Thanks a ton, much appreciated...
On 26-Jul-2012, at 7:56 PM, Michael Weylandt [via R] wrote:
On Thu, Jul 26, 2012 at 3:59 AM, guruappa [hidden email] wrote:
Hello all,
I am a newbie at R, with some experience in PERL.
I have a database table that contains the following data:
Thanks a ton, much appreciated.
On 26-Jul-2012, at 8:35 PM, John Kane [via R] wrote:
Let me count the ways...
R supplies a number of different ways. Here is sample using basic R and some
other packages. Youprobably will need to install the packages (
?install.packages) to run any but
I'm using eleaps to build a forward selection algorithm iteratively, but
the program unexpectedly crashes. In fact, it completely closes my session
in RStudio. The first 39 steps work fine, but on the 40th step, it
unexpectedly stops with no errors. I've isolated the error to the code
snippit
Hi Jean,
Thank you very much for getting back to me.
I tried the solutions that you have provided.
First I tried the
coef(result) statement
.and I got the below output
coef(result)
(Intercept)X Volume
-30.40275264 0.57786290 0.02594024
Then, I simply
Hi all,
I'm a newbie to R and it has been very helpful to use your website.
Unfortunately I've been struggling with my code now for two days so I wanted
to ask few questions. I've been trying to create nice graphs to put into a
pdf sheet but I'm having little problems with all the packages I've
Stop posting HTML. What you see is NOT what we see.
As regards to your problems... you need to learn how to get data into and out
of R, so please read the R Input/Output document supplied with R. The most
foolproof way is to write the data to a CSV file and read it from there into a
Dear Miao,
substr() ius waht you want.
substr(ABCD, 2,2)
[1] B
Cheers,
Henrik
jpm miao schrieb:
Dear Daniel and Jorge,
Thank you very much and it does help.
If I have a string ABCD, how can I access the second element of the
string B? Thanks,
Miao
2012/7/27 Daniel Nordlund
HI,
Try this:
string1-ABCD
idx-1:nchar(string1)
substr(string1,2,idx[2])
[1] B
substr(string1,4,idx[4])
[1] D
A.K.
- Original Message -
From: jpm miao miao...@gmail.com
To: Daniel Nordlund djnordl...@frontier.com; jorgeivanve...@gmail.com
Cc: r-help r-help@r-project.org
Sent:
Hi Jeff,
Sorry for the previous email.
I tried using write function, and used the following syntax
write(result,file=C:\\Users\\Krunal\\Desktop\\Book1.csv)
but it is giving the following error
Error in cat(list(...), file, sep, fill, labels, append) :
argument 1 (type 'list') cannot be
Dear all,
Following the advice of David Winsemius, I've restarted my R session : I was
able to load rgl library (rgl_0.92.892)
Sorry to have bothered you.
Next time, I'll include this step before submitting to R-help ;).
Anyway, thanks for support.
Bests,
=
library(rgl)
On Jul 27, 2012, at 03:48 , David Winsemius wrote:
On Jul 26, 2012, at 4:46 AM, Guillaume Meurice wrote:
Dear all,
I was willing to use the library rgl to plot some 3D graphics, but
unfortunately, I wan't able to instal the library. The error message is
below.
I would be very
Now i'm scratching my head as well, thought it might have to do with scaling at
first, so i turned it off, and also tried scaling the data for the plot
instead, but to no avail, it just switches the color, but doesn't show the
correct contours.
And it is at least predicting the stuff right, so
On Jul 26, 2012, at 9:00 AM, suman kumar wrote:
Dear all,
I have been trying to plot hazard function in R for survival data,
but in
vain.
Can anybody help me out in plotting hazard function in R?
I'm thinking this might not be what you want, although it is one
plausible guess at what
How about this?
Andpleasemakeusofthelargekeyatthebottomofyourkeyboard.Itmakescodemuchmorereadable.
library(ggplot2)
spd - factor(c(s,f,f,s,f,s,s,s,f,f,s,f))
r - c(4.9,3.2,2.1,.2,3.8,6.4,7.5,1.7,3.4,4.1,2.2,5)
dataset - data.frame(spd, r)
dataset - rbind(cbind(dataset, Type = DOE, delta = 2),
On Jul 26, 2012, at 10:06 AM, FJ M wrote:
It would be a useful additon to the help page to add
integrate(dnorm, lower = -1.96, upper = 1.96, mean = 2, sd = 1)
Wouldn't most statisticians instead use the more accurate and
undoubtedly faster:
pnorm(1.96, mean=2, sd=1) - pnorm(-1.96,
On 27/07/2012 09:14, peter dalgaard wrote:
On Jul 27, 2012, at 03:48 , David Winsemius wrote:
On Jul 26, 2012, at 4:46 AM, Guillaume Meurice wrote:
Dear all,
I was willing to use the library rgl to plot some 3D graphics, but
unfortunately, I wan't able to instal the library. The error
On Jul 27, 2012, at 12:14 AM, Krunal Nanavati wrote:
Hi Jeff,
Sorry for the previous email.
I tried using write function, and used the following syntax
write(result,file=C:\\Users\\Krunal\\Desktop\\Book1.csv)
but it is giving the following error
Error in cat(list(...), file, sep, fill,
Found it depends on what you put in in slice, since you have to define at what
constant the other variables should be held.
sl-list(V3=17,V4=14,V5=4,V6=0.5,V7=26,V8=10,V9=15,V10=0,V11=0.4,V12=0.3,V13=1.2,V14=2.3,V15=4.2,V16=5.2,V17=5.1,V18=4.3,V19=3.35)
plot(model,data,V1~V2,slice=sl)
For
On 07/26/2012 01:50 AM, David L Carlson wrote:
We often refer requesters to the Posting Guide and chide them for not
reading it.
...
I hesitate to sound too optimistic, but there might be some advantage in
making the statement more prominent and adding a reproducible example using
dput().
The
Dear list,
I try to use the eval function and to understand its functionning. I tried:
xy - global
f1 - function(){
xy - f1
a1 - eval.parent(xy)
b1 - eval(xy, sys.frame(0))
print(paste(a1 =,a1))
print(paste(b2 =,b1))
f3 - function(){
print(F3)
a3 - eval.parent(xy)
On 07/26/2012 10:27 PM, Henrik Singmann wrote:
Dear Waheed,
As you correctly inferred, these are just warnings and dont need to
bother you now. The maintainer/author of the taylor.diagram function
should be more worried.
These warnings just say that in upcoming versions of R the functions
Hello,
I am wanting to download the Vegan package zip file. When I tried to
do this I obtained the following message:
Object not found! The requested URL was not found on this server.
The link on the referring page seems to be wrong or outdated. Please
inform the author of that page about
On Thu, Jul 26, 2012 at 9:48 PM, Diviya Smith diviya.sm...@gmail.com wrote:
Hi there,
I would like to solve a simple equation in R
a^2 - a = 8.313
There is no real solution to this problem but I would like to get an
approximate numerical solution. Can someone suggest how I can set this up?
On Fri, Jul 27, 2012 at 1:21 AM, OTB olibir...@gmail.com wrote:
Hi all,
I'm a newbie to R and it has been very helpful to use your website.
Unfortunately I've been struggling with my code now for two days so I wanted
to ask few questions. I've been trying to create nice graphs to put into a
Thank you Rui.
With matrix works better. I got plot I have expected to have.
I want to be undirected. But
directed = FALSE
or
as.undirected(graph)
are not working? Where I'd gone wrong?
Shouldn't it be possible to add names instead of numbers of nods with
vertex.label= ?
2012/7/26 Rui
Hi everyone,
I'm working with the Vector Autoregressive Model (VAR), and it seems like
the ur.ca package provides the best
function for this purpose.
My problem is, that I don't know how to extract a certain value from the
output without using the variables names.
I was hoping that this could
Hi David,
Thanks for the reply.
With your first alternative, I am getting the beta values in different
cells in the excel file.
Is there a way to get all the information generated by the summary
function in different cells in a excel file, through the write function?
Also, can you please
hello everyone,
I'm modelling in lmer an average chick weight defined as
Total.brood.mass ~ offset(chick.number), with three fixed and two
random effect. Next, I want to use function dredge from MuMIn package
for model averaging. Not sure why, but in consequence the offset
variable is treated as
Hello,
I am an R user who wants to solve an optimization problem. To do so, I tried to
install the package Rcplex on my computer (Windows7-64), so I did the same as
installation Instructionshttp://www.geeklog.net/docs/english/install.html and
edited the file Makevars.win by adding the path
Dear R-help members,
I did the following pie chart:
R:Code=
plants-c(11,5,4,4,4,3,3,3,3,3,3,2,2,2,2,2,2,43)
pie(plants,labels =plant_labels,cex=0.7, col=colors)
par(mar=c(0,0,4,0),oma=c(0,0,0,0))
legend(1,1,cex=0.7,pt.cex=25,
You really need to discuss this with the package maintainer (as the
posting guide asked).
But there are several 'optimization' packages on CRAN which do have
Windows' binary versions that would therefore be easier to use.
On 27/07/2012 09:38, Shima Shahbazi wrote:
Hello,
I am an R user
Hello,
Here is a function that I wrote some time ago.
# pad with zeros
padz - function(x, width=max(nchar(x)), fill=0)
gsub( , fill, formatC(x, width=width))
##- test
padz( c(1, 10, 100) )
padz(1:10, 4)
##- non-sense
padz(-5:0, 4)
padz(runif(10))
Hope this helps,
Hello,
If it's the title, i.e., the header of a table read in by read.csv maybe
names(fx1)
is better, since data.frames are special cases of lists. The end result
is of course the same.
Hope this helps,
Rui Barradas
Em 27-07-2012 05:22, Daniel Nordlund escreveu:
-Original
On Jul 27, 2012, at 11:23 , Stéphane Dray wrote:
Dear list,
I try to use the eval function and to understand its functionning. I tried:
xy - global
f1 - function(){
xy - f1
a1 - eval.parent(xy)
b1 - eval(xy, sys.frame(0))
print(paste(a1 =,a1))
print(paste(b2 =,b1))
f3 -
Hi!
I'm failing to understand the value of the intercept value in a
multiple linear regression with categorical values. Taking the
warpbreaks data set as an example, when I do:
lm(breaks ~ wool, data=warpbreaks)
Call:
lm(formula = breaks ~ wool, data = warpbreaks)
Coefficients:
(Intercept)
Hello,
I'm not familiar with package urca but your problem seems to be in the
access of a list member.
The operator '$' is an alternative to '[[', and you are right, the
latter is recommended programmatically.
Try something along the lines of the following.
VARrow[[ varresult ]][[
On Jul 27, 2012, at 11:05 , Prof Brian Ripley wrote:
On 27/07/2012 09:14, peter dalgaard wrote:
I believe we have seen the R_decompress1 error before, though. If you can
reproduce it, it might be worth digging deeper --- over on R-sig-Mac.
It almost always indicates a corrupted lazyload
Thanks Peter. Sorry for this question... I really need holidays.
Cheers.
On 27/07/2012 13:30, peter dalgaard wrote:
On Jul 27, 2012, at 11:23 , Stéphane Dray wrote:
Dear list,
I try to use the eval function and to understand its functionning. I tried:
xy - global
f1 - function(){
xy -
Hello,
As for the directed = FALSE, it works with me:
g - graph(given, directed = FALSE)
As for the label, it's easy. Create an attribute 'name' and then set the
label to that attribute. For instance, using the alphabet's letters,
first uppercase.
V(g)$name - c(LETTERS, letters)[V(g)] #
Hi Michael,
I see some confusion here. The objects() command does not list
objects in the WorkingDirectory, but objects in your R environment.
R environments do not have directories or sub-directories, so I'm
finding your question very confusing. Can you clarify?
Best,
Ista
On Thu, Jul 26, 2012
Dear David and Paul,
Thank you for your answers!
Yes, Paul, I checked the SPSS file and the numerical variables that had no
value labels assigned to them in SPSS got the right measurements in R after
importing, namely interval. The two variables that had the measurement
nominal in R allthough
Joao,
There's a very thorough explanation at
http://www.ats.ucla.edu/stat/r/library/contrast_coding.htm
Jean
Joao Azevedo joao.c.azev...@gmail.com wrote on 07/27/2012 06:32:31 AM:
Hi!
I'm failing to understand the value of the intercept value in a
multiple linear regression with
Hi!
Thanks for the link. I've already stumbled upon that explanation. I'm
able to understand how the coding schemes are applied in the supplied
examples, but they only use a single explanatory variable. My problem
is with understanding the model when there are multiple categorical
explanatory
Thank you!
It works fine now! :)
2012/7/27 Rui Barradas ruipbarra...@sapo.pt
Hello,
As for the directed = FALSE, it works with me:
g - graph(given, directed = FALSE)
As for the label, it's easy. Create an attribute 'name' and then set the
label to that attribute. For instance, using the
Michi,
The code that you shared was incomplete. Two objects (plant_labels and
colors) were not defined.
The pie chart would be easier to interpret by direct labeling of slices,
rather than trying to decipher a color legend. If you change the initial
angle of the first slice, you can rotate
Greetings,
I am puzzled about why the _classical_ Mahalanobis distances that I get using
the {stats} mahalanobis() function do not match the distances I get from the
{robustbase} covMcd() function. Here is an example:
x - matrix(rnorm(10*3), ncol = 3)
#here is the {stats} result:
Sx - cov(x)
D2
Hi All,
I am trying to creat a simple example byusing ipf function in R, but i
could not get it succefully...I am very new to R, does anyone could help,
to instruct me about this ipf fucntion?
Actually, this is what I mean
50 | 50
--
Dear Jim,
indeed, you are right. As the OP did not include the package name I was to lazy
to check where taylor.diagram actually is from. Would I have known that it is
from plotrix I would have seen
that it actually is not a problem of the author but of handing over the wrong
object.
As I
Joao,
Your intuition is correct, the intercept represents the predicted value
for wool A and tension L. But, you're tripping up on how to figure out
that predicted value. In the model that you fit, the predicted value for
wool A and tension L is not simply the mean of the observations for
-Original Message-
From: j...@bitwrit.com.au
Sent: Fri, 27 Jul 2012 19:21:36 +1000
To: dcarl...@tamu.edu
Subject: Re: [R] On Reproducible Code
On 07/26/2012 01:50 AM, David L Carlson wrote:
We often refer requesters to the Posting Guide and chide them for not
reading it.
...
Hello,
I am working on my thesis and can't really figure out how to produce a
reasonable graph from the output from my glm.,
I could just give the R-output in my results and then discuss them, but it
would be more interesting if I could visualise what is going on.
My research is how bees react
HI Rui,
Not sure how to place the - before the zeros.
padz(-5:0,4)
[1] 00-5 00-4 00-3 00-2 00-1
padz(-(5:0),4)
[1] 00-5 00-4 00-3 00-2 00-1
formatC(-5:0,width=4,format=d,flag=0)
[1] -005 -004 -003 -002 -001
padz(1:-10,4)
[1] 0001 00-1 00-2 00-3 00-4 00-5 00-6 00-7 00-8
Obermeier Andrew andrewobermeier at me.com writes:
Hello, I just joined this list today, so am worried about proper
protocol, but would like to post a question about lme4.
You should probably join/post this question to the r-sig-mixed-models
at r-project.org mailing list, which is
Bob Green bgreen at dyson.brisnet.org.au writes:
I am wanting to download the Vegan package zip file. When I tried to
do this I obtained the following message:
Object not found! The requested URL was not found on this server.
The link on the referring page seems to be wrong or outdated.
HI Rui,
i found it. Though, it doesn't make much sense, trying to be consistent with
formatC.
padz - function(x, width=max(nchar(x)), fill=0)
gsub( ,fill, formatC(x,width=width,flag=0))
padz(-5:0,4)
[1] -005 -004 -003 -002 -001
A.K.
- Original Message -
From: Rui Barradas
Hello,
I would like to run a series of regressions on my data (response variable
over time):
1) regression from T1 to T2
2) regressions from T1 through T3
3) regression from T1 through T4, etc.
I have been struggling to find a way to do this through commands, as
opposed to cutting up the data
Dear Babs,
This is how I would present the model, if I had enough data to support the
model. The model is too complicated for your data and leads to a perfect fit.
Is this the aggregated dataset, or does your design has no replicates?
Best regards,
Thierry
dataset$combinatie -
I agree and would like to see it placed at the **TOP** of every post.
-- Bert
On Fri, Jul 27, 2012 at 7:11 AM, John Kane jrkrid...@inbox.com wrote:
-Original Message-
From: j...@bitwrit.com.au
Sent: Fri, 27 Jul 2012 19:21:36 +1000
To: dcarl...@tamu.edu
Subject: Re: [R] On
Hi, I have a matrix that I am displaying via image. I would like to
obtain an image where the columns are 'grouped' (I have a grouping
variable). But I am not sure how how I can draw the lines to indicate
the grouping in the margin. I realize this is essentially waht heatmap
does but as I have a
You could have googled R solve equation, and would have easily reached
http://r.789695.n4.nabble.com/R-solve-equation-td882585.html
and would have in there found something like this:
z - matrix(c(-8.313,-1,1), ncol=1)
polyroot(z)
[1] 3.42626+0i -2.42626+0i
p-polyroot(z)
p^2-p
[1] 8.313+0i
I just realize this:
For myVar1, I used colnames to name it firstly, and then convert myVar1 to
numeric;
However, I forgot to use rownames to name myVar2, instead I thought
as.numeric(names(myVar2)) would work.
Now I name myVar2 using rownames first, as.numeric(names(myVar2)) is
working.
Dear R users,
we proudly announce the latest release of our R package plsdof: Degrees
of Freedom and Statistical Inference for Partial Least Squares.
Features include:
* Degrees of Freedom estimates for Partial Least Squares (PLS) Regression
* Model selection for PLS based on various
This solution was the most elegant. Thanks everyone.
Josh
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Thursday, July 26, 2012 9:55 PM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] add leading zeros
Much easier than you think:
Hello -
When I export my files using the write.table command and name the file.xls
and use the sep=/t to try and separate the columns in excel, everything
just stays in one column. how do i get them all into separate columns (it
did this before but i can't figure out what's different between
I'd vote for that!
It would probably bug the blazes out of experienced users but the time savings
in getting a newbie to actually supply enough information so that someone can,
at least, try to answer the question would be well worth it.
John Kane
Kingston ON Canada
-Original
I think you have a type: Try \t
John Kane
Kingston ON Canada
-Original Message-
From: watson...@hotmail.com
Sent: Fri, 27 Jul 2012 09:30:34 -0700 (PDT)
To: r-help@r-project.org
Subject: [R] Separating Columns in Excel Export from R
Hello -
When I export my files using the
On Jul 27, 2012, at 3:10 AM, Krunal Nanavati wrote:
Hi David,
Thanks for the reply.
With your first alternative, I am getting the beta values in different
cells in the excel file.
Is there a way to get all the information generated by the summary
function in different cells in a excel file,
On Jul 27, 2012, at 4:34 AM, Rui Barradas wrote:
Hello,
I'm not familiar with package urca but your problem seems to be in
the access of a list member.
The operator '$' is an alternative to '[[', and you are right, the
latter is recommended programmatically.
Try something along the
No, this is not what i wanted.
Plotting of survfit object in therneu's survival package plots
survival/cumulative incidence and cumulative hazard function for a
given fit.
What I wanted to know was that is there a way to plot hazard function of a plot?
I got the reply from Dr Therneu yesterday.
That assumes:
* Everyone reads the mailing list before making the first posting
* Everyone reads every part of every email.
I'd argue that both assumptions are false. People are particular well
trained to skip over boilerplate text at the bottom of emails.
I'd suggest an alternative approach
Hello,
I agree with you. That's why I've proposed an itemized text.
I want my VCR manual to give me point by point instructions, not to give
me a clear and brief discourse on exactly what to do. And, though
without access to VCR manufacturers' data tables, I'm with the
impression that their
Dear List,
how can I draw the following path diagram
A B C D E F
\ | / \ | /
G -- H
/ \/ \
I JK L
the problem I've got is that G and H need to be horizontally alingned
but the best I've done is diagonally or vertically alingned,
kind regards,
Rene
## Begin: R-code
On 2012-07-27 09:30, watsonl wrote:
Hello -
When I export my files using the write.table command and name the file.xls
and use the sep=/t to try and separate the columns in excel, everything
just stays in one column. how do i get them all into separate columns (it
did this before but i can't
I would like to be able to refer briefly to longer explanations such as the
stackoverflow article on reproducible examples rather than patiently rewrite
such explanations. A posting guide with more specific recommendations would
make it easier to be patient.
On Fri, Jul 27, 2012 at 10:47 AM, Hadley Wickham had...@rice.edu wrote:
That assumes:
* Everyone reads the mailing list before making the first posting
* Everyone reads every part of every email.
I'd argue that both assumptions are false. People are particular well
trained to skip
hi all,
I want to get a cumsum according to the order of some variable.
However, it doesnt' work.
For example,
**
test-data.frame(cbind(x=c(3,5,2,6,7),y=c(8,1,4,9,0)))
test[order(test$x),]$sumy-cumsum(test[order(test$x),]$y)
**
R complians Warning message:
Philippe,
In your example, you have four unique values for Yrs (I had to change your
code a little to get it to run, so I have the modified version with my
code below), and those values are what you are referring to when you say
T1, T2, T3, T4, right? If I follow what you want to do, the code
test-data.frame(cbind(x=c(3,5,2,6,7),y=c(8,1,4,9,0)))
test[order(test$x),]$sumy-cumsum(test[order(test$x),]$y)
is asking a bit too much of R. If you add the line
test$sumy - numeric(nrow(test))
between those lines you get what you want.
Here are the details. The nested replacement
cowboy wrote
hi all,
I want to get a cumsum according to the order of some variable.
However, it doesnt' work.
For example,
**
test-data.frame(cbind(x=c(3,5,2,6,7),y=c(8,1,4,9,0)))
test[order(test$x),]$sumy-cumsum(test[order(test$x),]$y)
**
R
This has nothing to do with order(). The following also reproduces the behavior:
test - data.frame(x=letters[1:5],y = 1:5)
test[1:5,]$z - 11:15
Warning message:
In `[-.data.frame`(`*tmp*`, 1:5, , value = list(x = 1:5, y = 1:5, :
provided 3 variables to replace 2 variables
test
x y
1 a 1
2
Try this:
# define the locations on the x axis for each cell in the image
nxcells - dim(m)[2]
xlocs - (seq(nxcells)-1)/(nxcells-1)
# define the groupings
group - rep(1:3, c(10, 20, 25))
# calculate the range of locations on the xaxis for each group
group.ranges - sapply(split(xlocs, group),
It is not clear what you are trying to do. The ipf() function you are using
seems to be the one included in package cat for imputing missing values for
categorical variables. For ipf() you have not read the instructions
carefully because you have entered the marginal values, not their dimensions
Hi All,
I want to turn a categorical array (array with factors) into a matrix with
dummy variables. like array=c(a,a,b,b,b) should be turned into:
a b
1 0
1 0
0 1
0 1
0 1
Do you know any way of doing this?
Thanks
--
View this message in context:
Dear list members
I need a function that calculates the bivariate normal distribution for each
observation. It is part of a likelihood function and I have 1000's of cases. As
I understand it I cannot use packages like mvtnorm because it requres a
covariance matrix of the same dimension as
Hi Joshua ,
but, how can I do this?
Thanks
--
View this message in context:
http://r.789695.n4.nabble.com/odd-error-with-rJava-tp4462986p4638139.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Replying to quite old thread..but its awesome
RWeka package is quite good in dissecting the tree in more than 2 parts.
As someone said J48 which is implementation of C4.5 and thus ID3 will be
helpful.
Also to plot you may have to rage a war like situation.
Let us knoe if you face any problem
Hi all,
I'm sorry, I didn't notice this comment. Thank you Gabor for letting me
know. Following is a reproducible code and a new picture. The questions are
the same but I've figured little bit out how to use textplot but I would
like to have the table little bit more professional, maybe better to
Dear Users,
i have this time series, the tree lines means different level, i would use
a Markov switching model with two states to modelling this time series. i
would obtain the relative transition matrix (2X2)
the first state is above the value of 23.65 (the higher line)
the second state is
Hello,
I am using vegan to do an NMDS plot and I would like to suppress the labels
for the loading vectors. Is this possible? Alternatively, how can I avoid
overlap?
Many thanks for the help.
Example code:
#perform NMDS using metaMDS() function
spe.nmds-metaMDS(data, distance='bray',k=2 ,
I would like to load a binary file into R using load(), and then assign a new
name to it, regardless of the name it was saved under. Can you please
provide a code sample? Thank you!
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THANK YOU
R is s picky :)
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HI,
I guess you want to get the cumsum of y according to the order of x,
test1-test[order(test$x),]
test2-within(test1,{cumsumy-cumsum(y)})
test2
# x y cumsumy
#3 2 4 4
#1 3 8 12
#2 5 1 13
#4 6 9 22
A#5 7 0 22
A.K.
- Original Message -
From: cowboy
On 2012-07-27 05:50, Obermeier Andrew wrote:
Hello,
I just joined this list today, so am worried about proper protocol, but would
like to post a question about lme4.
The R-sig-mixed-models list
(https://stat.ethz.ch/mailman/listinfo/r-sig-mixed-models) may be a
better place for questions
Hi,
I would like to analyze some agilent aCGH copy number files. As a start, I
would like to normalize this data. I don't know what is the standard way to
do this. Which package is the standard one that people use for this
purpose? The chips that I am looking at are the agilent sure print 1M
?model.matrix
On Fri, Jul 27, 2012 at 11:32 AM, xuan zhao xuan.z...@sentrana.com wrote:
Hi All,
I want to turn a categorical array (array with factors) into a matrix with
dummy variables. like array=c(a,a,b,b,b) should be turned into:
a b
1 0
1 0
0 1
0 1
0 1
Do you know any way of
On 27/07/12 20:55, David Winsemius wrote:
On Jul 26, 2012, at 10:06 AM, FJ M wrote:
It would be a useful additon to the help page to add
integrate(dnorm, lower = -1.96, upper = 1.96, mean = 2, sd = 1)
Wouldn't most statisticians instead use the more accurate and
undoubtedly faster:
On 28/07/12 05:45, Anders Holm wrote:
Dear list members
I need a function that calculates the bivariate normal distribution for each observation.
It is part of a likelihood function and I have 1000's of cases. As I understand it I
cannot use packages like mvtnorm because it requres a
Here is one way. You seem to assume that the save file contains
exactly one object and this function makes the same assumption:
theObjectSavedIn - function(saveFile) {
env - new.env()
load(saveFile, envir=env)
loadedObjects - objects(env, all=TRUE)
On 28/07/12 06:59, Alireza Mahani wrote:
I would like to load a binary file into R using load(), and then assign a new
name to it, regardless of the name it was saved under. Can you please
provide a code sample? Thank you!
Ummm, what is the antecedent of the pronoun it in the forgoing?
The
On Fri, Jul 27, 2012 at 6:47 PM, Hadley Wickham had...@rice.edu wrote:
I'd argue that both assumptions are false. People are particular well
trained to skip over boilerplate text at the bottom of emails.
One day the list owner will subtly change the boilerplate text at the
bottom of R-help
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