On Thu, May 6, 2010 at 10:47 PM, Mohan L l.mohan...@gmail.com wrote:
snip
I am using source() to run program, like
source (sample.R)
I want to know how to pass the argument to my sample.R, some this like
source(sample.R, xxx,FeMale)
Is it possible? any link will greatly appreciated.
Hi Dennis,
It is similar to what I was trying to achieve. Is there a way to show the
grouped time courses as separate facets.
So in lattice, the time courses would be conditioned on Ab status and subject
name at the same time.
Thanks.
George
From: Dennis Murphy djmu...@gmail.com
-- Forwarded message --
From: Dr. Venkatesh drve...@liv.ac.uk
Date: Sun, May 9, 2010 at 4:55 AM
Subject: R apply() help -urgent
To: r-help@r-project.org
I have a file with 4873 rows of 1s or 0s and has 26 alphabets (A-Z) as
columns. the 27th column also has 1s and 0s but stands
Dear list,
I did multiple imputation with mice on a wide dataset. For my repeated
measures ANOVA I need to reshape the data from wide to long. In order
to pool the analysis, I would still like it to be a mids-object after
reshaping. Does anyone know how to do this?
Thanks,
Nicole
1. is there some criterion to estimate overfitting? e.g. R2 and Q2 in the
training set, as well as R2 in the test set, when means overfitting. for
example, in my data, I have R2=0.94 for the training set and for the test
set R2=0.70, is overfitting?
2. in this scatter, can one say this
I notice something curious about how aov() treats a numeric factor:
score is a dependent variable and group is a factor in a one-way ANOVA.
But group contains numeric codes and is not a factor (checked with
is.factor). An ANOVA done using:
aov(score~factor(group), data=mydata)
gives the right
Hi
I need to calculate the indicator U de Theil from my forecasts, so I want
to know if there is a specific command or function that provides me the
indicator U de Theil
Thanks..
Olga Maria Formigoni C. Walter
E-mail: mailto:olgaformig...@gmail.com olgaformig...@gmail.com
MSN:
On May 9, 2010, at 8:36 AM, Ravi Kulkarni wrote:
I notice something curious about how aov() treats a numeric factor:
score is a dependent variable and group is a factor in a one-way
ANOVA.
But group contains numeric codes and is not a factor (checked with
is.factor). An ANOVA done using:
On May 9, 2010, at 12:30 AM, Venkatesh Patel wrote:
-- Forwarded message --
From: Dr. Venkatesh drve...@liv.ac.uk
Date: Sun, May 9, 2010 at 4:55 AM
Subject: R apply() help -urgent
To: r-help@r-project.org
I have a file with 4873 rows of 1s or 0s and has 26 alphabets (A-Z) as
I do not know if this is what you want, but take a look at the External
links at the bottom of the Wikipedia page:
http://en.wikipedia.org/wiki/Theil_index
Ravi
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Hi,
Instead of accessing the data by its name in data.frame, you may use
index by [[ ]] as well. For your case, the looping may looks like
for (i in 1:26){
datatable - table(data1[[i+2]], data1$pLoss) #create a new
datatable2 or 3
fisher.test(datatable)
}
Bests,
Ruihong
On
On May 9, 2010, at 8:24 AM, Olga Maria Formigoni Carvalho Walter wrote:
Hi
I need to calculate the indicator U de Theil from my forecasts, so
I want
to know if there is a specific command or function that provides me
the
indicator U de Theil
It appears to me that you have not yet
On May 9, 2010, at 9:20 AM, bbslover wrote:
1. is there some criterion to estimate overfitting? e.g. R2 and Q2
in the
training set, as well as R2 in the test set, when means
overfitting. for
example, in my data, I have R2=0.94 for the training set and for
the test
set R2=0.70, is
Thank you for your replies.
As I said (wrote) before, 'I am no statistician'.
But I think I know what Random Variables are (not).
Random variables are not random, neither are they variable.
[It sounds better in french: Une variable aléatoire n'est pas variable,
et n'a rien d'aléatoire.]
See
Hello:
I am plotting some data using the box and whisker plot. However, I only want
to plot the median, max and min, as I only have these values and not the
quartile values. It seems R arbitrarily constructs the box margins to be
halfway between the median and the max/min. How do I make the
Dear Ravi,
On Sunday 09 May 2010, Ravi Kulkarni wrote:
I notice something curious about how aov() treats a numeric factor:
In R, there is no such thing as a numeric factor. A numeric vector is not a
factor unless declared as such.
score is a dependent variable and group is a factor in a
Hello!
I have a problem which I have tried to solve for several days now..
I have plottet a lineplot.CI in the library sciplot, and I am trying to
plot it with a logaritmic y-axis (with exponential base).
The problem is that; when I type log y, the axis transforms into the
logaritmic of
Time to rescue Random Variables before they drown!
On 09-May-10 16:53:02, Bak Kuss wrote:
Thank you for your replies.
As I said (wrote) before, 'I am no statistician'.
But I think I know what Random Variables are (not).
Random variables are not random, neither are they variable.
[It
Dear all,
I'm trying to read and sas file hen using read.ssd, I got this error message:
symbolic links are not supported
I have debug read.ssd function and the function file.symlink is used. I
run windows XP on virtual box, hosted by Vista Home
[[alternative HTML version
On 09-May-10 18:10:27, Elisabeth Bjerke Rastad wrote:
Hello!
I have a problem which I have tried to solve for several days now..
I have plottet a lineplot.CI in the library sciplot, and I am
trying to plot it with a logaritmic y-axis (with exponential base).
The problem is that; when I type
On May 9, 2010, at 1:33 PM, michael westphal wrote:
Hello:
I am plotting some data using the box and whisker plot.
What function?
However, I only want to plot the median, max and min, as I only
have these values and not the quartile values.
You could just read the help page for bxp
Hi:
Here's one way to get what you want, using the plyr and ggplot2 packages.
# Fake some data
dd - data.frame(g = factor(rep(LETTERS[1:10], each = 30)),
y = rnorm(300))
# Summarize to get min, median and max per group
# Uses function ddply() in the plyr package...
Hi:
On Sun, May 9, 2010 at 5:36 AM, Ravi Kulkarni ravi.k...@gmail.com wrote:
I notice something curious about how aov() treats a numeric factor:
score is a dependent variable and group is a factor in a one-way ANOVA.
But group contains numeric codes and is not a factor (checked with
Dear R experts---
I doubt that someone has already solved my problem, but I thought I
would ask quickly, just in case someone has.
Let' say I start with a (flattened panel) model that says
y[i] = x[i] + b*(T-x[i])
easy enough---this is just a linear model. I could also make this a
Hello Ted!
Thank you a lot for your reply!!!
I will try to explain again; what I want is a logarithmic scaled y-axis
with the base of e (not 10). And the values I would like to use in the
plot are the raw values (not transformed in any way). Do you still think
that the base of log does not matter
On 09-May-10 20:15:56, Elisabeth Bjerke Rastad wrote:
Hello Ted!
Thank you a lot for your reply!!!
I will try to explain again; what I want is a logarithmic scaled
y-axis with the base of e (not 10). And the values I would like
to use in the plot are the raw values (not transformed in any
On Sun, May 9, 2010 at 6:53 PM, Bak Kuss bakk...@gmail.com wrote:
Thank you for your replies.
As I said (wrote) before, 'I am no statistician'.
But I think I know what Random Variables are (not).
Random variables are not random, neither are they variable.
[It sounds better in french: Une
Dear R-helpers, an rgl-ers in particular,
what is the easiest way to plot a section of a plane in 3D, that is
given by the xyz coordinates of the outline?
Suppose I have a polygon - which I know for sure is a set of
coordinates on the same plane. One method I found is to use surf.tri
from the
On 09/05/2010 6:41 PM, Remko Duursma wrote:
Dear R-helpers, an rgl-ers in particular,
what is the easiest way to plot a section of a plane in 3D, that is
given by the xyz coordinates of the outline?
Suppose I have a polygon - which I know for sure is a set of
coordinates on the same plane.
Duncan,
thanks for the tip! I actually saw this 2D function but had no idea
how to use it in 3D. Works great.
Remko
-
Remko Duursma
Research Lecturer
Centre for Plants and the Environment
University of Western Sydney
Hawkesbury Campus
Richmond
On Sun, May 9, 2010 at 11:53 AM, David Winsemius dwinsem...@comcast.net wrote:
On May 9, 2010, at 9:20 AM, bbslover wrote:
1. is there some criterion to estimate overfitting? e.g. R2 and Q2 in the
training set, as well as R2 in the test set, when means overfitting. for
example, in my
Thanks for both. The reorder function works perfectly.
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a-1:5
b-2:6
plot(a,b)
Error in function (width, height, pointsize, record, rescale, xpinch, :
Graphics API version mismatch
before, R 2.10 , plot() is ok. Now, R 2.11.0 does not work
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Hello!
I have a problem which I have tried to solve for several days now..
I have plottet a lineplot.CI in the library sciplot, and I am trying to
plot it with a logaritmic y-axis (with exponential base).
The problem is that; when I type log y, the axis transforms into the
logaritmic of base
Dear Forum
I a running svychisq from the survey package and get errors with the number
of dimensions,
errors that I do not understand and do not know how to fix.
I ask you kindly to help me out.
The eror message follows with some information below. I hope there are
enough information to help
thanks for your suggestion.
many I need to learn indeed. I will buy that good book.
kevin
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Hi everybody,
I am trying to generate two random walks with an specific correlation,
for example, two random walks of 200 time steps with a correlation 0.7.
I built the random walks with:
x-cumsum(rnorm(200, mean=0,sd=1))
y-cumsum(rnorm(200, mean=0,sd=1))
but I don't know how to fix the
Venkatesh
Is this what you are looking for?
# Example data
df=data.frame(A=c(1,0,0,0,1),B=c(1,1,0,0,0),C=c(1,0,0,0,0),Val=c(1,0,1,0,1))
# Variation of code of David Winsemius
tbl = lapply(df[, 1:3] , function(x) table(x, df$Val))
fet = lapply(tbl, function(x) fisher.test(x))
# Identify
Why do I get this error message?
library(rtracklayer)
session - browserSession()
x-ucscTableQuery(session, knownGene , GenomicRanges(0,12000,chr1))
Error in solveUserSEW0(start = start, end = end, width = width) :
solving row 1: range cannot be determined from the supplied arguments (too
On 05/09/2010 10:53 AM, David Winsemius wrote:
On May 9, 2010, at 9:20 AM, bbslover wrote:
1. is there some criterion to estimate overfitting? e.g. R2 and Q2 in the
training set, as well as R2 in the test set, when means overfitting. for
example, in my data, I have R2=0.94 for the training
On 05/09/2010 07:11 PM, Sigal Blay wrote:
Why do I get this error message?
library(rtracklayer)
session - browserSession()
x-ucscTableQuery(session, knownGene , GenomicRanges(0,12000,chr1))
Error in solveUserSEW0(start = start, end = end, width = width) :
solving row 1: range cannot
Hi R users,
I have a matrix m of the type:
m
X4.20.2010 X4.19.2010 X4.16.2010
[1,] 0.008319468 0. -0.008250825
[2,] 0.005574136 0.01816118 0.073081608
[3,] -0.047830688 0.01612903 -0.030239833
[4,] NA NA NA
[5,] 0.008746356 0.02848576
It is exactly the same
tmp - matrix(1:24,6,4)
tmp[4,] - NA
tmp
apply(tmp, 2, sum, na.rm=TRUE)
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PLEASE do read the posting
Hi All,
I'm working with text processing and I have a problem. The problem is
the following:
I have a text, e.g.: 'R is a free software environment for statistical
computing and graphics.' and I need create a vector of characters such
that each position in the vector will be each letter in the
thank you, I have downloaded it. studying
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tmp - 'R is a free software environment for statistical computing and
graphics'
strsplit(tmp, )
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Hello,
I want to draw a histogram of the mean of sample observations drawn from
multivariate t distribution. I am getting the following error corresponding to
the code I used. Though I am getting the graph, but I am curious to know the
warning message.
Warning messages:
1: In if (freq)
many thanks . I can try to use test set with 100 samples.
anther question is that how can I rationally split my data to training set
and test set? (training set with 108 samples, and test set with 100 samples)
as I know, the test set should the same distribute to the training set. and
what
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