在 2020年9月21日星期一 UTC+8 下午8:02:44， 写道：
> Op 21-09-2020 om 12:14 schreef iMath:
> > Asked 3 days ago at
> > https://stackoverflow.com/questions/63951696/celery-multi-celery-exceptions-timeouterror-the-operation-timed-out
> >
> >
> > But nobody helped yet, any
Op 21-09-2020 om 12:14 schreef iMath:
Asked 3 days ago at
https://stackoverflow.com/questions/63951696/celery-multi-celery-exceptions-timeouterror-the-operation-timed-out
But nobody helped yet, anyone ?
Did you see
https://stackoverflow.com/questions/9769496/celery-received-unregistered-task
Asked 3 days ago at
https://stackoverflow.com/questions/63951696/celery-multi-celery-exceptions-timeouterror-the-operation-timed-out
But nobody helped yet, anyone ?
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ckends/base.py",
line 696, in wait_for
raise TimeoutError('The operation timed out.')
celery.exceptions.TimeoutError: The operation timed out.
>>>
So what's wrong ?
Test environment :
- Python 3.8.2
- celery multi v4.4.7
- rabbitmqctl version --->3.
It turns out that Comodo Antivirus auto-sandboxes any program that it doesn’t
recognize, and this included python in the C:\Users\$user\AppData\Programs
directory.
This also affects Cygwin and MSYS2 (but not MSYS).
If you are thinking about using Comodo, disable the Auto-Containment feature.
A
Hello, I am seeking some quick help, and probably am reporting bugs along the
way. I apologize that this is a long email. Please let me know what I should do
in the future.
On Windows, pip hangs and does not install packages in the proper location (or
perhaps, at all), even if pip claims it ins
list of strings, for each row in Legs.
> So, basically its like getting a dataframe that is subset of all_paths for
> each row in Legs. Then I need to perform a math operation on the columns of
> each subset and assign the values back to another column in all_paths.
> Followin
me that is subset of all_paths for each row
in Legs. Then I need to perform a math operation on the columns of each subset
and assign the values back to another column in all_paths. Following is my
implementation
def step1_vec(iti_list, idx):
mask= all_paths.loc[all_paths['Path'].isi
On Thursday 26 May 2016 15:47, San wrote:
> Following is the code i used.
>
> def test_results(filename):
> import csv
> with open(filename,"rU") as f:
> reader = csv.reader(f,delimiter="\t")
> result = {}
You should use more consistent indents. Can you set your editor to
auto
On Thursday, May 26, 2016 at 11:17:56 AM UTC+5:30, San wrote:
> On Wednesday, May 25, 2016 at 6:00:07 PM UTC+5:30, San wrote:
> > Hi Gorup,
> >
> > why i am getting "ValueError: I/O operation on closed file" this error.
> > Pls let me know.
> >
On Wednesday, May 25, 2016 at 6:00:07 PM UTC+5:30, San wrote:
> Hi Gorup,
>
> why i am getting "ValueError: I/O operation on closed file" this error.
> Pls let me know.
>
> Thanks in Advance.
> san
Hello,
Following is the code i used.
def test_results(filename
On Wed, 25 May 2016 05:29:53 -0700, San wrote:
> Hi Gorup,
>
> why i am getting "ValueError: I/O operation on closed file" this error.
> Pls let me know.
>
> Thanks in Advance.
> san
because you are trying to do something with a file that has been closed
the err
On Wed, May 25, 2016 at 8:29 AM, San wrote:
> Hi Gorup,
>
> why i am getting "ValueError: I/O operation on closed file" this error.
> Pls let me know.
Because your program is incorrect?
Why not list your code, so that someone might be able to help you?
>
&
Hi Gorup,
why i am getting "ValueError: I/O operation on closed file" this error.
Pls let me know.
Thanks in Advance.
san
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On 04/25/2016 07:13 AM, oyster wrote:
for a simple code
[code]
vexList = [1, 2, 3]
print('vexList', list(vexList))
vexList=map(lambda e: e+1, vexList)
print('vexList', list(vexList))
vexList = list(vexList)
print('vexList', list(vexList))
vexList=map(lambda e: e*2,vexList)
print('vexList', lis
On 04/25/2016 08:13 AM, oyster wrote:
> so, what produces this difference between py2 and py3 in nature? is
> there more examples? where can I find the text abiut his difference?
One thing I see is that both your py2 and py3 examples are treating
print as a function. It's only a function in Py3.
oyster writes:
- -
> I found
> type(map(lambda e: e, vexList)) is in py2
> type(map(lambda e: e, vexList)) is in py3
>
> so, what produces this difference between py2 and py3 in nature? is
> there more examples? where can I find the text abiut his difference?
Yes, there are more ways obtain o
for a simple code
[code]
vexList = [1, 2, 3]
print('vexList', list(vexList))
vexList=map(lambda e: e+1, vexList)
print('vexList', list(vexList))
vexList = list(vexList)
print('vexList', list(vexList))
vexList=map(lambda e: e*2,vexList)
print('vexList', list(vexList))
[/code]
py27 says
[quote]
On 11Dec2015 11:04, oyster wrote:
there is shutil module, but I find it limits the user heavily. For
example, I want to move 2 directories "a/scene" and "c/scene" to "d",
but there is "scene" under d already. Then shutil.move will raise
Error, "Destination path '%s' already exists" % real_dst
S
there is shutil module, but I find it limits the user heavily. For
example, I want to move 2 directories "a/scene" and "c/scene" to "d",
but there is "scene" under d already. Then shutil.move will raise
Error, "Destination path '%s' already exists" % real_dst
So is there any module, which allow me
I have a list of Pandas Dataframes that I am attempting to combine using the
concatenation function.
dataframe_lists = [df1, df2, df3]
result = pd.concat(dataframe_lists, keys = ['one', 'two','three'],
ignore_index=True)
The full traceback that I receive when I execute this function is:
-
On Thu, 4 Jun 2015 11:18 am, Russell Brennan wrote:
> I'm going to x-post this to stackoverflow but...
>
> When checking a method's arguments to see whether they were set, is it
> pythonic to do an identity check:
>
> def doThis(arg1, arg2=None):
> if arg2 is None:
> arg2 = myClass()
>
>
Frank Millman wrote:
> I have a slight variation in that I want to keep a reference to the
> argument -
>
> def __init__(self, arg=None):
> self.arg = arg or []
>
> Based on your comment, I have changed it to -
>
> def __init__(self, arg=None):
> self.arg = [] if arg is None else arg
>
"Peter Otten" <__pete...@web.de> wrote in message
news:mkp10p$n0l$1...@ger.gmane.org...
> Russell Brennan wrote:
>
>> I'm going to x-post this to stackoverflow but...
>>
>> When checking a method's arguments to see whether they were set, is it
>> pythonic to do an identity check:
>>
>> def doThis
Russell Brennan wrote:
> I'm going to x-post this to stackoverflow but...
>
> When checking a method's arguments to see whether they were set, is it
> pythonic to do an identity check:
>
> def doThis(arg1, arg2=None):
> if arg2 is None:
> arg2 = myClass()
>
>
> Or is it proper form to us
Russell Brennan writes:
> I'm going to x-post this to stackoverflow but...
>
> When checking a method's arguments to see whether they were set, is it
> pythonic to do an identity check:
>
> def doThis(arg1, arg2=None):
> if arg2 is None:
> arg2 = myClass()
That is the Pythonic way to test
I'm going to x-post this to stackoverflow but...
When checking a method's arguments to see whether they were set, is it
pythonic to do an identity check:
def doThis(arg1, arg2=None):
if arg2 is None:
arg2 = myClass()
Or is it proper form to use a short-circuiting boolean:
def doThis(arg1
On 04/30/2015 01:50 PM, Cecil Westerhof wrote:
Op Thursday 30 Apr 2015 21:38 CEST schreef Larry Hudson:
On 04/30/2015 01:06 AM, Cecil Westerhof wrote:
[snip]
I wrote a module where I have:
def get_indexed_message(message_filename, index):
"""
Get index message from a file, where 0 gets the fi
Op Thursday 30 Apr 2015 21:38 CEST schreef Larry Hudson:
> On 04/30/2015 01:06 AM, Cecil Westerhof wrote:
> [snip]
>
>> I wrote a module where I have:
>> def get_indexed_message(message_filename, index):
>> """
>> Get index message from a file, where 0 gets the first message
>> """
>>
>> return op
On 04/30/2015 01:06 AM, Cecil Westerhof wrote:
[snip]
I wrote a module where I have:
def get_indexed_message(message_filename, index):
"""
Get index message from a file, where 0 gets the first message
"""
return open(expanduser(message_filename),
'r').r
Op Wednesday 29 Apr 2015 20:08 CEST schreef siva sankari R.:
> file=open("input","r")
> line=file.seek(7)
> print line
>
> The above code is supposed to print a line but it prints "none". I
> don't know where the mistake is. Help.!
You could use my module:
https://github.com/CecilWesterhof/P
On Thu, Apr 30, 2015 at 7:06 PM, Cecil Westerhof wrote:
> I already done it. I thought it not to much work. And it even makes
> some code shorter:
> -marshal_file= open(expanduser(marshal_filename), 'r')
> -not_list= load(marshal_file)
> -marshal_file.close()
> -return
Op Thursday 30 Apr 2015 10:31 CEST schreef Dave Angel:
> On 04/30/2015 04:06 AM, Cecil Westerhof wrote:
>> Op Thursday 30 Apr 2015 09:33 CEST schreef Chris Angelico:
>>
>>> On Thu, Apr 30, 2015 at 4:27 PM, Cecil Westerhof wrote:
> with open("input.cpp") as f:
> lines = f.readlines()
>
On 04/30/2015 04:06 AM, Cecil Westerhof wrote:
Op Thursday 30 Apr 2015 09:33 CEST schreef Chris Angelico:
On Thu, Apr 30, 2015 at 4:27 PM, Cecil Westerhof wrote:
with open("input.cpp") as f:
lines = f.readlines()
print(lines[7])
Is the following not better:
print(open('input.cpp', 'r').read
Op Thursday 30 Apr 2015 09:33 CEST schreef Chris Angelico:
> On Thu, Apr 30, 2015 at 4:27 PM, Cecil Westerhof wrote:
>>> with open("input.cpp") as f:
>>> lines = f.readlines()
>>> print(lines[7])
>>
>> Is the following not better:
>> print(open('input.cpp', 'r').readlines()[7])
>>
>> Time is the
On Thu, Apr 30, 2015 at 4:27 PM, Cecil Westerhof wrote:
>> with open("input.cpp") as f:
>> lines = f.readlines()
>> print(lines[7])
>
> Is the following not better:
> print(open('input.cpp', 'r').readlines()[7])
>
> Time is the same (about 25 seconds for 100.000 calls), but I find this
> more
Op Thursday 30 Apr 2015 02:33 CEST schreef Chris Angelico:
> On Thu, Apr 30, 2015 at 4:08 AM, siva sankari R
> wrote:
>> file=open("input","r")
>> line=file.seek(7)
>> print line
>>
>> The above code is supposed to print a line but it prints "none". I
>> don't know where the mistake is. Help.!
>
On Thu, Apr 30, 2015 at 4:08 AM, siva sankari R wrote:
> file=open("input","r")
> line=file.seek(7)
> print line
>
> The above code is supposed to print a line but it prints "none". I don't know
> where the mistake is. Help.!
Going right back to the beginning... Are you aware that 'seek' works
w
On Thu, 30 Apr 2015 06:53 am, Mark Lawrence wrote:
> The only good top poster is a dead top poster, except for...
Since you just top posted, at least you're being honest.
Mark, I'm fairly sure you were trying to be funny, but I think you just
crossed a line from "funny and mean" to "just mean bu
The only good top poster is a dead top poster, except for...
On 29/04/2015 19:42, Billy Earney wrote:
if your filename is input.cpp, you first line of code should be:
file=open("input*.cpp*","r")
On Wed, Apr 29, 2015 at 1:26 PM, siva sankari R
wrote:
There is a file named "input.cpp"(c++ fi
stake is. Help.!
The seek() function doesn't return any data; it just relocates the file
pointer. You still have to do a read operation to get data from the
new location.
--
John Gordon Imagine what it must be like for a real medical doctor to
gor...@panix.comwatch &
On 2015-04-29 19:08, siva sankari R wrote:
file=open("input","r")
line=file.seek(7)
print line
The above code is supposed to print a line but it prints "none". I don't know
where the mistake is. Help.!
'seek' will seek to position 7 in the file. It doesn't read. That's
what 'read' is for! :-)
if your filename is input.cpp, you first line of code should be:
file=open("input*.cpp*","r")
On Wed, Apr 29, 2015 at 1:26 PM, siva sankari R
wrote:
> There is a file named "input.cpp"(c++ file) that contains some 80 lines of
> code.
> --
> https://mail.python.org/mailman/listinfo/python-list
>
There is a file named "input.cpp"(c++ file) that contains some 80 lines of
code.
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On Wed, Apr 29, 2015 at 2:08 PM, siva sankari R wrote:
> file=open("input","r")
> line=file.seek(7)
> print line
>
> The above code is supposed to print a line but it prints "none". I don't know
> where the mistake is. Help.!
> --
> https://mail.python.org/mailman/listinfo/python-list
What is in
file=open("input","r")
line=file.seek(7)
print line
The above code is supposed to print a line but it prints "none". I don't know
where the mistake is. Help.!
--
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On 14/08/2014 08:32, luofeiyu wrote:
I want to write a function to make operation as a argument in the function.
|def fun(op,x,y):
return(x op y)|
it is my target for the funciton:
if op ="+" fun(op,3,9) =12
if op ="*" fun(op,3,9) =27
How to write it?
With
I want to write a function to make operation as a argument in the function.
|def fun(op,x,y):
return(x op y)|
it is my target for the funciton:
if op ="+" fun(op,3,9) =12
if op ="*" fun(op,3,9) =27
How to write it?
--
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On Fri, 11 Apr 2014 07:02:33 +0800, length power wrote:
"ok" or "not ok"
> 'ok'
"ok" and "not ok"
> 'not ok'
> why "ok" or "not ok" output "ok" , "ok" and "not ok" output "not ok" ?
I believe that:
[ (falsey condition) or ]* (first truthy condition) or (any condition)
[ or
On 04/10/2014 04:02 PM, length power wrote:
>>> "ok" or "not ok"
'ok'
>>> "ok" and "not ok"
'not ok'
>>>
why "ok" or "not ok" output "ok" , "ok" and "not ok" output "not ok" ?
You are probably confusing yourself with the string "not ok". That
string, and any other non-empty string is co
On 4/10/2014 7:02 PM, length power wrote:
>>> "ok" or "not ok"
'ok'
>>> "ok" and "not ok"
'not ok'
>>>
why "ok" or "not ok" output "ok" , "ok" and "not ok" output "not ok" ?
This is explained in our fine manual.
https://docs.python.org/2/reference/expressions.html#boolean-operations
--
T
>>> "ok" or "not ok"
'ok'
>>> "ok" and "not ok"
'not ok'
>>>
why "ok" or "not ok" output "ok" , "ok" and "not ok" output "not ok" ?
--
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inpu = "3443331123377"
tstr = inpu[0]
for k in range(1, len(inpu)):
if inpu[k] != inpu[k-1] :
tstr = tstr + inpu[k]
print(tstr)
--
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On Thu, 16 Jan 2014 22:24:40 -, Nac Temha wrote:
Hi everyone,
I want to do operation with chars in the given string. Actually I want to
grouping the same chars.
For example;
input : "3443331123377"
operation-> (3)(44)()(333)(11)(2)(33)(77)
output: "3413
giacomo boffi writes:
> % python a.py
> 34131237
% cat a.py
i="3443331123377";n=0
while n+1!=len(i):i,n=(i[:n]+i[n+1:],n) if i[n+1]==i[n] else (i,n+1)
print i
% python a.py
34131237
%
--
for Nikos
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On Fri, 17 Jan 2014 00:24:40 +0200, Nac Temha wrote:
> Hi everyone,
>
> I want to do operation with chars in the given string. Actually I want
> to grouping the same chars.
>
> For example;
>
> input : "34411113331123377"
> operation-> (3)(44
Nac Temha writes:
> Hi everyone,
>
> I want to do operation with chars in the given string. Actually I want to
> grouping the same chars.
>
> For example;
>
> input : "34411113331123377"
> operation-> (3)(44)()(333)(11)(2)(33)(77)
> outp
In Mark Lawrence
writes:
> > input = "3443331123377"
> > output = []
> > previous_ch = None
> > for ch in input:
> > if ch != previous_ch:
> > output.append(ch)
> > previous_ch = ch
> > print ''.join(output)
> >
> Cheat, you've used a list :)
Ack! I missed that
On 16/01/2014 22:30, John Gordon wrote:
In Nac Temha
writes:
--047d7b6d95d0367a3d04f01de490
Content-Type: text/plain; charset=ISO-8859-1
Hi everyone,
I want to do operation with chars in the given string. Actually I want to
grouping the same chars.
For example;
input
On 2014-01-17 00:24, Nac Temha wrote:
> Hi everyone,
>
> I want to do operation with chars in the given string. Actually I
> want to grouping the same chars.
>
> For example;
>
> input : "34411113331123377"
> operation-> (3)(44)()(333)(11)(
In Nac Temha
writes:
> --047d7b6d95d0367a3d04f01de490
> Content-Type: text/plain; charset=ISO-8859-1
> Hi everyone,
> I want to do operation with chars in the given string. Actually I want to
> grouping the same chars.
> For example;
> input : "344333112
Hi everyone,
I want to do operation with chars in the given string. Actually I want to
grouping the same chars.
For example;
input : "3443331123377"
operation-> (3)(44)()(333)(11)(2)(33)(77)
output: "34131237"
How can I do without list, regular expres
Op Tue, 09 Jul 2013 10:08:01 +, schreef Antoine Pitrou:
> This may be a IIS-specific problem.
> Take a look at
> http://stackoverflow.com/questions/16365483/iis-7-5-mercurial-setup-
ignoring-maxallowedcontentlength
> http://bz.selenic.com/show_bug.cgi?id=3905
> http://bugs.python.org/issue179
rewall, the traffic passes without a problem.
>
> The error I get is that the SSL handshake operation timed out.
> I tried some code that specifies the ssl protocol but the results are the
> same.
This may be a IIS-specific problem.
Take a look at
http://stackoverflow.com/questions/16365483/
, the code works with
Python 2.7.3 but not with Python 3.3.2. Another difference is that the
testserver has a direct ip, so nothing in between the machine and the
internet. I checked the firewall, the traffic passes without a problem.
The error I get is that the SSL handshake operation timed o
12.06.13 10:26, Peter Otten написав(ла):
@contextmanager
def my_urlopen(url):
resp = urlopen(url)
yield io.TextIOWrapper(resp.fp)
with urlopen(url) as resp:
yield io.TextIOWrapper(resp)
Note that last bugfix releases (i.e. 3.3.1) are needed. There was a
On Wed, Jun 12, 2013 at 2:26 AM, Peter Otten <__pete...@web.de> wrote:
> Applying these findings to your script:
>
> from contextlib import contextmanager
> try:
> # python-2.x
> from urllib2 import urlopen
> from ConfigParser import ConfigParser
>
> @contextmanager
> def my_urlopen(url)
.read_file(fp, source=filename)
> File
>
"/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/configparser.py",
> line 708, in read_file
> self._read(f, source)
> File
>
"/opt/local/Library/Frameworks/Python.framework/Versions/
ry/Frameworks/Python.framework/Versions/3.3/lib/python3.3/configparser.py",
line 1010, in _read
for lineno, line in enumerate(fp, start=1):
ValueError: I/O operation on closed file.
$
Is there a way to get this working in both python2 and python3?
This is a small script and I'm s
On Thu, 02 May 2013 02:10:11 -0700, Ana Dionísio wrote:
> Hello! I have several numpy arrays in my script and i want to add them.
> For example:
>
> a=[1,2,3,4,5]
> b=[1,1,1,1,1]
> c=[1,0,1,0,1]
These are not numpy arrays, they are lists of ints. Based on the error
message you quote:
TypeError
Ana Dionísio wrote:
> Hello! I have several numpy arrays in my script and i want to add them. For
> example:
> a=[1,2,3,4,5]
> b=[1,1,1,1,1]
> c=[1,0,1,0,1]
> for i in range(5):
> d[i]=a[i]+b[i]+c[i]
> print d
> [3,3,5,5,7]
> I did it like that but I get an error: "TypeError: unsupported
Hello! I have several numpy arrays in my script and i want to add them. For
example:
a=[1,2,3,4,5]
b=[1,1,1,1,1]
c=[1,0,1,0,1]
for i in range(5):
d[i]=a[i]+b[i]+c[i]
print d
[3,3,5,5,7]
I did it like that but I get an error: "TypeError: unsupported operand type(s)
for +: 'float' and 'num
On 1/29/2013 1:49 PM, Alok Singhal wrote:
On Tue, 29 Jan 2013 00:41:54 -0800, C. Ng wrote:
Is there a numpy operation that does the following to the array?
1 2 ==> 4 3
3 4 2 1
Thanks in advance.
How about:
import numpy as np
a = np.array([[1,2],[3,4]])
a
array([[1, 2], [3
On Tue, 29 Jan 2013 00:41:54 -0800, C. Ng wrote:
> Is there a numpy operation that does the following to the array?
>
> 1 2 ==> 4 3
> 3 4 2 1
>
> Thanks in advance.
How about:
>>> import numpy as np
>>> a = np.array([[1,2],[3,4]])
>>> a
On Tuesday, January 29, 2013 3:41:54 AM UTC-5, C. Ng wrote:
> Is there a numpy operation that does the following to the array?
>
>
>
> 1 2 ==> 4 3
>
> 3 4 2 1
>
>
>
> Thanks in advance.
>>> import numpy as np
>>> a=np.
C. Ng wrote:
> Is there a numpy operation that does the following to the array?
>
> 1 2 ==> 4 3
> 3 4 2 1
How about
>>> a
array([[1, 2],
[3, 4]])
>>> a[::-1].transpose()[::-1].transpose()
array([[4, 3],
[2, 1]])
Or did you mean
>&
Is there a numpy operation that does the following to the array?
1 2 ==> 4 3
3 4 2 1
Thanks in advance.
--
http://mail.python.org/mailman/listinfo/python-list
On 17 October 2012 09:14, Mark Lawrence wrote:
> On 17/10/2012 05:16, 8 Dihedral wrote:
>
>> What you really want is b=a.copy()
>> not b=a to disentangle two objects.
>>
>> __eq__ is used in the comparison operation.
>>
>>
> The winner Smartest An
On 17/10/2012 05:16, 8 Dihedral wrote:
What you really want is b=a.copy()
not b=a to disentangle two objects.
__eq__ is used in the comparison operation.
The winner Smartest Answer by a Bot Award 2012 :)
--
Cheers.
Mark Lawrence.
--
http://mail.python.org/mailman/listinfo/python-list
;
>
>
>
> Now if I try:
>
>
>
> >>> a=myclass()
>
> >>> a.name = 'test'
>
> >>> b=a
>
What you really want is b=a.copy()
not b=a to disentangle two objects.
__eq__ is used in the comparison operation.
> &
On Tue, Oct 16, 2012 at 9:51 AM, Pradipto Banerjee
wrote:
> I am trying to define class, where if I use a statement a = b, then instead
> of "a" pointing to the same instance as "b", it should point to a copy of
> "b", but I can't get it right.
>
> Currently, I have the following:
>
>
>
> c
On Tue, 16 Oct 2012 08:51:46 -0500, Pradipto Banerjee wrote:
> I am trying to define class, where if I use a statement a = b, then
> instead of "a" pointing to the same instance as "b", it should point to a
> copy of "b", but I can't get it right.
It cannot be done.
Name binding ("variable = val
Am 16.10.2012 15:51 schrieb Pradipto Banerjee:
I am trying to define class, where if I use a statement a = b, then instead of "a" pointing to the
same instance as "b", it should point to a copy of "b", but I can't get it right.
This is not possible.
Currently, I have the following:
On 10/16/2012 09:51 AM, Pradipto Banerjee wrote:
> I am trying to define class, where if I use a statement a = b, then instead
> of "a" pointing to the same instance as "b", it should point to a copy of
> "b", but I can't get it right.
>
>
The __eq__ method is called for equals comparison, like
I am trying to define class, where if I use a statement a = b, then instead of
"a" pointing to the same instance as "b", it should point to a copy of "b", but
I can't get it right.
Currently, I have the following:
class myclass(object):
def __init__(self, name='')
On 12/30/2011 03:37 PM, Steven D'Aprano wrote:
On Fri, 30 Dec 2011 10:57:06 -0800, Roy Smith wrote:
Ah, cool. I didn't know you could do that. Thanks.
Who are you talking to, and what is "that"?
Replies with no context are somewhat less than useful. It might have made
sense in your head whe
On Fri, 30 Dec 2011 10:57:06 -0800, Roy Smith wrote:
> Ah, cool. I didn't know you could do that. Thanks.
Who are you talking to, and what is "that"?
Replies with no context are somewhat less than useful. It might have made
sense in your head when you wrote the reply, but to those reading, it
Ah, cool. I didn't know you could do that. Thanks.
--
http://mail.python.org/mailman/listinfo/python-list
Hi,
On 12/30/2011 12:01 PM, Roy Smith wrote:
Is there some way to make urllib2.urlopen() perform a DELETE instead of a GET
or POST?
I'm hoping I don't have to dip way down into httplib. I've got an
application test framework built on top of urllib2. It makes heavy use of
HTTPCookieProces
Is there some way to make urllib2.urlopen() perform a DELETE instead of a GET
or POST?
I'm hoping I don't have to dip way down into httplib. I've got an application
test framework built on top of urllib2. It makes heavy use of
HTTPCookieProcessor. If I need to use the httplib calls directly
t;, line 860, in endheaders
self._send_output()
File "C:\Python25\lib\httplib.py", line 732, in _send_output
self.send(msg)
File "C:\Python25\lib\httplib.py", line 699, in send
self.connect()
File "C:\Python25\lib\httplib.py", line 683, in connect
On 1/11/2011 6:18 AM, wiz1024 wiz1024 wrote:
Hi
I have a problem on Windows with the module urllib2 with python 2.5
when i use the "urlopen" function, i have some time the following error :
error
I don't understand why suddenly this error arrives
The urlopen function is called from a thread
Hi
I have a problem on Windows with the module urllib2 with python 2.5
when i use the "urlopen" function, i have some time the following error :
error
I don't understand why suddenly this error arrives
The urlopen function is called from a thread
Thanks in advance.
--
http://mail.python.org/
On Dec 4, 11:37 pm, Madhu wrote:
> * jvt <5e1f79ab-5432-4f18-b896-362b7406c...@i18g2000yqn.googlegroups.com> :
> Wrote on Sat, 4 Dec 2010 19:34:53 -0800 (PST):
>
> |
> | I think this is correct:
> |
> |
> | (defun unknown-function (sym0)
> | (let (sym1 sym2)
> | (while (or sym2 sym0)
> |
> > Thank emacs, not me.
>
> Lisp? Still can't read it... ;-)- Hide quoted text -
>
This is because madhu did not explain how he reasoned.
Does it appear to you that she broke first two rules.
its a list flattener that also reverses the operation.
it appears that she took the
On Dec 5, 3:34 am, jvt wrote:
> On Dec 4, 4:49 pm, Barb Knox wrote:
>
>
>
>
>
> > In article
> > <46365e1d-42d8-4b3b-8e69-941472467...@u25g2000pra.googlegroups.com>,
> > small Pox wrote:
>
> > > Rules :
>
> > No need to add any additional hurdles -- the code as presented is
> > thoroughly unrea
On Dec 4, 4:49 pm, Barb Knox wrote:
> In article
> <46365e1d-42d8-4b3b-8e69-941472467...@u25g2000pra.googlegroups.com>,
> small Pox wrote:
>
> > Rules :
>
> No need to add any additional hurdles -- the code as presented is
> thoroughly unreadable by humans.
>
> > @1@ No execution of the functio
In article
<46365e1d-42d8-4b3b-8e69-941472467...@u25g2000pra.googlegroups.com>,
small Pox wrote:
> Rules :
No need to add any additional hurdles -- the code as presented is
thoroughly unreadable by humans.
> @1@ No execution of the function, only checking syntax
What about "desk checking"
Rules :
@1@ No execution of the function, only checking syntax
@2@ No profiling using a debugger or profiler
@3@ Editing allowed to make simpler variables
(defun unknown-function (nano-thermite-911-FBI-fat-per-diem-bustards-
kept-their-odious-mouth-shut-on-anthrax-and-911-lie)
(let (BERNA
> -Original Message-
> From: c...@rebertia.com [mailto: c...@rebertia.com]
> Sent: 2010年11月23日 19:12
> To: huisky
> Cc: python-list@python.org
> Subject: Re: Time and date operation
>
> On Tue, Nov 23, 2010 at 9:47 AM, huisky wrote:
>> Hi everyone,
>>
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