Hi
>
> > Hi
> >
> > >
> > > Hello,
> > >
> > > I know that it'll be quite easy to do what I want but somehow I am
lost
> > as
> > > I am new to R. I want to get summary results arranged by groups. In
> > detail
> > > I'd like get the number (levels) of Species per Family like for this
> >
Hello all,
To anyone who is interested, I'm trying to learn a bit more about
developing applications in R with user interfaces. I've been playing
around with gWidgets to develop a model building interface.
I'd appreciate any comments, suggestions, or guidance on how to better
structure my R code
> Incidentally, gMail (on Windows) correctly rendered the Hebrew
> ("Shalom Olam"), so it would seem that this probably is a plotting
> issue rather than an OS issue
I tested a Persian text with this kind of parentheses in linux and
windows, and it seem it is indeed an OS issue. The text renders
On 03/01/12 17:02, Li SUN wrote:
Hello,
I am a beginner to the R language and find it fantastic and
well-designed, quite different from other programming languages.
What a refreshingly sensible attitude!!! :-)
This is the first time I post on the r-help mailing list.
In invoking the funct
Hi Aren,
Could you perhaps send us the output of:
dput(dallas[1:40, "offense_hour", drop = FALSE])
I believe your problem, but getting it to work in ggplot2 will be
easiest working with your actual data (or a bit of it anyway).
for ggplot2 specific questions, you might also checkout:
groups.goo
Hello,
I am a beginner to the R language and find it fantastic and
well-designed, quite different from other programming languages. This
is the first time I post on the r-help mailing list.
In invoking the function source(filename), it seems that the filename
has to exist in the current working d
Hi everyone,
I have been looking at the Bigglm (Basically does Generalised Linear Models
for big data under the Biglm package) command and I have done some profiling
on this code and found that to do a GLM on a 100mb file (9 million rows by 5
columns matrix(most of the numbers were either a 0,1 or
Hello all,
I'm using R to produce figures for people who want to be able to edit
the figures directly, and who use PowerPoint a lot. I use a Mac, and I'd
appreciate any advice about how to approach this. Here's what I've come
up with so far:
1) I can use xfig() and then ask them to install I
Aren,
On 2 January 2012 19:34, Aren Cambre wrote:
> I am making a plot using this:
> p <- ggplot(dallas, aes(x = offense_hour)) + geom_bar() + coord_polar()
> The plot shows up fine, but the X axis labels are 0.0 through 1.0. How
> do I convert this to 0:00 through 23:59 (or whatever may be
> appr
I am trying to learn nls using a simple simulation. I assumed that the
binomial prob varies linearly as 0.2 + 0.3*x in x {0,1},
and the objective is to recover the known parameters a=0.2, b=0.3
..data frame d has 1000 rows...
d$x<-runif(0,1)
d$y<-rbinom(1000,1,0.2+0.3*d$x)
tab
glht is probably what you should be using. Both TukeyHSD and glht give
essesntially identical confidence intervals for
the example in ?glht. What aren't you satisfied with?
amod <- aov(breaks ~ tension, data = warpbreaks)
confint(glht(amod, linfct = mcp(tension = "Tukey")))
TukeyHSD(amod)
On Mon
Thanks to Joshua Wiley for turning me on to ggplot2.
I am making a plot using this:
p <- ggplot(dallas, aes(x = offense_hour)) + geom_bar() + coord_polar()
Dallas is a data frame, and offense_hour is a column with chron
objects from the chron library. In this case, the chron object was
created wi
summary: I'd like a tool to use within an R session (better yet an ESS
buffer) that would
* (minimally) allow me to page (à la `less`) a large sparse matrix
* (preferably) page row-wise (i.e., show all values for row=1 before
proceeding to row=2)
details:
Apologies if this is a FAQ, but I di
On Mon, Jan 2, 2012 at 6:08 PM, Tom Roche wrote:
>
> Should one ask questions relating to the R package 'ncdf' here? or
> look for a more netCDF-oriented (but probably less R-oriented) list?
>
Hi Tom,
you can ask here and I can give a shot at answering them (I'm the author of
the ncdf and ncdf4
Should one ask questions relating to the R package 'ncdf' here? or
look for a more netCDF-oriented (but probably less R-oriented) list?
Why I ask:
I'm relatively new to R, which I've only used in the past for graphics.
I'm trying to learn R as an alternative to manipulating netCDF files
with NCO
If you are worried about an NA in the first, then use the following:
> y <- c(NA, 1, 2, NA, 4, NA)
> y <- na.locf(y, na.rm = FALSE)
> y
[1] NA 1 2 2 4 4
> y <- na.locf(y, fromLast = TRUE)
> y
[1] 1 1 2 2 4 4
>
On Mon, Jan 2, 2012 at 5:07 PM, Joshua Wiley wrote:
> Good points, Rui.
>
> On M
Hello,
I am trying to determine the most appropriate way to run post-hoc
comparisons on my lme model. I had originally planned to use Tukey
HSD method as I am interested in all possible comparisons between my
treatment levels. TukeyHSD, however, does not work with lme. The
only other c
Hello,
Can you please, as a matter of urgency, tell me which R version support
tm.plugin.sentiment
and how I can install the package in R studio. I use window 7.
Thanks.
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R-help@r-project.org mailing lis
Hi Bert,
Sorry for the sub-par post.. again. I've revamped my OP, I hope it's
sufficient now.
Thank you.
-
Isaac
Research Assistant
Quantitative Finance Faculty, UTS
--
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Good points, Rui.
On Mon, Jan 2, 2012 at 12:48 PM, Rui Barradas wrote:
> Hello again,
>
> I believe we are all missing something. Isn't it possible to have NAs as the
> first values of 'y'?
> And isn't it also possible to have x[1] > 3?
Theoretically, yes, in the OPs data, maybe? If the data is
On Jan 2, 2012, at 4:22 PM, David Stevens wrote:
Could it be
NO. You are not reading the documentation for "if" carefully enough,
despite several efforts to point you in the right direction. You
cannot make literal transliterations of SPSS syntax work in the manner
you imagine.
--
Dav
Hello again,
I believe we are all missing something. Isn't it possible to have NAs as the
first values of 'y'?
And isn't it also possible to have x[1] > 3?
Here is my point (I have changed function 'f2' to predict for such cases,
'f1' is rubbish)
# Rui
f3 <- function(x, y){
inx <- which(
On 12-01-02 04:09 PM, David Winsemius wrote:
>
> On Jan 2, 2012, at 11:49 AM, Ben Bolker wrote:
>
>> Jonas Stein jonasstein.de> writes:
>>
>>>
>>> i have a list of values like this
>>>
>>> x y
>>> 1 3
>>> 2 2
>>
>> [snip]
>>
>>>
>>> and need the inflexion [sic] points (and all max and min).
>>>
Could it be
if(variable1.fac == 0 & variable2.num == 0) {variable3 = 1} #
brackets {} aren't strictly required for a one liner.
if(variable1.fac == 0 & variable2.num >= 0) {variable3 = 2} #
brackets {} aren't strictly required for a one liner.
if(variable1.fac == 1 & variable2.nu
On Mon, 2 Jan 2012, Gabor Grothendieck wrote:
Assuming you need a separate column for each site see the read.zoo split=
argument. An example is here:
http://r.789695.n4.nabble.com/building-time-series-zoo-its-from-a-data-frame-tp2240349p2240814.html
I created a new data frame for a single s
On Jan 2, 2012, at 11:49 AM, Ben Bolker wrote:
Jonas Stein jonasstein.de> writes:
i have a list of values like this
x y
1 3
2 2
[snip]
and need the inflexion [sic] points (and all max and min).
Is there a nice way to get the local max, min and inflexion points?
diff(y) gives you t
I don't have experience with this in R and I'm not sure I understand the
question that well but maybe something like nearPD()?
Ken Hutchison
On Jan 2, 2012, at 6:36 AM, riccardo24 wrote:
> Hi, I need to maximize a quadratic function under constraints in R.
> For minimization I used solve.QP
I usually do this kind of thing like this:
variable3 <- rep(1,length(variable1.fac))
variable3[ variable1.fac == 0 & variable2.num >= 1 ] <- 2
variable3[ variable1.fac == 1 & variable2.num == 0 ] <- 3
variable3[ variable1.fac == 1 & variable2.num >= 1 ] <- 4
This approach is easy to read and unde
> Your request is reminding me of the analysis of aray functions in Philip S
> Abrams dissertation
> http://www.slac.stanford.edu/cgi-wrap/getdoc/slac-r-114.pdf
> AN APL MACHINE
>
> The section that starts on page 17 with this paragraph is the one that
> immediately applies
>
> C. The Standard Form
Here is a way of doing it without loops:
> df <- data.frame(x = c(1,2,3,4,5), y = c(10,20,30,NA,NA))
>
> require(zoo) # need na.locf to fix the NAs
>
> # replace NA with preceeding values
> df$y <- na.locf(df$y)
> df
x y
1 1 10
2 2 20
3 3 30
4 4 30
5 5 30
>
> # assuming that you want to increm
Here is another approach. Probably with some thought and fingerwork,
rle() could be used to avoid the while loop, but that should only slow
things down if there are long runs of NAs --- there can be a lot of
NAs as long as they are spaced apart and it should still be quite
efficient.
f <- functio
Am 02-01-2012 10:54, schrieb ken knoblauch:
Christof Kluß email.uni-kiel.de> writes:
lme<- lme(conc ~ name/time - 1,
random=conc~time|nr,method="ML",data=measurements)
see plot.augPred in the nlme package
thx, but how to set "primary"? I always get the error
plot(augPred(lme))
augPre
On 02.01.2012 18:53, Danai Katsande wrote:
Dear Sir/Madam,
Please kindly remove me from the mailing list as I no longer intend to
receive emails from R help.
Best
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R-help@r-project.org mailing list
ht
Hadley,
I started to throw some functions that I needed to be extended to arrays
together as package arrayhelpers. If you consider that a good home for
the new functions, they would be more than welcome.
Currently I have the package at r-forge, but I wouldn't mind github,
either (so far I just us
Dear Sir/Madam,
Please kindly remove me from the mailing list as I no longer intend to
receive emails from R help.
Best
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEA
Hadley,
Your request is reminding me of the analysis of aray functions in Philip S
Abrams dissertation
http://www.slac.stanford.edu/cgi-wrap/getdoc/slac-r-114.pdf
AN APL MACHINE
The section that starts on page 17 with this paragraph is the one that
immediately applies
C. The Standard Form for Se
On Jan 2, 2012, at 11:14 AM, Johannes Radinger wrote:
Thank you Petr,
that is exactly what I was looking for... no I played a little bit
around with that because I want to create a summary with FAM as a
grouping variable. Beside the number of unique SPEC per FAM also
want to get their
Ben Bolker gmail.com> writes:
>
> Jonas Stein jonasstein.de> writes:
> [snip]
>
[snip]
> sign(s2y)[which(dy==0)] ## test for max/min/saddle
oops, obviously this should be sign(d2y)[which(dy==0)]
__
R-help@r-project.org mailing list
https
Jonas Stein jonasstein.de> writes:
>
> i have a list of values like this
>
> x y
> 1 3
> 2 2
[snip]
>
> and need the inflexion points (and all max and min).
> Is there a nice way to get the local max, min and inflexion points?
diff(y) gives you the first difference, the analogue of the
I believe that I have a basic understanding of zoo and how to use read.zoo
on a text file, What I have not seen in the zoo help files and vignettes is
how to convert a data frame to a zoo matrix for irregular time series
analyses.
An example data frame is structured like this:
str(burns.cast
eigenvalet wrote
>
> How can I display a number as currency including a $ sign and commas?
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Display-number-in-currency-notation-with-commas-tp4253460p4253460.html
> Sent from the R help mailing list archive at Nabble.com.
>
>
Original-Nachricht
> Datum: Mon, 2 Jan 2012 14:29:07 +0100
> Von: Petr PIKAL
> An: "Johannes Radinger"
> CC: r-help@r-project.org
> Betreff: Re: [R] summary per group
> Hi
>
> >
> > Hello,
> >
> > I know that it'll be quite easy to do what I want but somehow I am lost
> a
something like
library(mgcv)
gam(y~s(x,k=50),method="REML")
is one option for spline smoothing y w.r.t. x and choosing the smoothing
parameter by GML (GML and REML do the same thing).
On 18/12/11 12:26, ali_protocol wrote:
Hi there,
How may I smooth spline two vectors with the smoothing
On Mon, Jan 2, 2012 at 3:54 PM, Barry Rowlingson
wrote:
> That looks suspiciously like a chunk of a GPX format file - GPS
> tracks, that kind of thing. Am I right?
>
> If so, then get the rgdal package, and read it in. You'll end up with
> a spatial data frame of some kind from which you can get
On Jan 2, 2012, at 10:42 AM, David Winsemius wrote:
On Jan 2, 2012, at 4:11 AM, Richard Kolodziej wrote:
Hello,
I'm using SPSS at work but really would like to switch to R. Right
now I'm
trying to learn R in reproducing calculations I did with SPSS but
am stuck
with something that is qu
On Mon, Jan 2, 2012 at 3:31 PM, Marion Wenty wrote:
.
>
> 387
> 2012-01-01T15:32:03Z
> 9
>
>
> 381
> 2012-01-01T15:32:34Z
> 9
>
> ...
>
> now we would like to create a text file looking like the following, in
> order to being able to read it into R afterwards.
>
> ->
>
>
Dear Richard,
You can do this with some nested ifelse statements.
Assuming variable2.num has only positive integers and variable1.fac is only 0
or 1
Variable3 <- ifelse(variable1.fac == 0, ifelse(variable2.num == 0, 1, 2),
ifelse(variable2.num == 0; 3; 4))
A more fancy solution
as.numeric(fac
How can I display a number as currency including a $ sign and commas?
--
View this message in context:
http://r.789695.n4.nabble.com/Display-number-in-currency-notation-with-commas-tp4253460p4253460.html
Sent from the R help mailing list archive at Nabble.com.
___
On Jan 2, 2012, at 4:11 AM, Richard Kolodziej wrote:
Hello,
I'm using SPSS at work but really would like to switch to R. Right
now I'm
trying to learn R in reproducing calculations I did with SPSS but am
stuck
with something that is quite simple and comprehensible in SPSS-Syntax:
IF (var
(To me, anyway) Incoherent. Reproducible code needed.
-- Bert
On Mon, Jan 2, 2012 at 1:59 AM, iliketurtles wrote:
> Sorry if there's an easy answer to this problem, but here goes..
> *
> INTRODUCTION & CONTEXT*
>
> I'm creating a function where the number of entries in the lm(y~...)
> varies
I have question related to predicting mutiple response sequences and am not
sure how to go about it. I have a training set of classifiers say T0, T1..TN
and am trying to predict a sequence of results (say a timeseries), say R0,
R1...Rx (R0, R1.etc may or may not be independent). How does one go
Hi Przemek,
Take a look at ?sm.density.compare : you forgot to include the "group"
argument in your call. Try
require(sm)
rno1 = rnorm(1000)
rno2 = rnorm(1000)
g <- rep(c(1, 2), each = 1000)
y <- c(rno1, rno2)
sm.density.compare(y, g, model = 'equal')
HTH,
Jorge.-
On Mon, Jan 2, 2012 at 7:00
I am trying to add a constant to the previous value of a variable based on
certain conditions. Maybe there is a simple way to do this that I am missing
completely. I have given an example below:
df <- data.frame(x = c(1,2,3,4,5), y = c(10,20,30,NA,NA))
> df
x y
1 1 10
2 2 20
3 3 30
4 4 NA
5 5
dear users,
we have got the following question:
we have got a text-file looking like this:
...
387
2012-01-01T15:32:03Z
9
381
2012-01-01T15:32:34Z
9
...
now we would like to create a text file looking like the following, in
order to being able to read it into
i have a list of values like this
x y
1 3
2 2
3 3
4 4
5 5
6 4
7 3
8 2
9 3
and need the inflexion points (and all max and min).
Is there a nice way to get the local max, min and inflexion points?
kind regards,
--
Jonas Stein
__
R-help@r-project.org
Hi Ana,
most probably this is one of the more ugly solutions:
> d=dim(A)
> d
[1] 2 4
> cbind(rep(1:d[1], each=d[2]), rep(1:d[2], d[1]))
[,1] [,2]
[1,]11
[2,]12
[3,]13
[4,]14
[5,]21
[6,]22
[7,]23
[8,]24
Thanks,
wr
* Ana [2012
Hi, I need to maximize a quadratic function under constraints in R.
For minimization I used solve.QP but for maximization it is not useful since
the matrix D of the quadratic function
should be positive definite hence I cannot simply change the sign.
any suggestion ?
thanks
--
View this message i
Hello,
I believe this works.
f1 <- function(x){
for(i in 2:length(x)) x[i] <- ifelse(x[i-1] > 3, x[i-1] + 2, x[i])
x
}
f2 <- function(x){
for(i in 2:length(x)) x[i] <- ifelse(is.na(x[i]) & (x[i-1] > 3), x[i-1]
+
2, x[i])
x
}
df <- data.frame(x = c(1,2,3,4,5), y
Dear all,
I would like to show a warning when a data file, that is embedded in the
package, is loaded. I have so far not been able to find any manual or mailing
list going on about that.
In code example:
library("myPackage")
data("myData")
# Now I want a warning containing info about this lo
Hi Ana,
> d=dim(A)
> d
[1] 2 4
> cbind(rep(1:d[1], each=d[2]), rep(1:d[2], d[1]))
[,1] [,2]
[1,]11
[2,]12
[3,]13
[4,]14
[5,]21
[6,]22
[7,]23
[8,]24
Thanks,
wr
* Ana [2012-01-01 23:21:12 +0100]:
> How can I extract a list of
Hello,
I'm using SPSS at work but really would like to switch to R. Right now I'm
trying to learn R in reproducing calculations I did with SPSS but am stuck
with something that is quite simple and comprehensible in SPSS-Syntax:
IF (variable1.fac = 0 AND variable2.num = 0) variable3=1.
IF (variabl
Sorry if there's an easy answer to this problem, but here goes..
*
INTRODUCTION & CONTEXT*
I'm creating a function where the number of entries in the lm(y~...)
varies. i.e. depending on the function input I want lm(y~x1+x2+x3),
sometimes I'll want lm(y~x1) only, et cetera.
I've completed this
Respected Sir
I fitted that model... lnrpe= a+bt and conducted sup F test since
autocorelation is present in the data and AIC as you mentioned might
not Is it OK... Since I am not well versed with time series
econometrics can you please tell me if the
work is now correct or not
--
Please h
Dear all,
Let say I have a sets of numbers:
rno1 = rnorm(1000)
rno2 = rnorm(1000)
If I write request as follow:
sm.density.compare (rno, rno3, xfit=min(rno), max(rno2))
why I receive a lot of curves in my plot, while I have only two data sets?
regards
Przemek
--
View this message in context:
On Jan 2, 2012, at 10:10 AM, David Winsemius wrote:
On Jan 2, 2012, at 4:31 AM, Öhagen Patrik wrote:
Seasonal Greetings!
I am trying to plot a simple survival curve using;
plot
(survfit
(Surv(d01,cens) ,conf.type="none" ),xlab="Time",ylab="Survival")
That does not look like a valid surv
On Jan 2, 2012, at 4:31 AM, Öhagen Patrik wrote:
Seasonal Greetings!
I am trying to plot a simple survival curve using;
plot
(survfit
(Surv(d01,cens) ,conf.type="none" ),xlab="Time",ylab="Survival")
That does not look like a valid survival formula to me but maybe I'm
insufficiently exper
Hi,
On Jan 2, 2012, at 7:00 AM, William Simpson wrote:
> Duncan, I checked out as.raster as you suggested. However, I can't
> find info on how to display and save a raster object. What a raster
> object is eludes me. These were fruitless
> ?as.raster
> ?grDevices
> library(help="grDevices")
> ?wi
I have figured out what I wanted to do using pixmap. Pixmap writes
.pgm files which I will batch convert to .bmp using Irfanview.
Thanks for your help.
Cheers,
Bill
On 1/2/12, William Simpson wrote:
> Duncan, I checked out as.raster as you suggested. However, I can't
> find info on how to displ
> But if not, it seems to me that it should be added as an array method
> to ?rev with an argument specifying which indices to rev() over.
Yes, agreed. Sometimes arrays seem like something bolted onto R that
is missing a lot of functionality.
Hadley
--
Assistant Professor / Dobelman Family Ju
Hi,
On Mon, Jan 2, 2012 at 8:08 AM, Johannes Radinger wrote:
> Hello,
>
> I know that it'll be quite easy to do what I want but somehow I am lost as I
> am new to R. I want to get summary results arranged by groups. In detail
> I'd like get the number (levels) of Species per Family like for this
Hi
>
> Hello,
>
> I know that it'll be quite easy to do what I want but somehow I am lost
as
> I am new to R. I want to get summary results arranged by groups. In
detail
> I'd like get the number (levels) of Species per Family like for this
dataset:
>
> SPEC <- factor(c("a","a","b","b","c","
A little bit more information about SWord:
It is similar to SWeave in the sense that one writes text and R code in one
document,
and the toolchain then replaces the R code by the results produced by running
the R code.
In SWeave, this produces a new file which then can processed by TeX.
In SWord,
Hello,
I know that it'll be quite easy to do what I want but somehow I am lost as I am
new to R. I want to get summary results arranged by groups. In detail
I'd like get the number (levels) of Species per Family like for this dataset:
SPEC <- factor(c("a","a","b","b","c","c","c","d","e","e","e",
Dear Michael,
Our current work flow is to use Sweave and LaTeX. If Word output is needed we
convert the LaTeX files to html using htlatex (installed with MikTex). Those
html files can be opened with ms word.
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek /
Dear friends, can I use Ryacas to solve the two equations
X = a/(a+b)
Y = (a+b)^2*(a+b+1)/(a*b)
subject to a>0 and b>0 ?
I'm on windows using latest R
Best wishes
Troels Ring
Nephrology
Aalborg, Denmark
Jeg bruger BullGuard til at holde min computer ren.
Prøv BullGuard gratis: www.bullguard.com
Hi,
I created a logistic regression model using the glmnet package. This model is
of class "glmnet" or "lognet". I wanted to plot a calibration curve for this
model using the calibrate() function from rms package, but the objects used are
different, rms requires a fit from lrm(). Is there anot
Duncan, I checked out as.raster as you suggested. However, I can't
find info on how to display and save a raster object. What a raster
object is eludes me. These were fruitless
?as.raster
?grDevices
library(help="grDevices")
?windows
?savePlot
x<-as.raster(matrix(runif(n*n),nrow=n))
How to d
Today I wanted to get R help to start up in text mode under Windows
XP. I had my own notes on how to do that. The method described there
didn't work. I checked on R-help. No helpful messages on the subject.
Therefore I post here in the hope that it helps someone else (or
myself, when I forget and s
The html route is one I have used quite a lot, but rather than R2HTML I
far prefer hwriter. I have spent some time on enhancing hwriter and you
can find my hwriterPlus on R-forge. It has fairly extensive examples and
a vignette in the inst directory. I am still working on some
improvements to t
Thanks Brian,
The short answer is that this needs someone in Vienna to fix (people do
> have vacations and take weekends off), and that the web/packages directory
> is pure sugar: the packages are still there, the check results are there
> ... just the summary pages are missing and they are access
On 01/01/12 15:50, Michael wrote:
Happy New Year all!
I am looking for a good solution for keeping record of my experiments -
could you please help me?
My work is about analysing data... My current work-flow:
1. Everyday my bosses give me some small steps/tasks for analysing data -
which are p
Christof Kluß email.uni-kiel.de> writes:
> I would like to plot the regression lines of a model like
>
> lme <- lme(conc ~ name/time - 1,
> random=conc~time|nr,method="ML",data=measurements)
>
> Ideally a seperate plot for each regression line (respectively name) and
> seperate colors for the
Ken Hutchison schrieb:
If stranded on a desert island and getting R fully functional on Droid would
save you, I'd advise looking for food; else be prepared to name your phone
Wilson.
Ken Hutchison
I propose to add that to fortunes :-D
Andreas Borg
--
Andreas Borg
Abteilung M
Hi,
first a happy new year ;)
I would like to plot the regression lines of a model like
lme <- lme(conc ~ name/time - 1,
random=conc~time|nr,method="ML",data=measurements)
Ideally a seperate plot for each regression line (respectively name) and
seperate colors for the measurements (nr).
H
Seasonal Greetings!
I am trying to plot a simple survival curve using;
plot(survfit(Surv(d01,cens) ,conf.type="none" ),xlab="Time",ylab="Survival")
I would be interested in a percentage scale on the y-axis. How do I achieve
sucha scale?
Thank you in advance!
On 02/01/2012 08:17, Graham Smith wrote:
I have been getting a object not found error trying to access the CRAN
package directory since the 30th December. I have tried several mirrors
with the same error. A search here only shows a single question on this
from anyone else (on the 30th December) w
Thanks Duncan for your help.
Bill
On 1/1/12, Duncan Murdoch wrote:
> On 12-01-01 9:05 AM, William Simpson wrote:
>> When using bmp() under Windows XP, I find that the saved image is a
>> shifted version of the correct image. Try this:
>
> The image() function isn't designed to be able to do pixel
I have been getting a object not found error trying to access the CRAN
package directory since the 30th December. I have tried several mirrors
with the same error. A search here only shows a single question on this
from anyone else (on the 30th December) which wasn't answered.
I am surprised that
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