Say it's a 2.5" C=.9. I've tried to work this out a couple different ways: 1) a kind of long drawn out way, call it 'brad's way', and I get ~168. 2) a way i call the 'Bill Brooks back of napkin' way based on a few words he posted here a few years ago-- lightening fast, and i'll be damned if i dont get the same ~168! Basically, since K is the square feet area of the orifice he says 5*5*5.6=140, times (.9/.75) = 168. Anyway, if a hydrant butt has a K we could pretty quickly get the Q after the pitot'd P with Q=K*SQRT(P).
thanks, Brad .
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