[R] Fw: Multiple Integrals

2015-08-30 Thread Shant Ch via R-help
Thank you very much to all for all your responses.

@Dr. Winsemius, E[f(X)] =f(E(X)) if f is convex. Now we know |x| is convex 
function, so clearly in this scenario if we compute the expectation of the 
((X1+X2+X3)/3-X4) and then take the absolute, then, we will get a lower bound 
of the expectation I want to find. 

  On Saturday, August 29, 2015 7:24 PM, David Winsemius 
dwinsem...@comcast.net wrote:
   

 
On Aug 29, 2015, at 11:35 AM, Shant Ch via R-help wrote:

 Hello Dr. Berry,
 
 I know the theoretical side but note we are not talking about expectation of 
 sums rather expectation of ABSOLUTE value of the function 
 (X1/3+X2/3+X3/3-X4), i.e. E|X1/3+X2/3+X3/3-X4|  , I don't think this can be 
 handled for log normal distribution by integrals by hand.
 

To Shnant Ch;

I admit to puzzlement (being a humble country doctor). Can you explain why 
there should be a difference between the absolute value of an expectation for a 
sum of values from a function, in this case dlnorm,  that is positive definite 
versus an expectation simply of the sum of such values?

-- 

David Winsemius
Alameda, CA, USA


   
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Re: [R] Multiple Integrals

2015-08-29 Thread Shant Ch via R-help
Hello Dr. Berry,

I know the theoretical side but note we are not talking about expectation of 
sums rather expectation of ABSOLUTE value of the function (X1/3+X2/3+X3/3-X4), 
i.e. E|X1/3+X2/3+X3/3-X4|  , I don#39;t think this can be handled for log 
normal distribution by integrals by hand.

Shant
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[R] Multiple Integrals

2015-08-28 Thread Shant Ch via R-help
Hello all,
For a study I want to find E|X1/3+X2/3+X3/3-X4| for variables following 
lognormal distribution. To get the value we need to use four integrals. This is 
the code which I is used

  fx-function(x){
    dlnorm(x,meanlog=2.185,sdlog=0.562)
  }
U31-integrate(function(y1) { sapply(y1, function(y1) { 
+  integrate(function(y2){  sapply(y2, function(y2) {
+  integrate(function(x1){  sapply(x1, function(x1) { 
+  integrate(function(x2)
+   abs(y1/3+y2/3+x1/3-x2)*fx(y1)*fx(y2)*fx(x1)*fx(x2),0, Inf)$value
+  })},0, Inf)$value })},0, Inf)$value})},0,Inf)$value
The error I received is the following:
Error in integrate(function(y2) { : 
  maximum number of subdivisions reached

I can understand the problem, but I am unable to figure out what can be done.. 
It would be great if you can let me know a solution to the problem so as to 
find a value for the integral.

Shant

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[R] rdagum(Library (VGAM))

2013-04-15 Thread Shant Ch
Hello!

I am working with a procedure where I need to draw one observation at a time 
from dagum distribution. I used the function defined in the VGAM library. 

when I did,
 rdagum(n=1, 0.2,1,4.5))
it says: Error in qdagum(runif(n), shape1.a = shape1.a, scale = scale, shape2.p 
= shape2.p) :   object 'Scale' not found.

In the description of dagum in R website I found that the sample size, n, that 
we need to draw using this function, should be strictly 1.

Can you please let me know what should I do in this case?

Thank you very much.
Shant
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[R] Solving the equation using uniroot

2012-03-24 Thread Shant Ch
Hello all,

I was going to solve (n-m)! * (n-k)! = 0.5 *n! * (n-m-k)!

for m when values of n and k are provided


n1-c(10,13,18,30,60,100,500)         # values of n

kx-seq(1,7,1);   # values of k


slv2-lapply(n1,function(n){

   slv1-lapply(kx,function(k){

lhs-function(m)
 {
    fnk-factorial(n-m)*factorial(n-k)-
  0.5*factorial(n-m-k)*factorial(n);
    return(fnk);
 }
 un2-uniroot(lhs,c(0,n))
 un1-un2$root/n;
   return(rbind(un1));
    });
    rjbk-data.frame(do.call(cbind,slv1));
    return(cbind(n,rjbk));
});
rj-data.frame(do.call(rbind,slv2));
rj

I used the above code, but I am getting this error, can anyone help me with 
this.


Error in uniroot(lhs, c(0, n)) : f.upper = f(upper) is NA
In addition: Warning message:
In gamma(x + 1) : NaNs produced


Thanks in advance.

Shant
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[R] Regarding as. Date function

2011-11-20 Thread Shant Ch

Hi all, 

 

I have a data set 
containing dates in the format of m/d/y starting from 1950. I wanted to 
use standard format of date R uses. So I read the data set in R and 
converted it using as.Dates. But for dates from 1950-1968, I have the 
following problem. 

as.Date(1/1/50,%m/%d/%y,origin=1900/01/01) =2050-01-01 instead of 
1950-01-01

But for dates 1969 onwards it is working fine.

as.Date(1/1/69,%m/%d/%y) = 1969-01-01


Can anyone please help me find out the problem?

Thanks
Shant
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[R] Neighbouring structure of school districts

2011-07-27 Thread Shant Ch
Hello R Users,

I wanted to find the weights and adjacency matrix of texas that can be used in 
Openbugs.

library(spdep)
library(maps)
library(maptools)

tx_shape-readShapePoly(.\\Districts_10_11.shp)
tx_nb-poly2nb(tx_shape)


There is a command called dnearneigh in spdep but is not useful here as it 
requires a set of coordinates for the whole data, but tx_shape is giving me 
coordinates for every district. 


I don't know what thing I am missing here. I would be glad if anyone can help 
with this.

Shant.
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[R] R code to extract shape polygons for any state for loading into Geobugs

2011-07-10 Thread Shant Ch
Hello R users,

I am fitting a spatio-temporal model for the areal data related to school 
districts of Texas, US using geobugs. For that I need to load the polygon shape 
file in geobugs.In Bradley Carlin's website there was an S-plus program called 
poly.S to extract polygons for  any state in the United States in the 
appropriate format for loading  into GeoBUGS which is no more now and that too 
on S. Is there any R code to extract the polygons for all school districts of a 
state in the United States or something of that type, the format which can be 
used in geobugs?

Bhargab









To: r-help@r-project.org
Sent: Thu, July 7, 2011 4:40:19 PM
Subject: [R] subset from a dataset after comparing its one column to a related 
vector

Hello R users,

I have two data sets like the following. Form of dataset:

data:

  X1   X2X3X4   X5
 1902   RE3  5949
  1903   RE3 13407
  1904   AA3  760   14
  1908   RE4 1759   18
  1909   EX2  3871
  2901   AU6 31162
  3801   AA1  304   29
3902   RE5 24826

I need to select rows of a data set based on the common observations of X1. 
Using intersect command I got the common observations of X1 from the two data 
sets as:

common=c(1902, 1904, 1908, 1909, 3801).

Using subset command I can select portions separately. But in general if I am 
given this type of dataset - data with large number of rows and also a list 
of 

X1 - common containing many elements, can anyone please let me know  how to 
select portion of the data whose X1 values are same as common values.

If any questions let me know.

Shant.
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[R] subset from a dataset after comparing its one column to a related vector

2011-07-07 Thread Shant Ch
Hello R users,

I have two data sets like the following. Form of dataset:

data:

  X1   X2X3X4   X5
 1902   RE3  5949
  1903   RE3 13407
  1904   AA3  760   14
  1908   RE4 1759   18
  1909   EX2  3871
  2901   AU6 31162
  3801   AA1  304   29
3902   RE5 24826

I need to select rows of a data set based on the common observations of X1. 
Using intersect command I got the common observations of X1 from the two data 
sets as:

common=c(1902, 1904, 1908, 1909, 3801).

Using subset command I can select portions separately. But in general if I am 
given this type of dataset - data with large number of rows and also a list 
of 
X1 - common containing many elements, can anyone please let me know  how to 
select portion of the data whose X1 values are same as common values.

If any questions let me know.

Shant.
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[R] plotting texas school district using shape files

2011-05-25 Thread Shant Ch
Hi,

I was plotting or creating a map for Texas school districts using the shape 
file 
of Texas. I could not find any other helpful mail in the mailing list.


txshp-read.shape(system.file(S:\\Districts_10_11.shp, package=maptools))

Error-  read.shape no found. But read.shape is there in maptools. 

If anyone can help me out it will be great. Thanks in advance.

Shant
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Re: [R] plotting texas school district using shape files

2011-05-25 Thread Shant Ch
Yes I had included the library(maptools) in my code, it is already installed in 
my computer. but still it is showing the same error.





From: Ben Bolker bbol...@gmail.com
To: r-h...@stat.math.ethz.ch
Sent: Wed, May 25, 2011 8:06:19 AM
Subject: Re: [R] plotting texas school district using shape files

Shant Ch sha1one at yahoo.com writes:

 
 Hi,
 
 I was plotting or creating a map for Texas school districts 
 using the shape file 
 of Texas. I could not find any other helpful mail in the mailing list.
 
 txshp-read.shape(system.file(S:\\Districts_10_11.shp, package=maptools))
 
 Error-  read.shape no found. But read.shape is there in maptools. 
 

   A couple of things: that's probably not the *exact* error you
got.  Did you remember to load the package first with library(maptools) ... ?
(You did install the package first, too, right?)
  
  After you have done that I suspect you will still have a problem with
finding the file -- I think you want something like

library(maptools)
txtshp - read.shape(S:\\Districts_10_11.shp)

  Ben Bolker

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[R] density at particular values

2010-11-20 Thread Shant Ch
Hello everyone!

I want to use density function of R to compute the density at x(=0, say). But 
it 
is giving me the 5-number summary and mean of the data and densities at that 
point. 
I just want the densities at different values specified by me. Can anyone let 
me 
know how can I find that?

For example 


Thanks in advance for your help.


Shant



  
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Re: [R] density at particular values

2010-11-20 Thread Shant Ch
David, I did look at ?density many times. I think I didn't explain what I have 
to find. 

Suppose I have a data.
x- c(rnorm(40,5,3),rcauchy(30,0,4),rexp(30,6))

Suppose I don't have information about the mixture, I have been given only the 
data. 

density(x) will give the 6 number summary of the data, given as x and also the 
6 
number summary of the density of density given as y.

I want to find the density of the given data at x=1. I basically want the value 
of y(=density) for x=1 i.e. kernel density at x=1.

Shant
 













From: David Winsemius dwinsem...@comcast.net

Cc: r-help@r-project.org
Sent: Sat, November 20, 2010 8:54:32 PM
Subject: Re: [R] density at particular values


On Nov 20, 2010, at 8:07 PM, Shant Ch wrote:

 Hello everyone!
 
 I want to use density function of R to compute the density at x(=0, say). But 
it
 is giving me the 5-number summary and mean of the data and densities at that
 point.
 I just want the densities at different values specified by me. Can anyone let 
me
 know how can I find that?

Here's what you should have done (even before posting):

?density
Read the help page to see the structure of what density() returns.
Value
x   the n coordinates of the points where the density is estimated.

y   the estimated density values. These will be non-negative, but can be zero.

Realize that the specified by me part is either going to be modified to pick 
an existing estimate near my specification or that you will need to 
approximate 
the value. So what is the actual problem (and the actual data setup) ?

--David.


 
 For example
 
 
 Thanks in advance for your help.
 
 
 Shant
 
 
 
 
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David Winsemius, MD
West Hartford, CT


  
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[R] Extending the accuracy of exp(1) in R

2010-11-09 Thread Shant Ch
Hi,

I want to use a more accurate value of exp(1).  The value given by R is 
2.718282. I want a value which has more than 15 decimal places. Can anyone let 
me know how can I increase the accuracy level.

Actually there are some large multipliers of exp(1) in my whole expression, and 
I want a more accurate result at the last step of my program, and for that I 
need to use highly accurate value of exp(1). 

Can anyone help me out? Thanks.

Shant



  
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[R] solving equation consisting of factorials

2010-10-30 Thread Shant Ch


Hi, 


I was trying to solve for m such that,

choose(n-1,k-1)+choose(n-2,k-1)+...+choose(n-m+1,k-1) - ck=0

ck is calculated by the way given in the code. Now I solved for m using uniroot 
but the error messages appeared. 

n-30
k=3
alpha-0.05
nk-choose(n,k);
ck-(nk/2)+k*nk*qnorm(1-alpha)/(12*n)# computation of ck.

lhs-function(z)
{
Smc=0;
fnk=0
for(y in 1:z)
{
   fnk[y]-choose((n-y+1),(k-1))
   Smc=Smc+fnk[y]-ck
}
return(Smc);
}
   

In order to solve the equation first I tried to find out the point near which 
lhs=0 using curve function.

curve(lhs,-70,-60)
 
Error in xy.coords(x, y, xlabel, ylabel, log) : 
  'x' and 'y' lengths differ
In addition: Warning message:
In 1:z : numerical expression has 101 elements: only the first used


 Then I computed lhs function for every z  one by one, I found that lhs changes 
its sign between (-64,-63), so I used the following uniroot function.

uniroot(lhs(-64,-63))   

Error in min(interval) : 'interval' is missing


Can anyone help me out? Thanks.

Shant


  
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[R] Solving equations involving gamma functions

2010-09-23 Thread Shant Ch
Hi,

I want to find a value of n1. I used the following code but I am getting the 
error - 


Error in as.vector(x, mode) : 
  cannot coerce type 'closure' to vector of type 'any'


n=10
a_g-(1/(n*(n-1)))*((pi/3)*(n+1)+(2*sqrt(3)*(n-2))-4*n+6)

a_s-function(n1)
{
  t1=(n1-1)/2;
  (t1*(gamma(t1)/gamma(n1/2))^2)/2-1-a_g
}
xm-solve(a_s)
 
Can anyone help me out. Thanks in advance for your help.

Shant


  
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Re: [R] Recursion problem

2010-08-22 Thread Shant Ch
Thanks Jim. Here are the following details:

I need to find the sum,
w=n*d1/2, fixed 
SUM [nCk* g(w,k)*g(w, n-k-1)].

Here the SUM is taken from k=1,2,..,n-1.

f1-exp(-t^2/(2*r*(r+1)))*G(t,r-1)

G(x,r)=integrate(f1,0,x), where G(x,0)=1

So, G(x,r) is related to G(x,r-1) by the above relation with the constraint 
G(x,0)=1.

g(x,r)= G(x,r)*exp(-x^2/(2*(r+1)))

I have described what I want to do, in the above, if any further details is 
rquired just let me know.





From: jim holtman jholt...@gmail.com

Cc: r-help@r-project.org
Sent: Sun, August 22, 2010 3:49:50 PM
Subject: Re: [R] Recursion problem

We replied once that your function Grx is not correct.  It will
recurse to an infinite depth because there is no condition to end the
calls.  I would expect that there would be some test at the beginning
of the function to see if it should be called again.  You need to
debug your function, or rewrite to compute what you want.  You have
not described the problem you are trying to solve, so no solution can
be provided.




 Hi,


 I wanted to compute the value of the function ifn at certain values of n. But 
I
 am receiving the following error when I was using the following code(given at
 the end).

 Error: evaluation nested too deeply: infinite recursion / 
options(expressions=)?

 I feel that since the function Grx is recursively related, perhaps making the
 code too complicated too handle. Can anyone let me know if there is any other
 way to handle this problem?


 d1=10.5
 Grx-function(x,r)
 {
 G0=Grx(x,0)
 G0=1;
 fu1-function(t){exp(-t^2/(2*r*(r+1)))*Grx(x,r-1)}
 return(integrate(fu1,0,x)$value)
 }

 grx-function(x,r)
 {
 Grx(x,r)*exp(-x^2/(2*(r+1)))
 }

 ifn-function(n)
 {
 w=n*d1/2;S1=0;
 for(k in  1:(n-1))
 {
  S1=S1+choose(n,k)*grx(w,k)*grx(w,n-k-1)
 }
 return(S1);
 }

 ifn(7)

 Thanks in advance.

 Shant



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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?



  
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[R] Recursion problem

2010-08-21 Thread Shant Ch


Hi,


I wanted to compute the value of the function ifn at certain values of n. But I 
am receiving the following error when I was using the following code(given at 
the end).

Error: evaluation nested too deeply: infinite recursion / options(expressions=)?
 
I feel that since the function Grx is recursively related, perhaps making the 
code too complicated too handle. Can anyone let me know if there is any other 
way to handle this problem? 


d1=10.5
Grx-function(x,r)
{
G0=Grx(x,0)
G0=1;
fu1-function(t){exp(-t^2/(2*r*(r+1)))*Grx(x,r-1)}
return(integrate(fu1,0,x)$value)
}

grx-function(x,r)
{
Grx(x,r)*exp(-x^2/(2*(r+1)))
}

ifn-function(n)
{
w=n*d1/2;S1=0;
for(k in  1:(n-1))
{
 S1=S1+choose(n,k)*grx(w,k)*grx(w,n-k-1)
}
return(S1);
}

ifn(7)

Thanks in advance.

Shant


  
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[R] handling recursion relation

2010-08-20 Thread Shant Ch
Hi,

I wanted to compute the value of the function ifn at certain values of n. But I 
am receiving the following error when I was using the following code(given at 
the end).

Error: evaluation nested too deeply: infinite recursion / options(expressions=)?
 
I feel that since the function Grx is recursively related, perhaps making the 
code too complicated too handle. Can anyone let me know if there is any other 
way to handle this problem? 


d1=10.5
Grx-function(x,r)
{
G0=Grx(x,0)
G0=1;
fu1-function(t){exp(-t^2/(2*r*(r+1)))*Grx(x,r-1)}
return(integrate(fu1,0,x)$value)
}

grx-function(x,r)
{
Grx(x)*exp(-x^2/(2*(r+1)))
}

ifn-function(n)
{
w=n*d1/2;S1=0;
for(k in 1:(n-1))
{
 S1=S1+choose(n,k)*grx(w,k)*grx(w,n-k-1)
}
return(S1);
}

ifn(5)

Thanks in advance.

Shant



  
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[R] Help in the legend()

2010-07-05 Thread Shant Ch
Hi R-users,

I was plotting the differences of the variances of the three estimators- T^(1), 
T^(2), T^(3), ofcourse taking two at a time. I was using the expression() in 
the legend function in order to show which line correspond to which of the 
difference, but the following that I had used didn't gave desired result. I 
would be grateful, if you help me out.

plot(n, pg, type=l,xlab=n,ylab=Differences of the 
variances,ylim=c(-0.0012,0.0023), xlim=c(0,60));
lines(gs,lty = 2)
lines(ps,lty=5)

legend(30, 0.0021, expression( c ( var(t^(3))-var(t^(2)), 
var(t^(2))-var(t^(1))), var(t^(3))-var(t^(1)) ) ), lty=c(1,2,5))

Thanks.
Shant


  
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Re: [R] Help in the legend()

2010-07-05 Thread Shant Ch
Thanks Dr. Winsemius. Here's the toy data set. 

Basically pg = var(t^(3))-var(t^(2), gs = var(t^(2))-var(t^(1))and   
ps=var(t^(3))-var(t^(1)). The revised code and the data set is as follows:  

n-seq(4:13)
pg-c(-1.241394e-03, -9.738079e-04, -7.158755e-04, -5.343962e-04, 
-4.088778e-04, -3.202068e-04, -2.558709e-04, -2.079914e-04, -1.715435e-04,
 -1.432430e-04)
gs-c(0.0022520038, 0.0020060234, 0.0017601434, 0.0015519810, 
0.0013810851,0.0012407732, 0.0011245410, 0.0010271681, 0.0009446642, 
0.0008740083)
ps-c( 0.0010106098, 0.0010322155, 0.0010442678, 0.0010175848, 
0.0009722074,0.0009205665, 0.0008686700, 0.0008191768, 0.0007731207, 
0.0007307653)

plot(n, pg, type=l,xlab=n,ylab=Differences of the 
variances,ylim=c(-0.0012,0.0023) );
lines(gs,lty = 2)
lines(ps,lty=5)
 
legend(30, 0.0021, expression( c ( var(t^(3))-var(t^(2)), 
var(t^(2))-var(t^(1))), var(t^(3))-var(t^(1)) ) ), lty=c(1,2,5)).




From: David Winsemius dwinsem...@comcast.net

Cc: r-help@r-project.org
Sent: Mon, July 5, 2010 9:43:19 PM
Subject: Re: [R] Help in the legend()


On Jul 5, 2010, at 8:06 PM, Shant Ch wrote:

 Hi R-users,
 
 I was plotting the differences of the variances of the three estimators- 
 T^(1), T^(2), T^(3), ofcourse taking two at a time. I was using the 
 expression() in the legend function in order to show which line correspond to 
 which of the difference, but the following that I had used didn't gave 
 desired result. I would be grateful, if you help me out.
 
 plot(n, pg, type=l,xlab=n,ylab=Differences of the 
 variances,ylim=c(-0.0012,0.0023), xlim=c(0,60));
 lines(gs,lty = 2)
 lines(ps,lty=5)
 
 legend(30, 0.0021, expression( c ( var(t^(3))-var(t^(2)), 
 var(t^(2))-var(t^(1))), var(t^(3))-var(t^(1)) ) ), lty=c(1,2,5))
 

Have you consider offering a toy set of objects which defines t, n, and 
pg.

 Thanks.
 Shant
 
 
 
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David Winsemius, MD
West Hartford, CT


  
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[R] help in expression( )

2010-06-02 Thread Shant Ch


Hi, 
I was trying to have a graph whose axes are of the following type:

X axis: n and Y axis: var[U ((a,b) in suffix, and (n,d) in the power)]. 

U ((a,b) in suffix, and (n,d) in the power)-U^(n,d) _ (a,b).
Actually I require many plots involving different values of a,b,n,d, so need to 
keep this complicated notation. 


The code I used:

plot(n, hn$h_pg,  ylab=expression(Var(U[2%,%1]^(n%,%0))-Var(U[1%,%1]^(n%,%0))), 
xlab=n,type=l);

The expression() didn't work out for this case. Can anyone help me out. 

Also due to the size of the expression in the Y axis, I want to shift the graph 
in the R Graphics window, so that the Y labels are also fully visible. i don't 
know such command which will shift the whole graph a little in the  Graphics 
window.

Thanks, in advance.
Shant



  
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[R] code for power and suffix for x,y labels in plot( ).

2010-06-01 Thread Shant Ch
Hi 

I was trying to have a graph whose axes are X axis: m, Y axis: var[X ((a,b) in 
suffix, and (n,d) in the power)]. 

X ((a,b) in suffix, and (n,d) in the power)-X^(n,d) _ (a,b).

Actually I require many plots involving different values of a,b,n,d, so need to 
keep this complicated notation. 
The expression() didn't work out for this case. Can anyone help me out. 
Thanks, in advance.
Shant






uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, 
tol = 0.001 )

While using this I am getting the following error. Can anyone please help me 
out.
Error in uniroot(function(x) x * (3^x) * log(4) - x * log(4/3) - (3^x) +  :   
f() values at end points not of opposite sign.

Thanks in advance.

Shant


  
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[R] Warning message

2010-05-09 Thread Shant Ch
Hello,

I want to draw a histogram of the mean of sample observations drawn from 
multivariate t distribution. I am getting the following error corresponding to 
the code I used. Though I am getting the graph, but I am curious to know the 
warning message.

Warning messages:
1: In if (freq) x$counts else { :
  the condition has length  1 and only the first element will be used
2: In if (!freq) Density else Frequency :
  the condition has length  1 and only the first element will be used
---
library(mvtnorm);
s12-c(1:1000);
var21-lapply(s12,function(x){
 rs-rmvt(10, sigma=diag(8), df=1);
 my-mean(rs);
 sy-sqrt(var(rs))
 return(cbind(my,sy))
});
data1-do.call(rbind,var21);
dataMat-data.frame(data1);
W-dataMat$my;
hist(W,breaks=20,probability=T)
---

Thanks.

Shant



  
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[R] Solving equation

2010-05-01 Thread Shant Ch
Hello,

I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the 
following code,

uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, 
tol = 0.001 )

While using this I am getting the following error. Can anyone please help me 
out.
Error in uniroot(function(x) x * (3^x) * log(4) - x * log(4/3) - (3^x) +  :   
f() values at end points not of opposite sign.

Thanks in advance.

Shant


  
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