You missed some parentheses
#!/usr/bin/perl
use strict;
use warnings;
open(DATA, '', data) || dieUnable to open the file;
while(DATA) {
#if($_=~/\d{2}-(\d{2}|\w{3})-\d{1,4}/) {
if(/(\d{2}-(\d{2})|(\w{3})-\d{1,4})/) {
print;
}
}
close(DATA);
exit 0;
On
-20009
15-10-2008
(C)/tmp/d$
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of
David Schmidt
Sent: Saturday, November 29, 2008 3:12 PM
To: Sureshkumar M (HCL Financial Services); beginners@perl.org
Subject: Re: date format search insdie
Hi all ,
Can someone help me on this
From: Sureshkumar M (HCL Financial Services)
Sent: Saturday, November 29, 2008 4:21 PM
To: 'David Schmidt'
Cc: beginners@perl.org
Subject: RE: date format search insdie the files
Hi David,
Thanks
Sureshkumar M (HCL Financial Services) schreef:
#/usr/bin/perl
open(DATA,a1)||dieUnable to open the file;
while(DATA)
{
if($_=~/\d{2}-(\d{2}|\w{3})-\d{1,4}/)
{
print $_;
}
}
close(DATA);
exit 0;
#!/usr/bin/perl
use strict;
use warnings;
my $in_name = data.in;
{ open my
5:30 PM
To: beginners@perl.org
Subject: Re: date format search insdie the files
Sureshkumar M (HCL Financial Services) schreef:
#/usr/bin/perl
open(DATA,a1)||dieUnable to open the file;
while(DATA)
{
if($_=~/\d{2}-(\d{2}|\w{3})-\d{1,4}/)
{
print $_;
}
}
close(DATA);
exit 0;
#!/usr
Sureshkumar M (HCL Financial Services) schreef:
Can you explain me this part how it's works?
(?:\d{2}|\w{3})
?: what this will do?
Read perlre (and find out what (?:) means).
And also, the output is like below
(C)/tmp/d$ perl 1
10-11-81
20-NOV-2008
05-07-1981
15-110-2008
Sureshkumar M (HCL Financial Services) schreef:
Can someone help me on this
Impossible.
--
Affijn, Ruud
Gewoon is een tijger.
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2008/11/22 Sureshkumar M (HCL Financial Services) [EMAIL PROTECTED]:
Hi All,
Hi
#!/usr/bin/perl
# Always use these, particularly when things aren't working as expected.
use strict;
use warnings;
open(DATA,i)||die Unable to open the file;
while(DATA)
{
if($_=~/(\d{2})([\W])\1\2\1]/)
Sureshkumar M (HCL Financial Services) wrote:
Hi All,
Hello,
I want to find the string which are having the date inside the
file.
Please help me how do I match it,below is my program and it's not
returning anything.
#!/usr/bin/perl
use warnings;
use strict;
open(DATA,i)||die Unable to
Dermot wrote:
2008/11/22 Sureshkumar M (HCL Financial Services) [EMAIL PROTECTED]:
#!/usr/bin/perl
# Always use these, particularly when things aren't working as expected.
use strict;
use warnings;
open(DATA,i)||die Unable to open the file;
while(DATA)
{
if($_=~/(\d{2})([\W])\1\2\1]/)
On Nov 22, 6:16 am, [EMAIL PROTECTED] (Dermot) wrote:
2008/11/22 Sureshkumar M (HCL Financial Services) [EMAIL PROTECTED]:
Hi All,
Hi
#!/usr/bin/perl
# Always use these, particularly when things aren't working as expected.
use strict;
use warnings;
open(DATA,i)||die Unable to
[EMAIL PROTECTED] wrote:
I have this code:
my ($month, $day, $year) = (localtime)[4,3,5];
printf (%02d/%02d/%02d\n, $month+1,$day,$year+1900);
which gives me
08/16/2004
what I want is 08/16/04.
perldoc -f localtime describes very clearly how you get a two digit
year. It's advisable to study the
[EMAIL PROTECTED] wrote:
All,
I have this code:
my ($month, $day, $year) = (localtime)[4,3,5];
printf (%02d/%02d/%02d\n, $month+1,$day,$year+1900);
which gives me
08/16/2004
what I want is 08/16/04. Should I just use Posix with strftime or is
there a quicker way w/out having to
On Mon, 16 Aug 2004 [EMAIL PROTECTED] wrote:
I have this code:
my ($month, $day, $year) = (localtime)[4,3,5];
printf (%02d/%02d/%02d\n, $month+1,$day,$year+1900);
which gives me
08/16/2004
what I want is 08/16/04. Should I just use Posix with strftime or is
there a quicker way w/out having to
Bob Showalter wrote:
($year + 1900) % 100
Actually just
$year % 100
is valid. The former makes it clearer what you're doing, if you're into that
:~)
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[EMAIL PROTECTED] wrote:
All,
I have this code:
my ($month, $day, $year) = (localtime)[4,3,5];
printf (%02d/%02d/%02d\n, $month+1,$day,$year+1900);
which gives me
08/16/2004
what I want is 08/16/04. Should I just use Posix with strftime or is
there a quicker way w/out having to load the
], [EMAIL PROTECTED]
cc:
Subject:RE: date format
Bob Showalter wrote:
($year + 1900) % 100
Actually just
$year % 100
is valid. The former makes it clearer what you're doing, if you're into
that
:~)
Flemming Greve Skovengaard wrote:
printf (%02d/%02d/%02d\n, $month + 1, $day, $year - 100);
# Only works when $year 1999.
And when $year = 2099 :~)
Stick to $year % 100;
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Bob Showalter wrote:
Flemming Greve Skovengaard wrote:
printf (%02d/%02d/%02d\n, $month + 1, $day, $year - 100);
# Only works when $year 1999.
And when $year = 2099 :~)
Stick to $year % 100;
Yes, you are correct. Your solution is fool proof.
--
Flemming Greve Skovengaard FAITH, n.
, $month + 1, $day, ($year %100));
}
while (D)
if ( $_ =~ $foodate) {
.
}
Flemming Greve Skovengaard [EMAIL PROTECTED]
08/16/2004 02:58 PM
To: [EMAIL PROTECTED] [EMAIL PROTECTED]
cc: Bob Showalter [EMAIL PROTECTED]
Subject:Re: date format
Bob
On Mon, 16 Aug 2004 [EMAIL PROTECTED] wrote:
sub datemanip
A name like that screams a need for the Date::Manip CPAN module:
http://search.cpan.org/~sbeck/DateManip-5.42a/Manip.pod
Look over the docs for that module, see if you can't use it to do what
you need to do, and let the list know if you
[EMAIL PROTECTED] wrote:
I have this value, from the date format solution emails, in a subroutine
and I want to pass it to a if clause, how would I go about this?
Can I assign a literal such as
sub datemanip {
my ( $month, $day, $year) = (localtime)[4,3,5];
my $foodate =
Jeff,
Check out
http://www.users.voicenet.com/~corr/macsupt/macperl/localtime.html
Steve
On Fri, Mar 12, 2004 at 01:38:28PM -0800, Jeff Westman wrote:
Is there a way in perl to get the month/day/year using localtime
WITHOUT using 'use POSIX qw(strftime)' or a system date call.
On Fri, 12 Mar 2004, Jeff Westman wrote:
Is there a way in perl to get the month/day/year using localtime
WITHOUT using 'use POSIX qw(strftime)' or a system date call.
Something using slices, maybe something like:
print scalar ((localtime(time))[4,3,7])
expecting the result to
Troy May wrote:
Hello, this guy finally emailed his script to me. The problem he is having
is with $year. Here's the dating part of the code:
---
$date = `/bin/date`;
chop($date);
has this guy considered using Date::Calc?
[ Don't Cc: me, I read this mailing list, thank you ]
Troy May [EMAIL PROTECTED] writes:
($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime;
$thisday = (Sun,Mon,Tue,Wed,Thu,Fri,Sat)[(localtime) [6]];
$s = (localtime)[0];
$m = (localtime)[1];
$m = ($m + 35) ;
Is
$year is a number. Numbers do not retain leading zeros. $year %= 100; does
not return the string 02; it returns the number 2. Try something like
this -
$s_year = sprintf(%02u, $year);
print $s_year;
The sprintf function basically converts the number into a string.
sprintf returns a string
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