Re: How lo load a model from a model?

2012-03-08 Thread phpMagpie
Is there a benefit/drawback to using ClassRegistry::init('Objekt')->translateStrings($results); in this situation? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their Ca

Re: How lo load a model from a model?

2012-03-06 Thread Rodrigo Rodrigues Moyle
Use: $this->load('Objeckt); instead of App::uses() Em terça-feira, 6 de março de 2012 08h14min42s UTC-3, heohni escreveu: > > Hi, > > class DetailsController extends AppController{ > var $name = 'Detail'; > > public function index($id){ > if($id){ > $results = $this->Detail->find('first', $co

Re: How lo load a model from a model?

2012-03-06 Thread Jeremy Burns | Class Outfit
Put in a Behaviour and apply the behaviour to each model that needs to use it. Jeremy Burns Class Outfit http://www.classoutfit.com On 6 Mar 2012, at 11:37:03, heohni wrote: > No there is not. > But I just found out that I can use it this way: > > $results = Objekt::translateStrings($results);

Re: How lo load a model from a model?

2012-03-06 Thread heohni
No there is not. But I just found out that I can use it this way: $results = Objekt::translateStrings($results); But - the function translateStrings() is using inside a call to $this->ExtractUet() and now it happens that I get the message *Fatal error*: Call to undefined method DetailsControl

Re: How lo load a model from a model?

2012-03-06 Thread Jeremy Burns | Class Outfit
Is there a model association between the two models? If so, you can daisy chain them: $results = $this->Detail->Objekt->translateStrings($results);debug($results); Jeremy Burns Class Outfit http://www.classoutfit.com On 6 Mar 2012, at 11:14:42, heohni wrote: > Hi, > > class DetailsControlle

How lo load a model from a model?

2012-03-06 Thread heohni
Hi, class DetailsController extends AppController{ var $name = 'Detail'; public function index($id){ if($id){ $results = $this->Detail->find('first', $conditions['Gesamtobjekt']); App::uses('Objekt', 'Model'); $results = $this->Objekt->translateStrings($results);debug($results); } }