I'm curious how others feel about this. When I'm creating an SQL
string, either for a non-prepared or prepared execution, I build it in
a variable and then pass the variable to the query or prepare
function. This lets me easily add something to view the SQL statement,
and also if there's an error,
I have Fedora 9/Apache 2/PHP 5.2.6
Everything is great but I cannot add the libraries for oci8 1.3.4 I have
in a directory.
The entries are grayed out.
I was getting an error oci_connect not found. I rebooted!
The php program runs **great** from /var/www/html under Apache
here is the
Hi everyone,
I just wanted to make sure that I am not making something more
complicated then it has to be.
I am working on a time clock application to use at my company, and so
far, I have a login table, and with a foreign key that links to the
time table. The thinking being, that when
On Sep 15, 2008, at 10:03 AM, Jason Pruim wrote:
On Sep 15, 2008, at 10:59 AM, Micah Gersten wrote:
Use 2 tables. You never know what the app might grow into and you
should do it right the first time.
That's what I was thinking too... Just wanted to hear it from
someone else... NOW I get
On Sep 15, 2008, at 10:59 AM, Micah Gersten wrote:
Use 2 tables. You never know what the app might grow into and you
should do it right the first time.
That's what I was thinking too... Just wanted to hear it from someone
else... NOW I get to learn about foreign keys and how to update
You'll actually want to have the User Id in the clocking table, not the
other way around. User Id is the foreign key because it has a many to
one relationship with the time logging.
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
Philip Thompson wrote:
On Sep 15, 2008, at 2:12 PM, Micah Gersten wrote:
You'll actually want to have the User Id in the clocking table, not
the
other way around. User Id is the foreign key because it has a many to
one relationship with the time logging.
Thank you,
Micah Gersten
onShore Networks
Internal
Hi Everyone,
I am attempting to wrap my head around an issue and wanted to see if I
was thinking right.
I am attempting to setup a pURL site, one where they go to something
like: example.com/purl.php?purl=jason1234 and the site says Welcome
Jason. I have that part of it working, and it's
Hi Everyone,
I am attempting to wrap my head around an issue and wanted to see if I was
thinking right.
I am attempting to setup a pURL site, one where they go to something like:
example.com/purl.php?purl=jason1234 and the site says Welcome Jason. I
have that part of it working, and it's
On Aug 26, 2008, at 8:32 AM, Dan Shirah wrote:
Hi Everyone,
I am attempting to wrap my head around an issue and wanted to see if
I was thinking right.
I am attempting to setup a pURL site, one where they go to something
like: example.com/purl.php?purl=jason1234 and the site says Welcome
Hi,
I have just installed the Apache on a Linux machine, and tried to run the
script that contains a
// connection to the database
$dbhandle= mssql_connect($myServer, $myUser, $myPass)
or die(Couldn't connect to SQL Server on $myServer);
When I try to run the PHP script, it gives me
Alice,
In regards to:
Call to undefined function mssql_connect() in
/home/TDC/Desktop/create_new_entry_master.php on line 20
Do you have the MSSQL extension uncommented in your PHP.ini?
Dan
Hi,
This may sound really stupid, but I installed Fedora and checked on the box
for web development to allow PHP and other web scripts on the platform.
Therefore, I could run PHP scripts fine, and the mentioning of this file, would
you be able to offer me suggestions on where it might be?
AM
To: Wei, Alice J.
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] Question on PHP connect MS SQL 2005
Alice,
In regards to:
Call to undefined function mssql_connect() in
/home/TDC/Desktop/create_new_entry_master.php on line 20
Do you have the MSSQL extension uncommented in your PHP.ini?
Dan
I know the package you need is called php-sybase in ubuntu. It's
probably something similar in Fedora. Know that this package will only
let you do a subset of the mssql function calls. If you are just
connecting and doing a normal query, it will suffice. If you need to
do prepared statements for
I sent this to the MySQL list but didn't receive any
response, My apologies if you have already received this.
Hi Everyone,
So having learned my lesson with the last application, I am trying to
plan out the addition of a feature to my database application.
Basically, some of my
Hi Jason,
There are a couple ways you could do this. Yes, this would make it a
relational database.
If you go with a second table, you'll want to be sure to include the UID
from the main address table in the SnowBirds table so that they are
linked. The UID in the second table would
in the addresses to be able
to pull the correct one based on date
bastien To: php-db@lists.php.net From: [EMAIL PROTECTED] Date: Wed, 24 Oct
2007 09:06:29 -0400 Subject: [PHP-DB] Question about database design
I sent this to the MySQL list but didn't receive any response, My
apologies if you have
Hi Tim,
Right now the customer I have has about 1,000 records which I know
isn't alot for MySQL to handle, but if people like the application we
could end up with 15 to 20 all having around 1,000 or more records
which would add up more on the database. Although right now I plan to
have a
to be able to pull the correct one
based on date
bastien
To: php-db@lists.php.net
From: [EMAIL PROTECTED]
Date: Wed, 24 Oct 2007 09:06:29 -0400
Subject: [PHP-DB] Question about database design
I sent this to the MySQL list but didn't receive any
response, My apologies if you
A second address table is definitely the way to go (the '*' signifies the
primary key):
People Table
*user_id
first_name
last_name
etc
Address Table (compound primary key)
=
*user_id (fk to People Table)
*address_id
*obs_no (you can skip this if you don't want to keep an
Nope, you got it
Bastien
CC: php-db@lists.php.net From: [EMAIL
PROTECTED] Subject: Re: [PHP-DB] Question about database design Date: Wed, 24
Oct 2007 15:18:05 -0400 To: [EMAIL PROTECTED] I think I understand what you
are saying here... On the main table just
HI, the question is whether there is any chance the LAST_INSERT_ID
could be wrong during inserting with a persistent DB connection?
For example, instance [AA] of a script insert one row with an
auto-increment field, and retrieve the LAST_INSERT_ID after the
operation, at the same time, there is
() {
top.document.getElementById(TOP).rows = 65,*,200,46,0;
}
bastien
From: suad [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Question in js about frameset rows
Date: Wed, 21 Jun 2006 11:44:07 +0200
Hi,
I have this page:
html
head
titletitle1/title
/head
frameset cols=*,200px
Hi,
I have this page:
html
head
titletitle1/title
/head
frameset cols=*,200px
frameset id=frameset1 rows=10%,30%,10%,*
frame src=/page1.phtml name=name1 frameborder=0 scrolling=no /
frame src=/page2.phtml name=name2 frameborder=0 /
frame src=/page3.phtml name=name3
appologies to the list. i think this should not be asked here. anyway i'll
answer.
IMHO, there is no easy way to do what you like. what i would suggest is use
document.write() or inclosing your frameset in a container div then
dynamically change it using innerHTML
hth
On 6/21/06, suad [EMAIL
;
}
bastien
From: suad [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Question in js about frameset rows
Date: Wed, 21 Jun 2006 11:44:07 +0200
Hi,
I have this page:
html
head
titletitle1/title
/head
frameset cols=*,200pxframeset id=frameset1
rows=10%,30%,10%,*
frame src
I have a few different pg_prepare statements in my PHP script. I was
wondering what scope they lie in. Im assuming they are not saved in the
PSQL database, so it is just for the script? They are inside of
functions... does it only last until the function exists? I just dont
want to keep on
On 4/14/06, Will Chapman [EMAIL PROTECTED] wrote:
I have a few different pg_prepare statements in my PHP script. I was
wondering what scope they lie in. Im assuming they are not saved in the
PSQL database, so it is just for the script? They are inside of
functions... does it only last until
**
IMPORTANT NOTICE
This communication is for the exclusive use of the intended recipient(s)
named above. If you receive this communication in error, you should
notify the sender by e-mail or by telephone (+44) 191 224 4461,
for not including that.
Thanks
-Rich
-Original Message-
From: Micah Stevens [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 13, 2005 9:13 PM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Question on CURDATE()
What SQL server are you using?
On Tuesday 13 September 2005 7:08 pm, reclmaples
I am trying to write a statement that will basically do this:
SELECT * FROM WEEKS WHERE BEGIN = CURDATE() and END = CURDATE;
But for some reason I can only use one CURDATE() reference in my sql
statement, does anyone know why? Is there a way I can get around this?
Any help would be greatly
What SQL server are you using?
On Tuesday 13 September 2005 7:08 pm, reclmaples wrote:
I am trying to write a statement that will basically do this:
SELECT * FROM WEEKS WHERE BEGIN = CURDATE() and END = CURDATE;
But for some reason I can only use one CURDATE() reference in my sql
I am using mysql Ver 12.22 Distrib 4.0.16
Sorry for not including that.
Thanks
-Rich
-Original Message-
From: Micah Stevens [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 13, 2005 9:13 PM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Question on CURDATE()
What SQL server are you
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Question on CURDATE()
What SQL server are you using?
On Tuesday 13 September 2005 7:08 pm, reclmaples wrote:
I am trying to write a statement that will basically do this:
SELECT * FROM WEEKS WHERE BEGIN = CURDATE() and END = CURDATE
Rich,
Did you try putting WHERE twice?
try:
SELECT * FROM WEEKS WHERE BEGIN = CURDATE() and WHERE END = CURDATE;
Jordan
On Sep 13, 2005, at 9:08 PM, reclmaples wrote:
I am trying to write a statement that will basically do this:
SELECT * FROM WEEKS WHERE BEGIN = CURDATE() and END =
You can't do that in SQL, that would give you a big fat syntax error.
On Tuesday 13 September 2005 7:45 pm, Jordan Miller wrote:
Rich,
Did you try putting WHERE twice?
try:
SELECT * FROM WEEKS WHERE BEGIN = CURDATE() and WHERE END = CURDATE;
Jordan
On Sep 13, 2005, at 9:08 PM,
Micah,
Oh, my bad. I was trying to remember how I did something like this
before, stringing together a lot of WHEREs. You're right, though,
it wasn't WHERE, it was OR.
Rich,
I think you need OR instead of AND, OR else I'm just totally out
to lunch tonight:
SELECT * FROM WEEKS WHERE BEGIN
Hi Jordan,
Syntactically, there is no restriction on OR'ing or AND'ing conditions. You
could very well do this:
Select somefield where otherfield = 1 and otherfield = 2;
Of course, otherfield would never be both 1 and 2, so this is a worthless
select statement, however, my point is, there
Hi,
I just noticed I was wrong, the original SQL statement would return rows, but
only if BEGIN = CURDATE(). I stated it would never happen, and that's wrong.
Sorry. :)
-Micah
On Tuesday 13 September 2005 9:42 pm, Micah Stevens wrote:
Hi Jordan,
Syntactically, there is no restriction on
Thanks Rory,
This query solves the problem:
SELECT client.client_name, IFNULL( COUNT( sales.sale_id ) , 0 ) AS total
FROM CLIENT LEFT JOIN sales ON client.client_id = sales.client_id
GROUP BY client.client_name
ORDER BY total DESC
Also thanks to Nandar and Prabhu, but MySQL does not recognize
Hi,
Let's say that I have 2 tables: client and sales
---
| client_id | client_name |
---
| 1 | John|
| 2 | Mark|
| 3 | Luke|
| 4 | Matthew |
---
: [PHP-DB] Question about COUNT(*)
Hi,
Let's say that I have 2 tables: client and sales
---
| client_id | client_name |
---
| 1 | John|
| 2 | Mark|
| 3 | Luke|
| 4 | Matthew
[EMAIL PROTECTED] wrote:
Hi,
Let's say that I have 2 tables: client and sales
---
| client_id | client_name |
---
| 1 | John|
| 2 | Mark|
| 3 | Luke|
| 4 | Matthew |
Team,
How do most of you get your clients, are their any other tricks besides word
of mouth.
I really want to become a freelance web designer, or work for a provider of
clients.
Also/or for a major coporation that.
Does anybody have any suggestions on how I can start getting paid for what I
Hi Mike,
I would suggest that you look for [A-Z],[a-z] and
[0-9] characters and build up your string for Media ID
instead of replacing \r and \n. I have gone
through the same situation for bar code scanning.
Regards,
Manjiri
__
Do you Yahoo!?
if the media_ID field is an autonumber, then there is no need to do anything
with it...mysql will take the null and generate the next id.
bastien
From: Mike Millner [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Question regarding how-to stop the form inputting empty
data at end
Mike Millner wrote:
Hello everyone,
I have this form that we use for keeping track of tapes we send off site
for storage where I work. The form works almost perfectly with the help
of a few people.
We use a scanner to input the tape id's. The scanner automatically puts
a carriage return at the
I want to send back a message when no matches are
found on my search page. Basically No matches
found. I assumed that mysql_fetch_assoc would be the
determining factor on whether any rows will come back.
As you can see below I do a if ($row_rsCS == false).
Apparently though (while the message
You might want to use:
mysql_num_rows function.mysql-num-rows.html -- Get number of rows in
result
Stuart Felenstein wrote:
I want to send back a message when no matches are
found on my search page. Basically No matches
found. I assumed that mysql_fetch_assoc would be the
determining factor
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
On 03 December 2004 14:39, Stuart Felenstein wrote:
I want to send back a message when no matches are
found on my search page. Basically No matches
found. I assumed that
The closing ? of a PHP segment also implies an
end-of-statement semicolon
-- so the above is equivalent to:
if ($row_rsCS == false) ;
?
Which, of course, means that the scope of the if
doesn't extend to anything
beyond this point.
You need to mark the block controlled by the
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
On 03 December 2004 15:06, Stuart Felenstein wrote:
The closing ? of a PHP segment also implies an
end-of-statement semicolon
-- so the above is equivalent to:
if
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
On 03 December 2004 15:16, Stuart Felenstein wrote:
--- Stuart Felenstein [EMAIL PROTECTED] wrote:
The reason the close is there is because the next
line
of code is the
--- Ford, Mike [EMAIL PROTECTED] wrote:
Well, your taste seems to be to use { }, so :-endif
is irrelevant.
Alright it's Friday, I'm punchy but we're all in a
good mood !
Yes, I like the closing curlies
So, then where do these lovely ladies go here ?
if ($row_rsCS == false) {
p
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
On 03 December 2004 15:26, Stuart Felenstein wrote:
--- Ford, Mike [EMAIL PROTECTED] wrote:
Well, your taste seems to be to use { }, so :-endif is irrelevant.
Alright it's
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
On 03 December 2004 15:26, Stuart Felenstein wrote:
--- Ford, Mike [EMAIL PROTECTED] wrote:
Well, your taste seems to be to use { }, so :-endif is irrelevant.
Alright it's
--- Ford, Mike [EMAIL PROTECTED] wrote:
And, by the way, why on earth are you using a
print_r an a straight literal
string? Seems to me you could just put that text in
as part of the HTML:
if ($row_rsCS == false) {
?
p align=centerstrongNo Matches
Found/strong/p
?php
Sorry ..hit the wrong button
--- Stuart Felenstein [EMAIL PROTECTED] wrote:
I posted this over on mysql list. Not trying to be
redundant, but would like to get some feedback.
Basically I'm wondering.
I am creating a search form , dynamic query, that
could potentially have in the area of
'].
';
$result = mysql_query($sql);
...
bastien
From: Stuart Felenstein [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Question on the use of where statements
Date: Wed, 1 Dec 2004 07:28:24 -0800 (PST)
I posted this over on mysql list. Not trying to be
redundant, but would like to get
--- Bastien Koert [EMAIL PROTECTED] wrote:
so...best to build the statement dynamically and
execute it once only if the
input box has a value in it...
And that is the way I'm building it. Just thinking
about the scenario that somone actually chooses 75% of
the options - would that
of SELECT statement.
If you find anything interesting, let us know. Sorry couldn't give you
a better answer.
-TG
-Original Message-
From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
Sent: Wednesday, December 01, 2004 10:56 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Question on the use
actually that would reduce it since a fewwer number of rows would
potentially match the query...ensure that there is a composite index on a
good selection of the columns to mkae the query quicker
bastien
From: Stuart Felenstein [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB
Can you hold a file in a session? I am trying to send a file to a third
page and it won't seem to work sending it in a session. Does anyone know
how to do this?
Thanks
Kathy A Wright | Keane Inc. | Suite:
Outside: 617-517-1706 | E-mail: [EMAIL PROTECTED]
[ Mailing: 100 City Sq.
about your situation.
-TG
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Friday, November 19, 2004 11:46 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Question on FilesSessions
Can you hold a file in a session? I am trying to send a
file to a third
Better to save the file locally, the pass the name in a session variable.
otherwise the overhead of holding a multi Kb or Mb file will be killer on
the system.
What are you trying to do with the file?
Bastien
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Question
those of St. Jude Children's Research Hospital.
-Original Message-
From: Jacob Hackamack [mailto:[EMAIL PROTECTED]
Sent: Monday, November 08, 2004 11:54 PM
To: PHP Databases
Subject: [PHP-DB] Question
Hello,
I am using PostNuke and have decided to create a page for a local
basketball team
Hello,
I am using PostNuke and have decided to create a page for a local basketball
team. I have this as the create team function:
//
/// Create a new Team for the given Tournament
///
/// Parameters:
/// 'cid' = Tournament ID
///'team' = Team name
///
I have a textarea field that will allow users to copy
and paste text into , it might be plain text, or it
might come out of word.
I'm wondering what type of validations I should
perform on this field ?
Any suggestions / ideas ?
Thank you,
Stuart
--
PHP Database Mailing List
I have a textarea field that will allow users to copy
and paste text into , it might be plain text, or it
might come out of word.
I'm wondering what type of validations I should
perform on this field ?
Any suggestions / ideas ?
Hi Stuart,
Check out the strip_tags and mysql_escape_string
Not exactly sure what I did here.
there are 5 skill textfields name skill[]
then the years sky[]
then the last used slu[]
I was following the format of my other arrays, so
stored them list this:
if ( empty( $_SESSION['l_skill'] ) ) {
$_SESSION['l_skill']=array();
}
if ( is_array(
Hi everybody,
For quite a while i'm struggeled with my session. It doesn't seem to work,
can anyone help me?
This is my code:
page 1:
session_start();
$_SESSION[test] = tryin...;
if (isset($_SESSION[test]))
{
echo a href='session2.php'next page/a;
echo br.session_id();
}
page 2:
Changed my direction somewhat but keep getting a parse
error and although I know where it is , I can't seem
to figure out what I need to do to make it syntax
correct:
This is how I am passing the arrays:
if ( empty( $_SESSION['l_skill'] ) ) {
$_SESSION['l_skill']=array();
}
if ( is_array(
Stuart, what does your echo($query) line output?
I would hazard a guess that your quotes are wrong and you are not getting
what you expect.
What is LUID?
I believe you will need to execute an INSERT query within each for($i=0;
$icount($l_skill); $i++) loop or increment add $LUID within each
PROTECTED]
Sent: 17 October 2004 16:14
To: Stuart Felenstein; Graham Cossey; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Question: Putting separate form elements into an
array
Changed my direction somewhat but keep getting a parse
error and although I know where it is , I can't seem
to figure
is the current situation? Iterating through the
3 arrays or inserting
into MySQL?
Graham
-Original Message-
From: Stuart Felenstein
[mailto:[EMAIL PROTECTED]
Sent: 17 October 2004 16:14
To: Stuart Felenstein; Graham Cossey;
[EMAIL PROTECTED]
Subject: RE: [PHP-DB] Question
Right now this seems something like solving a rubic's
cube. While I process, I hope it's alright that i'm
asking here. I think my quantity of posts have been
high :)
I have these form elements:(these are the names of the
elements)
skill1sky1 slu1
skill2sky2 slu2
skill3
Have you tried naming your form elements such as
skill[], sky[] and slu[] ?
(You could also use skill[1], skill[2], skill[3]
etc... within your form.)
Yes that makes sense.
Good.
This of course means you can build your form within a for loop (or similar).
So to place 10 skill text
Well, finally suceeding to get by activation page
working, where the 0 is flipped to 1 to mean actived,
I'm stuck on the login page.
Unfortunately I'm stuck :) with what I have below.
It's part of an authentication system. This code
doesn't include the includes, but I thought maybe
significant
Right now my registration / login system works like
this:
1-User goes to registration page and fills out form
2-User gets to choose username but password is
autogenerated by system
3-System encrypts password in database
4-Password is unencrypted and sent along with username
to registrant's email
the lines of userid, tousergroup, activationcode).
/ rylin
-Original Message-
From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
Sent: den 26 september 2004 13:46
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Question on Registration Method
Right now my registration / login system works like
Currently there are only 2 types of users planned
Each has a basic access level. I don't think this is
the same as a usergroup though.
If I don't have usergroups, but access levels, then
perhaps I should set the level to some less then what
is required login till activated.
Then it sounds like
I'd do it this way...
I'd add two column in the users table. 1- activated, 2- activation-hash
once the registeration form is ubmited..
a-the username and user info will be saved in the users table.
b-an encrypted hash would be made n saved in activation-hash column
and sent along with the
K...I've added the 2 columns, my names - activate and
activate_hash.
Upon registration, the activate_hash has a generated
string inserted. activate column is default to 0.
I can compare it to the database - but not sure how to
flip the switch on the activate column 0-1
Is that done through an
that is done when they click the link in thier email
if they are sent to domain.com/page.php?code=X4rfkj490T
the code in page.php will $_GET['code'] and compare it to the one in
the database, if they match, flip the switch if not show an error.
On Sun, 26 Sep 2004 06:35:59 -0700 (PDT), Stuart
Nothing like sharing my pain ;) sorry!
It seems that in order to compare the code to the one
in the database, don't I need the userid or something?
or just that it exists in the database?
Thank you,
Stuart
--- Joseph Crawford [EMAIL PROTECTED] wrote:
what i did is i used php to create a random
no you dont need a user id or anything, here is some sample code to
give you the idea
$result = mysql_query(SELECT fields FROM table WHERE code=.$_GET['code']);
if(mysql_num_rows($result) 0) {
// we have a match, activate the account
$result1 = mysql_query(UPDATE table SET activated=1 WHERE
I'm getting an error using the
mysql_num_rows($result)
Warning: mysql_num_rows(): supplied argument is not a
valid MySQL result resource in
/home/lurkkcom/public_html/lurktivate.php on line 7
Why am I counting the number of rows in the table?
Shouldn't I be looking to see if the code I was
I'm getting an error using the
mysql_num_rows($result)
Warning: mysql_num_rows(): supplied argument is not a
valid MySQL result resource in
/home/lurkkcom/public_html/lurktivate.php on line 7
Did you happen to remember to change fields in the query string to your
table column names, and
On Sunday 26 September 2004 19:45, Stuart Felenstein wrote:
While I'm okay with mine, not completely satisfied.
I'd like to change it to the type where like above the
username and password is sent via email, but with the
addition of a link in the email whereby the user must
click on link to
Unknown column 'a338265f' in 'where clause' is the
latest problem (and should be the last). I had this
same error earlier while just doing a straight sql to
the database. I corrected it then by putting
apostrophes around the column name. That didn't help
here , not quotes , maybe double
How are they any different?
I'm seeing the same thing as your method.
Stuart
--- Jason Wong [EMAIL PROTECTED] wrote:
On Sunday 26 September 2004 19:45, Stuart Felenstein
wrote:
While I'm okay with mine, not completely
satisfied.
I'd like to change it to the type where like above
the
Stuart... u got the logic now. check ur syntax problems urself...
this is the only way ull learn it!
a hint... if ur database query is giving u errors... try echoing it
before sending it to mysql_query. ull find out the problem yourself
then ;)
another hint... mysql_query always returns
On Monday 27 September 2004 03:01, Stuart Felenstein wrote:
How are they any different?
I'm seeing the same thing as your method.
These two methods are separate:
- Send user a system generated password with which
they can login and
subsequently change.
OR
- Send user an activation
$_GET['activation_hash] is missing the end '
On Mon, 27 Sep 2004 03:20:22 +0800, Jason Wong [EMAIL PROTECTED] wrote:
On Monday 27 September 2004 03:01, Stuart Felenstein wrote:
How are they any different?
I'm seeing the same thing as your method.
These two methods are separate:
-
Hello.
I have a question about behaviour of indices in queries with inversed LIKE
in MySQL. I mean something like this:
select foo from bar where '$some_string' LIKE some_field
where in the `some_field` I have a strings like 'symbols%' :)
Do you have some ideas?
WBR, Wicked
--
PHP Database
The index should still work normally.
Hello.
I have a question about behaviour of indices in queries with inversed LIKE
in MySQL. I mean something like this:
select foo from bar where '$some_string' LIKE some_field
where in the `some_field` I have a strings like 'symbols%' :)
Do you have some
/td
td id=right/td
/tr
/table
/form
/body
/html
-Original Message-
From: Neil Smith [MVP, Digital media] [mailto:[EMAIL PROTECTED]
Sent: Thursday, May 13, 2004 4:16 AM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re:RE: [PHP-DB] question on select
That *should* read
/plain;
charset=us-ascii
Content-Transfer-Encoding: 7bit
Message-ID: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] question on select
!--
function changeMenu()
{
document.fcountry.newcountry.value =
document.fcountry.country.options[document.fcountry.country.selectedIndex].v
alue;
}
--
/script
this information from
this point on. Can someone please tell me how I can use the selected item in
my next SQL query?
-Original Message-
From: Tony S. Wu [mailto:[EMAIL PROTECTED]
Sent: Wednesday, May 12, 2004 11:07 AM
To: hengameh
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] question on select
1 - 100 of 187 matches
Mail list logo
