-project.org; Thomas Lumley
Subject: Re: [R] median of two groups
Thank you very much for that.
What is then if I have unpaired and unbalanced samples?
Best regards,
Cheba
2010/5/7 Bert Gunter gunter.ber...@gene.com
Perhaps this might help clarify:
sample A: 10 15 20
-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of cheba meier
Sent: Monday, May 10, 2010 3:02 AM
To: Bert Gunter
Cc: R-help@r-project.org; Thomas Lumley
Subject: Re: [R] median of two groups
Thank you very much for that.
What is then if I have unpaired and unbalanced
-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
Behalf Of cheba meier
Sent: Friday, May 07, 2010 12:46 PM
To: Joris Meys
Cc: R-help@r-project.org; Thomas Lumley
Subject: Re: [R] median of two groups
Hi all,
Thank you for your reply.
if done properly! What does
Dear Thomas,
I have been running simulations in order me to understand this problem! I
have found something online where the absolute median difference is computed
and permutations are ran to compute a p-value. Is such a test (if I can call
it a test) tests the null hypothesis that median group 1
That's a robust way of obtaining a p-value, and can be classified as a test.
The important trick here is to take into account that you have two tails in
a distribution. If the p-value is calculated taking both tails into account,
then it indeed tests the null hypothesis that median group1 - median
Subject: Re: [R] median of two groups
Dear Thomas,
I have been running simulations in order me to understand this problem!
I
have found something online where the absolute median difference is
computed
and permutations are ran to compute a p-value. Is such a test (if I can
call
it a test
On Fri, 7 May 2010, cheba meier wrote:
Dear Thomas,
I have been running simulations in order me to understand this problem! I
have found something online where the absolute median difference is computed
and permutations are ran to compute a p-value. Is such a test (if I can call
it a test)
depends on how you interprete absolute median difference. Is that the
absolute difference of the medians, or the median of the absolute
differences. Probably the latter one, so you would be right. If it's the
former one, then it is testing whether the difference of the medians is
zero.
Cheers
Hi all,
Thank you for your reply.
if done properly! What does this mean? The R-code I have is using the
R-function sample without replacement. Am I doing this properly?
median of the differences is zero! Does this mean if I run 1000 permutation
and for each permutation I compute the median
On Fri, May 7, 2010 at 9:45 PM, cheba meier cheba.me...@googlemail.comwrote:
Hi all,
Thank you for your reply.
if done properly! What does this mean? The R-code I have is using the
R-function sample without replacement. Am I doing this properly?
median of the differences is zero!
This is
-project.org; Thomas Lumley
Subject: Re: [R] median of two groups
Hi all,
Thank you for your reply.
if done properly! What does this mean? The R-code I have is using the
R-function sample without replacement. Am I doing this properly?
median of the differences is zero! Does this mean if I run 1000
Dear Thomas,
Thank you very much for your answer! Can I use your function in my analysis?
The wilcox.test() tests the differences in average ranks (H0: F(X)=F(Y)),
why then do people in many studies compare t.test() with wilcox.test()?
This makes sometime people like me a bit confused!
On Wed, 7 Apr 2010, cheba meier wrote:
Dear Thomas,
Thank you very much for your answer! Can I use your function in my analysis?
Sure.
The wilcox.test() tests the differences in average ranks (H0: F(X)=F(Y)),
why then do people in many studies compare t.test() with wilcox.test()?
The
Dear all,
What is the right test to test whether the median of two groups are
statistically significant? Is it the wilcox.test, mood.test or the ks.test?
In the text book I have got there is explanation for the Wilcoxon (Mann
Whitney) test which tests ob the two variable are from the same
None of them.
- mood.test() looks promising until you read the help page and see that it
does not do Mood's test for equality of quantiles, it does Mood's test for
equality of scale parameters.
- wilcox.test() is not a test for equal medians
- ks.test() is not a test for equal medians.
15 matches
Mail list logo
