Thank you for your advice. So I am sending the whole code
data.dir - file.path(home.dir, Data)
file - file.path(data.dir, data4.csv)
SEM - read.csv(file)
print(SEM)
library(sem)
SEM1 - as.matrix(cbind(SEM$R1, SEM$I1, SEM$M1))
print(SEM1)
mod.cov - cov(SEM1)
print(mod.cov)
I - SEM$I1
M -
You don't appear to be defining Z here.
Might that be the problem?
Or, I, M, and R may not be defined either. It is unclear. What does
mod.cov look like?
On Jul 20, 2009, at 11:11 PM, Stein, Luba (AIM SE) wrote:
Thank you for your advice. So I am sending the whole code
data.dir -
Dear R Community,
I am pleased to announce the release of a new package called 'dlnm', now
available on CRAN (version 0.2.1).
The package dlnm provides some facilities to run distributed lag models (DLM's)
and their non-linear extension (DLNM's), a modelling framework to describe
Hi,
[,1] [,2] [,3]
[1,] 4.820719e-03 -5.558801e-05 -5.718939e-05
[2,] -5.558801e-05 4.763194e-06 -7.661872e-06
[3,] -5.718939e-05 -7.661872e-06 1.662150e-03
This is mod.cov. It is the covariance matrix of (R, I, M).
R, I and M are vectors of length 109 which
Hi,
I've used the following command in qplot
qplot(a$V1,geom=histogram,binwidth=0.15,fill =
factor(a$V2),ylab=Frequency,xlab=Rate);
but the title in the legend shows up as factor(a$V2)...how can i change
this?
--
Rajesh.J
[[alternative HTML version deleted]]
2009/7/21 Markus Mühlbacher muehli...@yahoo.com:
So just that I understand right. x and y are the scalings of the x and y axis
and the matrix represents the color of the points at each gridpoint?
Precisely! Try ?image for more details.
--
Michael Knudsen
micknud...@gmail.com
MartinMo == Martin Morgan mtmor...@fhcrc.org
on Mon, 20 Jul 2009 18:57:33 -0700 writes:
MartinMo L L lmla...@gmail.com writes:
Ok, I could solve also the latter problem by defining show.myclass
function in
the zzz.R file and adding the line 'S3method(show,myclass)' into
bwgoudey schreef:
I'm currently working with some large complex data structures eg list of
lists of data_frames containing lots more variables and lists etc.
Sometimes, I'd like to be able to bring up a simple representation of the
structure I'm working with, minus all of the values it
Ah, the larger problem is in how you specify your model. You provide
no parameter names, nor starting estimates (even an NA). See the sem
help file for an example. Basically, it must look something like as
follows
model - specify.model()
Z - M, zm, NA
Z - I, zi, NA
etc.
On Jul 20,
Hello,
Perhaps this is a good point. I use the Eclipse platform. The problem was that
when I first used the structure
Z - M, z1, NA the compiler took only the value Z -M. Thus I erased it totally.
Maybe it is really an Eclipse problem.
Do you know how to solve this difficulty?
Thanks for all
Hi All: I get the following error when trying to install the rjags package.
I've installed the
jags software and I'm using Fedora 10.0 and my sessionInfo is at the bottom
of this email.
I'm also sorry if this email ends up having control A's all over it. I still
haven't figured
Hello Jarrett,
Thank you very much indeed for your help. I could solve my problem and you were
right that I had to choose the connections in the model right.
Thus the entry
model - specify.model()
Z - M, z1, NA
Z - USM, z2, NA
Z - R, z3, 1
M - M
USM - USM
R - R
Z - Z
works and gave me moreover
G'day all,
I am trying to install the cairo package on FreeBSD and receiving an
error to do with Makevars - (I'm not very good at this stuff) so here
is my various bits of information. I guess this is a problem with a
missing library, but I have just been through a lot of grief trying to
Many thanks David for making the connection betweeen the two reports.
If I understand, other french users may have faced the same problem...
However I'll wait until it's solved to have a look at foreach.
Regards. Olivier
David M Smith a écrit :
A user in Japan reported a similar problem on the
Hello,
Perhaps this is a good point. I use the Eclipse platform. The problem was that
when I first used the structure
Z - M, z1, NA the compiler took only the value Z -M. Thus I erased it totally.
Maybe it is really an Eclipse problem.
Do you know how to solve this difficulty?
Thanks for all
Hi,
I have 100 price data series like price1, price2, price3, . All
are zoo objects. Now I want to merge all them together. Obviously I can do
this using merge(price1, price2, price3, ). However as I have lot
of price series (almost 1000) above systax is very tiresome. Is
Hi Daniel,
Thanks for the insight. My apologies for the unclearness of my original
question.
I have calculated the fit and se.fit values, see below
predict(fm,newdata=test, se.fit=TRUE, type=c(response))
If I wasn't mistaking, this would give me the fit values and the standard
errors.
I just
Hi Daniel,
Thanks for the insight. My apologies for the unclearness of my original
question.
I have calculated the fit and se.fit values, see below
predict(fm,newdata=test, se.fit=TRUE, type=c(response))
If I wasn't mistaking, this would give me the fit values and the standard
errors.
I just
On Tue, Jul 21, 2009 at 9:07 AM, RON70ron_michae...@yahoo.com wrote:
I have 100 price data series like price1, price2, price3, . All
are zoo objects. Now I want to merge all them together. Obviously I can do
this using merge(price1, price2, price3, ). However as I have lot
Let say, I have an arbitrary vector :
i=1
assign(paste(dat,i,sep=), rnorm(5))
Now I want to update that dat1 vector by ommiting last 2 elements i.e.
dat1 = dat1[c(1:3)]
However here my problem is, as dat1 depends on another variable i, I
cannot use above syntax directly. I want to automate
Dear all,
we are writing a wrapper for the nls function in library stats. We are
having a problem with one of the arguments (weightsArgument) which seems not
to reach nls even if we explicitly assign it in the function call. We are
attaching the simplest code reproducing the error and the output
?scale_fill_discrete()
qplot(x,y,data=data.frame(x=1,y=1,f=a),fill=f) +
scale_fill_discrete(test)
baptiste
HTH,
2009/7/21 rajesh j akshay.raj...@gmail.com
Hi,
I've used the following command in qplot
qplot(a$V1,geom=histogram,binwidth=0.15,fill =
factor(a$V2),ylab=Frequency,xlab=Rate);
On Tue, 21 Jul 2009, Michael Knudsen wrote:
On Tue, Jul 21, 2009 at 9:07 AM, RON70ron_michae...@yahoo.com wrote:
I have 100 price data series like price1, price2, price3, . All
are zoo objects. Now I want to merge all them together. Obviously I can do
this using merge(price1,
Hi all,
I have just uploaded a new package to the ftp site called exact2x2. The package
does exact conditional tests for 2x2 tables. Specifically, it does Fisher's
exact test and Blaker's exact test (see Blaker, 2000, Canadian Journal of
Statistics, 783-798). The motivation for the package is
I think that the (impressive) gamlss package (see
http://www.gamlss.com) may be helpful.
If I remember correctly, in gamlss you can fit model with zero-inflated
continuous distributions
hope this helps you,
vito
Alain Zuur ha scritto:
JPS2009 wrote:
Sorry bit of a Newbie question, and I
This seriously looks like a bug in load(): the gzcon() magic in the code
leaves the connection open. On Linux x86_64 I can do:
file.name - /tmp/foo.RData
data - runif(10)
save(data, file=file.name)
for ( i in 1:4000 ) { con - gzfile(file.name, rb); load(file=con);
close(con); }
## No
Allan Engelhardt wrote:
This seriously looks like a bug in load(): the gzcon() magic in the code
leaves the connection open. On Linux x86_64 I can do:
Have you tried very recent R-devel (which you always should do before
reporting bugs)? From the svn logs:
On 21/07/2009 5:00 AM, Allan Engelhardt wrote:
This seriously looks like a bug in load(): the gzcon() magic in the code
leaves the connection open. On Linux x86_64 I can do:
It was a bug (in gzcon, not load), and has now been fixed.
file.name - /tmp/foo.RData
data - runif(10)
save(data,
Hi
r-help-boun...@r-project.org napsal dne 21.07.2009 09:18:51:
Hi Daniel,
Thanks for the insight. My apologies for the unclearness of my original
question.
I have calculated the fit and se.fit values, see below
predict(fm,newdata=test, se.fit=TRUE, type=c(response))
If I wasn't
On 21-Jul-09 01:24:04, Rolf Turner wrote:
It has been pointed out to me that I erred in an earlier post.
``Go stick your head in a pig.'' is not the motto of the (entire)
Sirius Cybernetics Corporation. It is the motto if the Sirius
Cybernetics Corporation ***Complaints Division***.
My
The kmeans.big.matrix function seems to have disappeared between the 2.3
and the 3.5 release of the library. (?) I am not sure why. You can
download old versions from CRAN. The default package on Fedora
(R-bigmemory-2.3-4.fc11.x86_64 or similar for your platform) also has
the function (from
hi all,
i have a simple question. instead of defining my measurements in a
static way like ...
x - c(-0.475, -1.553, -0.434, -1.019, 0.395)
... i'd like them to be read from a file ...
x - read.table(07a673ac0cb1f7f8fa293860566f633c/1/raw0.txt, header=FALSE)
d1 - density(x, kernel = gaussian)
read.table() returns a data.frame by default. Try str(x). Options:
d1 - density(x[[1]], kernel = gaussian)
or
x - scan(07a673ac0cb1f7f8fa293860566f633c/1/raw0.txt)
Hope this helps
Allan.
On 21/07/09 11:09, leo mueller wrote:
hi all,
i have a simple question. instead of defining my
On 21/07/2009 6:09 AM, leo mueller wrote:
hi all,
i have a simple question. instead of defining my measurements in a
static way like ...
x - c(-0.475, -1.553, -0.434, -1.019, 0.395)
... i'd like them to be read from a file ...
x - read.table(07a673ac0cb1f7f8fa293860566f633c/1/raw0.txt,
I agree; the stripchart defaults place things too close to the edges for
'neat' layout.
Use at= coupled with ylim (or xlim, if vertical) to place the rows
explicitly and leave room at the margins.
Extending the last example in ?stripchart:
stripchart(decrease ~ treatment,
main =
Dear all,
How can I test for collinearity in the predictor data set
for multiple linear regression.
Thanks
Alex
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Dear R helpers,
I have a data of 2102 observations (consisting of 0's also), to which I am
trying to fit Normal distribution using lmom pacakage. If I use Excel, its
easy to estimate the parameters of Normal distribution as simple mean and
standard devaition. The results I get if I use teh
I suggest you start by doing some reading about Condition index (CI) and
variation inflation factor (VIF). Once you have reviewed the theory, a search
of search.r-project.org (under the help menu in a windows-based R installation)
for VIF will help you obtain values for VIF, c.f.
Dear R-Team!
I am a beginner in R and use the WISP library for a project. I am using
mark-recapture to estimate abundance. I would like to know if it is possible to
only survey a part of the created area (with the created population) and not
all of it. I am trying to quantify bias introduced by
big thanks to all, the x[[1]] worked fine! :)
2009/7/21 Duncan Murdoch murd...@stats.uwo.ca:
On 21/07/2009 6:09 AM, leo mueller wrote:
hi all,
i have a simple question. instead of defining my measurements in a
static way like ...
x - c(-0.475, -1.553, -0.434, -1.019, 0.395)
... i'd like
Dear all,
I am having v.4.36 of Quantreg package and I noticed strange behaviour when
weights were added. Could anyone please explain me what if the results are
really strange or the behavioiur is normal. As an example I am using dataset
Engel from the package and my own weights.
x-engel[1:50,1]
1. If the series are zoo series all starting with z, say, in the
current workspace then:
L - sapply(ls(pattern = ^z), get, simplify = FALSE)
znew - do.call(merge, L)
2. If your data originally comes from a single file with
a column that specifies which series that row pertains
to then you can
I need to make a fairly complex animated graphic and decided to use grid for it.
A very simple example of what I need:
##==
library(grid)
grid.newpage()
pushViewport(plotViewport())
pushViewport(viewport(xscale =
I issued the following command to obtain the std dev for each month.
psd-numSummary(Sal, groups=month, statistics=c(sd))
which resulted in
psd
sd n NA
1 6.930340 9367 2319
2 7.847003
megh wrote:
Let say, I have an arbitrary vector :
i=1
assign(paste(dat,i,sep=), rnorm(5))
Now I want to update that dat1 vector by ommiting last 2 elements i.e.
dat1 = dat1[c(1:3)]
However here my problem is, as dat1 depends on another variable i, I
cannot use above syntax directly. I want
Hi I wrotte this function but when I get the tmp.xls file it shows data
in a rare way. I mean not appears a matrix with 2000 rows and 100 columns.
Can anyone help me, guide me?
kim-function(){
tmp-randz-matrix(rnorm(20, mean=0,sd=0.01 ),2000,100);
dim(tmp)
write(tmp,file=tmp.xls)
Thanks
Jose Narillos de Santos wrote:
Hi I wrotte this function but when I get the tmp.xls file it shows data
in a rare way. I mean not appears a matrix with 2000 rows and 100 columns.
Can anyone help me, guide me?
kim-function(){
tmp-randz-matrix(rnorm(20, mean=0,sd=0.01 ),2000,100);
On Tue, Jul 21, 2009 at 2:28 PM, Jose Narillos de
Santosnarillosdesan...@gmail.com wrote:
Hi I wrotte this function but when I get the tmp.xls file it shows data
in a rare way. I mean not appears a matrix with 2000 rows and 100 columns.
Can anyone help me, guide me?
Short answer: ?write
Graves, Gregory wrote:
I issued the following command to obtain the std dev for each month.
psd-numSummary(Sal, groups=month, statistics=c(sd))
numSummary is not in base R, is it? If not, which package? Please read
the posting guide! Please provide reproducible code (we do not have
rajesh j wrote:
Hi,
I have a histogram.But I need seperate colours for fixed range of values.for
eg. between 2-3 on the x axis a colour.3-4 another colour etc. and the
legend has to say what each colour is.How can this be done in
geom_histogram?
geom_histogram
Error: object
its a function in ggplot2 for plotting complicated histograms.
2009/7/21 Uwe Ligges lig...@statistik.tu-dortmund.de
rajesh j wrote:
Hi,
I have a histogram.But I need seperate colours for fixed range of
values.for
eg. between 2-3 on the x axis a colour.3-4 another colour etc. and the
Hi,
Drawing grid graphics always takes long, I would write the images to
png's and make the animation. If you use Linux I can suggest some nice
tools to do this. This movie is also much more compatible with all kinds
of machines. It might be that you can get your grid animation working on
Uwe Ligges-3 wrote:
megh wrote:
Let say, I have an arbitrary vector :
i=1
assign(paste(dat,i,sep=), rnorm(5))
Now I want to update that dat1 vector by ommiting last 2 elements i.e.
dat1 = dat1[c(1:3)]
However here my problem is, as dat1 depends on another variable i, I
Hi,
I tried to use the Croston function from the forecasting package
1.24http://robjhyndman.com/software/forecasting with
the code below, but I get in return this message *Error in
decompose(ts(x[1L:wind], start = start(x), frequency = f), seasonal) : time
series has no or less than 2 periods*.
Hi
r-help-boun...@r-project.org napsal dne 21.07.2009 14:37:35:
Graves, Gregory wrote:
I issued the following command to obtain the std dev for each month.
psd-numSummary(Sal, groups=month, statistics=c(sd))
numSummary is not in base R, is it? If not, which package? Please
On 21/07/09 14:00, Paul Hiemstra wrote:
Hi,
Drawing grid graphics always takes long, I would write the images to
png's and make the animation. If you use Linux I can suggest some nice
tools to do this.
Please do suggest! I was thinking about a similar problem.
Allan.
Ups, I just realized that we have the possibility of using
grid.remove(..., redraw = FALSE) which is more or less what I was looking for.
But I'm still wondering if its possible to remove a viewport from
a viewport tree:
Without your code it is impossible to say why you are getting the error
message.
However, are you aware that you need to have a classifying variable to set the
colours?
Try this to see if it is something like what you want.
Ups, I just realized that we have the possibility of using
grid.remove(..., redraw = FALSE) which is more or less what I was looking for.
But I'm still wondering if its possible to remove a viewport from
a viewport tree:
I've talked with Paul about this (for the general case of modifying
Leslie J Seltzer wrote:
Greetings
I have a very simple question that I have not been able to solve by reading the
manual. When I produce a stripchart with two straight columns of dots
representing individual observations, one representing one group of subjects
and the other representing
Hello List,
I am modeling a binomial response (nest survival) and I want to incorporate
a random effect, in this case site. I had previously been using glm with a
custom link function, but my understanding is that lmer does not currently
allow a custom link. Therefore, I was investigating if
It looks like a data.frame to me. Try str(psd) or class(psd) to check. Typeof
returns list for a data.frame since data.frame apparently is a subset of
list. The 'months' that you are seeing are simply the rownames which by
chance are the same as the months.
I's suggest adding the months to
I'm afraid I am missing something. In my R function (call it foo, say) I
am doing something like
foo - function() {
...
.C(bar, ..., res=integer(n), ...)$res
}
but I don't know the n to use; that is determined inside my C function
bar. Is there a way around this?
Thomas Roth (geb. Kaliwe) wrote:
in the legend there's x but not the value of x which actually should be
shown...
#does not work
x = 2
plot(1:10)
legend(4,4, expression(t[m] == x, t[n] == x))
If in separate lines, e.g.:
legend(4, 4, do.call(expression, list(
substitute(t[m] == x,
Hi Everyone,
I'm having a problem with arima.sim. Namely specifying inital values
for the series.
If I generate a random walk
vs = rnorm(100,0,1)
xs = cumsum(vs)
and fit an ARIMA(1,0,0) to it
xarima = arima(xs,order=c(1,0,0))
xarima
Call:
arima(x = xs, order = c(1, 0, 0))
Coefficients:
On the other hand, everytime I execute a function that is locatd in
my
documents I must open it source(file.choose()) , there is a folder
where to
put my function to not necesessary run prevously
source(file.choose()).
See ?startup
Rather: ?Startup
-steve
--
Steve Lianoglou
Graduate
On 21 July 2009 at 06:56, Dan Kelley wrote:
| I'm afraid I am missing something. In my R function (call it foo, say) I
| am doing something like
|
| foo - function() {
| ...
| .C(bar, ..., res=integer(n), ...)$res
| }
|
| but I don't know the n to use; that is
Maithili Shiva wrote:
Dear R helpers,
I have a data of 2102 observations (consisting of 0's also), to which I am trying to fit Normal distribution using lmom pacakage. If I use Excel, its easy to estimate the parameters of Normal distribution as simple mean and standard devaition. The results
I have written a wrapper for heatmap.2 called
heatmap.w.row.and.col.clust which auto-generates breaks using
breaks-round((c(seq(from=(-20 * stddev), to=(20 * stddev/20,
digits = 2) #(stddev in this case = 2.5)
This has always worked well in the past but now I am getting an error
that
Dear useRs,
you probably already noticed that the
ERCIM (European Research Consortium for Informatics and Mathematics)
Working Group on Computing Statistics will meet at its Second
International Workshop, 29-31 October 2009, in Limassol, Cyprus.
Several topics are covered, many of them
--- On Mon, 7/20/09, 1Rnwb sbpuro...@gmail.com wrote:
I thought this forum is for help. now i know what the
statistician in my dept
does all day long
Clearly he's not talking to you. Your first step probably should be to go talk
to him or her.
You should also need coefficients for your error terms.
On Jul 21, 2009, at 12:36 AM, Stein, Luba (AIM SE) wrote:
Hello Jarrett,
Thank you very much indeed for your help. I could solve my problem
and you were right that I had to choose the connections in the model
right.
Thus the entry
Uwe,
Thank you for your reply. I am still not very clear about the meanings of
the arguments in the stats function. To make it clearer, quantile() uses
type=7 as default method. I believe this is the method bwplot() uses to
calculate the quantiles. I want to use type=6 method for bwplot(). How
Never mind, the problem seems to be that I have ignored the warning
Using scale=row or scale=column when breaks arespecified can
produce unpredictable results.Please consider using only one or the
other.
I just stop specifying the breaks and it works fine.
Mark
I need to estimate a model that predicts the proportional split of
travel among the vehicles of a household based on vehicle
characteristics such as age, fuel economy, and travel cost per mile. The
model estimation dataset has a record for each household vehicle with
information about the vehicle,
Hi,
I have two products which are substitudes. I try to fix a system as below to
mydata.
Demand1 = A1 -B1*Price1 + C1*Price2
Demand2 = A2 +B2*Price1 - C2*Price2
I would expect C1 B2 to be symmetric, If they are truly substitude. How
can I enforce this symmetry when creating a system of
Hi,
I would like to be able to shade the background of part of an axis. To
illustrate, consider the following code:
par(xaxt=n)
x=1:10
y=rnorm(10,0,1)
plot(x,y,type=l,xlab=NA)
mtext(text=LETTERS[1:10], side=1, at=1:10)
How can I make the background behind, say, G H I on the x-axis red? I have
Hello,
I would be very grateful if someone could give me a hand with my split
plot design problems.
So here is my design :
I am studying the crossed-effects of water (wet/dry) and mowing
(mowed/not-mowed = nm) on plant height (PH) within 2 types of plant
communities (Xerobromion and
Anja:
Unfortunately, WiSP does not offer a spatially-explicit way to specify
capture probabilities for the designated study region.
Although the members of the population are assigned spatial coordinates
within the study region, there is no specification of where the 'captures'
take place
Generally speaking, the pseudo R^2 of 70% is a rather good model
(obviously depends on the kind of data you have at hand). Because it's
pseudo, not real, R^2, so the range is not limited to [0, 100%], but
it's hard for me to imagine anyone getting 100%.
You may want to check the distribution of
Hi all!
I have an ordered vector of values. The distribution of these values can
be modeled by a sum of Gaussians.
So I'm using the package 'mclust' to get the Gaussians's parameters for
this 1D distribution. It works very well, but, for input sizes above
100.000 values it starts taking
Václav,
I think that the technical term for this is snafu. You are right of
course
that the magnitude of the weights should have no impact on the fitted
values. The good news is that the coefficient estimates satisfy this
obvious principle, but unfortunately the fitted.values component is
On Tue, Jul 21, 2009 at 7:47 AM, Jun Shenjun.shen...@gmail.com wrote:
Uwe,
Thank you for your reply. I am still not very clear about the meanings of
the arguments in the stats function. To make it clearer, quantile() uses
type=7 as default method. I believe this is the method bwplot() uses
Hi listers,
I have a problem in identifying a value between two vectors...
Suppose vector A is...
0. 0.0909 0.0909 0.1818 0.2727 0.3636 0.4545 0.6363 0. 0. 0.
0.
And vector B is...
3 5 7 18 43 85 91 98 100 130 230 487
I would like to identify the value of vector B
MarcioRibeiro wrote:
I have a problem in identifying a value between two vectors...
Suppose vector A is...
0. 0.0909 0.0909 0.1818 0.2727 0.3636 0.4545 0.6363 0. 0.
0. 0.
And vector B is...
3 5 7 18 43 85 91 98 100 130 230 487
I would like to identify the
On Jul 21, 2009, at 11:28 AM, Dieter Menne wrote:
MarcioRibeiro wrote:
I have a problem in identifying a value between two vectors...
Suppose vector A is...
0. 0.0909 0.0909 0.1818 0.2727 0.3636 0.4545 0.6363 0. 0.
0. 0.
And vector B is...
3 5 7 18 43 85 91 98
On Jul 21, 2009, at 11:11 AM, MarcioRibeiro wrote:
Hi listers,
I have a problem in identifying a value between two vectors...
Suppose vector A is...
0. 0.0909 0.0909 0.1818 0.2727 0.3636 0.4545 0.6363 0.
0. 0.
0.
And vector B is...
3 5 7 18 43 85 91 98 100 130
You are probably thinking of the str function. But also look at the
TkListView function in the TeachingDemos package for visualizing lists of
lists and complex objects.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
2009/7/21 Markus Mühlbacher muehli...@yahoo.com:
I tried to add white to the colors, but this did not change my problem. Still
the values of the diagonal seem to be different from those occurring in the
matrix. Or in other words all squares of the diagonal should have to SAME
color!
If
It's planning time for the 2010 Joint Statistical Meetings in Vancouver. I am
the Program Committee representative for the Section on Statistical Computing,
so I'm looking for suggestions for invited sessions.
Detailed proposals are welcome, as are vague suggestions for topics and
speakers
I'm running R 2.9.1 on winXP, using the library plyr.
Can anyone explain to me what is going wrong in this code? (in particular
see lines marked with **) Trying to modify objects in a list
created using dlply seems to corrupt the objects in the list.
library(plyr)
Using the gretl.sf.net dialect:
Static forecasts are one step ahead, based on realized values from the previous
period, while dynamic forecasts employ the chain rule of forecasting.
What kind of forecast is doing forecast.Arima?
Thanks,
Matteo Bertini
Imagemagick and gimp work on windows, linux, and mac as well and have tools for
creating animated gifs (and possibly other animation files).
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From:
How can I get the results of lm() into a list so I can loop through the results?
e.g.
myResults[1] - lm(...)
myResults[2] - lm(...)
myResults[3] - lm(...)
...
myResults[15] - lm(...)
myResults[16] - lm(...)
so far every attempt I've tried doesn't work throwing a number of
items to replace is
Hi,
I am embedding R into a C++ application. Is it possible to call R functions
from different threads? If yes, should I call Rf_initEmbeddedR once or for
each thread separately? I know that R is not thread safe and making sure
that no simultaneous calls from different threads happen. Now I am
Look at the xpd argument to the par function.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Miguel Lacerda
for teaching purposes I wrote a corresponding function; cf.
qbxp.stats (as well as qboxplot ...) in package MKmisc.
hth,
Matthias
Deepayan Sarkar schrieb:
On Tue, Jul 21, 2009 at 7:47 AM, Jun Shenjun.shen...@gmail.com wrote:
Uwe,
Thank you for your reply. I am still not very clear about
You could look at ?lmList in package lme ...
Idgarad idga...@gmail.com 21/07/2009 17:27:52
How can I get the results of lm() into a list so I can loop through the
results?
e.g.
myResults[1] - lm(...)
myResults[2] - lm(...)
myResults[3] - lm(...)
...
myResults[15] - lm(...)
myResults[16] -
Dear R-help,
When the result of a matrix subscription degenerates to a scalar the names
implied by the dimnames are discarded.
x - matrix(0, 1, 1, dimnames=list('a', 'x'))
## below I expected result to have names='x', it's not
x[1,]
[1] 0
## below I expected result to have names='a', it's
On Jul 21, 2009, at 12:27 PM, Idgarad wrote:
How can I get the results of lm() into a list so I can loop through
the results?
e.g.
myResults[1] - lm(...)
myResults[2] - lm(...)
myResults[3] - lm(...)
...
myResults[15] - lm(...)
myResults[16] - lm(...)
so far every attempt I've tried
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