Re: [Tutor] Dictionary viceversa

On 30/07/18 19:11, Zachary Ware wrote: > On Mon, Jul 30, 2018 at 1:08 PM Alan Gauld via Tutor wrote: >> There are lots of options including those suggested elsewhere. >> Another involves using get() which makes your function >> look like: >> >> def viceversa(d): >> new_d = dict() >> for k

Re: [Tutor] Dictionary viceversa

On Mon, Jul 30, 2018 at 1:08 PM Alan Gauld via Tutor wrote: > There are lots of options including those suggested elsewhere. > Another involves using get() which makes your function > look like: > > def viceversa(d): > new_d = dict() > for k in d: > for e in d[k]: >

Re: [Tutor] Dictionary viceversa

On 30/07/18 13:40, Valerio Pachera wrote: > users = {'user1':['office-a', 'office-b'], > 'user2':['office-b'], > 'user3':['office-a','office-c']} > > It's a list of users. > For each user there's a list of room it can access to. > > I wish to get the same info but "sorted" by room.

Re: [Tutor] Dictionary viceversa

Zachary Ware wrote: > On Mon, Jul 30, 2018 at 12:20 PM Valerio Pachera wrote: >> I was looking to substiture the cicle for e in new_d like this: >> [ new_d[e].append(k) if e in new_d else new_d[e].append(k) for e in >> [ d[k] ] >> but it can't work because 'new_d[e] = []' is missing. > >

Re: [Tutor] Dictionary viceversa

On Mon, Jul 30, 2018 at 12:20 PM Valerio Pachera wrote: > I was looking to substiture the cicle for e in new_d like this: > [ new_d[e].append(k) if e in new_d else new_d[e].append(k) for e in d[k] ] > but it can't work because 'new_d[e] = []' is missing. Have a look at `dict.setdefault` and

Re: [Tutor] Dictionary Question

On Mon, May 2, 2016 at 5:28 PM Jason N. via Tutor wrote: > Hello, > Wanted to ask if its possible to have a dictionary that can be looked up > by either values? > For example, > mydic = {"A: "Apple", "B": "Banana"}When user inputs "A" I want "Apple" to > come. But if the user

Re: [Tutor] Dictionary Question

On Mon, May 2, 2016 at 8:58 PM Jason N. via Tutor wrote: > What is the best way to make dictionary requests case in-sensitive? For > example, "Apple and "apple" should bring back the same dictionary > response. Thank you. > Take a look at how the requests library solves the

Re: [Tutor] Dictionary Question

Hello, Using iteritems would be much easier approach Something like this mydic = {"A": "Apple", "B": "Banana"} for key, value in mydic.iteritems():    if value == "Apple":        print key  Thanks & BR, Bharath Shetty On Tuesday, 3 May 2016 2:57 AM, Jason N. via Tutor

Re: [Tutor] Dictionary Question

On 03May2016 00:56, Jason N. wrote: Thank you all for your responses.  A quick follow up, what is the best way to make dictionary requests case in-sensitive? For example, "Apple and "apple" should bring back the same dictionary response. Thank you. There are a few ways

Re: [Tutor] Dictionary Question

If only I understand what you mean. You can just make all the values in the dictionary lower, upper or capitalized. Then if you want take an input or whatever you want to do with it just use .lower() or .upper() or .capitalized() to convert it to what is in the dictionary. Maybe someone has a

Re: [Tutor] Dictionary Question

Thank you all for your responses.  A quick follow up, what is the best way to make dictionary requests case in-sensitive? For example, "Apple and "apple" should bring back the same dictionary response. Thank you. On Monday, May 2, 2016 6:57 PM, Bob Gailer wrote:

Re: [Tutor] Dictionary Question

On May 2, 2016 5:27 PM, "Jason N. via Tutor" wrote: > > Hello, > Wanted to ask if its possible to have a dictionary that can be looked up by either values? > For example, > mydic = {"A: "Apple", "B": "Banana"}When user inputs "A" I want "Apple" to come. But if the user enter

Re: [Tutor] Dictionary Question

On 02/05/16 22:55, isaac tetteh wrote: > > For some reason i cant find reply all . But try this > for key, value in mydic.items(): > If A==value: >Print key or as a function: def findKey(dct, val): for k,v in dct.items(): if v == val: return k mydic = {"A:

Re: [Tutor] Dictionary Question

Sorry for the if statement the correct statement should be "if 'apple' ==value:" Sent from my iPhone > On May 2, 2016, at 4:58 PM, isaac tetteh wrote: > > > For some reason i cant find reply all . But try this > for key, value in mydic.items(): > If A==value: >

Re: [Tutor] Dictionary Question

For some reason i cant find reply all . But try this for key, value in mydic.items(): If A==value: Print key Nb: use iteritems() if using python2 Sent from my iPhone > On May 2, 2016, at 4:29 PM, Jason N. via Tutor wrote: > > Hello, > Wanted to ask if its

Re: [Tutor] Dictionary on data

jarod_v6--- via Tutor wrote: > Dear All! > I have this elements > > In [445]: pt = line.split("\t")[9] > > In [446]: pt > Out[446]: 'gene_id "ENSG0223972"; gene_version "5"; transcript_id > "ENST0456328"; transcript_version "2"; exon_number "1"; gene_name > "DDX11L1"; gene_source

Re: [Tutor] Dictionary Issue

On 08/08/15 00:05, Ltc Hotspot wrote: Hi Alan, On line 15, I replaced: 'count[address] = count.get(address, 0) + 1' with 'line = Counter(address)'. line = Counter(address) will create a new Counter object with the address in it with a count value of 1. Every line in the file will create a

Re: [Tutor] Dictionary Issue

On 8/6/2015 5:30 PM, Ltc Hotspot wrote: I'm following the instructor's video exercise, available at https://www.youtube.com/watch?v=3cwXN5_3K6Q. As you're clearly interested in learning python, you may find working the tutorial beneficial as it steps you through the fundamentals of python

Re: [Tutor] Dictionary Issue

Alan, I want to find the max val , keys and values are defined on line 10: for kee, val in count.items(): Then, maxval determines the max value on line 11: if val maxval: right, view a copy of the revised code at http://tinyurl.com/nvzdw8k Question1: are these assumptions true, above?

Re: [Tutor] Dictionary Issue

Mark, I'm following the instructor's video exercise, available at https://www.youtube.com/watch?v=3cwXN5_3K6Q. View attached screen shot file, image file shows a copy of the counter: cou[wrd] =cou.get(wrd,0) +1 Please, explain the differences in counter methods? Hal On Thu, Aug 6, 2015 at

Re: [Tutor] Dictionary Issue

Question1: How type of argument should I use for dict, i.e.,user argument or list argument. Read captured traceback: TypeError Traceback (most recent call last) C:\Users\vm\Desktop\apps\docs\Python\assignment_9_4_26.py in module() 1 fname = raw_input(Enter file name: ) 2 handle =

Re: [Tutor] Dictionary Issue

On 07/08/15 01:15, Ltc Hotspot wrote: Question1: How type of argument should I use for dict, i.e.,user argument or list argument. Read captured traceback: TypeError Traceback (most recent call last) C:\Users\vm\Desktop\apps\docs\Python\assignment_9_4_26.py in module() 1 fname =

Re: [Tutor] Dictionary Issue

On 07/08/2015 01:30, Ltc Hotspot wrote: Mark, I'm following the instructor's video exercise, available at https://www.youtube.com/watch?v=3cwXN5_3K6Q. View attached screen shot file, image file shows a copy of the counter: cou[wrd] =cou.get(wrd,0) +1 Please, explain the differences in

Re: [Tutor] Dictionary Issue

Hi Mark, Why is Counter not defined on line #15: line = Counter(address),i.e., NameError: name 'Counter' is not defined? Share a chat session at http://tinyurl.com/oull2fw View line entry at http://tinyurl.com/oggzn97 Hal On Fri, Aug 7, 2015 at 12:14 AM, Mark Lawrence breamore...@yahoo.co.uk

Re: [Tutor] Dictionary Issue

On 07/08/15 19:18, Ltc Hotspot wrote: I want to find the max val , keys and values are defined on line 10: for kee, val in count.items(): Yes we know that, but you are not answering the questions we pose. Instead you seem to post random changes to your code and ask new questions which

Re: [Tutor] Dictionary Issue

Mark, Visit the following URL link to view a captured copy of the latest code revision, available at http://tinyurl.com/nvzdw8k Regards, Hal On Thu, Aug 6, 2015 at 10:17 AM, Ltc Hotspot ltc.hots...@gmail.com wrote: On Thu, Aug 6, 2015 at 8:28 AM, Mark Lawrence breamore...@yahoo.co.uk

Re: [Tutor] Dictionary Issue

Hi Alan, I moved counter outside the loop and below dict, maxval = None maxkee = None are both positioned outside the loop. URL link to the revisions are available at http://tinyurl.com/nvzdw8k Question: How do I define Counter Revised code reads: fname = raw_input(Enter file name: ) handle =

Re: [Tutor] Dictionary Issue

On 06/08/15 19:30, Ltc Hotspot wrote: I moved counter outside the loop and below dict, maxval = None maxkee = None are both positioned outside the loop. You moved counter but it is still a dict() and you don't use it anywhere. URL link to the revisions are available at

Re: [Tutor] Dictionary Issue

On 06/08/15 03:27, Ltc Hotspot wrote: The output as reported by the latest code revision: c...@iupui.edu mailto:c...@iupui.edu 1← Mismatch Looks like python continues to print the wrong data set: Python will print what you ask it to. Don't blame the tool! :-) for line in handle: if

Re: [Tutor] Dictionary Issue

Mark, Replace count[address]= count.get(address,0) +1 with c = Counter(['address'])? Regards, Hal On Wed, Aug 5, 2015 at 9:03 PM, Mark Lawrence breamore...@yahoo.co.uk wrote: On 05/08/2015 23:58, Ltc Hotspot wrote: Hi Mark, Address identifies the email address with the maximum number

Re: [Tutor] Dictionary Issue

On my breath and soul, I did: Counter objects have a dictionary interface except that they return a zero count for missing items instead of raising a KeyError https://docs.python.org/3/library/exceptions.html#KeyError: c = Counter(['eggs', 'ham']) On Thu, Aug 6, 2015 at 11:59 AM, Mark

Re: [Tutor] Dictionary Issue

On 07/08/15 00:11, Ltc Hotspot wrote: Questions(1):Why does print line, prints blank space; and, (2) print address prints a single email address: See my previous emails. You are not storing your addresses so address only holds the last address in the file. line is at the end of the file so

Re: [Tutor] Dictionary Issue

On 06/08/2015 20:05, Ltc Hotspot wrote: On my breath and soul, I did: Counter objects have a dictionary interface except that they return a zero count for missing items instead of raising a KeyError https://docs.python.org/3/library/exceptions.html#KeyError: That's nice to know. What do the

Re: [Tutor] Dictionary Issue

On Thu, Aug 6, 2015 at 3:00 PM, Alan Gauld alan.ga...@btinternet.com wrote: On 06/08/15 19:30, Ltc Hotspot wrote: I moved counter outside the loop and below dict, maxval = None maxkee = None are both positioned outside the loop. You moved counter but it is still a dict() and you don't use

Re: [Tutor] Dictionary Issue

On 06/08/15 18:17, Ltc Hotspot wrote: View revised code here: fname = raw_input(Enter file name: ) handle = open (fname, 'r') c = Counter(['address']) count = dict () maxval = None maxkee = None for kee, val in count.items(): maxval = val maxkee = kee for line in handle:

Re: [Tutor] Dictionary Issue

On Thu, Aug 6, 2015 at 8:28 AM, Mark Lawrence breamore...@yahoo.co.uk wrote: On 06/08/2015 05:22, Ltc Hotspot wrote: Please don't top post here, it makes following long threads difficult. Mark, Replace count[address]= count.get(address,0) +1 with c = Counter(['address'])? Try it at

Re: [Tutor] Dictionary Issue

On 06/08/2015 18:17, Ltc Hotspot wrote: On Thu, Aug 6, 2015 at 8:28 AM, Mark Lawrence breamore...@yahoo.co.uk wrote: On 06/08/2015 05:22, Ltc Hotspot wrote: Please don't top post here, it makes following long threads difficult. Mark, Replace count[address]= count.get(address,0) +1 with c

Re: [Tutor] Dictionary Issue

On 06/08/15 18:17, Ltc Hotspot wrote: Replace count[address]= count.get(address,0) +1 with c = Counter(['address'])? You didn't do what Mark suggested. Did you read the documentation about Counter? NameError Traceback (most recent call last) 2 handle = open (fname, 'r') 3 c =

Re: [Tutor] Dictionary Issue

The revised output reads: In [3]: %run assignment_9_4_9.py Enter file name: mbox-short.txt c...@iupui.edu 14 The desired output: c...@iupui.edu 5 Question: How do I trace the source of the count? Revised data code reads: fname = raw_input(Enter file name: ) handle = open (fname, 'r') count =

Re: [Tutor] Dictionary Issue

Hi Alan The output as reported by the latest code revision: c...@iupui.edu 1 ← Mismatch Looks like python continues to print the wrong data set: In [11]: print val 1 In [12]: print kee r...@media.berkeley.edu In [13]: print address c...@iupui.edu In order to complete the assignment, using data

Re: [Tutor] Dictionary Issue

On 06/08/2015 05:22, Ltc Hotspot wrote: Please don't top post here, it makes following long threads difficult. Mark, Replace count[address]= count.get(address,0) +1 with c = Counter(['address'])? Try it at the interactive prompt and see what happens. Regards, Hal On Wed, Aug 5, 2015

Re: [Tutor] Dictionary Issue

On 05/08/2015 23:58, Ltc Hotspot wrote: Hi Mark, Address identifies the email address with the maximum number of sends: c...@iupui.edu. Secondly, we are missing a count on the number of messages sent by c...@iupui.edu, i.e., 5. Thirdly, maxval 'none' is not defined on line # 24 Questions:

Re: [Tutor] Dictionary Issue

On 06/08/15 02:05, Ltc Hotspot wrote: The revised output reads: In [3]: %run assignment_9_4_9.py Enter file name: mbox-short.txt c...@iupui.edu mailto:c...@iupui.edu 14 The desired output: c...@iupui.edu mailto:c...@iupui.edu 5 See my other post. Count the number of letters in the address.

Re: [Tutor] Dictionary Issue

On 05/08/15 23:58, Ltc Hotspot wrote: fname = raw_input(Enter file name: ) handle = open (fname, 'r') for line in handle: if line.startswith(From: ): address = line.split()[1] So far so good. ## The program creates a Python dictionary that maps ## the sender's mail address

Re: [Tutor] Dictionary Issue

On 05/08/15 15:15, Ltc Hotspot wrote: Raw data code reads: Being picky here but data and code are very different things (in most languages at least) and what you have below is definitely code not data. Meanwhile there are lots of issues in this code... fname = raw_input(Enter file name: )

Re: [Tutor] Dictionary Issue

On 05/08/2015 15:15, Ltc Hotspot wrote: Hi everyone: I want to write a python program that reads through the data file of mbox-short.txt.Mbox-short.txt, i.e., download is available at http://www.py4inf.com/code/mbox-short.txt. Secondly, I want for python to figure out who sent the greatest

Re: [Tutor] Dictionary Issue

-Original Message- From: Tutor [mailto:tutor-bounces+crk=godblessthe...@python.org] On Behalf Of Mark Lawrence Sent: Wednesday, August 05, 2015 3:23 PM To: tutor@python.org Subject: Re: [Tutor] Dictionary Issue On 05/08/2015 15:15, Ltc Hotspot wrote: Hi everyone: I want

Re: [Tutor] Dictionary Issue

On 05/08/15 23:36, Clayton Kirkwood wrote: It looks like the problem is with count=dict() Should be count=dict{} I may be wrong - U'm still a neophyte. Yes, you're wrong! :-) the correct form is as shown count = dict() Its calling the type operation which looks like any other function and

Re: [Tutor] Dictionary Issue

However, there is a traceback message: In [40]: %run 9_4_4.py File C:\Users\vm\Desktop\apps\docs\Python\_9_4_4.py, line 19 count = dict() ^ SyntaxError: invalid syntax Syntax error reporting is approximate: you might need to look a few lines earlier to get at the root

Re: [Tutor] Dictionary Issue

Hi Mark, Address identifies the email address with the maximum number of sends: c...@iupui.edu. Secondly, we are missing a count on the number of messages sent by c...@iupui.edu, i.e., 5. Thirdly, maxval 'none' is not defined on line # 24 Questions: How do we define the value of none for the

Re: [Tutor] dictionary of lists

On Thu, Jun 4, 2015 at 2:30 AM, Peter Otten __pete...@web.de wrote: Chris Stinemetz wrote: Although I am certain it is not very efficient I was able to accomplish what I wanted with the following code I wrote: import os import pprint import csv from collections import defaultdict

Re: [Tutor] dictionary of lists

Chris Stinemetz wrote: Although I am certain it is not very efficient I was able to accomplish what I wanted with the following code I wrote: import os import pprint import csv from collections import defaultdict print_map = {'MOU':0, 'Call_Att':1, 'Device':2} header =

Re: [Tutor] dictionary of lists

On 03/06/15 17:39, Chris Stinemetz wrote: I am trying to create a dictionary of lists as I read a file. I envision it looking like: {key: [float_type],[string_type]} Thats not a dictionary of lists. You maybe mean: {key: [[float_type],[string_type]]} Which is a dictionary of lists of lists?

Re: [Tutor] dictionary of lists

Resetting execution engine Running C:\Users\cs062x\Desktop\python\projects\PanHandle\PanHandle\PanHandle.py The Python REPL process has exited That's slightly unusual. How are you running this? I am running it with Microsoft Visual Studio Community 2013 using Python Tools for Visual

Re: [Tutor] dictionary keys

Alex Kleider wrote: On 2014-04-08 14:34, Peter Otten wrote: That's a change in Python 3 where dict.keys() no longer creates a list, but instead creates a view on the underlying dict data thus saving time and space. In the rare case where you actually need a list you can explicitly create

Re: [Tutor] dictionary keys

On 2014-04-08 23:55, Peter Otten wrote: You can create and sort the list in a single step: l = sorted(myDict) Thank you again; this is a new idiom for me. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options:

Re: [Tutor] dictionary keys

Alex Kleider wrote: I've got a fairly large script that uses a dictionary (called 'ipDic') each value of which is a dictionary which in turn also has values which are not simple types. Instead of producing a simple list, ips = ipDic.keys() print(ips) yields

Re: [Tutor] dictionary keys

On 2014-04-08 14:34, Peter Otten wrote: That's a change in Python 3 where dict.keys() no longer creates a list, but instead creates a view on the underlying dict data thus saving time and space. In the rare case where you actually need a list you can explicitly create one with ips =

Re: [Tutor] Dictionary from a text file

Nitish Kunder wrote: I have a dictionary which is in this format for ex: { '5x' : { '50' : { 'update' : { 'update-from-esxi5.0-5.0_update01' : { 'call' : Update, 'name' : 'Update50u1', 'release' : '15/03/12' }, 'update-from-esxi5.0-5.0_update02' : { 'call' : Update, 'name' :

Re: [Tutor] Dictionary from a text file

On 10/31/2013 2:16 AM, Nitish Kunder wrote: I have a dictionary which is in this format for ex: { '5x' : { '50' : { 'update' : { 'update-from-esxi5.0-5.0_update01' : { 'call' : Update, 'name' : 'Update50u1', 'release' : '15/03/12' }, 'update-from-esxi5.0-5.0_update02' : { 'call' : Update,

Re: [Tutor] Dictionary from a text file

Note: in* 'call' : Update* ,Update it is a function defined in my python script. My dictionary is too large so i taught rather than using directly in python program I save it in a text file and when needed i assign it to dictionary object . How can i assign this text file to dictionary

Re: [Tutor] Dictionary get method

On 20/03/13 14:54, Amit Saha wrote: Hello Phil, On Wed, Mar 20, 2013 at 12:54 PM, Phil phil_...@bigpond.com wrote: Thank you for reading this. I'm working my way through a series of exercises where the author only provides a few solutions. The reader is asked to modify the histogram example

Re: [Tutor] Dictionary get method

On 20/03/13 15:09, Mitya Sirenef wrote: cut By the way, you can further simplify it by doing: def histogram2(s): return {c: d.get(c,0)+1 for c in s} That will work in python 3, in python 2 you need: return dict((c: d.get(c,0)+1) for c in s) Thanks again Mitya, although I'm not

Re: [Tutor] Dictionary get method

Phil wrote: On 20/03/13 15:09, Mitya Sirenef wrote: cut By the way, you can further simplify it by doing: def histogram2(s): return {c: d.get(c,0)+1 for c in s} That will work in python 3, in python 2 you need: return dict((c: d.get(c,0)+1) for c in s) Thanks again

Re: [Tutor] Dictionary get method

On 03/20/2013 04:21 AM, Peter Otten wrote: Phil wrote: On 20/03/13 15:09, Mitya Sirenef wrote: cut By the way, you can further simplify it by doing: def histogram2(s): return {c: d.get(c,0)+1 for c in s} That will work in python 3, in python 2 you need: return dict((c:

Re: [Tutor] Dictionary get method

On 03/19/2013 10:54 PM, Phil wrote: Thank you for reading this. I'm working my way through a series of exercises where the author only provides a few solutions. The reader is asked to modify the histogram example so that it uses the get method thereby eliminating the if and else

Re: [Tutor] Dictionary get method

Hello Phil, On Wed, Mar 20, 2013 at 12:54 PM, Phil phil_...@bigpond.com wrote: Thank you for reading this. I'm working my way through a series of exercises where the author only provides a few solutions. The reader is asked to modify the histogram example so that it uses the get method

Re: [Tutor] Dictionary get method

On 03/19/2013 10:54 PM, Phil wrote: Thank you for reading this. I'm working my way through a series of exercises where the author only provides a few solutions. The reader is asked to modify the histogram example so that it uses the get method thereby eliminating the if and else

Re: [Tutor] Dictionary get method

On 03/20/2013 01:09 AM, Mitya Sirenef wrote: By the way, you can further simplify it by doing: def histogram2(s): return {c: d.get(c,0)+1 for c in s} That will work in python 3, in python 2 you need: return dict((c: d.get(c,0)+1) for c in s) Sorry, it should use a comma: return

Re: [Tutor] Dictionary

On 6/17/2012 2:26 PM, Selby Rowley-Cannon wrote: [snip] Do you have any programming (algorithm development) experience? Do you want to translate words independent of context? -- Bob Gailer 919-636-4239 Chapel Hill NC ___ Tutor maillist -

Re: [Tutor] Dictionary

Does this language have grammar independent of english? If no, just use .split() on the string and loop through that. If yes, well, its much more complicated On Jun 17, 2012 2:27 PM, Selby Rowley-Cannon selbyrowleycan...@ymail.com wrote: Version: 2.7 OS: Ubuntu 12.04 LTS I am writing a

Re: [Tutor] dictionary of methods calling syntax

Alan Gauld wrote: Since a class is effectively a disguised dictionary I'm not sure why you want to do this? If you just want to access the method by name then why not just call getattr(spam,'get_mean')? Thanks for the feedback and, yes, this makes sense. My use case was when the statistic

Re: [Tutor] dictionary of methods calling syntax

On 08/02/2012 17:41, Gregory, Matthew wrote: Alan Gauld wrote: Since a class is effectively a disguised dictionary I'm not sure why you want to do this? If you just want to access the method by name then why not just call getattr(spam,'get_mean')? Thanks for the feedback and, yes, this makes

Re: [Tutor] dictionary of methods calling syntax

On Tue, Feb 7, 2012 at 2:32 PM, Gregory, Matthew matt.greg...@oregonstate.edu wrote: Hi list, I'm trying to understand how to use a class-level dictionary to act as a switch for class methods.  In the contrived example below, I have the statistic name as the key and the class method as the

Re: [Tutor] dictionary of methods calling syntax

On 07/02/12 19:32, Gregory, Matthew wrote: class Statistics(object): STAT = { 'MEAN': get_mean, 'SUM': get_sum, } ... if __name__ == '__main__': spam = Statistics(4, 3) print spam.get_stat('mean') print spam.get_stat('sum') Since a class is

Re: [Tutor] Dictionary to variable copy

Op 08-12-11 10:03, sunil tech schreef: /Can i copy the content if a dictionary in to another variable, with out any link between the dictionary the variable? / Have a look at the copy module [1], or use the builtin dict.copy() method. Cheers, Timo [1]

Re: [Tutor] Dictionary to variable copy

On 08/12/11 09:03, sunil tech wrote: /Can i copy the content if a dictionary in to another variable, with out any link between the dictionary the variable? if so, please teach. Yes, but they will both refer to the same object. But the two references will be entirely independant: D =

Re: [Tutor] Dictionary File character reader

On Tue, May 10, 2011 at 5:27 AM, Clara Mintz jamani.s...@hotmail.com wrote: Sorry I am completely new at python and don't understand why this function is returning an empty dictionary. I want it to take a list of files open them then return the number of characters as the value and the file

Re: [Tutor] Dictionary File character reader

Noah Hall enali...@gmail.com wrote What you want is something that takes the length of each line, and add it to the sum. A simple way would be to do sum(len(line) for line in file) And if you just want the total count for the file an even simpler way is to use file.read() count =

Re: [Tutor] Dictionary File character reader

On 01/-10/-28163 02:59 PM, Clara Mintz wrote: Sorry I am completely new at python and don't understand why this function is returning an empty dictionary. I want it to take a list of files open them then return the number of characters as the value and the file name as the key. def

Re: [Tutor] dictionary

Supposing your dictionary like this: dict={1:'My name is X',2:'My name is x y z',3: 'i am X'} You can use len(list) : dict={1:'My name is X',2:'My name is x y z',3: 'i am X'} for values in dict.values(): ... if len(values.split(' '))3: ...print values My name is X My name is x y z

Re: [Tutor] dictionary

louis leichtnam wrote: HEllo everyone, I have a dictionnary, and I would like to print only the values that have more/equal than 3 spaces in them for example: My name is Xavier. d = {1: Hello world, 2: My name is Xavier, 3: ham and eggs, 4: Eat more cheese please!, 5: spam spam spam

Re: [Tutor] Dictionary Question

Garry Bettle wrote: Howdy all, Hope this message finds everyone well. I have dictionary of keys and a string of values. i.e. 8 Fixtures: I assume each fixture is a key, e.g. Swin, HGrn, etc. Swin1828 1844 1901 1916 1932 1948 2004 2019 2036 2052 2107 2122 HGrn1148 1204 1218 1232

Re: [Tutor] Dictionary Question

On 12/22/2010 7:31 AM, Steven D'Aprano wrote: Also note: len(dict.keys()) == len(dict.values()) == len(dict) -- Bob Gailer 919-636-4239 Chapel Hill NC ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options:

Re: [Tutor] Dictionary Question

On Wed, 22 Dec 2010 23:31:39 +1100, Steven D'Aprano wrote: In this case, you need to sum the number of races for all the fixtures: num_races = sum(len(racetimes) for racetimes in FixtureDict.values()) Many thanks Steven for your explanation and final golden nugget of code. On Wed, 22 Dec 2010

Re: [Tutor] dictionary and more

Hi- I apologize for the size of the attached file, but the question would make little sense if I made substantial deletions. The program gives the following error: Traceback (most recent call last): File /Javastuff/python/Glau_Is.py, line 131, in module Adestin[state]()

Re: [Tutor] dictionary and more

Jack Uretsky j...@hep.anl.gov wrote Please do not reply to an existing thread when starting a new topic. This messes up threaded newsreaders and several archives. Start a new topic with a newmessage. I apologize for the size of the attached file, but the question would make little sense

Re: [Tutor] dictionary and more

On 10/11/2010 9:19 AM Jack Uretsky said... Hi- I apologize for the size of the attached file, but the question would make little sense if I made substantial deletions. The program gives the following error: Traceback (most recent call last): File /Javastuff/python/Glau_Is.py, line 131, in module

Re: [Tutor] dictionary and more

On Tue, 12 Oct 2010 03:19:22 am Jack Uretsky wrote: Hi- I apologize for the size of the attached file, but the question would make little sense if I made substantial deletions. The program gives the following error: Traceback (most recent call last): File

Re: [Tutor] Dictionary Comprehensions

Khalid Al-Ghamdi wrote: Hi everyone! I'm using python 3.1 and I want to to know why is it when I enter the following in a dictionary comprehension: dc={y:x for y in list(khalid) for x in range(6)} I get the following: {'a': 5, 'd': 5, 'i': 5, 'h': 5, 'k': 5, 'l': 5} instead of the

Re: [Tutor] Dictionary Comprehensions

Lie Ryan lie.1...@gmail.com dixit: note that: [(y, x) for y in list(khalid) for x in range(6)] [('k', 0), ('k', 1), ('k', 2), ('k', 3), ('k', 4), ('k', 5), ('h', 0), ('h', 1), ('h', 2), ('h', 3), ('h', 4), ('h', 5), ('a', 0), ('a', 1), ('a', 2), ('a', 3), ('a', 4), ('a', 5), ('l', 0),

Re: [Tutor] Dictionary Comprehensions

Hugo Arts hugo.yo...@gmail.com dixit: bc = {y: x for x, y in enumerate(khalid)} Note that your output is like so: {'a': 2, 'd': 5, 'i': 4, 'h': 1, 'k': 0, 'l': 3} The first character in your original string gets a zero, the second a one, so on and so forth. I'm hoping that's what you

Re: [Tutor] Dictionary Comprehensions

On 12/5/2009 7:32 AM, Khalid Al-Ghamdi wrote: Hi everyone! I'm using python 3.1 and I want to to know why is it when I enter the following in a dictionary comprehension: dc={y:x for y in list(khalid) for x in range(6)} are you sure you want this? {'a': 0, 'd': 1, 'i': 2, 'h': 3, 'k': 4,

Re: [Tutor] Dictionary Comprehensions

On Fri, Dec 4, 2009 at 9:32 PM, Khalid Al-Ghamdi emailkg...@gmail.com wrote: Hi everyone! I'm using python 3.1 and I want to to know why is it when I enter the following in a dictionary comprehension: dc={y:x for y in list(khalid) for x in range(6)} I get the following: {'a': 5, 'd': 5, 'i':

Re: [Tutor] Dictionary Comprehensions

On 12/4/2009 12:32 PM Khalid Al-Ghamdi said... Hi everyone! I'm using python 3.1 and I want to to know why is it when I enter the following in a dictionary comprehension: dc={y:x for y in list(khalid) for x in range(6)} Try breaking this into pieces... First see what [(x,y) for y in in

Re: [Tutor] Dictionary Comprehensions

Khalid Al-Ghamdi wrote: Hi everyone! I'm using python 3.1 and I want to to know why is it when I enter the following in a dictionary comprehension: dc={y:x for y in list(khalid) for x in range(6)} I get the following: {'a': 5, 'd': 5, 'i': 5, 'h': 5, 'k': 5, 'l': 5} instead of

Re: [Tutor] Dictionary, integer, compression

Dinesh B Vadhia dineshbvad...@hotmail.com wrote Say, you have a dictionary of integers, are the integers stored in a compressed integer format or as integers ie. are integers encoded before being stored in the dictionary and then decoded when read? I can't think of any reason to compress

Re: [Tutor] Dictionary, integer, compression

Dinesh B Vadhia wrote: Say, you have a dictionary of integers, are the integers stored in a compressed integer format or as integers ie. are integers encoded before being stored in the dictionary and then decoded when read? Integer objects are not special cased in dictionaries. They are stored

Re: [Tutor] Dictionary, integer, compression

performance but could enhance it. Weird, I know! I'll check in with the comp.lang.python lot. Dinesh Message: 3 Date: Wed, 29 Apr 2009 17:35:53 +0100 From: Alan Gauld alan.ga...@btinternet.com Subject: Re: [Tutor

Re: [Tutor] dictionary looping problem

On Tue, Dec 02, 2008 at 01:08:09PM -0800, Jeremiah Jester wrote: Hello, I'm trying to gather a list of files and md5 hash them to do a checksum. I've created a function for each dictionary. However, when i print out the dictionary I don't get all the items. Any ideas? Yep. Don't use

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