Hi,
I want to add a box at the bottom of a lattice window (device/page?).
Lattice has drawn a nice group of panels with all the plots I need. How
do I add my own summary text at the bottom (several lines worth?)
__
R-help@r-project.org mailing list
Well, your example matrix is symmetric, so row and column operations
naturally return the same values.
You may want to note though that if you apply your function to a matrix
along rows, the results will be stored in the __columns__ of the resulting
matrix. Thus, if you want to simply divide the
Hi:
Ben's example worked for me as follows:
x - matrix(runif(22000),ncol=22)
library(lattice)
library(coda)
m - as.mcmc(x)
xyplot(m, layout = c(2, 11))
layout = uses columns first, then rows...I always forget that :) It also
has an optional
third argument for pages, which might come in handy
You are correct,
I initially missed the as.mcmc step. Without it, R doesn't want to
squeeze so many plots onto a page.
Thanks!
On 6/1/10 10:48 AM, Dennis Murphy wrote:
Hi:
Ben's example worked for me as follows:
x - matrix(runif(22000),ncol=22)
library(lattice)
library(coda)
m -
Another thought I had was to use Sweave.
I could, in theory, use Sweave to create a plot only 7 inches high, and
then a summary table 4 inches high below it, all on the same page of a
Latex document. Could be messy, but might work.
On 6/1/10 11:18 AM, Dennis Murphy wrote:
On Tue, Jun 1,
Hi,
It's not clear what you mean by summary text without a minimal
reproducible example. If your text is ordered as a matrix or a
data.frame, you might want to try this grid function,
gridExtra::grid.table(as.matrix(summary(iris)), theme=theme.white())
If your text has the form of a paragraph,
Hi,
It is a matrix. Exactly the output of summary(foo)
Would you call the gridExtra command before the xyplot command or after?
Now I have:
temp - as.mcmc(foo)
xyplot(temp, layout=c(2,11), main=plot title)
THANKS!!
On 6/1/10 11:35 AM, baptiste auguie wrote:
Hi,
It's not clear what you
That's amazing. (It would have taken me many hours to figure this out
on my own.)
Two quick last questions and then I'm off to plotting:
1) How can I reduce the font size of the table. (It is huge on my plot.)
2) How can I control the ratio of plot area to table area in the grid?
Thanks a
Noah Silverman wrote:
That's amazing. (It would have taken me many hours to figure this out
on my own.)
Two quick last questions and then I'm off to plotting:
1) How can I reduce the font size of the table. (It is huge on my plot.)
2) How can I control the ratio of plot area to table area in
Hi Marc,
I want to debate a couple points from your post:
1. Distribution of GPL covered applications is not permissible via the App
Store due to the Apple Terms of Service language, which infringes upon
rights
granted under the GPL.
'Nuff said.
I'm not sure I agree with this, but there's
Hi, I am wondering if there is a way to extract studentized residues from a
nls() object? I searched archive, someone posted a similar question before
(http://tolstoy.newcastle.edu.au/R/e6/help/09/04/10845.html), but didn't get an
answer.
Thanks for any suggestions,
John
Maybe not the cleanest way, but I create a fake data frame with one row so
ddply() is happy!!
if (nrow(futures)==0) futures-data.frame(...)
-Original Message-
From: Peter Ehlers [mailto:ehl...@ucalgary.ca]
Sent: Tuesday, June 01, 2010 12:07 PM
To: arnaud Gaboury
Cc: 'Prof
Thank you Henrique,
I still dont understand why my code doesnt work ? According to the
definition of apply function it should work no ?
From: Henrique Dallazuanna [mailto:www...@gmail.com]
Sent: Tuesday, June 01, 2010 7:34 PM
To: Joachim de Lezardiere
Cc: r-help@r-project.org
Subject:
Dears
When normality test violate and sample size is large(n=400) can I use t-test?
best gards kourosh
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Hello list helpers,
I'm working at a research institute and I've been asked to develop a way of
using R as a scripting and analysis tool which takes information from users
via web forms, perform a query to an Oracle Database running on a Linux
server and finally return formatted reports to the
R-help,
Sorry if this is more of a regex question than an R question. However,
help would be appreciated on my use of the regexpr function.
In the first example below, I ask for all characters (a-z) in 'abc123';
regexpr returns a 3-character match beginning at the first character.
I am trying to read a source program into a mac pro laptop, which uses
Snow Leopard. R is unable to find the file containing my source
program. I'm using the function source( file name). I need some
examples or detailed instructions. I have no problem reading the file
using PC.
Bob
McGehee, Robert wrote:
R-help,
Sorry if this is more of a regex question than an R question. However,
help would be appreciated on my use of the regexpr function.
In the first example below, I ask for all characters (a-z) in 'abc123';
regexpr returns a 3-character match beginning at the first
At 11:45 AM 6/1/2010, Kourosh Ks wrote:
Dears
When normality test violate and sample size is large(n=400) can I
use t-test?
best gards kourosh
Generally yes, unless there is something really pathological about
the distribution.
You should note that, for n = 400, even the simplest
Hi, Dear R- community,
I am use the intToChar function to convert the integers to letters. But the
output is mess. Can you guys give some suggestions? Thanks!
outcome.predict
[1] 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 7 4 4 4 4 4 4
4 4
[26] 4 4 4 4 4 4 4 4 4 4 4
Hi Marcos,
If your server is running Apache I highly recommend looking at RApache (see
http://biostat.mc.vanderbilt.edu/rapache/).
This will not help with the database connection part though.
Best,
Ista
On Tuesday 01 June 2010 3:05:27 pm marcos carvajalino wrote:
Hello list helpers,
I'm
Try this:
LETTERS[outcome.predict]
On Tue, Jun 1, 2010 at 5:43 PM, Changbin Du changb...@gmail.com wrote:
Hi, Dear R- community,
I am use the intToChar function to convert the integers to letters. But the
output is mess. Can you guys give some suggestions? Thanks!
outcome.predict
[1]
I refer to several resources on the subject here:
http://www.r-statistics.com/category/r-and-the-web/
But the first I would suggest you to look at is this:
http://www.r-statistics.com/2010/02/web-development-with-r-an-hd-video-tutorial-of-jeroen-ooms-talk/
It won't answer all of yor questions
It does not work.
outcome.label-LETTERS(outcome.predict)
Error: could not find function LETTERS
On Tue, Jun 1, 2010 at 1:48 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try this:
LETTERS[outcome.predict]
On Tue, Jun 1, 2010 at 5:43 PM, Changbin Du changb...@gmail.com wrote:
Hi,
That isn't really enough information to answer your question, since you
don't tell us where intToChar comes from or what you are trying to do,
but here are a couple of possibilities:
?intToChar
No documentation for 'intToChar' in specified packages and libraries:
you could try '??intToChar'
Changbin Du wrote:
It does not work.
outcome.label-LETTERS(outcome.predict)
Error: could not find function LETTERS
That is not when Henrique typed. LETTERS is a vector, and must be
indexed as such, i.e., with [].
__
R-help@r-project.org
use [ not (
On Tue, Jun 1, 2010 at 5:50 PM, Changbin Du changb...@gmail.com wrote:
It does not work.
outcome.label-LETTERS(outcome.predict)
Error: could not find function LETTERS
On Tue, Jun 1, 2010 at 1:48 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try this:
Dear all,
I am trying to avoid a for loop here and wonder if the following is possible:
I have a data.frame with 6 columns and i want to get a cross-correlogram (by
using ccf) . Obivously ccf only accepts two columns at once and then returms a
list.
In fact, with a for loop i´d do the
Changbin Du wrote:
Hi, Dear R- community,
I am use the intToChar function to convert the integers to letters. But the
output is mess. Can you guys give some suggestions? Thanks!
I suggest you tell us what you were expecting to happen, that is, what
do you actually want? It looks like
Have you set the correct working directory?
?setwd
?getwd
HTH
Stephan
Robert Tsutakawa schrieb:
I am trying to read a source program into a mac pro laptop, which uses
Snow Leopard. R is unable to find the file containing my source
program. I'm using the function source( file name). I
the intToChar function is in the package R.oo
I AM try to plot the SOM result, use the outcome.labels as labels in the
following plot command.
outcome.xyf - predict(final.xyf)$unit.prediction
outcome.predict- as.numeric(classmat2classvec(outcome.xyf))
Thanks to all!
Yes, LETTERS[outcome.predict] works!
I appreciated your guys help!
On Tue, Jun 1, 2010 at 1:53 PM, Henrique Dallazuanna www...@gmail.comwrote:
use [ not (
On Tue, Jun 1, 2010 at 5:50 PM, Changbin Du changb...@gmail.com wrote:
It does not work.
On Tue, 1 Jun 2010, marcos carvajalino wrote:
Hello list helpers,
I'm working at a research institute and I've been asked to develop a way of
using R as a scripting and analysis tool which takes information from users
via web forms, perform a query to an Oracle Database running on a Linux
Try this:
lapply(mydf[-6], ccf, y = mydf[6])
On Tue, Jun 1, 2010 at 5:50 PM, Bunny, lautloscrew.com
bu...@lautloscrew.com wrote:
Dear all,
I am trying to avoid a for loop here and wonder if the following is
possible:
I have a data.frame with 6 columns and i want to get a
Bunny, lautloscrew.com wrote:
Dear all,
I am trying to avoid a for loop here and wonder if the following is
possible:
I have a data.frame with 6 columns and i want to get a
cross-correlogram (by using ccf) . Obivously ccf only accepts two
columns at once and then returms a list. In fact,
I am not sure about specific timeseries objects, but using an ordinary
vector with the values the aggregate() function works fine:
monthly.means - aggregate(timeseries, mean, by=months)
months now only has to be a vector of length(timeseries) with numbers
relating each entry in timeseries to
As far as I can tell, your code works perfectly. It's just that the mean of
your rows is the same as the mean of your columns because the matrix
is symmetric.
Compare these two examples (the first one is yours):
m = matrix( c(1,4,7,4,5,8,7,8,9), nrow = 3 )
m
[,1] [,2] [,3]
[1,]14
On Tue, 2010-06-01 at 16:43 -0400, Erik Iverson wrote:
McGehee, Robert wrote:
R-help,
Sorry if this is more of a regex question than an R question. However,
help would be appreciated on my use of the regexpr function.
In the first example below, I ask for all characters (a-z) in
Ken,
See comments inline.
On Jun 1, 2010, at 2:25 PM, Ken Williams wrote:
Hi Marc,
I want to debate a couple points from your post:
1. Distribution of GPL covered applications is not permissible via the App
Store due to the Apple Terms of Service language, which infringes upon
rights
try this:
x - readLines(textConnection(V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
+ TP53 Dis1 Dis2 Dis3 Dis4 Dis5 Dis6
+ DCI New1 New2 New3 New4
+ FDI Hi2 H3 H4
+ GHD I1 I3 I4 I5 I6 I7 I8))[-1] # drop the first line
output - do.call(rbind, lapply(x, function(.line){
+ # split the data
+ parms -
Dear all,
It sounds as if regexp works according to the same rules as Perl, very
nicely explained in:
http://blob.perl.org/books/beginning-perl/3145_Chap05.pdf
Yet, I couldn't help but wonder if there are also differences in behaviour.
I couldn't find any yet, but there must be some. Anybody
Dear Changbin,
Please provide a self-contained, minimal example, meaning the whole code
should run and create the plot as it is now, without having to load your
dataset (which we don't have). Otherwise it's impossible to see what's going
on and help you.
Cheers
Joris
On Wed, Jun 2, 2010 at 2:21
I think you can use grid.layout() to create the appropriate layout,
allocating proper space for the upper plotting area and the bottom text
region, and then use viewport() with the layout parameter to control the
output by pushing the viewport at the proper region on the graphical device.
Armin,
On Tue, 1 Jun 2010, Armin Goralczyk wrote:
I have noticed that the MacOS X binary for lme4 is not available on
CRAN at the moment. I am aware that it may be possible to install from
source but I am not very familiar with that procedure and would rather
avoid it. But I need the package
Dear R-helpers,
thanks for yesterday's speeding-up tip. Here is my next query:
I have lots of polygons (not necessarily convex ones, and they never
have holes) given by x,y coordinates.
I want to get the polygon that is the union of these polygons. This is
my current method, but I am hoping
How do I get a list of subdirectories only, not files, in a directory
dir.create(test)
setwd(test)
dir.create(adir)
dir.create(bdir)
file.create(afile)
dir()
returns [1] adir afile bdir
in need to return [1] adir bdir
cheers
Nevil Amos
__
Try this:
dir()[file.info(dir())$isdir]
On Tue, Jun 1, 2010 at 11:06 PM, Nevil Amos nevil.a...@gmail.com wrote:
How do I get a list of subdirectories only, not files, in a directory
dir.create(test)
setwd(test)
dir.create(adir)
dir.create(bdir)
file.create(afile)
dir()
returns [1]
Dear Group Members,
First of all thanks for all the great work and effort.
I am trying to compile a part of the Project R, 'pnorm.c' in visual studio
6.0 c++ language.
First i downloaded the standalone R-2.11.0 and tried to compile it. Some
files were missing here such as 'Rconfig.h'.
Then i
On Jun 1, 2010, at 3:19 PM, Robert Tsutakawa wrote:
I am trying to read a source program into a mac pro laptop, which
uses Snow Leopard. R is unable to find the file containing my
source program. I'm using the function source( file name). I
need some examples or detailed instructions.
library(kohonen)
data(nir)
attach(nir)
#SOM, the supervised learning, train the map using temperature as the class
variable.
set.seed(13)
nir.xyf- xyf(data=spectra, Y=classvec2classmat(temperature), xweight = 0.9,
grid=somgrid(4, 4, hexagonal))
temp.xyf - predict(nir.xyf)$unit.prediction #get
Take a look at the R Installation and Administration manual
http://cran.r-project.org/doc/manuals/R-admin.pdf, under the section
with header The standalone Rmath library.
Matt Shotwell
Graduate Student
Division of Biostatistics and Epidemiology
Medical University of South Carolina
On Tue,
library(xts)
to.monthly(x)
The code is all Fortran, and is very fast. It should work just fine on most
all time-series-like objects/classes, including timeSeries.
Documentation in the vignette will help, as will ?to.period
A wealth of functions to manipulate/test/transform time-series data
Hi
I was trying to have a graph whose axes are X axis: m, Y axis: var[X ((a,b) in
suffix, and (n,d) in the power)].
X ((a,b) in suffix, and (n,d) in the power)-X^(n,d) _ (a,b).
Actually I require many plots involving different values of a,b,n,d, so need to
keep this complicated
Hi,
I think you could use a concave hull from the alphahull package,
http://yihui.name/en/2010/04/alphahull-an-r-package-for-alpha-convex-hull/
It may be difficult to find the right parameters if the polygons
differ widely in edge lengths, though.
HTH,
baptiste
On 2 June 2010 03:53, Remko
Hello,
I was hunting for something else and came across your old message, and
I noticed that it had never received an answer (at least on the list).
I really tried to figure out what might be going on just by looking
at your code, but I could not get enough information from your email
and your
On Wed, Jun 2, 2010 at 12:37 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Please do read the posting guide, in particular regarding reproducible
examples.
You can use a Grid layout to place the lattice plot and a table in the
same page. For example,
library(lattice)
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