Hi,
Thanks. Worked like a charm.
Also thanks for SqlAlchemy. A refreshing change for someone from java
background.
I am using this with Jython. Thanks for the Jython support also.
Steve
On Jan 18, 8:54 pm, Michael Bayer mike...@zzzcomputing.com wrote:
On Jan 18, 2011, at 9:11 AM, Steve
Maybe you can squelch the exception by using a synonym with the descriptor
argument to map to a fake property.
Oooh, I had not come across this construct before - looks as if it
might do exactly what I want. I might even be able to make a decorator
that wraps this all up nicely. Thank you
hi list,
I have the following (elixir) definitions
class Invoice(Entity):
user_name = Field(Unicode(255))
item = ManyToOne(Item)
class Item(Entity):
item_id = Field(Integer, primary_key=True)
service_id = Field(Unicode(255), primary_key=True)
item_class =
On Jan 20, 2011, at 2:04 AM, bool wrote:
If I dont use autocommit:True option, it seems the driver will be in a
chained transaction mode and results in every single statement
(including selects) being run in a new transaction. This is not
desirable either.
Is there a way out ?
The
its a little unfortunate that Invoice.item.distinct() is recursion overflowing
like that, but in general if you want to select distinct Item objects you'd be
saying query(Item).distinct().
not sure I understand what invoices that have distinct items means. I
understand invoices that have
Hi Michael,
thank you very much for your prompt answer.
What I want to achieve is, counting the number of distinct items,
grouped by user_name
Given
Item1:
item_id = 1
service_id = 'test'
item_class = 'dummy'
Item2:
item_id = 2
service_id = 'other'
item_class = 'dummy'
from sqlalchemy import func, distinct
query(Invoice.user_name,
func.count(distinct(Item.id))).join(Invoice.items).group_by(Invoice.user_name)
On Jan 20, 2011, at 9:51 AM, NiL wrote:
Hi Michael,
thank you very much for your prompt answer.
What I want to achieve is, counting the number
thanks again
but the unicity of Item is guaranteed by the triplet of PK
I can't just discriminate the distinct() based on the item_id only (it
is not unique by itself in my set of data)
--
You received this message because you are subscribed to the Google Groups
sqlalchemy group.
To post to
session.query(Invoice.user_name,
Item).join(Invoice.item).distinct().from_self(Invoice.user_name,
func.count(1)).group_by(Invoice.user_name)
On Jan 20, 2011, at 11:45 AM, NiL wrote:
thanks again
but the unicity of Item is guaranteed by the triplet of PK
I can't just discriminate the
Hello!
I have gtk application with sqlite db, contain russian words.
My model
code
class Patient(Base):
lastname = Column(Unicode)
/code
Search operation
code
patients = self.session.query(Patient)
lastname = unicode(self.lastname_entry.get_text())
if lastname:
patients =
Hi All,
After some additional peeking around I decided to do a test with
SQLAlchemy alone.
I took the tutorial fr0m the book Essential SQLAlchemy as my guide.
This is what I got working.
# testing the func following the tutorial in the book Essential SQLALchemy
#pg.25
from sqlalchemy
+1
2011/1/16 Jan Müller m...@dfi-net.de:
+1
On Jan 15, 9:58 am, Eric Ongerth ericonge...@gmail.com wrote:
+1
On Jan 13, 5:08 pm, rdlowrey rdlow...@gmail.com wrote:
To Michael Bayer: sqlalchemy simplifies my life every day and makes me
vastly more productive! Many thanks.
--
That's SQLite's lower() function. If you'd like to use Python's lower()
function, you should call lower() on the string and use
column.like(mystring.lower()). But that won't do case-insensitive comparison
since you need to call lower() on the database column in the statement.
So you really
On Jan 20, 2011, at 4:53 PM, F.A.Pinkse wrote:
Hi All,
After some additional peeking around I decided to do a test with SQLAlchemy
alone.
I took the tutorial fr0m the book Essential SQLAlchemy as my guide.
very very old outdated book. If you want a current book, go to
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