Hi,
I want to import data from teradata.Data set is very large in size , it has
around 1 million rows and 40 columns.
Could anyone tell me an efficient and fast way to import data sets with this
size.
Thanks.
Sumit
[[alternative HTML version deleted]]
Hi,
How do I fit a mixed-effects regression model for ordinal data in R? More
specifically, I have two crossed random effects and I would like to use
proportional odds assumption with a complementary log-log link.
Regards,
Hakan Demirtas
__
An improved version below (now the connections are drawn in the correct order),
library(grid)
arcTextGrob - function(x=unit(0.5, npc), y=unit(0.5, npc),
labels=library()$results[,1],
links=sample(seq_along(labels), 20, rep=T),
I want to fit a bivariate copula to bivariate data. Then I want to draw a
straight line on the copula. Then I want to retrieve those origianl pairs
(X.Y) which were above the line. Any ideas how to do this?
Thanks,
Jim
[[alternative HTML version deleted]]
Please see that correlogram for a arbitrary time series :
acf(zooreg(rnorm(39), start=as.yearmon(2008-01-01), frequency=12))
What is the meaning of lag 0.2, 0.4, in the plot? Those should not
be integers? Or I am missing something?
Thanks
--
View this message in context:
This worked for me in R 2.11.0 alpha:
df - data.frame(a = a\b, v = 4, z = this is Z)
write.csv(df, test.csv, row.names = FALSE, quote = FALSE)
read.csv(test.csv, quote = )
-Peter Ehlers
On 2010-04-07 19:09, Hadley Wickham wrote:
df- data.frame(a = a\b)
write.table(df, test.csv, sep = ,, row
Hi Bogaso,
You could try this to get integer x-axis values:
library(zoo)
z = zooreg(rnorm(39), start=as.yearmon(2008-01-01), frequency=12)
acf(ts(z,freq=1))
Steve Chen
On 2010/4/8 下午 03:32, Bogaso wrote:
Please see that correlogram for a arbitrary time series :
acf(zooreg(rnorm(39),
On Wed, 7 Apr 2010, Bogaso wrote:
Please see that correlogram for a arbitrary time series :
library(zoo) ## you example does not work without it!
acf(zooreg(rnorm(39), start=as.yearmon(2008-01-01), frequency=12))
What is the meaning of lag 0.2, 0.4, in the plot? Those should not
HAKAN DEMIRTAS wrote:
How do I fit a mixed-effects regression model for ordinal data in R? More
specifically, I have two crossed random effects and I would like to use
proportional odds assumption with a complementary log-log link.
Not out of the box, as far I know. Try
Please install v1.3 from R-forge :
install.packages(data.table,repos=http://R-Forge.R-project.org;)
It will be ready for CRAN soon.
Please follow up on datatable-h...@lists.r-forge.r-project.org
Matthew
bo bozha...@hotmail.com wrote in message
news:1270689586866-1755876.p...@n4.nabble.com...
Hi Dimitri,
A start has been made at explaining .SD in FAQ 2.1. This was previously on a
webpage, but its just been moved to a vignette :
https://r-forge.r-project.org/plugins/scmsvn/viewcvs.php/*checkout*/branch2/inst/doc/faq.pdf?rev=68root=datatable
Please note: that vignette is part of a
On 04/08/2010 12:44 AM, Gabor Grothendieck wrote:
There is draw.arc in the plotrix package.
Well, draw.arc is specified by center, radius and start/finish angles,
so it would be a lot of calculation to get these from the two points
that must be joined on the circumference. I would probably
I am studying Using R for Introductory Statistics and find it in
general very useful. At present, I am stumbling over the function
simple.median.test.
x
[1] 12.8 3.5 2.9 9.4 8.7 0.7 0.2 2.8 1.9 2.8 3.1 15.8
simple.median.test (x,median=5)
[1] 0.3876953
simple.median.test
Please consider using the R-sig-geo list for kriging questions.
In fact, using str() would show that your z is badly impacted by your misuse
of the c() function - this was almost certainly not what you wanted to do.
Constructing your coordinates by using seq() is always a bad idea, as you
need
On 08/04/2010 02:11, Felix Andrews wrote:
On 8 April 2010 03:34, Luigi Ponti lpo...@inbox.com wrote:
Thanks for the hint, Felix: the following code makes it but (don't know why)
the median dots disappear.
bwplot(count ~ spray, data = InsectSprays,
groups = spray,
panel =
Hello! All,
I am working on 1x1000 matrix say 'mat' and i want to subset this matrix
in a fashion that in new matrix i get columns 2,3,9,10,16,17,23,24...so
on. That is pair of columns after every interval of 7. I tried following but
i got an error which is obvious.
dim(mat)
[1] 1
Hi,
just wanted to note this (mild) regression.
I tried saveXML(traml) with different compression=
and indent= settings, but the output remained
in a single line for XML-2.8-1
Without writing to a file the string representation
after saveXML() looks quite similar, with the exception
of a \n
On Apr 8, 2010, at 7:39 AM, Lee William wrote:
Hello! All,
I am working on 1x1000 matrix say 'mat' and i want to subset
this matrix
in a fashion that in new matrix i get columns
2,3,9,10,16,17,23,24...so
on. That is pair of columns after every interval of 7. I tried
following
On 07/04/2010 4:24 PM, Changbin Du wrote:
Hi, r-community,
This morning, I MET the following problem several times when I try to attach
the data set.
When I closed the current console and reopen the R console, the problem
disappear. BUt with the time passed on, the problem occurs again.
Can
On Apr 8, 2010, at 1:45 AM, arindam fadikar wrote:
Dear users,
How to get a symmetric square root of a positive definite matrix? I
have
tried using spectral decomposition, but some eigen values come out
to be
complex. Is there any function in R that can give the symmetric
square root
Dear,
my variable is numerical indicating how many times smb done test
summary(Q12)
Min. 1st Qu. MedianMean 3rd Qu.Max.NA's
0. 0. 0. 0.7989 1. 30. 66.
I want to change this to categories-- 0=none testing; 1:30=done testing (NA
excluded)
John,
On Apr 8, 2010, at 8:13 AM, Vlatka Matkovic Puljic wrote:
Dear,
my variable is numerical indicating how many times smb done test
summary(Q12)
Min. 1st Qu. MedianMean 3rd Qu.Max.NA's
0. 0. 0. 0.7989 1. 30. 66.
I want to change this to categories--
Hello R users, and perhaps William Revelle in particular,
I'm curious as to how ICC deals with missing data, so for example you are
sampling individuals over set periods in time and one individual is missing
or was not recaptured at that given time point - leading to NA in the
dataset. My
Now I have :)
Thanx a lot!
2010/4/8 David Winsemius dwinsem...@comcast.net
On Apr 8, 2010, at 8:13 AM, Vlatka Matkovic Puljic wrote:
Dear,
my variable is numerical indicating how many times smb done test
summary(Q12)
Min. 1st Qu. MedianMean 3rd Qu.Max.NA's
0. 0.
Dear Max,
Thanks for the reply. I will wait for your further comment
on this.
Regards
Linda Garcia
On Wed, Apr 7, 2010 at 8:03 PM, Max Kuhn mxk...@gmail.com wrote:
Linda,
Thanks for the example.
I did this to make it more reproducible:
set.seed(1)
On 2010-04-08 4:52, Uwe Dippel wrote:
I am studying Using R for Introductory Statistics and find it in
general very useful. At present, I am stumbling over the function
simple.median.test.
x
[1] 12.8 3.5 2.9 9.4 8.7 0.7 0.2 2.8 1.9 2.8 3.1 15.8
simple.median.test (x,median=5)
[1] 0.3876953
I would like to know if there is anyone like me interested in an R User
Group in Dallas, TX. David Smith at REvolutions was kind enough to help
getting it started.
My first thought would to have some informal meet ups at some local Dallas
locations to discuss overall goals, ideas, wishes of the
df - data.frame(a = a\b, v = 4, z = this is Z)
write.csv(df, test.csv, row.names = FALSE, quote = FALSE)
read.csv(test.csv, quote = )
Unfortunately my real example is more like:
df - data.frame(a = a\b, v = 4, z = this is: A, B, C)
so quote = F won't work.
Can write.table and read.table
Ah, I see. Thanks. It works for me too.
Best,
R.
2010/4/7 Jens Oehlschlägel jens.oehlschlae...@truecluster.com:
Ramon,
for me this works
setwd(d:/tmp)
ffd - as.ffdf(d, col_args=list(pattern = paste(getwd(), /fftmp, sep =
)))
filename(ffd)
$x
[1] d:/tmp/fftmp35c34861.ff
$y
[1]
You were using read.csv and not read.table. The following seems to work
with using a separator that will probably not appear in the text:
df - data.frame(a = a\b, v = 4, z = this is: A, B, C)
write.table(df, test.csv, row.names = FALSE, quote = FALSE, sep='\x01')
read.table(test.csv, quote =
On Apr 8, 2010, at 9:07 AM, Hadley Wickham wrote:
df - data.frame(a = a\b, v = 4, z = this is Z)
write.csv(df, test.csv, row.names = FALSE, quote = FALSE)
read.csv(test.csv, quote = )
Unfortunately my real example is more like:
df - data.frame(a = a\b, v = 4, z = this is: A, B, C)
so quote
Dear Thomas,
Thank you for your informative answer. We used epi.stratasize() to
estimate the required sample size per stratum. Notice in the example
below that it can select a sample size smaller than 2 in the very small
strata. Would you recommend to sample at least two items per stratum or
Dear David, Erik and Charles,
Thank you for your input. Both mapply() and which() can do the job. Just one
exception. If there is a missing value as NA in the data frame a and a
data point (either numerical or character) in the corresponding position of
b, then mapply() only returns NA for that
Regarding the screen argument in wireframe(), here is what I understand about
how it works after much trial-and-error:
After each rotation, new axes are in effect defined for the next rotation as at
the start: x is to the right of the 2D view, y is towards the top, and z is
positive out of
On Apr 8, 2010, at 9:20 AM, jim holtman wrote:
You were using read.csv and not read.table. The following seems to
work
with using a separator that will probably not appear in the text:
Modified Jim's version:
df - data.frame(a = a\b, v = 4, z = this is: A, B, C,
Hello,
I am wondering whether 'R' has a command to produce coefficient
estimates for AR/MA model when variance-covariance matrix is given as an
input.
Thank you very much for your help,
MoonJung
*
Moon Jung Cho
Office of Survey Methods Research
U.S. Bureau of Labor
Dear list,
I have a question regarding the included polygon in the khat function of the
splancs library defining the area where points appear.
I have not only one simple polygon included, my map includes several islands.
I read my map which was a shape file by readShapeSpatial of the maptools
Hi,
Does anyone know how to halt Rcmdr?
If I make an error and execution is taking a very long time. Is there a way
to halt it WITHOUT killing Rcmdr or Rconsole?
--
View this message in context:
http://n4.nabble.com/Halting-execution-in-Rcmdr-tp1773753p1773753.html
Sent from the R help
It's possible I have failed to understand your situation (it's not clearly
described).
If your model captures the dependence structure (e.g. that induced by a
common-but-unknown block effect), then in many cases it could be set up to
work. If the dependence is of some form not captured in the
I was testing some strategy and got very bizarre results (too good). I
quickly found, that the problem is in addTxn() method and it is related to
the commission parameter. In the description of the method, you can find
that the fees will be subtracted.
TxnFees: fees associated with the
Can write.table and read.table really be so asymmetric?
write() is a wrapper for cat() and read() is a wrapper for scan() so the
question should really be can cat() and scan() be so asymmetric. Looking at
their help pages, I would say that at least some degree of asymmetry is
plausible.
On Thu, Apr 8, 2010 at 8:20 AM, jim holtman jholt...@gmail.com wrote:
You were using read.csv and not read.table. The following seems to work
with using a separator that will probably not appear in the text:
df - data.frame(a = a\b, v = 4, z = this is: A, B, C)
write.table(df, test.csv,
On Apr 8, 2010, at 9:47 AM, Jun Shen wrote:
Dear David, Erik and Charles,
Thank you for your input. Both mapply() and which() can do the job.
Just one
exception. If there is a missing value as NA in the data frame a
and a
data point (either numerical or character) in the corresponding
Hi everyone,
I've got a matrix data with 20 variables (V1, V2, V3, ...) and 215
rows (observations). I'm interested to read only the first and second
variables using read.table function. How can I do?
Thanks in advance.
Paolo.
__
Hi
what about
some.data - read.table()[ ,1:2]
Regards
Petr
r-help-boun...@r-project.org napsal dne 08.04.2010 16:05:39:
Hi everyone,
I've got a matrix data with 20 variables (V1, V2, V3, ...) and 215
rows (observations). I'm interested to read only the first and second
variables
Hi
So my particular problem is this:
I have a row vector of length 5200 elements - specifically created by
x-rbinom(5200,1,0.5)
y-matrix(x,nrow=1,ncol=5200)
y
now, each element is either a 0 or a 1 - e.g. it could be
(0,1,1,1,1,0,0,0,1,1,1) e.t.c.
when the element is a 1, i need to multiply
Hi
So my particular problem is this:
I have a row vector of length 5200 elements - specifically created by
x-rbinom(5200,1,0.5)
y-matrix(x,nrow=1,ncol=5200)
y
now, each element is either a 0 or a 1 - e.g. it could be
(0,1,1,1,1,0,0,0,1,1,1) e.t.c.
when the element is a 1, i need to
Dear all,
I've just migrated from STATA to R for runing panel regressions and I was
very happy to discover the plm package. However, I have a problem when
trying to access the Total Sum of Squares and Residual Sum of Squares on
this output:
summary(output)
Oneway (individual) effect Within
just convert your vector from 0,1 to .995,1.005 and use cumprod
On Thu, Apr 8, 2010 at 10:22 AM, Redhwan redhwanza...@hotmail.com wrote:
Hi
So my particular problem is this:
I have a row vector of length 5200 elements - specifically created by
x-rbinom(5200,1,0.5)
Hadley,
The cause of the count.fields result is the comma in 'nftc,%20'
at about column 300 (for me).
Since commas between quotes should normally not matter, this
must be due to the comma appearing inside escaped quotes, i.e.
we have: abc\def,ghi\jkl.
Remove the comma and count.fields gives 11
Hi,
I have two zoo objects (time series of same frequency) say A and B. I
need to exchange A's dates for B's.
Is there and easy way?
I managed to do it by converting A to a vector and pasting it on a zoo
vector (all ones) with B's dates but I wonder if there is an easier way
by some zoo
Hi
r-help-boun...@r-project.org napsal dne 08.04.2010 16:23:53:
Hi
So my particular problem is this:
I have a row vector of length 5200 elements - specifically created by
x-rbinom(5200,1,0.5)
y-matrix(x,nrow=1,ncol=5200)
y
now, each element is either a 0 or a 1 - e.g. it
Dear all R users,
I am building a Cox PH model on a small dataset. I am wondering how to
measure the predictive power of my cox model? Normally the ROC curve or Gini
value are used in logistic regression model. Is there any similar
measurement suitable for Cox model?
Also if I use C-index
Whew, figured it out through trial and error.
In case anyone else runs into this problem, the issue ended up being with the
data in one of the columns. I knew I didn't have any actual missing values, but
one of the columns is a text field which can have the literal value of NA. I
guess R was
Assuming they are of the same length try this:
library(zoo)
# test data
A - zoo(1:3, Sys.Date() + 1:3)
B - zoo(4:6, Sys.Date() + 14:16)
time(A) - time(B)
A
2010-04-22 2010-04-23 2010-04-24
1 2 3
Next time please provide test data with your post.
On Thu, Apr 8,
On Apr 8, 2010, at 10:01 AM, Hadley Wickham wrote:
Can write.table and read.table really be so asymmetric?
write() is a wrapper for cat() and read() is a wrapper for scan()
so the
question should really be can cat() and scan() be so asymmetric.
Looking at
their help pages, I would say
Hullo
I may have missed something blindingly obvious here. I'm using xts to
handle some timeseries data. I've got daily measurements for 100
years. If I try to reduce the error rate by taking means of each
month, I'm getting what at first sight appears to be conflicting
information.
Remove the comma and count.fields gives 11 for all rows.
From your other post(s) on escaped quotes, I assume that
this won't solve your problem with the existing files. (:
Right - but assuming I'm not crazy, that should cause an error in
read.csv, right? It shouldn't just parse the file
Hello Everyone,
Â
I am a newbie with about a month's worth of experience using R. I've just spent
a little time learning how to work with date values. Mostly, this has involved
converting text values into dates.
Â
So far, I've managed to figure out how to do this in R proper using as.Date.
Hello, everyone
I have the following problem:
Say I have an irregular zoo timeseries like this:
a - zoo(rep(1:9), as.Date(c(2009-03-20, 2009-03-27, 2009-04-24,
2009-04-25, 2009-04-30, 2009-05-15, 2009-05-22, 2009-05-29,
2009-06-26)))
and I have regular zoo timeseries like this:
b -
On Thu, Apr 8, 2010 at 5:38 PM, David Winsemius dwinsem...@comcast.netwrote:
On Apr 8, 2010, at 1:45 AM, arindam fadikar wrote:
Dear users,
How to get a symmetric square root of a positive definite matrix? I have
tried using spectral decomposition, but some eigen values come out to be
Hello everyone,
I have a peoblem to create the twoways effect in the plm package.
when i try to create the following
dsn1-plm(lnQ~lnC+lnL+lnM+lnE+eco+RD,data=newdata,effect=twoways,model=within)
i have this error:
Error in rep.int(c(1, numeric(n)), n - 1L) : negative length vectors
are not
Omit rep. You just want a - zoo(1:9, ...). To get the last day of
the month you don`t need b since as.Date.yearmon will give it with the
argument frac = 1:
aggregate(a, as.Date(as.yearmon(time(a)), frac = 1), tail, 1)
2009-03-31 2009-04-30 2009-05-31 2009-06-30
2 5 8
try this,
install.packages(expm, repos=http://R-Forge.R-project.org;)
On 8 April 2010 17:28, arindam fadikar arindam.fadi...@gmail.com wrote:
On Thu, Apr 8, 2010 at 5:38 PM, David Winsemius dwinsem...@comcast.netwrote:
On Apr 8, 2010, at 1:45 AM, arindam fadikar wrote:
Dear users,
How
Thank you, Gabor! This is a very elegant solution.
But instead of general last day of month in the index, how can I have
last day of each month as they are presented in a, for example, not
March 31, but March 27?
Regards,
Sergey
On Thu, Apr 8, 2010 at 17:27, Gabor Grothendieck
On Thu, 8 Apr 2010, arindam fadikar wrote:
On Thu, Apr 8, 2010 at 5:38 PM, David Winsemius dwinsem...@comcast.netwrote:
On Apr 8, 2010, at 1:45 AM, arindam fadikar wrote:
Dear users,
How to get a symmetric square root of a positive definite matrix? I have
tried using spectral
On Apr 8, 2010, at 11:28 AM, arindam fadikar wrote:
On Thu, Apr 8, 2010 at 5:38 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Apr 8, 2010, at 1:45 AM, arindam fadikar wrote:
Dear users,
How to get a symmetric square root of a positive definite matrix? I
have
tried using
On 2010-04-08 9:10, Hadley Wickham wrote:
Remove the comma and count.fields gives 11 for all rows.
From your other post(s) on escaped quotes, I assume that
this won't solve your problem with the existing files. (:
Right - but assuming I'm not crazy, that should cause an error in
read.csv,
Scott,
This is a good explanation and a good practice.
Thank you,
John
--- On Thu, 4/8/10, Waichler, Scott R scott.waich...@pnl.gov wrote:
From: Waichler, Scott R scott.waich...@pnl.gov
Subject: Re: 3-D response surface using wireframe()
To: arrayprof...@yahoo.com arrayprof...@yahoo.com
Hello,
I have a MANOVA model and I want to test the following hypothesis: LBM =
0 where B is the parameter estimates.
Is there any function to do this in R?
Cheers,
Philippe
--
Philippe Hupé
Institut Curie, CNRS UMR 144, INSERM U900
26 rue d'Ulm
75005 Paris - France
Email :
On Thu, Apr 8, 2010 at 11:42 AM, Sergey Goriatchev serg...@gmail.com wrote:
Thank you, Gabor! This is a very elegant solution.
But instead of general last day of month in the index, how can I have
last day of each month as they are presented in a, for example, not
March 31, but March 27?
Try
This reads like homework. You should show some evidence where you are stuck
or pick up an R book/manual/introduction after which you should be able to
do this yourself quite easily.
Daniel
-
cuncta stricte discussurus
-
-
On Thu, 8 Apr 2010, ONKELINX, Thierry wrote:
Dear Thomas,
Thank you for your informative answer. We used epi.stratasize() to
estimate the required sample size per stratum. Notice in the example
below that it can select a sample size smaller than 2 in the very small
strata. Would you recommend
On Wed, 7 Apr 2010, thedoctor81877 wrote:
Hullo,
I am trying to use the leaps package, keep getting the following error:
Error in leaps.setup(x, y, wt = wt, nbest = nbest, nvmax = NCOL(x) + int, :
y and x different lengths
x might be a data frame rather than a matrix.
In any case,
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Lee William
Sent: Thursday, April 08, 2010 4:40 AM
To: r-help@r-project.org
Subject: [R] subsetting a matrix with specified no of columns
Hello! All,
I am working on
Thanks so much! Duncan, I appreciated!
On Thu, Apr 8, 2010 at 5:03 AM, Duncan Murdoch murd...@stats.uwo.ca wrote:
On 07/04/2010 4:24 PM, Changbin Du wrote:
Hi, r-community,
This morning, I MET the following problem several times when I try to
attach
the data set.
When I closed the
I have a data set with observations on 549 cities spanning an 18 year
period. However, some of cities did not report in one or more of the 18
years. I would like to implement the procedure suggested by Wooldridge
section 17.1.3 in his Econometric analysis of cross section and panel data
to
I am working on a Windows XP machine with R 2.10.1 and a recent
installation of MiKTeX 2.8. I use LyX (www.lyx.org) to write documents
and have it set up to run Sweave, Stangle, and make the PDF through R
using a batch script and a MakeSweave.R file. This system worked just
fine until I ran some
Dear Philippe,
The linear.hypothesis() function in the car package should do what you want.
I hope this helps,
John
John Fox
Senator William McMaster
Professor of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
web:
Good afternoon everyone,
I am pleased to confirm the details of the next LondonR meeting:
Date:Wednesday 4th May
Time:6pm - 9pm
Venue: The Shooting Star
125- 129 Middlesex Street
E1 7JF
(Nearest Tubes- Liverpool Street, Moorgate or Bank)
I will
Dear list
I am experiencing a very annoying problem with mtext, although I have
been using this command for many years. The following code prints
test twice in the outer margin, once at .7 where it should be, and
once at the bottom somewhere. I also notice that the command takes
longer
I want to run some R script using the inline package (which allows to create
and run inline C++ code in my humble understanding).
So, after loading the required packages and copy and paste the example that
runs C code (in the Reference Manual as a PDF), I have a compilation error.
Any body has
See:
http://n4.nabble.com/panel-data-td1749549.html
On Thu, Apr 8, 2010 at 12:55 PM, Richard Saba saba...@auburn.edu wrote:
I have a data set with observations on 549 cities spanning an 18 year
period. However, some of cities did not report in one or more of the 18
years. I would like to
I'm trying to do:
randomForest(f, data = moths.train)
But I get this error:
Error in randomForest.default(m, y, ...) :
Need at least two classes to do classification.
When I look at the data for this, I realize there are no positive cases of
this item:
[1] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
David,
Thanks for the suggestion. Now I have worked out a general solution.
Assume a and b are two data frames with same dimensions
1. Call identical(a,b) to get an overall assessment. If you get a FALSE
2. Call which(mapply(identical,unlist(a),unlist(b))==FALSE), you will get a
result like
On Thu, Apr 8, 2010 at 11:32 AM, satu satu2...@live.com.ar wrote:
I want to run some R script using the inline package (which allows to create
and run inline C++ code in my humble understanding).
So, after loading the required packages and copy and paste the example that
runs C code (in the
Hi
I am trying this
x - read.table(/home/kenji/1245/GDS1_2grps_.cls, header = F, skip = 2)
x - read.table(/home/kenji/1246/MYCset.cls, header = F, skip = 2)
Warning message:
In read.table(/home/kenji/1246/MYCset.cls, header = F, skip = 2) :
incomplete final line found by readTableHeader on
On Apr 8, 2010, at 2:14 PM, Leonardo K. Shikida wrote:
Hi
I am trying this
x - read.table(/home/kenji/1245/GDS1_2grps_.cls, header = F,
skip = 2)
x - read.table(/home/kenji/1246/MYCset.cls, header = F, skip = 2)
Warning message:
In read.table(/home/kenji/1246/MYCset.cls, header = F, skip
sorry, it was read, indeed.
TIA
Leonardo K. Shikida
Vetta Labs
+55(31)2551-6936 ext 203
http://www.vettalabs.com
On Thu, Apr 8, 2010 at 3:43 PM, David Winsemius dwinsem...@comcast.net wrote:
On Apr 8, 2010, at 2:14 PM, Leonardo K. Shikida wrote:
Hi
I am trying this
x -
I have a case where the easiest way to draw a particular symbol would be
to draw something a little bigger, and then use polygon(... , col=0) to
erase the extra stuff. Just how to do this best when par('bg') =
'transparent' is, however, eluding me. I've looked through the archives
and the book R
On Apr 8, 2010, at 1:34 PM, Jun Shen wrote:
David,
Thanks for the suggestion. Now I have worked out a general solution.
Assume a and b are two data frames with same dimensions
1. Call identical(a,b) to get an overall assessment. If you get a
FALSE
2. Call
David,
That does the job! Thanks a lot.
Now I am very very close to what I want. Still have a couple of small
adjustments to make.
1. I use drape=TRUE to draw grid and color on the surface, is there a parameter
to adjust the density of the grid?
2. Is there a way that I can add grid to the
On Thu, 8 Apr 2010, seral wrote:
Hello everyone,
I have a peoblem to create the twoways effect in the plm package.
when i try to create the following
dsn1-plm(lnQ~lnC+lnL+lnM+lnE+eco+RD,data=newdata,effect=twoways,model=within)
i have this error:
Error in rep.int(c(1, numeric(n)), n -
On Thu, 8 Apr 2010, ECAMF wrote:
Dear all,
I've just migrated from STATA to R for runing panel regressions and I was
very happy to discover the plm package. However, I have a problem when
trying to access the Total Sum of Squares and Residual Sum of Squares on
this output:
summary(output)
If you want to look at the dataframe, then consider using View.
On Thu, Apr 8, 2010 at 11:14 AM, Paul Miller pjmiller...@yahoo.com wrote:
Hello Everyone,
I am a newbie with about a month's worth of experience using R. I've just
spent a little time learning how to work with date values.
On Apr 8, 2010, at 3:13 PM, array chip wrote:
David,
That does the job! Thanks a lot.
Now I am very very close to what I want. Still have a couple of
small adjustments to make.
1. I use drape=TRUE to draw grid and color on the surface, is there
a parameter to adjust the density of the
Hi
I want to simplify my problem into a prototype, how to write a function to
get all the object in your current environment, e.g. .GlobalEnv, and print
their mode?
For example, if I have object a,b,c... in my environment,
a=1;b='test';c=matrix(0,3,3).
I want to write a function myfun(),
David,
all.equal() only tells how many mismatches there are including missing
values but it doesn't tell me the location of each mismatch.
For example, if I have one NA mismatch and three numerical mismatches,
all.equal(a,b) gives
[1] Component 2: 'is.NA' value mismatch: 1 in current 0 in
Hi Dave,
first of all, fitting starting values of a dynamic model the same way
like its parameters is indeed the usual method. In that case parameters
*and* some or all initial value(s) of the dynamic model are both in fact
'parameters' for the statistical model fitting problem.
Fitting a
On Apr 8, 2010, at 4:03 PM, Jun Shen wrote:
David,
all.equal() only tells how many mismatches there are including
missing values but it doesn't tell me the location of each mismatch.
Yes, I noticed that after further testing. I agree Charles' solution
is more informative and I wonder if
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