On 2012-12-02, Thomas Bach thb...@students.uni-mainz.de wrote:
On Sun, Dec 02, 2012 at 04:16:01PM +0100, Lutz Horn wrote:
len([x for x in l if x[1] == 'VBD'])
Another way is
sum(1 for x in l if x[1] == 'VBD')
which saves the list creation.
To also index them:
vbdix = [i for i, a in
In 8c0a3ea9-2560-47eb-a9c7-3770e41fe...@googlegroups.com
subhabangal...@gmail.com writes:
Dear Group,
I have a list of the following pattern,
[('', ''), ('Eastern', 'NNP'), ('Army', 'NNP'), ('Commander', 'NNP'), (=
'Lt', 'NNP'), ('Gen', 'NNP'), ('Dalbir', 'NNP'), ('Singh', 'NNP'),
Dear Group,
I have a list of the following pattern,
[('', ''), ('Eastern', 'NNP'), ('Army', 'NNP'), ('Commander', 'NNP'),
('Lt', 'NNP'), ('Gen', 'NNP'), ('Dalbir', 'NNP'), ('Singh', 'NNP'), ('Suhag',
'NNP'), ('briefed', 'VBD'), ('the', 'DT'), ('Army', 'NNP'), ('chief', 'NN'),
('on', 'IN'),
Him
Am 02.12.2012 um 16:03 schrieb subhabangal...@gmail.com:
I have a list of the following pattern,
[('', ''), ('Eastern', 'NNP'), ('Army', 'NNP'), ('Commander', 'NNP'),
('Lt', 'NNP'), ('Gen', 'NNP'), ('Dalbir', 'NNP'), ('Singh', 'NNP'), ('Suhag',
'NNP'), ('briefed', 'VBD'), ('the',
On Sun, Dec 02, 2012 at 04:16:01PM +0100, Lutz Horn wrote:
len([x for x in l if x[1] == 'VBD'])
Another way is
sum(1 for x in l if x[1] == 'VBD')
which saves the list creation.
Regards,
Thomas.
--
http://mail.python.org/mailman/listinfo/python-list
On Sunday, December 2, 2012 9:29:22 PM UTC+5:30, Thomas Bach wrote:
On Sun, Dec 02, 2012 at 04:16:01PM +0100, Lutz Horn wrote:
len([x for x in l if x[1] == 'VBD'])
Another way is
sum(1 for x in l if x[1] == 'VBD')
which saves the list creation.
Regards,
I have a nested list. Whenever I make a copy of the list, changes in one affect
the other, even when I use list(orig) or even copy the sublists one by one. I
have to manually copy each cell over for it to work.
Link to broken code: http://jimbopy.pastebay.net/1090401
--
On Sunday, September 23, 2012 2:31:48 PM UTC-7, jimbo1qaz wrote:
I have a nested list. Whenever I make a copy of the list, changes in one
affect the other, even when I use list(orig) or even copy the sublists one by
one. I have to manually copy each cell over for it to work.
Link to broken
On 23 September 2012 22:31, jimbo1qaz jimmyli1...@gmail.com wrote:
I have a nested list. Whenever I make a copy of the list, changes in one
affect the other, even when I use list(orig) or even copy the sublists one
by one. I have to manually copy each cell over for it to work.
Link to broken
On Mon, Sep 24, 2012 at 7:44 AM, jimbo1qaz jimmyli1...@gmail.com wrote:
On Sunday, September 23, 2012 2:31:48 PM UTC-7, jimbo1qaz wrote:
I have a nested list. Whenever I make a copy of the list, changes in one
affect the other, even when I use list(orig) or even copy the sublists one
by one.
On 09/23/2012 05:44 PM, jimbo1qaz wrote:
On Sunday, September 23, 2012 2:31:48 PM UTC-7, jimbo1qaz wrote:
I have a nested list. Whenever I make a copy of the list, changes in one
affect the other, even when I use list(orig) or even copy the sublists one
by one. I have to manually copy each
On Sun, 23 Sep 2012 14:31:48 -0700, jimbo1qaz wrote:
I have a nested list. Whenever I make a copy of the list, changes in one
affect the other,
Then you aren't making a copy.
py first_list = [1, 2, 3]
py second_list = first_list # THIS IS NOT A COPY
py second_list.append()
py print
On Sunday, September 23, 2012 2:31:48 PM UTC-7, jimbo1qaz wrote:
I have a nested list. Whenever I make a copy of the list, changes in one
affect the other, even when I use list(orig) or even copy the sublists one by
one. I have to manually copy each cell over for it to work.
Link to broken
On 9/23/2012 3:44 PM, jimbo1qaz wrote:
On Sunday, September 23, 2012 2:31:48 PM UTC-7, jimbo1qaz wrote:
I have a nested list. Whenever I make a copy of the list, changes in one affect
the other, even when I use list(orig) or even copy the sublists one by one. I
have to manually copy each cell
On Mon, Sep 24, 2012 at 10:56 AM, Littlefield, Tyler
ty...@tysdomain.com wrote:
I've not been following this thread fully, but why not just use x=list(y) to
copy the list?
The issue is that when you assign i=[1,2,3] and then j = i, j is just a
reference to i, which is why you change either and
On Tue, 28 Sep 2010 20:11:51 +0100, Rog wrote:
On Tue, 28 Sep 2010 11:59:08 -0700, geremy condra wrote:
On Tue, Sep 28, 2010 at 11:44 AM, Rog r...@pynguins.com wrote:
Hi all,
Have been grappling with a list problem for hours... a = [2, 3, 4,
5,.]
b = [4, 8, 2, 6,.]
Basicly I am
On 29 sep, 14:17, Steven D'Aprano st...@remove-this-
cybersource.com.au wrote:
On Tue, 28 Sep 2010 20:11:51 +0100, Rog wrote:
On Tue, 28 Sep 2010 11:59:08 -0700, geremy condra wrote:
On Tue, Sep 28, 2010 at 11:44 AM, Rog r...@pynguins.com wrote:
Hi all,
Have been grappling with a list
, Rog r...@pynguins.com wrote:
Hi all,
Have been grappling with a list problem for hours... a = [2, 3, 4,
5,.]
b = [4, 8, 2, 6,.]
Basicly I am trying to place a[0], b[0] in a seperate list IF a[2]
and b[2] is present.
I have tried sets, zip etc with no success. I am tackling
:59:08 -0700, geremy condra wrote:
On Tue, Sep 28, 2010 at 11:44 AM, Rog r...@pynguins.com wrote:
Hi all,
Have been grappling with a list problem for hours... a = [2, 3, 4,
5,.]
b = [4, 8, 2, 6,.]
Basicly I am trying to place a[0], b[0] in a seperate list IF a[2]
and b
Hi all,
Have been grappling with a list problem for hours...
a = [2, 3, 4, 5,.]
b = [4, 8, 2, 6,.]
Basicly I am trying to place a[0], b[0] in a seperate list
IF a[2] and b[2] is present.
I have tried sets, zip etc with no success.
I am tackling Euler projects with Python 3.1, with minimal
On Wed, Sep 29, 2010 at 12:14 AM, Rog r...@pynguins.com wrote:
Hi all,
Have been grappling with a list problem for hours...
a = [2, 3, 4, 5,.]
b = [4, 8, 2, 6,.]
Basicly I am trying to place a[0], b[0] in a seperate list
IF a[2] and b[2] is present.
You are not exactly clear
On Tue, Sep 28, 2010 at 11:44 AM, Rog r...@pynguins.com wrote:
Hi all,
Have been grappling with a list problem for hours...
a = [2, 3, 4, 5,.]
b = [4, 8, 2, 6,.]
Basicly I am trying to place a[0], b[0] in a seperate list
IF a[2] and b[2] is present.
I have tried sets, zip etc
On Tue, 28 Sep 2010 11:59:08 -0700, geremy condra wrote:
On Tue, Sep 28, 2010 at 11:44 AM, Rog r...@pynguins.com wrote:
Hi all,
Have been grappling with a list problem for hours... a = [2, 3, 4,
5,.]
b = [4, 8, 2, 6,.]
Basicly I am trying to place a[0], b[0] in a seperate list
On Wed, Sep 29, 2010 at 1:15 AM, rog r...@pynguins.com wrote:
Shashwat Anand wrote:
On Wed, Sep 29, 2010 at 12:14 AM, Rog r...@pynguins.com mailto:
r...@pynguins.com wrote:
Hi all,
Have been grappling with a list problem for hours...
a = [2, 3, 4, 5,.]
b = [4, 8, 2, 6
Thanks for the help so far.
The background to the problem is that the lists come from reading a
dbf file. The code that I am trying to write is to merge lines of the
dbf based on the first column. So in my example there would be three
lines:
a 2 3 4
b 10 11 12
a 2 3 4
The expected output from
Mark Lawrence breamore...@yahoo.co.uk wrote:
On 22/06/2010 15:06, Neil Webster wrote:
I have a list of lists such as [[a,2,3,4],[b,10,11,12], [a,2,3,4]]. I
need to combine the two lists that have the same first character in
this example 'a'. In reality there are 656 lists within the list.
[
Neil Webster a écrit :
Thanks for the help so far.
The background to the problem is that the lists come from reading a
dbf file. The code that I am trying to write is to merge lines of the
dbf based on the first column. So in my example there would be three
lines:
a 2 3 4
b 10 11 12
a 2 3 4
Hi all,
I've got a simple problem but it's defeated me and I was wondering if
somebody could point out where I'm going wrong or offer an alternative
solution to the problem?
I have a list of lists such as [[a,2,3,4],[b,10,11,12], [a,2,3,4]]. I
need to combine the two lists that have the same
On 23 June 2010 00:06, Neil Webster nswebs...@gmail.com wrote:
Hi all,
I've got a simple problem but it's defeated me and I was wondering if
somebody could point out where I'm going wrong or offer an alternative
solution to the problem?
I have a list of lists such as
On Wed, Jun 23, 2010 at 12:06 AM, Neil Webster nswebs...@gmail.com wrote:
I've got a simple problem but it's defeated me and I was wondering if
somebody could point out where I'm going wrong or offer an alternative
solution to the problem?
Is this a hypothetical/mathematical problem of sorts ?
On 22/06/2010 15:06, Neil Webster wrote:
Hi all,
I've got a simple problem but it's defeated me and I was wondering if
somebody could point out where I'm going wrong or offer an alternative
solution to the problem?
I have a list of lists such as [[a,2,3,4],[b,10,11,12], [a,2,3,4]]. I
need to
Neil Webster a écrit :
Hi all,
I've got a simple problem but it's defeated me and I was wondering if
somebody could point out where I'm going wrong
1/ not posting working code (got a NameError)
2/ not posting the expected output
3/ not posting the actual output
or offer an alternative
On Sat, 17 Apr 2010 13:31:54 -0700 Chris Rebert c...@rebertia.com
wrote:
On Sat, Apr 17, 2010 at 12:40 PM, Martin Hvidberg
mar...@hvidberg.net wrote:
I have this code, it builds up a data structure of nested lists,
and filling data in them. My problem is that it seems that one of
the
Dear list
I have this code, it builds up a data structure of nested lists, and filling
data in them.
My problem is that it seems that one of the lists SA[1] is not a list of unique
instances but rather individual links to the same variable.
In the example below I assign 'X' to what I intended
On Sat, Apr 17, 2010 at 12:40 PM, Martin Hvidberg mar...@hvidberg.net wrote:
I have this code, it builds up a data structure of nested lists, and filling
data in them.
My problem is that it seems that one of the lists SA[1] is not a list of
unique instances but rather individual links to the
Hi All,
I have one problem for List. Like that:
format='just a little test'
part = format.split('')
print part
the result is : ['just ', 'a', ' ', '', 'little', '', ' test']
the list part have 7 element.
If I execute part[1], I have got 'a'. If I execute part[2], I have
got ' '. But, if I
On Wed, Dec 10, 2008 at 3:40 PM, dongzhi [EMAIL PROTECTED] wrote:
If I execute part[1], I have got 'a'. If I execute part[2], I have
got ' '. But, if I execute part[1::2], I have got ['a', '', '']. I
don't know why. Please tell me why.
Perhaps you meant:
part[1:2]
pydoc list
This will tell
On Dec 10, 2:00 pm, James Mills [EMAIL PROTECTED]
wrote:
On Wed, Dec 10, 2008 at 3:40 PM, dongzhi [EMAIL PROTECTED] wrote:
If I execute part[1], I have got 'a'. If I execute part[2], I have
got ' '. But, if I execute part[1::2], I have got ['a', '', '']. I
don't know why. Please tell me
On Tue, 09 Dec 2008 21:40:08 -0800, dongzhi wrote:
I have one problem for List. Like that:
format='just a little test'
part = format.split('')
print part
the result is : ['just ', 'a', ' ', '', 'little', '', ' test']
the list part have 7 element.
If I execute part[1], I have got
I wish to create a list of empty lists and then put something in one of
the empty lists. Below is what I tried, but instead of appending 1 to
a[2] it was appended to all the sub-lists in a. What am I doing wrong?
a = 6*[[]]
a
[[], [], [], [], [], []]
a[2].append(1)
a
[[1], [1], [1],
Alan Bromborsky wrote:
I wish to create a list of empty lists and then put something in one of
the empty lists. Below is what I tried, but instead of appending 1 to
a[2] it was appended to all the sub-lists in a. What am I doing wrong?
a = 6*[[]]
a
[[], [], [], [], [], []]
I'm creating one aplicattion and I use SQLObject, but I have a little
problem, when I try to create one table my aplicattion crash! :(
Let me show you:
[EMAIL PROTECTED]:~/Proyectos/ghhp/lib$ python
Python 2.4.4 (#2, Apr 5 2007, 20:11:18)
[GCC 4.1.2 20061115 (prerelease) (Debian 4.1.1-21)] on
[EMAIL PROTECTED] wrote:
For example i write the following code in the Python command line;
list = ['One,Two,Three,Four']
Then enter this command, which will then return the following;
['One,Two,Three,Four']
This is already wrong. Assignments do not return anything.
Georg
--
For example i write the following code in the Python command line;
list = ['One,Two,Three,Four']
Then enter this command, which will then return the following;
['One,Two,Three,Four']
Now the problem, reading through the Python tutorial's, it describe's
that list's can sliced, concatenated and
[EMAIL PROTECTED] wrote:
For example i write the following code in the Python command line;
list = ['One,Two,Three,Four']
Then enter this command, which will then return the following;
['One,Two,Three,Four']
Now the problem, reading through the Python tutorial's, it describe's
[EMAIL PROTECTED] wrote:
For example i write the following code in the Python command line;
list = ['One,Two,Three,Four']
Then enter this command, which will then return the following;
['One,Two,Three,Four']
Now the problem, reading through the Python tutorial's, it describe's
that
[EMAIL PROTECTED] wrote:
It looks like the PyTensor object *should* have .xx, .xy, etc
properties, but they may be accessible through a matrix, i.e. .t(i,j)
Thanks to all of you for your help!
The solution is easy: The tensor components have labels t11, t12,...
Good guess ruibalp!
--
placid:
This may be a solution:
l1 = ['acXXX1', 'XXX2', 'wXXX3', 'kXXX5']
l2 = [ 'bXXX1', 'xXXX2', 'efXXX3', 'yXXX6', 'zZZZ9']
import re
findnum = re.compile(r[0-9]+$)
s1 = set(int(findnum.search(el).group()) for el in l1)
s2 = set(int(findnum.search(el).group()) for el in l2)
nmax =
placid wrote:
Hi all,
I have two lists that contain strings in the form string + number for
example
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the second list contains the following
list1 = [ ' XXX1',
placid wrote:
But there may be other characters before XXX (which XXX is constant). A
better example would be, that string s is like a file name and the
characters before it are the absolute path, where the strings in the
first list can have a different absolute path then the second list
placid wrote:
Hi all,
I have two lists that contain strings in the form string + number for
example
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the second list contains the following
list1 = [ ' XXX1',
Gerard Flanagan wrote:
placid wrote:
Hi all,
I have two lists that contain strings in the form string + number for
example
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the second list contains the
placid [EMAIL PROTECTED] writes:
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the second list contains the following
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX6']
I think you meant list2 for the second one.
Thank you all for the replies, i now have a better solution.
Cheers
--
http://mail.python.org/mailman/listinfo/python-list
Hi all,
I have two lists that contain strings in the form string + number for
example
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the second list contains the following
list1 = [ ' XXX1', 'XXX2', 'XXX3',
placid wrote:
Hi all,
I have two lists that contain strings in the form string + number for
example
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the second list contains the following
list1 = [ ' XXX1',
Simon Forman wrote:
Finally, you can say:
for i in xrange(1,10):
s = XXX1%04i % i
if s not in list1 and s not in list2:
print s
HTH,
~Simon
D'oh! Forgot to break.
for i in xrange(1,10):
s = XXX1%04i % i
if s not in list1 and s not in list2:
print s
Simon Forman wrote:
placid wrote:
Hi all,
I have two lists that contain strings in the form string + number for
example
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the second list contains the
placid wrote:
Simon Forman wrote:
placid wrote:
Hi all,
I have two lists that contain strings in the form string + number for
example
list1 = [ ' XXX1', 'XXX2', 'XXX3', 'XXX5']
the second list contains strings that are identical to the first list,
so lets say the
I can't figure out why my code is not working. I thought I had the list
copied correctly:
Here is my code:
a=[[u'HF', []], [u')F', [u'75']], [u'RE', []], [u'C', []]]
b=a[:]
for index in reversed(range(0,len(a)-1)):
if '75' in b[index][1]:
b[index][1].remove('75')
Hi,
if u check the id's of a and b lists and also its elements, you will
obeserve that the id's of a and b have changed but id's of their
elements have not changed.
If you make a deep copy of the list a and then make your changes in
that list, it shud work. this can be done using the copy
manstey wrote:
for index in reversed(range(0,len(a)-1)):
if '75' in b[index][1]:
b[index][1].remove('75')
b[index][1].append('99')
What on earth is all that messing around in the for loop intended to do? If
you want a range from len(a)-2 to 0 inclusive then just do it in
Thanks very much. Deepcopy works fine, as does reversed(b). I thought I
needed the index number but I didn't.
Duncan Booth wrote:
manstey wrote:
for index in reversed(range(0,len(a)-1)):
if '75' in b[index][1]:
b[index][1].remove('75')
b[index][1].append('99')
What
Fredrik Lundh wrote:
Jon Bowlas wrote:
(snip)
But I get the following error- Line 5: Yield statements are not allowed.
umm. I might be missing something, but I cannot find any trace of that
error message in the Python interpreter source code. it doesn't even look
like a Python
HI all,
I'm fairly new to python and programming in general so I was hoping someone
here may be able to help me. Let me explain what the problem I'm having is:
I am trying to parse the XML of an attributes object I created, this object
has the structure outlined below. Everything is ok on the
Jon Bowlas wrote:
attobject = context.get_attobject()
navstring = context.get_uclattribute(attobject, 'ucl_navhide')
hiddennavelements = navstring.split(' ')
for hiddennavelement in hiddennavelements:
return hiddennavelement
So the script 'get_attobject' basically looks for an instance
are not allowed.
Any ideas
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
Fredrik Lundh
Sent: 16 August 2005 13:44
To: python-list@python.org
Subject: Re: looping list problem
Jon Bowlas wrote:
attobject = context.get_attobject()
navstring
Well, you are returning prematurely from a for loop, so that is why you
are only getting the first value. Its just like:
for i in range(100):
return i
It doesn't matter how big the range is you are iterating over, you'll
return on the first element and that's it.
If what you want is
Jon Bowlas wrote:
Ok so I changed it to this:
attobject = context.get_attobject()
navstring = context.get_uclattribute(attobject, 'ucl_navhide')
hiddennavelements = navstring.split(' ')
for hiddennavelement in hiddennavelements:
yield hiddennavelements
But I get the following error-
Jon Bowlas wrote:
Ok so I changed it to this:
attobject = context.get_attobject()
navstring = context.get_uclattribute(attobject, 'ucl_navhide')
hiddennavelements = navstring.split(' ')
for hiddennavelement in hiddennavelements:
yield hiddennavelements
But I get the following
Jon Bowlas wrote:
Ok so I changed it to this:
attobject = context.get_attobject()
navstring = context.get_uclattribute(attobject, 'ucl_navhide')
hiddennavelements = navstring.split(' ')
for hiddennavelement in hiddennavelements:
yield hiddennavelements
But I get the following
I'm doing this in zope.
Jon
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Peter
Otten
Sent: 16 August 2005 14:41
To: python-list@python.org
Subject: RE: looping list problem
Jon Bowlas wrote:
Ok so I changed it to this:
attobject
Jon Bowlas wrote:
Incidentally I'm doing this in zope.
Many posters (including me) in this newsgroup don't do zope, so your best
option is to ask on a zope-related mailing list.
I was hoping that this would loop through the elements in the list
returned by the hiddens function comparing them
Many thanks for your help, worked a treat
Jon
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Peter
Otten
Sent: 16 August 2005 17:25
To: python-list@python.org
Subject: RE: looping list problem
Jon Bowlas wrote:
Incidentally I'm doing this in zope
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