Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Fri, 29 Mar 2013 16:48:47 -0400: Hi, [snip] >There is a limit to stability, once stability reaches that limit, there is >no way to go but toward instability. As the EMF grows in strength, the >nuclear forces become increasingly unstable. Given a sufficiently intense >EMF field, sufficient instability can be achieved to overcome the fission >limit. >The key is to produce an irresistibly strong disruptive EMF to overcome the >fission limit of the nucleus. This is the engineering challenge. > >Cheers:Axil [snip] A sufficiently strong gamma ray will sometimes cause fission in a Uranium nucleus. The gamma needs be in the ball park of 10 MeV. That's because that's approximately the energy needed to fission the nucleus, i.e. to overcome the difference in energy between the volume term and the rest. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
On Fri, Mar 29, 2013 at 6:23 PM, Harry Veeder wrote: > > On Fri, Mar 29, 2013 at 4:48 PM, Axil Axil wrote: > >> There is a limit to stability, once stability reaches that limit, there >> is no way to go but toward instability. >> > > > > Is this something like "buckling"? > Failure without breaking > > http://www.youtube.com/watch?v=wrdO8hPJGyg > > http://www.youtube.com/watch?v=EKngs1vvcJU > > harry > > > The first video shows buckling under compression which is familiar However buckling can also occur under tension. This is less well known and is shown in the second video. Harry
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
On Fri, Mar 29, 2013 at 4:48 PM, Axil Axil wrote: > There is a limit to stability, once stability reaches that limit, there is > no way to go but toward instability. > Is this something like "buckling"? Failure without breaking http://www.youtube.com/watch?v=wrdO8hPJGyg http://www.youtube.com/watch?v=EKngs1vvcJU harry
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
There is a limit to stability, once stability reaches that limit, there is no way to go but toward instability. As the EMF grows in strength, the nuclear forces become increasingly unstable. Given a sufficiently intense EMF field, sufficient instability can be achieved to overcome the fission limit. The key is to produce an irresistibly strong disruptive EMF to overcome the fission limit of the nucleus. This is the engineering challenge. Cheers:Axil On Fri, Mar 29, 2013 at 3:53 PM, wrote: > In reply to Axil Axil's message of Thu, 28 Mar 2013 15:54:02 -0400: > Hi, > [snip] > >When two things are balanced, the balance can be upset in two ways: you > can > >change the first thing or you can change the second thing. > > > >In either case the thing that was once balanced is now unbalanced. > > > >It does not matter how you get to the unbalanced state, the result is the > >same, fission. > > > ..but the two things are not in balance. The surface term, the Coulomb > term, and > the asymmetry term are all negative, but their sum is still less than the > positive volume term. If you decrease any of the three negative terms in > magnitude, then the difference with the volume term increases, i.e. the > nucleus > becomes more stable. > [snip] > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Thu, 28 Mar 2013 15:54:02 -0400: Hi, [snip] >When two things are balanced, the balance can be upset in two ways: you can >change the first thing or you can change the second thing. > >In either case the thing that was once balanced is now unbalanced. > >It does not matter how you get to the unbalanced state, the result is the >same, fission. ..but the two things are not in balance. The surface term, the Coulomb term, and the asymmetry term are all negative, but their sum is still less than the positive volume term. If you decrease any of the three negative terms in magnitude, then the difference with the volume term increases, i.e. the nucleus becomes more stable. [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
When two things are balanced, the balance can be upset in two ways: you can change the first thing or you can change the second thing. In either case the thing that was once balanced is now unbalanced. It does not matter how you get to the unbalanced state, the result is the same, fission. On Thu, Mar 28, 2013 at 3:43 PM, wrote: > In reply to Axil Axil's message of Wed, 27 Mar 2013 17:27:07 -0400: > Hi, > [snip] > >Since we know that proton charge can be screened and therefore variable, > >the coulomb coefficient is reduced relative to the Asymmetry term as a > >result of screening. > >See > > > >http://en.wikipedia.org/wiki/Semi-empirical_mass_formula > > The Coulomb term is negative. If you reduce it, the binding energy > increases, > making the nucleus more stable, not less. (The Coulomb term reduces the > binding > energy of the nucleus because of the mutual repulsion of the protons.) > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Wed, 27 Mar 2013 17:27:07 -0400: Hi, [snip] >Since we know that proton charge can be screened and therefore variable, >the coulomb coefficient is reduced relative to the Asymmetry term as a >result of screening. >See > >http://en.wikipedia.org/wiki/Semi-empirical_mass_formula The Coulomb term is negative. If you reduce it, the binding energy increases, making the nucleus more stable, not less. (The Coulomb term reduces the binding energy of the nucleus because of the mutual repulsion of the protons.) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Thanks for the inspiration. It has just occurred to me that the use of Ni64 which has an abundant neutrons will be most susceptible to fission due to an imbalance of nuclear forces; more specifically the coulomb force relative to the Asymmetry force. Now it makes sense that Rossi uses a minuscule amount of Ni64 to build the nanowires that form the NAE on the micropowder in his reactor. Thanks: Axil On Wed, Mar 27, 2013 at 5:27 PM, Axil Axil wrote: > Since we know that proton charge can be screened and therefore variable, > the coulomb coefficient is reduced relative to the Asymmetry term as a > result of screening. > See > > http://en.wikipedia.org/wiki/Semi-empirical_mass_formula > > > > > > > > > > > > On Wed, Mar 27, 2013 at 5:03 PM, wrote: > >> In reply to Axil Axil's message of Mon, 25 Mar 2013 10:23:03 -0400: >> Hi, >> [snip] >> >As this positive charge is reduced, the attraction between protons and >> >neutrons are decreased. >> >> Why? >> Regards, >> >> Robin van Spaandonk >> >> http://rvanspaa.freehostia.com/project.html >> >> >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Since we know that proton charge can be screened and therefore variable, the coulomb coefficient is reduced relative to the Asymmetry term as a result of screening. See http://en.wikipedia.org/wiki/Semi-empirical_mass_formula On Wed, Mar 27, 2013 at 5:03 PM, wrote: > In reply to Axil Axil's message of Mon, 25 Mar 2013 10:23:03 -0400: > Hi, > [snip] > >As this positive charge is reduced, the attraction between protons and > >neutrons are decreased. > > Why? > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Mon, 25 Mar 2013 10:23:03 -0400: Hi, [snip] >As this positive charge is reduced, the attraction between protons and >neutrons are decreased. Why? Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
RE: EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Dear Axil, It does make for controversy but I think certain lattice geometries or layers of compressed noble gases can pit stiction forces against the normally unexploitable random motion of gas loaded between said geometry or layers... I often use the disassociation threshold of H2 as a convenient example where the stiction force and changes in stiction levels oppose random motion of gas and discount the energy needed to disassociate a gas molecule below the level released when the molecule immediately reforms... But other exploitations of these quantum forces and gas motion could also explain the bootstrap for your theory, I am simply convinced that the underlying bootstrap principle is zero point energy.. a self assembling maxwellian demon/Heisenberg trap [as long as you prevent stiction from completely collapsing the geometry] that opposes random motion of gas through the geometry...It isn't the classic demon separating hot from cold atoms but segregating vacuum pressure into zones big enough for atoms to occupy IS still a form of maxwellian sorting where random motion is exploited to fill one zone in preference to the other. I like Jan Naudts paper on the Hydrino as relativistic hydrogen because it gives EXTRA strength to the energy available from zero point through time dilation.. in my example of exploiting the disassociation threshold of gas molecules because the endless reaction between atomic and molecular state can now occur millions of time faster from our perspective when it occurs inside a casimir cavity where the theory for casimir plates opposing longer vacuum wavelengths is exchanged for a temporal version of the theory where all the wavelengths still fit between the plates from their local perspective inside the cavity while we see them as shorter from our perspective through Lorentzian contraction/dilation... [a tiny TARTUS] the wavelengths are rotated onto the time axis and gas atom caught in this cavity see the walls shrink away from them such that they can occupy a volume of space that appears to small from our frame outside the cavity. This could be the poor mans vehicle for relativistic effects using segregation of vacuum pressure at the nano scale instead of compression due to near luminal speeds at the macro. Regards: Fran From: Axil Axil [mailto:janap...@gmail.com] Sent: Tuesday, March 26, 2013 1:43 PM To: vortex-l@eskimo.com Subject: Re: EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your minds of confusion Dear Francis, Your post got me thinking. We may have a chicken or the egg situation here. The speed of light may well be modified in the nuclear active environment (NAE). But why? The first think that passed through my head was how Joe Papp shot large amounts of current through isotopes to increase the alpha production from radioactive alpha emitters. From the ScienceDaily reference as follows: "They found that a specific property of vacuum called the impedance, which is crucial to determining the speed of light, depends only on the sum of the square of the electric charges of particles but not on their masses." If we increase the charge density in and immediately around the NAE, the speed of light might well be modified. The increase in the electric charge concentration might modify the character and the strength of the vacuum, and therefore the speed of light. Is it the increase in the charge concentration that lowers the coulomb barrier or is it the associated change in the speed of light, or is it the modification of the vacuum impedance that is the active agent. The Papp engine does concentrate charge in the noble gas clusters without the presence of a NAE. The Noble gas cluster provides a different type of NAE. Where does the increase in energy within a LENR system come from, the vacuum or the fusion and/or fission that causes transmutation due to a lowered coulomb barrier? How can we understand what the ultimate cause of LENR really is and what are the associated effects? Cheers: Axil On Tue, Mar 26, 2013 at 8:34 AM, Roarty, Francis X mailto:francis.x.roa...@lmco.com>> wrote: Axil, I am totally ok with your description regarding virtual energy exceeding the columb barrier but less convinced about your conclusion based on lack of radioactive ash [snip] After this nuclear relaxation process, if the energy level inside the nucleus has been lowed enough so that it can never again surmount the coulomb barrier no matter how much virtual energy may appear, the element is said to be stable. [/snip] IMHO the material really is radioactive from "our" perspective while the material is inside the NAE.. the geometry is segregating the vacuum density and producing anomalous decay rates from our perspective... time dilation.. while from it's own local perspective the decay rate may appear to be millions of years see "speed of light may n
Re: EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Dear Francis, Your post got me thinking. We may have a chicken or the egg situation here. The speed of light may well be modified in the nuclear active environment (NAE). But why? The first think that passed through my head was how Joe Papp shot large amounts of current through isotopes to increase the alpha production from radioactive alpha emitters. From the ScienceDaily reference as follows: “They found that a specific property of vacuum called the impedance, which is crucial to determining the speed of light, depends only on the sum of the square of the electric charges of particles but not on their masses.” If we increase the charge density in and immediately around the NAE, the speed of light might well be modified. The increase in the electric charge concentration might modify the character and the strength of the vacuum, and therefore the speed of light. Is it the increase in the charge concentration that lowers the coulomb barrier or is it the associated change in the speed of light, or is it the modification of the vacuum impedance that is the active agent. The Papp engine does concentrate charge in the noble gas clusters without the presence of a NAE. The Noble gas cluster provides a different type of NAE. Where does the increase in energy within a LENR system come from, the vacuum or the fusion and/or fission that causes transmutation due to a lowered coulomb barrier? How can we understand what the ultimate cause of LENR really is and what are the associated effects? Cheers: Axil On Tue, Mar 26, 2013 at 8:34 AM, Roarty, Francis X < francis.x.roa...@lmco.com> wrote: > Axil, > > I am totally ok with your description regarding virtual energy exceeding > the columb barrier but less convinced about your conclusion based on lack > of radioactive ash [snip] After this nuclear relaxation process, if the > energy level inside the nucleus has been lowed enough so that it can never > again surmount the coulomb barrier no matter how much virtual energy may > appear, the element is said to be stable. [/snip] IMHO the material really > is radioactive from “our” perspective while the material is inside the > NAE.. the geometry is segregating the vacuum density and producing > anomalous decay rates from our perspective… time dilation.. while from it’s > own local perspective the decay rate may appear to be millions of years…. > see “speed of light may not be fixed” > http://www.sciencedaily.com/releases/2013/03/13032554.htm .. There > have been some anomalous half life reports on radioactive gas decay when > loaded into an NAE both accelerated and even some decelerated which is why > I posit the geometry allows for a balanced segregation effect and it is the > flow path that exposes the gas molecules to the environment in a manner > that can unbalance the time metric in favor of one of the segregated areas > over the other. The gas on average spends, for instance, more time in an > area where virtual particles are suppressed inside a cavity vs compressed > outside the cavity. > > Fran > > ** ** > > ** ** > > *From:* Axil Axil [mailto:janap...@gmail.com] > *Sent:* Monday, March 25, 2013 7:17 PM > *To:* vortex-l@eskimo.com > *Subject:* EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your > minds of confusion > > ** ** > > The Bumpy Road. > > The binding energy contained inside the nucleus is an uncertain thing; it > goes up and down at the whim of quantum mechanics; it varies with the > uncertainty principle. This energy is comprised of two parts: a real energy > and a virtual energy. It is this virtual energy that can vary widely and is > not constrained by the laws of energy and momentum. > > When constrained inside the nucleus and when this nuclear energy is > composed of these two parts get strong enough, it spills over the top of > the coulomb barrier and forms a real particle outside the nucleus. This is > quantum mechanical tunneling. The virtual part of this spillover energy > only lasts for the briefest of instants and immediately goes away and only > the real part remains to congeal into the newly radiated particle that has > tunneled through the barrier. This process is called radioactive decay (AKA > tunneling through the coulomb barrier). > > After this nuclear relaxation process, if the energy level inside the > nucleus has been lowed enough so that it can never again surmount the > coulomb barrier no matter how much virtual energy may appear, the element > is said to be stable. > > In regards to LENR, we can draw and amazing and informative conclusion > from this behavior of the nuclear reaction. > > The fact that no radioactive isotopes are found in the ash of the cold > fusion reaction is unequivocal proof that LENR is caused by t
RE: EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Axil, I am totally ok with your description regarding virtual energy exceeding the columb barrier but less convinced about your conclusion based on lack of radioactive ash [snip] After this nuclear relaxation process, if the energy level inside the nucleus has been lowed enough so that it can never again surmount the coulomb barrier no matter how much virtual energy may appear, the element is said to be stable. [/snip] IMHO the material really is radioactive from "our" perspective while the material is inside the NAE.. the geometry is segregating the vacuum density and producing anomalous decay rates from our perspective... time dilation.. while from it's own local perspective the decay rate may appear to be millions of years see "speed of light may not be fixed" http://www.sciencedaily.com/releases/2013/03/13032554.htm .. There have been some anomalous half life reports on radioactive gas decay when loaded into an NAE both accelerated and even some decelerated which is why I posit the geometry allows for a balanced segregation effect and it is the flow path that exposes the gas molecules to the environment in a manner that can unbalance the time metric in favor of one of the segregated areas over the other. The gas on average spends, for instance, more time in an area where virtual particles are suppressed inside a cavity vs compressed outside the cavity. Fran From: Axil Axil [mailto:janap...@gmail.com] Sent: Monday, March 25, 2013 7:17 PM To: vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your minds of confusion The Bumpy Road. The binding energy contained inside the nucleus is an uncertain thing; it goes up and down at the whim of quantum mechanics; it varies with the uncertainty principle. This energy is comprised of two parts: a real energy and a virtual energy. It is this virtual energy that can vary widely and is not constrained by the laws of energy and momentum. When constrained inside the nucleus and when this nuclear energy is composed of these two parts get strong enough, it spills over the top of the coulomb barrier and forms a real particle outside the nucleus. This is quantum mechanical tunneling. The virtual part of this spillover energy only lasts for the briefest of instants and immediately goes away and only the real part remains to congeal into the newly radiated particle that has tunneled through the barrier. This process is called radioactive decay (AKA tunneling through the coulomb barrier). After this nuclear relaxation process, if the energy level inside the nucleus has been lowed enough so that it can never again surmount the coulomb barrier no matter how much virtual energy may appear, the element is said to be stable. In regards to LENR, we can draw and amazing and informative conclusion from this behavior of the nuclear reaction. The fact that no radioactive isotopes are found in the ash of the cold fusion reaction is unequivocal proof that LENR is caused by the lowering of the coulomb barrier and NOT a fusion process. That is, when the coulomb barrier is very low during the LENR moment, the energy in the nucleus is stabilized at the lowest barrier level in relation to the lowered coulomb barrier. Now when the barrier neutralization is removed and the barrier springs back to full power, the binding energy contained in the newly formed nucleus is completely relaxed in regards to the newly recovered strength of the coulomb barrier. Here is an analog from the real world to explain this principle. If you take a glass of water filled to the brim on a car trip over a bumpy road, the water will splash over the brim until water reaches a maximum level to where the water does not slash anymore. Now suppose you could magically reduce the sides of the glass to a low level when the bumpy trip first starts and the water level reaches this maximum no spill level, now you magically raise the sides of the glass very high again. No water will ever spill out no matter how bumpy the road gets. The water level in the glass is now forever stable. The nuclear binding energy excess produced by the LENR reaction is spread around the lattice to all the other members of the Bose-Einstein condensate, so both the new nucleus and the expelled particle(s) have little excess energy to dissipate into the localized lattice. These nuclear fragments part ways at a very slow pace with little disruptions on the other NAE around them. This is why a LENR reactor that contains a Lattice characterized by a Bose-Einstein condensate can operate for a lone tine: the nuclear energy that is released by the LENR reaction is delocalized throughout the lattice and the expelled particles have little energy to damage the area close to the NAE. The NAEs remain intact and the LENR reaction can repeat many times. When a condensate is not present, the LENR energy is localized and the lattic
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
The Bumpy Road. The binding energy contained inside the nucleus is an uncertain thing; it goes up and down at the whim of quantum mechanics; it varies with the uncertainty principle. This energy is comprised of two parts: a real energy and a virtual energy. It is this virtual energy that can vary widely and is not constrained by the laws of energy and momentum. When constrained inside the nucleus and when this nuclear energy is composed of these two parts get strong enough, it spills over the top of the coulomb barrier and forms a real particle outside the nucleus. This is quantum mechanical tunneling. The virtual part of this spillover energy only lasts for the briefest of instants and immediately goes away and only the real part remains to congeal into the newly radiated particle that has tunneled through the barrier. This process is called radioactive decay (AKA tunneling through the coulomb barrier). After this nuclear relaxation process, if the energy level inside the nucleus has been lowed enough so that it can never again surmount the coulomb barrier no matter how much virtual energy may appear, the element is said to be stable. In regards to LENR, we can draw and amazing and informative conclusion from this behavior of the nuclear reaction. The fact that no radioactive isotopes are found in the ash of the cold fusion reaction is unequivocal proof that LENR is caused by the lowering of the coulomb barrier and NOT a fusion process. That is, when the coulomb barrier is very low during the LENR moment, the energy in the nucleus is stabilized at the lowest barrier level in relation to the lowered coulomb barrier. Now when the barrier neutralization is removed and the barrier springs back to full power, the binding energy contained in the newly formed nucleus is completely relaxed in regards to the newly recovered strength of the coulomb barrier. Here is an analog from the real world to explain this principle. If you take a glass of water filled to the brim on a car trip over a bumpy road, the water will splash over the brim until water reaches a maximum level to where the water does not slash anymore. Now suppose you could magically reduce the sides of the glass to a low level when the bumpy trip first starts and the water level reaches this maximum no spill level, now you magically raise the sides of the glass very high again. No water will ever spill out no matter how bumpy the road gets. The water level in the glass is now forever stable. The nuclear binding energy excess produced by the LENR reaction is spread around the lattice to all the other members of the Bose-Einstein condensate, so both the new nucleus and the expelled particle(s) have little excess energy to dissipate into the localized lattice. These nuclear fragments part ways at a very slow pace with little disruptions on the other NAE around them. This is why a LENR reactor that contains a Lattice characterized by a Bose-Einstein condensate can operate for a lone tine: the nuclear energy that is released by the LENR reaction is delocalized throughout the lattice and the expelled particles have little energy to damage the area close to the NAE. The NAEs remain intact and the LENR reaction can repeat many times. When a condensate is not present, the LENR energy is localized and the lattice is destroyed. The LENR reaction will quickly stop as all the NAEs are cratered. Cheers: Axil On Mon, Mar 25, 2013 at 6:19 PM, wrote: > In reply to Axil Axil's message of Mon, 25 Mar 2013 04:03:34 -0400: > Hi, > [snip] > >You are right. They are in superposition. They are nowhere and everywhere > >at the same time: delocalized. > > > >This is why LENR gammas get thermalized. A fission reaction in a > condensate > >will spread its energy throughout the condensate, > > Most of the energy of a fission reaction is usually carried by the > particles. > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Mon, 25 Mar 2013 04:03:34 -0400: Hi, [snip] >You are right. They are in superposition. They are nowhere and everywhere >at the same time: delocalized. > >This is why LENR gammas get thermalized. A fission reaction in a condensate >will spread its energy throughout the condensate, Most of the energy of a fission reaction is usually carried by the particles. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
For example, the waves in a body of water can coalesce into a big wave in less space than the small waves: a rogue wave. You can’t really tell where those small waves went. They are forever gone as separate entities. But in quantum mechanics, if one of those waves produces energy, all the small waves will reappear as separate waves: decoherence. These small waves expand in dimentionality. http://en.wikipedia.org/wiki/Decoherence The energy that caused them to separate will be spread around in all the small waves as they interface with the environment because they were joined at the time that the energy was produced. You did not ask but I will say, if you look at the last formula in this reference: http://en.wikipedia.org/wiki/Semi-empirical_mass_formula you will see that the many forces that hold the nucleus together are finely tuned and in a delicate balance. In a very stable nucleus like nickel, if the charge coefficient ac in changed in either direction, the nucleus will become unstable and want to reconfigure into a more stable configuration. I call this reconfiguration process fission. Cheers: Axil On Mon, Mar 25, 2013 at 1:02 PM, David Roberson wrote: > Actually, I thought that the wave/particle duality suggests that one can > look at the particle as just a waveform in certain cases which occupies a > large amount of space. If that amount of space is significant, then it > might be easy to hide several particle sized objects in one general wave > region. Is that what we are considering in this discussion? > > Dave > > > -Original Message- > From: mixent > To: vortex-l > Sent: Mon, Mar 25, 2013 3:37 am > Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion > > In reply to Axil Axil's message of Mon, 25 Mar 2013 03:27:46 -0400: > Hi, > [snip] > >Bosons can. That is what a Bose-Einstein condensate is. It is one large > >waveform added together from many small ones. > > One large waveform doesn't necessarily imply that all the composite entities > are > in the same place however. > [snip] > Regards, > > Robin van Spaandonk > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Actually, I thought that the wave/particle duality suggests that one can look at the particle as just a waveform in certain cases which occupies a large amount of space. If that amount of space is significant, then it might be easy to hide several particle sized objects in one general wave region. Is that what we are considering in this discussion? Dave -Original Message- From: mixent To: vortex-l Sent: Mon, Mar 25, 2013 3:37 am Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion In reply to Axil Axil's message of Mon, 25 Mar 2013 03:27:46 -0400: Hi, [snip] >Bosons can. That is what a Bose-Einstein condensate is. It is one large >waveform added together from many small ones. One large waveform doesn't necessarily imply that all the composite entities are in the same place however. [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Since the screening comes from the geometry of the NAE, any elements can fission and/or fusion. It is a nuclear free for all inside the NAE. For example, a light element can become heavier because of subsequent fusion with hydrogen. The large verities of elements found in the transmutation products indicate that charge screening is causing activity in the NAE. Cheers: Axil On Mon, Mar 25, 2013 at 10:23 AM, Axil Axil wrote: > Protons don’t become neutrons, but their collective charge is screened. > This collective charge of all the protons in the nucleus is where the > coulomb barrier comes from. > > When the coulomb barrier is suppressed, there must be a reduction of > charge in each and every proton in the nucleus. > > As this positive charge is reduced, the attraction between protons and > neutrons are decreased. The nucleus will become more unstable. > > See the Semi-empirical mass formula as the Coulomb force is reduced. > > http://en.wikipedia.org/wiki/Semi-empirical_mass_formula > > The nucleus gains more energy as the screening increases. > > As the energy of the nucleus increases, the nucleus will eventually > fission to relieve this energy in order to become more stable. > > This is not to say that fusion is not also going on too. But the light > elements with Z less than that of nickel come mostly from fission. > > > Chees: axil > > On Mon, Mar 25, 2013 at 8:15 AM, OrionWorks - Steven Vincent Johnson < > orionwo...@charter.net> wrote: > >> I'm sure I missed something crucial here. >> >> How do protons in the nucleus lose their positive charge, and as such >> presumably transform into neutrons? >> >> IOW, what is the theorized mechanism(s) involved here? >> >> Regards, >> Steven Vincent Johnson >> www.OrionWorks.com >> www.zazzle.com/orionworks >> tech.groups.yahoo.com/group/newvortex/ >> >> >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Protons don’t become neutrons, but their collective charge is screened. This collective charge of all the protons in the nucleus is where the coulomb barrier comes from. When the coulomb barrier is suppressed, there must be a reduction of charge in each and every proton in the nucleus. As this positive charge is reduced, the attraction between protons and neutrons are decreased. The nucleus will become more unstable. See the Semi-empirical mass formula as the Coulomb force is reduced. http://en.wikipedia.org/wiki/Semi-empirical_mass_formula The nucleus gains more energy as the screening increases. As the energy of the nucleus increases, the nucleus will eventually fission to relieve this energy in order to become more stable. This is not to say that fusion is not also going on too. But the light elements with Z less than that of nickel come mostly from fission. Chees: axil On Mon, Mar 25, 2013 at 8:15 AM, OrionWorks - Steven Vincent Johnson < orionwo...@charter.net> wrote: > I'm sure I missed something crucial here. > > How do protons in the nucleus lose their positive charge, and as such > presumably transform into neutrons? > > IOW, what is the theorized mechanism(s) involved here? > > Regards, > Steven Vincent Johnson > www.OrionWorks.com > www.zazzle.com/orionworks > tech.groups.yahoo.com/group/newvortex/ > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Last public report did not says there was no He4, just that they did not measure them with XRF separately, and they talk of "light element"... The announce of Be and B elements are new, since they were all inside the "light elements" moreover they were testing only the NAE, not all the material This is the table I refer to, published at ICCF17 [image: Images intégrées 1] do you have more recent data ? maybe I missed a paper when looking for... 2013/3/25 Axil Axil > In their report, DEFKALION said they did no isotope analysis, yet they > said there was no transmutation of Ni. > > Also, they did not find Tritium, He3 or He4 among the light elements. They > found lithium, beryllium and boron, though. > > It seems that each LENR reactor r > <>
RE: [Vo]:It is fission dear fellows; clear your minds of confusion
I'm sure I missed something crucial here. How do protons in the nucleus lose their positive charge, and as such presumably transform into neutrons? IOW, what is the theorized mechanism(s) involved here? Regards, Steven Vincent Johnson www.OrionWorks.com www.zazzle.com/orionworks tech.groups.yahoo.com/group/newvortex/
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
You are right. They are in superposition. They are nowhere and everywhere at the same time: delocalized. This is why LENR gammas get thermalized. A fission reaction in a condensate will spread its energy throughout the condensate, On Mon, Mar 25, 2013 at 3:37 AM, wrote: > In reply to Axil Axil's message of Mon, 25 Mar 2013 03:27:46 -0400: > Hi, > [snip] > >Bosons can. That is what a Bose-Einstein condensate is. It is one large > >waveform added together from many small ones. > > One large waveform doesn't necessarily imply that all the composite > entities are > in the same place however. > [snip] > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Mon, 25 Mar 2013 03:27:46 -0400: Hi, [snip] >Bosons can. That is what a Bose-Einstein condensate is. It is one large >waveform added together from many small ones. One large waveform doesn't necessarily imply that all the composite entities are in the same place however. [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Bosons can. That is what a Bose-Einstein condensate is. It is one large waveform added together from many small ones. Cheers: Axil On Mon, Mar 25, 2013 at 3:21 AM, wrote: > In reply to Axil Axil's message of Mon, 25 Mar 2013 03:05:27 -0400: > Hi, > [snip] > >Not when neutrons repeal each other. > > > >Neutrons have spin 1/2 and therefore obey the pauli exclusion principle, > >meaning two neutrons cannot occupy the same space at the same time. > > I think you mean the same state at the same time. I'm not sure that any two > things can occupy the space at the same time. ;) > > >When > >two neutrons' wavefunctions overlap, they feel a strong repulsive force. > >See http://en.wikipedia.org/wiki/Exchange_interaction .. > > > >When electrons are hot, they will repeal more than when they are cold > >because their wave functions are larger. > > When any particle is "hot", it's Be Broglie wavelength is smaller, not > larger. > (h/p). Momentum is in the denominator. > > > > > > >Cheers: Axil > > > >On Mon, Mar 25, 2013 at 2:53 AM, David Roberson > wrote: > > > >> One thing that has bothered me lately is that tritium is unstable wh > each > >> other.ile helium 3 is stable. You take tritium with its two neutrons > and > >> one proton and convert one of the neutrons into a proton and it becomes > >> more stable. That just seems wrong when you end up with a nucleus that > has > >> coulomb repulsion which is more stable than one without. Nature can be > >> cruel. > >> > >> Dave > >> > >> > >> > >> -Original Message- > >> From: Axil Axil > >> To: vortex-l > >> Sent: Mon, Mar 25, 2013 1:58 am > >> Subject: Re: [Vo]:It is fission dear fellows; clear your minds of > confusion > >> > >> As the protons lose their charge, the neutrons in the nucleus become > >> repulsive and push the nucleus apart. > >> You cannot have a nucleus full of neutrons, it just won’t do. > >> Charge screening means neutron repulsion. There is a wide range of > charge > >> screening levels that can happen and an associated nuclear breakup > profile > >> for each level. > >> Cheers: Axil > >> On Mon, Mar 25, 2013 at 1:50 AM, wrote: > >> > >>> In reply to Axil Axil's message of Mon, 25 Mar 2013 01:21:53 -0400: > >>> Hi, > >>> [snip] > >>> >It is fission dear fellows; clear your minds of confusion so forget > about > >>> >fusion and neutron formation. > >>> > >>> ...something has to provide the energy to initiate the fission. > >>> > >>> Regards, > >>> > >>> Robin van Spaandonk > >>> > >>> http://rvanspaa.freehostia.com/project.html > >>> > >>> > >> > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Mon, 25 Mar 2013 03:05:27 -0400: Hi, [snip] >Not when neutrons repeal each other. > >Neutrons have spin 1/2 and therefore obey the pauli exclusion principle, >meaning two neutrons cannot occupy the same space at the same time. I think you mean the same state at the same time. I'm not sure that any two things can occupy the space at the same time. ;) >When >two neutrons' wavefunctions overlap, they feel a strong repulsive force. >See http://en.wikipedia.org/wiki/Exchange_interaction .. > >When electrons are hot, they will repeal more than when they are cold >because their wave functions are larger. When any particle is "hot", it's Be Broglie wavelength is smaller, not larger. (h/p). Momentum is in the denominator. > > >Cheers: Axil > >On Mon, Mar 25, 2013 at 2:53 AM, David Roberson wrote: > >> One thing that has bothered me lately is that tritium is unstable wh each >> other.ile helium 3 is stable. You take tritium with its two neutrons and >> one proton and convert one of the neutrons into a proton and it becomes >> more stable. That just seems wrong when you end up with a nucleus that has >> coulomb repulsion which is more stable than one without. Nature can be >> cruel. >> >> Dave >> >> >> >> -----Original Message- >> From: Axil Axil >> To: vortex-l >> Sent: Mon, Mar 25, 2013 1:58 am >> Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion >> >> As the protons lose their charge, the neutrons in the nucleus become >> repulsive and push the nucleus apart. >> You cannot have a nucleus full of neutrons, it just wont do. >> Charge screening means neutron repulsion. There is a wide range of charge >> screening levels that can happen and an associated nuclear breakup profile >> for each level. >> Cheers: Axil >> On Mon, Mar 25, 2013 at 1:50 AM, wrote: >> >>> In reply to Axil Axil's message of Mon, 25 Mar 2013 01:21:53 -0400: >>> Hi, >>> [snip] >>> >It is fission dear fellows; clear your minds of confusion so forget about >>> >fusion and neutron formation. >>> >>> ...something has to provide the energy to initiate the fission. >>> >>> Regards, >>> >>> Robin van Spaandonk >>> >>> http://rvanspaa.freehostia.com/project.html >>> >>> >> Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
Not when neutrons repeal each other. Neutrons have spin 1/2 and therefore obey the pauli exclusion principle, meaning two neutrons cannot occupy the same space at the same time. When two neutrons' wavefunctions overlap, they feel a strong repulsive force. See http://en.wikipedia.org/wiki/Exchange_interaction .. When electrons are hot, they will repeal more than when they are cold because their wave functions are larger. Cheers: Axil On Mon, Mar 25, 2013 at 2:53 AM, David Roberson wrote: > One thing that has bothered me lately is that tritium is unstable wh each > other.ile helium 3 is stable. You take tritium with its two neutrons and > one proton and convert one of the neutrons into a proton and it becomes > more stable. That just seems wrong when you end up with a nucleus that has > coulomb repulsion which is more stable than one without. Nature can be > cruel. > > Dave > > > > -Original Message- > From: Axil Axil > To: vortex-l > Sent: Mon, Mar 25, 2013 1:58 am > Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion > > As the protons lose their charge, the neutrons in the nucleus become > repulsive and push the nucleus apart. > You cannot have a nucleus full of neutrons, it just won’t do. > Charge screening means neutron repulsion. There is a wide range of charge > screening levels that can happen and an associated nuclear breakup profile > for each level. > Cheers: Axil > On Mon, Mar 25, 2013 at 1:50 AM, wrote: > >> In reply to Axil Axil's message of Mon, 25 Mar 2013 01:21:53 -0400: >> Hi, >> [snip] >> >It is fission dear fellows; clear your minds of confusion so forget about >> >fusion and neutron formation. >> >> ...something has to provide the energy to initiate the fission. >> >> Regards, >> >> Robin van Spaandonk >> >> http://rvanspaa.freehostia.com/project.html >> >> >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
One thing that has bothered me lately is that tritium is unstable while helium 3 is stable. You take tritium with its two neutrons and one proton and convert one of the neutrons into a proton and it becomes more stable. That just seems wrong when you end up with a nucleus that has coulomb repulsion which is more stable than one without. Nature can be cruel. Dave -Original Message- From: Axil Axil To: vortex-l Sent: Mon, Mar 25, 2013 1:58 am Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion As the protons lose their charge, the neutrons in the nucleus become repulsive and push the nucleus apart. You cannot have a nucleus full of neutrons, it just won’t do. Charge screening means neutron repulsion. There is a wide range of charge screening levels that can happen and an associated nuclear breakup profile for each level. Cheers: Axil On Mon, Mar 25, 2013 at 1:50 AM, wrote: In reply to Axil Axil's message of Mon, 25 Mar 2013 01:21:53 -0400: Hi, [snip] >It is fission dear fellows; clear your minds of confusion so forget about >fusion and neutron formation. ...something has to provide the energy to initiate the fission. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
As the protons lose their charge, the neutrons in the nucleus become repulsive and push the nucleus apart. You cannot have a nucleus full of neutrons, it just won’t do. Charge screening means neutron repulsion. There is a wide range of charge screening levels that can happen and an associated nuclear breakup profile for each level. Cheers: Axil On Mon, Mar 25, 2013 at 1:50 AM, wrote: > In reply to Axil Axil's message of Mon, 25 Mar 2013 01:21:53 -0400: > Hi, > [snip] > >It is fission dear fellows; clear your minds of confusion so forget about > >fusion and neutron formation. > > ...something has to provide the energy to initiate the fission. > > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's message of Mon, 25 Mar 2013 01:21:53 -0400: Hi, [snip] >It is fission dear fellows; clear your minds of confusion so forget about >fusion and neutron formation. ...something has to provide the energy to initiate the fission. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
I have always thought that He4 is also a product of increase alpha decay caused by a slight coulomb barrier lowering and not a product of fusion. It is fission all the way, Pd/D and Ni/H. It is tragic that fusion has confused so many excellent minds for so long. Cheers: Axil On Mon, Mar 25, 2013 at 1:33 AM, Eric Walker wrote: > On Sun, Mar 24, 2013 at 10:21 PM, Axil Axil wrote: > >> The reaction should be called cold fission. >> > Yes, it is tempting to think there is fission going on (or perhaps > "cluster decay"). > >> He4 being a gas will escape the nuclear active zone before a fusion >> process can build on it so that a step based transmutation process can get >> to the next higher element in the transmutation chain. >> > 4He is not necessarily mobile in a metal the way H is, so it could > potentially stay put. 4He is normally thought to arise in Pd/D. If Ni/H > is real, there is no consensus that 4He is a product. > > Eric > >
Re: [Vo]:It is fission dear fellows; clear your minds of confusion
On Sun, Mar 24, 2013 at 10:21 PM, Axil Axil wrote: > The reaction should be called cold fission. > Yes, it is tempting to think there is fission going on (or perhaps "cluster decay"). > He4 being a gas will escape the nuclear active zone before a fusion > process can build on it so that a step based transmutation process can get > to the next higher element in the transmutation chain. > 4He is not necessarily mobile in a metal the way H is, so it could potentially stay put. 4He is normally thought to arise in Pd/D. If Ni/H is real, there is no consensus that 4He is a product. Eric
[Vo]:It is fission dear fellows; clear your minds of confusion
In their report, DEFKALION said they did no isotope analysis, yet they said there was no transmutation of Ni. Also, they did not find Tritium, He3 or He4 among the light elements. They found lithium, beryllium and boron, though. It seems that each LENR reactor reflects a unique transmutation profile based on the degree of coulomb barrier lowering that the reactor achieves. The reaction should be called cold fission. It is near impossible for fusion to build up this light transmutation profile of these light elements one neutron or proton at a time in a stepwise repetitive fusion process. Getting past Helium 4 is not possible because it is in an island of inaccessibility. He4 being a gas will escape the nuclear active zone before a fusion process can build on it so that a step based transmutation process can get to the next higher element in the transmutation chain. In these Rossi type reactors, the coulomb barrier is lowered not all the way but just enough for some light nuclear materials to leak out of the Nickel nucleus to form light elements. Rossi reported the same thing. With many of the first 19 lightest elements found in his transmutation products; even though there were many gases in that list of elements. It is fission dear fellows; clear your minds of confusion so forget about fusion and neutron formation. Cheers: Axil