Dear All,
In Storey's estimator of the proportion of true nulls, the estimator depends on
the tuning parameter lamda.
Suppose now that an estimator of this proportion has been obtained by the
qvalue package, what is the lamda that
corresponds to the estimate? How to get this lamda?
Thanks,
-Chee
Hi folks,
I have come across a simple quirk that took me a long time to figure
out. The gist is that if I write, in the example section of an Rd
file, the line
c = a %*% b
what R will see when running the example is
c = a
since the % signs are apparently considered comment signs even in the
Hi Eric,
I have the same issue in Windows. When I upgrade, I just copy all the
packages I need from the 2.12 to the 2.13 library folder and run
update.packages afterwards. However, be careful not to replace any of
the existing packages with older versions, as this might break the
On 11-04-18 9:51 PM, Matt Shotwell wrote:
Does anyone know if there is a simple way to print raw vectors, such
that ASCII characters are printed for bytes in the ASCII range, and
their hex representation otherwise? rawToChar doesn't work when we have
something like c(0x00, 0x00, 0x44, 0x00).
On 11-04-19 2:26 AM, Peter Langfelder wrote:
Hi folks,
I have come across a simple quirk that took me a long time to figure
out. The gist is that if I write, in the example section of an Rd
file, the line
c = a %*% b
what R will see when running the example is
c = a
since the % signs
Dear all
I have written a function to perform a very simple but useful task which I
do regularly. It is designed to show how many values are missing from each
variable in a data.frame. In its current form it works but is slow because I
have used several loops to achieve this simple task.
Hi
Hi
try
colSums(is.na(data.m))
It is not in data frame but you can easily transform it if you want.
Regards
Petr
r-help-boun...@r-project.org napsal dne 19.04.2011 09:29:08:
Dear all
I have written a function to perform a very simple but useful task which
I
do regularly. It is
On Tue, Apr 19, 2011 at 03:29:08PM +0800, Tim Elwell-Sutton wrote:
Dear all
I have written a function to perform a very simple but useful task which I
do regularly. It is designed to show how many values are missing from each
variable in a data.frame. In its current form it works but is
On Tue, Apr 19, 2011 at 03:29:08PM +0800, Tim Elwell-Sutton wrote:
Dear all
I have written a function to perform a very simple but useful task which I
do regularly. It is designed to show how many values are missing from each
variable in a data.frame. In its current form it works but is
Dear R Users,
Lets assume I have this data frame:
x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04 7 0.1
4 1.06 9 0.4
x and y columns are sorted and the values not necessarily integers. z
values are not sorted. Now I would like to create a matrix out of this
with x as first column values and y
I use the following code/function which gives me some quick descriptives about
each variable (ie. n of missing values, % missing, case #'s missing, etc.):
Fairly quick, maybe not pretty but effective on either single variables or
entire data sets.
NAhunter-function(dataset)
{
Dear R Gurus,
I would like to make a line-plot of a large data-set (200 data-points)
for a document which will be printed in black and white. The plot will
contain 5 different lines. So i need a way to differentiate between the
lines. Since color is not an option i tried different line styles
Dear Petr
Thanks so much. That is a LOT more efficient.
Tim
-Original Message-
From: Petr PIKAL [mailto:petr.pi...@precheza.cz]
Sent: Tuesday, April 19, 2011 3:37 PM
To: tesutton
Cc: r-help@r-project.org
Subject: Odp: [R] Simple Missing cases Function
Hi
Hi
try
colSums(is.na(data.m))
Thanks Tyler
This function has some useful features
Tim
From: Tyler Rinker [mailto:tyler_rin...@hotmail.com]
Sent: Tuesday, April 19, 2011 3:52 PM
To: tesutton; r-help@r-project.org
Subject: RE: [R] Simple Missing cases Function
I use the following code/function which gives me some
On 04/19/2011 06:05 PM, Timo Schneider wrote:
Dear R Gurus,
I would like to make a line-plot of a large data-set (200 data-points)
for a document which will be printed in black and white. The plot will
contain 5 different lines. So i need a way to differentiate between the
lines. Since color is
On 2011-04-18 17:52, Tom La Bone wrote:
Below is a SIMEX object that was generated with the simex function from the
simex package applied to a logistic regression fit. From this mountain of
information I would like to extract all of the values summarized in this
line:
.. ..$
Thank Rolf,
I am aware of the extrapolation possibilities within the interpolation
packages within akima but this interpolation often leads to unrealistic
results for my sedimentary units. Therefore I would like to be able to just
apply the interpolation to the thickness measurements within the
Dear R,
Usually when I want to read pdf help for R functions under Linux, I do
the following steps
help(par,help_type=pdf)
system(paste(getOption(pdfviewer),par.pdf))
which works well. First question, can I let help to save the pdf
file to a different place other than current working
What is the function to have the entire part of a number?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hello List,
I have a data frame like:
V130V131V132V133V134V135V136
1 0 0 0.9 0 0.9
0 0
2 0 0 0 0
0
What is the function to have the entire part of a number?
If entire refers to integer take a look at
?trunc
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
Just to update everyone, I found out the source of the problem: antivirus.
The real time file system protection was blocking R from copying the files
between folders once they were downloaded.
Upon adding the R directory to the exception list, the problem went away :)
(I updated my post with the
Dear All,
in the sources of robustbase, there appears a function called rPsort()
(say l253 of qn_sn.c). I could not find its source in the robustbase
package and a google search yields too many unrelated response.
Can anyone point to its source ?
thanks,
--
View this message in context:
On 19/04/11 21:30, barbara.r...@uniroma1.it wrote:
What is the function to have the entire part of a number?
[[alternative HTML version deleted]]
I'm not quite sure what you mean, but perhaps you want floor().
cheers,
Rolf Turner
On Mon, Apr 18, 2011 at 6:34 PM, new2R bv_agr...@yahoo.co.in wrote:
Hi,
I am new to R and trying to migrate from SAS. I am trying to use sqldf to
create a new table from existed table and change some of the columns. I have
table called DataOld with columns commodity, rate and total and I am
you could try something along these lines:
DF - data.frame(V1 = c(0, 0.9, , 0.8, 0.1, 0),
V2 = c(0.9, , 0.8, 0.7, , 1))
DF
sapply(DF, function (x)
as.numeric(gsub((^ +)|( +$), 0, x)))
I hope it helps.
Best,
Dimitris
On 4/19/2011 11:39 AM, Simone Gabbriellini wrote:
Hello List,
By the way, is there any difference between trunc() and floor()?
x - c(1.05, 1.95, 2.5, 3.51)
trunc(x)
[1] 1 1 2 3
floor(x)
[1] 1 1 2 3
identical(trunc(x), floor(x))
Ivan
Le 4/19/2011 11:46, Rolf Turner a écrit :
On 19/04/11 21:30, barbara.r...@uniroma1.it wrote:
What is the function to
On 04/19/2011 07:39 PM, Simone Gabbriellini wrote:
Hello List,
I have a data frame like:
V130V131V132V133V134V135V136
1 0 0 0.9 0 0.9
0 0
2 0 0
Dear folks,
I have been struggling to create what I fondly imagined would be a
straightforward adaptation of the package's example to my own dataset, which
looks at incidence of depression following the birth of initial and up to 3
subsequent children (4 children in all, with all subjects having
trunc(-1.5)
# [1] -1
floor(-1.5)
# [1] -2
Ted.
On 19-Apr-11 09:57:43, Ivan Calandra wrote:
By the way, is there any difference between trunc() and floor()?
x - c(1.05, 1.95, 2.5, 3.51)
trunc(x)
[1] 1 1 2 3
floor(x)
[1] 1 1 2 3
identical(trunc(x), floor(x))
Ivan
Le
Dear Allan,
thank you very much for your answer.
If I got it right your idea is
a: create first all the i,j combinations and then
b. use mclapply (parallel version of lapply).
so I wrote some draft and run three experiments:
# code
require('multicore')
sr-matrix(data=NA,ncol=256,nrow=256)
Make two assumptions:
(1) The initial state probability distribution (``ispd'') is *NOT* a
function of the
transition probability matrix (``tpm'').
(2) The boxes are stochastically independent of each other.
Both of these assumptions may be dubious. The second assumption is
the crucial
On 19/04/11 21:39, Simone Gabbriellini wrote:
Hello List,
I have a data frame like:
V130V131V132V133V134V135V136
1 0 0 0.9 0 0.9
0 0
2 0 0 0
Hi
r-help-boun...@r-project.org napsal dne 19.04.2011 12:02:31:
On 04/19/2011 07:39 PM, Simone Gabbriellini wrote:
Hello List,
I have a data frame like:
V130 V131 V132 V133 V134 V135 V136
1 0 0 0.9 0 0.9 0 0
2 0 0 0
Hi
r-help-boun...@r-project.org napsal dne 19.04.2011 09:46:47:
Dear R Users,
Lets assume I have this data frame:
x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04 7 0.1
4 1.06 9 0.4
x and y columns are sorted and the values not necessarily integers. z
values are not sorted. Now I
Dear Group,
I am doing an apply function on a zoo object. I need the rownames to
be passed to the function.
Any suggestions on how to accomplish this?
Here is the code I am using
tmp -
structure(c(611.55, 611.55, 611.55, 611.55, 611.55, 520, 520,
520, 520, 520, 425, 425, 425, 432.2, 432.2, 337,
On Apr 19, 2011, at 3:46 AM, Michael Bach wrote:
Dear R Users,
Lets assume I have this data frame:
x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04 7 0.1
4 1.06 9 0.4
x and y columns are sorted and the values not necessarily integers. z
values are not sorted. Now I would like to create a
On Tue, Apr 19, 2011 at 1:45 PM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 19/04/11 21:39, Simone Gabbriellini wrote:
Hello List,
I have a data frame like:
V130 V131 V132 V133 V134 V135 V136
1 0 0 0.9 0
0.9
On Apr 19, 2011, at 6:59 AM, santosh wrote:
Dear Group,
I am doing an apply function on a zoo object. I need the rownames to
be passed to the function.
Any suggestions on how to accomplish this?
Here is the code I am using
tmp -
structure(c(611.55, 611.55, 611.55, 611.55, 611.55, 520, 520,
Thanks David. Is there a way of explicitly passing the rowname since I
need it in the function.
On Apr 19, 4:19 pm, David Winsemius dwinsem...@comcast.net wrote:
On Apr 19, 2011, at 6:59 AM, santosh wrote:
Dear Group,
I am doing an apply function on a zoo object. I need the
Dear Deepayan,
Thank you for pointing out those functions. They will be helpful to me. If
you don't mind, I may get back to you on that topic if I cannot find a way
to apply them to my actual problem (the example I gave was just for
illustration). This problem is more complex and involves
On Tue, Apr 19, 2011 at 6:59 AM, santosh santosh.srini...@gmail.com wrote:
Dear Group,
I am doing an apply function on a zoo object. I need the rownames to
be passed to the function.
Any suggestions on how to accomplish this?
Here is the code I am using
tmp -
structure(c(611.55, 611.55,
This is probably very simple but I'm new to R so apologies for being stupid.
I have some data with No coded as 0 and yes coded as 1.
e.g.
id sex alcohol smoker
1 M 01
2 F 10
3 M 00
I realise I can covert the numerical variable back to a factor by
Hi,
I'm using the library MICE to make multiple imputations. I'can pool the
results to show how the predicted values fit, but how to combine the five
imputed datasets? I take the mean?
for exemple :
x1-complete(imp)
x2-complete(imp, 2)
x3-complete(imp, 3)
x4-complete(imp, 4)
x5-complete(imp,
Hello,
Is it possible to estimate prediction interval using GAM? I looked through
?gam, ?predict.gam etc and the mgcv.pdf Simon Wood. I found it can
calculate confidence interval but not clear if I can get it to calculate
prediction interval. I read Inference for GAMs is difficult and somewhat
Nice example, I forgot about negative numbers...
Thanks
Ivan
Le 4/19/2011 12:17, (Ted Harding) a écrit :
trunc(-1.5)
# [1] -1
floor(-1.5)
# [1] -2
Ted.
On 19-Apr-11 09:57:43, Ivan Calandra wrote:
By the way, is there any difference between trunc() and floor()?
x- c(1.05, 1.95,
Hello list members, i'd like to calculate the Moran I on a large dataset, a
8640x3432 grid of values.
When i try to create the neighbours list with the cell2nb function, on such
a scale, R works for several hours and seems to crash. I'm using the last
version (2.13), 64 bits, on a mac pro with
Hi,
I'm trying to fit a hidden Markov model (mixture of Gaussians) to stock prices
(Open, High, Low, Close) data.
Here's my code:
#First download the data with package TTR
library(TTR)
n - 200
data - getYahooData(GOOG, strftime(as.POSIXlt(Sys.time() -
n*24*3600),format=%Y%m%d))
keep -
Thanks.
On Tue, Apr 19, 2011 at 5:16 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Tue, Apr 19, 2011 at 6:59 AM, santosh santosh.srini...@gmail.com wrote:
Dear Group,
I am doing an apply function on a zoo object. I need the rownames to
be passed to the function.
Any suggestions
Dear R Users,
I'm wondering how is it possible to get |factor loadings| 1 in factor
analysis model (factanal) performing maximum-likelihood estimation. Is
it caused by some constraints? If so, what kind of constraints are
placed and when (during the estimation or after)?
Robert
one way is the following:
DF - data.frame(id = 1:6,
sex = gl(2, 3, labels = c(M, F)),
x = sample(0:1, 6, TRUE), y = sample(0:1, 6, TRUE),
z = rnorm(6))
f - function (x) {
if (all(unique(x) %in% 0:1))
factor(x, levels = 0:1, labels = c(No, Yes))
else
x
}
DF[]
On 18.04.2011 23:41, James Shaw wrote:
I am using robreg.evol (part of the RFreak package) to fit models via
least trimmed squares (LTS) regression and am encountering the
following error message when attempting to access the coefficients:
Error in fit1$coef : $ operator not defined for this
On Apr 19, 2011, at 10:57 , dereksloan wrote:
This is probably very simple but I'm new to R so apologies for being stupid.
I have some data with No coded as 0 and yes coded as 1.
e.g.
id sex alcohol smoker
1 M 01
2 F 10
3 M 00
I
David Winsemius dwinsem...@comcast.net writes:
Perhaps but only if the third row of your example was incorrectly constructed:
dta - rd.txt( x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04 7 0.1
4 1.06 9 0.4)
#rd.txt() is a combo fn of read.table and textConnection
mat - matrix(NA,
On 19.04.2011 05:19, Kevin Wright wrote:
For a package that I am creating, I have some files in the inst
directory. In the package man pages, I want to have R code that accesses
these files.
As of R-2.13.0, it looks like I can use any of: system.file() path.package()
find.package()
There
On 14.04.2011 14:37, suparna mitra wrote:
Hello,
I have a contingency table showing relation between two datasets. I tried
to see association among them with the assocplot, but it shows
error. mosaicplot of the same data worked perfectly.
Can anyone please help me.
Perhaps, given you
Petr PIKAL petr.pi...@precheza.cz writes:
Hi
r-help-boun...@r-project.org napsal dne 19.04.2011 09:46:47:
Dear R Users,
Lets assume I have this data frame:
x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04 7 0.1
4 1.06 9 0.4
x and y columns are sorted and the values not necessarily
This is an amazing website which would definitely have what you want,
probably in many ways.
*http://www.gapminder.org/*
There are a wealth of data sources, and the GUI is very intuitive and
interesting. I encourage you to view a few samples to get an idea of what
you can do with the
On Apr 19, 2011, at 13:58 , Robert Ruser wrote:
Dear R Users,
I'm wondering how is it possible to get |factor loadings| 1 in factor
analysis model (factanal) performing maximum-likelihood estimation. Is
it caused by some constraints? If so, what kind of constraints are
placed and when
On Apr 19, 2011, at 8:16 AM, Michael Bach wrote:
David Winsemius dwinsem...@comcast.net writes:
Perhaps but only if the third row of your example was incorrectly
constructed:
dta - rd.txt( x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04 7 0.1
4 1.06 9 0.4)
#rd.txt() is a combo fn of read.table
Inter ocular data
Quite amusing :)
Thank you for the help. For some reason I was thinking that I could get the
n values for the combined test, but that doesn't make sense as there could
be an infinite number of combinations of n values.
Thanks again for the replies.
--
View this message in
Hi
Michael Bach pha...@gmail.com napsal dne 19.04.2011 14:21:13:
Petr PIKAL petr.pi...@precheza.cz writes:
Hi
r-help-boun...@r-project.org napsal dne 19.04.2011 09:46:47:
Dear R Users,
Lets assume I have this data frame:
x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04
Just load the package and type
qvalue
so you will see what the underlying R code is. You will find some parts
of the code may be worth to be improved, hence time to contribute to the
package.
Uwe Ligges
On 19.04.2011 07:53, Chee Chen wrote:
Dear All,
In Storey's estimator of the
On Tue, 2011-04-19 at 03:14 -0400, Duncan Murdoch wrote:
On 11-04-18 9:51 PM, Matt Shotwell wrote:
Does anyone know if there is a simple way to print raw vectors, such
that ASCII characters are printed for bytes in the ASCII range, and
their hex representation otherwise? rawToChar doesn't
Thank you very much. Its working.
--
View this message in context:
http://r.789695.n4.nabble.com/SQLDF-syntax-tp3458919p3460448.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Dear Rxperts,
Below is a small sample of values (cut short due to space considerations
while posting).. I was wondering if it is possible to construct boundaries
(or intervals) based on the distribution of points. Is it anything similar
to boundary detection of distributions?
x1 -
Hello!
I've just build one-inflated beta regression model using package
GAMLSS. It all worked very nicely but now I want to make prediction
using it. I use typical function predict() give all necessary
arguments (my new data is in data frame and all relevant columns have
same names as before).
On Apr 19, 2011, at 8:43 AM, Schatzi wrote:
Inter ocular data
Quite amusing :)
Thank you for the help. For some reason I was thinking that I could get the
n values for the combined test, but that doesn't make sense as there could
be an infinite number of combinations of n values.
Thanks
On Apr 19, 2011, at 10:32 AM, Santosh wrote:
Dear Rxperts,
Below is a small sample of values (cut short due to space
considerations
while posting).. I was wondering if it is possible to construct
boundaries
(or intervals) based on the distribution of points. Is it anything
similar
to
An alternative that you may find interesting is the TkListView function in the
TeachingDemos package. This opens a separate window and shows the list
structure there with options for scrolling and expanding/collapsing sublists.
You will probably need to be a little patient while the display
Hi all, I generally use the Reduce() function to reduce the dimension of
list object. However in my current session I have few objects which are
actually list of list of list..(say n step). If I reduce their dimension
then I have call Reduce() function many times. Therefore my question is, is
Hi,
Would unlist() do what you want?
unlist(lis3)
[1] 4 1 8
HTH,
Ivan
Le 4/19/2011 17:32, Bogaso Christofer a écrit :
Hi all, I generally use the Reduce() function to reduce the dimension of
list object. However in my current session I have few objects which are
actually list of list of
David Winsemius dwinsem...@comcast.net writes:
On Apr 19, 2011, at 8:16 AM, Michael Bach wrote:
David Winsemius dwinsem...@comcast.net writes:
Perhaps but only if the third row of your example was incorrectly
constructed:
dta - rd.txt( x y z
1 1.00 5 0.5
2 1.02 5 0.7
3 1.04 7 0.1
Is it possible to estimate prediction interval using GAM? I looked
through ?gam,
- The easiest and most general way is by posterior simulation. Here's an
example...
## Prediction interval example for Gamma GAM
library(mgcv)
## simulate some data...
f - function(x) (0.2 * x^11 * (10 * (1
Hi together,
I found a solution to my problem that works for me and performs
reasonable well in my opinion. Instead of looping through both
datasets, I decided to replicate each row in d2 from Min_Month to
Max_Month and then use the match-function. Here is the code (I changed
the original example
On 2011-04-19 02:45, kv wrote:
Dear All,
in the sources of robustbase, there appears a function called rPsort()
(say l253 of qn_sn.c). I could not find its source in the robustbase
package and a google search yields too many unrelated response.
Can anyone point to its source ?
It's not in
Dr. Ligges:
Thank you for the prompt reply. I am sorry that I did not include my
code. I submitted my post as I was running to a meeting and did not
have time to provide more detail. Given the information you provided,
I was able to access the coefficient vector.
--
Jim
2011/4/19 Uwe Ligges
Dear all,
my colleagues and I have to write some R code for some of our projects.
I would like to ask you help to organize us a little.
a. Do you know if there is any system that can convert our R scripts to html
pages with some nice dependency graphs (which functions calls which).
b. Could you
Alex writes:
Dear all,
...
a. Do you know if there is any system that can convert our R scripts
to html pages with some nice dependency graphs (which functions calls
which).
b. Could you please suggest me an easy way to exchange the R code
with my colleagues. I know about these version
On Tue, Apr 19, 2011 at 6:20 PM, Alaios ala...@yahoo.com wrote:
b. Could you please suggest me an easy way to exchange the R code with my
colleagues. I know about these version systems but unfortunately they look
pretty bizarre to me.
Nothing looks more bizarre than a project that isn't
a. Check out Roxygen.
b. Use version control. You will not regret it.
Thanks,
Dale Smith, Ph.D.
Senior Financial Quantitative Analyst
Risk Compliance
Fiserv.
107 Technology Park
Norcross, GA 30092
Direct NYC: 212-419-3242
Mail: dale.sm...@fiserv.com
www.fiserv.com
-Original Message-
To keep the table dimensions the same, try changing the columns to factors...
boxes$y97-factor(boxes$y97, 1:4)
boxes$y98-factor(boxes$y98, 1:4)
boxes$y99-factor(boxes$y99, 1:4)
...
table(boxes$y98, boxes$y97)
1 2 3 4
1 1 0 1 0
2 0 0 0 0
3 0 0 0 0
4 1 0 0 1
table(boxes$y99,
Dear all,
I'm trying to plot, in the same window, two different series, using
barplot() for the first one and plot() for the second. What happens is that the
second chart has a different axes origin, therefore the final plot is wrong.
This piece of code shows the differences between the
If you don't need the web browser part then look at the tkexamp function in the
TeachingDemos package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org
What is Coredata(Z0)?
It would be very useful. as the posting guidelines suggest to supply working
code and sample data.
--- On Tue, 4/19/11, Barbaglia, Guido (ESA) guido.barbag...@fao.org wrote:
From: Barbaglia, Guido (ESA) guido.barbag...@fao.org
Subject: [R] Axes Alignment Problem for
Thank you very much Peter,
Best,
--
View this message in context:
http://r.789695.n4.nabble.com/Robustbase-source-question-tp3459966p3461263.html
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__
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Hello R Users!
I have a data frame that has many variables, some with missing observations,
and some that are correlated with each other. I would like to subset the data
by dropping one of the variables that is correlated with another variable that
I will keep int he data frame. Alternatively,
Hello,
I am not sure if I have done something wrong or something changed between
12.2.2 and 2.13.0, but I just installed R-2.13.0 from CRAN install
executable on 64 bit Windows 7 Pro and when I try HelpManuals (in
PDF)An Introduction to R I get the following
Error: 'doc\manual\R-intro.pdf'
On 19/04/2011 3:14 PM, apjawor...@mmm.com wrote:
Hello,
I am not sure if I have done something wrong or something changed between
12.2.2 and 2.13.0, but I just installed R-2.13.0 from CRAN install
executable on 64 bit Windows 7 Pro and when I try HelpManuals (in
PDF)An Introduction to R I get
Dear all
I have several files which claim to be *.csv (one attached, maybe it
will come through) . They can be read to Open Office without much
problem, however I can not read them into R. I tried
read.table(H2O.CSV, sep=,, dec=.)
V1
1 ˙ţ1
2
3
read.table(H2O.CSV, sep=,, dec=., skip=1)
Error
I am trying to convert a string to a vector, and I'm stuck!
Suppose you have a string of numbers (string) that you want to convert to a
vector (vec). I am able to split the string turning it into a list by using
strsplit, but this makes a list, which I can't seem to access the way that
I'd
Hello,
I've recently started using the rms package to fit some continuation ratio
models using cr.setup. The package runs beautifully and I'm getting good
fits with my data, however, I'm having trouble getting plots of the
predicted mean values of y in relation to predictor variables with
Dear guys,
I'm almost there... how can I fix the final problems?
Cheers,
Marius
PS: the info function is the one I will then try to call within splom...
library(lattice)
library(gridExtra)
## trial 1
info - function(a,b){
grid.table(as.expression(substitute(expression(alpha==alph,
On Apr 19, 2011, at 3:19 PM, Steven Wolf wrote:
I am trying to convert a string to a vector, and I'm stuck!
Suppose you have a string of numbers (string) that you want to
convert to a
vector (vec). I am able to split the string turning it into a list
by using
strsplit, but this makes a
Some might have noticed that REvolution Computing released the doSMP
package to the general public about a month and a half ago, which allows
multiple cores to be accessed for parallel computation in R. Some of our
physical habitat calculations were taking an extraordinary amount of time
to
On 19.04.2011 20:47, Petr Pikal wrote:
Dear all
I have several files which claim to be *.csv (one attached, maybe it
will come through).
Can you provide the file on some webspace or send it to me privately, I
will take a look tomorrow then.
Uwe Ligges
They can be read to Open Office
Not attached. You might succeed if you rename the file with a .txt
extension and re-post.
Almost surely an encoding issue. We may need your session Info to get
locale.
--
David
On Apr 19, 2011, at 2:47 PM, Petr Pikal wrote:
Dear all
I have several files which claim to be *.csv (one
I'm sorry for the way OT post, but here goes. I'm an informatics
specialist, and R user. My wife is a secondary school maths teacher.
The first place to look for this sort of information in the US is the
Statistical Abstract of the United States [which is, sadly, scheduled
to be a victim of
Ok, I can replicate your problem, with following code:
dat - 1:10
barplot(dat, beside=TRUE,ylim=c(0,100));
par()$usr;
par(new=T);
plot(dat, ylim=c(0,100), type=l);
par()$usr;
So it looks like even if you specify yourself ylim, the resulting
effective ylim (usr[3:4] ) will be
Hi,
This is always a challenge with expressions vs calls, etc. grid.table
expects an input that can be coerced into a matrix of unevaluated
expressions. This seems to work,
info - function(a,b){
grid.table(c(bquote(alpha==.(a)), bquote(beta==.(b))),
parse=TRUE, # parse labels as
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