Each number in the list belowresides in a quantile. When put in order,
there are 10 numbers, so the first is in the 0.1 quantile, the second
in the 0.2 etc.
Lets say we have 10 examples of systolic blood pressure from 30 year olds:
104,95,106,105,110,150,101,98,85,104
This is a random
Please do tell us exactly what you are doing via a reproducible example
(see the footer to every R-help message).
I added paper=special to postscript() to make this easier: are you using
it? From the help page
The postscript produced for a single R plot is EPS (_Encapsulated
Hello,
I'm trying to document this little package I'm working on and have the
following issue:
one of the man files (*.Rd) contains this bit
\value{
Returns a \code{\link[base]{data.frame}} representing the tabular data.
}
The resulting link is broken on my debian system. It points
to
I am having trouble getting a loop to work for the following problem. Any
help would be much appreciated. Thanks.
I need to find the slope and intercept from the linear regression of Drug
Level on Day by Participant. There are a total of 37 Participants. I need to
store the Participant, Label,
look at function lmList() from package 'nlme', e.g.,
# say 'dat' is you data.frame
library(nlme)
fm - lmList(DrugLevel ~ Day | Participant, data = dat)
fm
summary(fm)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic
On Mon, 3 Dec 2007, Johannes Graumann wrote:
Hello,
I'm trying to document this little package I'm working on and have the
following issue:
one of the man files (*.Rd) contains this bit
\value{
Returns a \code{\link[base]{data.frame}} representing the tabular data.
}
The resulting
Cleber N. Borges a écrit :
hello all,
I trying to use the package 'odfWeave'
and I get the follow error:
### error message
#
...
Removing content.xml
Post-processing the contents
Error in .Call(RS_XML_Parse, file,
I'm just a R user who joined the list searching solution for a problem.
I do not think rating helpers is a good idea. For once, they do it freely;
no need to harrash (?) anybody. On the other hand, it could have the
opposite effect; people afraid to get a bad rating do not post
Hello R Experts,
I started to work with the qcc package and it wprks quite nicely.
Heres My Code:
n -
c(55,5,94,25,10,15,15,40,44,34,90,114,204,37,30,28,12,68,64,29,24,14,31,16,62,45,55,20,24,14,9,19,76,57,55,42,6,
54,32,117,19,32,9,11,13,31,27,33,44,28)
x -
Dear useRs,
I'm trying to specify the colour of a factor with ggplot2. The example
below gets me close to what I want, but it's missing a legend.
Any ideas?
Thanks,
Thierry
library(ggplot2)
dataset - data.frame(x = rnorm(40), y = runif(40), z = gl(4, 10, labels
= LETTERS[1:4]))
ggplot(data =
Prof Brian Ripley wrote:
So you are talking about the HTML conversion of your help (.Rd) file?
(Links appear in other versions too.)
The HTML links are intended to be used via help.start(), not directly, and
I think you find it actually points to ../../base/html/data.frame.html,
which is
On Mon, 3 Dec 2007, Johannes Graumann wrote:
Prof Brian Ripley wrote:
So you are talking about the HTML conversion of your help (.Rd) file?
(Links appear in other versions too.)
The HTML links are intended to be used via help.start(), not directly, and
I think you find it actually points
There are three ways listed here:
https://stat.ethz.ch/pipermail/r-help/2007-May/132866.html
On Dec 2, 2007 5:33 PM, stathelp [EMAIL PROTECTED] wrote:
I am having trouble getting a loop to work for the following problem. Any
help would be much appreciated. Thanks.
I need to find the slope
posted mailed
Prof Brian Ripley wrote:
Using non-linked HTML file: style sheet and hyperlinks may be incorrect
- which is what happens ... how to switch to linked HTML file?
It all works via help.start() (as I did say), at least in a reliable R
front end. Running help.start() is how you
Hello everyone. I want to thank you for your response.
I tried this on weekend to attack my problem:
1) Turned into factors all my variables to tabulate:
infec1-bamas$P2_A
infec2-bamas$P2_B
infec3-bamas$P2_C
aglomera-bamas$QCL_1
Where bamas is my data
tintin_et_milou wrote:
Hello,
I have a vector of two columns like this:
m/ZI
1000.235 125
1000.356 126.5
...
and a second vector with only one column:
m/Z
995.547
1000.320
...
For each value of the second vector I want to associate the
On Mon, 3 Dec 2007, Johannes Graumann wrote:
posted mailed
Prof Brian Ripley wrote:
Using non-linked HTML file: style sheet and hyperlinks may be incorrect
- which is what happens ... how to switch to linked HTML file?
It all works via help.start() (as I did say), at least in a reliable
Hi,everyone.
I use the following program calculates Fisher's alpha from counts of
individuals and species. The program is wrote by Prof. Kyle Harm.
However, when I run the program, it can work very quickly sometimes, but it can
not work very well sometimes. It depends on the counts of
On Mon, 3 Dec 2007, Johannes Graumann wrote:
Hmmm, I see. This is all local. So there does not seem to be a way to make any
old R installation that loads the package initialize this functionality, so
that the help files will be correctly interlinked directly after require
or library? How do
qplot(data=dataset, x, y, colour=z)
ONKELINX, Thierry wrote:
Dear useRs,
I'm trying to specify the colour of a factor with ggplot2. The example
below gets me close to what I want, but it's missing a legend.
Any ideas?
Thanks,
Thierry
library(ggplot2)
dataset - data.frame(x =
Hmmm, I see. This is all local. So there does not seem to be a way to make any
old R installation that loads the package initialize this functionality, so
that the help files will be correctly interlinked directly after require
or library? How do other packages manage that?
Joh
On Monday 03
zhang jian wrote:
Hi,everyone.
I use the following program calculates Fisher's alpha from counts of
individuals and species. The program is wrote by Prof. Kyle Harm.
However, when I run the program, it can work very quickly sometimes, but
it can not work very well sometimes. It depends
Dear Domenico,
It looks like my question wasn't very clear. I want to specify the
colours meself. Colour = z will use default colours and I'd like to
change those. I need to change them into red, green, blue and black
instead of pink, brown, green and blue.
The solution should have the layout
Hello,
I would like to perform a linear regression and the data is a list.e.g
lm(list$abc~., data=list) or lm(abc~., data=list), which would give the same
result.
The problem is I would like to call the response variable in a more general
form. What I try to achieve is sth like
try
RSiteSearch(Fisher's alpha)
which indicates that there is the fishers.alpha() function in package
'untb' that does the same thing, e.g.,
fishers.alpha(1000, 70)
fishers.alpha(1580, 30)
fishers.alpha(1000, 7)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Hi Thierry,
Have a look at http://had.co.nz/ggplot2/scale_identity. (The way you
are currently doing it only works because you are not using any kind
of grouping/facetting, and I'm thinking about adding an explicit
message/warning for this case)
Hadley
On 12/3/07, ONKELINX, Thierry [EMAIL
In using cor(data.frame), it is annoying that you have to explicitly
filter out non-numeric columns, and when you don't, the error message
is misleading:
cor(iris)
Error in cor(iris) : missing observations in cov/cor
In addition: Warning message:
In cor(iris) : NAs introduced by coercion
It
Thorsten Muehge [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]
Hello R Experts,
I started to work with the qcc package and it wprks quite nicely.
Heres My Code:
n -
c(55,5,94,25,10,15,15,40,44,34,90,114,204,37,30,28,12,68,64,29,24,14,31
,16,62,45,55,20,24,14,9,19,76,57,55,42,6,
You can calculate the Kendall rank correlation with such a matrix
so you would not want to exclude factors in that case:
cor(iris, method = kendall)
Sepal.Length Sepal.Width Petal.Length Petal.WidthSpecies
Sepal.Length 1. -0.076996790.7185159 0.6553086 0.670
Hi Everyone,
I'm trying to load some C++ code using dyn.load but I'm getting
unresolved symbols associated with some external libraries
(CSparse). I gather this is something to do with linking as the the
code compiles fine. However, I've passed
I want to know how to use R to get the
numerical values of the estimated ACF b(k) and PACF b kk ?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Thanks Hadley.
The page you referred to was actually
http://had.co.nz/ggplot2/scale_identity.html
The solution to my problem was
library(ggplot2)
dataset - data.frame(x = rnorm(40), y = runif(40), z = gl(4, 10, labels
= LETTERS[1:4]))
dataset$MyColour - factor(dataset$z, labels = c(red, green,
Perhaps:
acf(rnorm(100), plot=FALSE)$acf[,,1]
pacf(rnorm(100), plot=FALSE)$acf[,,1]
On 02/12/2007, fancy hou [EMAIL PROTECTED] wrote:
I want to know how to use R to get the
numerical values of the estimated ACF b (k) and PACF b kk ?
__
I'm interested in performing permutation tests of regression tree models (my
models are developed using rpart). The package rpart.permutation is not
available for Windows, so I am wondering if there are any alternative
packages available (a search of R-project.org did not turn up anything).
If i understand your question, you can try this:
lapply(paste(lis$, names(lis), ~ . , sep=), lm, data=lis)
On 03/12/2007, livia [EMAIL PROTECTED] wrote:
Hello,
I would like to perform a linear regression and the data is a list.e.g
lm(list$abc~., data=list) or lm(abc~., data=list), which
Dear All,
I have two vectors:
tt = c(6.87, 7.43, 6.4, 4.5, 5.5, 5.87, NA, NA, NA, 7.7)
year = 1966:1975
Residuals
lm(tt~year)$res
do not contain NAs for the three years of missing temperature tt. Is there a
simple way to get these NAs back into the residual's vector?
Thank you,
Sorama
Try this:
resid(lm(tt~year, na.action = na.exclude))
1 2 3 4 5 6 7
0.7114894 1.2231383 0.1447872 -1.8035638 -0.8519149 -0.5302660 NA
8 9 10
NA NA 1.1063298
On Dec 3, 2007 10:31
See:
http://www.nabble.com/matrix-(column-wise)-multiple-regression-t4862261.html
On Dec 3, 2007 8:58 AM, livia [EMAIL PROTECTED] wrote:
Hello,
I would like to perform a linear regression and the data is a list.e.g
lm(list$abc~., data=list) or lm(abc~., data=list), which would give the same
You need to use na.action=na.exclude, _and_ to use the proper extractor
function residuals() rather than pick up a component of the fitted object
by partial matching.
See ?residuals.lm and ?naresid
On Mon, 3 Dec 2007, rem la wrote:
Dear All,
I have two vectors:
tt = c(6.87, 7.43, 6.4,
On 12/2/07, Jim Lemon [EMAIL PROTECTED] wrote:
[EMAIL PROTECTED] wrote:
Hi Jim,
Thanks for getting back to me so quickly.
I did look at color.legend, but that seems to plot colored blocks for
the observations (in this case the mean) and not for the color.scale
(which represents
Hello
Works fine for me:
data
-scan(file='http://en.wikipedia.org/wiki/Special:Recentchanges',what='c
haracter')
Read 3581 items
So I don't think it is the Wikipedia end.
Regards
John Seers
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf
On 3 December 2007 at 14:54, Jarrod Hadfield wrote:
| I'm trying to load some C++ code using dyn.load but I'm getting
| unresolved symbols associated with some external libraries
| (CSparse). I gather this is something to do with linking as the the
| code compiles fine. However, I've
Hallo,
I am trying to import a website and structure it from within R:
The following code:
data -
scan(file='http://en.wikipedia.org/wiki/Special:Recentchanges',what='character')
results in the error:
Error in file(file, r) : unable to open connection
In addition: Warning message:
cannot
Hi Dirk,
ldd is not bringing up csparse which suggests that it is a linking
problem. For liking I used both the SHLIB and INSTALL comands using -
L (see below), but both generate the same problem.
Cheers,
Jarrod
[EMAIL PROTECTED] ~]$ R CMD SHLIB ~/Work/AManal2/src/SStest.cc -L/
I have the following timeseries tab
=
str(tab)
mts [1:23, 1:2] 79.5 89.1 84.9 75.7 72.8 ...
- attr(*, dimnames)=List of 2
..$ : NULL
..$ : chr [1:2] Ipex...I Omel...E
- attr(*, tsp)= num [1:3] 2006 2008 12
- attr(*, class)= chr [1:2] mts ts
tab
Good evening,
I am trying to add labels to the point of a simple plot, using the
text() function; the problem is that sometimes, if two points are too
close to each other, labels overlap and are no longer readable.
I was wondering whether there are options that I can use to prevent this
Hi Jim,
Thanks for your suggestion. My guess is that most of the time is taken
by various kinds of assignments that I am making using loops; and these
can be done without loops. In a follow-up post, I will try to explain in
greater detail each part of my code (especially the parts where
John Sorkin [EMAIL PROTECTED] wrote:
I believe we need to know the following about packages:
(1) Does the package do what it purports to do, i.e. are the results valid?
(2) Have the results generated by the package been validate against some
other statistical package, or hand-worked example?
... but the best option is not to do this kind of technicolor extravaganza
at all!
See ?dotplot (in lattice) and ?dotchart for better alternatives.
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of hadley
,
Thank you for trying. Strange.
I am using R version 2.6.0 Patched (2007-11-09 r43408) on OSX and it is
not working. I guess it has something to do with the language settings.
However.
Regards
Marc Schwenzer
john seers (IFR) wrote:
Hello
Works fine for me:
data
On 12/3/07, Bert Gunter [EMAIL PROTECTED] wrote:
... but the best option is not to do this kind of technicolor extravaganza
at all!
Yes, good point! And of a course of a scatterplot of mean vs variance
will best reveal the relationship between the two variables.
Hadley
--
http://had.co.nz/
On 12/3/2007 12:21 PM, Biscarini, Filippo wrote:
Good evening,
I am trying to add labels to the point of a simple plot, using the
text() function; the problem is that sometimes, if two points are too
close to each other, labels overlap and are no longer readable.
I was wondering whether
Jim and others,
As far as I can see the computation of certain conditional probabilities
(required for computing my likelihood function) is what is slowing down
the evaluation of the likelihood function. Let me explain what these
conditional probabilities are and how I am (no doubt inefficiently)
In the code below the first source command works fine, but the second
does not, as can be seen from the error message. Is there a way to
have the second command work?
I am using R 2.6.1 on Windows Vista.
(The command that is in the clipboard is just x - 3)
source(clipboard, echo = F)
Hello,
I have a problem when making packages with version 2.6.1. I have a
package which I could install in version 2.5.1. I have made some
modifications of the package, and I would like to install it to 2.6.1. I
check the package with R CMD check, I build it with R CMD build and when
I try to
Hi All.
I would like to compute a separate covariance matrix for a set of variables
for each of the levels of a factor and then compute the average covariance
matrix over the factor levels. I can loop through this computation but I
need to perform the calculation for a large number of levels and
You are right but I was just trying to stick to the same example.
In reality it would be ok as long as its an ordered factor. One could
restrict it to those of class ordered.
On Dec 3, 2007 1:58 PM, Liaw, Andy [EMAIL PROTECTED] wrote:
I'd call that another infelicity. Species is supposed to
Hi,
I wrote a panel function called panelwhite.corplot. If i use this function in a
coplot is working fine, but if i use same function with xyplot i get the error:
Error using packet 1: plot.new has not been called yet . and so on filling
all my plots.
So with:
coplot(be~ch|dbh1,
Hi,
If I do the following I can have a NULL in a list
x - list( 1, list(3,NULL,4), 5 )
x
[[1]]
[1] 1
[[2]]
[[2]][[1]]
[1] 3
[[2]][[2]]
NULL
[[2]][[3]]
[1] 4
[[3]]
[1] 5
This is a good thing for me as it can be passed through into C++ where I
can know the value is missing. (Can't seem to
I'd call that another infelicity. Species is supposed to be nominal,
not ordinal, so rank correlation wouldn't make much sense. So what does
cor(, method=kendall) do? It looks like it simply uses the underlying
numeric code. (Change Species to numerics and you'll see the same
answer.)
affy snp [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
For example, it should go from
very red---red---less red---darkgreen---very green coinciding
with the descending order of values, just like the very left panel
shown in
This can be done with plot.zoo and a panel function:
tab - ts(cbind(A = c(79.47, 89.13, 84.86, 75.68, 72.82, 78.87, 93.46,
78.18, 82.46, 77.25, 80.95, 84.39, 81.7, 74.76, 65.29, 60.3,
66.59, 73.19, 92.39, 65.76, 77.45, 74.22, 101.36, 100.01), B = c(77.95,
76.73, 51.2, 51.86, 51.29, 49.45, 53.88,
I'm working with Andrew Gelman on a book project and we're having some
difficulties getting coef() to work in some lmer() calls.
Some versions of the model work and some do not. For example, this works
(in that we can run the model and do coef() from the output):
R2 - lmer(y2 ~ factor(z.inc) +
A new package 'bvls' is available on CRAN.
The package provides an R interface to the Stark-Parker algorithm for
bounded-variable least squares (BVLS) that solves A x = b with the
constraint l = x = u under least squares criteria, where l,x,u \in R^n,
b \in R^m and A is an m \times n matrix.
The
Duncan Murdoch wrote:
On 12/3/2007 12:21 PM, Biscarini, Filippo wrote:
Good evening,
I am trying to add labels to the point of a simple plot, using the
text() function; the problem is that sometimes, if two points are too
close to each other, labels overlap and are no longer readable.
I
On 12/3/07, Monica Pisica [EMAIL PROTECTED] wrote:
Hi,
I wrote a panel function called panelwhite.corplot. If i use this function in
a coplot is working fine, but if i use same function with xyplot i get the
error: Error using packet 1: plot.new has not been called yet . and so on
Thanks for your help, but there is some more problem. The two vectors have
not the same length so there is a problem with cbind. I give you an example.
My first vector is
g[g[,1]2035 g[,1]2050,]
M.Z Intensity
2035.836 652.9494
2035.939 664.5841
2036.043 696.0554
2036.146
Prof Brian Ripley wrote:
Please do tell us exactly what you are doing via a reproducible example
(see the footer to every R-help message).
That code was in my original message, here it is again:
par(bg=yellow,
lab=c(10,6,7),
#mai=c(1.25, 1, 0.2, 0.2),
Hello there,
I am having trouble installing R-2.6.1 on GNU/linux.
Here is how I configure and run it:
./configure --with-x=no --enable-R-shlib
make
The configure step is uneventful, the tail end of make follows. Does anyone
have any experience with that?
Thanks a lot in advance for any
Hi All.
I would like to compute a separate covariance matrix for a set of
variables for each of the levels of a factor and then compute the
average covariance matrix over the factor levels. I can loop through
this computation but I need to perform the calculation for a large
number of levels and
On Mon, 3 Dec 2007, Rees, David wrote:
Hi,
If I do the following I can have a NULL in a list
x - list( 1, list(3,NULL,4), 5 )
x
[[1]]
[1] 1
[[2]]
[[2]][[1]]
[1] 3
[[2]][[2]]
NULL
[[2]][[3]]
[1] 4
[[3]]
[1] 5
This is a good thing for me as it can be passed through into C++
Dear Greg,
thank you for your reply - that is very helpful!
regards
Avril
Greg Snow [EMAIL PROTECTED] wrote:
As an alternative you could try quantile regression (find a regression
line for the 95th percentile), if the relationship between max(y) and x
is only due to more points (and therefore
I made a google group archive of current and future R-help posts at
http://groups.google.com/group/r-help-archive
If you are signed-up for the R-help mailing list with a gmail account you
can reply to posts through the google group pages. Note that this is not a
separate mailing-list, just a copy
Unfortunately something doesn't work:
tab - ts(cbind(A = c(79.47, 89.13, 84.86, 75.68, 72.82, 78.87, 93.46,
+ 78.18, 82.46, 77.25, 80.95, 84.39, 81.7, 74.76, 65.29, 60.3,
+ 66.59, 73.19, 92.39, 65.76, 77.45, 74.22, 101.36, 100.01), B = c(77.95,
+ 76.73, 51.2, 51.86, 51.29, 49.45, 53.88, 47.96,
Hi,
I have a vector in a data frame that looks
something like this:
day-c('Day -1','Day 6','Day 10')
This vector specifies the order in which several
panel will appear in a lattice plots. But the order in
which such plots will appear will be the following:
Day -1, Day 10, Day 6. Which
On 12/3/07, Judith Flores [EMAIL PROTECTED] wrote:
Hi,
I have a vector in a data frame that looks
something like this:
day-c('Day -1','Day 6','Day 10')
This vector specifies the order in which several
panel will appear in a lattice plots. But the order in
which such plots will
On Mon, 2007-12-03 at 13:21 -0800, Judith Flores wrote:
Hi,
I have a vector in a data frame that looks
something like this:
day-c('Day -1','Day 6','Day 10')
This vector specifies the order in which several
panel will appear in a lattice plots. But the order in
which such
Returning to my original post, I still believe that a basic work-horse
like cor(data.frame) with the default method=pearson should try to do
something more useful in this case than barf with a misleading error
message if the data frame contains character variables.
To paraphrase Einstein,
Try mixedsort in the gtools package.
On Dec 3, 2007 4:21 PM, Judith Flores [EMAIL PROTECTED] wrote:
Hi,
I have a vector in a data frame that looks
something like this:
day-c('Day -1','Day 6','Day 10')
This vector specifies the order in which several
panel will appear in a lattice
1.
If you would like to use your way, you can reduce the steps by assigning the
common factor levels to all three variables in step 1).
Then, all the tables will have the same dimension, so you can completely
skip step 3) and 4).
Then, the code would be slightly more general but not general
I made a google group archive of current and future R-help posts at
http://groups.google.com/group/r-help-archive
If you are signed-up for the R-help mailing list with a gmail account
you can post/reply through the google group pages. Note that this is
not a separate mailing-list, just a copy of
I played around with this a bit more and noticed that the plinear
algorithm of nls converged using nearly every starting value I tried. In fact
A = 0 was the only starting value that I could find that did not converge.
Note that with plinear you only specify the starting values for non-linear
eugen pircalabelu wrote:
Good afternoon!
I'm trying to model a time series on the following data, which represent a
monthly consumption of juices:
x-scan()
1: 2859 3613 3930 5193 4523 3226 4280 3436 3235 3379 3517 6022
13: 4465 4604 5441 6575 6092 6607 6390 6150 6488
my understanding is that this behavior is known (the help file
mentions something along these lines in the example).
i'd use something like:
theText - a,,b,
theText - gsub(\\,$, , , theText)
and then use strsplit() on theText
b
On Dec 3, 2007, at 6:22 PM, dankelley wrote:
I have a
I have a comma-separated data file in which trailing commas sometimes occur.
I am using strsplit to extract the data from this file, and it seems great
except in cases with trailing comma characters.
The example below illustrates. What I'd like is to get a fourth element in
the answer, being
dankelley wrote:
I have a comma-separated data file in which trailing commas sometimes occur.
I am using strsplit to extract the data from this file, and it seems great
except in cases with trailing comma characters.
The example below illustrates. What I'd like is to get a fourth element in
Try appending another comma:
strsplit(paste(a,,b,, ,, sep = ), ,)
On Dec 3, 2007 6:22 PM, dankelley [EMAIL PROTECTED] wrote:
I have a comma-separated data file in which trailing commas sometimes occur.
I am using strsplit to extract the data from this file, and it seems great
except in
This works perfectly. Thanks!
Peter Dalgaard wrote:
Hmm, I don't think strsplit can do that. However:
scan(textConnection(a,,b,), sep=,, what=)
Read 4 items
[1] a b
--
O__ Peter Dalgaard Øster Farimagsgade 5, Entr.B
c/ /'_ --- Dept. of
Hi, I deal with 3D array say:
, , 1
[,1] [,2] [,3] [,4] [,5]
[1,]147 10 13
[2,]258 11 14
[3,]369 12 15
, , 2
[,1] [,2] [,3] [,4] [,5]
[1,] 16 19 22 25 28
[2,] 17 20 23 26 29
[3,] 18 21 24 27 30
, , 3
say your array is called no.named.array.
then:
no.named.array[no.named.array == 0] - NA
rowMeans(no.named.array, dims=2, na.rm=T)
b
On Dec 3, 2007, at 7:24 PM, threshold wrote:
Hi, I deal with 3D array say:
, , 1
[,1] [,2] [,3] [,4] [,5]
[1,]147 10 13
[2,]25
So a message from
Benilton Carvalho [EMAIL PROTECTED] (sent by
[EMAIL PROTECTED])
arrives and goes in the Junk Mail even tho I have set @r-project.org to not
be junk
Why does this go in Junk mail if @r-project.org is defined as not junk?
--
If we knew what we were doing, it would not be
Hi All,
I am looking for a color palette like this:
http://www.ncl.ucar.edu/Applications/Images/h_long_5_lg.png
I think I found out how some time ago (something like Colors[1:n]), but when
I now wanna use it, I could not remember how I did it.
Does anyone know which package I could use?
Many
see if this is what you need:
require(lattice)
x - matrix(1:100,10)
levelplot(x,col.regions=colorRampPalette(c('dark red','white','dark blue')))
On Dec 3, 2007 5:41 PM, Linda Smith [EMAIL PROTECTED] wrote:
Hi All,
I am looking for a color palette like this:
On 03/12/2007 8:56 PM, Loren Engrav wrote:
So a message from
Benilton Carvalho [EMAIL PROTECTED] (sent by
[EMAIL PROTECTED])
arrives and goes in the Junk Mail even tho I have set @r-project.org to not
be junk
Why does this go in Junk mail if @r-project.org is defined as not junk?
On Mon, 3 Dec 2007, jim holtman wrote:
see if this is what you need:
require(lattice)
x - matrix(1:100,10)
levelplot(x,col.regions=colorRampPalette(c('dark red','white','dark blue')))
Instead of colorRampPalette(), you could also use diverge_hcl() in package
vcd to get a
From: Thomas Jones
I have several user-defined functions. As is standard practice, I am
defining a logical vector named idebug in order to control debugging
printouts. For example, if idebug [1] has the value TRUE, such-and-such
debugging printouts are enabled. After the function works, some
You may wish to use the options command. You can create
your own options, not just use pre-existing ones.
Please read the last line of every message to r-help.
On Dec 4, 2007 12:51 AM, Thomas L Jones, PhD [EMAIL PROTECTED] wrote:
From: Thomas Jones
I have several user-defined functions. As
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