Hi Jose,
thank you for the reply. I want to keep voltage in kV, hence the 0.415. I
am looking for alternatives that could allow me to run analysis without
having to divide my load demand by 1000 each time. And I thought probably
by changing the R+jX value, it might help. If I don't want to divide
If you want to do things properly, I guess you would have to do *all* of
the following:
- First, MATPOWER expects baseMVA to be in MW. If you want to use a
p.u. system based around Volts and 1 kW (instead of the traditional kV and
100 MW), then you need baseMVA=0.001 at the beginning of
But does that means I should not divide my input power data by 1000 to make
it in MW? If I do that, it won't converge. For example, these are my Power
input for one time:
Columns 1 through 6
1.3. 0 0 0 0
2.1.0.00120.0004
Aren't I supposed to make the R and X in p.u. if I want to use them in
MATPOWER? Regardless, your simulation seems to be more sensible. But, I
just curious, so we don't necessarily change the R and X into p.u. values?
Thanks for the response.
On Wed, Oct 26, 2016 at 3:26 PM, Saranya A wrote:
>
what name type matlab program can run this my matlab R2013a dont's run
On 26 October 2016 at 07:26, Saranya A wrote:
> Hi Nur,
> Dont divide R and X with the voltage. I get the following power flow
> without those two lines.
>
>
> runpf('LV10')
>
> MATPOWER Version 6.0b1, 01-Jun