this should work:
$(frames['Theiframe']).attr('src', new_page_url);
On Tue, Sep 15, 2009 at 4:45 PM, ximo wallas wrote:
>
> How can I tell to the iframe to load() a different content from the main
> document?
>
> --- On Tue, 9/15/09, Paolo Chiodi wrote
7;Theiframe']).get(0).contentWindow.$('#login')
BTW, you can access child dom only if in same domain
Paolo
On Tue, Sep 15, 2009 at 10:53 AM, ximo wallas wrote:
>
> After 1 day googling and trying I find no agreement in a solid method for
> comunicating with iframe, this is
maybe:
$(data).find('#xyz title').text();
On Fri, Aug 28, 2009 at 7:44 PM, jeanluca wrote:
>
> Hi All
>
> I'm truggling with this for a while now, without succes. Here is the
> test code:
>
> $.ajax({
> type: "GET",
> url: url,
> cache: false,
> dataType: 'xml
To open a window you must use window.open. With jquery you have a
better way to add the event handler.
$('a').click(function(ev){
window.open('/plans/individual/continue-to-ap-pop.asp',
'Continue_to_Application','width=200,height=400');
ev.preventDefa
Sound strange to me. $({your selector}) should acces the html dom
document, not the xml document.
And what is the xmlData variable? You can youse createElement if it is
the xml dom document, not if it is a jqery object
On Fri, Aug 28, 2009 at 7:59 AM, g...@iec wrote:
>
> Hi Paolo,
>
>
maybe the hover is generated more than once while it is sliding.
I would try to add a callback on animation end, setting tha state of
the menu: open or closed.
then on mouse over animate only if open, on mouse out close only if closed
On Fri, Aug 28, 2009 at 12:01 PM, Mario wrote:
>
> Toggle work
try $('#first_input').css('background-color', null)
On Fri, Aug 28, 2009 at 12:23 PM, dziobacz wrote:
>
> I have inputs with validationin in jquery. If data are wrong I make
> red background color in input:
> $('#first_input').css('background-color', 'red');
>
> After click reset I would like to
n: prepend automatically insert the element as
the first child (opposite of append that insert the element as the
last)
On Thu, Aug 27, 2009 at 8:02 AM, Fabio wrote:
>
> Hi Paolo ,
>
> I Tried perpending
>
> like this
>
>
> var errImg = '/img/errIcon.gif'
$(document).ready(function(){
img=$(".img");
img.each(function(i){
var imga = $(this).attr("href");
$("#imgbox").append("");
});
});
Paolo
On Thu, Aug 27, 2009 at 4:08 AM, Jottae wrote:
> $(document).ready(function(){
> img=$(&q
quite simple. instead of setting the color to green in the :active
class, just use jquery.hover to set the color. Maybe when you hover
the submenu you set yhe color, when exit the submenu set the color to
default
Paolo
On Thu, Aug 27, 2009 at 2:52 PM, Karen Morales wrote:
> Hi
>
> I w
obal variable on
> change in form data from any other function.
>
> On Aug 26, 3:47 pm, Paolo Chiodi wrote:
>> You don't have to use xmlData, which is the jquery object, but data
>> which is the xml dom (if you set xml as type of the request)
>>
>> Paolo
>
$("."+errId).prepend('');
On Wed, Aug 26, 2009 at 5:45 AM, Fabio wrote:
> $("."+errId)
one way could be $('div.pic:eq(1)').find('ul li a:eq(2))
Paolo
On Wed, Aug 26, 2009 at 12:17 PM, Bart wrote:
>
> Hi all,
>
> In a HTML document I'm having a few divs with the same class. In each
> of this divs is nested an unordered list with inside the list
You don't have to use xmlData, which is the jquery object, but data
which is the xml dom (if you set xml as type of the request)
Paolo
On Wed, Aug 26, 2009 at 12:35 PM, g...@iec wrote:
>
> Thanks for your reply.
> But this is not working.The data which i got as a result from
ritten in the html
(never tried to see with firebug some differen orders?).
Otherwise if you create the style attribute by using .css('A','B'),
you can't be sure of what the entire style attribute could be.
Paolo
On Tue, Aug 25, 2009 at 11:22 PM, John wrote:
>
> Thanks M
live is no longer a plugin, but core of jquery
Paolo
On Wed, Aug 26, 2009 at 10:14 AM, Leonard
Martin wrote:
>
> You will either need to use the live plugin as follows:
>
> $('#thumbs a').live('click',function(){...});
>
> Or move the binding of your &
when you do document.createElement you create an element that is child
of "document" document.
Try to create the element with data.createElement.
Paolo
On Wed, Aug 26, 2009 at 10:14 AM, g...@iec wrote:
>
> I am making an ajax call and in response, i am getting an XML.
> And t
Another way is to alert($(this).find("#property_links").size()) to see
how many dom elements you get with that selector
Have you tried to use firebug to see the value of the hidden inputs?
maybe also that the error was server side...
Paolo
On Tue, Aug 25, 2009 at 8:09 PM, Paolo Ch
What kind of error have you now? Have you tried to do alert(prop) to
see if the value is correct?
Paolo
On Tue, Aug 25, 2009 at 5:49 PM, ArySal wrote:
>
> Hi Paolo,
>
> Thanks for the advice.
>
> I tried what you mentioned still it does not work, the error is
> slightly dif
have to replace
var prop = $("#property_links").val();
with
var prop = $(this).find("#property_links").val();
By the way, it is not reccomanded to have more then one element with same id
Paolo
On Tue, Aug 25, 2009 at 3:30 PM,
arysal...@hotmail.com wrote:
>
> Hi Guy
xtButton').css('visibility', 'visible');
}
});
});
I had to insert the oneTime function otherwise after the (*) I got the
whole width size... it's as if the DOM refreshed after a little bit of
time... but this cause the page to show up two seconds later... any
suggestion??
Thanks in advance
Paolo
Yes, naturally, but how do I get JQuery to have the datasource as its input?
Paolo
-Original Message-
From: jquery-en@googlegroups.com [mailto:[EMAIL PROTECTED] On
Behalf Of aschmid
Sent: Monday, December 08, 2008 12:43 PM
To: jQuery (English)
Subject: [jQuery] Re: SlideShow based on
come from a column in a SQL
Server database (perhaps minus the width and height). I am using Visual
Studio 2008, and would be delighted if there were a way to use either Linq
or any other Asp.Net technology to be able to feed the slideshow, or jQuery
in general.
Thank you again,
Paolo
datasource.
Is there a way to have the Linq datasource feed the data to JQuery to
produce a database driven slideshow?
Thank you all,
Paolo
Hello,
I have 2 images and 1 button. When I click on the button, I'd like to
move image 2 on top of image 2. I know there are some ways of doing
this, but they all require the image coordinates. Is there a way to do
this at the object level as i don't have coordinates?
thanks,
Paolo
Hello,
I have 2 images and 1 button. When I click on the button, I'd like to
move image 2 on top of image 2. I know there are some ways of doing
this, but they all require the image coordinates. Is there a way to do
this at the object level as i don't have coordinates?
thanks,
Paolo
Hi,
I'd like to rotate by a certain angle (e.g. a box by 45 degrees); that
object is going to be draggable. What are the options? I'd like to
avoid swf approaches that rotate objects after loading them rather
than before.
Thanks!
Paolo
Hi,
I'd like to rotate by a certain angle (e.g. a box by 45 degrees); that
object is going to be draggable. What are the options? I'd like to
avoid swf approaches that rotate objects after loading them rather
than before.
Thanks!
Paolo
d but being the object B loaded after object A, it will
always be in the background.
How can I bring the dragged object always in foreground independently
on when it was loaded?
Thanks!
Paolo
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