On Thu, 29 Jun 2000 19:44:27 -0500 (CDT), you wrote:
>Hello Everyone:
>
> I have 2 computers (Computer A and B).
>
>Case:1
>Computer A running Win 98 and Redhat 6.0
>
>Spec: I have a 17 gig harddrive on computer A. Linux had to be installed
>in the 1st 1024 cylinders or bytes ( do not recall exactly ) so my Win98
>partition is 3 gig and the rest 14gig of the harddrive goes to linux,
>which does not need that much space.
>
>Question: Does redhat 6.2 fix. I am thinking about upgrading to 6.2 and
>is there a solution to install linux in the last 3 gig of the harddrive.
6.2 doesn't fix it, but you only need to have the kernel below 1024
cylinders, so just make a small boot partition (I use 8MB) at the beginning
of the harddrive and put the rest of the installation wherever you want.
>Case:2
>Computer B running Win 98 only
>Spec: I have a 19 gig harddrive. I want to install Win2000, 98 and
>Redhat 6.2 I want the Win98 to take the 1st 8 gig and Win 2000 to take
>the next 8 gigs each and then the rest 3 gig will be for Redhat 6.2.
>
>Question: Is there a way to do this ? Please let me know.
Yes, it's called partitioning.
--
Be seeing you.
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