On Sun, Jul 25, 2010 at 8:49 PM, Nguyen Manh Cuong
cuong.m...@vienthongso.com wrote:
Hi Mark,
Please test this query:
select test1.*, (select name from test2 where test2.id=test1.`v_id` limit
1) as name_1,
(select name from test2 where test2.id=test1.`h_id` limit 1) as name_2
from test1;
Hi Mark,
Please test this query:
select test1.*, (select name from test2 where test2.id=test1.`v_id` limit 1) as
name_1,
(select name from test2 where test2.id=test1.`h_id` limit 1) as name_2
from test1;
- test1 table:
col1v_idh_id
America 1 2
- test2 table:
id name
2
On 07/25/2010 09:29 PM, Mark Phillips wrote:
I have been away from sql for awhile, and can't seem to figure out how to
write a simple query for two tables.
Table 1 has many columns, two of which are hID and vID. Table 2 has two
columns, ID and name. The hID and vID in table 1 correspond to the
Thanks Brent, good tip. Works like a charm.
On Jun 14, 2007, at 7:42 PM, Brent Baisley wrote:
Here's a little trick. Get your DELETE query working as a SELECT.
Then replace everything before FROM with DELETE tablename.
SELECT order_items.ord_id FROM order_items LEFT JOIN orders ON
- Original Message -
From: Ben Liu [EMAIL PROTECTED]
To: mysql@lists.mysql.com
Sent: Thursday, June 14, 2007 3:11 PM
Subject: need help with delete query
I'm trying to delete a subset of items in a table. The problem is, I don't
want to query for the subset first, store the results
Mark Phillips wrote:
I am running mysql 4.0.24 on Debian sarge.
I have a table with two columns, team and division, both varchar(255).
There are some errors in the table where division has a value but team is
blank. Given that I am getting new data, and the data entry folks may create
a
On Monday 23 January 2006 03:33 pm, Michael Stassen wrote:
Mark Phillips wrote:
I am running mysql 4.0.24 on Debian sarge.
I have a table with two columns, team and division, both varchar(255).
There are some errors in the table where division has a value but team is
blank. Given
Hello.
You may use these queries:
select flight_id
,baseline*tan(radians(angle)) as attitude
from flights
where (baseline*tan(radians(angle))) =
( select max(baseline*tan(radians(angle)))
from flights f2);
I forgot to copy the list as well
Mark
-- Forwarded Message --
Subject: Re: Need Help with a query
Date: Sunday 11 December 2005 06:47 pm
From: Mark Phillips [EMAIL PROTECTED]
To: Rhino [EMAIL PROTECTED]
Rhino,
My apologies for leaving out the version of mysql. I agree
Cory Robin [EMAIL PROTECTED] wrote on 16/06/2005 08:09:22:
I need to speed up a search, big time.
I have an application that searches for records on a date field. If it
doesn't find an exact date match, it keeps searching adjacent days until
it
finds a certain amount of records.
The
[EMAIL PROTECTED] wrote on 06/16/2005 11:30:10 AM:
Cory Robin [EMAIL PROTECTED] wrote on 16/06/2005 08:09:22:
I need to speed up a search, big time.
I have an application that searches for records on a date field. If
it
doesn't find an exact date match, it keeps searching adjacent
[EMAIL PROTECTED] wrote on 16/06/2005 16:29:46:
[EMAIL PROTECTED] wrote on 06/16/2005 11:30:10 AM:
Cory Robin [EMAIL PROTECTED] wrote on 16/06/2005 08:09:22:
I need to speed up a search, big time.
I have an application that searches for records on a date field. If
it
At 03:09 AM 6/16/05, Cory Robin wrote:
I need to speed up a search, big time.
I have an application that searches for records on a date field. If it
doesn't find an exact date match, it keeps searching adjacent days until it
finds a certain amount of records.
The problem now is, I'm using my
well - that was what I tried first - but that does not work because that
returns the latest date for which the task_id has a record as Assignment.
(It is like it picks up the max date from all records that have
name_rec_type as Assignment)
But I wanted was if the date corresponding to the
OK - I have found the cause of the inconsistency -
Whenever I have more than one record which has name_rec_type as 'Assignment'
I do not get any results (I get an empty result)
But if I have only one Assignment record then it returns the correct row.
Question is: How can I overcome this - I
SOLVED:
I changed my query to include max(t1.dt_aud_rec) instead of t1.dt_aud_rec.
I had guessed that it required just a tweak here and there...
Does anybody have any other suggestions apart from this??
Thanks,
Anoop
On 6/2/05, Anoop kumar V [EMAIL PROTECTED] wrote:
OK - I have found the
Hi,
Try just :
SELECT id_secr_rqst task_id, MAX(dt_aud_rec) AS latest
FROM isr2_aud_log WHERE
name_rec_type = 'Assignment' AND id_secr_rqst
='TASK23C6054B9D416C08:1284FD4:103FB047DF1:-7ECF'
GROUP BY id_secr_rqst
;
++-+
| task_id
You should *ALWAYS* indicate which version of MySQL you are using when you
ask this sort of question; the answers is almost always it depends: if you
are using 3.x, do X, if you are using 4.0.x do Y, if you are using 4.1.x do
Z. It's a lot of work to list all of those options and most people won't
On 1/20/05 11:16 AM, Rhino [EMAIL PROTECTED] wrote:
You should *ALWAYS* indicate which version of MySQL you are using when you
ask this sort of question; the answers is almost always it depends: if you
are using 3.x, do X, if you are using 4.0.x do Y, if you are using 4.1.x do
Z. It's a lot
Mike Zornek [EMAIL PROTECTED] wrote on 01/20/2005 11:01:38 AM:
I have the following query which will get me all of the emails for my
current membership:
SELECT email.email_address
FROM member, email
WHERE
member.member_primary_email_id = email.email_id
AND member.member_standing !=
Cc: Rhino [EMAIL PROTECTED]
Sent: Thursday, January 20, 2005 11:26 AM
Subject: Re: Need help forming SQL query
On 1/20/05 11:16 AM, Rhino [EMAIL PROTECTED] wrote:
You should *ALWAYS* indicate which version of MySQL you are using when
you
ask this sort of question; the answers is almost
Are you assuming that all months have 30 days? You can use the same syntax
with INTERVAL 1 MONTH
I would also format the date comparison to use the same precision that the
DATE_ADD function outputs.
So,
DATE_ADD(table.date, INTERVAL 1 MONTH) = DATE_FORMAT(CURDATE(), '%Y-%m-%d')
I might be off
Redmond Militante wrote:
hi
i need advice on a query i'm trying to do. i'm trying to find
entries with that are about to expire. entries expire if their date
of submission is older than 60 days. i want to find all entries with
a date of submission greater than 30 days, or those that are going
David Perron wrote:
Are you assuming that all months have 30 days? You can use the same syntax
with INTERVAL 1 MONTH
True.
I would also format the date comparison to use the same precision that the
DATE_ADD function outputs.
Why would you do that? The date column contains a DATE. CURDATE()
awesome. thank you!
[Wed, Aug 25, 2004 at 06:27:38PM -0700]
This one time, at band camp, David Perron said:
Are you assuming that all months have 30 days? You can use the same syntax
with INTERVAL 1 MONTH
I would also format the date comparison to use the same precision that the
select name
from mytable a
where changedate
(select changedate
from mytable b
where a.name=b.name
and a.changedate != b.changedate);
or:
select name
from mytable a
where exists
(select * from mytable b
Hi Claire,
On Mon, 23 Aug 2004 14:52:29 -0700 (PDT), Claire Lee [EMAIL PROTECTED] wrote:
Hi,
Here's a table of mine
namedate changeDate
n1d1 cd1
n2d1 cd3
n2d2 cd1
n4d1 cd2
n1d2 cd5
n5d1
You were so very close to getting what you wanted!
What is causing the problem is the comma (,) in your FROM clause. MySQL
permits two methods of declaring an INNER JOIN. The first is by using the
keyphrase INNER JOIN the second is with a comma in your table list. Here
is how to rephrase your
sounds like you need a join.
Select * from Poll, poll_votes where (Poll.poll_id = poll_votes.poll_id) and
(poll_votes.user_ID = WHATEVER);
But I'm still a beginner so
Respectfully,
Ligaya Turmelle
Anders Gjermshus [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi.
I'm having
* Soheil Shaghaghi
Hello everyone,
I need help with MySQL coding in php please if anyone can help.
I can try. :)
I have 3 tables:
-users, where the user info is stored.
-awards: contains the list of all the awards for each user
-award_types: contains different types of award
The tables
Tibby wrote:
..and I want to get this with a single query:
+-++--+
| key | desc| value |
+-++--+
| 2 | book| 7 |
| 6 | pen | 7 |
+-++--+
I need to get only one row from col. DESC, the one with the highest VALUE.
Hi,
I have already tried the 'rtfm', but it just didn't help.
But it's right there :)
3.5.2 The Row Holding the Maximum of a Certain Column
..and I want to get this with a single query:
+-++--+
| key | desc| value |
+-++--+
| 2 | book|
* Aleksandar Bradaric
select key, desc, value
from your_table t1
where value = (select max(value) from your_table where desc = t1.desc)
Anyway, when i execute this query, i get an error near 'select
max(value)'... :(
It's because the subselects are supported from version 4.1.
Veysel Harun Sahin wrote:
select vanNumber, sum(grossPay) from usertableDaily group by vanNumber;
The above is the correct query, to save yourself some time. As for your
problem:
But when I execute I get this:
Resource id#3
Resource id#4
This means you're using a resource
select vanNumber, sum(grossPay) from usertableDaily group by vanNumber;
[EMAIL PROTECTED] wrote:
hello,
I've performed searches on this site and php.net to try and figure out
why this is occuring. I can't find any instance in my searches that
helped me. So, I'm posting my very first question
Hi
Interesting problem, normally to get a total by type, you would have a query
like,
select van, sum(pay) from ($usertableDaily) group by van;
However you are individually quering each total, your approach is correct, but
slower.
The problem you have though is the return of
Resource
Are you referencing the result set correctly in php ?
How are you dealing with what MySQL returns ?
Looks like the info is there, you just not getting it out of the result
set.
-
Jerry @
MetalCat.Net
-
- Original Message -
From: Guru Geek
Hi John Kelly,
This is not a perfect solution but may be useful to you. But still with two
queries!
From Mysql prompt issue these two queries.
SELECT @maxcat := max(Category) FROM table
WHERE category = 'Sports:Football:Players' OR
category = 'Sports:Football' OR category = 'Sports';
Select
You need to use the LIKE command I think. The MySQL manual should give you
all the details. If you need further help I can just write the whole query
out for you. Or was the problem that you only want to worry about the
if..then stuff if needed? If so could you tell what your pulling back from
]
Cc: [EMAIL PROTECTED]
Sent: Friday, November 02, 2001 7:09 PM
Subject: Re: Need help with a query ...
You need to use the LIKE command I think. The MySQL manual should give you
all the details. If you need further help I can just write the whole query
out for you. Or was the problem that you
On Fri, Nov 02, 2001 at 06:15:08PM -0800, John Kelly wrote:
Hi, I have a MySQL table with a column that contains some of a web site
directory's category names in the format:
Sports:Football:Players
I am trying to build a query that that locates all records that match the
above category
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