On Tue, 2003-06-10 at 08:37, Randy Perkins wrote:
> On Tue, 2003-06-10 at 02:09, Manuel Aróstegui Ramirez wrote:
> and that will kill X
> however i would like to do something cleaner,
> so that i am properlys shutting down kde
>
Try something like '/sbin/init 3'. that will take you out of runlevel
On Tue, 2003-06-10 at 02:09, Manuel Aróstegui Ramirez wrote:
> Use ps -aux to find the PID, which is called X and
> kdm, and kill them with: kill -9 PID
>
hello
thanks for your response
i have used
# kill $(pidof X)
and that will kill X
however i would like to do something cleaner,
so
from the kde menu,
> or use
> .
>
> how can i cleanly shutdown kde and Xserver from
> within a bash
> script. thanks, Randy
>
>
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>
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> https://www.redhat.com/mailman/l
hello,
i need to shut down my X server before i use software suspend.
i am using kde, and can "logout" from the kde menu, or use
.
how can i cleanly shutdown kde and Xserver from within a bash
script. thanks, Randy
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On Thu, 3 Apr 2003, Ron Franke wrote:
> I'm having a strange problem with a bash script when trying to cd with a
> $variable. A simple example script follows. The issue is on the line
shopt -s cdable_vars
--
Guvf gntyvar jnf rapbqrq jvgu gur ebg13.fu fpevcg, ninvyn
Thanks.
Bret Hughes wrote:
On Thu, 2003-04-03 at 17:54, Ron Franke wrote:
Hi:
I'm having a strange problem with a bash script when trying to cd with a
$variable. A simple example script follows. The issue is on the line
with cd ${copydir}. I'm wondering if there
Thanks.
[EMAIL PROTECTED] wrote:
Yeah, I tried the script too and it works fine.
Carlo Aureus
On 3 Apr 2003, Bret Hughes wrote:
On Thu, 2003-04-03 at 17:54, Ron Franke wrote:
Hi:
I'm having a strange problem with a bash script when trying to cd w
Yeah, I tried the script too and it works fine.
Carlo Aureus
On 3 Apr 2003, Bret Hughes wrote:
> On Thu, 2003-04-03 at 17:54, Ron Franke wrote:
> > Hi:
> >
> > I'm having a strange problem with a bash script when trying to cd with a
> > $variable. A si
On Thu, 2003-04-03 at 17:54, Ron Franke wrote:
> Hi:
>
> I'm having a strange problem with a bash script when trying to cd with a
> $variable. A simple example script follows. The issue is on the line
> with cd ${copydir}. I'm wondering if there is a bash issue or somet
To: [EMAIL PROTECTED]
Subject: Strange Bash Script Behavior -- Doesn't Recognize $variable in
cd Statement
Hi:
I'm having a strange problem with a bash script when trying to cd with a
$variable. A simple example script follows. The issue is on the line
with cd ${copydir}. I'm won
Hi:
I'm having a strange problem with a bash script when trying to cd with a
$variable. A simple example script follows. The issue is on the line
with cd ${copydir}. I'm wondering if there is a bash issue or something
in my environment that I'm missing. I have RedHat 8.0 and
On Thu, 2003-04-03 at 07:50, santosh kumar wrote:
> Hi guys,
>
> Have small doubt in bash scripting..(#!/bin/bash)
> Need to write script to get all m/c info, If I do cat /proc/cpuinfo will
> display CPU info.
> My requirement is grep CPU model, speed and display the outputs like
> For example m/c
On Thu, Apr 03, 2003 at 10:57:31AM -0300, Rodrigo Nascimento wrote:
>
> What you want?
I believe that the poster wants our advice on how to obtain the
output he posted.
[EMAIL PROTECTED] seyman]$ cat /proc/cpuinfo | grep -E "MHz|name"
model name : Pentium III (Coppermine)
cpu MHz :
Hi,
I didn't understand.
What is wrong or confused in output for more one CPU?
1st CPU model : pentium III
1st CPU speed : 1.73 GHz
2nd CPU model : pentium IV
2nd CPU speed : 2.4 GHz
The 1st CPU is a PIII with 1.7 Ghz and 2nd CPU is a P4
with 2.4 Ghz.
What you want?
--- santosh kumar <[E
Hi guys,
Have small doubt in bash scripting..(#!/bin/bash)
Need to write script to get all m/c info, If I do cat /proc/cpuinfo will
display CPU info.
My requirement is grep CPU model, speed and display the outputs like
For example m/c has single CPU
CPU model : pentium III
CPU speed : 1.73 GHz
I
On 19 Mar 2003, will wrote:
> The .bash_logout script is not executing when my system is in run level
If your xterm is not defined as a login shell, it won't execute .bashrc or
.bash_profile, either. You may need to define the xterm as a login shell
to get .bash_logout working.
--
Guvf gntyva
TERM=xterm
COLORTERM=gnome-terminal
BTW -- I've read the man on xdm that recommends using the Xreset script
(e.g., xdm-config: DisplayManager._0.reset=/etc/X11/xdm/TakeConsole) to
run after the users session is terminated. It should contain commands
such as unmounting directories from file servers
what terminal do you use on your X Window..
Quoting will <[EMAIL PROTECTED]>:
> The .bash_logout script is not executing when my system is in run level
> init 5 (Xsession); however, in init 3 it runs fine. Any one know how
> this can be fixed?
>
> Red Hat Linux release 8.0 (Psyche) -- X
The .bash_logout script is not executing when my system is in run level
init 5 (Xsession); however, in init 3 it runs fine. Any one know how
this can be fixed?
Red Hat Linux release 8.0 (Psyche) -- X window manager is
Bluecurve/GNOME if it matters.
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[ test ]
then
Dave
-Original Message-
From: R P Herrold [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, February 05, 2003 12:11 PM
To: [EMAIL PROTECTED]
Subject: RE: Bash script help ?
On Wed, 5 Feb 2003, David Simmons wrote:
> I have noticed in this thread that everyone is puttin
On Wed, 5 Feb 2003, David Simmons wrote:
> I have noticed in this thread that everyone is putting a ";" after their
> tests: if [ test ] ; and for [ test ] ;
>
> When is the ";" required or is it always required after the test in a
> conditional statement?
Ehhh? Not all people do. I never
quot; required or is it always required after the test in a
conditional statement?
Thanks,
Dave Simmons
-Original Message-
From: Raymundo M. Vega [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, February 05, 2003 11:00 AM
To: [EMAIL PROTECTED]
Subject: Re: Bash script help ?
I think sev
undo M. Vega [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, February 05, 2003 11:00 AM
To: [EMAIL PROTECTED]
Subject: Re: Bash script help ?
I think several lines are not quite right:
- regular expression in gawk should be inside the {}, but
you will have to pass the argument to gawk.
- next line aft
=
hope it helps
raymundo
Ryan Babchishin wrote:
[EMAIL PROTECTED] wrote:
I'm trying to get a pidof a php script by capturing the path:
like /home/somebody/my_script which will be the first arg. to the bash
script
Could anybody tell me what's wrong with this scri
[EMAIL PROTECTED] wrote:
I'm trying to get a pidof a php script by capturing the path:
like /home/somebody/my_script which will be the first arg. to the bash script
Could anybody tell me what's wrong with this script ?
I'm new to scripting in general so any help would be apreci
On Wednesday, February 5, 2003, at 02:24 PM, Jan wrote:
In your awk stmt you search for '1st_arg' rather than the value of the
variable 1st_arg, which would be $1st_arg - or perhaps ${1st_arg}, as
$1 is something else...
Ok ! Thanks !
Lars
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unsubscribe mailto:[E
>Jon Haugsand wrote:
>> * [EMAIL PROTECTED]
>>
>>>#!/bin/bash
>>>1st_arg=$1
>>
>> number not allowed in front.
>>
>>
>>>prosesses=`lsof -i`
>>>prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`
>>
>> Cannot understand this to work in gawk. In any case, you might do
>> this a lot more e
Jon Haugsand wrote:
* [EMAIL PROTECTED]
#!/bin/bash
1st_arg=$1
number not allowed in front.
prosesses=`lsof -i`
prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`
Cannot understand this to work in gawk. In any case, you might do
this a lot more effective:
echo $prosessid
if [ -z
* [EMAIL PROTECTED]
> #!/bin/bash
> 1st_arg=$1
number not allowed in front.
> prosesses=`lsof -i`
> prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`
Cannot understand this to work in gawk. In any case, you might do
this a lot more effective:
> echo $prosessid
> if [ -z "$prosessid" ]
mis
[EMAIL PROTECTED] wrote:
I'm trying to get a pidof a php script by capturing the path:
like /home/somebody/my_script which will be the first arg. to the bash script
Could anybody tell me what's wrong with this script ?
I'm new to scripting in general so any help would be apreci
I'm trying to get a pidof a php script by capturing the path:
like /home/somebody/my_script which will be the first arg. to the bash script
Could anybody tell me what's wrong with this script ?
I'm new to scripting in general so any help would be apreciated !
#!/bin/bash
1st_a
On Thu, 9 Jan 2003, David Busby wrote:
> List,
> I've got a bash script, that executes other scripts (wow!) and the sub
> scripts return a value.
> How can I get the parent script to capture that return value? I've been all
> over the BASH manual (more than one h
David Busby wrote:
Here's the BASH code that I currently have
#!/bin/bash
for YEAR in 2003 2004 2005 2006
do
CMD="./import.php $YEAR"
$CMD
done
#!/bin/bash
for YEAR in $(seq 2003 1 2006)
do
./import.php $YEAR
RETVAL=$?
echo $RETVAL;
done
You can create different RETVALs if you
to the
number of items it imported.
I would like BASH to trap this value and at the end echo the total of the 4
script executions.
/B
- Original Message -
From: "Todd A. Jacobs" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, January 09, 2003 19:39
Subject:
On Thu, 9 Jan 2003, David Busby wrote:
> How can I get the parent script to capture that return value? I've been
> all over the BASH manual (more than one hour) and Google, still no luck.
Not sure what you're really trying to do. If you posted real code, that
would help.
The exit status of th
List,
I've got a bash script, that executes other scripts (wow!) and the sub
scripts return a value.
How can I get the parent script to capture that return value? I've been all
over the BASH manual (more than one hour) and Google, still no luck.
What I've tried (I can
On 07:42 20 Dec 2002, Robert P. J. Day <[EMAIL PROTECTED]> wrote:
| from the man page for bash, when you run a script normally,
| it runs as a non-login, non-interactive script. but with
| one or more options, you can run it as a login script, an
| interactive script, or both (options being some
On Fri, 2002-12-20 at 06:42, Robert P. J. Day wrote:
>
> after looking a bit more at the different ways to invoke
> a bash shell script, i'm curious about whether there are
> legitimate applications for the "non-standard" ways.
>
> from the man page for bash, when you run a script normally,
>
after looking a bit more at the different ways to invoke
a bash shell script, i'm curious about whether there are
legitimate applications for the "non-standard" ways.
from the man page for bash, when you run a script normally,
it runs as a non-login, non-interactive script. but with
one or m
i remember some scripts that test variables by the following way:
if [ "X$1" == "X" ]
obviously if $1 is null then the statement is true X==X, and if the
variable not null, the statement is false, so
if [ "X$1" == "X" ]
then
echo "arg is null"
else
echo "arg is $1"
fi
will work.
dbrett wro
Thanks to everybody for your help and explainations. I ended up with what
I needed and an explaination of how somethings work. I also have a
direction on where to learn more
thanks again
david
On Wed, 11 Dec 2002, Robert P. J. Day wrote:
> On Wed, 11 Dec 2002, dbrett wrote:
>
> > Now I am rea
On Wed, 11 Dec 2002, dbrett wrote:
> Now I am really confused!
>
> This works:
> #!/bin/bash
>
> if [ -z $1 ]; then
> echo ''
> echo "format is $0 'math equation'"
> echo "i.e. $0 (2+2)*3"
> echo ''
> exit
> fi
>
> echo $1 | /usr/bin/bc -l
assuming that
On Wed, 11 Dec 2002, dbrett wrote:
> Nope, unless I missed what you trying to get at.
>
> #!/bin/bash
>
> if [$1 == '']; then
> echo ''
> echo "format is $0 'math equation'"
> echo "i.e. $0 (2+2)*3"
> echo ''
> exit
> fi
>
> echo $1 | /usr/bin/bc -l 2>&1
; To: Robert P. J. Day
> > Cc: [EMAIL PROTECTED]
> > Subject: Re: minor bash script issue
> >
> >
> > I though your correction would work, but the output still gives me the
> > error message. I would really like to fix it, but will settle for not
> > s
On 11 Dec 2002, Bret Hughes wrote:
> format is ./bc.test.sh 'math equation'
> i.e. ./bc.test.sh (2+2)*3
>
> [bhughes@bretsony bhughes]$ bc.test.sh (2+2)*3
> bash: syntax error near unexpected token `(2+2)'
> [bhughes@bretsony bhughes]$
> [bhughes@bretsony bhughes]$ bc.test.sh '(2+2)*3'
> 12
by
Now I am really confused!
This works:
#!/bin/bash
if [ -z $1 ]; then
echo ''
echo "format is $0 'math equation'"
echo "i.e. $0 (2+2)*3"
echo ''
exit
fi
echo $1 | /usr/bin/bc -l
If you notice the only change I made was go with the better test for a
blank v
> -Original Message-
> From: dbrett [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, December 11, 2002 2:29 PM
> To: Robert P. J. Day
> Cc: [EMAIL PROTECTED]
> Subject: Re: minor bash script issue
>
>
> I though your correction would work, but the output still g
I though your correction would work, but the output still gives me the
error message. I would really like to fix it, but will settle for not
seeing the error.
#!/bin/bash
if [$1 == '']; then
echo ''
echo "format is $0 'math equation'"
echo "i.e. $0 (2+2)*3"
echo
Nope, unless I missed what you trying to get at.
#!/bin/bash
if [$1 == '']; then
echo ''
echo "format is $0 'math equation'"
echo "i.e. $0 (2+2)*3"
echo ''
exit
fi
echo $1 | /usr/bin/bc -l 2>&1 /dev/null
Here is the output
./math "2 + 3 *( 5 - 3 )" <---
On Wed, 2002-12-11 at 12:05, dbrett wrote:
> I have a bash to math calucations. It works but also complains about the
> last line, even though it works.
>
> Any ideas how to fix the problem or at least not see the error message and
> still work.
>
> #!/bin/bash
>
> if [$1 == '']; then
>
On Wed, 11 Dec 2002, Francisco Neira wrote:
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> dbrett wrote:
> | I have a bash to math calucations. It works but also complains about the
> | last line, even though it works.
> |
> | Any ideas how to fix the problem or at least not see the error
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
dbrett wrote:
| I have a bash to math calucations. It works but also complains about the
| last line, even though it works.
|
| Any ideas how to fix the problem or at least not see the error message and
| still work.
|
| #!/bin/bash
|
| if [$1 == ''];
I have a bash to math calucations. It works but also complains about the
last line, even though it works.
Any ideas how to fix the problem or at least not see the error message and
still work.
#!/bin/bash
if [$1 == '']; then
echo ''
echo "format is $0 'math equation'"
e
On Wed, 6 Nov 2002, MET wrote:
> for i in $#
> do echo Loop iteration - $i
> done
What shell? Have you read the appropriate manual? Have you bought the
appropriate O'Reilly book? Is this a homework assignment?
--
"Whenever I feel blue, I start breathing again."
raft/linux/docs/uniqlinuxfeatures/lsst/
Good luck,
Andy.
-Original Message-
From: MET [mailto:met@;uberstats.com]
Sent: Wednesday, November 06, 2002 2:07 PM
To: RedHat List
Subject: Bash Script || Loop Through Parameters
I'm trying to loop through all the parameters given to a script
Replace $# with $* in ur script..
-Original Message-
From: MET [mailto:met@;uberstats.com]
Sent: Wednesday, November 06, 2002 20:07
To: RedHat List
Subject: Bash Script || Loop Through Parameters
I'm trying to loop through all the parameters given to a script. My script
is
exe
I'm trying to loop through all the parameters given to a script. My script is
executed like so: ./app Matthew Timmy Daniel
for i in $#
do echo Loop iteration - $i
done
This loop just loops once and prints: Loop iteration - 3
Any ideas what I'm doing wrong?
Th
On Wed, 6 Nov 2002, Hella wrote:
> You want to use sed and awk for a truly robust solution.
a sadly-overlooked but useful text processing command is "expr".
$ man expr
which can do simple things like matching, extraction, length,
substr and stuff like that. check it out before going on to sed,
, 4 Nov 2002, Chad Skinner wrote:
Is there a way in a bash script to trim the spaces from the front and end of
a variable
I have a script that contains the following variable definition
BLOCKED_SERVICES="tcp,111,Sun RPC;\
udp,111,Sun RPC;\
On Mon, 4 Nov 2002, Chad Skinner wrote:
> Is there a way in a bash script to trim the spaces from the front and end of
> a variable
>
> I have a script that contains the following variable definition
>
>
> BLOCKED_SERVICES="tcp,111,Sun RPC;\
>
> -Original Message-
> From: mark
> Subject: Re: Bash Script Question
>
>
> For example, with a datafile, you could then say
> export BLOCKED_SERVICES=`cat myblocked` but where you
> need the services broken out, youi would want to use awk:
>
> # start o
On Tuesday 05 November 2002 09:51 am, Chad is done writ:
> Is there a way in a bash script to trim the spaces from the front and
> end of a variable
> I have a script that contains the following variable definition
> BLOCKED_SERVICES="tcp,111,Sun RPC;\
>
essage-
From: [EMAIL PROTECTED]
[mailto:redhat-list-admin@;redhat.com]On Behalf Of Chad Skinner
Sent: Monday, November 04, 2002 5:32 PM
To: redhat-list
Subject: Bash Script Question
Is there a way in a bash script to trim the spaces from the front and end of
a variable
I have a scri
On Mon, 4 Nov 2002, Chad Skinner wrote:
> Is there a way in a bash script to trim the spaces from the front and end of
> a variable
Not the way you're doing it. The easiest thing to do is to change your
data representation, rather than spending a lot of time trying to strip
whit
> -Original Message-
> From: Chad Skinner
> Subject: Bash Script Question
>
>
> Is there a way in a bash script to trim the spaces from the
> front and end of a variable
>
> I have a script that contains the following variable definition
>
>
>
Is there a way in a bash script to trim the spaces from the front and end of
a variable
I have a script that contains the following variable definition
BLOCKED_SERVICES="tcp,111,Sun RPC;\
udp,111,Sun RPC;\
tcp,443,Microso
gives more control, but I want to do it first en bash script just for
fun :) Any suggestion?
Regards,
Freddy Chavez.
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7;t work. I've read somewhere that
> "telnet is not interactive so it will not work". I know Perl is much better
> and gives more control, but I want to do it first en bash script just for
> fun :) Any suggestion?
The best tool for this type of work is "expect".
p [
Hope this helps,
Ken
> Date: Wed, 17 Jul 2002 20:19:36 -0500 (CDT)
> Subject: Re: Question on 'if' in bash script
>
> to access a command from within shell, enclose it in ` `
> as
> for files in `cat some.list`
> do
> blah
> etc
>
> On Wed, 17
p [
Hope this helps,
Ken
> Date: Wed, 17 Jul 2002 20:19:36 -0500 (CDT)
> Subject: Re: Question on 'if' in bash script
>
> to access a command from within shell, enclose it in ` `
> as
> for files in `cat some.list`
> do
> blah
> etc
>
> On Wed, 17 Jul 200
On Wed, 17 Jul 2002 at 5:38pm (-0700), David Busby wrote:
> How would I construct the "if" to see if a module is loaded
>
> I've tried
>
> if [ -n "lsmod |grep $module" ]
> as well as
> if [ -z "lsmod |grep $module" ]
>
The main problem with your code is that bash doens't know the stuff in th
On Wed, Jul 17, 2002 at 05:38:26PM -0700, David Busby wrote:
> How would I construct the "if" to see if a module is loaded
>
> I've tried
>
> if [ -n "lsmod |grep $module" ]
> as well as
> if [ -z "lsmod |grep $module" ]
>
> I can't get either to work...what am I doing wrong?
lsmod |grep $modu
How would I construct the "if" to see if a module is loaded
I've tried
if [ -n "lsmod |grep $module" ]
as well as
if [ -z "lsmod |grep $module" ]
I can't get either to work...what am I doing wrong?
/b
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On Wed, Jan 23, 2002 at 01:51:50PM -0600, JW wrote:
>
> if [ -n `mount |grep "/mnt/root/cschomeserver/e"` ] #if it's already mounted don't
>mount it
>
> fluorite:~ # ./test.sh
> ./test.sh: [: too many arguments
The problem in your script is that the result of the command in backquotes is
put a
On Wed, Jan 23, 2002 at 01:51:50PM -0600, JW wrote:
>
> Obviously I do not understand how to properly get a yes/no value out
> of the string returned from a nested command. If someone could
> explain even that much I'd appreciate it.
I think your syntax is squirrely. Probably don't want to be us
Hello,
I'm trying to write a bash script for a back up job. Unfortunately I'm not getting
anywhere.
>I need to mount a file system only if the filesystem is
>_not_ already mounted.
>
>I'm thinking of it like this:
Ok, I've been reading documentation and
er 04, 2001 6:38 PM
> To: [EMAIL PROTECTED]
> Subject: Re: Command-line mail syntax for bash script
>
>
> On Tue, Dec 04, 2001 at 12:47:20PM -0600, Vinny Valdez
> <[EMAIL PROTECTED]> wrote:
> | I have a quick question, I'm sure the answer is simple.
> |
> | I
On Tue, Dec 04, 2001 at 12:47:20PM -0600, Vinny Valdez
<[EMAIL PROTECTED]> wrote:
| I have a quick question, I'm sure the answer is simple.
|
| I want to do the following:
|
| 1. send an email to a list through a bash script (no interaction)
| 2. hide the recepients (bcc)
| 3.
I have a quick question, I'm sure the answer is simple.
I want to do the following:
1. send an email to a list through a bash script (no interaction)
2. hide the recepients (bcc)
3. be able to alter the from: address (or set a reply-to), to
listoperator@domain instead of [EMAIL PROTECTE
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On Fri, 23 Nov 2001, Enrico Payne wrote:
>Hi, is it possible to compile a bash script, or encrypt it, but have it
>still execute when running it form the shell?
>
>I have a number of scripts that I do not want people to edit, or see what
Hi, is it possible to compile a bash script, or encrypt it, but have it
still execute when running it form the shell?
I have a number of scripts that I do not want people to edit, or see what is
going on inside for $$$ reasons.
Any help is appreciated.
Regards
Enrico
0 more searches to perform and each one takes
> between 10 and 15 mins searching over 12,000 files. This is the first bash
> script I have evr written and I am sure it could be done better but it works
> for me for now. What I really need is a quick and dirty way for the script
> to pull t
between 10 and 15 mins searching over 12,000 files. This is the first bash
script I have evr written and I am sure it could be done better but it works
for me for now. What I really need is a quick and dirty way for the script
to pull the search words from a list so that I can go home tonight :)
The
John H Darrah <[EMAIL PROTECTED]> writes:
> On Thu, 15 Feb 2001, Jonathan Wilson wrote:
>
>
> > if [ "$1" != *.src.rpm ] && [ "$1" != *.srpm ]
>
> I didn't notice the above line in my previous post.
> Unfortunatly, the file globing is expanding to multiple
> arguments.
>
> You will have to u
Hey, cool!
The line if [ ! -z "${1##*.src.rpm}" ] && [ ! -z "${1##*.srpm}" ] works perfect, and
it got rid of the echoing "Terminated" too!
Thanks a ton dude :-)
At 03:17 PM 2/15/2001 -0800, you wrote:
>On Thu, 15 Feb 2001, Jonathan Wilson wrote:
>
>
>> if [ "$1" != *.src.rpm ] && [ "$1" !=
On Thu, 15 Feb 2001, Jonathan Wilson wrote:
> if [ "$1" != *.src.rpm ] && [ "$1" != *.srpm ]
I didn't notice the above line in my previous post.
Unfortunatly, the file globing is expanding to multiple
arguments.
You will have to use a `case' statement or other trickery.
Maybe like this:
i
In addition, I find now that it's not performing the tests anymore. As per this
example:
[root@csc003 SrcRpms]# ~/Scripts/srpm_arch_tester.sh ladeda
/root/Scripts/srpm_arch_tester.sh: [: too many arguments
i386 failed
i486 failed
i586 failed
i686 failed
athlon failed
test done
Terminated
Thou
Still no-go. Same exact message. I tried stracing it but it's didn't really tell me
anything. I also tried -noprofile, thinking that it might be the bashrc that was
different. It didn't care.
Here's the current version:
#!/bin/bash -noprofile
#srpm_arch_tester.sh
trap 'kill 0' 0 1 2 3
if [ -
On Thu, 15 Feb 2001, Todd A. Jacobs wrote:
> On Thu, 15 Feb 2001, John H Darrah wrote:
>
> > To answer your last question, "kill 0" is equivalent to
> > "kill -15 -0".
>
> This isn't a valid command. There's no signal 0 (run "kill -l" for proof),
> and no PID 0, either. What exactly is this sup
On Thu, 15 Feb 2001, John H Darrah wrote:
> To answer your last question, "kill 0" is equivalent to
> "kill -15 -0".
This isn't a valid command. There's no signal 0 (run "kill -l" for proof),
and no PID 0, either. What exactly is this supposed to accomplish?
--
Todd A. Jacobs
CodeGnome Consult
On Thu, 15 Feb 2001, Jonathan Wilson wrote:
> /root/Scripts/srpm_arch_tester.sh: [: too many arguments
> Terminated
>
>
> #!/bin/bash
> #srpm_arch_tester.sh
>
> trap 'kill 0' 0 1 2 3
>
> if [ -z $1 ]
> then
Quote your variables with double quotes like the
following:
if [ -z "$1" ]
John,
Thanks so much for helping, that really worked!
Now I have a stranger problem:
I developed this script on a RH 6.2 server and it works fine, but when O move it to
another RH 6.2 server and try to run it, I get the following error:
[root@csc003 SrcRpms]# ~/Scripts/srpm_arch_tester.sh glib
On Wed, 14 Feb 2001, rpjday wrote:
> > >Try:
> > >trap 'kill 0' 0 1 2 3
> > >
> > >This should cleanup all the children.
>
> huh? i understand all of the above except for the "kill
> 0" command. what does it mean to say "kill 0"? what
> signal is being sent to what, exactly?
To ans
On Wed, 14 Feb 2001, rpjday wrote:
> > >
> > >Try:
> > >trap 'kill 0' 0 1 2 3
> > >
> > >This should cleanup all the children.
>
> huh? i understand all of the above except for the "kill
> 0" command. what does it mean to say "kill 0"? what
> signal is being sent to what, exactly?
S
On Mon, 12 Feb 2001, Jonathan Wilson wrote:
> At 08:25 PM 2/10/2001 -0800, you wrote:
> >
> >Try:
> >
> >trap 'kill 0' 0 1 2 3
> >
> >This should cleanup all the children.
>
> Do I then need to change "function cleanup ()" to
> "function kill 0 ()" ? Can it be two words like that? or
> i
On Mon, 12 Feb 2001, Jonathan Wilson wrote:
> At 08:25 PM 2/10/2001 -0800, you wrote:
> >On Sat, 10 Feb 2001, Jonathan Wilson wrote:
> >
> >> I wonder if someone could help with a script I'm trying to
> >> write. What this script does is rebuild a src.rpm in
> >> every possible architecture, and
At 08:25 PM 2/10/2001 -0800, you wrote:
>On Sat, 10 Feb 2001, Jonathan Wilson wrote:
>
>> I wonder if someone could help with a script I'm trying to
>> write. What this script does is rebuild a src.rpm in
>> every possible architecture, and report if it's successful
>> or not, as well as log the
On Sat, 10 Feb 2001, Jonathan Wilson wrote:
> I wonder if someone could help with a script I'm trying to
> write. What this script does is rebuild a src.rpm in
> every possible architecture, and report if it's successful
> or not, as well as log the output. While writing it I
> discovered that
Howdy,
I wonder if someone could help with a script I'm trying to write.
What this script does is rebuild a src.rpm in every possible architecture, and report
if it's successful or not, as well as log the output.
While writing it I discovered that hitting ^C gave my the prompt back, but didn't
On Thu, Feb 01, 2001 at 05:40:30PM -0800, Hidong Kim <[EMAIL PROTECTED]>
wrote:
| I have the following bash script called push:
|
| #!/bin/bash
|
| pushd ()
| {
| dirname=$1
| DIR_STACK="$dirname ${DIR_STACK:-$PWD' '}"
| cd ${dirname:?"missi
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