Indeed, Indiana had a go at pi. Have a look here
http://en.wikipedia.org/wiki/Indiana_Pi_Bill
Dr. Iasonas Lamprianou
Department of Social and Political Sciences
University of Cyprus
[[alternative HTML version deleted]]
__
Dear Sir/ Madam,
I am trying to install R in my AIX-5.3 machine but its giving some error
during configuration as given below:
checking how to hardcode library paths into programs... immediate
checking for cos in -lm... yes
checking for sin in -lm... yes
checking for dlopen in -ldl... yes
http://r.789695.n4.nabble.com/file/n3567636/ecdfs.jpg ecdfs.jpg
http://r.789695.n4.nabble.com/file/n3567636/ecdf_curve.gif ecdf_curve.gif
Hello,
I have generated a plot of two empirical CDFs (attachment 1). As a result,
they are stepwise when plotted. The following code was used:
Thank you all,
tried all options and it gives me exactly what I needed! Many many thanks
again)
to Bert,
oh, I see, yes, next time I will do that.
Kristina
--
View this message in context:
http://r.789695.n4.nabble.com/subsetting-with-condition-tp3567193p3567645.html
Sent from the R help
Hello,
I am attempting to randomly select a data of equal length from my dataset.
My dataset is of equal length each ranging from 1 to 16 rows. Since they are
of equal length, I can form a matrix of equal length and rows or concatenate
them into a data of 16n x 2 matrix where n is number of
Dear R-listers,
I am fitting bivariate mixed models for cost-effectiveness data of cluster
randomized trials using lme in R. So I have individuals nested within
clusters. My response variable is a vector with bivariate response (individual
level costs and effects) stacked into a single
1) Please ask about R installation on the R-devel list: as the posting
guide says
Questions likely to prompt discussion unintelligible to
non-programmers should go to to R-devel.
2) This is covered quite explicitly in the 'R Installation and
Administration Manual'. Search for 'readline'
Dear all,
I have a few gaussian distributions with known (mean and sd). How can I plot
in R easily the cdf of them? In matlab there is a guid where you can give the
values and have the plots ready.
Is anything like that in R?
Best Regards
Alex
__
Well, that's a good question. It actually applies to many different contexts
(not just meta-analysis). Think of the ANOVA F-test and post-hoc/planned
contrasts. It's essentially the same situation. And if you would ask 10
different statisticians about this, you may get 11 different answers.
My
You can plot explicitly over a range of x; for example
x-seq(10, 15, 0.1)
#for mean 12.5, sd 0.6
plot(x, pnorm(x, 12.5, 0.6), type=l, ylim=c(0,1)
Or you can try the default plot for a univariate function (see ?curve)
plot(function(x) pnorm(x, 12.5, 0.6), xlim=c(10,15))
#Note use of the
You could try:
f - function(x){pnorm(x,mean=10,sd=20)}
curve(f,from=-10,to=30)
Or:
x - seq(-10,30,len=101)
y - pnorm(x,mean=10,sd=20)
plot(x,y,type=l)
--
Patrick Breheny
Assistant Professor
Department of Biostatistics
Department of Statistics
University of Kentucky
On 06/02/2011 07:05 AM,
What is wrong with lsa? You could contact author of that package if it is close
and discuss better options if no one here can help. your latest def just
reiterate summarization but that you want complrtr sentences. if you can site
specific algor or impl and go to a sig list may be more help
On 06/02/2011 02:18 AM, teriri wrote:
I have generated a plot of two empirical CDFs (attachment 1). As a
result, they are stepwise when plotted.
...
But what I need instead are smooth curves, similar to ones that are
generated from a theoretical cdf (attachment 2).
To obtain a smooth curve,
Error in lda.default(x, grouping, ...) :
variables 1 3 5 8 10 15 17 20 27 29 34 appear to be constant within groups
what this sentence means??
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
I have been browsing the pages about ggplot and it really doesn't deal with
such problems as far as I can see.
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
Hello to everyone
I have written a small c++ function of type double function(double,double);
and i want to export it in R using RCPP. After some trials i have realized
that the only way i could do it working is to declare the function as void
function (double x, double y, double result) and pass
János Korponai korponai.janos at nyuduvizig.hu writes:
Dear List!
I installed R and quite a few packages I use. When I try to start
BiodiversityR the library loads without any problems but GUI do not start.
Rcmdr loads without any problems. I am using R 2.13.0 64 bit.
Downgrade to R
Indeed, ylab position is not connected to the panel size / position.
You would have to place them manually...
## scaling factors on panels
h - c(5,3,4)
update(ABCur, ylab = list(c(AAA, BBB, CCC), rot=0,
y = (cumsum(h) - h/2) / sum(h) ))
Cheers
Felix
On 2 June 2011
Duarte Viana viana.sptd at gmail.com writes:
Hello all,
I am trying to do a Latin Hypercube Sampling (LHS) to a 5-parameter
design matrix. I start as follows:
library(lhs)
p1-randomLHS(1000, 5)
If I check the distribution of each parameter (column), they are
perfectly uniformly
Dear all,
I´m trying to get a output table for age and the summary of a and b, stratified
by epo as follows using summary.formula
h-data.frame(a=sample(c(A,NA),100,replace=T),b=sample(c(B,NA),100,replace=T),age=rnorm(100,50,25),epo=sample(c(Y,N),100,T))
library(rms)
I'm writing a function for ordinal regression for an ad hoc situation. To
estimate threshold parameters (4 levels), IÂ applied reparameterization
method to avoid using linear constraint suggested by C. Croux. This is
working fine, but I have a problem finding varaince for theÂ
I am not sure, but this thread from a couple of months ago might be relevant
(and useful):
https://stat.ethz.ch/pipermail/r-help/2011-March/273423.html
Ravi.
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] on behalf of
Rob Carnell
On Thu, Jun 02, 2011 at 09:56:51AM +0200, ogbos okike wrote:
Hello,
I am attempting to randomly select a data of equal length from my dataset.
My dataset is of equal length each ranging from 1 to 16 rows. Since they are
of equal length, I can form a matrix of equal length and rows or
Thanks Rob and Ravi for the replies.
Let me try to explain my problem. I am trying to make a kind of
sensitivity analysis where I have 5 parameters (the margins of the
Latin hypercube), 3 of them are proportions that should sum to one. My
idea is to obtain uniform combinations of the 3
I have 2 datafiles 'target' and 'observed' as shown below (I will gladly
email these 2 small files to whomever). X25. And X75. Indicate the
value of 25th and 75th-percentile of the target ('what should be') and
the observed ('what is'). The i.value is simply the month.
target
X
Hi,
Can someone tell me how to remove rows of zeros from a matrix?
For example if I have the following matrix,
0 0
0 1
2 8
0 0
4 56
I should end up with
0 1
2 8
4 56
--
Thanks,
Jim.
[[alternative HTML version deleted]]
__
On 2 June 2011 at 01:27, arvanitis wrote:
| I have written a small c++ function of type double function(double,double);
| and i want to export it in R using RCPP. After some trials i have realized
Rcpp uses the .Call() interface which imposes 'SEXP function(SEXP, SEXP, ...);
Please see 'Writing
Assuming the matrix is named X:
X[which(rowSums(X) 0),]
should work.
Also, this list is a text-only list. As you are using gmail, sending
text only messages is very easy, and may clear confusion in future
posts.
HTH,
Jon
On Thu, Jun 2, 2011 at 11:23 AM, Jim Silverton jim.silver...@gmail.com
On Thu, Jun 02, 2011 at 11:23:28AM -0400, Jim Silverton wrote:
Hi,
Can someone tell me how to remove rows of zeros from a matrix?
For example if I have the following matrix,
0 0
0 1
2 8
0 0
4 56
I should end up with
0 1
2 8
4 56
Hi.
Try the following
a - matrix(c(0, 0, 2, 0,
Dear R-experts,
Please, excuse me for disturbing... I tried to find the answer to my
question in archives without any result...
I assume, this is going to look like a stupid question... I have dataset of
different brain structures within two groups of subjects. But unfortunately
these groups are
Dear all,
I have a problem. I have m variables each of which has n observations. I want
to
calculate pairwise correlation among the m variables and store the values in a
m
x m matrix. It is extremely slow to use nested 'for' loops if m and n are
large.
Is there any efficient alternative to
On Jun 2, 2011, at 2:18 AM, teriri wrote:
http://r.789695.n4.nabble.com/file/n3567636/ecdfs.jpg ecdfs.jpg
http://r.789695.n4.nabble.com/file/n3567636/ecdf_curve.gif
ecdf_curve.gif
Hello,
I have generated a plot of two empirical CDFs (attachment 1). As a
result,
they are stepwise when
Hello list, and thank you in advance.
I'm unable to generate predicted values when specifying newdata using
phreg and aftreg models
in the eha package, but I do not have the same problem with a
proportional hazards model from coxph. Without the newdata argument
the predicted values are returned,
thank you so much for the very detailed indications which turned out to be a
real help in ponting me to the right direction;
referring back to my previous questions there is something still open:
2- I'm in trouble with the point labels because I would like to rotate them
by an angle of 90
Dear all...
I am looking for the zip file of an old version of the ARM package
compatible for R 2.10.1 version.
When I try to charge the ARM package I get the following message package
'arm' was built under R version 2.13.0 .
I can not update R to 2.13.0 as I always get this error the setup
Hi guys!
I'm new to R, but I was wondering if one could plot many histograms into a
single graph each having a different color. To make things clear:
Suppose you have a matrix of 100 rows and 10 columns. I'm interested in
plotting the histogram for each row, but it should not appear as bars but
Hi,
I used the package vars for my project but when the impulse response plots
were produced, some of the levels are out of the confidence band. I was
wondering what the problem is and also, does anyone know what type of
bootstrapping the package is using: is it parametric, case resampling,
I use package multicore, and it works very well. There is, however, one thing I
wonder if I don't do correctly, here is one example: I read ca 5.5 mill
records into a dataframe, using read.dta through a one-line function rdam1. It
runs nicely in parallel with other activitites.
p1 -
Hi list, based on the following data.frame I would like to create a variable
that indicates the number of occurrences of A in the 3 years prior to the
current year:
DF = data.frame(read.table(textConnection( A B
8025 1995
8026 1995
8029 1995
8026 1996
8025 1997
8026 1997
8025 1997
8027
To whom it may concern,
I am a new user to R and I need help in my if and for statements as I need a
place marker.
I would like to convert the following table:
Observation | Variable 1
|-
1 | 1
2 | A
3 | 631
Into :
Observation| Variable 1 | Variable 1 Flag
I have a data frame in R with the following values.
cars
autocar
cars info
what is that
donna drive
car
telephone
i need car...
I want to select all values which contain 'car', values with three
words, and those keywords with car that contain three words.
The first part is done with :
Hi:
Here's one approach using geom_ribbon() in ggplot2 - the 'overlap' is
the change in color where the two ribbons intersect. Using your
example data with the same names and the 'one.month' variable removed,
library(ggplot2)
ggplot() +
geom_ribbon(data = target, aes(x = i.value, ymin = X25,
?cor
Example:
dd - data.frame(x1 = rnorm(40), x2 = rnorm(40), x3 = runif(40, 0, 10))
'data.frame': 40 obs. of 3 variables:
$ x1: num -0.5585 1.3831 -1.7862 0.0572 0.2825 ...
$ x2: num -0.5247 -0.8636 -0.0749 0.2399 -0.1592 ...
$ x3: num 7.698 5.259 0.918 3.251 5.169 ...
cor(dd)
Duarte Viana viana.sptd at gmail.com writes:
Thanks Rob and Ravi for the replies.
Let me try to explain my problem. I am trying to make a kind of
sensitivity analysis where I have 5 parameters (the margins of the
Latin hypercube), 3 of them are proportions that should sum to one. My
idea
Thanks for the quick reply,
I understand that the predict(zip1A, type = response) command is computing
the fitted_means and these are different than the probabilities
predict(zip1A, type = prob). Although, according to Martin (2005), the
highest probabilities do not simply lead to the true count
Hello,
following problem:
i have a written my own function to draw some sophisticated graphic,
which after manipulating data somewhere contains a plot comand
function - function(x) {
...
plot(xy)
}
to tidy up my final graphs, it would be very handy to be able forward
all low-level graphic
Hello,
three commands might do the job (NOTE: df=your data frame,
obser=Observation, var1=Variable 1 [TYPE: string], var1flag=Variable 1
flag [TYPE: string])
1. df$var1flag-NA
2. df$var1flag[ is.na(as.numeric(df$var1)) ]-df$var1[
is.na(as.numeric(df$var1)) ]
3. df$var1-as.numeric(df$var1)
Hi,
this is my R-script
I need to make a confusion matrix
but the last row return me an error
require(mixOmics)
require(SDMTools)
file - C:\\data.txt
d - read.table(file, header=T, row.names = NULL)
X - as.matrix(d[,2:11])
Y - as.factor(d[,1])
i - 1
samp - sample(1:3, nrow(X), replace = TRUE)
I would recommend trying to fix the installation of R 2.13.0 rather
than trying to obtain old packages. Try downloading the installer
again from a different mirror.
On Thu, Jun 2, 2011 at 10:33 AM, jmdpulido jmdpul...@yahoo.es wrote:
Dear all...
I am looking for the zip file of an old version
try using `...`
function - function(x, ...) {
#do stuff
plot(xy, ...)
}
On Thu, Jun 2, 2011 at 1:26 PM, eldor ado rat.c...@gmail.com wrote:
Hello,
following problem:
i have a written my own function to draw some sophisticated graphic,
which after manipulating data somewhere contains a
Thanks Prof. Ripley and Duncan for your pointers. Noting down your
points I have modified my way of building package and have done
following so far:
1. In my C: drive I create one working folder naming R_PackageBuild
2. In R console I have written following codes:
setwd(c:/R_packageBuild)
On Thu, 2 Jun 2011, Jonathan Daily wrote:
I would recommend trying to fix the installation of R 2.13.0 rather
than trying to obtain old packages. Try downloading the installer
again from a different mirror.
He has already been given help (3x) to that effect. People who fail
to acknowledege
Thanks again Rob for your help.
In terms of parameter comparison there won't be a problem. However, if
one wants to assume a particular distribution (and not the one given
by the imposed condition), for example an uniform distribution to
obtain all the possible combinations (all the
On 02/06/2011 2:03 PM, Nipesh Bajaj wrote:
Thanks Prof. Ripley and Duncan for your pointers. Noting down your
points I have modified my way of building package and have done
following so far:
1. In my C: drive I create one working folder naming R_PackageBuild
2. In R console I have written
What else I need to do? In the Read-and-delete-me file following steps
are asked to perform:
* Edit the help file skeletons in 'man', possibly combining help files
for multiple functions.
* Edit the exports in 'NAMESPACE', and add necessary imports.
* Put any C/C++/Fortran code in 'src'.
* If you
On Jun 2, 2011, at 11:04 AM, Sakti wrote:
Hi guys!
I'm new to R, but I was wondering if one could plot many histograms
into a
single graph each having a different color. To make things clear:
Suppose you have a matrix of 100 rows and 10 columns. I'm interested
in
plotting the histogram
Dear all,
I have a vector of expressions and would like to paste some string to it
before using it in a plot:
vars - vector(expression, 2)
vars[1] - expression(alpha)
vars[2] - expression(beta)
plot(0, 0, main=substitute(bold(Foo ~~ VAR), list(VAR=vars[2]) ))
Although I tried hard, I just
Greetings to all,
I have a similar issue with Snowball.
I am runing R version 2.12.1 (2010-12-16) on windows 7
Here is my script :
library(tm)
custom.xml - system.file(texts, custom.xml, package = tm)
print(readLines(custom.xml), quote = FALSE)
myXMLReader - readXML(
spec =
Hi!
I am very new to R, I hope someone can help me.
I have two dataframes:
data1-data.frame(from=c(1,12,16,40,55,81,101),to=c(10,13,23,45,67,99,123))
data2-data.frame(name=c(1,2,3,4,5,6,7,8,9),position=c(2,14,20,50,150,2000,2001,2002,85))
I want to know which of the entries in position of
Hi,
First of all, I would like to introduce myself as I will probably have many
questions over the next few weeks and want to thank you guys in advance for
your help. I'm a cancer researcher and I need to learn R to complete a few
projects. I have an introductory background in Python.
My
You did not read the help files carefully enough.
The Help for panel.text tells you that it is the same function as
ltext. ltext lists a bunch of parameters, srt among them, and refers
you to the corresponding base R graphics function, which is text().
?text then refers you to par for this and
Hi,
eset is an expressionset based on hgu133plus2 platform.
Using hgu133plus2.db package, I want to map probes to UniGene cluster IDs.
It results in an error message.
xx=hgu133plus2UNIGENE
uniaf1=xx[[as.character(featureNames(eset))]]
Error in .checkKeys(value, Lkeys(x), x@ifnotfound) :
I have run R CMD check trial1 and saw an error. This says that:
* checking pdf version of manual without hyperrefs or index ... ERROR
Re-running with no redirection of stdout/stderr.
Hmm... looks like a package
Error in texi2dvi(Rd2.tex, pdf = (out_ext == pdf), quiet = FALSE, :
pdflatex is not
On Jun 2, 2011, at 2:54 PM, Ben Ganzfried wrote:
Hi,
First of all, I would like to introduce myself as I will probably
have many
questions over the next few weeks and want to thank you guys in
advance for
your help. I'm a cancer researcher and I need to learn R to
complete a few
Doesn't deal with what problems?
Hadley
On Thursday, June 2, 2011, rmje robinmje...@gmail.com wrote:
I have been browsing the pages about ggplot and it really doesn't deal with
such problems as far as I can see.
--
View this message in context:
Hello R people,
I am looking to pay someone to help write some R code.
Inputs:
Study identifier: ID Number for the study, each ID number is for one study
only each block set should only be used for that study. This will require
that you store the results from the blocks someplace on the
Dear all,
do you know any easy way based on a vector input how to plot easily cdf and pdf.
I would like to thank you in advance for your help
Regards
Alex
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Greetings
Grateful for any help on this one:
In the following demo code, I am trying to get the points in the line to
appear over the same x-axis labels as are used by the paired Bars. It
appears, however, that R/lattice ignores the x-axis points used by the bars
and plots the x points
On 02.06.2011 20:43, Marius Hofert wrote:
Dear all,
I have a vector of expressions and would like to paste some string to it
before using it in a plot:
vars- vector(expression, 2)
vars[1]- expression(alpha)
vars[2]- expression(beta)
plot(0, 0, main=substitute(bold(Foo ~~ VAR),
The rms package includes the nomogram function, which generates a list
object that can be passed to plot for graphical production of nomograms.
I would like to remove the linear predictor line in the graph, which
means (I suspect) removing it from the nomogram output object. I've
looked at
Dear Uwe,
thanks for your help. Actually, I first thought about writing your solution in
the email in order to make clear that it is not the solution I'm looking for
:-) My goal is to work with the vector vars of expressions. The example is
only a minimal example and for that your solution is
Thank you very much for your help. It saved me a lot of time and it worked
perfectly. I have a quick follow-up as I'm not sure I understand yet why
the code works and where it comes from.
For example, in: Tstg - sub(.*T(\\d)N., \\1, tmp)
*How exactly does the substitution operation work?
*On
Hi:
This seems to work:
vars2 - c(quote(alpha), quote(beta)) # returns a list of mode call
plot(0, 0, main = bquote(bold('Foo '~.(vars2[[2]]
Expressions are only evaluated once, which means that inner
expressions are not evaluated. You need a call object rather than an
expression inside
On Jun 2, 2011, at 4:21 PM, Ben Ganzfried wrote:
Thank you very much for your help. It saved me a lot of time and it
worked perfectly. I have a quick follow-up as I'm not sure I
understand yet why the code works and where it comes from.
For example, in: Tstg - sub(.*T(\\d)N., \\1,
Dear Rxperts!
Below are relevant lines of code, I am having problems with.. I am not sure
if it is a bug in R or OS related or something else...
When viewing the pdf file, I notice overlaid plots in a panel of the plot
are shifted to the right. The Y-axes and X-labels are not exactly on top of
On Jun 2, 2011, at 4:19 PM, Marius Hofert wrote:
Dear Uwe,
thanks for your help. Actually, I first thought about writing your
solution in the email in order to make clear that it is not the
solution I'm looking for :-) My goal is to work with the vector
vars of expressions. The example
On Jun 2, 2011, at 2:41 PM, Hess, Michael wrote:
Hello R people,
I am looking to pay someone to help write some R code.
Inputs:
Study identifier: ID Number for the study, each ID number is for one study
only each block set should only be used for that study. This will require
that
The documentation includes this: nomogram(fit, ..., lp=FALSE)
Frank
Rob James-2 wrote:
The rms package includes the nomogram function, which generates a list
object that can be passed to plot for graphical production of nomograms.
I would like to remove the linear predictor line in the
On Jun 2, 2011, at 4:19 PM, Rob James wrote:
The rms package includes the nomogram function, which generates a
list object that can be passed to plot for graphical production of
nomograms.
I would like to remove the linear predictor line in the graph,
which means (I suspect) removing
(1) For crying out loud don't muck about with par(new=TRUE)
like that. Use points() and lines() (and other plot functions) to
add graphical constructs to existing plots. (And use TRUE
not T --- it's a lot safer.)
(2) In general for shading in regions between two lines
on a plot, use
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my script
I use break long lines to avoid lines hiden on my monitor and in sweave
document pages. I use graphics like this
plot(1, main=
)
but I would like a plot
Dear Dennis, Dear Uwe, Dear David,
many thanks for helping. Dennis and David, your solutions seemed perfectly
fine, but when I applied it to my original problem, it did not show a title.
Below is a (longer) minimal example (the first part is from the help page of
bbmle). Is this a bug in
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Marius Hofert
Sent: Thursday, June 02, 2011 1:20 PM
To: Uwe Ligges
Cc: Help R
Subject: Re: [R] plotmath: paste string and expression [from
a vectorof expressions]
Dear Uwe,
I hope you're successful because I'm having issues as well building a simple
package on
windows. maybe when you're finished you can share back a step by step
guide.
On Thu, Jun 2, 2011 at 12:21 PM, Nipesh Bajaj bajaj141...@gmail.com wrote:
I have run R CMD check trial1 and saw an error. This
On Jun 2, 2011, at 1:42 PM, Filippo Beleggia wrote:
Hi!
I am very new to R, I hope someone can help me.
I have two dataframes:
data1-data.frame(from=c(1,12,16,40,55,81,101),to=c(10,13,23,45,67,99,123))
Still I am struggling to get some inputs from the experts here :(
Definitely We can shere our experiences once I am done (really, it
seems to me very hard nut to crack!) I strongly feel that related
documentations should be more Statistician-friendly, than some Engg.
guys
Thanks,
On Fri, Jun 3,
On 03/06/11 09:03, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my script
I use break long lines to avoid lines hiden on my monitor and in sweave
document pages. I use graphics like this
plot(1, main=
I don't use windows, but this error message you report:
Error in texi2dvi(Rd2.tex, pdf = (out_ext == pdf), quiet = FALSE, :
pdflatex is not available
Error in running tools:: texi2dvi
strongly indicates that you need to install pdflatex, don't you think?
If you don't have non-R code (c or
On Thu, Jun 2, 2011 at 3:13 PM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 03/06/11 09:03, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my
script
I use break long lines to avoid lines hiden on my monitor and in sweave
document pages.
On Jun 2, 2011, at 5:07 PM, Marius Hofert wrote:
Dear Dennis, Dear Uwe, Dear David,
many thanks for helping. Dennis and David, your solutions seemed
perfectly fine, but when I applied it to my original problem, it did
not show a title. Below is a (longer) minimal example (the first
part
On Jun 2, 2011, at 6:13 PM, Rolf Turner wrote:
On 03/06/11 09:03, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I
my script
I use break long lines to avoid lines hiden on my monitor and in
sweave
document pages. I use graphics like
Dear all,
How can I get a bold 1000 in the title? I would like to use a variable (as
opposed to putting in 1000 directly).
library(lattice)
N - 1000
xyplot(0~0, xlab.top=list(label=as.expression(bquote(bold(foo ~ .(N) ~
bar))), font=2, cex=1.2))
## = font=2 is ignored (of course)
Cheers,
On 2011-06-02 15:50, Marius Hofert wrote:
Dear all,
How can I get a bold 1000 in the title? I would like to use a variable (as opposed to
putting in 1000 directly).
library(lattice)
N- 1000
xyplot(0~0, xlab.top=list(label=as.expression(bquote(bold(foo ~ .(N) ~
bar))), font=2, cex=1.2))
## =
Hi,
On Thu, Jun 2, 2011 at 11:30 AM, Nipesh Bajaj bajaj141...@gmail.com wrote:
I editied the help page for fn1() function (as I already communicated
in previous mail) as follows:
\name{fn1}
\alias{fn1}
\title{
A function.
}
\description{
A function.
}
\usage{
A function.
What
On 03/06/11 10:16, Peter Langfelder wrote:
On Thu, Jun 2, 2011 at 3:13 PM, Rolf Turnerrolf.tur...@xtra.co.nz wrote:
On 03/06/11 09:03, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my
script
I use break long lines to avoid lines hiden on
Absolutely not! Did you *read* the OP's question? He wants to break
the line in the code --- for readable code presumably --- but ***not***
in the output! Your advice is the antithesis of what is required.
cheers,
Rolf Turner
I stand corrected, indeed I missed the crucial
On 03/06/11 11:33, Joshua Wiley wrote:
Hi,
On Thu, Jun 2, 2011 at 11:30 AM, Nipesh Bajajbajaj141...@gmail.com wrote:
I editied the help page for fn1() function (as I already communicated
in previous mail) as follows:
\name{fn1}
\alias{fn1}
\title{
A function.
}
\description{
A function.
}
On Thu, Jun 2, 2011 at 4:49 PM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 03/06/11 11:33, Joshua Wiley wrote:
Hi,
On Thu, Jun 2, 2011 at 11:30 AM, Nipesh Bajajbajaj141...@gmail.com
wrote:
I editied the help page for fn1() function (as I already communicated
in previous mail) as
Okay, that might have been a little strong. screams bloody murder
is a warning, not technically an error, and does not occur when simply
running R CMD build. That said, the OP did mention using R CMD check
and pdflatex is not an issue when only building anyway. Still, it is
not the cause of the
On 03/06/11 12:16, Joshua Wiley wrote:
Okay, that might have been a little strong. screams bloody murder
is a warning, not technically an error, and does not occur when simply
running R CMD build. That said, the OP did mention using R CMD check
and pdflatex is not an issue when only building
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