RE: [PHP] How to access a program outside of PHP?

2003-09-11 Thread Adam Douglas
No I have Safe_Mode = off. I also have error_reporting = E_ALL and display_errors = on and I have php errors to log to a log file. I have no log file of php errors nor is there an error being display on the page. Geez this is frustrating, yeah that's what I figure but you would think there can be

Re: [PHP] How to access a program outside of PHP?

2003-09-11 Thread Raditha Dissanayake
btw have you checked if you are in safe_mode? in php.ini error level can also be set in php.ini my guess is that you have a problem in your chroot setup. best regards Adam Douglas wrote: Mmm... okay. I tried that and nothing. Is there no way for me to determine what the problem is? Error message

RE: [PHP] How to access a program outside of PHP?

2003-09-11 Thread Adam Douglas
Mmm... okay. I tried that and nothing. Is there no way for me to determine what the problem is? Error message some place, log file, etc? I do not understand why this is not work. Even a simple example from the PHP manual on system() does not work. > I meant to do this: > > $szPipe = `/htdocs/gs -

Re: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Raditha Dissanayake
I meant to do this: $szPipe = `/htdocs/gs -q -dNOPAUSE -dBATCH -sDEVICE=pdfwrite -sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf /htdocs/Sep08-113523.pdf`; Adam Douglas wrote: Backticks is simply the ` sign (usually the character above the tab). Popularly know as `hair on the ear` in

RE: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Adam Douglas
> Backticks is simply the ` sign (usually the character above the tab). > Popularly know as `hair on the ear` in my country :-) > for example if you want to invoke ls from php you just type > > $result = `ls`; > > hey presto the output from ls is now in your $result variable. Ohhh okay. Well if

Re: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Raditha Dissanayake
hi Backticks is simply the ` sign (usually the character above the tab). Popularly know as `hair on the ear` in my country :-) for example if you want to invoke ls from php you just type $result = `ls`; hey presto the output from ls is now in your $result variable. all the best Adam Douglas wr

RE: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Adam Douglas
> >1) When I echo out $szPipe I get "Resource id #2". > > > Sorry i was thinking of backticks. btw have you tried it ? > (backticks) Backticks? Is this a PHP API function, I can't find it? That's the thing here I haven't been able to get things to work and I have no clue what I should use, exec(

Re: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Marek Kilimajer
Adam Douglas wrote: 3)Yes I tried running gs in the console as root works fine and as myself and that works fine. The user is www that runs httpd. How could I test to see if www has access? To my understanding such accounts can not be used to log in with. # su www -- PHP General Mailing List (

Re: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Raditha Dissanayake
Adam Douglas wrote: 1) When I echo out $szPipe I get "Resource id #2". Sorry i was thinking of backticks. btw have you tried it ? (backticks) 2) Oops, that chrooted in /var/www/. So I thought I should be putting just a /htdocs/, no? yeps. 3)Yes I tried running gs in the console as root works f

RE: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Adam Douglas
> > Hi. I'm trying to develop a web interface to the ghostscript (gs) > > application. I have the ghostscript syntax down perfectly > in the console. > > Now when I go to try and do it in PHP I get nothing. No > errors, nothing > just > > a blank page with PHP logs turned on and errors turned on.

RE: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Adam Douglas
> 1) please try $szPipe and see if you get any output. > 2) if you are jailed in /var/htdocs/ your pathname /htdocs/qs > is incorrect. > 3) I guess you tried running gs from the jail either as > yourself or as > root. > please see if nobody or apache (the webserver's user) can run > gostscript.

Re: [PHP] How to access a program outside of PHP?

2003-09-10 Thread CPT John W. Holmes
From: "Adam Douglas" <[EMAIL PROTECTED]> > Hi. I'm trying to develop a web interface to the ghostscript (gs) > application. I have the ghostscript syntax down perfectly in the console. > Now when I go to try and do it in PHP I get nothing. No errors, nothing just > a blank page with PHP logs turn

Re: [PHP] How to access a program outside of PHP?

2003-09-10 Thread Raditha Dissanayake
Hi, 1) please try $szPipe and see if you get any output. 2) if you are jailed in /var/htdocs/ your pathname /htdocs/qs is incorrect. 3) I guess you tried running gs from the jail either as yourself or as root. please see if nobody or apache (the webserver's user) can run gostscript. all the best