What voltage are you running these days Wong?

The resistor value can be calculated using R = V/I (resistance in ohms
equals the voltage divided by the current in amps. For 12 Volts and
assuming a 2mA  short circuit current then a 6000 ohm (6K0) resistor
will suffice but is probably not necessary.
[ I have found in my system the load resistance (CS solution) is about
20K ohms at 12 to 15 ppm. As the load resistance is higher than the
determined limiting resistor value, the actual current does not reach
the chosen current, in fact the limiting resistor further limits the
current, in this case, to 0.46mA (12V divided sum of load and limiting
resistor) and is therefore not required] The actual current without a
limiting resistor is 0.6mA which I feel is a pretty good maximum.

For  36V in my system an 18K0 resistor will limit the short circuit
current to 2mA. In actual current terms, the current will be 0.95mA,
with a load resistance of 20K ohms.

For a 27V a 7K0 resistor will limit the actual current to 1mA and will
have a short circuit current of about 4mA.

This resistor (just a cheap 1/4 watt resistor from your local electronic
shop) is wired in series, that is, placed between one electrode and its
power source wire. You don't need to solder it, just wrap one leg around
the silver electrode and grab the other leg with the alligator clip of
your power supply lead.

Regards - Ivan.

----- Original Message -----
From: <wong...@aol.com>
To: <silver-list@eskimo.com>; <i...@win.co.nz>
Sent: Wednesday, 20 October 1999 21:53
Subject: Re: CS>power supply


> Ivan
>
> How do you do this? Very poor with electronics or electricity.
> wong
>
> In a message dated 10/19/1999 8:42:02 AM Pacific Daylight Time,
> mdev...@mail.id.net writes:
>
> << You'll might want to throw a current limiting resistor in line with
>  things, so that dead short current will not exceed a few milliamps.
>  Assuming that you're using a couple of silver wire electrodes, this
>  will prevent peak current from getting above a milliamp or so.
>   >>
>
>
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