Yes, I'm using Postgres.
This does exactly what I need:
session.query(Product.attribute_x, func.min(Product.price),
func.array_agg(func.distinct(Product.color))).group_by(Product.attribute_x)
Thanks Varun, that's saved me a real headache. I appreciate your help.
--
SQLAlchemy -
The Python
What database are you using?
Some databases might support this natively, others would have to be
emulated by the ORM.
I’m not a big user of the ORM, so someone else would have to help you with
that.
If you’re using Postgres, then the array_agg function on the color column
will give you exactly
Thank you Varun - what you've shown in the table is exactly what I'm
looking for.
--
SQLAlchemy -
The Python SQL Toolkit and Object Relational Mapper
http://www.sqlalchemy.org/
To post example code, please provide an MCVE: Minimal, Complete, and Verifiable
Example. See
Just so I understand what you're asking?
You want the minimum price per product (across all colors), as well as the
list of colors?
A result set looking something like this?
| Attribute | Min Price | Colors |
|---|---|--|
| Attr_1| 10|
Hi,
I would like to use distinct inside a group_by query, e.g.:
session.query(Product.attribute_x, func.min(Product.price),
distinct(Product.color)). group_by(Product.attribute_x)
That is, for each value of attribute_x, I want to find the lowest price and
all of the colors available.
I don't
On 05/30/2017 07:42 AM, Christopher Wilson wrote:
Dear Michael and fellow SQLAlchemy users/developers,
I think I have found an issue with the use of distinct() over specified
columns on a Query:
http://docs.sqlalchemy.org/en/latest/orm/query.html#sqlalchemy.orm.query.Query.distinct
As the
Dear Michael and fellow SQLAlchemy users/developers,
I think I have found an issue with the use of distinct() over specified columns
on a Query:
http://docs.sqlalchemy.org/en/latest/orm/query.html#sqlalchemy.orm.query.Query.distinct
As the Postgres documentation notes, this is a non-standard
Thanks very much! I got it to work apparently fine using from_self().
I didn't seem to need anything special for eager loads to continue to
function... were you only expecting I'd have troubles with eager loads
if I used subquery()?
On 5/30/2013 6:29 PM, Michael Bayer wrote:
On May 30,
Am 30.05.2013, 23:19 Uhr, schrieb Kent jkentbo...@gmail.com:
For example, a query may look like this:
select distinct
count(*) over () as recordcount, tablea.colx, tableb.coly
from tablea, tableb
where
limit 100
This doesn't *quite* work because the analytical window function
I allow the user to join with other tables for the purpose of filtering
(even though the joined tables won't be selected). Cartesian is
probably the wrong term for the effect, but in the end, I get duplicate
rows. I could get rid of the need for distinct by extensively using
EXISTS clauses
We use func.count().over() in order to help support result pagination.
When attempting to limit the result set, I have found that if other tables
are being joined (for the where clause, but not selected), then I need to
add DISTINCT to the query or else the Cartesian result of my query messes
On May 30, 2013, at 5:19 PM, Kent jkentbo...@gmail.com wrote:
Solution A:
Group by all columns (yielding the same effect as distinct), but which
makes the window analytical function process after the group by and yields
the correct count (17 instead of 72):
are all
Thank you, I'll try that, but quick concern: I specifically skipped
trying to use .subquery() because the docs say Eager JOIN generation
within the query is disabled.
Doesn't that mean I won't get my joinedload() results from the inner query?
Or does that refer to the outer query having
On May 30, 2013, at 6:06 PM, Kent jkentbo...@gmail.com wrote:
Thank you, I'll try that, but quick concern: I specifically skipped trying
to use .subquery() because the docs say Eager JOIN generation within the
query is disabled.
Doesn't that mean I won't get my joinedload() results from
Thanks for reply, Mariano.
j
On 05/23/2013 12:37 PM, Mariano Mara wrote:
On 05/23/2013 04:42 AM, jo wrote:
|Hi all,
I wondered if it is possible to execute a partial distinct in
sqlalchemy.
The following query works in oracle and postgresql:
select distinct col1, first_value(col2) over
|Hi all,
I wondered if it is possible to execute a partial distinct in sqlalchemy.
The following query works in oracle and postgresql:
select distinct col1,
first_value(col2) over (partition by col1 order by col2 asc)
from tmp;
How can I do such query in sqlalchemy?
Thanks for any help.
j
On 05/23/2013 04:42 AM, jo wrote:
|Hi all,
I wondered if it is possible to execute a partial distinct in sqlalchemy.
The following query works in oracle and postgresql:
select distinct col1, first_value(col2) over (partition by col1 order by
col2 asc)
from tmp;
How can I do such query in
Hello,
qry =
session.query(AssetCategory).join(Asset).join(Shot).filter(Shot.id==1).distinct()
this one already did the trick.
qry = qry.filter(Shot.id==shot_id_of_interest)
what did you add this for? The results seem to be identical...
that generates
SELECT DISTINCT AssetCategory.id
Hello,
I am stuck here with a query, it't not too complicated I think, but I dont
get it...
I have three Class/table mappings:
Shots, Assets, which belong to a Shot (1:n) and AssetCategories, which are
owned by Assets (n:1)
The objective is:
For a given shot instance get all distinct
Did you try
qry =
session.query(AssetCategory).join(Asset).join(Shot).filter(Shot.id==1).distinct()
qry = qry.filter(Shot.id==shot_id_of_interest)
that generates
SELECT DISTINCT AssetCategory.id AS AssetCategory_id
FROM AssetCategory JOIN Asset ON AssetCategory.id =
Asset.category_id JOIN Shot
How do I write an expression (in sqlalchemy 0.4.6) that will generate
the following expression:
select count(distinct field1, field2) from tableA;
I know how to do it for one field and I know how to do it with no
count using distinct=True, but not this combination.
--
You received this
Thanks.
The DB is MySQL.
On Fri, Mar 12, 2010 at 2:16 AM, Conor conor.edward.da...@gmail.com wrote:
Moshe C. wrote:
How do I write an expression (in sqlalchemy 0.4.6) that will generate
the following expression:
select count(distinct field1, field2) from tableA;
I know how to
Hi,
I've recently started learning sqlalchemy. So far, I am able to do everything I
needed with sqlalchemy query. Now, I am getting into a situation, and hope
someone would give me a suggestion. Below is my question.
My test table has two columns Name and Count
Name Count
A
I am mapping 3 tables linearly. The first 2 have a many-to-many
relation and the last one is a one-to-one relation.
I would like to get all the distinct entries from the third table.
I was not able to figure how to do the mapping. So, I tried by doing
my own set of entries outside of SA but when
Is it possible to specify a DISTINCT option to select_by()? Couldn't
find it in the docs. In general, what select() options does select_by()
take, if any?
Thx,
Rick
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