Jonathan Greenberg wrote:
>
> The problem is that I'm trying to create a path to use with a system()
> call, and the command window will not work with the forward slash,
> only with the standard backslash. I do understand that within R it
> will work with either way, but not via the system call.
(a) Most likely you need GNU make: what are you using? (See the 'R
Installation and Administration' manual.) This does not look like
normal GNU make (which does not call itself 'Make').
(b) R-devel is the list for such questions: see the posting guide.
On Tue, 28 Jun 2011, Zhou, Hong wrote:
The problem is that I'm trying to create a path to use with a system()
call, and the command window will not work with the forward slash,
only with the standard backslash. I do understand that within R it
will work with either way, but not via the system call. I'm trying to
create a "generic" sys
Windows will work with either separator.
---
Jeff Newmiller The . . Go Live...
DCN: Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with
/Software/Embedded C
(1) You really ought to do your own homework.
(2) What has this to do with R?
cheers,
Rolf Turner
On 29/06/11 14:03, Lisa wrote:
Dear all,
I just want to get the derivative of a function that looks like:
y = exp(x1*b) / (exp(x1*b) + exp(x2*b))
where y is a scalar, x1, x2, and
Thanks Henrik, but as the help for this function states:
Note
The components are separated by / (not \) on Windows.
, the slashes it uses are incorrect for use in a CMD window on a
Windows box (they need to be \ but file.path uses /). I suppose I can
do a query as to whether the platform is Wind
Dear all,
I just want to get the derivative of a function that looks like:
y = exp(x1*b) / (exp(x1*b) + exp(x2*b))
where y is a scalar, x1, x2, and b are vectors. I am going to take the
derivative of b with respect to y, but I cannot derive an expression in
which b is function of y. I know there
Problem solved. I lazily forgot to clean up my workspace with rm(list=ls()).
A good reminder to do so after each exit. Sorry for the wasted server space.
From: tyler_rin...@hotmail.com
To: r-help@r-project.org
Date: Tue, 28 Jun 2011 22:58:47 -0400
Subject: Re: [R] library(doBy) will not loa
This is the error I get when I try to load snow.
> library(snow)
Error in as.character(t) : 't' is missing
Error in library(snow) : .First.lib failed for snow
From: tyler_rin...@hotmail.com
To: r-help@r-project.org
Date: Tue, 28 Jun 2011 22:47:06 -0400
Subject: [R] library(doBy) will not lo
Greetings R Community,
One of my favorite packages won't load and I'm not sure why. It loaded earlier
today. The problem appears with the snow package, which doBy requires. I tried
reinstalling both packages again ,shutting [R] down, reinstalling [R] in the
workspace (shortcut). Here's the
On 24/06/11 01:44, Adriana Bejarano wrote:
Dear R gurus,
I have the following code, but I still not know how to estimate and extract
confidence intervals (95%CI) from resampling.
Some sound advice --- still sound after all these years I believe --- in
respect
of boot strap confidence inter
You can specify the weights=... argument in the lm() function as vector of
weights, one for each observation. Should that not do what your are trying
to do?
HTH,
Daniel
--
View this message in context:
http://r.789695.n4.nabble.com/a-Weighted-Least-Square-Model-for-a-Binary-Outcome-tp3631551p363
Thanks, that worked like a charm.
Daisy
On Wed, Jun 29, 2011 at 11:47 AM, David Winsemius
wrote:
>
> On Jun 28, 2011, at 9:18 PM, Daisy Englert Duursma wrote:
>
>> Hello,
>>
>> I think this is a simple problem but I am not coming up with a simple
>> solution. I think it just an indexing problem.
See file.path().
/Henrik
On Tue, Jun 28, 2011 at 6:59 PM, Jonathan Greenberg
wrote:
> Hopefully this is a pretty easy fix -- I need to have R query the path
> separator for some code I'm trying to write (it involves using a
> system() call) -- the call requires a path and a wildcard, e.g.:
>
> c
Hopefully this is a pretty easy fix -- I need to have R query the path
separator for some code I'm trying to write (it involves using a
system() call) -- the call requires a path and a wildcard, e.g.:
command="mycommand /path/to/*.files" in the case of unix or,
command="mycommand.exe C:\\path\\to\
A) Relying on floating point numbers for predictable indexing is a recipe for
failure. Convert your floating point numbers to integers before using them to
index.
B) Row and column labels are strings, and you are giving numerics to the
brackets. You would need to use as.character() on ddr$x and
On Jun 28, 2011, at 9:18 PM, Daisy Englert Duursma wrote:
Hello,
I think this is a simple problem but I am not coming up with a simple
solution. I think it just an indexing problem.
I can easily replace values in a matrix from a dataframe when the
dataframe has row and column numbers. In the
Hello,
I think this is a simple problem but I am not coming up with a simple
solution. I think it just an indexing problem.
I can easily replace values in a matrix from a dataframe when the
dataframe has row and column numbers. In the example below I use row
and column names and I can not get it
Hello,
I think this is a simple problem but I am not coming up with a simple
solution. I think it just an indexing problem.
I can easily replace values in a matrix from a dataframe when the
dataframe has row and column numbers. In the example below I use row
and column names and I can not get it
Excellent, thanks.
On 28 June 2011 16:36, jim holtman wrote:
> forgot to sent the sapply solution:
>
>> sapply(x, '[', 3)
> Median Median Median Median Median Median Median Median Median Median
> Median Median Median Median Median Median
> 0.4769 0.4880 0.4916 0.4021 0.4474 0.4449 0.5169 0.5067 0
Assuming that your column are numeric, you would need 4GB of memory
just to store one copy of the object. If this is 5 years, then you
would need almost 1GB for a copy, but the processing probably will use
up twice as much as it is processing. Try reading a month's worth and
see how much you use.
forgot to sent the sapply solution:
> sapply(x, '[', 3)
Median Median Median Median Median Median Median Median Median Median
Median Median Median Median Median Median
0.4769 0.4880 0.4916 0.4021 0.4474 0.4449 0.5169 0.5067 0.5189 0.4088
0.4887 0.5392 0.4964 0.4141 0.5155 0.4461
Median Median Medi
single brackets:
> x <- as.list(100)
> for(loop in c(1:100)) {
+ x[[loop]] <- summary(runif(100))
+ }
> x[[1]][1]
Min.
0.007595
> x[[1]][3]
Median
0.4769
>
On Tue, Jun 28, 2011 at 7:22 PM, Jeremy Miles wrote:
> Hi All,
>
> I want to extract elements of elements in a list.
>
> x <- lapply(1:100, function(x) summary(runif(100)))
> head(x, 4)
[[1]]
Min. 1st Qu. MedianMean 3rd Qu.Max.
0.02922 0.38330 0.58120 0.58230 0.83430 0.99870
[[2]]
Min. 1st Qu. Median Mean 3rd Qu. Max.
0.004903 0.281400 0.478900 0.497100 0.729900 0.990700
[[3]]
Hi All,
I want to extract elements of elements in a list.
Here's an example of what I mean:
If I create a list:
x <- as.list(100)
for(loop in c(1:100)) {
x[[loop]] <- summary(runif(100))
}
> head(x)
[[1]]
Min. 1st Qu. MedianMean 3rd Qu.Max.
0.02271 0.25260 0.58130
On Wed, Jun 29, 2011 at 1:51 AM, Robert Baer wrote:
> Subject: Re: [R] Running R from windows command prompt
>
> ---
> Actually, you can 'cut and paste' from at Windows Cmd prompt. It is done by
> clicking the
> C: icon in the upper left of the command window, choosing edit, and
On Jun 28, 2011, at 6:26 PM, David Winsemius wrote:
On Jun 28, 2011, at 5:46 PM, Trey Batey wrote:
Hello.
I am trying to write an R function to plot the survival function (and
associated hazard and density) for a Siler competing hazards model.
This model is similar to the Gompertz-Makeham,
On Jun 28, 2011, at 5:46 PM, Trey Batey wrote:
Hello.
I am trying to write an R function to plot the survival function (and
associated hazard and density) for a Siler competing hazards model.
This model is similar to the Gompertz-Makeham, with the addition of a
juvenile component that includes
Hello.
I am trying to write an R function to plot the survival function (and
associated hazard and density) for a Siler competing hazards model.
This model is similar to the Gompertz-Makeham, with the addition of a
juvenile component that includes two parameters---one that describes
the initial in
Dear R Users,
I am new to the mailing list. I posted this message about two hours
ago but did not receive it through the list, so I am posting it again.
Sorry for duplicates.
I would like to use R to fit a Weighted Least Square model for a
binary outcome, say Y. The model is the one widely used
I use RODBC and have got it to work fine on Windows, Linux and Mac.
There's some basic info here, and plenty of blog posts out there with
step by step instructions for the different OS's.
http://hosho.ees.hokudai.ac.jp/~kubo/Rdoc/library/RODBC/html/00Index.html
On Tue, Jun 28, 2011 at 11:53 PM
On 11-06-28 4:22 PM, David Kaplan wrote:
Greetings,
I'm getting this error message using Joe Shafer's "NORM" package.
Error in storage.mode(x)<- "double" :
(list) object cannot be coerced to type 'double'
I'm not sure what this means.
It means just what it says, but fixing it is another
MAny Thanks¡¡¡
2011/6/28 jim holtman
> try this:
>
> > x <- read.fwf(textConnection("188556644
> + 225588666
> + 55555"), width = rep(1,9))
> >
> > x
> V1 V2 V3 V4 V5 V6 V7 V8 V9
> 1 1 8 8 5 5 6 6 4 4
> 2 2 2 5 5 8 8 6 6 6
> 3 5 5 8 8 8 8 5 5 5
> >
>
>
> On Tue,
Thank you Jholtman.
Now count is 46001902. I was trying to retrieve one-year data, but I still
receive the following message:
"Error: cannot allocate vector of size 64.0 Mb"
--
View this message in context:
http://r.789695.n4.nabble.com/Error-cannot-allocate-vector-of-size-tp3629384p3631354.html
On Jun 28, 2011, at 4:53 PM, David Winsemius wrote:
On Jun 28, 2011, at 3:59 PM, Daniel Malter wrote:
Hi all,
I have two numeric variables that form combinations in a matched
sample.
Let's say I have five levels of x and y. What I am seeking to
create is a
factor variable that ignores t
On Jun 28, 2011, at 3:59 PM, Daniel Malter wrote:
Hi all,
I have two numeric variables that form combinations in a matched
sample.
Let's say I have five levels of x and y. What I am seeking to create
is a
factor variable that ignores the order of x and y, i.e., the factor
should
indicate
Greetings,
I'm getting this error message using Joe Shafer's "NORM" package.
Error in storage.mode(x) <- "double" :
(list) object cannot be coerced to type 'double'
I'm not sure what this means.
I get this message when running
s <- prelim.norm(filename)
prelim.norm is used to develop so
select count(*) from yourData
On Tue, Jun 28, 2011 at 3:07 PM, xin123620 wrote:
> Thank you Jeff. You are absolutely right. I just edited the R and computer
> info in: R is 32 bit; computer is his computer is Windows XP, 32bit Intel(R)
> Core(TM) e8...@3.ghz, 2.99GHz, 2.95GB of RAM.
>
> The data
try this:
> x <- read.fwf(textConnection("188556644
+ 225588666
+ 55555"), width = rep(1,9))
>
> x
V1 V2 V3 V4 V5 V6 V7 V8 V9
1 1 8 8 5 5 6 6 4 4
2 2 2 5 5 8 8 6 6 6
3 5 5 8 8 8 8 5 5 5
>
On Tue, Jun 28, 2011 at 3:47 PM, Trying To learn again
wrote:
> Hi all,
>
Hi all,
I have two numeric variables that form combinations in a matched sample.
Let's say I have five levels of x and y. What I am seeking to create is a
factor variable that ignores the order of x and y, i.e., the factor should
indicate x=1, y=5, as the same factor as x=5, y=1. Obviously, this b
On Jun 28, 2011, at 3:56 PM, David Winsemius wrote:
On Jun 28, 2011, at 3:47 PM, Trying To learn again wrote:
Hi all,
I have a matrix like this:
188556644
225588666
55555
I try to read the table using read table but if I put sep="" I have
seen it
expects a white space, is there a "s
On Jun 28, 2011, at 3:47 PM, Trying To learn again wrote:
Hi all,
I have a matrix like this:
188556644
225588666
55555
I try to read the table using read table but if I put sep="" I have
seen it
expects a white space, is there a "sep" option to read this matrix so
each single number
Trying To learn again gmail.com> writes:
> 188556644
> 225588666
> 55555
>
> I try to read the table using read table but if I put sep="" I have seen it
> expects a white space, is there a "sep" option to read this matrix so
> each single number is a position of the matrix
?read.fwf, I
Hi all,
I have a matrix like this:
188556644
225588666
55555
I try to read the table using read table but if I put sep="" I have seen it
expects a white space, is there a "sep" option to read this matrix so
each single number is a position of the matrix
You see this matrix would be an 3x9
Hi all,
I would like to parallelize some R code and would like to use the 'foreach'
package with a foreach loop. However, whenever I call a function from an
enabled package outside of MASS, I get an error message that a number of the
functions aren't recognized (even though the functions should be
Thank you Jeff. You are absolutely right. I just edited the R and computer
info in: R is 32 bit; computer is his computer is Windows XP, 32bit Intel(R)
Core(TM) e8...@3.ghz, 2.99GHz, 2.95GB of RAM.
The data I am trying to retrieve is through postgre from a university
server. I checked the postgre
> for (i in 1:(dat[(unique(dat$Subject)),)]
I don't think the order of the parentheses when you open the loop is
correct. You have four (s and only three )s. Plus the brackets (square
parentheses) seem so be out of order too.
If you use RStudio to write your code, when you highlight a parenthe
Dear list members,
I am estimating an ordinal generalized estimating equations (GEE) regression
model on repeated measurements data.
Is there any way (preferably in R) to test the proportional odds assumption of
this model?
Thanks in advance.
Andreas
Dear R Users,
I would like to use R to fit a Weighted Least Square model for a
binary outcome, say Y. The model is the one widely used for a binary
dependent variable when the logistic model has not been proposed.
Does anyone know how to specify the weight as the square root of
1/(E(Y)(1-E(Y)) i
I have a data frame in which missing values exist, and I need to
recode the string "missing" to a missing value. For the example, let's
assume I cannot do this while reading it in. Even though this has been
discussed extensively, I'm still a little confused about when to index
with "which" and when
Thank you again David for the thoughtful comments on plotmath. Really
appreciated.
John
- Original Message
From: David Winsemius
To: array chip
Cc: Peter Ehlers ; R
Sent: Tue, June 28, 2011 12:20:49 PM
Subject: Re: [R] how to print "<=" in plot title
On Jun 28, 2011, at 2:52 PM,
On Jun 28, 2011, at 2:51 PM, Edward Patzelt wrote:
Huh, not sure I understand your feedback. There is only 1 file that
is 1
large dataframe. I want to execute the commands on each subject in
the
dataframe and ouput their respective files with the subject # and
file type
appended (10_gre
Zhou, Hong email.chop.edu> writes:
> ./configure was run successfully on my HP-UX ia64 server with exit=0,
> but when type make at prompt, get this
> error "Make: Don't know how to make #. Stop." Does anyone has
> any clues about this message? Thank you very much!
> #make
> Rmath.h is unchang
On Jun 28, 2011, at 2:52 PM, array chip wrote:
Thank you David for the obvious fix and sorry for my lacking
innovative spirit,
:-)
Really, I know I haven't grasped the essence of plotting these math
symbols in
R.
A lot of people (including me) have had trouble understanding to to
writ
On 2011-06-28 00:12, Louis Plough wrote:
Hi,
I have binary (0,1) data for a trait as my response variable, and
a dependent variable, genotype, with three classes (AA, AB, BB).
I would like to plot this data so that across the three genoytpes, even
though the points are all either 0 or 1, i want
Thank you David for the obvious fix and sorry for my lacking innovative spirit,
:-)
Really, I know I haven't grasped the essence of plotting these math symbols in
R.
John
- Original Message
From: David Winsemius
To: array chip
Cc: Peter Ehlers ; R
Sent: Tue, June 28, 2011 11:50:0
Huh, not sure I understand your feedback. There is only 1 file that is 1
large dataframe. I want to execute the commands on each subject in the
dataframe and ouput their respective files with the subject # and file type
appended (10_green.txt).
How would I do this loop index?
- Show quoted text
On Jun 28, 2011, at 2:42 PM, array chip wrote:
David,
I tried your suggestion, still not working:
x<-3
plot(1:10)
title(bquote(bold(x) <= bold(as.character(.(x)) )))
It prints x<=as.character(3) as title
Kids these days! No innovative spirit. Why in my day... they would be
jumping with
Thank you Alan again! Hope you could also share your thought on my another
email about the coding of censoring before death..
Thanks again!
John
- Original Message
From: alanm (Alan Mitchell)
To: array chip ; David Winsemius
Cc: r-help@r-project.org
Sent: Tue, June 28, 2011 11:4
David,
I tried your suggestion, still not working:
x<-3
plot(1:10)
title(bquote(bold(x) <= bold(as.character(.(x)) )))
It prints x<=as.character(3) as title
Thanks
John
- Original Message
From: David Winsemius
To: array chip
Cc: Peter Ehlers ; R
Sent: Tue, June 28, 2011 11:30:2
Jacob Brogren brogren.nu> writes:
>
> All,
>
> I rerun once again and managed to reproduce the results from the text book.
> Made no changes to the code. Could
> it be some problem with convergence?
It is possible, but *extremely* unlikely, to get non-deterministic
results from R (i.e. runn
>So in cuminc() function, the argument "fstatus" should be coded like:
0=censored, 1=event of interest, 2=event of competing risk. Then the
function will calculate CI for each of the 2 types of events >(event of
interest and event of competing risk), am I correct?
Correct.
>What about running regu
matotope gmail.com> writes:
> I installed the 2.8.0 version and it seems to be working fine now.
Hard to see from a brief glance at the code why it would not work
in 2.13.0 as well, but glad you got the problem solved. If you will
need to maintain and extend this code in the future it may be
The * operator can be used for a non-space separation.
expression(Chlorophyll*italic(a)~mu*g~cm^-2)
--
David.
On Jun 28, 2011, at 2:21 PM, Sam Albers wrote:
Hello all,
I can't seem to figure how to use a greek character in expression() in
plot() labels without adding a space. So for examp
On Jun 28, 2011, at 2:19 PM, array chip wrote:
Thank you David and Bert.
x<-3plot(1:10)
title(bquote( x <= .(x) ))
would do what I want. But I also want the title printed in bold
font. so I tried
x<-3
plot(1:10)
title(bquote(bold(x <= .(x)) ))
But this did not print the "less than equal
nevill.uk.net> writes:
> I am using the chull function to create a convex hull of a series of about
> 20,000 data points.
You already posted this statement (not a question). One more try? (You
might as well read the posting guide while you're at it -- please refrain
from sending your e-mai
On Jun 28, 2011, at 1:44 PM, Edward Patzelt wrote:
R help -
I am attempting to write a script that has multiple subjects in 1
data file.
Each subject has multiple rows with columns as variables. Here is
my code,
I am having problem executing it on each unique subject id (dat
$Subject).
Hello all,
I can't seem to figure how to use a greek character in expression() in
plot() labels without adding a space. So for example below when plotting
this out
x<-1:10
plot(x,x^2, xlab=expression(Chlorophyll~italic(a)~mu~g~cm^-2))
the axis label read as μ g cm^-2 because I have space there
Thank you David and Bert.
x<-3plot(1:10)
title(bquote( x <= .(x) ))
would do what I want. But I also want the title printed in bold font. so I tried
x<-3
plot(1:10)
title(bquote(bold(x <= .(x)) ))
But this did not print the "less than equal to" symbol and the number 3 (from
variable x) in bol
R help -
I am attempting to write a script that has multiple subjects in 1 data file.
Each subject has multiple rows with columns as variables. Here is my code,
I am having problem executing it on each unique subject id (dat$Subject).
getwd()
setwd("/Users/edwardpatzelt/Desktop/Neuroimaging
Hi, all,
./configure was run successfully on my HP-UX ia64 server with exit=0, but when
type make at prompt, get this error "Make: Don't know how to make #. Stop."
Does anyone has any clues about this message? Thank you very much!
#make
Rmath.h is unchanged
`libRblas.sl' is up to date.
/app/R/
> sapply(fitSUR$eq, function(x) summary(x)$r.squared)
> You can abbreviate that to:
> sapply(summary(fitSUR)$eq, "[[", "r.squared")
This is fantastic! Thanks so much.
I had a hunch that it would be something related to the apply family but I
am still not very good at using it. Thank you immensel
Dear all,
I am using the function ‘unfold’ from the ‘RcmdrPlugin.survival’ to convert
my time-varying covariates dataset from wide to long. I managed to have it
working for my data.
However, the problem I have is that the observations after an event, won’t
be dropped from the dataset. For example
Greetings R Users,
I´m new to R but at least managed to read in multiple files:
filenames <- list.files(path=getwd())
numfiles <- length(filenames)
for (all_temp in c(1:numfiles)) {
filenames[all_temp] <- paste(filenames[all_temp],sep="")
assign(gsub("[.]ASC$","temp",filenames[all_temp]),r
Hi Georg,
I am new to R and I am curious if there is a simple way to do the feature
selection you described:
"feature selection is essentially an exhaustive approach which tries
every possible subset of your predictors, trains a network and sees what
the prediction error is. The subset which is b
Hi David -
I wanted to thank you for your response! This was exactly what I needed.
Sincerely,
Alicia
On Fri, Jun 17, 2011 at 3:33 PM, David L Carlson [via R]
wrote:
> You need to use hhid as the rownames for housing.cluster rather than
> including it as a variable in the data.frame:
>
> housing
John,
Since death precludes recurrence, censoring deaths would violate the KM
estimator assumption that additional follow-up would eventually lead to
an event. If your goal is to estimate the probability of recurrence,
then you want CI with deaths as a competing risk. The cuminc function
in the
For the record, I was wrong -- using plotmath's "less than or equal"
does NOT require platform info. However, I was unsure if you meant
that it was some kind of an arrow you wanted to render, a clear
misinterpretation on my part.
-- Bert
On Tue, Jun 28, 2011 at 10:57 AM, array chip wrote:
> Than
On Jun 28, 2011, at 1:52 PM, Peter Ehlers wrote:
On 2011-06-28 10:25, array chip wrote:
Hi, how can I print "<=" (I mean the symbol of just one character)
in the main
title of a plot?
for example:
plot(1:10, main=paste("x<=", x))
where variable x is some number generated on the fly.
x
Hello Duncan,
testci.R is a test function for the survival package. I compared the .Rout and
.Rout.save files by eyeball (I'm on a Windows 7 machine, so I can't use the
diff function). The only differences I found were in the file headers.
This is the header from the .Rout file:
R version 2
Thank Peter! How do I make the title in bold font?
John
- Original Message
From: Peter Ehlers
To: array chip
Cc: R
Sent: Tue, June 28, 2011 10:52:07 AM
Subject: Re: [R] how to print "<=" in plot title
On 2011-06-28 10:25, array chip wrote:
> Hi, how can I print "<=" (I mean the sym
On 2011-06-28 10:25, array chip wrote:
Hi, how can I print "<=" (I mean the symbol of just one character) in the main
title of a plot?
for example:
plot(1:10, main=paste("x<=", x))
where variable x is some number generated on the fly.
x <- 2.718
plot(0, 0)
title(bquote( x %<=% .(x) ))
Thanks Bert. here is info:
R version 2.12.2 (2011-02-25)
Platform: i386-pc-mingw32/i386 (32-bit)
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United
States.1252LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C LC_TIME=English_United Stat
Alan,
Let's say that I code censoring as "0", recurrence as "1" for fstat and
death/competing risk as "2". If a patient did not have recurrence and lost
follow-up at 2 years in terms of recurrence monitoring, but he also died at 5
years. How should I code this patient? I think I still code this
On 2011-06-28 09:54, Ana Kolar wrote:
Hi Sarah,
Thank you for your response. Here is a toy example:
library(MatchIt)
data(lalonde)
A<-lalonde
f<-treat ~ age + I(age^2) + educ + I(educ^2) + black + hispan +
married + nodegree + re74 + I(re74^2) + re75 + I(re75^2)
m<-"nearest"
m.out.base<-
This is highly system dependent: what "character" do you intend to use
for this 2 character representation? Hence, you need to follow the
posting guide and give the "at a minimum" system info. ?sessionInfo
-- Bert
On Tue, Jun 28, 2011 at 10:25 AM, array chip wrote:
> Hi, how can I print "<=" (I
Hi, how can I print "<=" (I mean the symbol of just one character) in the main
title of a plot?
for example:
plot(1:10, main=paste("x <=", x))
where variable x is some number generated on the fly.
Thanks
John
__
R-help@r-project.org mailing list
ht
Many thanks to Uwe Ligges, Peter Ehlers, and Dennis Murphy for suggesting
work-arounds for this bug. Because the suggestions are work-arounds, rather
than actually correcting the bug, I have opted simply to copy and paste the
plotting commands a few times with the subscripts specified as constants
Thank you Alan! Now I sort of understand what it means by competing risk! So in
cuminc() function, the argument "fstatus" should be coded like: 0=censored,
1=event of interest, 2=event of competing risk. Then the function will
calculate
CI for each of the 2 types of events (event of interest an
Hi Sarah,
Thank you for your response. Here is a toy example:
library(MatchIt)
data(lalonde)
A<-lalonde
f<-treat ~ age + I(age^2) + educ + I(educ^2) + black + hispan +
married + nodegree + re74 + I(re74^2) + re75 + I(re75^2)
m<-"nearest"
m.out.base <- matchit(formula=f, data=A, method=m)
B
Hi Ana,
On Tue, Jun 28, 2011 at 12:28 PM, Ana Kolar wrote:
> Let's say I have an original data set which is called A and data extracted
> from this original data set, called B. Based on these A and B data set I
> would like to get data set C which includes all the remaining data from the
> dat
Let's say I have an original data set which is called A and data extracted from
this original data set, called B. Based on these A and B data set I would like
to get data set C which includes all the remaining data from the data set A
after we exclude data of the data set B.
Any idea how to do
On Tue, 28 Jun 2011, StellathePug wrote:
Greetings R Users,
I have a system of equations for which I would like to output all the
R-squares. Assume there are four equations in my system, the only way I
found to output all the R-squares is by calling them out one by one as this:
summary(fitSUR$e
Greetings R Users,
I have a system of equations for which I would like to output all the
R-squares. Assume there are four equations in my system, the only way I
found to output all the R-squares is by calling them out one by one as this:
summary(fitSUR$eq[[1]])$r.squared
summary(fitSUR$eq[[2]])$r.
Subject: Re: [R] Running R from windows command prompt
Hi Siddharth, many experts already answered your query, however I
would like to share how I run R in command prompt:
1. open command prompt
2. change working directory: cd C:\\R-2.13.0\bin\i386
(put the entire path here, howe
Ops!
Thank-you Duncan for clarifying the 2 vs. 3 colon difference and a
couple of other things.
Working like a charm now.
Cheers,
jcb!
> If you are using ::: (three colons), then you may be looking into the
> unexported functions in log4r. The only normal way to see unexported
> functions is to u
Hi Siddharth, many experts already answered your query, however I
would like to share how I run R in command prompt:
1. open command prompt
2. change working directory: cd C:\\R-2.13.0\bin\i386
(put the entire path here, however many people might find this step
weird, you can have
All,
I rerun once again and managed to reproduce the results from the text book.
Made no changes to the code. Could it be some problem with convergence?
Anyhow, now it works!
Cheers
Jacob
ps. I find "The R Book" very useful ds.
28 jun 2011 kl. 15.48 skrev Robert A LaBudde:
> Did you create
yes it is.
and a correlation of 0 isn't exactly white (#FF) either.
have a look at the panel.pie function.
the crucial part is
ncol <- 14
pal <- col.corrgram(ncol)
col.ind <- round(ncol * (corr + 1)/2)
so an correlation near -1 maps to an index 0, which isn't a proper index
in R.
Thank you Bert and Prof. Ripley for your feedback. I did read the language
documentation and it was not entirely clear to me, but I'm one of those people
that has to read and digest something before it clicks. However, I did realize
that the issue with "call"and "formula" was not the real reas
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