Thanks Stephen
I did a cake bake all (auto) which generated all the models- in hindsight
perhaps manually coding them would have been an advantage?
I used dogmatic69(.com) yesterday and it told me there was about 3 tables which
were named incorrectly: it would of been nice for cake bake to
No problem Paul
The dogmatic69 website seems like a good resource, plural tables, singular
foreign keys (underscored followed by _id) and usually a good idea to add
created DATETIME and modified DATETIME to each table (with the exception of
hasAndBelongsToMany etc)
Hopefully this will work out
Should i just move everything to a different controller? surely there must
be a way to do the association i need right in/before the query??
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hi paul
if you are using recursive =1 in you queries you won't get all the info you
need. I suggest you look at containable behaviour. ]
http://book.cakephp.org/2.0/en/core-libraries/behaviors/containable.html
BTW Its makes no odds which controller calls the model function.
On 11 Sep 2014, at
Cheers for that Mike,
I tried containing and ran into lots of different issues, I then spent
about half an hour writing a REALLY UGLY javascript client side hack to do
my lookup for me (against a different set of results), it was fast becoming
a farce (see what i did there?)
Would you be
Hi Paul
I notice you've got both DeviceRepairs and DeviceRepair within your
associations, this is likely your issue.
It's convention to have a singular model name i.e. *DeviceRepair,
RepairType*, a plural controller name i.e. *DeviceRepairsController,
RepairTypesController* and a plural table
I think it's also worth mentioning that you don't need to define all the
parameters of an association if you're not overwriting the default values,
this can be a good way to test if you've set up your associations correctly.
public $belongsTo = array(
'DeviceType'
);
I will also note that
Any thoughts are welcome at all - I've managed to run the chained query in
a different controller so I'm now sure it's my has many/belongs to rules -
But after trying some (even more) ideas with the relationships i'm still
getting the error relating to a non object when i try it in the
Hi Guys,
I've been trying to get this query going for a couple of days - I wrote
some really hacky (non cakey php) code to lookup a 'name' field given the
'id' field that I *am* getting out of the query - it sort of worked but it
was a real mess.
I know that this can be done, and it can be
Hi,
I know that it is always recommended to use find() instead of custom SQL,
but I have a use case where I need to use a custom prepared statement.
Problem is, it always returns bool(true) instead of a results array, even
if I'm just doing a very basic SELECT with nothing complex going
statement.
Problem is, it always returns bool(true) instead of a results array, even
if I'm just doing a very basic SELECT with nothing complex going on in the
query. Is this a bug or am I using the function wrong?
Here's an example of code that would return bool(true) as shown by
dump_var
an array with ['A'] and all the data
which should go to A.
I already disabled any beforeSave and validation rules, but still no save.
My question: How can I see with which sql statement Cake tries to add
the data to my table? All I found is ways to see the select statements,
but none for inset
You should be able to set debug level to 2 and see all statement types.
On Feb 2, 2013 12:58 PM, Anja Liebermann c...@anjaliebermann.de wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hello everybody,
I need help to find out why my model isn't saving. I use version 1.3.14
and develop
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hi Jonathan,
debug 2 ( or also 3) only shows me the SELECT statements, but not the
INSERT statements.
Calamity Jane
Am 02.02.2013 20:01, schrieb Jonathan Sundquist:
You should be able to set debug level to 2 and see all statement types.
On Feb
:
You should be able to set debug level to 2 and see all statement types.
On Feb 2, 2013 12:58 PM, Anja Liebermann c...@anjaliebermann.de
wrote:
Hello everybody,
I need help to find out why my model isn't saving. I use version 1.3.14
and develop with Cake since some years
, but not what I intended.
Also no further information to find in
tail -f /var/www/myapp/tmp/logs/debug.log
tail -f /var/www/myapp/tmp/logs/error.log
When I try the mentioned method in the post for the app_model I get as
last request a select statement searching for the slug I implemented.
Strange
solved,...
On Friday, November 23, 2012 9:53:16 PM UTC-8, Chris wrote:
hi guys,...
is there a way of show group, blog, photo,... whichever comes in in
notification table
I have a view of:
?php $i = 0 ?
?php foreach($notes as $note): ?
?php echo
hi guys,...
is there a way of show group, blog, photo,... whichever comes in in
notification table
I have a view of:
?php $i = 0 ?
?php foreach($notes as $note): ?
?php echo $html-link($groupBannerShow-square($note), '/groups/view/' .
$note['Group']['id'], array('escape'=false)) ?
?php
belongs to
rent-time.
in table for rent-time there are two timestamps (start and end).
now i want to modify every find-statement for model car and add a
subquery like this:
select *, (select id from rent-time where start gt;= time() and
end lt;= time
Hi,
i have a model which belongs to another like model car belongs to
rent-time.
in table for rent-time there are two timestamps (start and end).
now i want to modify every find-statement for model car and add a subquery
like this:
select *, (select id from rent-time where start = time
Thanks people.
I debug, it returns null :/
Means something is wrong in code.
Here is my controller:
?php
class IndexsController extends AppController {
public $helpers = array('Html', 'Form', 'Session');
public $components = array('Session');
public function index() {
//
sry, what you are doing there is just horrible. I cannot find any other
words for it.
please go through tutorials and the book first
your code is a mess in multiple ways
and it doesnt seem you have understood a single bit of what i wrote. you
cannot just use those deep arrays in php functions.
Yeah, dear euromark. I completely agree with you. I know i should and I'm
planning start this week.
Just I have a small php code and need to do it with cake.
ANyways, thanks for reply.
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To post to this
Hi ppl...
I'm an absolute beginner in programming and what I ask, maybe is very
simple, but i need it very much and soon :)
So the problem is in if statement
I write
$this-set('position', 0);
if(in_array($_GET['var'], $this-Word-findById(11)))
{
$this-set('position', $this-array_search($_GET
Hi ppl...
I'm a beginner in programming, and I know what i ask my seem too simple, I
just need it too much and soon :)
there is a problem in in statement.
$this-set('position', 0);
if(in_array($_GET['var'], $this-Word-findById(11)))
{
$this-set('position', $this-array_search($_GET['
var
Hi,
It means that either the word you are searching is in first position,
that's why its echoing 0 or (in_array($var_get, $word ) is empty ,meaning
$var_get is not inside the array $word.
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To post to
you should firstly debug your variables properly
using debug() you would find out that the result returned by
findBySomething is a deep array (not a flat one)
from there I am certain you will figure it out
Am Freitag, 31. August 2012 11:44:26 UTC+2 schrieb marco metal:
Hi,
It means that
just in case you are unaware in core.php
Configure::write('debug', 2);
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(i.e., member, as opposed to admin?
Note: I do NOT want to hear about routes. That might be the right way to
go generally, but in this case it's not. I just want to know how to do an IF
statement in the index action that will redirect the user to the view
action.
Thank you.
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the index action to the view action if the
user has a particular role (i.e., member, as opposed to admin?
Note: I do NOT want to hear about routes. That might be the right way to
go generally, but in this case it's not. I just want to know how to do an
IF statement in the index action
an IF
statement in the index action that will redirect the user to the view
action.
Thank you.
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with their CakePHP related questions
: I do NOT want to hear about routes. That might be the right way to
go generally, but in this case it's not. I just want to know how to do an
IF statement in the index action that will redirect the user to the view
action.
Thank you.
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Hi,
In my model I would like to add $hasMany after checking the
availability of the other model first (which is in a plugin), so
something like this:
if (condition) {
public $hasMany = array(
...
}
Can someone tell me how this is done?
Thanx in advance.
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public function __construct($id = false, $table = null, $ds = null) {
parent::__construct($id, $table, $ds);
if (App::import('Model', 'PluginName.ModelName')) {
$this-bindModel(array(
'hasMany' = array(
'PluginName.ModelName'
)
),
Perhaps the result from the second find is empty, because the article is
not active? Also, I can't tell from the view code snippet, but if you're
expecting one result then you'll have a problem because find('all') returns
multiple in the following format:
when fetch articles and comments i use this function
function view($id=null) {
$article = $this-Article-findById($id);
$comment = $this-Article-Comment-find('all',
array('conditions' =
array('Comment.article_id' = $id, 'Comment.status' = 1)));
I know why it's not working, I just cannot figure out how to fix it.
These are my errors:
1. Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'id'
in 'where clause'
2. SQL Query: SELECT `Period`.`period_id`, `Period`.`title`,
`Period`.`created`, `Period`.`modified`,
It looks like the issue is with your non-standard database structure, perhaps.
On your Model/Period.php model, set the primary key to be 'period_id' since
that looks like your primary key:
class Period extends AppModel {
public $primaryKey = 'period_id';
/// Other code here...
}
Let me clarify...
private function isActionable($id)
{
if($this-Session-read('Auth.User.role') == 'admin'){
return true;
}
$post = $this-Period-find('first', array(
'conditions' = array(
'id' = $id,
Actually, that worked... It's perfect
As far as database structure... would this be a standard way of
structuring my tables?
Table 1 (users)
id usernamepassword
Table 2 (posts)
id postuser_idtype_id
Table 3 (types)
type_idtype_name
On Nov 29, 5:48 pm, Graham Weldon
Yeah, so the conventions approach would be to use:
Primary Key: id (int 11, or char 36)
Foreign Key: name_id (int 11 or char 36) where name is the singular name of a
model.
Example:
CREATE TABLE `posts` (
`id` CHAR(36) NOT NULL PRIMARY KEY,
`user_id` CHAR(36) NOT NULL,
`name`
http://book.cakephp.org/view/1237/Custom-Query-Pagination explains how to
implement custom pagination logic.
On Thu, Sep 29, 2011 at 12:55 AM, heohni
heidi.anselstet...@consultingteam.de wrote:
Hi,
I have to use a own sql statement:
$results = $this-Bookmark-query('
SELECT
Hi,
I have to use a own sql statement:
$results = $this-Bookmark-query('
SELECT
DISTINCT OBJ_NUMMER
FROM
Gesamtobjekt
WHERE obj_id IN ($variableIDs) AND eia_id IN (SELECT
les_fkid_eia_id FROM Link_eia_static
wrote:
On May 11, 2011, at 10:45,varaiwrote:
the onclick statement in the following code is giving an error:
Parse error: parse error, expecting `')'' in C:\wamp\www\merry_flowers
\views\pages\faq.ctp on line 13
div id=questionDiv?php echo $this-Html-link('Q.Are admissions
to Merry
On May 12, 2011, at 02:22, varai wrote:
By the way, do you know on what is the difference between
$this-Html-link and $html-link?
$html-link() was used in CakePHP 1.2 and earlier. As of CakePHP 1.3
the new preferred way to write it is $this-Html-link(). See the first
paragraph here:
Ok, I got it. Thanks.
On May 12, 11:02 pm, Ryan Schmidt google-2...@ryandesign.com wrote:
On May 12, 2011, at 02:22,varaiwrote:
By the way, do you know on what is the difference between
$this-Html-link and $html-link?
$html-link() was used in CakePHP 1.2 and earlier. As of CakePHP 1.3
Hi
the onclick statement in the following code is giving an error:
Parse error: parse error, expecting `')'' in C:\wamp\www\merry_flowers
\views\pages\faq.ctp on line 13
div id=questionDiv?php echo $this-Html-link('Q.Are admissions
to Merry Flowers program open throughout the
year?','#',array
On May 11, 2011, at 10:45, varai wrote:
the onclick statement in the following code is giving an error:
Parse error: parse error, expecting `')'' in C:\wamp\www\merry_flowers
\views\pages\faq.ctp on line 13
div id=questionDiv?php echo $this-Html-link('Q.Are admissions
to Merry Flowers
Ok you're right! But I have the need to use the data for later
processing
So regarding the view, I use pagination, that is ok! But I am still
thinking about an solution for the later steps.
On 31 Mrz., 20:40, cricket zijn.digi...@gmail.com wrote:
On Thu, Mar 31, 2011 at 8:15 AM, Jeremy
On Fri, Apr 1, 2011 at 8:42 AM, heohni
heidi.anselstet...@consultingteam.de wrote:
Ok you're right! But I have the need to use the data for later
processing
So regarding the view, I use pagination, that is ok! But I am still
thinking about an solution for the later steps.
If you have
Hi,
I have the following models:
Member hasMany Payments
Payment belongs to a member
To get now all members and their payments I do the following
statement:
$this-paginate = array(
'fields' = array(.),
'conditions' = array(...),
'contain' = array
to a member
To get now all members and their payments I do the following
statement:
$this-paginate = array(
'fields' = array(.),
'conditions' = array(...),
'contain' = array(
'Payment' = array(
'fields' = array
a LEFT JOIN, I get nicer statement, but loosing the sorted
result, as the array will look like:
Array
(
[0] = Array
(
[Member] = Array
(
[id] = 5
)
[Payment] = Array
(
[id
)
)
)
Which is really perfect for me.
I am just worried about the performance later when the number of
member is raising.
If I do a LEFT JOIN, I get nicer statement, but loosing the sorted
result, as the array will look like:
Array
(
[0] = Array
nicer statement, but loosing the sorted
result, as the array will look like:
Array
(
[0] = Array
(
[Member] = Array
(
[id] = 5
)
[Payment] = Array
(
[id] = 3270
the performance later when the number of
member is raising.
If I do a LEFT JOIN, I get nicer statement, but loosing the sorted
result, as the array will look like:
Array
(
[0] = Array
(
[Member] = Array
(
[id] = 5
On Thu, Mar 31, 2011 at 8:15 AM, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
If you are returning this data to display on a view you wouldn't want to show
this much data,
so you'd use pagination which cuts down the number of rows returned. This
won't apply if
you are
Chris:
After reviewing your code snippets, here are some of my
recommendations:
1) Instead of defining your classes as:
Video
- belongsTo VideoCategory
- belongsTo User
- hasMany VideoComment
- hasMany VideoFavorite
VideoFavorite
- belongsTo User
- belongsTo Video
User
- hasMany Video
-
Hi Shadow,
and again Thank you so much, but in some point it still unclear for me
what to do exactly, I have tried it tried it,... and not giving up...!
lol You sound like one of the Senior Programmer in here. I would like
to ask you if you can take a look of my script,... I will give you
access
Hi Chris:
In the simplest scenario, where the user is viewing one video at a
time:
- you have the Video id (passed as a parameter to the action, i.e.
http://www.example.com/app/videos/view/123)
- you have the User id ($this-user['id'] from your previous code
snippets)
- you can use the find()
some group, or video,...
the button to Add to Favorites MUST BE REPLACED WITH Remove
Favorites
I want to know how to make that statement in php... I don't know
how... lol I'm still a newbie,... but have some experiance from long
time ago. And what I'm doing is creating Social Network site
Hi Shadow,
Thank you for your help and try, ...
here are the tables say for Videos Favorite Feature:
videos Table:
id int(11) UNSIGNEDNo auto_increment
user_id int(11) Yes NULL
category_id int(11)
;
//better choice
if (isset($this-params['controller']) $this-controller == 'gifts')
{
}
}}}
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Lep pozdrav, Tilen Majerlehttp://majerle.eu
2011/2/7 chris...@yahoo.com chris...@yahoo.com
Hi guys,...
how u ding...
I need help with php statement. I'm
/7 chris...@yahoo.com chris...@yahoo.com
Hi guys,...
how u ding...
I need help with php statement. I'm getting an error:
Parse error: syntax error, unexpected ';' in /home/zipmaniak/
zippopeople.com/html/app/views/gifts/admin_manage.ctp on line 93
?php
that statement in php... I don't know
how... lol I'm still a newbie,... but have some experiance from long
time ago. And what I'm doing is creating Social Network site, and with
little or no knowlllege at all do so far this much. Can you PLEASE
help me with my project??
Or anyone... ??
Here is my
that statement in php... I don't know
how... lol I'm still a newbie,... but have some experiance from long
time ago. And what I'm doing is creating Social Network site, and with
little or no knowlllege at all do so far this much. Can you PLEASE
help me with my project??
Or anyone... ??
Here is my
Favorites
I want to know how to make that statement in php... I don't know
how... lol I'm still a newbie,... but have some experiance from long
time ago. And what I'm doing is creating Social Network site, and with
little or no knowlllege at all do so far this much. Can you PLEASE
help me
Chris:
I find it extremely difficult to make any recommendations without
additional details, particularly:
- the associations you defined in your User and Video models
- the code in the controller/action that will be used to retrieve the
information from the model(s)
- the code (or snippet) of
Hi guys,...
how u ding...
I need help with php statement. I'm getting an error:
Parse error: syntax error, unexpected ';' in /home/zipmaniak/
zippopeople.com/html/app/views/gifts/admin_manage.ctp on line 93
?php if(!(array_key_exists($gift['GiftCategory']['name'])) ?
Please some one help me
As the error says;
?php if(!(array_key_exists($gift['GiftCategory']['name'])); ?
Sent from my iPad
On 7 Feb 2011, at 05:56, chris...@yahoo.com chris...@yahoo.com wrote:
Hi guys,...
how u ding...
I need help with php statement. I'm getting an error:
Parse error: syntax error
== 'gifts')
{
}
}}}
--
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http://majerle.eu
2011/2/7 chris...@yahoo.com chris...@yahoo.com
Hi guys,...
how u ding...
I need help with php statement. I'm getting an error:
Parse error: syntax error, unexpected ';' in /home/zipmaniak/
zippopeople.com/html/app/views
['controller']) $this-controller == 'gifts')
{
}
}}}
--
Lep pozdrav, Tilen Majerlehttp://majerle.eu
2011/2/7 chris...@yahoo.com chris...@yahoo.com
Hi guys,...
how u ding...
I need help with php statement. I'm getting an error:
Parse error: syntax error, unexpected ';' in /home
statement. I'm getting an error:
Parse error: syntax error, unexpected ';' in /home/zipmaniak/
zippopeople.com/html/app/views/gifts/admin_manage.ctp on line 93
?php if(!(array_key_exists($gift['GiftCategory']['name'])) ?
Please some one help me with this... or if I have to call from
video_id int(11) UNSIGNEDNo 0
user_idint(11) No 0
video_user_id int(11) UNSIGNEDNo 0
created
where video_user_id is original video poster.
I need to create this statement
e.g. ?php if(($favorite['VideoFavorite
No 0
user_id int(11) No 0
video_user_id int(11) UNSIGNED No 0
created
where video_user_id is original video poster.
I need to create this statement
e.g. ?php if(($favorite['VideoFavorite']['user_id'] == )): ? ...??
I don't know how
int(11) No 0
video_user_id int(11) UNSIGNED No 0
created
where video_user_id is original video poster.
I need to create this statement
e.g. ?php if(($favorite['VideoFavorite']['user_id'] == )): ? ...??
I don't know how... lol
Thank You All
video poster.
I need to create this statement
e.g. ?php if(($favorite['VideoFavorite']['user_id'] == )): ? ...??
I don't know how... lol
Check against $this-Session-read('Auth.User.id').
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, chris...@yahoo.com chris...@yahoo.com wrote:
Hi guys,
I wanna to make a statement in ../views/resume/view.ctp
I have a table named: resume
id int(11) UNSIGNED No auto_increment
user_id int(11) Yes NULL
name varchar(120
Hi guys,
I wanna to make a statement in ../views/resume/view.ctp
I have a table named: resume
id int(11) UNSIGNEDNo auto_increment
user_idint(11) Yes NULL
name varchar(120)latin1_swedish_ci No
content
On Sun, Jan 23, 2011 at 5:59 PM, chris...@yahoo.com chris...@yahoo.com wrote:
Hi guys,
I wanna to make a statement in ../views/resume/view.ctp
I have a table named: resume
id int(11) UNSIGNED No auto_increment
user_id int(11) Yes
No cricket,... no,.. no,... there is no java issue that I have.
All I want is to make a statement to hide Create Resume link when
resume is created, and show links to Edit Resume and Delete
Resume .
Please,... anyone help...
Thanks
Chris
On Jan 23, 4:21 pm, cricket zijn.digi...@gmail.com wrote
make your display link dependent on the action.
On 24/01/2011, chris...@yahoo.com chris...@yahoo.com wrote:
No cricket,... no,.. no,... there is no java issue that I have.
All I want is to make a statement to hide Create Resume link when
resume is created, and show links to Edit Resume
make your nav display links dependent on the action.
On 24/01/2011, chris...@yahoo.com chris...@yahoo.com wrote:
No cricket,... no,.. no,... there is no java issue that I have.
All I want is to make a statement to hide Create Resume link when
resume is created, and show links to Edit Resume
'];
endforeach;
?
/span
/div
i dont need the loop, do I!!
the SELECT statement would now be without further restrictions in my
WHERE clause. it finds all entries . but i just wanna have the user
($users as $user):
echo $user['User']['firstname'];
endforeach;
?
/span
/div
i dont need the loop, do I!!
the SELECT statement
'];
endforeach;
?
/span
/div
i dont need the loop, do I!!
the SELECT statement would now be without further restrictions in my
WHERE clause. it finds all entries . but i just wanna
):
echo $user['User']['firstname'];
endforeach;
?
/span
/div
i dont need the loop, do I!!
the SELECT statement would now be without further
Hi, is it possible to do prepared statement in cake??
http://dev.mysql.com/doc/refman/5.0/en/sql-syntax-prepared-statements.html
if so, how?
Thanks
Tomas
Check out the new CakePHP Questions site http://cakeqs.org and help others with
their CakePHP related questions.
You received
Is there any PDO support in cake? PDO is able to prepare and execute
statements...
http://www.php.net/manual/en/pdo.prepared-statements.php
On 12 dub, 11:39, toka...@gmail.com toka...@gmail.com wrote:
Hi, is it possible to do prepared statement in cake??
http://dev.mysql.com/doc/refman/5.0
I am getting the SQL error below but its not showing me the actual SQL
statement that Cake is generating. Is there any way of seeing what it is?
Warning (512): SQL Error: 1064: You have an error in your SQL syntax; check
the manual that corresponds to your MySQL server version for the right
I am getting the SQL error below but its not showing me the actual SQL
statement that Cake is generating. Is there any way of seeing what it is?
Turn on debug mode.
http://cake-php.blogspot.com/2006/09/21-things-you-must-know-about-cakephp.html
Wayne
Check out the new CakePHP Questions site
it to the DB as an
SQL statement. It's possible that Cake's virtual modeling (or whatever
it's called) is the culprit. It could be that your SpecialsController
isn't properly seeing the Special model and so is relying on AppModel,
which doesn't know about your method. To tell the truth, I can't
remember
It turns out I did have a mix of cases. Sorted that out now thanks. Have
another issue though:
When I try to add a new entry for my page's comments, I am returned to the
main page (which is what I want), but the main page is blank!? I then have
to refresh the page (usually I can only do it by
Greetings,
I am a bit new to cake, and am diving in via the cookbook. I have a
simple app I am trying to develop, and am modifying the cookbook
example to fit it. So far everything has worked great with one
exception. I have an edit form that when I go to it it fills in with
the DB data from the
Hi,
I'm guessing your primary key field is misspelled? You could try
replacing ID with id (lower case).
Cheers,
OJ
On Nov 10, 2:26 am, dpinion dpin...@gmail.com wrote:
Greetings,
I am a bit new to cake, and am diving in via the cookbook. I have a
simple app I am trying to develop, and am
Hi all,
I am having some difficulty finding a cakePHP solution to this MySQL
statement:
SELECT `id`, `issue_date` FROM icapsdb3.print_issues where id =2043
limit 45,1
Can somebody help me please?
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You received this message because you
to get a much clear idea
http://book.cakephp.org/view/456/query
On Tue, Jul 14, 2009 at 11:39 AM, liaogz82 liaog...@gmail.com wrote:
Hi all,
I am having some difficulty finding a cakePHP solution to this MySQL
statement:
SELECT `id`, `issue_date` FROM icapsdb3.print_issues where id
all,
I am having some difficulty finding a cakePHP solution to this MySQL
statement:
SELECT `id`, `issue_date` FROM icapsdb3.print_issues where id =2043
limit 45,1
Can somebody help me please?
--~--~-~--~~~---~--~~
You received this message because you
to this MySQL
statement:
SELECT `id`, `issue_date` FROM icapsdb3.print_issues where id =2043
limit 45,1
Can somebody help me please?
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To post to this group
Hi, I want to see wat sql statement made in back by cake ORM? How can
I get that?
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