ...
  $ IE.2007: num  4 95 621 116 80 ...
  $ IE.2008: num  8 94 1071 90 74 ...
  $ IE.2009: num  16 81 1301 94 69 ...
  $ IE.2010: num  5 76 1225 1911 72 ...

 D

 X.  media IE.2003 IE.2004 IE.2005 IE.2006 IE.2007 IE.2008 IE.2009
 IE.2010
 1   1108   22.032.063.060.0  39 4.0   8
  16 5.0
 2   1591   86.692.0   122.8   276.6  8795.0  94
  8176.0
 3   3408  807.0   166.0   290.0   302.0 322   621.01071
  1301  1225.0
 4   3872  103.25000   237.2   117.8   154.4 113   116.0  90
  94  1911.2
 5   5823   73.0   160.673.6   133.6  7080.0  74
  6972.0
 6   8099  125.16667   169.0   206.0   196.0 161   150.0  94
  7278.0
 7  10640   67.3   494.8   168.2   424.8 476   670.6  74
  7751.0
 8  12600 2417.0  1958.0  1871.0  1960.02383  2453.02506
  2758  2442.0
 9  14680   38.0   142.246.030.0  61   404.0  42
  19   243.8
 10 14698  698.16667   505.0   482.0   553.0 664   847.0 800
 679   646.0



 WHat I really want to do is:

  for( i in 1: nrow(D))
  {
for( j in 5:ncol(D))
{
 D[((D[i,j]/D[i,2])1.5)]15999)]-100
}

  }






 Error en `[-.data.frame`(`*tmp*`, (D[i, j] 15999), value = 1e+06) :
   missing values are not allowed in subscripted assignments of data frames
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Re: [R] R Language Newbie

2013-08-28 Thread Zsurzsa Laszlo

Can you specify you're task? I don't understand totally what you need to
do?  You're already getting odd numbers with :  seq(1,100,by=2)

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Wed, Aug 28, 2013 at 12:18 AM, arun smartpink...@yahoo.com wrote:

 Hi,
 set.seed(29)

 myVector- rnorm(100)
  seq(1,100,by=2)
 # [1]  1  3  5  7  9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43
 45 47 49
 #[26] 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95
 97 99


 myVector[seq(1,100,by=2)]


 rev(myVector)

  sum(myVector0)
 #[1] 46
 #or

  table(myVector0)
 #
 #FALSE  TRUE
  #  5446



 A.K.



 Hey guys, this is my first week taking R language courses and I'm having
 trouble with this assignment. I think I got the hang of it to an extent but
 was wondering if I could get help on one tiny part of my
 assignment.

 How can I get odd numbers from the vector I've created? To show
 you guys I've done the majority of my homework by myself I've included
 screenshots.

 __
 R-help@r-project.org mailing list
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Re: [R] R Language Newbie

2013-08-28 Thread Zsurzsa Laszlo

Hello,

#3

myVector  - c(1:100)
oddVector - myVector[c(1:100) %% 2 == 1]

odd - myVector[c(1:100) %% 2 == 1]
identical( odd, seq(1,100,by=2)) gives me FALSE

#3

Is this what you suggested?

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Wed, Aug 28, 2013 at 2:17 PM, arun smartpink...@yahoo.com wrote:



 HI,

 I was talking about another method to get the same result:

  myVector[1:100%%2==1]


 identical(myVector[1:100%%2==1],myVector[seq(1,100,by=2)])
 #[1] TRUE

 Hope it helps.
 A.K.
 
 From: Zsurzsa Laszlo zsurzsalas...@gmail.com
 To: arun smartpink...@yahoo.com
 Cc: R help r-help@r-project.org
 Sent: Wednesday, August 28, 2013 5:21 AM
 Subject: Re: [R] R Language Newbie



 Can you specify you're task? I don't understand totally what you need to
 do?  You're already getting odd numbers with :  seq(1,100,by=2)

 --
 László-András Zsurzsa,-
 - Msc. Infromatics, Technical University Munich, Germany -
 - Scientific Employee, TUM -


 -


 On Wed, Aug 28, 2013 at 12:18 AM, arun smartpink...@yahoo.com wrote:

 Hi,
 set.seed(29)
 
 myVector- rnorm(100)
  seq(1,100,by=2)
 # [1]  1  3  5  7  9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43
 45 47 49
 #[26] 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93
 95 97 99
 
 
 myVector[seq(1,100,by=2)]
 
 
 rev(myVector)
 
  sum(myVector0)
 #[1] 46
 #or
 
  table(myVector0)
 #
 #FALSE  TRUE
  #  5446
 
 
 
 A.K.
 
 
 
 Hey guys, this is my first week taking R language courses and I'm having
 trouble with this assignment. I think I got the hang of it to an extent but
 was wondering if I could get help on one tiny part of my
 assignment.
 
 How can I get odd numbers from the vector I've created? To show
 you guys I've done the majority of my homework by myself I've included
 screenshots.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 


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and provide commented, minimal, self-contained, reproducible code.

Re: [R] R Language Newbie

2013-08-28 Thread Zsurzsa Laszlo

Hey

Sure sorry for the mistake, That was i meant to be also. I this what you
were searching?

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-


On Wed, Aug 28, 2013 at 3:03 PM, arun smartpink...@yahoo.com wrote:

 HI,
 'odd' and 'oddVector' are the same.


  identical(odd,oddVector)
 #[1] TRUE
  identical(odd,myVector[seq(1,100,by=2)])  myVector#
 #[1] TRUE

 A.K.

 
 From: Zsurzsa Laszlo zsurzsalas...@gmail.com
 To: arun smartpink...@yahoo.com
 Cc: R help r-help@r-project.org
 Sent: Wednesday, August 28, 2013 8:58 AM
 Subject: Re: [R] R Language Newbie



 Hello,

 #3

 myVector  - c(1:100)

 oddVector - myVector[c(1:100) %% 2 == 1]

 odd - myVector[c(1:100) %% 2 == 1]

 identical( odd, seq(1,100,by=2)) gives me FALSE

 #3

 Is this what you suggested?



 -
 - László-András Zsurzsa,-
 - Msc. Infromatics, Technical University Munich, Germany -
 - Scientific Employee, TUM -


 -


 On Wed, Aug 28, 2013 at 2:17 PM, arun smartpink...@yahoo.com wrote:


 
 HI,
 
 I was talking about another method to get the same result:
 
  myVector[1:100%%2==1]
 
 
 identical(myVector[1:100%%2==1],myVector[seq(1,100,by=2)])
 #[1] TRUE
 
 Hope it helps.
 
 A.K.
 
 From: Zsurzsa Laszlo zsurzsalas...@gmail.com
 To: arun smartpink...@yahoo.com
 Cc: R help r-help@r-project.org
 Sent: Wednesday, August 28, 2013 5:21 AM
 Subject: Re: [R] R Language Newbie
 
 
 
 
 Can you specify you're task? I don't understand totally what you need to
 do?  You're already getting odd numbers with :  seq(1,100,by=2)
 
 --
 László-András Zsurzsa,-
 
 - Msc. Infromatics, Technical University Munich, Germany -
 - Scientific Employee, TUM -
 

 -
 
 
 On Wed, Aug 28, 2013 at 12:18 AM, arun smartpink...@yahoo.com wrote:
 
 Hi,
 set.seed(29)
 
 myVector- rnorm(100)
  seq(1,100,by=2)
 # [1]  1  3  5  7  9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43
 45 47 49
 #[26] 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93
 95 97 99
 
 
 myVector[seq(1,100,by=2)]
 
 
 rev(myVector)
 
  sum(myVector0)
 #[1] 46
 #or
 
  table(myVector0)
 #
 #FALSE  TRUE
  #  5446
 
 
 
 A.K.
 
 
 
 Hey guys, this is my first week taking R language courses and I'm having
 trouble with this assignment. I think I got the hang of it to an extent but
 was wondering if I could get help on one tiny part of my
 assignment.
 
 How can I get odd numbers from the vector I've created? To show
 you guys I've done the majority of my homework by myself I've included
 screenshots.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 
 


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and provide commented, minimal, self-contained, reproducible code.

[R] PubChem Request Search Script

2013-08-27 Thread Zsurzsa Laszlo

Dear all,

The question would be:

   I would love to get information and match names of different chemistry
compounds. A compound looks like this.
Link: http://pubchem.ncbi.nlm.nih.gov/summary/summary.cgi?cid=2

The task is the following:

1. You input a name via R to the link, then a database searches a
similar or the same compound for you. (you autotype the name in the input
field left to the search button.)
2. parse the information that you get back. (This I can do already via
R)

Thank you for you're attention,

-
- László-András Zsurzsa,-
- Msc. Infromatics, Technical University Munich, Germany -
- Scientific Employee, TUM -
-

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and provide commented, minimal, self-contained, reproducible code.

[R] readLines() problem-error

2013-07-12 Thread Zsurzsa Laszlo

Hello everyone,

I have my program like this:


while (length(oneLine - readLines(con, n = 1, warn = FALSE))  0)  {
   # here I process the line I read
}


The problem is it gives me different output every time. I get a problem/
error like:

Closing unused connection (con). Sadly I can't provide the file because
it's ,ore then a GB.

Thank you in advance,
---
- László-András Zsurzsa,  -
- Msc. Infromatics, Technical University Munich, -
---

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and provide commented, minimal, self-contained, reproducible code.

Re: [R] Help with installing a .tar.gz package on windows

2013-07-08 Thread Zsurzsa Laszlo

have you checked the bit version !?

Which R do you use? 32 or 64 bit?


---
- László-András Zsurzsa,  -
- Msc. Infromatics, Technical University Munich, -
---


On Mon, Jul 8, 2013 at 2:15 AM, Lucy Leigh lucy.le...@newcastle.edu.auwrote:

 Hi,
 I have a source package that isn't available as a windows zip file. Can
 anyone explain to me how I can install this on my windows R platform?
 When I use the following code:
  install.packages(PReMiuM_3.0.21.tar.gz, type = source)


 I get this error message:



 * installing *source* package 'PReMiuM' ...
 ** libs

 *** arch - i386
 ERROR: compilation failed for package 'PReMiuM'
 * removing 'C:/Program Files/R/R-3.0.1/library/PReMiuM'
 Warning messages:
 1: running command 'C:/PROGRA~1/R/R-30~1.1/bin/x64/R CMD INSTALL -l
 C:\Program Files\R\R-3.0.1\library PReMiuM_3.0.21.tar.gz' had status
 1
 2: In install.packages(PReMiuM_3.0.21.tar.gz, type = source) :
   installation of package PReMiuM_3.0.21.tar.gz had non-zero exit
 status
 

 Thanks for any help anyone can give me,
 Lucy

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 https://stat.ethz.ch/mailman/listinfo/r-help
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[R] String based chemical name identification

2013-07-03 Thread Zsurzsa Laszlo

The problem is the following:

I have two big databases one look like this:

  2-Methyl-4-trimethylsilyloxyoct-5-yne   Benzoic acid, methyl ester   Benzoic
acid, 2-methyl-, methyl ester   Acetic acid, phenylmethyl ester
 2,7-Dimethyl-4-trimethylsilyloxyoct-7-en-5-yne   etc.

The second one looks like this:

 Name: D-Tagatose 1,6-bisphosphate  Name: 1-Phosphatidyl-D-myo-inositol;:
1-Phosphatidyl-1D-myo-inositol;: 1-Phosphatidyl-myo-inositol;:
Phosphatidyl-1D-myo-inositol;: (3-Phosphatidyl)-1-D-inositol;:
1,2-Diacyl-sn-glycero-3-phosphoinositol;: Phosphatidylinositol  Name:
Androstenedione;: Androst-4-ene-3,17-dione;: 4-Androstene-3,17-dione  Name:
Spermine;: N,N'-Bis(3-aminopropyl)-1,4-butanediamine  Name: H+;: Hydron  Name:
3-Iodo-L-tyrosine  etc.

Both of them have more then 3000 lines. Matching their name by hand is not
an option because I don't know chemistry.

*Possible solution I came up with*:

Go through all the names of the first database and then try to match with
the other one. I'm using *regexec *and *strsplit *functions for the
matching. Basically I split the name into small chunks and try to get some
hit in the other database.

I can supply code If needed but I did not want to spam in the first mail.


Any solution is welcome! It can be in pseudo-cod also or in any type of
logical arguing. It does not matter.


Laszlo-Andras Zsurzsa

Msc. Informatics, Technical University Munchen

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[R] altering identity column

2011-04-18 Thread Bodnar Laszlo EB_HU

Hi there,

I have a huge dataframe containing 70,000 observations.

I have filtered this dataframe (let it's name be transformed_dataframe) as I 
wanted to select only those observations which are greater than or equal to 
60,001 regarding the very first identity column.

So I have a transformed dataframe now including 10,000 obeservations (from 
60,001 - to 70,000) and if you send head(transformed_dataframe) into R it 
looks like this:

variable1   variable2   variable3   
variable4   ...
60 001  ...... ...  
  ...
60 002  ...... ...  
  ...
60 003  ...... ...  
  ...
60 004  ...... ...  
  ...
60 005  ...... ...  
  ...

Sending tail(transformed_dataframe) into R it is going to be something like:

variable1   variable2   variable3   
variable4   ...
69 996  ...... ...  
  ...
69 997  ...... ...  
  ...
69 998  ... ... ... 
   ...
69 999  ...... ...  
  ...
70 000  ...... ...  
  ...


Now is there a quick way to alter this indexing of rows in case of my 
transformed_dataframe? I mean, I would like to get indices 1, 2, 3, etc... 
instead of 60 001, 60 002, 60 003 etc...

So by sending head(transformed_dataframe) and tail(transformed_dataframe) I 
would like to see:

variable1   variable2   variable3   
variable4   ...
1  .........
...
2  .........
...
3  .........
...
4  .........
...
5  .........
...

and

variable1   variable2   variable3   
variable4   ...
9 996.........  
  ...
9 997.........
...
9 998.........  
  ...
9 999.........  
  ...
10 000  .........   
 ...

Thank you very much, best regards,

Laszlo

Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


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[R] quantile function - I need only the quantile value itself

2011-03-28 Thread Bodnar Laszlo EB_HU

Hi,

I am using the quantile function currently and I have just bumped into a little 
problem.

I have a very small data frame something like this:

small_df - 
c(7,3,4,7,1,10,12,1,12,4,4,8,6,11,9,10,4,13,3,9,6,5,2,10,7,14,2,7,10,10,7,8,2,11,3,10,11,3,11,14,12,7,6,11)
small_df

Now in the next step I would like to calculate the quantile value of the 
previous data frame at the probability of 95% the following way:
quantile(small_df,probs=0.95)

The result:
 95%
 12.85

Now I need to get only the number 12.85. I do not want to present the 
probability 95% here. Is there any possible way to tell the program to do 
so?

Regards,
Laszlo

Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


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[R] deleting the first two characters in each row of a factorized column

2011-03-28 Thread Bodnar Laszlo EB_HU

Hello,

I'd like to ask you something again.
I have a database and it has a column which looks like this one here:

small_factor - factor(c(d_variable1,d_variable2,d_variable3))
small_factor

Now the thing is that I would like to convert each element of this factorized 
column. Basically I want to rewrite the words in it without the first two 
characters: d and _ and I would like to get the followings as a result: 
variable1, variable2, variable3.

Is there an easy way to do this?

Thank you,
Laszlo

Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

__
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and provide commented, minimal, self-contained, reproducible code.

[R] recalling different data frames (the way you do in Excel VB but now) in

2011-03-21 Thread Bodnar Laszlo EB_HU

Hello everyone,

I'd like to ask you a question again, basically focusing on referring to 
different objects.

Let's suppose we create the following databases this way:

id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a -c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3)
b -c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2)
c -c(1,3,2,3,2,1,2,3,3,2,2,3,1,2,3,3,3,1,1,2,3,3,1,2,2,3,2,2,3,2)
d -c(3,3,3,1,3,2,2,1,2,3,2,2,2,1,3,1,2,2,3,2,3,2,3,2,1,1,1,1,1,2)
e -c(2,3,1,2,1,2,3,3,1,1,2,1,1,3,3,2,1,1,3,3,2,2,3,3,3,2,3,2,1,4)
df -data.frame(id,a,b,c,d,e)
df

for (i in 1:3) assign(paste(df, i, sep=.), split(df,df$id)[[i]])
df.1
df.2
df.3

Now in the next step I'd like to get or recall these databases but not just 
simply sending 'df.1', 'df.2', 'df.3' to R (because my real df database is much 
bigger and much more complicated than this simplified one as usual). I would 
have liked to do this the similar way you recall these things in Excel Visual 
Basic.

You know, if we were in an Excel VB world I would do something like:
sub exercise ()
for i = 1 to 3
df.i
// perform this and that etc.//
next i
end sub

Returning to R: first I wanted to do it this way:
for (i in 1:3)
df.i (perform this and that etc...)

But of course it is wrong. Is there a proper way to handle this one? What do I 
miss? I do not know if my question is clear...
Thank you very much and thanks for the previous answers as well!
Happy R-exploring!
Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

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[R] recalling different data frames (the way you do in Excel VB)

2011-03-21 Thread Bodnar Laszlo EB_HU

Hello everyone,

I'd like to ask you a question again, basically focusing on referring to 
different objects.

Let's suppose we create the following databases this way:

id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a -c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3)
b -c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2)
c -c(1,3,2,3,2,1,2,3,3,2,2,3,1,2,3,3,3,1,1,2,3,3,1,2,2,3,2,2,3,2)
d -c(3,3,3,1,3,2,2,1,2,3,2,2,2,1,3,1,2,2,3,2,3,2,3,2,1,1,1,1,1,2)
e -c(2,3,1,2,1,2,3,3,1,1,2,1,1,3,3,2,1,1,3,3,2,2,3,3,3,2,3,2,1,4)
df -data.frame(id,a,b,c,d,e)
df

for (i in 1:3) assign(paste(df, i, sep=.), split(df,df$id)[[i]])
df.1
df.2
df.3

Now in the next step I'd like to get or recall these databases but not just 
simply sending 'df.1', 'df.2', 'df.3' to R (because my real df database is much 
bigger and much more complicated than this simplified one as usual). I would 
have liked to do this the similar way you recall these things in Excel Visual 
Basic.

You know, if we were in an Excel VB world I would do something like:
sub exercise ()
for i = 1 to 3
df.i
// perform this and that etc.//
next i
end sub

Returning to R: first I wanted to do it this way:
for (i in 1:3)
df.i (perform this and that etc...)

But of course it is wrong. Is there a proper way to handle this one? What do I 
miss? I do not know if my question is clear...
Thank you very much and thanks for the previous answers as well!
Happy R-exploring!
Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


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[R] persuade tabulate function to count NAs in a data frame

2011-03-19 Thread Bodnar Laszlo EB_HU

Hi,

I'd like to ask you a question again. It is basically about data frames, NAs 
and tabulate function.

I have this data frame. I already used this in one of the previous questions of 
mine. It intentionally looks this simple, my real 'df' dataframe is much bigger 
actually and again, I am not willing to annoy anyone with huge databases... So, 
my database:

id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a -c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3)
b -c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2)
c -c(1,3,2,3,2,1,2,3,3,2,2,3,1,2,3,3,3,1,1,2,3,3,1,2,2,3,2,2,3,2)
d -c(3,3,3,1,3,2,2,1,2,3,2,2,2,1,3,1,2,2,3,2,3,2,3,2,1,1,1,1,1,2)
e -c(2,3,1,2,1,2,3,3,1,1,2,1,1,3,3,2,1,1,3,3,2,2,3,3,3,2,3,2,1,4)
df -data.frame(id,a,b,c,d,e)
df

I have managed to calculate the distributions of the numbers occurring in 
columns 'b' to 'e' but considering the fact at the very same time that these 
distributions should be 'groupped by' the id numbers in column 'id'. It works 
fine, check it -

matrix(matrix(unlist(lapply(df[,(-(1))],function(x) 
tapply(x,df$id,tabulate,nbins=nlevels(factor(df[,2] 
[[1]])),ncol=3,nrow=3,byrow=TRUE)
matrix(matrix(unlist(lapply(df[,(-(1))],function(x) 
tapply(x,df$id,tabulate,nbins=nlevels(factor(df[,3] 
[[2]])),ncol=3,nrow=3,byrow=TRUE)
matrix(matrix(unlist(lapply(df[,(-(1))],function(x) 
tapply(x,df$id,tabulate,nbins=nlevels(factor(df[,4] 
[[3]])),ncol=3,nrow=3,byrow=TRUE)
matrix(matrix(unlist(lapply(df[,(-(1))],function(x) 
tapply(x,df$id,tabulate,nbins=nlevels(factor(df[,5] 
[[4]])),ncol=3,nrow=3,byrow=TRUE)
matrix(matrix(unlist(lapply(df[,(-(1))],function(x) 
tapply(x,df$id,tabulate,nbins=nlevels(factor(df[,6] 
[[5]])),ncol=4,nrow=3,byrow=TRUE)

Now my problem is: what if my data frame contains NA values here and there and 
what if I want my in-built tabulate function to collect these NAs as well? So 
what if I want it to count how many occurrences I have from these NAs?

Here's my modified data frame with the NAs:
id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a -c(NA,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3)
b -c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2)
c -c(1,3,2,3,2,1,2,3,3,2,2,3,NA,2,3,3,3,1,1,2,3,3,1,2,2,3,2,2,3,2)
d -c(3,3,3,1,3,2,2,1,2,3,2,2,2,1,3,1,2,2,3,2,3,2,3,2,1,1,1,1,1,2)
e -c(2,3,1,2,1,2,3,3,1,1,2,1,1,3,3,2,1,1,3,3,2,2,3,3,3,2,3,NA,1,4)
df -data.frame(id,a,b,c,d,e)
df

At first I tried something like this (you see, the only thing I did was that I 
tried to apply this exclude=NULL thing).
unlist(lapply(df[,(-(1))],function(x) 
tapply(x,df$id,tabulate,nbins=nlevels(factor(df[,2],exclude=NULL [[1]])

At least my code realizes the fact that I have 4 different levels in column 'a' 
(1,2,3,NA) and not only three (1,2,3). Check it here:
nlevels(factor(df[,2],exclude=NULL))

But you see in the result that somehow it could not calculate the NAs. It says
3  0  6  0(!)  4  3  3  0  4  1  5  0

Instead of the correct:
3  0  6  1(!)  4  3  3  0  4  1  5  0

Or in case of:
unlist(lapply(df[,(-(1))],function(x) 
tapply(x,df$id,tabulate,nbins=nlevels(factor(df[,4],exclude=NULL [[3]])

It says
2  4  4  0  2  3  4  0(!)  1  5  4  0

Instead of the correct
2  4  4  0  2  3  4  1(!)  1  5  4  0
etc.

Does someone have any ideas how to persuade the function tabulate to count 
NAs? Is it possible at all?
Thanks very much and have a pleasant weekend,
Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


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[R] calculating the occurrences of distinct observations in the subsets of a dataframe

2011-03-17 Thread Bodnar Laszlo EB_HU

Hello everybody,

I have a data frame in R which is similar to the follows. Actually my real 'df' 
dataframe is much bigger than this one here but I really do not want to confuse 
anybody so that is why I try to simplify things as much as possible.

So here's the data frame.

id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a -c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3)
b -c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2)
c -c(1,3,2,3,2,1,2,3,3,2,2,3,1,2,3,3,3,1,1,2,3,3,1,2,2,3,2,2,3,2)
d -c(3,3,3,1,3,2,2,1,2,3,2,2,2,1,3,1,2,2,3,2,3,2,3,2,1,1,1,1,1,2)
e -c(2,3,1,2,1,2,3,3,1,1,2,1,1,3,3,2,1,1,3,3,2,2,3,3,3,2,3,2,1,3)
df -data.frame(id,a,b,c,d,e)
df

Basically what I would like to do is to get the occurrences of numbers for each 
column (a,b,c,d,e) and for each id group (1,2,3) (for this latter grouping see 
my column 'id').

So, for column 'a' and for id number '1' (for the latter see column 'id') the 
code would be something like this:
as.numeric(table(df[1:10,2]))

The results are:
[1] 3 7

Just to briefly explain my results: in column 'a' (and regarding only those 
records which have number '1' in column 'id') we can say that:
number 1 occured 3 times, and
number 3 occured 7 times.

Again, just to show you another example. For column 'a' and for id number '2' 
(for the latter grouping see again column 'id'):
as.numeric(table(df[11:20,2]))

After running the codes the results are: [1] 4 3 3

Let me explain a little again: in column 'a' and regarding only those 
observations which have number '2' in column 'id') we can say that
number 1 occured 4 times
number 2 occured 3 times and
number 3 occured 3 times.

Last example: for column 'e' and for id number '3' the code would be:
as.numeric(table(df[21:30,6]))

With the results:
[1] 1 4 5

...meaning that number '1' occured once, number '2' occured four times and 
number '3' occured 5 times.

So this is what I would like to do. Calculating the occurrences of numbers for 
each custom-defined subsets (and then collecting these values into a data 
frame). I know it is NOT a difficult task but the PROBLEM is that I'm gonna 
have to change the input 'df' dataframe on a regular basis and hence both the 
overall number of rows and columns might CHANGE over time...

What I have done so far is that I have separated the 'df' dataframe by columns, 
like this:
for (z in (2:ncol(df))) assign(paste(df,z,sep=.),df[,z])

So df.2 will refer to df$a, df.3 will equal df$b, df.4 will equal df$c etc. But 
I'm really stuck now and I don't know how to move forward, you know, getting 
the occurrences for each column and each group of ids.

Do you have any ideas?
Best regards,
Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


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[R] changing the dimensions of a matrix in a real specific way

2011-03-17 Thread Bodnar Laszlo EB_HU

Hi again,

I'd like to ask you a question again.

I have a matrix like this:
a -matrix(c(1,2,3,4,5,6,7,8,9,10,11,12))
a

  [,1]
 [1,]1
 [2,]2
 [3,]3
 [4,]4
 [5,]5
 [6,]6
 [7,]7
 [8,]8
 [9,]9
[10,]   10
[11,]   11
[12,]   12

Is there a proper way to change the dimensions of this matrix so that I'll get 
this as a result:
 [,1] [,2] [,3]
[1,]   123
[2,]   456
[3,]   789
[4,]  10   11   12

Thank you very much and have a pleasant day,
Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

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Re: [R] changing one character in the name of dataframes repeatedly

2011-03-16 Thread Laszlo

Hello Ivan,

Thank you very much for your comments, they were really useful and I’ll try
to memorize and use them in the future.

Getting back to my problem… well, I try to put it in a different way because
I’m afraid this is gonna be a little bit more difficult than I thought.

So, here is my refreshed database (it is a little bit more similar to my
original database than my previous ’df’ database in my previous letter,
although still simplified).

id -c(1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3)
a -c(3,1,3,3,1,3,3,3,3,1,3,2,1,2,1,3,3,2,1,1,1,3,1,3,3,3,2,1,1,3)
b -c(3,2,1,1,1,1,1,1,1,1,1,2,1,3,2,1,1,1,2,1,3,1,2,2,1,3,3,2,3,2)
c -c(1,3,2,3,2,1,2,3,3,2,2,3,1,2,3,3,3,1,1,2,3,3,1,2,2,3,2,2,3,2)
d -c(3,3,3,1,3,2,2,1,2,3,2,2,2,1,3,1,2,2,3,2,3,2,3,2,1,1,1,1,1,2)
e -c(2,3,1,2,1,2,3,3,1,1,2,1,1,3,3,2,1,1,3,3,2,2,3,3,3,2,3,2,1,3)
df -data.frame(id,a,b,c,d,e)
df

Basically what I would like to do is to get the distributions of the numbers
for each column (a,b,c,d,e) and for each group (1,2,3) (for this latter
grouping see my column ’id’). 

So, for column ’a’ and for number ’1’ (for the latter see column ’id’):
as.numeric(table(df[1:10,2]))[1]/sum(as.numeric(table(df[1:10,2])))
as.numeric(table(df[1:10,2]))[2]/sum(as.numeric(table(df[1:10,2])))

Fist time you get: [1] 0.3, then you get: [1] 0.7

Just to briefly explain my results: in column ’a’ (and regarding only those
records which have number ’1’ in column ’id’) we can say that:
number 1 occured 3 times, and 
number 3 occured 7 times.
3 / (3+7) = 0.3, and 7 / (3+7) = 0.7

Again, just to show you another example. For column ’a’ and for number ’2’
(for the latter grouping see again column ’id’):
as.numeric(table(df[11:20,2]))[1]/sum(as.numeric(table(df[11:20,2])))
as.numeric(table(df[11:20,2]))[2]/sum(as.numeric(table(df[11:20,2])))
as.numeric(table(df[11:20,2]))[3]/sum(as.numeric(table(df[11:20,2])))

After running the codes the results are: 0.4, 0.3, 0.3.

Let me explain a little again: in column ’a’ and regarding only those
observations which have number ’2’ in column ’id’) we can say that
Number 1 occured 4 times
number 2 occured 3 times and
number 3 occured 3 times.
Now the results are obvious: 4/10 = 0.4, 3/10=0.3, 3/10=0.3 etc.

So this is what I would like to do. Calculating distributions for each
custom-defined subsets and then collecting these values into a data frame. 

The reason I wanted to sort out the problem with indices like ’i’, ’k’ etc.
(you know we discussed it previously) was because I’m gonna have to change
the input ’df’ dataframe on a regular basis and hence both the overall
number of rows and columns might change over time…

Thank you again,
Laszlo

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[R] changing one character in the name of dataframes repeatedly

2011-03-11 Thread Bodnar Laszlo EB_HU

Dear R-community,

I'd like to ask you a question concerning R again. I try to keep this simple 
because I am not willing to confuse you at all.

I have a little data frame which I have created the following way:

a -c(1,1,1,1,1,2,2,2,2,2,3,3,3,3,3,4,4,4,4,4,5,5,5,5,5,6,6,6,6,6)
b 
-c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30)
df -as.data.frame(cbind(a,b))
df

Now in the next step I would have liked to create smaller dataframes where the 
data have been extracted (basically splitted) from the main 'df' dataframe 
according to the numbers in df$a. Something like this:
a b
1 1
1 2
1 3
1 4
1 5

a  b
2  6
2  7
2  8
2  9
2 10

a  b
3 11
3 12
3 13
3 14
3 15

a  b
4 16
4 17
4 18
4 19
4 20

etc.

It is not quite difficult to do this part. But!! I also want that the name of 
each and every small dataframe should refer to the fact that according to which 
number in df$a have I selected the data in df$b.

For example:

df.1 meaning I have only chosen those numbers in df$b which have value 1 in 
df$a

df.1
a b
1 1
1 2
1 3
1 4
1 5

df.2 meaning I have only chosen those numbers in df$b which have value 2 in 
df$a.

df.2
a  b
2  6
2  7
2  8
2  9
2 10

df.3 meaning I have only chosen those numbers in df$b which have value 3 in 
df$a.
a  b
3 11
3 12
3 13
3 14
3 15
etc...

I know it would not be difficult to do this in this way:
df.1 -split(df,df$a)[[1]]
df.2 -split(df,df$a)[[2]]
df.3 -split(df,df$a)[[3]]
df.4 -split(df,df$a)[[4]]
etc...

But as a matter of fact, my real df dataframe consists of more than 4400 
records so it is impossible to do this manually for a numerous times with the 
previously mentioned split function.

I wanted to use loops and managing the problem in the following (wrong) way:
for (i in 1:6)
{
df.i -split(df,df$a)[[i]]
}

After I wanted to enter df.1, df.2, etc... R sent me the message:
Error: object 'df.1' not found.

However, it recognized df.i and listed following:
   a  b
6 26
6 27
6 28
6 29
6 30

Can you help me with this matter? I wonder if there is a proper way to do this 
which I haven't figured out yet...

Thank you very much and have a pleasant weekend,
Laszlo Bodnar


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[R] changing one character in the name of dataframes repeatedly

2011-03-11 Thread Bodnar Laszlo EB_HU

Dear R-community,

I'd like to ask you a question concerning R again. I try to keep this simple 
because I am not willing to confuse you at all.

I have a little data frame which I have created the following way:

a -c(1,1,1,1,1,2,2,2,2,2,3,3,3,3,3,4,4,4,4,4,5,5,5,5,5,6,6,6,6,6)
b 
-c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30)
df -as.data.frame(cbind(a,b))
df

Now in the next step I would have liked to create smaller dataframes where the 
data have been extracted (basically splitted) from the main 'df' dataframe 
according to the numbers in df$a. Something like this:
a b
1 1
1 2
1 3
1 4
1 5

a  b
2  6
2  7
2  8
2  9
2 10

a  b
3 11
3 12
3 13
3 14
3 15

a  b
4 16
4 17
4 18
4 19
4 20

etc.

It is not quite difficult to do this part. But!! I also want that the name of 
each and every small dataframe should refer to the fact that according to which 
number in df$a have I selected the data in df$b.

For example:

df.1 meaning I have only chosen those numbers in df$b which have value 1 in 
df$a

df.1
a b
1 1
1 2
1 3
1 4
1 5

df.2 meaning I have only chosen those numbers in df$b which have value 2 in 
df$a.

df.2
a  b
2  6
2  7
2  8
2  9
2 10

df.3 meaning I have only chosen those numbers in df$b which have value 3 in 
df$a.
a  b
3 11
3 12
3 13
3 14
3 15
etc...

I know it would not be difficult to do this in this way:
df.1 -split(df,df$a)[[1]]
df.2 -split(df,df$a)[[2]]
df.3 -split(df,df$a)[[3]]
df.4 -split(df,df$a)[[4]]
etc...

But as a matter of fact, my real df dataframe consists of more than 4400 
records so it is impossible to do this manually for a numerous times with the 
previously mentioned split function.

I wanted to use loops and managing the problem in the following (wrong) way:
for (i in 1:6)
{
df.i -split(df,df$a)[[i]]
}

After I wanted to enter df.1, df.2, etc... R sent me the message:
Error: object 'df.1' not found.

However, it recognized df.i and listed following:
   a  b
6 26
6 27
6 28
6 29
6 30

Can you help me with this matter? I wonder if there is a proper way to do this 
which I haven't figured out yet...

Thank you very much and have a pleasant weekend,
Laszlo Bodnar


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Re: [R] creating additional column

2011-03-11 Thread Laszlo

Thank you Philipp, it is very useful! How come I haven't figured it out
myself I dont know...
Have a pleasant weekend!
Laszlo

--
View this message in context: 
http://r.789695.n4.nabble.com/creating-additional-column-tp3341224p3348552.html
Sent from the R help mailing list archive at Nabble.com.

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and provide commented, minimal, self-contained, reproducible code.

[R] creating additional column

2011-03-08 Thread Bodnar Laszlo EB_HU

Hello everybody,

I have a little problem in good old R. It is basically the following.

I have this small database with 3 rows and the following columns:
d1,
d2,
d3 and
Highest d value - which selects the highest value from d1, d2, d3 in each row.

d1  d2  d3  Highest d value
1   51.398426   39.111721   11.6086220  51.398426
2   4.0578017.7284070.1234711   7.728407
3   7.2793417.36050918.2964676  18.296468

I'd like to make an additional column which shows the label of the relevant 
column where we've found the maximum d value. Something like this:

d1  d2  d3  Highest d value Where is the 
maximum?
1   51.398426   39.111721   11.6086220  51.398426   d1
2   4.0578017.7284070.1234711   7.728407d2
3   7.2793417.36050918.2964676  18.296468   d3

Is there an easy way to do this?
Thank you very much and have a pleasant day!

Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[R] bootstrap resampling question

2011-03-01 Thread Bodnar Laszlo EB_HU

Hello there,

I have a problem concerning bootstrapping in R - especially focusing on the
resampling part of it. I try to sum it up in a simplified way so that I would
not confuse anybody.

I have a small database consisting of 20 observations (basically numbers from 1
to 20, I mean: 1, 2, 3, 4, 5, ... 18, 19, 20).

I would like to resample this database many times for the bootstrap process
with the following two conditions. The resampled databases should also have 20
observations and you can select each of the previously mentioned 20 numbers
with replacement. I guess it is obvious so far. Now the more difficult second
condition is that one number can be selected only maximum 5 times. In order to
make this clear I try to show you an example. So there can be resampled
databases like the following ones:

(1st database) 1,2,1,2,1,2,1,2,1,2,3,3,3,3,3,4,4,4,4,4
(4 different numbers are chosen, each selected 5 times)

(2nd database) 1,8,8,6,8,8,8,2,3,4,5,6,6,6,6,7,19,1,1,1
(Two numbers - 8 and 6 - selected 5 times, number 1 selected four times, the
others selected less than 4 times)

My very first guess that came to my mind whilst thinking about the problem was
the sample function where there are settings like replace=TRUE and prob=...
where you can create a probability vector i.e. how much should be the
probability of selecting a number. So I tried to calculate probabilities first.
I thought the problem can basically described as a k-combination with
repetitions. Unfortunately the only thing I could calculate so far is the total
number of all possible selections which amounts to 137 846 527 049.

Anybody knows how to implement my second tricky condition into one of the R
functions? Are 'boot' and 'bootstrap' packages capable of managing this? I
guess they are, I just couldn't figure it out yet...

Thanks very much! Best regards,
Laszlo Bodnar

Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat.
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se,
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se,
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.

This e-mail and any attached files are confidential and/...{{dropped:19}}

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[R] bootstrap resampling - simplified

2011-03-01 Thread Bodnar Laszlo EB_HU

Hello there,

I have a problem concerning bootstrapping in R - especially focusing on the 
resampling part of it. I try to sum it up in a simplified way so that I would 
not confuse anybody.

I have a small database consisting of 20 observations (basically numbers from 1 
to 20, I mean: 1, 2, 3, 4, 5, ... 18, 19, 20).

I would like to resample this database many times for the bootstrap process 
with the following conditions. Firstly, every resampled database should also 
include 20 observations. Secondly, when selecting a number from the 
above-mentioned 20 numbers, you can do this selection with replacement. The 
difficult part comes now: one number can be selected only maximum 5 times. In 
order to make this clear I show you a couple of examples. So the resampled 
databases might be like the following ones:

(1st database)  1,2,1,2,1,2,1,2,1,2,3,3,3,3,3,4,4,4,4,4
4 different numbers are chosen (1, 2, 3, 4), each selected - for the maximum 
possible - 5 times.

(2nd database)  1,8,8,6,8,8,8,2,3,4,5,6,6,6,6,7,19,1,1,1
Two numbers - 8 and 6 - selected 5 times (the maximum possible times), number 1 
selected 4 times, the others selected less than 4 times.

(3rd database)  1,1,2,2,3,3,4,4,9,9,9,10,10,13,10,9,3,9,2,1
Number 9 chosen for the maximum possible 5 times, number 10, 3, 2, 1 chosen for 
3 times, number 4 selected twice and number 13 selected only once.

...

Anybody knows how to implement my tricky condition into one of the R 
functions - that one number can be selected only 5 times at most? Are 'boot' 
and 'bootstrap' packages capable of managing this? I guess they are, I just 
couldn't figure it out yet...

Thanks very much! Best regards,
Laszlo Bodnar



Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[R] help - the condition has length 1 and only the first element will be used

2011-02-10 Thread Bodnar Laszlo EB_HU

Hello there,

I don't know if I'm addressing my question to the right e-mail address, I hope 
I do. Actually I have a little problem concerning writing a code in R. I try to 
briefly sum up my problem.

As you can see below, I created the functions Equation1 and Equation2 with 
some conditions.

  Equation1 -function(x){
 if (x=0.25) y -1-4*x
 if (x0.25)   y -0
 y
 }

  Equation2 -function(x){
 if (x=0.25)y -4*x
 if (x0.25  x=0.5)   y -2-4*x
 if (x0.5)   y -0
 y
 }

  And then I generated a sequence of numbers from 0 to 1 using the 
following code:

  x -seq(0,1,0.05)

  What I intended to do was to create 3 columns like below. In the first 
column you can find all the x values I created just before using the seq 
procedure and in the next 2 columns you can see all the calculated values of 
functions Equation1 and Equation2 respectively.

  x  Egyenlet1  Egyenlet2
  0.00  1.000.00
  0.05  0.800.20
  0.10  0.600.40
  0.15  0.400.60
  0.20  0.200.80
  0.25  0.001.00
  0.30  0.000.80
  0.35  0.000.60
  0.40  0.000.40
  0.45  0.000.20
  0.50  0.000.00
  0.55  0.000.00
  0.60  0.000.00
  0.65  0.000.00
  0.70  0.000.00
  0.75  0.000.00
  0.80  0.000.00
  0.85  0.000.00
  0.90  0.000.00
  0.95  0.000.00
  1.00  0.000.00

  Unfortunately I didn't know how to create these columns. Whenever I tried 
to send the following codes into R:
  Equation1(x) or Equation1(x) (remember x representing the values from 
0 to 1)
  ...I instantaneously got a warning message saying:

   [1]  1.0  0.8  0.6  0.4  0.2  0.0 -0.2 -0.4 -0.6 -0.8 -1.0 -1.2 -1.4 
-1.6 -1.8 -2.0 -2.2 -2.4 -2.6 -2.8 -3.0
  Warning messages:
  1: In if (x = 0.25) y - 1 - 4 * x :
the condition has length  1 and only the first element will be used
  2: In if (x  0.25) y - 0 :
the condition has length  1 and only the first element will be used

  Could somebody please help me with this? I would greatly appreciate if 
somebody would reply.
  Thank you very much and have a pleasant day!

  Best regards,
  Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

__
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[R] help - the condition has length 1 and only the first element will be used

2011-02-10 Thread Bodnar Laszlo EB_HU

Hello there,

I don't know if I'm addressing my question to the right e-mail address, I hope 
I do. Actually I have a little problem concerning writing a code in R. I try to 
briefly sum up my problem.

As you can see below, I created the functions Equation1 and Equation2 with 
some conditions.

  Equation1 -function(x){
 if (x=0.25) y -1-4*x
 if (x0.25)   y -0
 y
 }

  Equation2 -function(x){
 if (x=0.25)y -4*x
 if (x0.25  x=0.5)   y -2-4*x
 if (x0.5)   y -0
 y
 }

  And then I generated a sequence of numbers from 0 to 1 using the 
following code:

  x -seq(0,1,0.05)

  What I intended to do was to create 3 columns like below. In the first 
column you can find all the x values I created just before using the seq 
procedure and in the next 2 columns you can see all the calculated values of 
functions Equation1 and Equation2 respectively.

  x  Egyenlet1  Egyenlet2
  0.00  1.000.00
  0.05  0.800.20
  0.10  0.600.40
  0.15  0.400.60
  0.20  0.200.80
  0.25  0.001.00
  0.30  0.000.80
  0.35  0.000.60
  0.40  0.000.40
  0.45  0.000.20
  0.50  0.000.00
  0.55  0.000.00
  0.60  0.000.00
  0.65  0.000.00
  0.70  0.000.00
  0.75  0.000.00
  0.80  0.000.00
  0.85  0.000.00
  0.90  0.000.00
  0.95  0.000.00
  1.00  0.000.00

  Unfortunately I didn't know how to create these columns. Whenever I tried 
to send the following codes into R:
  Equation1(x) or Equation1(x) (remember x representing the values from 
0 to 1)
  ...I instantaneously got a warning message saying:

   [1]  1.0  0.8  0.6  0.4  0.2  0.0 -0.2 -0.4 -0.6 -0.8 -1.0 -1.2 -1.4 
-1.6 -1.8 -2.0 -2.2 -2.4 -2.6 -2.8 -3.0
  Warning messages:
  1: In if (x = 0.25) y - 1 - 4 * x :
the condition has length  1 and only the first element will be used
  2: In if (x  0.25) y - 0 :
the condition has length  1 and only the first element will be used

  Could somebody please help me with this? I would greatly appreciate if 
somebody would reply.
  Thank you very much and have a pleasant day!

  Best regards,
  Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[R] help - the condition has length 1 and only the first element will be used

2011-02-10 Thread Bodnar Laszlo EB_HU

Hi again!

I just wanted to say that during typing my message before I mistyped certain of 
characters and I was just afraid that it might spoil the understanding of my 
message. So I corrected the characters and now I'm sending you this corrected 
letter again.
Terribly sorry for my mistake.

Thank you again,
Laszlo.
-

Hello there,

I don't know if I'm addressing my question to the right e-mail address, I hope 
I do. Actually I have a little problem concerning writing a code in R. I try to 
briefly sum up my problem.

As you can see below, I created the functions Equation1 and Equation2 with 
some conditions.

  Equation1 -function(x){
 if (x=0.25) y -1-4*x
 if (x0.25)   y -0
 y
 }

  Equation2 -function(x){
 if (x=0.25)y -4*x
 if (x0.25  x=0.5)   y -2-4*x
 if (x0.5)   y -0
 y
 }

  And then I generated a sequence of numbers from 0 to 1 using the 
following code:

  x -seq(0,1,0.05)

  What I intended to do was to create 3 columns like below. In the first 
column you can find all the x values I created just before using the seq 
procedure and in the next 2 columns you can see all the calculated values of 
functions Equation1 and Equation2 respectively.

  x  Equation1  Equation2
  0.00  1.000.00
  0.05  0.800.20
  0.10  0.600.40
  0.15  0.400.60
  0.20  0.200.80
  0.25  0.001.00
  0.30  0.000.80
  0.35  0.000.60
  0.40  0.000.40
  0.45  0.000.20
  0.50  0.000.00
  0.55  0.000.00
  0.60  0.000.00
  0.65  0.000.00
  0.70  0.000.00
  0.75  0.000.00
  0.80  0.000.00
  0.85  0.000.00
  0.90  0.000.00
  0.95  0.000.00
  1.00  0.000.00

  Unfortunately I didn't know how to create these columns. Whenever I tried 
to send the following codes into R:
  Equation1(x) or Equation2(x) (remember x representing the values from 
0 to 1)
  ...I instantaneously got a warning message saying:

   [1]  1.0  0.8  0.6  0.4  0.2  0.0 -0.2 -0.4 -0.6 -0.8 -1.0 -1.2 -1.4 
-1.6 -1.8 -2.0 -2.2 -2.4 -2.6 -2.8 -3.0
  Warning messages:
  1: In if (x = 0.25) y - 1 - 4 * x :
the condition has length  1 and only the first element will be used
  2: In if (x  0.25) y - 0 :
the condition has length  1 and only the first element will be used

  Could somebody please help me with this? I would greatly appreciate if 
somebody would reply.
  Thank you very much and have a pleasant day!

  Best regards,
  Laszlo


Ez az e-mail Ã©s az Ã¶sszes hozzÃ¡ tartozÃ³ csatolt mellÃ©klet titkos Ã©s/vagy 
jogilag, szakmailag vagy mÃ¡s mÃ³don vÃ©dett informÃ¡ciÃ³t tartalmazhat. 
Amennyiben nem Ãn a levÃ©l cÃmzettje akkor a levÃ©l tartalmÃ¡nak kÃ¶zlÃ©se, 
reprodukÃ¡lÃ¡sa, mÃ¡solÃ¡sa, vagy egyÃ©b mÃ¡s Ãºton tÃ¶rtÃ©nÅ terjesztÃ©se, 
felhasznÃ¡lÃ¡sa szigorÃºan tilos. Amennyiben tÃ©vedÃ©sbÅl kapta meg ezt az 
Ã¼zenetet kÃ©rjÃ¼k azonnal Ã©rtesÃtse az Ã¼zenet kÃ¼ldÅjÃ©t. Az Erste Bank 
Hungary Zrt. (EBH) nem vÃ¡llal felelÅssÃ©get az informÃ¡ciÃ³ teljes Ã©s pontos 
- cÃmzett(ek)hez tÃ¶rtÃ©nÅ - eljuttatÃ¡sÃ¡Ã©rt, valamint semmilyen 
kÃ©sÃ©sÃ©rt, kapcsolat megszakadÃ¡sbÃ³l eredÅ hibÃ¡Ã©rt, vagy az informÃ¡ciÃ³ 
felhasznÃ¡lÃ¡sÃ¡bÃ³l vagy annak megbÃzhatatlansÃ¡gÃ¡bÃ³l eredÅ kÃ¡rÃ©rt.

Az Ã¼zenetek EBH-n kÃvÃ¼li kÃ¼ldÅje vagy cÃmzettje tudomÃ¡sul veszi Ã©s 
hozzÃ¡jÃ¡rul, hogy az Ã¼zenetekhez mÃ¡s banki alkalmazott is hozzÃ¡fÃ©rhet az 
EBH folytonos munkamenetÃ©nek biztosÃtÃ¡sa Ã©rdekÃ©ben.


This e-mail and any attached files are confidential and/...{{dropped:19}}

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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[R] help - the condition has length 1 and only the first element will be used

[R] help - the condition has length 1 and only the first element will be used

[R] help - the condition has length 1 and only the first element will be used

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