[R] Generating data with a certain correlation length

2005-10-19 Thread Roy Werkman
Hi,
 
Can anyone help me with following? I want to write a program which does
following: for a 2dim surface generate random data, for certain points
on that surface, for which a certain correlation length exists. 
 
Thanx,
Roy


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[R] Forum of Mac questions (Was: loading packages - mac user)

2005-10-19 Thread Jari Oksanen
On Tue, 2005-10-18 at 13:13 -0700, Thomas Lumley wrote:

 Both for this and for working out why Tcl/Tk isn't installed you might be 
 better off trying R-sig-mac rather than r-help
 

This is a very common piece of advice. However, this is not what you
would imagine if you read the description of R-SIG-mac on the R home
page:

R-SIG-Mac R Special Interest Group on Mac Development

This is very similar to the description of R-devel:

This list is intended for questions and discussion about code
development in R.

And that description is even more intimidating when you read further:

Questions likely to prompt discussion unintelligible to non-programmers
or topics that are too technical for R-help's audience should go to
R-devel

Would it make sense to change the description of R-SIG-mac so that it
would welcome question on R usage in Mac, instead of being a Mac
Devolepment forum that sounds like being unintelligible to
non-programmers?

cheers, jari oksanen
-- 
Jari Oksanen [EMAIL PROTECTED]

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Re: [R] Forum of Mac questions (Was: loading packages - mac user)

2005-10-19 Thread Prof Brian Ripley
On Wed, 19 Oct 2005, Jari Oksanen wrote:

 On Tue, 2005-10-18 at 13:13 -0700, Thomas Lumley wrote:

 Both for this and for working out why Tcl/Tk isn't installed you might be
 better off trying R-sig-mac rather than r-help


 This is a very common piece of advice. However, this is not what you
 would imagine if you read the description of R-SIG-mac on the R home
 page:

It is not actually on the R home page or even on www.r-project.org.  I 
think you mean

https://stat.ethz.ch/mailman/listinfo/r-sig-mac

This arises because the purpose of the list has changed from

   R Special Interest Group on Macintosh Development and Porting, both for
   MacOS 8.6 - 9.x and MacOS X

I think a wording like R-sig-debian namely

   R Special Interest Group for MacOS X ports of R

would be better.

 R-SIG-Mac R Special Interest Group on Mac Development

 This is very similar to the description of R-devel:

 This list is intended for questions and discussion about code
 development in R.

 And that description is even more intimidating when you read further:

 Questions likely to prompt discussion unintelligible to non-programmers
 or topics that are too technical for R-help's audience should go to
 R-devel

 Would it make sense to change the description of R-SIG-mac so that it
 would welcome question on R usage in Mac, instead of being a Mac
 Devolepment forum that sounds like being unintelligible to
 non-programmers?

Which seems quite reasonable to me.  The topics which provoke this 
response usually are questions unintelligible except to Mac 
sysadmins/programmers and definitely `too technical for R-help's 
audience'.


-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] Unix proxy and firewall problems

2005-10-19 Thread Assa Yeroslaviz
I was trying to install R on a unix server. Because of a firewall i can't
install biocLite for working with Bioconductor.

With windows it wasn't a problem. I used the option '--internet2' to bypass the
firewall.
I don't have any idea, how to do it with unix.
I tried to set my proxy
Sys.putenv(http_proxy=http...:8080)
Sys.getenv(http_proxy)
http_proxy
http://...:8080;
http://by-cache.bayer-ag.com:8080/
but than by try to use the source command to download the bioC.R script I'm
getting the message:
source(http:/bioconductor.org/getBioC.R)
Error in file(file, r, encoding = encoding) :
unable to open connection
In addition: Warning message:
cannot open file 'http:/bioconductor.org/getBioC.R'


Is there a possibility to change the proxy setting after the programm is already
running or do i need to do it before?

THX

Assa



--
Assa Yeroslaviz
Loetzenerstr. 15
51373 Leverkusen

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[R] Wavelet recunstruction

2005-10-19 Thread Amir Safari
 
 
   Hi There,
 I tried to find a function in {waveslim} or {wavethresh} in order to 
recunstruct the decomposed signals. As far as I found there is no function in 
{waveslim} to recunstruct decomposed data. The function   wr{wavethresh} 
recunstructs the results of wd function. Apart from its limitations ( for 
example the length of vector must be power of 2 ) it apparently doesn't work 
with the functions and objects in waveslim.
What could help ?
So many thanks for your any idea.
Amir Safari


-

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Re: [R] Unix proxy and firewall problems

2005-10-19 Thread Prof Brian Ripley
From ?download.file

  These environment variables must be set before the download code
  is first used: they cannot be altered later by calling
  'Sys.putenv'.

Also, Sys.putenv(http_proxy=http...:8080) sets that to the value
in  and not the value of a variable named that: for the latter you must 
use `` quoting.  This is I suspect the actual failure cause.

On Wed, 19 Oct 2005, Assa Yeroslaviz wrote:

 I was trying to install R on a unix server. Because of a firewall i can't
 install biocLite for working with Bioconductor.

 With windows it wasn't a problem. I used the option '--internet2' to bypass 
 the
 firewall.
 I don't have any idea, how to do it with unix.
 I tried to set my proxy
 Sys.putenv(http_proxy=http...:8080)
 Sys.getenv(http_proxy)
http_proxy
 http://...:8080;
 http://by-cache.bayer-ag.com:8080/
 but than by try to use the source command to download the bioC.R script I'm
 getting the message:
 source(http:/bioconductor.org/getBioC.R)
 Error in file(file, r, encoding = encoding) :
unable to open connection
 In addition: Warning message:
 cannot open file 'http:/bioconductor.org/getBioC.R'


 Is there a possibility to change the proxy setting after the programm is 
 already
 running or do i need to do it before?

 THX

 Assa



 --
 Assa Yeroslaviz
 Loetzenerstr. 15
 51373 Leverkusen

 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html


-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] Wavelet reconstruction

2005-10-19 Thread Amir Safari
 Hi There, I tried to find a function in {waveslim} or {wavethresh} in order to 
reconstruct the decomposed signals. As far as I found there is no function in 
{waveslim} to reconstruct decomposed data. The function   wr{wavethresh} 
reconstructs the results of wd function. Apart from its limitations ( for 
example the length of vector must be power of 2 ) it apparently doesn't work 
with the functions and objects in waveslim.
What could help ?
So many thanks for your any idea.
Amir Safari



-

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[R] www.krankenversicherung.ch News - Krankenkassen - Information Newsletter

2005-10-19 Thread krankenversicherung
Guten Tag
 
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[R] error open .RData

2005-10-19 Thread Muhammad Subianto
Dear R-list,
I have a problem to open my R workspace.
When I try to open my file .Rdata with double-clik on windows explore I 
get the error like this:

Error in load(name, envir = .GlobalEnv) : error reading from connection

and on windows error:

Fatal error: unable to restore saved data in .RData

I try with,

  load(CaseStudyHouseID50.RData, .GlobalEnv)
Error in load(CaseStudyHouseID50.RData, .GlobalEnv) :
 error reading from connection
 

  load(CaseStudyHouseID50.RData)
Error in load(CaseStudyHouseID50.RData) :
 error reading from connection
 

I have done to save my R workspace like this:

   save(list = ls(all=TRUE),
file = CaseStudyHouseID50.RData)


What is wrong?
Is there anyway to open .RData?

Regards, Muhammad Subianto

  R.version
  _
platform i386-pc-mingw32
arch i386
os   mingw32
system   i386, mingw32
status
major2
minor2.0
year 2005
month10
day  06
svn rev  35749
language R
 

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[R] forrest plot

2005-10-19 Thread Michela Ballardini
Hi,

can you tel me how can I make a Forrest Plot with R? 
It is possible and easy or are there a more practical free software available?

Than you
Mic


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[R] Access to matrix values from labels

2005-10-19 Thread Toni Viúdez
Hi everybody:
I've a output interpolation matrix files, and my question is if are there 
anybody that could tell me how access to particular values of this matrix 
from labels.
Thnaks in advance.
-- 

   Antoni Viúdez Mora   
Dept. Dinámica de Contaminantes
Fundación CEAM
Paterna (Valencia)-Spain
tel: 961318190. ext: 216
 e-mail: [EMAIL PROTECTED]  [EMAIL PROTECTED]


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Re: [R] error open .RData

2005-10-19 Thread Petr Pikal
Hi

Your .Rdata file is probably corrupted. Unless you have a working 
copy of it elsewhere or sources of your data together with history 
of your commands you are probably in deep trouble .Rdata is a 
binary format and it is not recommended to safe and reliable saving 
of your work as you have only limited, if any, possibilities to 
recover it if anything goes wrong.

I usually have all my important source data in txt or xls format and 
I frequently save history in separate files (on daily basis or 
sometimes several times a day) to be able to repeat everything I 
have done.

Cheers
Petr


On 19 Oct 2005 at 11:58, Muhammad Subianto wrote:

Date sent:  Wed, 19 Oct 2005 11:58:11 +0200
From:   Muhammad Subianto [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Subject:[R] error open .RData

 Dear R-list,
 I have a problem to open my R workspace.
 When I try to open my file .Rdata with double-clik on windows explore
 I get the error like this:
 
 Error in load(name, envir = .GlobalEnv) : error reading from
 connection
 
 and on windows error:
 
 Fatal error: unable to restore saved data in .RData
 
 I try with,
 
   load(CaseStudyHouseID50.RData, .GlobalEnv)
 Error in load(CaseStudyHouseID50.RData, .GlobalEnv) :
  error reading from connection
  
 
   load(CaseStudyHouseID50.RData)
 Error in load(CaseStudyHouseID50.RData) :
  error reading from connection
  
 
 I have done to save my R workspace like this:
 ##
 ##
save(list = ls(all=TRUE),
 file = CaseStudyHouseID50.RData)
 ##
 ##
 
 What is wrong?
 Is there anyway to open .RData?
 
 Regards, Muhammad Subianto
 
   R.version
   _
 platform i386-pc-mingw32
 arch i386
 os   mingw32
 system   i386, mingw32
 status
 major2
 minor2.0
 year 2005
 month10
 day  06
 svn rev  35749
 language R
  
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide!
 http://www.R-project.org/posting-guide.html

Petr Pikal
[EMAIL PROTECTED]

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[R] FIGARCH

2005-10-19 Thread Sumanta Basak
Hi All,

 

Does R have the function for FIGARCH?

 

SUMANTA BASAK.


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Re: [R] Subsetting a list

2005-10-19 Thread John Wilkinson \(pipex\)
Dennis 

Try 

  TEST[-3]
[[1]]
[1] A1 A2

[[2]]
[1] B1 B2

for removing more than one element from the list (say 2  3) --

 TEST[-c(2,3)]
[[1]]
[1] A1 A2

HTH

John

Dennis Fisher wrote---

Colleagues,

I have created a list in the following manner:
 TEST- list(c(A1, A2), c(B1, B2), c(C1, C2))

I now want to delete one element from the list, e.g., the third.  The  
command
 TEST[[3]]
yields (as expected):
 [1] C1 C2

The command
 TEST[[-3]]
yields:
 Error: attempt to select more than one element

How can I accomplish delete one or more elements from this list?

I am running R2.2.0 on a Linux platform.

Dennis

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Re: [R] Forum of Mac questions (Was: loading packages - mac user)

2005-10-19 Thread Martin Maechler
 BDR == Prof Brian Ripley [EMAIL PROTECTED]
 on Wed, 19 Oct 2005 08:58:20 +0100 (BST) writes:

BDR On Wed, 19 Oct 2005, Jari Oksanen wrote:
 On Tue, 2005-10-18 at 13:13 -0700, Thomas Lumley wrote:
 
 Both for this and for working out why Tcl/Tk isn't
 installed you might be better off trying R-sig-mac
 rather than r-help
 
  This is a very common piece of advice. However, this is
 not what you would imagine if you read the description of
 R-SIG-mac on the R home page:

BDR It is not actually on the R home page or even on
BDR www.r-project.org.  I think you mean

BDR https://stat.ethz.ch/mailman/listinfo/r-sig-mac

BDR This arises because the purpose of the list has changed
BDR from

BDRR Special Interest Group on Macintosh Development
BDR and Porting, both for MacOS 8.6 - 9.x and MacOS X

BDR I think a wording like R-sig-debian namely

BDRR Special Interest Group for MacOS X ports of R

BDR would be better.

yes, thank you both   IFF this is really the intention.

Stefano Iacus is the maintainer (and initiator) of the list
and should say (and maybe ask on the R-SIG-Mac list) what he 
(and the subscribers) really wants.

 R-SIG-Mac R Special Interest Group on Mac Development
 
 This is very similar to the description of R-devel:
 
 This list is intended for questions and discussion about
 code development in R.
 
 And that description is even more intimidating when you
 read further:
 
 Questions likely to prompt discussion unintelligible to
 non-programmers or topics that are too technical for
 R-help's audience should go to R-devel
 
 Would it make sense to change the description of
 R-SIG-mac so that it would welcome question on R usage in
 Mac, instead of being a Mac Devolepment forum that
 sounds like being unintelligible to non-programmers?

BDR Which seems quite reasonable to me.  The topics which
BDR provoke this response usually are questions
BDR unintelligible except to Mac sysadmins/programmers and
BDR definitely `too technical for R-help's audience'.

I agree.  We shouldn't let R users on the Mac think that all
their questions should go to R-SIG-Mac.
Regular R questions should continue to come to R-help (or
R-devel) just as per the posting guide.

Martin Maechler


BDR -- Brian D. Ripley, [EMAIL PROTECTED] Professor of
BDR Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
BDR University of Oxford, Tel: +44 1865 272861 (self) 1
BDR South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG,
BDR UK Fax: +44 1865 272595

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Re: [R] forrest plot

2005-10-19 Thread Thomas Schönhoff
Hello,

2005/10/19, Michela Ballardini [EMAIL PROTECTED]:
 Hi,

 can you tel me how can I make a Forrest Plot with R?
 It is possible and easy or are there a more practical free software available?

Maybe this will help you to find an answer:

http://finzi.psych.upenn.edu/R/library/rmeta/html/metaplot.html


regards
Thomas

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Re: [R] error open .RData

2005-10-19 Thread Muhammad Subianto

  Your .Rdata file is probably corrupted.

I will investigate. Thanks for you info.
Because of my file .RData very large about 75MB.
Best wishes, Muhammad Subianto

On this day 19/10/2005 12:21 PM, Petr Pikal wrote:
 Hi
 
 Your .Rdata file is probably corrupted. Unless you have a working 
 copy of it elsewhere or sources of your data together with history 
 of your commands you are probably in deep trouble .Rdata is a 
 binary format and it is not recommended to safe and reliable saving 
 of your work as you have only limited, if any, possibilities to 
 recover it if anything goes wrong.
 
 I usually have all my important source data in txt or xls format and 
 I frequently save history in separate files (on daily basis or 
 sometimes several times a day) to be able to repeat everything I 
 have done.
 
 Cheers
 Petr
 
 
 On 19 Oct 2005 at 11:58, Muhammad Subianto wrote:
 
 Date sent:Wed, 19 Oct 2005 11:58:11 +0200
 From: Muhammad Subianto [EMAIL PROTECTED]
 To:   r-help@stat.math.ethz.ch
 Subject:  [R] error open .RData
 
 
Dear R-list,
I have a problem to open my R workspace.
When I try to open my file .Rdata with double-clik on windows explore
I get the error like this:

Error in load(name, envir = .GlobalEnv) : error reading from
connection

and on windows error:

Fatal error: unable to restore saved data in .RData

I try with,

  load(CaseStudyHouseID50.RData, .GlobalEnv)
Error in load(CaseStudyHouseID50.RData, .GlobalEnv) :
 error reading from connection
 

  load(CaseStudyHouseID50.RData)
Error in load(CaseStudyHouseID50.RData) :
 error reading from connection
 

I have done to save my R workspace like this:
##
##
   save(list = ls(all=TRUE),
file = CaseStudyHouseID50.RData)
##
##

What is wrong?
Is there anyway to open .RData?

Regards, Muhammad Subianto

  R.version
  _
platform i386-pc-mingw32
arch i386
os   mingw32
system   i386, mingw32
status
major2
minor2.0
year 2005
month10
day  06
svn rev  35749
language R
 

__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html
 
 
 Petr Pikal
 [EMAIL PROTECTED]
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html


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[R] anova with models from glmmPQL

2005-10-19 Thread Emmanuelle TASTARD
Hi !
 
I try to compare some models obtained from glmmPQL.
 
model1 -
glmmPQL(y~red*yellow+I(red^2)+I(yellow^2)+densite8+I(densite8^2)+freq8_4
+I(freq8_4^2), random=~1|num, binomial);
model2 -
glmmPQL(y~red*yellow+I(red^2)+I(yellow^2)+densite8+I(densite8^2)+freq8_4
, random=~1|num, binomial);
anova(model1, model2)
 
here is the answer :
Erreur dans anova.lme(model1, model2) : Objects must inherit from
classes gls, gnls lm,lmList, lme,nlme,nlsList, or nls
 
Yet, according to “?glmmPQL”, glmmPQL gives an object of class lme:
Value:
 A object of class 'lme': see 'lmeObject'.
 
What should I do to be able to compare my models?
 
Thank you.
Emmanuelle 
 
 
Emmanuelle TASTARD
UMR 5174 'Evolution et Diversité Biologique'  
Université Paul Sabatier Bat 4R3
31062 TOULOUSE CEDEX 9 France
tel : 05 61 55 67 59
 

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[R] Error in opening .RData containing a genefilter object

2005-10-19 Thread David Ruau
Hi,
I discover that when I save a workspace containing a genefilter (pkg 
from Bioconductor) object I cannot open no more after. I have to 
restore the .RData file from a backup to be able to start R again.
I didn't upgrade to Version 2.2 but I'm not sure that it will solve the 
problem.
Did anyone have encounter the same problem?
Below is a short r session to reproduce the error:
...
[Previously saved workspace restored]

  library(genefilter)
Loading required package: Biobase
Loading required package: tools
Welcome to Bioconductor
  Vignettes contain introductory material.  To view,
  simply type: openVignette()
  For details on reading vignettes, see
  the openVignette help page.
Loading required package: survival
Loading required package: splines
  f1 - kOverA(5, 60)
  q()
Save workspace image? [y/n/c]: y
[computer:admin]$ r

R : Copyright 2005, The R Foundation for Statistical Computing
Version 2.1.1  (2005-06-20), ISBN 3-900051-07-0

R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain conditions.
Type 'license()' or 'licence()' for distribution details.

R is a collaborative project with many contributors.
Type 'contributors()' for more information and
'citation()' on how to cite R or R packages in publications.

Type 'demo()' for some demos, 'help()' for on-line help, or
'help.start()' for a HTML browser interface to help.
Type 'q()' to quit R.

Error in .initContents() : couldn't find function isGeneric
Error: .onLoad failed in 'loadNamespace' for 'Biobase'
Fatal error: unable to restore saved data in .RData

[gaia:admin]$
---
I am working under OS X 10.3.9.

David

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[R] Help needed with ks.test

2005-10-19 Thread Emanuele Mazzola
Hello to everybody,

I'd like to submit a problem I'm dealing with, and I can't get an answer to 
by myself.
I have to test if my data come from a specific probability distribution, of 
which I know the analytic form both of the p.d.f. and the c.d.f.
Namely, it is the hypoexponential distribution, sum of two exponentials with 
different parameters.
Is there any way I can manage the task with ks.test?
It's not straightforward to compute the inverse of the c.d.f in order to 
simulate data from that distribution...

Thank you very much in advance for your kind answers!
See you
EM

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[R] how to test poisson distribution

2005-10-19 Thread Wensui Liu
Dear All,

I am wonderng how to test whether the data follows poisson distribution.

Thank you so much!

[[alternative HTML version deleted]]

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[R] Problem with na in nls

2005-10-19 Thread Florent Bresson
I'm trying to run a nls on a subset of a data.frame.
In the subset, one observation is NA. So I drop the
observation but when I ask for :

sm  -  nls(machin$revcum ~
Lc.singh(machin$popcum,p), start=list(p=c(2,3)))

I get :

Erreur dans parse(file, n, text, prompt) : syntax
error in ~ 

If I put some value for the non available observation
instead of droping it, it works. So what's the problem ?

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Re: [R] Error in opening .RData containing a genefilter object

2005-10-19 Thread Duncan Murdoch
On 10/19/2005 8:37 AM, David Ruau wrote:
 Hi,
 I discover that when I save a workspace containing a genefilter (pkg 
 from Bioconductor) object I cannot open no more after. I have to 
 restore the .RData file from a backup to be able to start R again.
 I didn't upgrade to Version 2.2 but I'm not sure that it will solve the 
 problem.
 Did anyone have encounter the same problem?
 Below is a short r session to reproduce the error:
 ...
 [Previously saved workspace restored]
 
   library(genefilter)
 Loading required package: Biobase
 Loading required package: tools
 Welcome to Bioconductor
   Vignettes contain introductory material.  To view,
   simply type: openVignette()
   For details on reading vignettes, see
   the openVignette help page.
 Loading required package: survival
 Loading required package: splines
   f1 - kOverA(5, 60)
   q()
 Save workspace image? [y/n/c]: y
 [computer:admin]$ r
 
 R : Copyright 2005, The R Foundation for Statistical Computing
 Version 2.1.1  (2005-06-20), ISBN 3-900051-07-0
 
 R is free software and comes with ABSOLUTELY NO WARRANTY.
 You are welcome to redistribute it under certain conditions.
 Type 'license()' or 'licence()' for distribution details.
 
 R is a collaborative project with many contributors.
 Type 'contributors()' for more information and
 'citation()' on how to cite R or R packages in publications.
 
 Type 'demo()' for some demos, 'help()' for on-line help, or
 'help.start()' for a HTML browser interface to help.
 Type 'q()' to quit R.
 
 Error in .initContents() : couldn't find function isGeneric
 Error: .onLoad failed in 'loadNamespace' for 'Biobase'
 Fatal error: unable to restore saved data in .RData

Looks like it might be a bug in Biobase.  I'd first confirm that it 
happens in a current release of R, then post again to the Bioconductor list.

Duncan Murdoch

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Re: [R] forrest plot

2005-10-19 Thread Romain Francois
Le 19.10.2005 13:56, Thomas Schönhoff a écrit :

Hello,

2005/10/19, Michela Ballardini [EMAIL PROTECTED]:
  

Hi,

can you tel me how can I make a Forrest Plot with R?
It is possible and easy or are there a more practical free software available?



Maybe this will help you to find an answer:

http://finzi.psych.upenn.edu/R/library/rmeta/html/metaplot.html


regards
Thomas
  

Hello Thomas,

Pretty interresting. You just pointed to a good candidate for r graph 
gallery.
A 3D plot of that kind can be done with the scatterplot3d package.

See Figure 5 page 14 of :
Ligges, U., and Maechler, M. (2003): Scatterplot3d – an R Package for 
Visualizing Multivariate Data. /Journal of Statistical Software/ 8(11), 
1–20. http://www.jstatsoft.org/

Romain

-- 
visit the R Graph Gallery : http://addictedtor.free.fr/graphiques
 ~ 
~~  Romain FRANCOIS - http://addictedtor.free.fr ~~
Etudiant  ISUP - CS3 - Industrie et Services   
~~http://www.isup.cicrp.jussieu.fr/  ~~
   Stagiaire INRIA Futurs - Equipe SELECT  
~~   http://www.inria.fr/recherche/equipes/select.fr.html~~
 ~ 

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Re: [R] Finding code for R functions

2005-10-19 Thread Roger D. Peng
If you're really interested in reading the source for functions and aren't 
interested in tracking down various methods (possibly hidden in namespaces) at 
the R prompt, I think it's much easier to download the R source code from CRAN 
and go through the original source files.

-roger

Wolfrum, Ed wrote:
 Greetings,
 
 I am trying to figure out how to find the source code for R functions. I
 am specifically interested in finding the code for the prcomp
 function. I know that typing the function name without parenthesis will
 lead to the code (or to a .Internal or .FORTRAN or .C  call). However, I
 don't really understand what is going on. For example, typing mean
 gives a UseMethod response, while typing mean.default give the
 actual code:
 
 
mean
 
 function (x, ...) 
 UseMethod(mean)
 environment: namespace:base
 
mean.default
 
 function (x, trim = 0, na.rm = FALSE, ...) 
 ---SNIP---
 }
 environment: namespace:base
 
 Why is this? What does mean.default mean? I tried the same thing with
 prcomp. With the stats package loaded, I cannot get to the source code
 for prcomp.
 
 
require(stats)
 
 [1] TRUE
 
prcomp
 
 function (x, ...) 
 UseMethod(prcomp)
 environment: namespace:stats
 
prcomp.default
 
 Error: object prcomp.default not found
  
 How do I find the prcomp code? Are there general rules for finding the
 source code for functions that I should know?
 
 Thanks in Advance,
 
 Edward J. Wolfrum, Ph.D.
 National Renewable Energy Laboratory
 Golden, Colorado
 
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-- 
Roger D. Peng
http://www.biostat.jhsph.edu/~rpeng/

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[R] npmc package

2005-10-19 Thread Carlos Mauricio Cardeal Mendes
Hi

Does anyone know where is the package: npmc (Nonparametric Multiple 
Comparisons).

I found the reference on R Site Search, but not the package itself on 
CRAN as suggested.

Thanks

Mauricio

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Re: [R] npmc package

2005-10-19 Thread Uwe Ligges
Carlos Mauricio Cardeal Mendes wrote:

 Hi
 
 Does anyone know where is the package: npmc (Nonparametric Multiple 
 Comparisons).
 
 I found the reference on R Site Search, but not the package itself on 
 CRAN as suggested.

The packages is ORPHANED and removed from the CRAN main repository. 
You can get older versions from the archives, though:

your-CRAN-mirror/src/contrib/Archive/N/npmc_1.0-1.tar.gz

Uwe Ligges

 Thanks
 
 Mauricio
 
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Re: [R] forrest plot

2005-10-19 Thread Romain Francois
Le 19.10.2005 15:11, Romain Francois a écrit :

Le 19.10.2005 13:56, Thomas Schönhoff a écrit :

Hello,

2005/10/19, Michela Ballardini [EMAIL PROTECTED]:

i,

can you tel me how can I make a Forrest Plot with R?
It is possible and easy or are there a more practical free software 
available?
  

Maybe this will help you to find an answer:

http://finzi.psych.upenn.edu/R/library/rmeta/html/metaplot.html


regards
Thomas
 



Hello Thomas,

Pretty interresting. You just pointed to a good candidate for r graph 
gallery.
(..)
  

Included. I just added :
R par(lend=square)
so it is nicer. Maybe a change to make in the function code ?

Romain

-- 
visit the R Graph Gallery : http://addictedtor.free.fr/graphiques
 ~ 
~~  Romain FRANCOIS - http://addictedtor.free.fr ~~
Etudiant  ISUP - CS3 - Industrie et Services   
~~http://www.isup.cicrp.jussieu.fr/  ~~
   Stagiaire INRIA Futurs - Equipe SELECT  
~~   http://www.inria.fr/recherche/equipes/select.fr.html~~
 ~ 

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Re: [R] anova with models from glmmPQL

2005-10-19 Thread Lorenz . Gygax
 I try to compare some models obtained from glmmPQL.
  
 model1 -
 glmmPQL(y~red*yellow+I(red^2)+I(yellow^2)+densite8+I(densite8^
 2)+freq8_4
 +I(freq8_4^2), random=~1|num, binomial);
 model2 -
 glmmPQL(y~red*yellow+I(red^2)+I(yellow^2)+densite8+I(densite8^
 2)+freq8_4
 , random=~1|num, binomial);
 anova(model1, model2)

You try to compare models that differ in their fixed parts. This is not
possible with the default method 'REML'. This would only be possible if you
fitted your models using method 'ML' (see Pinheiro  Bates, 2000).

In addition, if I understood a remark by José Pinheiro during one of his
courses correctly, the anova comparisons are not save with a distribution
other than normal. Thus, one should rely on the function intervals () to see
whether confidence intervals of the parameters overlap zero or not. Perhaps
someone else can comment on this issue?

Regards, Lorenz
- 
Lorenz Gygax
Centre for proper housing of ruminants and pigs
Swiss Federal Veterinary Office
agroscope FAT Tänikon, CH-8356 Ettenhausen / Switzerland

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Re: [R] ... Job Openings .. on R-help

2005-10-19 Thread Martin Maechler
 BertG == Berton Gunter [EMAIL PROTECTED]
 on Wed, 12 Oct 2005 10:47:40 -0700 writes:

BertG I hope that this job posting does not offend
BertG anyone. My sincere apologies if it is inappropriate
BertG -- blame me, not my company.

since you ask for it .. ;-)

BertG -- Bert Gunter
BertG Genentech Nonclinical Statistics
BertG South San Francisco, CA
 

 Genentech has an opening 
 ...
 ...
 ...

a job advertisement with a word count of  (50 352 2486) [lines,words,chars]
which is a bit too long, but ok,
but with a final paragraph which can be read as a blatant
advertisement for your company.  That (last paragraph) was not
appropriate in my opinion.

People have contacted me (as mailing list maintainer) and asked
about the appropriateness of such postings, and I've usually
explained that it is ok, as long as it remains short, is
explicitly related to R, to the
point, and refers to a URL for further information.

Hence Bert's add was close to the target.

The other anonymous add which only gave an anonymous e-mail
address for contact (see above; of course we really should
e-bomb it :-) was *VERY* inappropriate though.

Martin Maechler, ETH Zurich
as R mailing lists maintainer.

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Re: [R] Error in opening .RData containing a genefilter object

2005-10-19 Thread David Ruau
Thanks a lot Professor Ripley, it works that way.
I will upgrade to v 2.2 one day when I have time and see if it still 
happen.

David

On Oct 19, 2005, at 15:58, Prof Brian Ripley wrote:

 On Wed, 19 Oct 2005, Duncan Murdoch wrote:

 On 10/19/2005 8:37 AM, David Ruau wrote:
 Hi,
 I discover that when I save a workspace containing a genefilter (pkg
 from Bioconductor) object I cannot open no more after. I have to
 restore the .RData file from a backup to be able to start R again.
 I didn't upgrade to Version 2.2 but I'm not sure that it will solve 
 the
 problem.
 Did anyone have encounter the same problem?
 Below is a short r session to reproduce the error:
 ...
 [Previously saved workspace restored]

  library(genefilter)
 Loading required package: Biobase
 Loading required package: tools
 Welcome to Bioconductor
   Vignettes contain introductory material.  To view,
   simply type: openVignette()
   For details on reading vignettes, see
   the openVignette help page.
 Loading required package: survival
 Loading required package: splines
  f1 - kOverA(5, 60)
  q()
 Save workspace image? [y/n/c]: y
 [computer:admin]$ r

 R : Copyright 2005, The R Foundation for Statistical Computing
 Version 2.1.1  (2005-06-20), ISBN 3-900051-07-0

 R is free software and comes with ABSOLUTELY NO WARRANTY.
 You are welcome to redistribute it under certain conditions.
 Type 'license()' or 'licence()' for distribution details.

 R is a collaborative project with many contributors.
 Type 'contributors()' for more information and
 'citation()' on how to cite R or R packages in publications.

 Type 'demo()' for some demos, 'help()' for on-line help, or
 'help.start()' for a HTML browser interface to help.
 Type 'q()' to quit R.

 Error in .initContents() : couldn't find function isGeneric
 Error: .onLoad failed in 'loadNamespace' for 'Biobase'
 Fatal error: unable to restore saved data in .RData

 Looks like it might be a bug in Biobase.  I'd first confirm that it
 happens in a current release of R, then post again to the 
 Bioconductor list.

 Something in that workspace requires the Biobase namespace, and that 
 needs to import the methods namespace.  It does not in the version I 
 have.

 A solution is to use R --vanilla and then load(.RData).

 -- 
 Brian D. Ripley,  [EMAIL PROTECTED]
 Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
 University of Oxford, Tel:  +44 1865 272861 (self)
 1 South Parks Road, +44 1865 272866 (PA)
 Oxford OX1 3TG, UKFax:  +44 1865 272595


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[R] schoenfeld residuals in the cox.zph function

2005-10-19 Thread Christoph Leuchtner

To R-project help

I work with a clinical dataset including about 27,000 patients and I wanted to 
do some model diagnostics on cox regression models with frailty effects (for 
every patient). But in this case the cox.zph function did not work. I always 
got the following error message:

Fehler in residuals.coxph(fit, schoenfeld) :
NA/NaN/Inf in externem Funktionsaufruf (arg 5)

Does anyone know what's wrong? I did the same without using frailty effects and 
everything was o.k. What could I do?

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Re: [R] forrest plot

2005-10-19 Thread Thomas Lumley
On Wed, 19 Oct 2005, Romain Francois wrote:
 Pretty interresting. You just pointed to a good candidate for r graph
 gallery.

There is an example on the R home page, and has been for some time. I have 
an improved version based on grid code by Paul Murrell, but it's not on a 
nearby computer.  The other meta-analysis package also has a forest-plot 
function.

Incidentally, I was just motivated to track down whether it is Forrest 
or forest [ie for\^et], as I had assumed. Both spellings appear on 
meta-analyses, even in the top medical journals (which, unlike most 
academic journals, have moderately aggresive copy-editors).  A feedback 
archive for the  Cochrane Collaboration style guide says

The plot was not called a forest plot in print for some time, and the
  origins of this title are obscured by history and myth. At the September
  1990 meeting of the breast cancer overview, Richard Peto jokingly
  mentioned the the plot was named after the breast cancer researcher Pat
  Forrest, and, at times, the names has been spelt forrest plot.
  However, the phrase actually originates from the idea that the typical
  plot appears as a forest of lines.
  Lewis S, Clarke M. Forest plots: trying to see the wood and the trees.
  BMJ 2001;322:1479-80.


-thomas

Thomas Lumley   Assoc. Professor, Biostatistics
[EMAIL PROTECTED]   University of Washington, Seattle

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[R] diag() problem

2005-10-19 Thread Robin Hankin
Hi

I have a matrix u, for which diag() gives an error:

u - structure(c(5.42334674128216, -2.31319389204264, -5.83059042218476,
  -1.64112369640695, -2.31319389212801, 3.22737617646609,  
1.85200668021569,
  -0.57102273078531, -5.83059042231881, 1.85200668008156,  
11.9488923894962,
  -3.5525537165941, -1.64112369587405, -0.571022730886046,  
-3.55255371755604,
  10.0989829379577), .Dim = c(4, 4), .Dimnames = list(c(constant,
  NA, NA, NA), c(constant, NA, NA, NA)))

  u
   constant   NA  NA   NA
constant  5.423347 -2.3131939 -5.830590 -1.6411237
NA -2.313194  3.2273762  1.852007 -0.5710227
NA -5.830590  1.8520067 11.948892 -3.5525537
NA -1.641124 -0.5710227 -3.552554 10.0989829
  is.matrix(u)
[1] TRUE
  diag(u)
Error in if (is.list(nms)  !any(sapply(nms, is.null))  all((nm -  
nms[[1]][1:m]) ==  :
 missing value where TRUE/FALSE needed

 


What's going on here?




  R.version
  _
platform powerpc-apple-darwin8.2.0
arch powerpc
os   darwin8.2.0
system   powerpc, darwin8.2.0
status
major2
minor2.0
year 2005
month10
day  06
svn rev  35749
language R
 




--
Robin Hankin
Uncertainty Analyst
National Oceanography Centre, Southampton
European Way, Southampton SO14 3ZH, UK
  tel  023-8059-7743

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Re: [R] Problem with na in nls

2005-10-19 Thread Florence Combes
maybe you should keep your NA but deal with the na.action option of the
nls() function ?

HTH.
Florence.


On 10/19/05, Florent Bresson [EMAIL PROTECTED] wrote:

 I'm trying to run a nls on a subset of a data.frame.
 In the subset, one observation is NA. So I drop the
 observation but when I ask for :

 sm - nls(machin$revcum ~
 Lc.singh(machin$popcum,p), start=list(p=c(2,3)))

 I get :

 Erreur dans parse(file, n, text, prompt) : syntax
 error in ~ 

 If I put some value for the non available observation
 instead of droping it, it works. So what's the problem ?

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[[alternative HTML version deleted]]

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Re: [R] Subsetting a list

2005-10-19 Thread Martin Maechler
 Jose == José Ernesto Jardim [EMAIL PROTECTED]
 on Tue, 18 Oct 2005 15:30:59 +0100 writes:

Jose Dennis Fisher wrote:
 Colleagues,
 
 I have created a list in the following manner:
 TEST- list(c(A1, A2), c(B1, B2), c(C1, C2))
 
 I now want to delete one element from the list, e.g., the third.  The  
 command
 TEST[[3]]
 yields (as expected):
 [1] C1 C2
 
 The command
 TEST[[-3]]
 yields:
 Error: attempt to select more than one element
 
 How can I accomplish delete one or more elements from this list?
 
 I am running R2.2.0 on a Linux platform.
 
 Dennis
 

Jose TEST[[3]] - NULL

Jose Lists are not subsetable like data.frames or arrays, see the manuals.

yes, they are, almost, see other replies and the manuals :

Lists can have 'dim' attributes and hence be treated as arrays;
Note that this is pretty rarely used and not too well supported
by some tools, one could say even 'print()' :

 set.seed(0); L0 - L - lapply(rpois(12, lambda=3), seq); dim(L) - 3:4; L
 [,1]  [,2]  [,3]  [,4] 
[1,] Integer,5 Integer,3 Integer,5 Integer,3
[2,] Integer,2 Integer,5 Integer,6 1
[3,] Integer,2 Integer,2 Integer,4 Integer,2
 str(L)
List of 12
 $ : int [1:5] 1 2 3 4 5
 $ : int [1:2] 1 2
 $ : int [1:2] 1 2
 $ : int [1:3] 1 2 3
 $ : int [1:5] 1 2 3 4 5
 $ : int [1:2] 1 2
 $ : int [1:5] 1 2 3 4 5
 $ : int [1:6] 1 2 3 4 5 6
 $ : int [1:4] 1 2 3 4
 $ : int [1:3] 1 2 3
 $ : int 1
 $ : int [1:2] 1 2
 - attr(*, dim)= int [1:2] 3 4
 L[2,3]
[[1]]
[1] 1 2 3 4 5 6

 L[-(1:10)] ## treated matrix ``as vector''
[[1]]
[1] 1

[[2]]
[1] 1 2

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Re: [R] diag() problem

2005-10-19 Thread Ravi Varadhan
It has to do with the NAs in dimnames, but I don't know why this is a
problem.  If you either got rid of dimnames or assigned actual names, this
works fine.

Ravi.

 -Original Message-
 From: [EMAIL PROTECTED] [mailto:r-help-
 [EMAIL PROTECTED] On Behalf Of Robin Hankin
 Sent: Wednesday, October 19, 2005 10:55 AM
 To: RHelp
 Subject: [R] diag() problem
 
 Hi
 
 I have a matrix u, for which diag() gives an error:
 
 u - structure(c(5.42334674128216, -2.31319389204264, -5.83059042218476,
   -1.64112369640695, -2.31319389212801, 3.22737617646609,
 1.85200668021569,
   -0.57102273078531, -5.83059042231881, 1.85200668008156,
 11.9488923894962,
   -3.5525537165941, -1.64112369587405, -0.571022730886046,
 -3.55255371755604,
   10.0989829379577), .Dim = c(4, 4), .Dimnames = list(c(constant,
   NA, NA, NA), c(constant, NA, NA, NA)))
 
   u
constant   NA  NA   NA
 constant  5.423347 -2.3131939 -5.830590 -1.6411237
 NA -2.313194  3.2273762  1.852007 -0.5710227
 NA -5.830590  1.8520067 11.948892 -3.5525537
 NA -1.641124 -0.5710227 -3.552554 10.0989829
   is.matrix(u)
 [1] TRUE
   diag(u)
 Error in if (is.list(nms)  !any(sapply(nms, is.null))  all((nm -
 nms[[1]][1:m]) ==  :
  missing value where TRUE/FALSE needed
 
  
 
 
 What's going on here?
 
 
 
 
   R.version
   _
 platform powerpc-apple-darwin8.2.0
 arch powerpc
 os   darwin8.2.0
 system   powerpc, darwin8.2.0
 status
 major2
 minor2.0
 year 2005
 month10
 day  06
 svn rev  35749
 language R
  
 
 
 
 
 --
 Robin Hankin
 Uncertainty Analyst
 National Oceanography Centre, Southampton
 European Way, Southampton SO14 3ZH, UK
   tel  023-8059-7743
 
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Re: [R] diag() problem

2005-10-19 Thread Duncan Murdoch
On 10/19/2005 10:55 AM, Robin Hankin wrote:
 Hi
 
 I have a matrix u, for which diag() gives an error:
 
 u - structure(c(5.42334674128216, -2.31319389204264, -5.83059042218476,
   -1.64112369640695, -2.31319389212801, 3.22737617646609,  
 1.85200668021569,
   -0.57102273078531, -5.83059042231881, 1.85200668008156,  
 11.9488923894962,
   -3.5525537165941, -1.64112369587405, -0.571022730886046,  
 -3.55255371755604,
   10.0989829379577), .Dim = c(4, 4), .Dimnames = list(c(constant,
   NA, NA, NA), c(constant, NA, NA, NA)))
 
   u
constant   NA  NA   NA
 constant  5.423347 -2.3131939 -5.830590 -1.6411237
 NA -2.313194  3.2273762  1.852007 -0.5710227
 NA -5.830590  1.8520067 11.948892 -3.5525537
 NA -1.641124 -0.5710227 -3.552554 10.0989829
   is.matrix(u)
 [1] TRUE
   diag(u)
 Error in if (is.list(nms)  !any(sapply(nms, is.null))  all((nm -  
 nms[[1]][1:m]) ==  :
  missing value where TRUE/FALSE needed
 
  
 
 
 What's going on here?

It's trying to check whether the row names match the column names, in 
which case it will assign those names to the diagonal elements.  But the 
writer didn't figure someone would have NA names, so the test

all((nm - nms[[1]][1:m]) == nms[[2]][1:m])

fails.

It could be fixed by putting na.rm=TRUE into the all(), but that's 
probably not right:

  all(c(1, NA) == c(1, 2), na.rm = TRUE)
[1] TRUE

I think we want to wrap the values in paste, to convert to non-missing 
characters.  That would be

all(paste((nm - nms[[1]][1:m])) == paste(nms[[2]][1:m]))

and would give

  diag(u)
  constant  NA  NA  NA
  5.423347  3.227376 11.948892 10.098983

Any objections to me committing this change?

Duncan Murdoch

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Re: [R] diag() problem

2005-10-19 Thread Duncan Murdoch
 On 10/19/2005 10:55 AM, Robin Hankin wrote:
 
 Hi
 
 I have a matrix u, for which diag() gives an error:
 
 u - structure(c(5.42334674128216, -2.31319389204264, -5.83059042218476,
   -1.64112369640695, -2.31319389212801, 3.22737617646609,  
 1.85200668021569,
   -0.57102273078531, -5.83059042231881, 1.85200668008156,  
 11.9488923894962,
   -3.5525537165941, -1.64112369587405, -0.571022730886046,  
 -3.55255371755604,
   10.0989829379577), .Dim = c(4, 4), .Dimnames = list(c(constant,
   NA, NA, NA), c(constant, NA, NA, NA)))
 
   u
constant   NA  NA   NA
 constant  5.423347 -2.3131939 -5.830590 -1.6411237
 NA -2.313194  3.2273762  1.852007 -0.5710227
 NA -5.830590  1.8520067 11.948892 -3.5525537
 NA -1.641124 -0.5710227 -3.552554 10.0989829
   is.matrix(u)
 [1] TRUE
   diag(u)
 Error in if (is.list(nms)  !any(sapply(nms, is.null))  all((nm -  
 nms[[1]][1:m]) ==  :
  missing value where TRUE/FALSE needed
 
  
 
 
 What's going on here?
 
 
 It's trying to check whether the row names match the column names, in 
 which case it will assign those names to the diagonal elements.  But the 
 writer didn't figure someone would have NA names, so the test
 
 all((nm - nms[[1]][1:m]) == nms[[2]][1:m])
 
 fails.
 
 It could be fixed by putting na.rm=TRUE into the all(), but that's 
 probably not right:
 
   all(c(1, NA) == c(1, 2), na.rm = TRUE)
 [1] TRUE
 
 I think we want to wrap the values in paste, to convert to non-missing 
 characters.  That would be
 
 all(paste((nm - nms[[1]][1:m])) == paste(nms[[2]][1:m]))
 
 and would give
 
   diag(u)
   constant  NA  NA  NA
   5.423347  3.227376 11.948892 10.098983
 
 Any objections to me committing this change?

I object:  it can't tell the difference between the name NA and a 
missing name.  A better fix is to wrap the all() in isTRUE().  This 
leaves the names off the result (since we don't know if the rownames and 
colnames match).

Duncan Murdoch

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[R] nlme Singularity in backsolve at level 0, block 1

2005-10-19 Thread Elizabeth Lawson
Hi,
 
I am hoping some one can help with this.
 
I am using nlme to fit a random coefficients model. It ran for hours before 
returning 
 
Error: Singularity in backsolve at level 0, block 1

The model is 
 plavix.nlme-nlme(PLX_NRX~loglike(PLX_NRX,PD4_42D,GAT_34D,VIS_42D,MSL_42D,SPE_ROL,XM2_DUM,THX_DUM,b0,b1,b2,b3,b4,b5,b6,b7,alpha),
+ data=data,
+ fixed=list(b0 + b1+b2+b3+b4+b5+b6+b7+alpha~1),
+ random=b0+b1+b2+b3+b4+b5+b6+b7~1|menum,
+ 
+ start=c(b0=0,b1=0,b2=0,b3=0,b4=0,b5=0,b6=0,b7=0,alpha=5)
+ )

Can anyone tell me what this error means and how I can run the model?
 
Thanks,
 
Elizabeth Lawson


-

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Re: [R] diag() problem

2005-10-19 Thread Prof Brian Ripley
On Wed, 19 Oct 2005, Duncan Murdoch wrote:

 On 10/19/2005 10:55 AM, Robin Hankin wrote:
 Hi

 I have a matrix u, for which diag() gives an error:

 u - structure(c(5.42334674128216, -2.31319389204264, -5.83059042218476,
   -1.64112369640695, -2.31319389212801, 3.22737617646609,
 1.85200668021569,
   -0.57102273078531, -5.83059042231881, 1.85200668008156,
 11.9488923894962,
   -3.5525537165941, -1.64112369587405, -0.571022730886046,
 -3.55255371755604,
   10.0989829379577), .Dim = c(4, 4), .Dimnames = list(c(constant,
   NA, NA, NA), c(constant, NA, NA, NA)))

  u
constant   NA  NA   NA
 constant  5.423347 -2.3131939 -5.830590 -1.6411237
 NA -2.313194  3.2273762  1.852007 -0.5710227
 NA -5.830590  1.8520067 11.948892 -3.5525537
 NA -1.641124 -0.5710227 -3.552554 10.0989829
  is.matrix(u)
 [1] TRUE
  diag(u)
 Error in if (is.list(nms)  !any(sapply(nms, is.null))  all((nm -
 nms[[1]][1:m]) ==  :
  missing value where TRUE/FALSE needed

 


 What's going on here?

 It's trying to check whether the row names match the column names, in
 which case it will assign those names to the diagonal elements.  But the
 writer didn't figure someone would have NA names, so the test

 all((nm - nms[[1]][1:m]) == nms[[2]][1:m])

 fails.

 It could be fixed by putting na.rm=TRUE into the all(), but that's
 probably not right:

  all(c(1, NA) == c(1, 2), na.rm = TRUE)
 [1] TRUE

 I think we want to wrap the values in paste, to convert to non-missing
 characters.  That would be

 all(paste((nm - nms[[1]][1:m])) == paste(nms[[2]][1:m]))

 and would give

  diag(u)
  constant  NA  NA  NA
  5.423347  3.227376 11.948892 10.098983

 Any objections to me committing this change?

Yes, you don't want NA to match NA.

If you think NA names should match, use identical.   Otherwise (and I 
think this would be more consistent with other parts of R), do something
like

eq - (nm - nms[[1]][1:m]) == nms[[2]][1:m]
if(all(!is.na(eq)  eq)) ...

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] diag() problem

2005-10-19 Thread Duncan Murdoch
On 10/19/2005 11:37 AM, Prof Brian Ripley wrote:
 On Wed, 19 Oct 2005, Duncan Murdoch wrote:
 
 On 10/19/2005 10:55 AM, Robin Hankin wrote:
 Hi

 I have a matrix u, for which diag() gives an error:

 u - structure(c(5.42334674128216, -2.31319389204264, -5.83059042218476,
   -1.64112369640695, -2.31319389212801, 3.22737617646609,
 1.85200668021569,
   -0.57102273078531, -5.83059042231881, 1.85200668008156,
 11.9488923894962,
   -3.5525537165941, -1.64112369587405, -0.571022730886046,
 -3.55255371755604,
   10.0989829379577), .Dim = c(4, 4), .Dimnames = list(c(constant,
   NA, NA, NA), c(constant, NA, NA, NA)))

  u
constant   NA  NA   NA
 constant  5.423347 -2.3131939 -5.830590 -1.6411237
 NA -2.313194  3.2273762  1.852007 -0.5710227
 NA -5.830590  1.8520067 11.948892 -3.5525537
 NA -1.641124 -0.5710227 -3.552554 10.0989829
  is.matrix(u)
 [1] TRUE
  diag(u)
 Error in if (is.list(nms)  !any(sapply(nms, is.null))  all((nm -
 nms[[1]][1:m]) ==  :
  missing value where TRUE/FALSE needed

 


 What's going on here?

 It's trying to check whether the row names match the column names, in
 which case it will assign those names to the diagonal elements.  But the
 writer didn't figure someone would have NA names, so the test

 all((nm - nms[[1]][1:m]) == nms[[2]][1:m])

 fails.

 It could be fixed by putting na.rm=TRUE into the all(), but that's
 probably not right:

  all(c(1, NA) == c(1, 2), na.rm = TRUE)
 [1] TRUE

 I think we want to wrap the values in paste, to convert to non-missing
 characters.  That would be

 all(paste((nm - nms[[1]][1:m])) == paste(nms[[2]][1:m]))

 and would give

  diag(u)
  constant  NA  NA  NA
  5.423347  3.227376 11.948892 10.098983

 Any objections to me committing this change?
 
 Yes, you don't want NA to match NA.
 
 If you think NA names should match, use identical.   Otherwise (and I 
 think this would be more consistent with other parts of R), do something
 like
 
 eq - (nm - nms[[1]][1:m]) == nms[[2]][1:m]
 if(all(!is.na(eq)  eq)) ...
 

I agree with your objection; I realized the same thing just after I 
posted my original.  The solution I came up with was putting the all() 
in isTRUE().  I think that achieves an identical result to your solution.

Can you see any reason to prefer one over the other?

Duncan Murdoch

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Re: [R] Lattice graphics strip labels for shingles

2005-10-19 Thread Deepayan Sarkar
On 10/18/05, Kiermeier, Andreas (PIRSA - SARDI)
[EMAIL PROTECTED] wrote:
 Dear all,

 back in 2002 Martin Henry H. Stevens wrote
 (https://stat.ethz.ch/pipermail/r-help/2002-May/019851.html)

  How do I control the text in strips? Specifically, I want to put in the
  ranges generated in shingle(x) where x is continuous.

 with an answer from Deepyan Sarkar (see strip.new towards the end of this
 message).  I assume that the answer worked back then, but I've tried to
 implement it today, with little success.  I think that it may have to do
 with namespaces - but I'm not sure.

It does have to do with namespaces. grid.rect etc are in the grid
namespace which is not attached when you are calling strip.new. The
simplest solution is to attach it first, e.g. by

library(grid)

(or put 'require(grid)' inside strip.new).

Deepayan

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Re: [R] how to test poisson distribution

2005-10-19 Thread Thomas Schönhoff
Hi,


2005/10/19, Wensui Liu [EMAIL PROTECTED]:
 Dear All,

 I am wonderng how to test whether the data follows poisson distribution.

 Thank you so much!

Did you notice the PDF on distribution tests using R by Vito Ricci,
its found at CRAN in the docs contrib section, called FITTING
DISTRIBUTIONS WITH R

Maybe this could be of some help for you, especially look at page 7
(poisson dsitribution example).

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Re: [R] how to test poisson distribution

2005-10-19 Thread Berton Gunter
To be pedantic (I'm feeling cranky today):

One can never test whether the data follow [data is plural] a Poisson
distribution -- only whether there is sufficient evidence to cast that
assumption into doubt. Perhaps a better shorthand is whether the data are
consistent with Poisonness . This correctly leaves open the possibility
that the data are consistent with lots of other distribution-nesses, too. I
welcome alternatives, perhaps privately to reduce the list noise level.

(And,yes, I'm sure that Thomas knows this perfectly well).

I do think that we should be a bit less sloppy about such things even here,
lest we continue to promulgate already widespread misunderstandings, even at
the cost of slightly increased bandwidth. After all, precision is supposed
to be a major concern or ours.

As I've been cranky, others are free to return the favor. Sauce for the
goose ...

-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
 
The business of the statistician is to catalyze the scientific learning
process.  - George E. P. Box
 
 

 -Original Message-
 From: [EMAIL PROTECTED] 
 [mailto:[EMAIL PROTECTED] On Behalf Of Thomas 
 Schönhoff
 Sent: Wednesday, October 19, 2005 10:00 AM
 To: r-help@stat.math.ethz.ch
 Subject: Re: [R] how to test poisson distribution
 
 Hi,
 
 
 2005/10/19, Wensui Liu [EMAIL PROTECTED]:
  Dear All,
 
  I am wonderng how to test whether the data follows poisson 
 distribution.
 
  Thank you so much!
 
 Did you notice the PDF on distribution tests using R by Vito Ricci,
 its found at CRAN in the docs contrib section, called FITTING
 DISTRIBUTIONS WITH R
 
 Maybe this could be of some help for you, especially look at page 7
 (poisson dsitribution example).
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
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 http://www.R-project.org/posting-guide.html


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[R] matching two plots

2005-10-19 Thread Rui Cardoso
Hi,

I have a problem about graphics. I would like to plot two graphs: a barplot 
and curve. Here is the code:

  barplot(dpois(0:45,20),xlim=c(0,45),names=0:45)
  curve(dnorm(x,20,sqrt(20)),from=0,to=45,add=T)

Both graphs are drawn in the same figure, however the scale in both graphs 
dooes not match. For some reason the second plot is shifted to left. I 
think there is a problem concerning the axis scale.

Thanks a lot.

Rui

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Re: [R] how to test poisson distribution

2005-10-19 Thread Achim Zeileis
On Wed, 19 Oct 2005 10:18:02 -0700 Berton Gunter wrote:

 To be pedantic (I'm feeling cranky today):
 
 One can never test whether the data follow [data is plural] a
 Poisson distribution -- only whether there is sufficient evidence to
 cast that assumption into doubt. Perhaps a better shorthand is
 whether the data are consistent with Poisonness . This correctly
 leaves open the possibility that the data are consistent with lots of
 other distribution-nesses, too. I welcome alternatives, perhaps
 privately to reduce the list noise level.

...now that Berton mentioned `checking distribution-nesses': the
function distplot() in the package vcd implements various plots for
distribution-nesses that can be used for graphical checking. Ord_plot()
is made for a similar purpose.
Finally, there is also a function goodfit() that computes
goodness-of-fit tests for such hypotheses.

All three functions are written following Chapter 2 `Fitting and
Graphing Discrete Distributions' in Michael Friendly's book `Visualizing
Categorical Data'.

hth,
Z

 (And,yes, I'm sure that Thomas knows this perfectly well).
 
 I do think that we should be a bit less sloppy about such things even
 here, lest we continue to promulgate already widespread
 misunderstandings, even at the cost of slightly increased bandwidth.
 After all, precision is supposed to be a major concern or ours.
 
 As I've been cranky, others are free to return the favor. Sauce for
 the goose ...
 
 -- Bert Gunter
 Genentech Non-Clinical Statistics
 South San Francisco, CA
  
 The business of the statistician is to catalyze the scientific
 learning process.  - George E. P. Box
  
  
 
  -Original Message-
  From: [EMAIL PROTECTED] 
  [mailto:[EMAIL PROTECTED] On Behalf Of Thomas 
  Schönhoff
  Sent: Wednesday, October 19, 2005 10:00 AM
  To: r-help@stat.math.ethz.ch
  Subject: Re: [R] how to test poisson distribution
  
  Hi,
  
  
  2005/10/19, Wensui Liu [EMAIL PROTECTED]:
   Dear All,
  
   I am wonderng how to test whether the data follows poisson 
  distribution.
  
   Thank you so much!
  
  Did you notice the PDF on distribution tests using R by Vito Ricci,
  its found at CRAN in the docs contrib section, called FITTING
  DISTRIBUTIONS WITH R
  
  Maybe this could be of some help for you, especially look at page 7
  (poisson dsitribution example).
  
  __
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  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide! 
  http://www.R-project.org/posting-guide.html
 
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
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 http://www.R-project.org/posting-guide.html


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Re: [R] Subsetting a list

2005-10-19 Thread Vincent Goulet
Le 19 Octobre 2005 11:09, Martin Maechler a écrit :

[...]

 Lists can have 'dim' attributes and hence be treated as arrays;

For me, this is an amazing feature that I discovered almost by accident (I 
tried it an it worked)! This creates a sort of three-dimensional object --- 
much like an array --- where the third dimension is of varying length. Wow.

I agree, though, that the result of 'print' on such an object is not crystal 
clear (but does make sense).

[...]

-- 
  Vincent Goulet, Associate Professor
  École d'actuariat
  Université Laval, Québec 
  [EMAIL PROTECTED]   http://vgoulet.act.ulaval.ca

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Re: [R] npmc package

2005-10-19 Thread Carlos Mauricio Cardeal Mendes
So, is there another package to substitute those functions described on 
ORPHANED npmc package ?

Regards,
Mauricio
Brazil

Uwe Ligges escreveu:

 Carlos Mauricio Cardeal Mendes wrote:

 Hi

 Does anyone know where is the package: npmc (Nonparametric Multiple 
 Comparisons).

 I found the reference on R Site Search, but not the package itself on 
 CRAN as suggested.


 The packages is ORPHANED and removed from the CRAN main repository. 
 You can get older versions from the archives, though:

 your-CRAN-mirror/src/contrib/Archive/N/npmc_1.0-1.tar.gz

 Uwe Ligges

 Thanks

 Mauricio

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[R] how to compare a null model with a model with NAs?

2005-10-19 Thread Ronaldo Reis-Jr.
Hi,

I make a model:

m.null - glm(y~1)

m.comp - glm(y~x1+x2+x3)

I try make a anova like this

anova(m.null,m.comp,test=F)

The result:

Erro em anova.glmlist(c(list(object), dotargs), dispersion = dispersion,  : 
models were not all fitted to the same size of dataset

The problem is that I have some NAs in x1, x2 and x3 and is not teh same row 
fo NAs. How to set is in a null model without I need to remove these rows?

Thansk
Ronaldo
-- 
Quem cedo madruga, fica com sono o dia todo.
--
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|  V  [UFV/DBA-Entomologia]
|/ \   [36570-000 Viçosa - MG  ]
|  /(.''`.)\  [Fone: 31-3899-4007 ]
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[R] Range plots (lattice or base?)

2005-10-19 Thread Mike Bock
I am looking to create what I would call a simple variation on the
boxplot. What I would like to do is to be able to plot the upper and
lower confidence limits as the box and the 10th and 90th percentile as
the whiskers. What I have done is write the code to create a dataframe,
the columns of which are the mean, sd, 10th percentile, 90th percentile,
lower confidence limit of the mean, and upper confidence limit of the
mean, the rows are the groups. I have exported this to excel and get the
graph I want by using the stock graphs in excel that plot open, close,
high and low but I would much prefer to do this in R for reason too
numerous to enumerate.

I have looked high and low and even took a brief look at the bwplot code
in the lattice package.  Given my experience level it would take quite a
while for me to modify the bwplot code to get what I want and create a
new graph type, assuming I could get it to work at all. Does anyone know
of an easier way to get what I want, with and example? Lattice, grid,
base, whatever, I don't especially care what tools I need to use. My
only constrante is that I feed it the values required as a dataframe
rather than calculate it on the fly so if we change our minds about UCL
method or percentiles there is no problem.

Thanks in advance,
Mike


Michael Bock PhD
ENVIRON International Corporation
136 Commerical Street, Suite 402
Portland, ME 04101
phone: not active yet
fax: not active yet


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Re: [R] Range plots (lattice or base?)

2005-10-19 Thread Paul Murrell
Hi


Mike Bock wrote:
 I am looking to create what I would call a simple variation on the
 boxplot. What I would like to do is to be able to plot the upper and
 lower confidence limits as the box and the 10th and 90th percentile as
 the whiskers. What I have done is write the code to create a dataframe,
 the columns of which are the mean, sd, 10th percentile, 90th percentile,
 lower confidence limit of the mean, and upper confidence limit of the
 mean, the rows are the groups. I have exported this to excel and get the
 graph I want by using the stock graphs in excel that plot open, close,
 high and low but I would much prefer to do this in R for reason too
 numerous to enumerate.
 
 I have looked high and low and even took a brief look at the bwplot code
 in the lattice package.  Given my experience level it would take quite a
 while for me to modify the bwplot code to get what I want and create a
 new graph type, assuming I could get it to work at all. Does anyone know
 of an easier way to get what I want, with and example? Lattice, grid,
 base, whatever, I don't especially care what tools I need to use. My
 only constrante is that I feed it the values required as a dataframe
 rather than calculate it on the fly so if we change our minds about UCL
 method or percentiles there is no problem.


Can you put the Excel-generated version up somewhere for us to see the 
final output you want?  Then we could make some specific suggestions.

Paul
-- 
Dr Paul Murrell
Department of Statistics
The University of Auckland
Private Bag 92019
Auckland
New Zealand
64 9 3737599 x85392
[EMAIL PROTECTED]
http://www.stat.auckland.ac.nz/~paul/

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Re: [R] error open .RData

2005-10-19 Thread Horacio Montenegro

 hi

 It seems that, in some cases, saving a .RData
containing objects from some packages and later trying
to start R (or load the .RData) before loading the
package could cause this error. See

http://finzi.psych.upenn.edu/R/Rhelp02a/archive/46910.html

 If the .RData contains objects from some specific
packages, try loading the package first and then load
the .RData file.

 Also, RSiteSearch(.RData corrupted) results in
lots of hits.

 hope this helps,
 horacio montenegro

--- Muhammad Subianto [EMAIL PROTECTED] wrote:

 Dear R-list,
 I have a problem to open my R workspace.
 When I try to open my file .Rdata with double-clik
 on windows explore I 
 get the error like this:
 
 Error in load(name, envir = .GlobalEnv) : error
 reading from connection
 
 and on windows error:
 
 Fatal error: unable to restore saved data in .RData
 
 I try with,
 
   load(CaseStudyHouseID50.RData, .GlobalEnv)
 Error in load(CaseStudyHouseID50.RData,
 .GlobalEnv) :
  error reading from connection
  
 
   load(CaseStudyHouseID50.RData)
 Error in load(CaseStudyHouseID50.RData) :
  error reading from connection
  
 
 I have done to save my R workspace like this:


save(list = ls(all=TRUE),
 file = CaseStudyHouseID50.RData)


 
 What is wrong?
 Is there anyway to open .RData?
 
 Regards, Muhammad Subianto
 


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Re: [R] Range plots (lattice or base?)

2005-10-19 Thread Mike Bock

The first example on this page is pretty close to what I want, but the
x-axis would be a category (like location), and the true range
anotations are left out. I don't; have a place to post but can e-mail a
pdf of my excel version by request.


http://www.stockcharts.com/education/IndicatorAnalysis/indic_ATR.html

Mike


 -Original Message-
 From: Paul Murrell [mailto:[EMAIL PROTECTED] 
 Sent: Wednesday, October 19, 2005 3:04 PM
 To: Mike Bock
 Cc: r-help@stat.math.ethz.ch
 Subject: Re: [R] Range plots (lattice or base?)
 
 
 Hi
 
Delete orginal message for brevity
 
 Can you put the Excel-generated version up somewhere for us 
 to see the 
 final output you want?  Then we could make some specific suggestions.
 
 Paul
 -- 
 Dr Paul Murrell
 Department of Statistics
 The University of Auckland
 Private Bag 92019
 Auckland
 New Zealand
 64 9 3737599 x85392
 [EMAIL PROTECTED]
 http://www.stat.auckland.ac.nz/~paul/
 


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Re: [R] Range plots (lattice or base?)

2005-10-19 Thread Greg Snow
Using base graphics you can use the bxp function.  This is what 
boxplot calls to do the actual plotting.  Look at the return value
for boxplot in the help for boxplot to see the form of the data
that needs to be passed to bxp (also look at the help for bxp)
You could write a simple function that takes your data frame
and extracts the appropriate numbers into a matrix within a list
to pass to bxp.

hope this helps,

Greg Snow, Ph.D.
Statistical Data Center, LDS Hospital
Intermountain Health Care
[EMAIL PROTECTED]
(801) 408-8111

 Mike Bock [EMAIL PROTECTED] 10/19/05 12:53PM 
I am looking to create what I would call a simple variation on the
boxplot. What I would like to do is to be able to plot the upper and
lower confidence limits as the box and the 10th and 90th percentile
as
the whiskers. What I have done is write the code to create a
dataframe,
the columns of which are the mean, sd, 10th percentile, 90th
percentile,
lower confidence limit of the mean, and upper confidence limit of the
mean, the rows are the groups. I have exported this to excel and get
the
graph I want by using the stock graphs in excel that plot open, close,
high and low but I would much prefer to do this in R for reason too
numerous to enumerate.

I have looked high and low and even took a brief look at the bwplot
code
in the lattice package.  Given my experience level it would take quite
a
while for me to modify the bwplot code to get what I want and create a
new graph type, assuming I could get it to work at all. Does anyone
know
of an easier way to get what I want, with and example? Lattice, grid,
base, whatever, I don't especially care what tools I need to use. My
only constrante is that I feed it the values required as a dataframe
rather than calculate it on the fly so if we change our minds about
UCL
method or percentiles there is no problem.

Thanks in advance,
Mike


Michael Bock PhD
ENVIRON International Corporation
136 Commerical Street, Suite 402
Portland, ME 04101
phone: not active yet
fax: not active yet


[[alternative HTML version deleted]]

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Re: [R] Range plots (lattice or base?)

2005-10-19 Thread Deepayan Sarkar


On 10/19/05, Mike Bock [EMAIL PROTECTED] wrote:
 I am looking to create what I would call a simple variation on the
 boxplot. What I would like to do is to be able to plot the upper and
 lower confidence limits as the box and the 10th and 90th percentile as
 the whiskers. What I have done is write the code to create a dataframe,
 the columns of which are the mean, sd, 10th percentile, 90th percentile,
 lower confidence limit of the mean, and upper confidence limit of the
 mean, the rows are the groups. I have exported this to excel and get the
 graph I want by using the stock graphs in excel that plot open, close,
 high and low but I would much prefer to do this in R for reason too
 numerous to enumerate.
 
 I have looked high and low and even took a brief look at the bwplot code
 in the lattice package.  Given my experience level it would take quite a
 while for me to modify the bwplot code to get what I want and create a
 new graph type, assuming I could get it to work at all. Does anyone know
 of an easier way to get what I want, with and example? Lattice, grid,
 base, whatever, I don't especially care what tools I need to use. My
 only constrante is that I feed it the values required as a dataframe
 rather than calculate it on the fly so if we change our minds about UCL
 method or percentiles there is no problem.

Is your UCL method guaranteed to work separately on groups (e.g. if the s.d. is 
estimated per group) or does it share information across groups (e.g. some sort 
of pooled estimate of s.d.)? In the former case, you could try writing a 
replacement for boxplot.stats and use that in panel.bwplot.

Deepayan

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Re: [R] matching two plots

2005-10-19 Thread Romain Francois
Le 19.10.2005 19:27, Rui Cardoso a écrit :

Hi,

I have a problem about graphics. I would like to plot two graphs: a barplot 
and curve. Here is the code:

  barplot(dpois(0:45,20),xlim=c(0,45),names=0:45)
  curve(dnorm(x,20,sqrt(20)),from=0,to=45,add=T)

Both graphs are drawn in the same figure, however the scale in both graphs 
dooes not match. For some reason the second plot is shifted to left. I 
think there is a problem concerning the axis scale.

Thanks a lot.

Rui
  

Hello,

The problem is barplot. To see that :

R (barplot(dpois(0:45,20),xlim=c(0,45),names=0:45))
R axis(3)

Try something like :

R plot(0:45, dpois(0:45,20), type=h, lwd=4, col=gray)
R curve(dnorm(x,20,sqrt(20)),from=0,to=45,add=T)

Romain

-- 
visit the R Graph Gallery : http://addictedtor.free.fr/graphiques
 ~ 
~~  Romain FRANCOIS - http://francoisromain.free.fr  ~~
   Doctorant INRIA Futurs / EDF
 ~ 

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Re: [R] matching two plots

2005-10-19 Thread Marc Schwartz (via MN)
On Wed, 2005-10-19 at 18:27 +0100, Rui Cardoso wrote:
 Hi,
 
 I have a problem about graphics. I would like to plot two graphs: a barplot 
 and curve. Here is the code:
 
   barplot(dpois(0:45,20),xlim=c(0,45),names=0:45)
   curve(dnorm(x,20,sqrt(20)),from=0,to=45,add=T)
 
 Both graphs are drawn in the same figure, however the scale in both graphs 
 dooes not match. For some reason the second plot is shifted to left. I 
 think there is a problem concerning the axis scale.
 
 Thanks a lot.
 
 Rui


This came up this past summer and Gabor and I had a couple of different
approaches to the solution. You can see the posts here:

http://finzi.psych.upenn.edu/R/Rhelp02a/archive/57431.html

and

http://finzi.psych.upenn.edu/R/Rhelp02a/archive/57432.html


Using my approach with barplot(), what you need to do is to set the
'space' argument to 0 so that there is no space between the bars. This
will then place the bar centers at increments of 0.5, in your case
seq(0.5, 45.5, 5).

Knowing this, you can then adjust the x axis position in curve() by +0.5
to coincide with the bars. So you end up with this:

barplot(dpois(0:45, 20), names = 0:45, space = 0, ylim = c(0, .1))
curve(dnorm(x, 20 + 0.5, sqrt(20)), add = TRUE)

HTH,

Marc Schwartz

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[R] Automatic rounding of values after factors , converted to numeric, are multipled by a real number

2005-10-19 Thread Nelson, Gary \(FWE\)
I am wondering if someone would have any suggestion about my issue?


I have the following code:

wgts-aggregate(subset(lendata,select=c(Length)),list(lendata$Cruise,len
data$Station,lendata$Region,lendata$Total),mean)
wgts-wgts[order(wgts$Group.3,wgts$Group.1,wgts$Group.1),]
names(wgts)-c(Cruise,Station,Region,Total,MLen)
wgts$Total-as.numeric(levels(wgts$Total))[wgts$Total]
wgts$swmean-with(wgts,wgts$Total*wgts$MLen) 

When I run it, I get:
   Cruise Station Region Total MLen swmean
32350 256  1 2 70.5141
52350 254  1 3 73.3220
62350 287  1 3 65.7197
92350 232  1 4 75.25000301
10   2350 294  1 4 56.0224
12   2350 301  1 5 70.2351
14   2350 316  1 6 67.3404
15   2350 255  1 7 55.0385
17   2350 285  1 8 73.5588
19   2350 212  110 57.5575
20   2350 250  110 61.5615
27   2350 221  124 95.29167   2287
33   2350 229  135 55.62857   1947
37   2350 293  147 53.82979   2530
38   2350 203  150 55.54000   2777
39   2350 248  155 63.30909   3482
41   2350 246  163 95.82540   6037
42   2350 265  168 55.54412   3777
43   2350 251  182 62.60976   5134
44   2350 234  185 57.21176   4863

Every value is correct except that the swmeans are rounded and I can't
get values with the decimals fractions.  I have tried as.double and have
change the options(digits=7), but nothing seems to work. I have spent
several hours combing manuals and archives. 

Any suggestions would be appreciated.

*
Gary A. Nelson
Massachusetts Division of Marine Fisheries
30 Emerson Avenue
Gloucester, MA 01930
Phone: (978) 282-0308 x114
Fax: (617) 727-3337
Email: [EMAIL PROTECTED]

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[R] Weights in survReg

2005-10-19 Thread Alexander Antonyuk
Dear R users,

I am trying to find out what the function survReg does exactly with the 
Weights parameters. I looked in Terry Therneau documentations and other 
places and couldn't find anything. I tried to make an analogy with weighted 
OLS and assumed that the scale parameter Sigma in the accelerated 
failure-time model log(Time)= X*betas +Sigma*E, is of the form Sigma(i) = 
Sigma/Weights(i).

Can anyone confirm that or point me in the direction where I can find out 
for sure?

Thank you,
Sasha

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Re: [R] Forum of Mac questions (Was: loading packages - mac user)

2005-10-19 Thread stefano iacus

On 19/ott/05, at 13:36, Martin Maechler wrote:

 BDR == Prof Brian Ripley [EMAIL PROTECTED]
 on Wed, 19 Oct 2005 08:58:20 +0100 (BST) writes:


 BDR On Wed, 19 Oct 2005, Jari Oksanen wrote:

 On Tue, 2005-10-18 at 13:13 -0700, Thomas Lumley wrote:


 Both for this and for working out why Tcl/Tk isn't
 installed you might be better off trying R-sig-mac
 rather than r-help


  This is a very common piece of advice. However, this is
 not what you would imagine if you read the description of
 R-SIG-mac on the R home page:


 BDR It is not actually on the R home page or even on
 BDR www.r-project.org.  I think you mean

 BDR https://stat.ethz.ch/mailman/listinfo/r-sig-mac

 BDR This arises because the purpose of the list has changed
 BDR from

 BDRR Special Interest Group on Macintosh Development
 BDR and Porting, both for MacOS 8.6 - 9.x and MacOS X

 BDR I think a wording like R-sig-debian namely

 BDRR Special Interest Group for MacOS X ports of R

Brian's definition  seems appropriate to me nowadays

and the (extended) disclaimer should include both development issues  
specific to OS X (ports, etc) and user feedback on R.app GUI (we  
don't want R.app bugs go into the R-bugs list), but NOT general R- 
help topics which should go to R-help indeed.

I think we should keep the devel part in R-sig-Mac.

I'm including Simon Urbanek and waiting for some reaction before  
taking actions on R-sig-mac.

stefano



 BDR would be better.

 yes, thank you both   IFF this is really the intention.

 Stefano Iacus is the maintainer (and initiator) of the list
 and should say (and maybe ask on the R-SIG-Mac list) what he
 (and the subscribers) really wants.


 R-SIG-Mac R Special Interest Group on Mac Development

 This is very similar to the description of R-devel:

 This list is intended for questions and discussion about
 code development in R.

 And that description is even more intimidating when you
 read further:

 Questions likely to prompt discussion unintelligible to
 non-programmers or topics that are too technical for
 R-help's audience should go to R-devel

 Would it make sense to change the description of
 R-SIG-mac so that it would welcome question on R usage in
 Mac, instead of being a Mac Devolepment forum that
 sounds like being unintelligible to non-programmers?


 BDR Which seems quite reasonable to me.  The topics which
 BDR provoke this response usually are questions
 BDR unintelligible except to Mac sysadmins/programmers and
 BDR definitely `too technical for R-help's audience'.

 I agree.  We shouldn't let R users on the Mac think that all
 their questions should go to R-SIG-Mac.
 Regular R questions should continue to come to R-help (or
 R-devel) just as per the posting guide.

 Martin Maechler


 BDR -- Brian D. Ripley, [EMAIL PROTECTED] Professor of
 BDR Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
 BDR University of Oxford, Tel: +44 1865 272861 (self) 1
 BDR South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG,
 BDR UK Fax: +44 1865 272595


 !DSPAM:43562fae226121420620285!



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[R] clustering algorithm detail

2005-10-19 Thread Tim Smith
Hi all,
 
I wanted to run the hclust (or any other clustering algorithm) on a distance 
matrix. I have formed the distance matrix as:
 
distmat:
 
ab c de
a0.000.961.601.601.68
b0.960.000.961.802.64
c   1.600.960.000.841.80
d   1.601.800.840.000.96
e   1.682.641.800.960.00
 
Now, I would like to run a clustering algorithm on it. I tried:
 
newclust = hclust(distmat)
 
and got the following error:
 
Error in if (n  2) stop(Must have n = 2 objects to cluster) : 
argument is of length zero
 
I understand that the documentation says that the matrix ' d: a dissimilarity 
structure as produced by 'dist''. Does that mean that I need to convert it into 
a lower triangle matrix? I also tried:
 
newclust = hclust(vech(distmat))
 
but this gave a similar error. Where am I going wrong?
 
 
Also, will hclust be able to handle 'NA' in the dissimilarity matrix?
 
many thanks,
 
 
Tim
 
 


-

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Re: [R] Automatic rounding of values after factors , converted to numeric, are multipled by a real number

2005-10-19 Thread Peter Dalgaard
Nelson, Gary (FWE) [EMAIL PROTECTED] writes:

 I am wondering if someone would have any suggestion about my issue?
 
 
 I have the following code:
 
 wgts-aggregate(subset(lendata,select=c(Length)),list(lendata$Cruise,len
 data$Station,lendata$Region,lendata$Total),mean)
 wgts-wgts[order(wgts$Group.3,wgts$Group.1,wgts$Group.1),]
 names(wgts)-c(Cruise,Station,Region,Total,MLen)
 wgts$Total-as.numeric(levels(wgts$Total))[wgts$Total]
 wgts$swmean-with(wgts,wgts$Total*wgts$MLen) 
 
 When I run it, I get:
Cruise Station Region Total MLen swmean
 32350 256  1 2 70.5141
 52350 254  1 3 73.3220
 62350 287  1 3 65.7197
 92350 232  1 4 75.25000301
 10   2350 294  1 4 56.0224
 12   2350 301  1 5 70.2351
 14   2350 316  1 6 67.3404
 15   2350 255  1 7 55.0385
 17   2350 285  1 8 73.5588
 19   2350 212  110 57.5575
 20   2350 250  110 61.5615
 27   2350 221  124 95.29167   2287
 33   2350 229  135 55.62857   1947
 37   2350 293  147 53.82979   2530
 38   2350 203  150 55.54000   2777
 39   2350 248  155 63.30909   3482
 41   2350 246  163 95.82540   6037
 42   2350 265  168 55.54412   3777
 43   2350 251  182 62.60976   5134
 44   2350 234  185 57.21176   4863
 
 Every value is correct except that the swmeans are rounded and I can't
 get values with the decimals fractions.  I have tried as.double and have
 change the options(digits=7), but nothing seems to work. I have spent
 several hours combing manuals and archives. 

as far as I can see, the issue is that Total*MLen just *are* pretty
close to being integers, e.g.

 4863/85
[1] 57.21176

 z - x$Total*x$MLen
 z - round(z)
 [1]  0.0 -0.1  0.1  0.0  0.0  0.0 -0.2  0.0
 [9]  0.0  0.0  0.0  0.8 -0.5  0.00013  0.0 -0.5
[17]  0.00020  0.00016  0.00032 -0.00040

 

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] Optim with two constraints

2005-10-19 Thread Alexis Diamond
Hello,

I have a follow-up from Jens's question and Professor Ripley's response.

Jens wants to do quadratic optimization with 2 constraints:

   # I need two constraints:
   # 1. each element in par needs to be between 0 and 1
# 2. sum(par)=1, i.e. the elements in par need to sum to 1

how does one set both constraints in quadprog, per Prof. Ripley's suggestion?

i know how to get quadprog to handle the second constraint, but not
BOTH, since quadprog only takes as inputs the constraint matrix A
and constraint vector b--
unlike in ipop (kernlab), there is no additional option for box constraints.

apologies if i am not seeing something obvious here.

thanks in advance,

alexis

On 10/19/05, Jens Hainmueller [EMAIL PROTECTED] wrote:


  -Ursprüngliche Nachricht-
  Von: Prof Brian Ripley [mailto:[EMAIL PROTECTED]
  Gesendet: Thursday, October 13, 2005 2:46 AM
  An: Jens Hainmueller
  Cc: r-help@stat.math.ethz.ch
  Betreff: Re: [R] Optim with two constraints
 
  This is actually quadratic programming, so why do you want to
  use optim()?
  There are packages specifically for QP, e.g. quadprog.
 
  A more general approach is to eliminate one variable, which
  gives you an inequality constrained problem in n-1 variables
  to which you could apply contrOptim().  Other
  re-parametrizations (e.g. of weights as a log-linear model)
  will work provided none of the parameters are going to be
  zero at the optimum (one cannot be one without all the others
  being zero).
 
  On Wed, 12 Oct 2005, Jens Hainmueller wrote:
 
   Hi R-list,
  
   I am new to optimization in R and would appreciate help on the
   following question. I would like to minimize the following function
   using two
   constraints:
  
   ##
   fn - function(par,H,F){
  
   fval - 0.5 * t(par) %*% H %*% par + F%*% par
   fval
  
}
  
   # matrix H is (n by k)
   # matrix F is (n by 1)
   # par is a (n by 1) set of weights
  
   # I need two constraints:
   # 1. each element in par needs to be between 0 and 1 # 2.
  sum(par)=1
   i.e. the elements in par need to sum to 1
  
   ## I try to use optim
   res - optim(c(runif(16),fn, method=L-BFGS-B, H=H, F=f
   ,control=list(fnscale=-1), lower=0, upper=1) ##
  
   If I understand this correctly, using L-BFGS-B with lower=0 and
   upper=1 should take care of constraint 1 (box constraints).
  What I am
   lacking is the skill to include constraint no 2.
  
   I guess I could solve this by reparametrization but I am
  not sure how
   exactly. I could not find (i.e. wasn't able to infer) the answer to
   this in the archives despite the many comments on optim and
   constrained optimization (sorry if I missed it there). I am
  using version 2.1.1 under windows XP.
  
   Thank you very much.
  
   Jens
  
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  --
  Brian D. Ripley,  [EMAIL PROTECTED]
  Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
  University of Oxford, Tel:  +44 1865 272861 (self)
  1 South Parks Road, +44 1865 272866 (PA)
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Re: [R] clustering algorithm detail

2005-10-19 Thread Christian Hennig
Have you tried as.dist(distmat)?

Christian

On Wed, 19 Oct 2005, Tim Smith wrote:

 Hi all,

 I wanted to run the hclust (or any other clustering algorithm) on a distance 
 matrix. I have formed the distance matrix as:

 distmat:

 ab c de
 a0.000.961.601.601.68
 b0.960.000.961.802.64
 c   1.600.960.000.841.80
 d   1.601.800.840.000.96
 e   1.682.641.800.960.00

 Now, I would like to run a clustering algorithm on it. I tried:

 newclust = hclust(distmat)

 and got the following error:

 Error in if (n  2) stop(Must have n = 2 objects to cluster) :
 argument is of length zero

 I understand that the documentation says that the matrix ' d: a dissimilarity 
 structure as produced by 'dist''. Does that mean that I need to convert it 
 into a lower triangle matrix? I also tried:

 newclust = hclust(vech(distmat))

 but this gave a similar error. Where am I going wrong?


 Also, will hclust be able to handle 'NA' in the dissimilarity matrix?

 many thanks,


 Tim




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*** --- ***
Christian Hennig
University College London, Department of Statistical Science
Gower St., London WC1E 6BT, phone +44 207 679 1698
[EMAIL PROTECTED], www.homepages.ucl.ac.uk/~ucakche

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[R] sqlQuery and string selection

2005-10-19 Thread Jérôme Lemaître
Dear alls,

Could someone tell me how to select a subset of string observations (e.g.
females in a sex column) with sqlQuery in the RODBC library?

Indeed, I'm trying to select a subset of observations on my access database
with:

female-sqlQuery(mychannel,SELECT Micromammiferes.sex
FROM Micromammiferes
WHERE (((Micromammiferes.sex)=females));)

The sql works well in access but in R, I keep getting:

Error: syntax error.

Any help would be very appreciated,

Thanks a lot

Jérôme Lemaître
Ph.D. student
Départment of biology,
University Laval
Quebec, Canada

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[R] adding error bars to lattice plots

2005-10-19 Thread Mario Aigner-Torres
Dear R-Users,

how to include error bars within lattice?
How should the panel = function(x,y,...){
looks like?
Does panel.arrows works here as well?

I appreciate any help on this.

Regards,

Mario AT

[[alternative HTML version deleted]]

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[R] Filter design in R?

2005-10-19 Thread Israel Christie
Dr. Williams,
I ran across your inquiry on one of the R-help mailing lists regarding 
digital filter design and implementation. I found no response to your 
email in the archives and was wondering if you were able to find anything.

Thanks,
Israel

-- 

Israel Christie, Ph.D.
Email: [EMAIL PROTECTED]
Phone: 865.766.0214
Mobile: 865.406.4615

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Re: [R] sqlQuery and string selection

2005-10-19 Thread paul sorenson
Jérôme Lemaître wrote:
 Dear alls,
 
 Could someone tell me how to select a subset of string observations (e.g.
 females in a sex column) with sqlQuery in the RODBC library?
 
 Indeed, I'm trying to select a subset of observations on my access database
 with:
 
 female-sqlQuery(mychannel,SELECT Micromammiferes.sex
 FROM Micromammiferes
 WHERE (((Micromammiferes.sex)=females));)
 
 The sql works well in access but in R, I keep getting:
 
 Error: syntax error.

R is likely to have problems with nested quote characters.

Ie:

x = SELECT Micromammiferes.sex FROM Micromammiferes WHERE 
(((Micromammiferes.sex)=females));

also results in a syntax error (my mailer split the line).

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Re: [R] sqlQuery and string selection

2005-10-19 Thread paul sorenson (sosman)
(sorry if a duplicate pops through ...)
Jérôme Lemaître wrote:
 Dear alls,
 
 Could someone tell me how to select a subset of string observations (e.g.
 females in a sex column) with sqlQuery in the RODBC library?
 
 Indeed, I'm trying to select a subset of observations on my access database
 with:
 
 female-sqlQuery(mychannel,SELECT Micromammiferes.sex
 FROM Micromammiferes
 WHERE (((Micromammiferes.sex)=females));)
 
 The sql works well in access but in R, I keep getting:
 
 Error: syntax error.

Most computer software has problems with nested quote characters.

Ie:

  x = SELECT Micromammiferes.sex FROM Micromammiferes WHERE
(((Micromammiferes.sex)=females));

also results in a syntax error (my mailer split the line).

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Re: [R] adding error bars to lattice plots

2005-10-19 Thread Berton Gunter
?llines, lsegments and the like can be used in the panel functions to draw
any sort of error bar that you can compute from the x,y,... data of the
panel.

-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
 
The business of the statistician is to catalyze the scientific learning
process.  - George E. P. Box
 
 

 -Original Message-
 From: [EMAIL PROTECTED] 
 [mailto:[EMAIL PROTECTED] On Behalf Of Mario 
 Aigner-Torres
 Sent: Wednesday, October 19, 2005 2:34 PM
 To: r-help@stat.math.ethz.ch
 Subject: [R] adding error bars to lattice plots
 
 Dear R-Users,
 
 how to include error bars within lattice?
 How should the panel = function(x,y,...){
 looks like?
 Does panel.arrows works here as well?
 
 I appreciate any help on this.
 
 Regards,
 
 Mario AT
 
   [[alternative HTML version deleted]]
 
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 http://www.R-project.org/posting-guide.html


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Re: [R] sqlQuery and string selection

2005-10-19 Thread Prof Brian Ripley

The syntax error is that you have unescaped quotes inside quotes.
You also do not need a semicolon, nor to refer to columns in this
table.column form.  Try

'select sex from Micromammiferes where sex=females'

(I suspect you do not need quotes, but keep forgetting the quirks of
various DBMSs.)

On Wed, 19 Oct 2005, Jérôme Lemaître wrote:


Dear alls,

Could someone tell me how to select a subset of string observations (e.g.
females in a sex column) with sqlQuery in the RODBC library?

Indeed, I'm trying to select a subset of observations on my access database
with:

female-sqlQuery(mychannel,SELECT Micromammiferes.sex
FROM Micromammiferes
WHERE (((Micromammiferes.sex)=females));)

The sql works well in access but in R, I keep getting:

Error: syntax error.

Any help would be very appreciated,

Thanks a lot

Jérôme Lemaître
Ph.D. student
Départment of biology,
University Laval
Quebec, Canada

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--
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595__
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Re: [R] Weights in survReg

2005-10-19 Thread Prof Brian Ripley
Sasha,

This is R, which has survreg with weights (no caps).  You can find out for 
sure from the source code, but the help file says these are `observation 
weights'. I take that to mean weight=2 says `I have two cases like this' 
in forming the likelihood.  The C code says `case weights', the usual term 
for that meaning.


On Wed, 19 Oct 2005, Alexander Antonyuk wrote:

 Dear R users,

 I am trying to find out what the function survReg does exactly with the
 Weights parameters. I looked in Terry Therneau documentations and other
 places and couldn't find anything. I tried to make an analogy with weighted
 OLS and assumed that the scale parameter Sigma in the accelerated
 failure-time model log(Time)= X*betas +Sigma*E, is of the form Sigma(i) =
 Sigma/Weights(i).

 Can anyone confirm that or point me in the direction where I can find out
 for sure?

 Thank you,
 Sasha

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] mid-p CIs for common odds ratio

2005-10-19 Thread Tim Churches
mantelhaen.test() gives the exact conditional p-value (for independence) and 
confidence intervals (CIs)for the common odds ratio for a stratified 2x2 table. 
The epitools package by Tomas Aragon (available via CRAN) contains functions 
which use fisher.test() to calculate mid-p exact p-values and CIs for the CMLE 
odds ratio for a single 2x2 table. The mid-p p-value for independence for a 
stratified 2x2 table is easy to calculate using mantelhaen.test(), but can 
anyone suggest a method for calculation of mid-p CIs for the common odds ratio? 
A search in the usual places draws a blank (but I am sure someone will 
immediately prove me wrong on that point...). Thanks to Andy Dean (of Epi-Info 
fame), I have a copy of public domain Pascal code from 1991 by David Martin and 
Harland Austin which calculates mid-p CIs for the common odds ratio by finding 
polynomial roots. Before trying to replicate that code in R (or C), I was 
wondering if anyone could suggest a better or easier way?

Tim C

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[R] Plotting more than one series on the same graph

2005-10-19 Thread mtb954
I'm new to R and have searched for help and consulted the the pdf
manuals, but I can't seem to figure out how to plot more than one
series on the same graph.

I've tried using multiple par(new=TRUE) statements such as

plot(series1, ci.type=line, col=red, lwd=2, ci.lty=0, ci.col=red)
par(new=TRUE)
plot(series2, ci.type=line, col=green, lwd=2, ci.lty=0, ci.col=green)
par(new=TRUE)
plot(series3, ci.type=line, col=blue, lwd=2, ci.lty=0, ci.col=blue)

and this does plot the three series on one graph, but makes a mess of
the y-axis.

There must be a more elegant solution.

Also, I wonder why the final series (series 3) doesn't plot until I
manually hit enter?

Thanks for any help, Mark

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Re: [R] Plotting more than one series on the same graph

2005-10-19 Thread Sundar Dorai-Raj


[EMAIL PROTECTED] wrote:
 I'm new to R and have searched for help and consulted the the pdf
 manuals, but I can't seem to figure out how to plot more than one
 series on the same graph.
 
 I've tried using multiple par(new=TRUE) statements such as
 
 
plot(series1, ci.type=line, col=red, lwd=2, ci.lty=0, ci.col=red)
par(new=TRUE)
plot(series2, ci.type=line, col=green, lwd=2, ci.lty=0, ci.col=green)
par(new=TRUE)
plot(series3, ci.type=line, col=blue, lwd=2, ci.lty=0, ci.col=blue)
 
 
 and this does plot the three series on one graph, but makes a mess of
 the y-axis.
 
 There must be a more elegant solution.
 
 Also, I wonder why the final series (series 3) doesn't plot until I
 manually hit enter?
 
 Thanks for any help, Mark
 

Hi, Mark,

In general, see ?lines. However, your use of ci.type suggests you're 
using ?plot.acf, which may require you describe what you are trying to 
do in more detail.

Thanks,

--sundar

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[R] creating a derived variable in a data frame

2005-10-19 Thread Avram Aelony
Hello,

I have read through the manuals and can't seem to find an answer.

I have a categorical, character variable that has hundreds of values.  I want 
to group the existing values of this variable into a new, derived (categorical) 
variable by applying conditions to the values in the data.

For example, suppose I have a data frame with variables: date, country, x, y, 
and z.  

x,y,z are numeric and country is a 2-digit character string.  I want to create 
a new derived variable named continent that would also exist in the data 
frame. The Continent variable would have values of Asia, Europe, North 
America, etc...   

How would this best be done for a large dataset (10MB) ?  
I have tried many variations on following without success (note in a real 
example I would have a longer list of countries and continent values):

 mydata$continent - mydata[ mydata$country==list('US','CA','MX'), ] - North 
 America

I have read about factors, but I am not sure how they apply here.  

Can anyone help me with the syntax?  I am sure it is trivial and a common thing 
to do.
The ultimate goal is to compute percentages of x by continent.

Thanks for any help in advance.

-Avram

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[R] RE : sqlQuery and string selection

2005-10-19 Thread Jérôme Lemaître
Dear Prof Ripley,

I tried what you suggested and it worked perfectly well! 
I also appreciated your corrections about my SQL formulation. However, it
seems that quotes are indeed needed to get string observations (but my
access software is in french...).
Finally, do you think that it might be worth to add an example for sqlQuery
using string variables in a later version of RODBC, just in case others
encounter the same problem as me?

I thank you very much for your help,


Jérôme Lemaître
Ph.D. student
Départment of biology,
University Laval
Quebec, Canada


-Message d'origine-
De : Prof Brian Ripley [mailto:[EMAIL PROTECTED] 
Envoyé : 19 octobre 2005 18:23
À : Jérôme Lemaître
Cc : R-help@stat.math.ethz.ch
Objet : Re: [R] sqlQuery and string selection

The syntax error is that you have unescaped quotes inside quotes.
You also do not need a semicolon, nor to refer to columns in this
table.column form.  Try

'select sex from Micromammiferes where sex=females'

(I suspect you do not need quotes, but keep forgetting the quirks of
various DBMSs.)

On Wed, 19 Oct 2005, Jérôme Lemaître wrote:

 Dear alls,

 Could someone tell me how to select a subset of string observations (e.g.
 females in a sex column) with sqlQuery in the RODBC library?

 Indeed, I'm trying to select a subset of observations on my access
database
 with:

 female-sqlQuery(mychannel,SELECT Micromammiferes.sex
 FROM Micromammiferes
 WHERE (((Micromammiferes.sex)=females));)

 The sql works well in access but in R, I keep getting:

 Error: syntax error.

 Any help would be very appreciated,

 Thanks a lot

 Jérôme Lemaître
 Ph.D. student
 Départment of biology,
 University Laval
 Quebec, Canada

 __
 R-help@stat.math.ethz.ch mailing list
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-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] creating a derived variable in a data frame

2005-10-19 Thread ronggui
I suggest you use the recode function in car package to do your job.


=== 2005-10-20 08:09:08 您在来信中写道:===

Hello,

I have read through the manuals and can't seem to find an answer.

I have a categorical, character variable that has hundreds of values.  I want 
to group the existing values of this variable into a new, derived 
(categorical) variable by applying conditions to the values in the data.

For example, suppose I have a data frame with variables: date, country, x, y, 
and z.  

x,y,z are numeric and country is a 2-digit character string.  I want to create 
a new derived variable named continent that would also exist in the data 
frame. The Continent variable would have values of Asia, Europe, North 
America, etc...   

How would this best be done for a large dataset (10MB) ?  
I have tried many variations on following without success (note in a real 
example I would have a longer list of countries and continent values):

 mydata$continent - mydata[ mydata$country==list('US','CA','MX'), ] - 
 North America

I have read about factors, but I am not sure how they apply here.  

Can anyone help me with the syntax?  I am sure it is trivial and a common 
thing to do.
The ultimate goal is to compute percentages of x by continent.

Thanks for any help in advance.

-Avram

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= = = = = = = = = = = = = = = = = = = =



 

2005-10-20

--
Deparment of Sociology
Fudan University

My new mail addres is [EMAIL PROTECTED]
Blog:http://sociology.yculblog.com

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