url: http://escribe.com/health/thesilverlist/m60419.html
Re: CS>Re: Nebulizing CS for SARS Redux
From: Robert Berger
Date: Thu, 19 Jun 2003 15:00:10
> Mike,
> Look at my data plot. I don't run 335 uA continually. The current
> starts out at 2.64 ma or 66 uA/sqin. and builds until the regualto
> cuts in at 12.6 ma. running in 2 gallons of 4 ppm CS. This was a
> reprocessed lot as stated.
> I guess I could order in the silver for this experiment. I'll
> think about it.
> "Ole Bob"
Hey Bob, that's great!
You will find this system is quite different from what you are used
to.
Your LM117 regulator won't go down to 335 uA. A LM134 would work
better, but there's no need to complicate things just to take a look.
You may be using a 24V doorbell transformer to supply the DC. If so,
you should get about 34 to 36 Volts.
Here's my notes from the last run:
--------------------------------------------------------------------
Sun Jun 15, 2003, 06:13:45 pm Started run. Quit at midnight
Sun Jun 15, 2003, 06:13:25 pm 6.43V 323uA
Sun Jun 15, 2003, 07:23:51 pm 2.598 322uA
Sun Jun 15, 2003, 08:29:35 pm 2.200 321uA
Sun Jun 15, 2003, 09:48:25 pm 1.754 322Ua
Sun Jun 15, 2003, 10:27:32 pm 1.632 321uA
Sun Jun 15, 2003, 11:58:56 pm 1.501 333uA
Mon Jun 16, 2003, 12:17:11 am 1.483 335uA
Tiny bit on anode rods. Make them the cathode next time.
--------------------------------------------------------------------
You can see the voltage dropped quite rapidly at first, then
gradually decreased. This is the familiar 1/t curve where most of
the change occurs at the beginning.
The reason for the increase at the end is the line voltage changed
when everyone turned off the lights and tv and went to bed. The tv
draws high current at the peak of the cycle, which flattens the
peak. When this effect is removed, the peak voltage increases and my
rectifier/filter shows a 4% increase in DC voltage. That's OK.
After the first hour, the voltage across the cell was about 2V or
less.
If you have 34V available, then all you need is a resistor to set
the current. The value is
R = E / I
= (34 - 2) / 335e-6
= 95522.388 ohms
A 100K is a common standard value. It will probably have 5%
tolerance. That's OK.
The current will be slightly low at the beginning, then
asymptotically approach the final value.
When you integrate it over time, there will be a small error but not
enough to change the results significantly. You can use the
integrated value to calculate the ppm.
400 millitres should be a good volume to try. It won't take so long.
I'm thrilled that you might give this a try. Thanks!
Best Regards,
Mike Monett
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