On 2 June 2010 07:55, Deepayan Sarkar deepayan.sar...@gmail.com wrote:
Something like this should also work, except that the grob produced by
tableGrob() doesn't seem to know its height.
Indeed, I have not been successful in writing good
widthDetails/heightDetails methods for this grob since
Dear group,
Here is a list of elements :
l -
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426, 100427, 100428, 100429, 100430, 100503,
100504, 100505, 100506, 100507, 100510, 100511, 100512,
100513, 100514, 100517, 100518, 100519, 100520, 100521,
100524, 100525, 100526,
The correct line is :
l[(which(100420==l)-1):which(100420==l)]
[1] 100419 100420
-Original Message-
From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
Sent: Wednesday, June 02, 2010 9:41 AM
To: r-help@r-project.org
Cc: 'arnaud Gaboury'
Subject: which function
Dear group,
Hi Arnaud
Try this
l[((which(100420==l))-1):which(100420==l)]
Regards
Mo
arnaud Gaboury arnaud.gabo...@gmail.com a écrit :
Dear group,
Here is a list of elements :
l -
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426, 100427, 100428, 100429, 100430, 100503,
100504,
Hi,
Try with more parentheses:
l[((which(100420==l))-1):which(100420==l)]
[1] 100419 100420
It was interpreted as 4-(1:4)=3 2 1 0
Ivan
Le 6/2/2010 09:41, arnaud Gaboury a écrit :
Dear group,
Here is a list of elements :
l-
c(100415, 100416, 100419, 100420, 100421, 100422,
100423, 100426,
As I noted in my closing comments in my second post, if one has a desire to
make R's functionality available on smartphones (iPhone, Android, etc.) or
iPad-class devices, then a client/server approach may be the most efficient
means to do so. That approach also avails you of more powerful
Henrique,
thx, your suggestion worked perfectly fine for me.
On 01.06.2010, at 23:01, Henrique Dallazuanna wrote:
lapply(mydf[-6], ccf, y = mydf[6])
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Dear falks, here I have written following function :
fn - Vectorize(function(x = 1:3, y = 3:6) {
x - matrix(x, nrow=1)
y - matrix(y, ncol=1)
dat - apply(x, 2, function(xx) {
apply(y, 1, function(yy) {
Hi Ivan,
Thanks, Jorvis did answer the question - but good to know about list() and
that matrix is no good for a mixture of output. I'm slowly getting my head
around it!
Thanks again for your help, it really was much appreciated!
Ross
--
View this message in context:
Hi Jorvis,
Many thanks for sorting that! I haven't seen it done that way before, so
I'll have to look in to the properties of lapply a bit more to get a full
appreciation of other approaches to looping data in R.
Thanks again for your help, it is much appreciated,
Ross
--
View this message
Hi Ross,
the trick is especially split() and unsplit(). Split() splits up the
dataframe based on the combined factors, unsplit() transforms it to a
dataframe again. This way you can do the calculation for a set of
mini-dataframes that contain only the information for 1 combination of the
factors.
Your arguments are not coming through.
fn - function(x = 1:3, y = 3:6) {
x - matrix(x, nrow=1)
y - matrix(y, ncol=1)
dat - apply(x, 2, function(xx) {
apply(y, 1, function(yy) {
return(xx + yy) } ) })
Baptiste,
thanks for the tip but this would give me an approximate union, and I
really need a (nearly) exact one. I am also not sure how to set the
alpha parameter in a non-arbitrary way.
Remko
-
Remko Duursma
Research Lecturer
Centre for
Dear all,
I am using gamlss (Package gamlss version 4.0-0, R version 2.10.1, Windows XP
Service Pack 3 on a HP EliteBook) to relate bird counts to habit variables.
However, most models fail because the global deviance is increasing and I am
not sure what causes this behaviour. The dataset
Hi Changbin,
I looked at your code again, and it appears as if you're using the mapping
plot for something that it isn't meant for. The mapping shows you how many
points you have in every circle, and these points are represented by the
labels. Your first plot gives the majority vote.
This said,
Hi Diederik,
I can't say immediately why your models fail without seeing the data and
running a number of tests. You could play around with the other parameters,
as the problem might be related to the optimization algorithm.
A different approach would be using the methods in the vegan package.
Hi all R users,
I download market data from Yahoo Finance to save file in csv.
But, I can't load data set into R successfully. I don't why ?
Below is error message.
data - readSeries(D:/data.csv,header=T,sep=,)
Error in midnightStandard2(charvec, format) :
'charvec' has non-NA entries of
Dear all
I encountered strange problem with regexpr replacement
I made this character object
str - 02.06.10 12:40
str(str)
chr 02.06.10 12:40
I read in an object which seems to be quite similar
str(as.character(becva$V1)[1])
chr 02.06.10 12:40
However I can not remove
Could you provide us with dput(becva$V1[1])?
Cheers
Joris
On Wed, Jun 2, 2010 at 2:07 PM, Petr PIKAL petr.pi...@precheza.cz wrote:
Dear all
I encountered strange problem with regexpr replacement
I made this character object
str - 02.06.10 12:40
str(str)
chr 02.06.10 12:40
On Wed, 2010-06-02 at 08:07 -0400, Petr PIKAL wrote:
Dear all
I encountered strange problem with regexpr replacement
I made this character object
str - 02.06.10 12:40
str(str)
chr 02.06.10 12:40
I read in an object which seems to be quite similar
Hello.
I'd like to compute the associate vector of distances between leaves in a
binary non-rooted tree. The definition of a distance between two leaves in a
binary non-rooted tree is the number of edges in the path joining the two
leaves.
I've tried the ape package but I'm unable to find this
Dear all,
I'm having difficulties installing a package on Windows. It has only R
data files, no code. I've built it on a Linux platform and installed it
there without problems. When I tried installing the .tar.gz on Windows,
via install.packages, I got the following errors:
Error in gzfile(file,
Hi,
with a little hack you can use the function cophenetic.phylo from ape. You
just set all branch lengths to 1 :
require(ape)
tree - rtree(5,rooted=F)
n - length(tree$edge.length)
tree$edge.length - rep(1,n)
cophenetic.phylo(tree)
t3 t1 t2 t4 t5
t3 0 3 3 3 3
t1 3 0 2 4 4
t2 3 2
Hi
dput(bbb)
c(02.06.10 12:40 , 02.06.10 12:00 , 02.06.10 11:00 ,
02.06.10 10:00 , 02.06.10 09:00 , 02.06.10 08:00 ,
02.06.10 07:00 , 02.06.10 06:00 , 02.06.10 05:00 ,
02.06.10 04:00 , 02.06.10 03:00 , 02.06.10 02:00 ,
02.06.10 01:00 , 02.06.10 00:00 , 01.06.10
Hello R experts,
can you tell me a simple way to convert a charactor matrix to numeric matrix?
if I use as.numeric, the matrix is converted to a vector.
a-cbind(c(23,54,65),c(1,2,3))
a
[,1] [,2]
[1,] 23 1
[2,] 54 2
[3,] 65 3
as.numeric(a)
[1] 23 54 65 1 2 3
thanks
Jian
Hi all R users,
I download market data from Yahoo Finance to save file in csv.
But, I can't load data set into R successfully. I don't why ?
Below is error message.
data - readSeries(D:/data.csv,header=T,sep=,)
Error in midnightStandard2(charvec, format) :
'charvec' has non-NA entries of
Hi Arnaud,
I've added this case to the set of test cases in plyr and it will be
fixed in the next version.
Hadley
On Tue, Jun 1, 2010 at 2:33 PM, arnaud Gaboury arnaud.gabo...@gmail.com wrote:
Maybe not the cleanest way, but I create a fake data frame with one row so
ddply() is happy!!
if
Dear R-users,
I build already many contour graphs using the contour-procedure in R (akima
library), after interpollating my data z on x,y (see e.g. graphs in this paper:
http://www.biomedcentral.com/content/pdf/1471-2148-9-16.pdf).
Now, however, i experience unexpected and completely
Hi,
I want to write a matrix (n*m) in a file (Text file) such that the file
will be as Result file (below).
I use the below command but it write all numbers in one column,
write(paste(matrixname),file=test.txt,append=TRUE)
how can I do this?
Result file:
55 -1 -1 -1 -1
88
try this:
a-cbind(c(23,54,65),c(1,2,3))
a
[,1] [,2]
[1,] 23 1
[2,] 54 2
[3,] 65 3
mode(a) - 'numeric'
a
[,1] [,2]
[1,] 231
[2,] 542
[3,] 653
On Wed, Jun 2, 2010 at 8:15 AM, Yuan Jian jayuan2...@yahoo.com wrote:
Hello R experts,
can you tell me a simple way to
Hi Jian,
Try
matrix(as.numeric(a), ncol = 2)
HTH,
Jorge
On Wed, Jun 2, 2010 at 8:15 AM, Yuan Jian wrote:
Hello R experts,
can you tell me a simple way to convert a charactor matrix to numeric
matrix?
if I use as.numeric, the matrix is converted to a vector.
Hi
you have several options
apply(a, 2, as.numeric)
matrix(as.numeric(a),3,2)
b-as.numeric(a)
dim(b)-c(3,2)
Regards
Petr
r-help-boun...@r-project.org napsal dne 02.06.2010 14:15:25:
Hello R experts,
can you tell me a simple way to convert a charactor matrix to numeric
matrix?
if I use
try this:
x - matrix(1:25,5)
x
[,1] [,2] [,3] [,4] [,5]
[1,]16 11 16 21
[2,]27 12 17 22
[3,]38 13 18 23
[4,]49 14 19 24
[5,]5 10 15 20 25
write.table(x, file='')
V1 V2 V3 V4 V5
1 1 6 11 16 21
2 2 7 12 17 22
3 3 8 13 18 23
Hi Amir,
Here is a suggestion:
write.table(yourmatrix, mymatrix.txt, col.names = FALSE, row.names =
FALSE, sep = \t, quote = FALSE)
After executing this, you will see a mymatrix.txt file in your working
directory. Here, typing getwd() in the R console may also help.
Do not forget to take a look
You had the wrong case on 'w' and the wrong expression with
[:space:]'; see below
bbb - c(02.06.10 12:40 , 02.06.10 12:00 , 02.06.10 11:00 ,
+ 02.06.10 10:00 , 02.06.10 09:00 , 02.06.10 08:00 ,
+ 02.06.10 07:00 , 02.06.10 06:00 , 02.06.10 05:00 ,
+ 02.06.10 04:00 , 02.06.10
On 10-06-02 10:34 AM, amir wrote:
I want to write a matrix (n*m) in a file (Text file) such that the file
will be as Result file (below).
I use the below command but it write all numbers in one column,
write(paste(matrixname),file=test.txt,append=TRUE)
how can I do this?
...
Matrix:
sub(\\s+$, '', bbb,perl=T)
does it for me.
On Wed, Jun 2, 2010 at 3:22 PM, Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
dput(bbb)
c(02.06.10 12:40 , 02.06.10 12:00 , 02.06.10 11:00 ,
02.06.10 10:00 , 02.06.10 09:00 , 02.06.10 08:00 ,
02.06.10 07:00 , 02.06.10 06:00 ,
Hi
thanks. I am puzzled what was wrong. Now even
sub(' +$', '', bbb[1])
works. I am checking water throughput in nearby river and copying data
from internet. So I wonder if there was some change recently as during
floods they update it in about 10 minutes interval.
Regards
Petr
jim holtman
On Wed, 2010-06-02 at 09:22 -0400, Petr PIKAL wrote:
Hi
dput(bbb)
c(02.06.10 12:40 , 02.06.10 12:00 , 02.06.10 11:00 ,
02.06.10 10:00 , 02.06.10 09:00 , 02.06.10 08:00 ,
02.06.10 07:00 , 02.06.10 06:00 , 02.06.10 05:00 ,
02.06.10 04:00 , 02.06.10 03:00 , 02.06.10
[Reposting to list]
Thank you Rich.
I still don't get it.
If i understand correctly- the MMC example on maize data outlines an
issue with the multiple ties between group means. As a result of this,
user specified contrasts needed specifying.
Its this part, understanding the design matrix
Hi Petr,
Matt may very well have been right. As I copied the dput from the mail, any
white space is converted to spaces apparently. Still, it might be possible
the white spaces in your original data are tabs or even newline characters.
You can check that easily with
grep(\t,
I do really think it is a very good idea.
TY
-Original Message-
From: h.wick...@gmail.com [mailto:h.wick...@gmail.com] On Behalf Of
Hadley Wickham
Sent: Wednesday, June 02, 2010 3:31 PM
To: arnaud Gaboury
Cc: Peter Ehlers; r-help@r-project.org; Prof Brian Ripley
Subject: Re:
Dear group,
Here is my environment:
ls()
[1] DailyPL100419 DailyPL100420 DailyPL100421 ddi
l PLglobal Pos100416 Pos100419 Pos100420
Pos100421 position
[13] resultsel Trad100416Trad100419
Trad100420Trad100421trade
With
Did you try using the type=source parameter for install.packages?
On Jun 2, 2010, at 3:02 PM, Erick Rocha Fonseca wrote:
Dear all,
I'm having difficulties installing a package on Windows. It has only R
data files, no code. I've built it on a Linux platform and installed it
there without
Hi R experts,
I'm using the xyplot function in lattice to draw a multipanel plot consiting
of 5x6 scatterplots.
Now I need to link single points in each of those scatterplots (=panel),but
the points, that need linking are different for each panel.
I tried to use the panel.segments function for
Hello,
Does this do what you are looking for?
output - NULL
for(i in paste(DailyPL, sel, sep=)[-1]){
output - rbind(output, get(i))
}
If you just want to rbind all the data frames, there are ways of doing
it without a loop too, but since you specifically asked with
Yes indeed I just want to rbind the data frames with numbers belonging to
sel, and if possible, avoid a loop.
To be more precise, if sel[-1]-c(100420, 100421), I look for a line which
will give me this result :
dd-rbind(DailyPL100420,DailyPL100421)
-Original Message-
From: Joshua
Hi
I have original data for which sub(' +$', '', ...) did not work in Excel
so I could try them again.
grep(\t, as.character(becva$V1[1]))
integer(0)
grep(\n, as.character(becva$V1[1]))
integer(0)
and Jim's solutions work as expected
sub('[[:space:]]+$', '', becva$V1[1])
[1] 02.06.10 12:40
I am working with something like this :
for (i in sel[-1]) {
dd-data.frame(do.call(rbind,
mget(paste(DailyPL,i,sep=),envir=.GlobalEnv)),row.names=NULL)
}
But the result is not good. In the case where sel[-1]-c(100420, 100421),
dd is only equal to DailyPL100421
This should do the trick:
dd - do.call(rbind, mget(paste(DailyPL,sel[-1], sep=), envir=.GlobalEnv))
On Wed, Jun 2, 2010 at 8:06 AM, arnaud Gaboury arnaud.gabo...@gmail.com wrote:
I am working with something like this :
for (i in sel[-1]) {
dd-data.frame(do.call(rbind,
Hi Arnaud,
Try the following (untested):
txt - paste('DailyPL',c(100419, 100420, 100421), sep = )
do.call(rbind, lapply(txt, get))
HTH,
Jorge
On Wed, Jun 2, 2010 at 10:24 AM, arnaud Gaboury wrote:
Dear group,
Here is my environment:
ls()
[1] DailyPL100419 DailyPL100420 DailyPL100421
On Wed, Jun 2, 2010 at 8:06 AM, arnaud Gaboury arnaud.gabo...@gmail.com wrote:
I am working with something like this :
for (i in sel[-1]) {
dd-data.frame(do.call(rbind,
mget(paste(DailyPL,i,sep=),envir=.GlobalEnv)),row.names=NULL)
}
But the result is not good. In the case
Hi:
This is shorter:
t(outer(x, y, '+'))
[,1] [,2] [,3]
[1,]456
[2,]567
[3,]678
[4,]789
[5,]89 10
HTH,
Dennis
On Wed, Jun 2, 2010 at 2:25 AM, Megh Dal megh700...@yahoo.com wrote:
Dear falks, here I have written following function
Hi Arnaud,
Just replace c(...) by sel[-1] in the paste(...) call and you will be ready
to go.
Regards,
Jorge
On Wed, Jun 2, 2010 at 11:13 AM, arnaud Gaboury wrote:
Jorge,
Your line works and give the desired result. Now I need to be able to work
with i instead of 100419..., as I need to
Yes Joshua, it does the trick. Once more, I am surprised by the easiness and
obviousness of R.
Now, I would like to add argument row.names=NULL.
dd - do.call(rbind, mget(paste(DailyPL,sel[-1], sep=),
envir=.GlobalEnv),row.names=NULL)
Error in do.call(rbind, mget(paste(DailyPL, sel[-1], sep =
Hi all,
I want to draw a arrow (small) of any length along with OsCYP right side i.e
parrallel and antiparallel arrows both
text(os[1], 10.2, pos = 4, OsCYP, font=1, cex = 1, col = red)
and
how can I connect two points with dotted line lets say
bp[1 ]10.2
Doris,
You might get lucky and find some kind soul who's willing to
dig through your *un*reproducible code, but your chances for
help would probably increase dramatically if you were to
provide *reproducible* and *minimal* code to illustrate your
problem. I imagine that you might benefit from
Here we go :
dd-data.frame(do.call(rbind,
mget(paste(DailyPL,sel[-1],sep=),envir=.GlobalEnv)),row.names=NULL)
TY so much Joshua and Jorge.
-Original Message-
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Wednesday, June 02, 2010 5:11 PM
To: arnaud Gaboury
Cc:
Dear R People:
I have the following data frame:
x.df
datecond freq
1 04/01/09 Fever 12
2 04/02/09 Fever 11
3 04/03/09 Fever 10
4 04/04/09 Fever 13
5 04/05/09 Fever6
6 04/01/09Rash6
7 04/02/09Rash 10
8
Hello Martin and Ted,
First off thank you to you guys and all the volunteers for providing
this wonderful service. I have two questions.
1) Do you know if it is a problem to respond to a post from nabble
using a gmail account?
2) Would it be easier for you if people just used non free
Thanks, Joris!
It works! I appreciated!
On Wed, Jun 2, 2010 at 4:23 AM, Joris Meys jorism...@gmail.com wrote:
Hi Changbin,
I looked at your code again, and it appears as if you're using the mapping
plot for something that it isn't meant for. The mapping shows you how many
points you have
On Tue, Jun 1, 2010 at 9:59 PM, Shant Ch sha1...@yahoo.com wrote:
Hi
I was trying to have a graph whose axes are X axis: m, Y axis: var[X ((a,b)
in suffix, and (n,d) in the power)].
X ((a,b) in suffix, and (n,d) in the power)- X^(n,d) _ (a,b).
Actually I require many plots
El 02/06/10 15:14, Joris Meys escribió:
Hi,
with a little hack you can use the function cophenetic.phylo from ape.
You just set all branch lengths to 1 :
require(ape)
tree - rtree(5,rooted=F)
n - length(tree$edge.length)
tree$edge.length - rep(1,n)
cophenetic.phylo(tree)
t3 t1 t2
-Original Message-
From: Tonja Krueger [mailto:tonja.krue...@web.de]
Sent: Monday, May 31, 2010 2:03 AM
To: William Dunlap
Cc: r-help@r-project.org
Subject: RE: [R] Peak Over Threshold values
Thanks a lot for your help. That's the time period I was looking for.
I've got one
I have a function that I am currently using very inefficiently. The following
are needed to illustrate the problem:
set.seed(12345)
dat - matrix(sample(c(0,1), 110, replace = TRUE), nrow = 11, ncol=10)
mis - sample(1:110, 5)
dat[mis] - NA
theta - rnorm(11)
b_vector - runif(10, -4,4)
empty -
Hi:
Here's one approach, converting the sub-data frames to zoo objects:
# Function to convert one of the data frames to a zoo object
makezoo - function(df) {
require(zoo)
date - as.Date(df[, 1], format = '%m/%d/%y')
with(df, zoo(freq, date))
}
library(zoo)
# Split the data
Jorge,
Your line works and give the desired result. Now I need to be able to work
with i instead of 100419..., as I need to be able to change these numbers.
TY for your help
From: Jorge Ivan Velez [mailto:jorgeivanve...@gmail.com]
Sent: Wednesday, June 02, 2010 5:09 PM
To: arnaud Gaboury
I am trying to figure out how parameters are defined in a function that is used
by DEOptim. That is, when I set upper and lower bounds for DEOptim how does it
know which element of the function to apply those bounds to? For example, in
DEOptim call below, when DEOptim goes into optimfxn how
Take a look at contrast package. It has functions to handle with user
contrasts. Below you have a reproducible and minimal example using
contrast's functions.
da - expand.grid(A=factor(paste(A, 1:3, sep=)),
B=factor(paste(B, 1:4, sep=)), rep=1:4)
eta - model.matrix(~A*B,
Hello fellow R users,
I have been getting a strange error message when using the cv.glmnet
function in the glmnet package. I am attempting to fit a multinomial
regression using the lasso. covars is a matrix with 80 rows and roughly 4000
columns, all the covariates are binary. resp is an eight
On 31.05.2010 10:31, Benedikt Gehr wrote:
Hi
I'm trying to run an admb model from R by using the system () command.
The admb model runs fine when running it from the admb command line or
when using emacs. However when I try it with system() then R crashes
every time.
And I tried using the R
Position Profile:
This position will work directly with the head of the Advanced Analytics
group, as well as other members of the Marketing Evolution team, to
design and perform analytical research necessary to address client's
marketing issues. Responsibilities include
Hi,
I was trying to have a graph whose axes are of the following type:
X axis: n and Y axis: var[U ((a,b) in suffix, and (n,d) in the power)].
U ((a,b) in suffix, and (n,d) in the power)-U^(n,d) _ (a,b).
Actually I require many plots involving different values of a,b,n,d, so need to
Karl,
The definition and interpretation of contrasts is part of any intermediate
design of
experiments text.
Contrasts for interactions say that the effect of moving
from level 1 of A to level 2 of A depends on the level of B.
I will use notation YAB to indicate the levels of A and B.
For
Dear R users,
After running Sweave, this is what I get :
Warning messages:
1: glm.fit: algorithm did not converge
2: glm.fit: algorithm did not converge
There is no glm.fit function in my code.
Where does it come from ? From Sweave ? From system.time ?
Thanks for your help,
Jimmy
hi folks, i use ESS mode in emacs often to interact with R, and while
i know how to save a session transcript, i'm wondering how to save
just the history of the commands (i.e. identically to how R gives the
history save option from its native CLI).
if you use ESS with an R process, commands
How could we possibly tell without your code? Do you call glm or fit
*any* models in your code? Can you use traceback() to see the trace of
function calls that generated the error?
Jimmy Söderly wrote:
Dear R users,
After running Sweave, this is what I get :
Warning messages:
1:
Erik Iverson wrote:
How could we possibly tell without your code? Do you call glm or fit
*any* models in your code? Can you use traceback() to see the trace of
function calls that generated the error?
Sorry you aren't getting an error, but a warning, my mistake.
I think you are asking for M-x ess-transcript-clean-buffer
Save your output file in a file named something.rt which will open
in ess-transcript-mode. It opens read-only and you will need to C-x C-q
to make it writable. Then run
M-x ess-transcript-clean-buffer
On Wed, Jun 2, 2010 at 2:35 PM,
On 02.06.2010 20:22, Shant Ch wrote:
Hi,
I was trying to have a graph whose axes are of the following type:
X axis: n and Y axis: var[U ((a,b) in suffix, and (n,d) in the power)].
U ((a,b) in suffix, and (n,d) in the power)-U^(n,d) _ (a,b).
Actually I require many plots involving
All,
When saving plots to a pdf file via the pdf function, I would like to be
able to automatically expand the graphics device to achieve the same result
as when one does this manually (e.g., clicking the green expand button on
the upper left of the graph on Mac OS). Consider simple example
Joris,
Thank you, I have corrected my mistakes. I very much appreciate your time
and patience.
All my best,
Cobbler.
--
View this message in context:
http://r.789695.n4.nabble.com/Linear-Discriminant-Analysis-in-R-tp2231922p2240547.html
Sent from the R help mailing list archive at Nabble.com.
Dearest all,
Objective: I am now learning neural networks. I want to see how well can
train an artificial neural network model to discriminate between the two
files I am attaching with this message.
http://r.789695.n4.nabble.com/file/n2240582/3dMaskDump.txt 3dMaskDump.txt
I found the same annoying warning, but I ignore it, as you said it's not use
at all. The error (at least for me) is in the line
class(xreg) - NULL
This makes xreg a list, so you cannot apply cbindmaybe they will fix
that some time in the future (you can always recompile the code)
Huber
Could you give us the traceback? (In case you don't know, just type
traceback() right after you got the error message.) I can't reproduce the
error, so it gets a bit difficult to solve without having the real data.
Cheers
Joris
On Wed, Jun 2, 2010 at 6:51 PM, Dave_F friedenbe...@battelle.org
r-help seems to have rejected the first attempt at sending this so I
am trying again.
read.zoo has a split= argument which lets you read in the data and
split it all at the same time. You can also use it on a data frame.
Due to a bug which is fixed in the development version, you will need
the
Hello,
I have basic familiarity with Unix but by most standards a novice. I am
trying to install R on a linux machine and am following the instructions in
the R install and admin guide in terms of what is required to compile the R
source code. I downloaded R version 2.11.1 and extracted the
David,
I would use either the 'width=' argument to pdf() or
use a smaller font for the x-axis (or both).
Something like:
pdf(file = foo.pdf, width = 10)
xyplot(Y ~ Time | as.factor(Subject), data = foo.frm,
layout = c(2,2),
scale = list(x = list(
at = c(0, 15, 30,
dim(tmp)
[1] 576 12
tmp
1 10 11 12 13 2 3 4 5 6 7 9
10 0 0 0 0 0 0 12 0 0 0 0
20 0 0 0 0 0 0 15 0 0 0 0
30 0 0 0 0 0 0 11 0 0 0 0
40 0 0 0 0 0 0 11 0 0 0 0
50 0 0 0 0 0 0 12 0 0 0 0
60 0 0 0
Hi Changbin,
it's not line numbers. It's row names, and you deleted some of them. If you
checked, you'd have seen that eg 107-109 are missing. So you have 576 lines
left from a matrix that had 600 when it was formed.
Cheers
Joris
On Wed, Jun 2, 2010 at 11:47 PM, Changbin Du changb...@gmail.com
Changbin -
If you take the time to look at your data frame,
you'll see the following 24 numbers are missing
from the rownames.
78 84 107 108 109 158 164 194 197 203 240 241
243 255 256 264 275 277 282 284 300 305 311 312
(I found this using
(1:600)[!(1:600) %in% rownames(tmp)]
)
row names are not the same as line numbers or indices.
you've likely done some row-based selection on an original matrix or
data frame.
observe from the example below.
(and in the future please don't expect people to sort through your
500+ line matrices by hand to find your problems.)
x -
This is a guess since you didn't say where it comes from.
It looks like a data.frame where some rows were deleted.
Also, note that the column names in your example are sorted alphabetically
instead of numerically. This example shows one way to get that behavior.
Rich
tmp -
This is not an issue with R, but with gfortran. See the following:
http://gcc.gnu.org/wiki/GFortran#news (under heading gfortran 4.5)
http://gcc.gnu.org/ml/fortran/2010-04/msg00061.html
Also, I suspect you are using a precompiled gcc/gfortran, and it assumes
you have libmpc.so.2
Thanks all of you, I appreciated!
On Wed, Jun 2, 2010 at 2:58 PM, Phil Spector spec...@stat.berkeley.eduwrote:
Changbin -
If you take the time to look at your data frame,
you'll see the following 24 numbers are missing
from the rownames.
78 84 107 108 109 158 164 194 197 203 240 241
text() can draw text on a plot.
Do we have a way/function to draw text with a box surround it?
Thanks,
-james
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Without checking R or the rest of the code, the error seems quite clear to
me: R finds a formula where it expects a data frame. cvc_lda is not a
dataframe. Do str(cvc_lda) to check for yourself. You really need to learn
this btw. Whenever you get an error, first thing to do is to check whether
On 2010-06-02 16:57, g...@ucalgary.ca wrote:
text() can draw text on a plot.
Do we have a way/function to draw text with a box surround it?
Thanks,
There may be a function in some package, but I would just use rect().
?rect
-Peter Ehlers
__
Not really a direct answer on your question, but:
system.time(replicate(1,apply(as.matrix(theta), 1, rasch, b_vector)))
user system elapsed
4.510.034.55
system.time(replicate(1,theta%*%t(b_vector)))
user system elapsed
0.250.000.25
It does make a
Hello,
I have been trying to get an ANOVA table for a linear model containing a
single nested factor, two fixed factors and a covariate:
carbonmean-lm(C.Mean~ Mean.richness + Diversity + Zoop + Diversity/Phyto +
Zoop*Diversity/Phyto)
where, *Mean.richness* is a covariate*, Zoop* is a
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